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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 36051. |
A block of mass 1 kg is fastended to one end of a wire of cross-sectional area 2 mm^(2) and is rotated in a verticalcircle of radius 20 cm. The speed of the block at the bottom of the circle is 3.5 ms^(-1). Find the elongation of the wire when the block is at the top of the circle. |
| Answer» <html><body><p></p>Solution : i) Tension at the <a href="https://interviewquestions.tuteehub.com/tag/bottom-401202" style="font-weight:bold;" target="_blank" title="Click to know more about BOTTOM">BOTTOM</a> of the circle,<br/>`T = (mv^2)/(r ) + <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>= (1 xx (3.5)^2)/(0.2) + 1 xx 9.8` <br/>` = 61.25 + 9.8 = 71.05 N`<br/>This tension in the <a href="https://interviewquestions.tuteehub.com/tag/string-11290" style="font-weight:bold;" target="_blank" title="Click to know more about STRING">STRING</a> is equal to the force, F i.e., F=71.05N, L =r=0.2m. <br/>The increase in length,<br/>` e = (FL)/(AY) = (71.05 xx 0.2)/(2 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) xx 2 xx 10^11)` <br/>` = 3.553 xx 10^(-5) m` <br/>ii) Tension at the top of the circle,T = Tension at the bottom - 6 mg<br/>`= 71.05 - <a href="https://interviewquestions.tuteehub.com/tag/6xx-1913072" style="font-weight:bold;" target="_blank" title="Click to know more about 6XX">6XX</a> 1 xx 9.8 = 71.05 - 58.8 = 12.25 N.`<br/>F= 12.25 N, L = 0.2 m.<br/>The increase in length ` = (FL)/(AY)` <br/> ` = (12.25 xx 0.2)/(2 xx 10^(-6) xx 2 xx 10^11)` <br/>` = 0.6125 xx 10^(-5) m`</body></html> | |
| 36052. |
A mobile phone lies along the principal axis of a concave mirror , as shown in Fig. Shown by suitable diagram, the formation of its image. Explain why the magnification is not uniform. Will the distortion of image depend on the location of the phone with respect to the mirror? |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/ray-1177996" style="font-weight:bold;" target="_blank" title="Click to know more about RAY">RAY</a> diagram for the formation of the image of the phone is <a href="https://interviewquestions.tuteehub.com/tag/shown-1206565" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWN">SHOWN</a> in <a href="https://interviewquestions.tuteehub.com/tag/fig-460913" style="font-weight:bold;" target="_blank" title="Click to know more about FIG">FIG</a>. The image of the part which is on the plane perpendicular to <a href="https://interviewquestions.tuteehub.com/tag/principal-1166121" style="font-weight:bold;" target="_blank" title="Click to know more about PRINCIPAL">PRINCIPAL</a> <a href="https://interviewquestions.tuteehub.com/tag/axis-889931" style="font-weight:bold;" target="_blank" title="Click to know more about AXIS">AXIS</a> will be on the same plane. It will be of the same size, i.e., `B.C=BC`. You can youself realise why the image is distorted.</body></html> | |
| 36053. |
Three identical thin rods each of length l and mass M are joined together to form a letter H. What is the moment of inertia of the system about one of the sides of H? |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^2`<br/>`(1)/(4) Ml^2`<br/>`(2)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) Ml^2`<br/>`(4)/(3) Ml^2`</p>Solution :Moment of inertia of the system about <a href="https://interviewquestions.tuteehub.com/tag/rod-1190628" style="font-weight:bold;" target="_blank" title="Click to know more about ROD">ROD</a> A <br/> `I = I_(A) + I_(B) + I_(C) =0 + ((Ml^2)/(12)+ (Ml^2)/(4)) + Ml^(2) = (4)/(3) Ml^(2)` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/MTG_NEET_GID_PHY_XI_C05_E01_076_S01.png" width="80%"/></body></html> | |
| 36054. |
In the above problem the horizontal distance between the two fragments when their velocity vectors are perpendicular to each other is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/10m-267115" style="font-weight:bold;" target="_blank" title="Click to know more about 10M">10M</a> <br/>20m<br/>40m<br/>50m</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36055. |
If the coefficient of real expansion of a liquid is 7.4xx 10^(-4)// ^(@)C, and the coefficient of apparent expansion of a liquid is 7.4 xx 10^(-4)//^(@)C. Find the coefficient of linear expansion of the material of the vessel. |
| Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a> <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10 ^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) // ^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`</body></html> | |
| 36056. |
Give, potential difference V = (8 + 0.5) V and current I = (2 + 0.2) A. The value of resistance R is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> pm 16.25%)`<br/>`(4pm 6.25%)`<br/>`(4 pm <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>%)`<br/>`(4pm 8%)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36057. |
(A): A steel wire of natural length 'l' breaks, when elongated by length 'x'. If original length is halved and elongated by x/2 it breaks. (R): Breaking force is directly proportional to the length of the wire |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A) <br/> Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/>(A) is true but (R) is false<br/>Both (A) and (R) are false</p>Answer :C</body></html> | |
| 36058. |
Does a hydraulic press work, if the liquid used in it is replaced by a gas? |
| Answer» <html><body><p></p>Solution :The thrust applied will no doubt be multiplied if the liquid <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a> in a hydraulic press is replaced by a gas. But, due to the <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> <a href="https://interviewquestions.tuteehub.com/tag/compressibility-20830" style="font-weight:bold;" target="_blank" title="Click to know more about COMPRESSIBILITY">COMPRESSIBILITY</a> of a gas, the thrust developed on the larger piston will bot be <a href="https://interviewquestions.tuteehub.com/tag/large-1066424" style="font-weight:bold;" target="_blank" title="Click to know more about LARGE">LARGE</a> enough. For this reason, the press cannot be used for <a href="https://interviewquestions.tuteehub.com/tag/efficient-966565" style="font-weight:bold;" target="_blank" title="Click to know more about EFFICIENT">EFFICIENT</a> pressing.</body></html> | |
| 36059. |
If the paticle is moving along a straight line given by the relation s=2-3t+4t^(3) where s is in cms., and t in sec. its average velocity during the third sec is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/73-334616" style="font-weight:bold;" target="_blank" title="Click to know more about 73">73</a> cm/s<br/>80 cm/s<br/>85 cm/s<br/>90 cm/s</p>Answer :A</body></html> | |
| 36060. |
Vector vecA is 2 cm long and is 60^(@)above th e x-axis in the first quadrant, vector vecB is 2cm long and is 60^(0)below the x-axis in the fourth quadrant . Find vecA+vecB. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`vecR=vecA+vecB`<br/> `R=2 cos <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(0)<a href="https://interviewquestions.tuteehub.com/tag/hati-2693493" style="font-weight:bold;" target="_blank" title="Click to know more about HATI">HATI</a>+2sin60hatj+2 cos 60hati-2sin60hatj`<br/> `vecR = <a href="https://interviewquestions.tuteehub.com/tag/4cos-318914" style="font-weight:bold;" target="_blank" title="Click to know more about 4COS">4COS</a> 60^(0)hati = 2hati`<br/> `:. 2cm `, <a href="https://interviewquestions.tuteehub.com/tag/along-1974109" style="font-weight:bold;" target="_blank" title="Click to know more about ALONG">ALONG</a> x-axis<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_PHY_XI_V01_A_C03_SLV_011_S01.png" width="80%"/></body></html> | |
| 36061. |
A hot body is placed in cooler surroundings. When the body temperature is 75^(@)C, the rate of cooling is 4^(@)C/ min. When it is 55^(@)C, the rate of cooling is 2^(0)C/ min. The temperature of the surroundings is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>^(@)` C <br/>`25^(@) C `<br/>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)C `<br/>`<a href="https://interviewquestions.tuteehub.com/tag/35-308504" style="font-weight:bold;" target="_blank" title="Click to know more about 35">35</a>^(@)` C </p>Answer :D</body></html> | |
| 36062. |
Why are the springs made of steel and not of copper ? |
| Answer» <html><body><p></p>Solution :The Young.s <a href="https://interviewquestions.tuteehub.com/tag/modulus-1100097" style="font-weight:bold;" target="_blank" title="Click to know more about MODULUS">MODULUS</a> of steel is more than the Young.s modulus of <a href="https://interviewquestions.tuteehub.com/tag/copper-933790" style="font-weight:bold;" target="_blank" title="Click to know more about COPPER">COPPER</a> and Young.s modulus is the <a href="https://interviewquestions.tuteehub.com/tag/measure-1091857" style="font-weight:bold;" target="_blank" title="Click to know more about MEASURE">MEASURE</a> of elasticity of material. Hence steel is used for making springs.</body></html> | |
| 36063. |
What is the acceleration of the blockandtrolley system shown in a Fig.(a), if the coefficient of kinetic friction between the trolley and the surface is 0.04? What is the tension in the string? (Take g = 10 m s^(-2) ).Neglect the mass of the string. |
| Answer» <html><body><p></p>Solution :As the string is <a href="https://interviewquestions.tuteehub.com/tag/inextensible-2736845" style="font-weight:bold;" target="_blank" title="Click to know more about INEXTENSIBLE">INEXTENSIBLE</a> and the pully is smooth, the <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> kg block and the 20 kg trolley both have same magnitude of acceleration.Applying second law to motion of the block (Fig. (b))<br/> `30 - T = 3a` <br/> Apply the second law to motion of the trolley (Fig. (c)),<br/>`T - f_k = 20a` <br/>`f_k = mu_k N`<br/> ` mu_k = 0.04` <br/>`N = 20 xx 10` <br/> = <a href="https://interviewquestions.tuteehub.com/tag/200n-290170" style="font-weight:bold;" target="_blank" title="Click to know more about 200N">200N</a> <br/> Thus the equation for the motion of the trolley is<br/> `T - 0.04 xx 200 = 20 a " or" T - 8 = 20a ` <br/> These <a href="https://interviewquestions.tuteehub.com/tag/equations-452536" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATIONS">EQUATIONS</a> give a ` = 22/23 ms^(-2) = 0.96 ms^(-2)`and T = 27.1 N</body></html> | |
| 36064. |
Set the drifts suffered by boat in increasing order. (a) d=1000 m V_(R)=2m//s V_(b)=4m//s (b) d=500 m V_(R)=1m//s V_(b) =6 m//s (c) d=100m V_(R) =6m//s V_(b)=6 m//s ( d width of river V_(R)velocity of river V_(b)veclocity of boat). The boat moves perpendicular to bank of the river |
| Answer» <html><body><p>a, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>, <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a><br/>b, c, a<br/>b, a, c<br/>c, b, a</p>Answer :C</body></html> | |
| 36065. |
A body of mass 5kg starts from the origin with an initial velocity vecu=30hati+40hatjms^(-1). If a constant force vecF=-(hati+5hatj)N acts on the body, the time in which the y-component of the velocity becomes zero is |
| Answer» <html><body><p>5s<br/>20s<br/>40s<br/>80s</p>Solution :`V=u+at, a=(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>)/(m)`</body></html> | |
| 36066. |
State and explain zeroth law of thermodynamics . |
| Answer» <html><body><p></p>Solution :If two bodies are in <a href="https://interviewquestions.tuteehub.com/tag/thermal-706916" style="font-weight:bold;" target="_blank" title="Click to know more about THERMAL">THERMAL</a> <a href="https://interviewquestions.tuteehub.com/tag/equillibrium-974439" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILLIBRIUM">EQUILLIBRIUM</a> separately with a <a href="https://interviewquestions.tuteehub.com/tag/third-1414358" style="font-weight:bold;" target="_blank" title="Click to know more about THIRD">THIRD</a> body then they are in thermal equillibrium with each other .</body></html> | |
| 36067. |
In electricity consumption, 1 unit means …... J work. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`3.6xx10^6`</body></html> | |
| 36068. |
Jupiter is at a distance of 824.7 million km from the Earth. Its angular diameter is measured to be 35.72". Calculate the diameter of Jupiter. |
| Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> = 35.72..` <br/> l" = `4.85 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)` radian `rArr 35.72.. = 35.72 xx 4.85 xx 10^(-6)` rad <br/> `d = Dtheta = 824.7 xx 35.72 xx 4.85 xx 10^(-6) = 1.4287 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)` <a href="https://interviewquestions.tuteehub.com/tag/km-1064498" style="font-weight:bold;" target="_blank" title="Click to know more about KM">KM</a></body></html> | |
| 36069. |
What is rotational motion? Explain it with example. |
| Answer» <html><body><p></p>Solution :Here rigid body as a solid metallic or wooden cylinder. <br/> This cylinder shifts from the top of bottom of the inclined plane and thus it has <a href="https://interviewquestions.tuteehub.com/tag/translation-1426133" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSLATION">TRANSLATION</a> motion. <br/> All its particles are not moving with the same velocity at any instant. The particle <a href="https://interviewquestions.tuteehub.com/tag/near-1112277" style="font-weight:bold;" target="_blank" title="Click to know more about NEAR">NEAR</a> from the axis of cylinder has less velocity and particles for <a href="https://interviewquestions.tuteehub.com/tag/away-386546" style="font-weight:bold;" target="_blank" title="Click to know more about AWAY">AWAY</a> from the axis of cylinder has more velocity. <br/> Such type of cylinder velocity is not pure translation it has combined velocity of rotation with it. <br/> The line along which the body is fixed is termed as its axis of rotation, its motion known as rotational motion. <br/> If all the paticles motion of a rigid body move along circular <a href="https://interviewquestions.tuteehub.com/tag/path-11833" style="font-weight:bold;" target="_blank" title="Click to know more about PATH">PATH</a> and the centre of all these circles fall on a definite straight line then the motion of the body is called rotational motion. <br/> If all the particles of a rigid body perform circular motion and the <a href="https://interviewquestions.tuteehub.com/tag/centres-912272" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRES">CENTRES</a> of these circles are steady on a definate straight line called axis of rotation. <br/> Examples of rotation motion : A ceiling fan, a potter.s wheel, a giant wheel in a fair, a marry-go-round etc.</body></html> | |
| 36070. |
(A) : With increase in temperature, elastic property of a substance decreases(R): Elasticity is due to intermolecular forces which decrease with increase of intermolecular distance |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of (A) <br/> Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/>(A) is true but (R) is false<br/>Both (A) and (R) are false</p>Answer :B</body></html> | |
| 36071. |
Show that if the force acting on the particleis zeroits momentum remains unchaged |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a>(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> ) =(vec( dp))/(<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a>)` <br/> As `vec(F ) = 0::.(vec(d p))/( dt ) =0 " (or)"vec(p )=`constant</body></html> | |
| 36072. |
The celling of a long hall is 25 m high What is the maximum horizontal distance that a ball thrown with a speed of 40 " ms "^(-1) can go without hitting the ceiling of the hall ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :150.5 m</body></html> | |
| 36073. |
A mass of 2 kg oscillates on a spring with force constant 50 N/m. By what factor does the frequency of oscillation decrease when a damping force with constant b=12 is introduced? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a> by 10 %<br/>decreases by <a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a>%<br/>decreases by 50 %<br/>decreases by 20%</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 36074. |
A boat of mass 80 kg is floating on still water. A dog of mass 20 kg on the boat is at a distance of 10 m from the shore. The dog moves on the boat by a distance of 2m towards the shore. The distance of the dog from the shore is |
| Answer» <html><body><p>11.6 m <br/>8.4 m <br/>9.6 m <br/>10.4 m </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36075. |
A block of mass 4 kg is placed on a rough horizontal plane. A time dependent horizontal force F = kt acts on the block (k = 2 N/s). Find the frictional force between the block and the plane at t = 2 second and t = 5 second (mu = 0.2) |
| Answer» <html><body><p> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :When t=2sec F=4N<br/> `f_(ms)=mu" mg"=0.2xx4xx10=8N`<br/> `:. Fltf_(ms) :."friction"=4N`<br/> When t=5sec F=2(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)=<a href="https://interviewquestions.tuteehub.com/tag/10n-267183" style="font-weight:bold;" target="_blank" title="Click to know more about 10N">10N</a>,<br/> `Fgtf :." friction"=8N`</body></html> | |
| 36076. |
Automobiles are provided with shock absorbers why |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :whenthere <a href="https://interviewquestions.tuteehub.com/tag/isa-500762" style="font-weight:bold;" target="_blank" title="Click to know more about ISA">ISA</a> bumpon theroada suddenforceis transferredto thevehcile. Theshockabsorberprolongsthe periodof <a href="https://interviewquestions.tuteehub.com/tag/transfer-1425652" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSFER">TRANSFER</a> offorceon tothe <a href="https://interviewquestions.tuteehub.com/tag/bodyof-900362" style="font-weight:bold;" target="_blank" title="Click to know more about BODYOF">BODYOF</a> the rider. Vehiclesswithoutshocksabsorberswill humanthe bodydue tothisreason.</body></html> | |
| 36077. |
In question number 7,the temperatureof other interfaces(in .^(@)C) is |
| Answer» <html><body><p>`26.5, 0.5`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/27-298706" style="font-weight:bold;" target="_blank" title="Click to know more about 27">27</a>.5, <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>`<br/>`28.5, <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`<br/>`29.5, 3`</p>Solution :`T_(1) = 27-(Ht_(1))/(K_(1)A_(1)) = 27-0.52 = 26.48^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>= 26.5^(@)C` <br/> and `T_(2) = 0+ (Ht_(1))/(K_(1)A_(1)) = 0.52^(@)C`</body></html> | |
| 36078. |
A particle of mass 1 kg is executing SHM with an amplitude of 1m and time period pis. Calculate the kinetic energy of the particle at the moment when the displacement is 0.8m from mean position? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`omega= (2pi)/(T)= (2pi)/(pi)= 2s` we have `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>= omegasqrt(A^(2)-x^(2))= 2sqrt((<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)^(2)-(0.8)^(2))= 2 xx 0.6 = 1.2m//s` <br/> `"<a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a>"= (1)/(2)mv^(2)= (1)/(2)xx 1xx (1.2)^(2)= 0.72J`</body></html> | |
| 36079. |
Canthe givenheatenergybecompletely converted to workin a cyclicprocess? Ifnot ,whencan theheat cancompletelyconvertedto work ? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to first law of thermodynamics <a href="https://interviewquestions.tuteehub.com/tag/work-20377" style="font-weight:bold;" target="_blank" title="Click to know more about WORK">WORK</a> can be completely converted into heat. Since the <a href="https://interviewquestions.tuteehub.com/tag/system-1237255" style="font-weight:bold;" target="_blank" title="Click to know more about SYSTEM">SYSTEM</a> <a href="https://interviewquestions.tuteehub.com/tag/comes-2017383" style="font-weight:bold;" target="_blank" title="Click to know more about COMES">COMES</a> back to the initial stage, the <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in the internal energy is zero. In cyclic process, heat can flow in to system and heat flow out of the system. The net heat transferred to the system is equal to work done by the gas. <br/> `Q_("net") = Q_("in") -Q_("out")= W"(for a cyclic process)"`</body></html> | |
| 36080. |
Identify the pair whose dimensions are equal. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/torque-1422441" style="font-weight:bold;" target="_blank" title="Click to know more about TORQUE">TORQUE</a> and work<br/>stress and energy<br/>force and stress<br/>force and work</p>Answer :A</body></html> | |
| 36081. |
An object O is placed in front of a small plane mirror M_1 and a large convex mirror M_2 of focal length f. The distance between O and M_1 is x and the distance between M_1 and M_2 is y. The images of O formed by M_1 and M_2 coincide. The magnitude of f is |
| Answer» <html><body><p>`x-y`<br/>`(x^2-y^2)/(<a href="https://interviewquestions.tuteehub.com/tag/2y-301307" style="font-weight:bold;" target="_blank" title="Click to know more about 2Y">2Y</a>)`<br/>`(x^2+y^2)/(2y)`<br/>`(x^2+y^2)/(x+y)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36082. |
m_(1) and m_(2) are separated by distance 'r' M.I. of system about axis passing through centre of mass perpendicular to 'r' is ______ |
| Answer» <html><body><p>`m_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(m_(1)m_(2))/(m_(1)+m_(2))r^(2)`<br/>`(m_(1)+m_(2))/(m_(1)m_(2))r^(2)`<br/>`(m_(1)m_(2))/(r^(2))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36083. |
In measuring 'g' using a simple pendulum a student makes a positive error of 1% in length of pendulum and a negative error of 3% in the value of time period. Percentage error in measurement of value of g is |
| Answer» <html><body><p>0.02<br/>0.04<br/>0.07<br/>0.1</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 36084. |
When 8 droplets of water of radius 1 mm each combine into one, then the energy evolved is approximately equal to 7 xx 10^(-6)J. Find the value of x. |
| Answer» <html><body><p></p>Solution :`S=0.07 N//m, r=<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> mm =1 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(-3)m` <br/> Let R=radius of big drop `<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>/3 pi R^(3)=8 xx 4/3 <a href="https://interviewquestions.tuteehub.com/tag/pir-591537" style="font-weight:bold;" target="_blank" title="Click to know more about PIR">PIR</a>^(3)` <br/> `R=2r =2 xx 10^(-3)m` <br/> Surface area of bigger drop `=4piR^(2)` <br/> `=4pi xx (2 xx 10^(-3))^(2)` <br/> `=4pi xx 4 xx 10^(-6)m^(2)` <br/> `=16 pi xx 10^(-6) m^(2)` <br/> Surface area of 8 small drops `=8 xx 4pi xx (1 xx 10^(-3))^(2)` <br/> `=32 pi xx 10^(-6) m^(2)` <br/> `triangleA=` decreases in surface area <br/> `=(32 pi xx 10^(-6) -16pi xx 10^(-6))` <br/> `=16 pi xx 10^(-6) m^(2)` <br/> Energy evolved `="Surface Tesnion "xx " decreases in surface area"` <br/> `=0.06 xx 16pi xx 10^(-6)` <br/> `=0.96 pi xx 10^(-6)J=1pi xx 10^(-6) <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>`</body></html> | |
| 36085. |
Two discs of same moment of inertia rotating about their regular axis passing through centre and perpendicular to the plane of disc with angular velocities omega_(1) and omega_(2) . They are brought into contact face to face coinciding the axis of rotation . The expression for loss of energy during this process is |
| Answer» <html><body><p>`(1)/(4) I (omega_1 - omega_2)^(2)`<br/>`I (omega_(1) - omega_(2))^(2)`<br/>`(1)/(8) I (omega_(1) - omega_(2))^(2)`<br/>`(1)/(2) I (omega_(1)+ omega_(2))^(2)`</p>Solution :Initial angular momentum = `I omega_(1) + I omega_(2)` <br/> Let `omega` be angular speed of the combined system . <br/> Final angular momentum = `2 I omega` <br/> Final angular momentum = `2 I omega` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` According to conservation of angular momentum `I omega_(1) + I omega_(2) = 2 I omegaor omega = (omega_(1) + omega_(2))/(2)` <br/> Initial <a href="https://interviewquestions.tuteehub.com/tag/rotational-625601" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATIONAL">ROTATIONAL</a> <a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> , `E_(1) = (1)/(2) I (omega_(1)^(2) + omega_(2)^(2))` <br/> Final rotational kinetic energy <br/> `E_(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>) = (1)/(2) (2 I) omega^(2) = (1)/(2) (2I) ((omega_(1) + omega_(2))/(2))^(2) = (1)/(4) I (omega_(1) + omega_(2))^(2)` <br/> `therefore` Loss of energy `Delta E= E_(i) - E_(f)` <br/> `= (1)/(2) (omega_(1)^(2) + omega_(2)^(2))- (1)/(4) (omega_(1)^(2) + omega_(2) ^(2) + 2omega_(1) omega_(2))` <br/> `= (1)/(4) [ omega_(1)^(2) + omega_(2) ^(2) - 2 omega_(1) omega_(2)] = (1)/(4) (omega_(1) - omega_(2))^(2)`</body></html> | |
| 36086. |
A police jeep, approaching a right-angled intersection from the north, is chasing a speeding car that has turned the corner and is now moving straight east. When the jeep is 0.6km north of the intersection and the car is 0.8km to the east, the police determine with radar that the distance between them and the car is increasing at 20kmh^-1. If the jeep is moving at 60kmh^-1 at the instant of measurement, what is the speed of the car? |
| Answer» <html><body><p></p>Solution :We draw a diagram of the <a href="https://interviewquestions.tuteehub.com/tag/car-909011" style="font-weight:bold;" target="_blank" title="Click to know more about CAR">CAR</a> and jeep in the coordinate <a href="https://interviewquestions.tuteehub.com/tag/plane-1155510" style="font-weight:bold;" target="_blank" title="Click to know more about PLANE">PLANE</a>, using the positive <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>-axis as the eastbound highway and the positive y-axis as the northbound highway(figure). Let x be the position of car at time t. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_V01_C02_S01_052_S01.png" width="80%"/> <br/> y=position of jeep at time t, <br/> s=distance between can and jeep at time t. <br/> We assume x,y and s to be differentiable functions of t. <br/> `x=0.8km`, `y=0.6km`, `(dy)/(dt)=-60kmh^-1` <br/> `(ds)/(dt)=20kmh^-1` (`dy//dt` is negative because y is decreasing.) <br/> The variables are related as: <br/> `s^2=x^2+y^2` ...(i) (Pythagorean theorem) <br/> Differentiate Eq. (i) with respect to t, we get <br/> `(ds^2)/(dt)=(dx^2)/(dt)+(dy^2)/(dt)=(ds^2)/(ds)*(ds)/(dt)=2s(ds)/(dt)` <br/> Similarly, `(dx^2)/(dt)=(dx^2)/(dx)*(dx)/(dt)=2x(dx)/(dt)` <br/> and similarly `(dy^2)/(dt)=(dy^2)/(dy)*(dy)/(dt)=<a href="https://interviewquestions.tuteehub.com/tag/2y-301307" style="font-weight:bold;" target="_blank" title="Click to know more about 2Y">2Y</a>(dy)/(dt)` <br/> `2s(ds)/(dt)=2x(dx)/(dt)+2y(dy)/(dt)` <br/> Chain rule, `(ds)/(dt)=1/s(x(dx)/(dt)+y(dy)/(dt))` <br/> `=(1)/(sqrt(x^2+y^2))(x(dx)/(dt)+y(dy)/(dt))` <br/> Evaluate, with `x=0.8km`, `y=0.6km`, `dy//dt=-60kmh^-1`, <br/> `ds//dt=20kmh^-1`, and solve for `dx//dt`. <br/> `20=(1)/(sqrt(underbrace((0.8)^2+(0.6)^2)))(0.8(dx)/(dt)+(0.6)(-60))` <br/> `implies 20=0.8(dx)/(dt)-36implies(dx)/(dt)=(20+36)/(0.8)=70`</body></html> | |
| 36087. |
A sphere is rotating about a diameter |
| Answer» <html><body><p>The <a href="https://interviewquestions.tuteehub.com/tag/particles-1147533" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLES">PARTICLES</a> on the surface of the sphere do not have any <a href="https://interviewquestions.tuteehub.com/tag/linear-1074458" style="font-weight:bold;" target="_blank" title="Click to know more about LINEAR">LINEAR</a> accelerations<br/>The particles on the <a href="https://interviewquestions.tuteehub.com/tag/diameter-950836" style="font-weight:bold;" target="_blank" title="Click to know more about DIAMETER">DIAMETER</a> mentioned above do not have any linear acceleration<br/>Different particles on the surface have different <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> speeds <br/>All the particles on the surface have same linear speed.</p>Answer :B</body></html> | |
| 36088. |
Two particles A and B of equal mass m each are attached by a string of length 21 and initally placed over a smooth horizontal table in the position shown in figure Particle B is projected across the table with speed u perpendicular to AB as shown in figure. Find the velocities of the particles after the string becomes taut and the magnitude of the impulsive tension. |
| Answer» <html><body><p></p>Solution :When the string beomes taut , both particles move with equal velocity component v in the <a href="https://interviewquestions.tuteehub.com/tag/directon-2584492" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTON">DIRECTON</a> AB.. Perpendicular to AB. there is no impulse on either particle, velocity components in this direction are therefore <a href="https://interviewquestions.tuteehub.com/tag/unchanged-2316761" style="font-weight:bold;" target="_blank" title="Click to know more about UNCHANGED">UNCHANGED</a>. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_PHY_XI_V01_B_C04_SLV_030_S01.png" width="80%"/> <br/> Using conservation of momentum in the direction `AB.. 0 +m u sin <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@) = mv + mv` <br/> (or) `v = (sqrt3)/(4) u` therefore, just after the jerk <br/> (i) Velocity of mass `A = (sqrt3)/(4) u` along AB.<br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) Velocity of mass `B = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a> (( u cos 60 ^(@) ) ^(2) + (( sqrt3)/( 4) u )^(2)) = (sqrt7)/(4) u` <br/> in a direction inclined to AB. at an ange `tan ^(-1) (( u cos 60 ^(@) )/(v)) , i.e., at tan ^(-1) ((2)/(sqrt3)) `<br/> The magnitude of impulsive tension (J) can be calculated by considering the change of in momentum of one of the particles. <br/> For the mass A, in the direction `AB. , J = mv - 0 (or) J = (sqrt3)/(4) m u`</body></html> | |
| 36089. |
The density of a non-uniform rod of length 1 m is given by rho(x)=a(1+bx^(2)) where, a and b are constants and 0lexle1. The centre of mass of the rod will be at ……….. |
| Answer» <html><body><p>`(3(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>+b))/(4(3+b))`<br/>`(4(2+b))/(3(3+b))` <br/>`(3(3+b))/(4(2+b))` <br/>`(4(3+b))/(3(2+b))` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> = `rho(x)=a(1+bx^(2))` <br/> if `b=0`, then `rho(x)=a` = constant <br/> Hence, centre of mass will be at <a href="https://interviewquestions.tuteehub.com/tag/middle-1096062" style="font-weight:bold;" target="_blank" title="Click to know more about MIDDLE">MIDDLE</a> of the rod, `x=0.5m`. Only (A) gives 0.5.</body></html> | |
| 36090. |
Imagine a light planet is revolving round a very massive star in a circular orbit of radius R with a time period of revolution T. If the gravitational force of attraction between the star and planetis propostional to R^(-n), then T^(2) is propostional to |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(n+1)`<br/>`R^(n+2)`<br/>`R^(n-1)`<br/>`R^(n-2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36091. |
A body of mass M is being pulled by a string of mass m with a force P applied at one end. The force exerted by the string on the body is |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`(<a href="https://interviewquestions.tuteehub.com/tag/pm-1156895" style="font-weight:bold;" target="_blank" title="Click to know more about PM">PM</a>)/((M+m))`<br/>`(PM)/((M+m))`<br/>`Pm(M+m)`<br/>`(P)/((M-m))`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>=ma,a=(F)/(M)=(F)/(M+m), T=Ma`</body></html> | |
| 36092. |
One mole of an ideal gas at temperature T_1 expands according to the law (P/V) = constant. If thework done when the final temperature becomes T_2 is (xR/8) (T_2-T_1)then find x = ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a></body></html> | |
| 36093. |
A satellite S moving in an elliptical orbit around the earth the mass of satellite is very small compared to the mass of the earth then |
| Answer» <html><body><p>The acceleration of S is always directed <a href="https://interviewquestions.tuteehub.com/tag/towards-7269729" style="font-weight:bold;" target="_blank" title="Click to know more about TOWARDS">TOWARDS</a> centre of earth<br/>The angular momentum of S about the centre of earth changes in <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a>, but magnitude remains <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a><br/>The <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> mechanical energy of S varies <a href="https://interviewquestions.tuteehub.com/tag/periodically-7377676" style="font-weight:bold;" target="_blank" title="Click to know more about PERIODICALLY">PERIODICALLY</a> with time <br/>The linear momentum of S remains constant in magnitude</p>Answer :A</body></html> | |
| 36094. |
The rubber cord of a catapult has a cross sectional area 1"mm"^(2) and total unstretched length 10cm. It is stretched to 12cm and then released to project a missile of mass 5gm. Taking Y for rubber 5 xx 10^(8) "Nm"^(-2) calculate the velocity of projection.... |
| Answer» <html><body><p>`10 "ms"^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> "ms"^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> "ms"^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a> "ms"^(-1)`</p>Answer :B</body></html> | |
| 36095. |
A stone is projected from the ground with a velocity of 14ms^(-1) one second later it clears a wall 2m high. The angle of projection is (g = 10 ms^(-2)) |
| Answer» <html><body><p>`45^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a>^(@)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 36096. |
Consider that an ideal gas (n moles) is expanding in a process given by P=f(V), which passes through a point(V_(0),P_(0)). Show that the gas is absorbing heat at (P_(0),V_(0))if the slope of the curve P=f (V) is larger than the slope of the adiabat passing through (P_(0), V_(0)). |
| Answer» <html><body><p></p>Solution :Slope of `P=f(V)`, curve at `(V_(0) , P_(0))= f(V_(0))` <br/> Slope of <a href="https://interviewquestions.tuteehub.com/tag/adiabat-2400725" style="font-weight:bold;" target="_blank" title="Click to know more about ADIABAT">ADIABAT</a> at `(V_(0) P_(0))` <br/> `=k(-gamma) V_(0)^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>-gamma)= -gammaP_(0)//V_(0)` <br/> Now heat absorbed in the process P = f(V) <br/> `dQ = dU +dW = nC_(v)dT +PdV` <br/> Since `T=(1//nR) PV=(1//nR) V f(V)` <br/> `dT = (1//nR) [f(V)+Vf.(V)]dV` <br/> Thus `(dQ)/(dV)underset(V=V_(0))("" ) =(CV)/(R )[f(V_(0))+V_(0)f.(V_(0))]+f(V_(0))`<br/> `=[(1)/(gamma-1)+1]f(V_(0)) +(V_(0)f.(V_(0)))/(gamma-1)` <br/> `=(gamma)/(gamma-1)P_(0) +(V_(0))/(gamma-1)f.(V_(0))` <br/> Heat is absorbed when `dQ//dV <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> 0` when gas <a href="https://interviewquestions.tuteehub.com/tag/expands-2076032" style="font-weight:bold;" target="_blank" title="Click to know more about EXPANDS">EXPANDS</a>, that is when <br/> `gammaP_(0) +V_(0) f.(V_(0)) gt 0` <br/> `f.(V_(0)) gt -gammaP_(0)//V_(0)`</body></html> | |
| 36097. |
Two non -mixing liquids of densities rho and np (ngt1) are put in container . The height of each liquidis h.A solid cylinder of length L and density d is put in this container . The cylinder floats with its axis vertical and length PL(Plt1) in the denser liquid .The density d is equal to ....... |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`[2+(n+1)P]<a href="https://interviewquestions.tuteehub.com/tag/rho-623364" style="font-weight:bold;" target="_blank" title="Click to know more about RHO">RHO</a>`<br/>`[2+(n-1)P]rho`<br/>`[1+(n-1)P]rho`<br/>`[1+(n+1)P]rho`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Weight of cylinder `=Th_(1)+Th_(2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/aldg-3538528" style="font-weight:bold;" target="_blank" title="Click to know more about ALDG">ALDG</a>=(1-P)ALrhog+(<a href="https://interviewquestions.tuteehub.com/tag/pla-591662" style="font-weight:bold;" target="_blank" title="Click to know more about PLA">PLA</a>)nrhog`<br/>`therefored=(1-P)rho+Pnrho`<br/>`=rho-Prho+nPrho`<br/>`=rho[1-Prho(1-n)]`<br/>`=[1+(n-1)P]rho`<br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C10_E05_023_S01.png" width="80%"/></body></html> | |
| 36098. |
Kinetic theory of gases is based on the |
| Answer» <html><body><p> <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> <a href="https://interviewquestions.tuteehub.com/tag/picture-600284" style="font-weight:bold;" target="_blank" title="Click to know more about PICTURE">PICTURE</a> of matter<br/>nuclear picture<br/>electron picture<br/>none of the above </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 36099. |
Which of the following statements is true ? (i) A car of mass M is tied by one end of a massless rope of length 10 m. The other end of the rope is in the hands of a man of mass M. The entire system is on a smooth horizontal surface.The man is at x = 0 and the cart at x = 10 m. If the man pulls the cart by the rope, the man and the cart will meet at the point x = 5 m. (ii) Two spherical bodies of mass M and 5 M and radii R and 2 R, respectively , are released in free space with initial separation between their centers equal to 12 R. If they attract each other due to the gravitational force only , then the distance covered by the smaller body just before collision is 7.5 R. (iii) Two skaters A and B , having masses 40 kg and 60 kg , respectively stand facing each other 10 m apart on a horizontal smooth surface. They pull on a rope stretched between them , the distance covered by A, when skaters meet is 6 m. (iv) A ballon (mass M) is attached to light rope of length L. To the other end of the rope a boy (mass m) is hanging in air. The system is at rest. The distance travelled by the balloon (in downward direction) when the boy touches the ballon is (ML)/(M + m). |
| Answer» <html><body><p>`(i),(ii)`<br/>`(i) , (ii) ,(iii)`<br/>`(iii) ,(iv)`<br/>all of the above</p>Solution :Initially when the <a href="https://interviewquestions.tuteehub.com/tag/system-1237255" style="font-weight:bold;" target="_blank" title="Click to know more about SYSTEM">SYSTEM</a> is at rest (i.e.`v_(c.m.) = 0`) and the net <a href="https://interviewquestions.tuteehub.com/tag/external-981194" style="font-weight:bold;" target="_blank" title="Click to know more about EXTERNAL">EXTERNAL</a> force is zero , the location of center of mass is fixed. The particles will meet at center of mass is fixed. The particles will meet at center of mass (if the particles are treated as point masses). <br/> (i) `Mx_(1) = Mx_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) , x_(1) + x_(2) = <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> rArr x_(1) = x_(2) = (L)/(2) = 5 m` <br/> (ii) `Mx = 5 M( 9 R - x) rArr x = 7.5 R` <br/> `40 x = <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>(10 - x) rArr x = 6 m` <br/> (iv) `Mx = m(L - x) rArr x = (mL)/(M + m)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CPS_V01_C10_E01_018_S01.png" width="80%"/></body></html> | |
| 36100. |
Textbooks on scinence may give you a worng impression that studying science is dry and all too serious and that scientist are absent - minded introverts who never laugh or grin. This image of science and scientists is patentlyfalse. Scientists, like any other group of humans, have their share of humorists, and many have led their lives with a great sense of fun and adventure, even as they seriously pursued their scinetific work. Two great physicists of this genre are Gamow and Feynman. You will enjoy reading their books listed in the Bibliography. |
| Answer» <html><body><p></p>Solution :True, scientist like any other grup of <a href="https://interviewquestions.tuteehub.com/tag/humans-1033536" style="font-weight:bold;" target="_blank" title="Click to know more about HUMANS">HUMANS</a> have their <a href="https://interviewquestions.tuteehub.com/tag/share-25805" style="font-weight:bold;" target="_blank" title="Click to know more about SHARE">SHARE</a> of <a href="https://interviewquestions.tuteehub.com/tag/humorists-2720734" style="font-weight:bold;" target="_blank" title="Click to know more about HUMORISTS">HUMORISTS</a> , lively, jovial fun <a href="https://interviewquestions.tuteehub.com/tag/loving-2802340" style="font-weight:bold;" target="_blank" title="Click to know more about LOVING">LOVING</a> <br/> adventurists people. Some of them are absent minded introvent too. Students are advised to go through <br/> books by two great Physcists, Feynman and Gamow to <a href="https://interviewquestions.tuteehub.com/tag/realise-2977713" style="font-weight:bold;" target="_blank" title="Click to know more about REALISE">REALISE</a> this view.</body></html> | |