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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 35651. |
A bird is sitting at the bottom of a cage and, in this condition, the cage is weighed with the help of a spring balance. Now, the bird starts flying inside the cage. Will the reading of the balance change? |
| Answer» <html><body><p></p>Solution :The reading of the spring balance on the design of the bottom of the cage. <a href="https://interviewquestions.tuteehub.com/tag/suppose-656311" style="font-weight:bold;" target="_blank" title="Click to know more about SUPPOSE">SUPPOSE</a> the bottom of the cage is totally covered with a <a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> sheet. As <a href="https://interviewquestions.tuteehub.com/tag/soon-3049924" style="font-weight:bold;" target="_blank" title="Click to know more about SOON">SOON</a> as the bird <a href="https://interviewquestions.tuteehub.com/tag/starts-1224822" style="font-weight:bold;" target="_blank" title="Click to know more about STARTS">STARTS</a> flying, it flaps its wings. Hence, due to an extra thrust developed in each flapping acting on the bottom of the cage, the reading of the spring balance fluctuates. But, if the bottom of the cage is covered with a net, then the reading of the spring balance will decrease. Because the spring balance will then give the reading of the weight of the cage only.</body></html> | |
| 35652. |
Assertion In isochoric process p-V graph is straight line parallel to p-axis. Reason In isochoric process density p remains constant. |
| Answer» <html><body><p>If both Assertion and <a href="https://interviewquestions.tuteehub.com/tag/reason-620214" style="font-weight:bold;" target="_blank" title="Click to know more about REASON">REASON</a> are correct and Reason is the correct explanation of Assertion.<br/>If both Assertion and Reason are correct but Reason is not the correct explation os Assertion.<br/>If Assertionis true bur Reason is false.<br/>If Assertion is false but Reason is true.</p>Solution :In isohoric process, we increase <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> by <a href="https://interviewquestions.tuteehub.com/tag/increasing-1040633" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASING">INCREASING</a> temperature so assertion is true Since mass and volume does not change so density is <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a>.</body></html> | |
| 35653. |
A liquid is filled into a vessel at rest with a hole in the wall closed by a valve. It is filled with the liquid to a height .h. above the valve. What horizontal acceleration .a. should be given to the vessel, so that the liquid does not come out of hole valve is opened ? The base length of vessel is |
| Answer» <html><body><p>`(2gh)/(l)`<br/>`(gh)/(l)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/2gl-1837332" style="font-weight:bold;" target="_blank" title="Click to know more about 2GL">2GL</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/gl-468610" style="font-weight:bold;" target="_blank" title="Click to know more about GL">GL</a>)/(h)`</p>Answer :A</body></html> | |
| 35654. |
A uniform cube of slide a and mass m rests on a rough horizontal table. A horizontal force F is applied normal to one of the face at a point directly above the centre of the face, at a height 3a/4 above the base. What is the minimum value of F for which the cube begins to topple about an edge ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In the limiting cse normal <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> will <a href="https://interviewquestions.tuteehub.com/tag/pass-1148402" style="font-weight:bold;" target="_blank" title="Click to know more about PASS">PASS</a> through O. The cube will <a href="https://interviewquestions.tuteehub.com/tag/topple-3224023" style="font-weight:bold;" target="_blank" title="Click to know more about TOPPLE">TOPPLE</a> about O if torque of F ecceeds the torque of <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>.<br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C07_SLV_032_S01.png" width="80%"/><br/>`rArr F((3a)/(4))gt mg((a)/(2)), rArr F gt (2)/(3)mg`<br/>So, the minimum value of F is `(2)/(3)mg`.</body></html> | |
| 35655. |
A vertical glass tube, closed at the bottom contains mercury to a height of 100cm at 30°C. The height of mercury column at 50°C is. ( gamma for Hg = 1.8 xx 10^(-4)//""^(@) C, alpha_(g) = 8 xx 10^(-6)//""^(@) C) |
| Answer» <html><body><p>100.329 cm<br/>100.328 mm<br/>1003.28 cm<br/>10.0328 cm</p>Answer :A</body></html> | |
| 35656. |
A drop of water detaches itself from the exit of a tap when [sigma= surface tension of water, rho= density of water, R = radius of the tap exit, r = radius of the drop] |
| Answer» <html><body><p>` <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> gt (2/3(Rsigma)/(rho g))^((1)/(3))`<br/>` r gt (2/3(Rsigma)/(rho g))`<br/>`(2sigma)/(r ) gt "atmospheric pressure"`<br/>`r gt ((2)/(3)(R sigma )/(rho g)^(2/3))`<br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/upward-721781" style="font-weight:bold;" target="_blank" title="Click to know more about UPWARD">UPWARD</a> force due to surface tension <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P2_U07_C03_E15_032_S01.png" width="80%"/> <br/> `=Fsintheta=sigmaxx2piR sin theta` <br/> `=sigmaxx2piRxxR/r=(2pisigmaR^2)/(r )` <br/> Weight of the drop of water = <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> `=4/3 pi r^3 rho g` <br/> The drop will detach if, <br/> `4/3pi r^3 rho g gt (2pi sigma R^2)/(r ) or, r^4 gt (3 sigma R^2)/( 2 rho g)` <br/> `thereforer gt ((3)/(2) (sigma R^2)/(rho g))^(1/4)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> of the options are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a>.</body></html> | |
| 35657. |
The gravitationl potential due to a mass distribution isV = (A)/(sqrt(x^(2) + a^(2))), then the gravitational. Field is. |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/ay-386628" style="font-weight:bold;" target="_blank" title="Click to know more about AY">AY</a>)/((<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>^(2) + a^(2))^(1//2))`in the x-direction <br/>`(Ax)/((x^(2) + a^(2))^(3//2))` inx-direction <br/>`A(x^(2) + a^(2))` in y-direction <br/>2xA in z-direction </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 35658. |
Consider the 6 idential rods as shown in figure, the conductivity of x is double that of y. The temperatre of the junciton B is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)C`<br/>`40^(@)C`<br/>`50^(@)C`<br/>`20^(@)C`</p>Solution :(2) `K_(x) = 2 K, K_(y) = K` <br/> `R_(x) = R, R_(y) = 2 R` <br/> Let temperature of `B` is `theta`. <br/> Current will flow in the <a href="https://interviewquestions.tuteehub.com/tag/rod-1190628" style="font-weight:bold;" target="_blank" title="Click to know more about ROD">ROD</a> `DE` <br/> `i= (<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a> - theta)/(R ) = (theta - 10)/((<a href="https://interviewquestions.tuteehub.com/tag/3r-311113" style="font-weight:bold;" target="_blank" title="Click to know more about 3R">3R</a>)/(2))` <br/> `180 - 3 theta = 2 theta - 20` <br/> `5 theta = <a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a>` <br/> `theta = 40^(@)C` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CPS_V01_C22_E01_030_S01.png" width="80%"/><br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CPS_V01_C22_E01_030_S02.png" width="80%"/><br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CPS_V01_C22_E01_030_S03.png" width="80%"/></body></html> | |
| 35659. |
A small body of superdense material, whose mass is half the mass of the earth but where size is very small compared to the size of the earth. Starts from rest at a hight H lt lt Rabove the earth.s surface and radius the earth.s surface in time .t., then .t. is equal to |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2H//g)`<br/>`sqrt(H//g)`<br/>`sqrt(2H//3g)`<br/>`sqrt(4H//3g)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35660. |
What should be the length of a day on the earth when a body has no apparent weight at the equatorial region? (Radius of the earth = 6400 kg)or, should be the time period of rotation of the earth about its own axis so that a person on the equator feels weightless?(Equatorial radius = 6400 km,g = 9.8 mcdot s^(-2)) |
| Answer» <html><body><p></p>Solution :Weight mg of a body acts towards the centre of the earth. If the radius of the earth is R, at the <a href="https://interviewquestions.tuteehub.com/tag/equatorial-2617989" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATORIAL">EQUATORIAL</a> region, the centrifugal <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> experiencedby the body is `m omega^(2)` R, where, `omega` is the angular velocity of the earth about its own axis. <br/> When the centrifugal force acting on the body becomes equal and opposite ot the weight of the body, the apparent weight of the body becomes zero. In that case, <br/> mg = m`omega^(2)` R <br/> or,` "" omega = sqrt((g)/(R))` <br/> So, length of a day <br/> = time period of rotation of the earth (T) <br/>` = (2pi)/(omega) = 2pi sqrt((R)/(g)) = 2pi xxsqrt( (<a href="https://interviewquestions.tuteehub.com/tag/6400-330890" style="font-weight:bold;" target="_blank" title="Click to know more about 6400">6400</a> xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))/(9.8) ) =` 5077.6 s <br/> = 1 h 24.6 min.</body></html> | |
| 35661. |
A beam of light from a source L is incident normally on a plane mirror fixed at a certain distance x from the source. The beam is reflected back as a spot on a scale placed just above the source L, when the mirror is rotated through a small angle theta the spot of the light is found to move through a distance y on the scale. The angle theta is given by: |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>/y`<br/>`x/(<a href="https://interviewquestions.tuteehub.com/tag/2x-301182" style="font-weight:bold;" target="_blank" title="Click to know more about 2X">2X</a>)`<br/>`y/x`<br/>`x/(<a href="https://interviewquestions.tuteehub.com/tag/2y-301307" style="font-weight:bold;" target="_blank" title="Click to know more about 2Y">2Y</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 35662. |
The change in temperature of a substance , when a given quantity of heat is absorbed or rejected by it is characterised by the heat capacity. Define specific heat capacity, molar specific heat capacity at constant presssure and molar specific heat capacity at constant volume. Give the reason for using water as a coolant in automobile radiators. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :For definations, <br/> The reason for using water as a coolant is its <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> <a href="https://interviewquestions.tuteehub.com/tag/specific-1220917" style="font-weight:bold;" target="_blank" title="Click to know more about SPECIFIC">SPECIFIC</a> heat <a href="https://interviewquestions.tuteehub.com/tag/capacity-908575" style="font-weight:bold;" target="_blank" title="Click to know more about CAPACITY">CAPACITY</a>.</body></html> | |
| 35663. |
If the length of a cylinder is measured to be 4.28cm with an error of 0.01cm. The percentage error in the measured length is nearly |
| Answer» <html><body><p>0.004<br/>0.005<br/>0.002<br/>0.001</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35664. |
An open pipe made up of glass is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional 46 cm. What will be length of the air column above mercury in the tube now?(atm pressure =76 cm of HG) |
| Answer» <html><body><p>16cm<br/>22cm<br/>38cm<br/>6cm</p>Solution :Let a=cross sectional <a href="https://interviewquestions.tuteehub.com/tag/area-13372" style="font-weight:bold;" target="_blank" title="Click to know more about AREA">AREA</a> of the pipe (`i n cm^2`) <br/> So, initially volume of the above <a href="https://interviewquestions.tuteehub.com/tag/mercury-558950" style="font-weight:bold;" target="_blank" title="Click to know more about MERCURY">MERCURY</a> <br/> `V_1=<a href="https://interviewquestions.tuteehub.com/tag/8a-340116" style="font-weight:bold;" target="_blank" title="Click to know more about 8A">8A</a> cm^3`, pressure `=p_1 76 cmHg` <br/> When the top of the pipe is (46+8) or 54 cm higher than the outer mercury level [Fig.1.9] let x=rise of mercury level <a href="https://interviewquestions.tuteehub.com/tag/inside-1045864" style="font-weight:bold;" target="_blank" title="Click to know more about INSIDE">INSIDE</a> the pipe <br/> Then volume of air inside the pipe, `v_2=(54-x)a cm^3` <br/> and its pressure `p_2(76-x)cmHg` <br/> From Boyle.s law `p_1V_1=p_2V_2` <br/> or, `76 times 8a=(76-x)(54-x)a` <br/> or, `608=1404-130x+x^2` <br/> or, `x^2-130x+3496=0` <br/> or, `(x-38)(x-92)=0`, <br/> So x=38 cm or, x=92 cm <br/> The only physically meaningful solution is x=38 cm. Therefore the <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> of the air column in the pipe above mercury =`54-38=16 cm` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P2_U09_C01_E04_026_S01.png" width="80%"/></body></html> | |
| 35665. |
A ball released from a heightof 20m, hits the ground and rebounds to a height of 16m. The percentage loss of energy during collision is |
| Answer» <html><body><p>0.2<br/>0.4<br/>0.25<br/>0.75</p>Answer :A</body></html> | |
| 35666. |
The simple harmonic oscillation of a particle are according to the equation x=5os(2pit+(pi)/4) metre. Find the (i) displacement (ii) velcoity and (iii) acceleration at t=0. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Comparing with the general equation <br/> `x=A <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> (omegat +phi_(0))` <br/> Amplitude `A=5m` and `omega=2pi` <br/> (i) Displacement `x=5 cos (2pit+(pi)/4)` metre <br/>when `t=0, x=x_(0)=5"cos"(pi)/4=5xx1/(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))=3.54m` <br/> (ii) velocity `v=omega sqrt(A^(2)-x^(2))` <br/>when `t=0, v=v_(0)=omegasqrt(A^(2)-x_(0)^(2))` <br/> `=2pisqrt(5^(2)-(5/(sqrt(2)))^(2))=2pisqrt(25-25/2)` <br/> `=2pisqrt(25/2)=22.2ms^(-1)` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) Acceleration `a=-omega^(2)x` <br/> when `t=0=a=a_(0)=-omega^(2)-omega^(2)x_(0)`<br/> `=-(2pi)^(2)3.54=-4pi^(2)(3.54)^(2)` <br/> `:.a_(0)=139.42ms^(-2)`</body></html> | |
| 35667. |
Match lists I and II |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35668. |
A block is placed at the top of an inclined plane 5 m long. The plane makes an angle of 60^(@) with the horizontal. If the coefficient offriction between the wood and the plane is 0.3, find the time taken by the block of slide down the bottom of the plane. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`t=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/2s-301125" style="font-weight:bold;" target="_blank" title="Click to know more about 2S">2S</a>//a)=sqrt(2s(sintheta-mucostheta)<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)=sqrt(2xx5(sin60-0.3cos60)xx9.8)=1.19s`</body></html> | |
| 35669. |
A person fire bullet of 40 g w ith speed of 1200 m /s from his rifle. If rifle can w ithstant maximum recoil force of 144 N. How many bullet he can fire every second ? |
| Answer» <html><body><p>1<br/>2<br/><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a><br/>4</p>Solution :`F= <a href="https://interviewquestions.tuteehub.com/tag/32-144-273643" style="font-weight:bold;" target="_blank" title="Click to know more about 144">144</a> N` <br/> `m= 40 g= 40 xx10^(-3)kg` <br/>`v=1200 m//s` <br/> Momentumof one buller= mv <br/>Letpersone firen bulleteverysecond<br/> Totalmomentumof nbullet<br/> `=nmv ` <br/> <a href="https://interviewquestions.tuteehub.com/tag/recoil-1180224" style="font-weight:bold;" target="_blank" title="Click to know more about RECOIL">RECOIL</a> <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a><br/> NowF= <a href="https://interviewquestions.tuteehub.com/tag/mnv-3728708" style="font-weight:bold;" target="_blank" title="Click to know more about MNV">MNV</a> <br/> `n=(F)/(m v) = (144)/( 40 xx 10^(-3)xx 1200)` <br/> `= 3` <br/> Person can fire3 bulleteverysecond</body></html> | |
| 35670. |
What is gravitational force on a particl at the centre of earth ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a></body></html> | |
| 35671. |
The surface tension of a liquid decreases with a rise in |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/diameter-950836" style="font-weight:bold;" target="_blank" title="Click to know more about DIAMETER">DIAMETER</a> of container<br/>Temperature of the <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a><br/>Thickness of container <br/>Viscosity of the liquid </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 35672. |
For a concave mirror of focal length 20 cm, match the following |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(A) S, (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) P, (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) Q, (D) <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a></body></html> | |
| 35673. |
A black body emits radiations of maximum intensity at wavelength of 5000Å When the temperature of the body is 1227^(@)C. If the temperature of the body is increased by 1000^(@)C, the maximum intensity of emitted radiation would be observed at. . . . . . . |
| Answer» <html><body><p>`3000Å`<br/>`4000Å`<br/>`5000Å`<br/>`6000Å`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :According to Wien.s <a href="https://interviewquestions.tuteehub.com/tag/displacement-956081" style="font-weight:bold;" target="_blank" title="Click to know more about DISPLACEMENT">DISPLACEMENT</a> law, <br/> `lamda_(m)T=` constant <br/> `:.lamda_(m_(1))T_(1)=lamda_(m_(2))T_(2)` <br/> `:.lamda_(m_(2))=lamda_(m_(1))<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>(T_(1))/(T_(2))` <br/> `lamda_(m_(1))=5000Å` <br/> `T_(1)=1227^(@)C=1500K` <br/> `T_(2)=2227^(@)C=2500K` <br/> `lamda_(m_(2))=?`<br/> `=5000xx(1500)/(2500)` <br/> `:.lamda_(m_(2))=3000Å`</body></html> | |
| 35674. |
These questions consists of two statements each printed as Assertion and Reason. While answering these question you are required to choose any one of the following four responses Assertion A particle is thrown vertically upwards. If air resistance is taken into consideration then retardation in upward journey is more than the acceleration in downward journey. Reason Some mechanical energy is lost in the form of heat due to air friction. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(b) Retardation in upward <a href="https://interviewquestions.tuteehub.com/tag/journey-1062300" style="font-weight:bold;" target="_blank" title="Click to know more about JOURNEY">JOURNEY</a>, `a_(1)=(w+F)/(m)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V01_C05_E01_158_S01.png" width="80%"/> <br/> Acceleration in downward journey, `a_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=(w-F)/(m)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> a_(1) gt a_(2)`</body></html> | |
| 35675. |
These questions consists of two statements each printed as Assertion and Reason. While answering these question you are required to choose any one of the following four responses Assertion In the diagram shown in figure, string is massless and pulley is smooth, Net force on 1 kg block is (10)/(3)N. Reason Net force on both the blocks will be same. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :( <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) `F_("net")=ma` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V01_C05_E01_157_S01.png" width="80%"/><br/> Solving we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a>, `F_("net")=(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)/(3)N`</body></html> | |
| 35676. |
A refrigerator is to maintain eatables kept inside at 9^@ C. If room temperature is 36^@ C, calculate the coefficient of performance of refrigerator. |
| Answer» <html><body><p>10.4<br/>11.4<br/>12.4<br/>13.4</p>Solution :`T_1`=36+273 = 309 <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> <br/> `T_2`=9+273 =<a href="https://interviewquestions.tuteehub.com/tag/282-299641" style="font-weight:bold;" target="_blank" title="Click to know more about 282">282</a> K <br/> <a href="https://interviewquestions.tuteehub.com/tag/coefficient-920926" style="font-weight:bold;" target="_blank" title="Click to know more about COEFFICIENT">COEFFICIENT</a> of <a href="https://interviewquestions.tuteehub.com/tag/performance-11671" style="font-weight:bold;" target="_blank" title="Click to know more about PERFORMANCE">PERFORMANCE</a> of refrigerator , <br/> `beta=T_2/(T_1-T_2)=282/(309-282)=282/27` <br/> `therefore beta=10.4`</body></html> | |
| 35677. |
These questions consists of two statements each printed as Assertion and Reason. While answering these question you are required to choose any one of the following four responses Assertion A string has a mass m. If it is accelerated, tension is non-uniform and if it is not accelerated, tension is uniform. Reason Tension force is an electromagnetic force. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(d) <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> is non-uniform <a href="https://interviewquestions.tuteehub.com/tag/even-976335" style="font-weight:bold;" target="_blank" title="Click to know more about EVEN">EVEN</a> if <a href="https://interviewquestions.tuteehub.com/tag/string-11290" style="font-weight:bold;" target="_blank" title="Click to know more about STRING">STRING</a> is not <a href="https://interviewquestions.tuteehub.com/tag/accelerated-366473" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATED">ACCELERATED</a>. <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V01_C05_E01_156_S01.png" width="80%"/></body></html> | |
| 35678. |
These questions consists of two statements each printed as Assertion and Reason. While answering these question you are required to choose any one of the following four responses Assertion Static friction acting on a body is always greater than the kinetic friction acting on this body. Reason Coefficient of static friction is more than the coefficient of kinetic friction. |
| Answer» <html><body><p><br/></p>Solution :(a) Static friction varies between zero to a maximum limiting <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a>. <br/> Since `mu <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> cos <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>` is more, <a href="https://interviewquestions.tuteehub.com/tag/block-18865" style="font-weight:bold;" target="_blank" title="Click to know more about BLOCK">BLOCK</a> will remain stationary.</body></html> | |
| 35679. |
Sometimes positive charged particle comes from space towards earth with high velocity. Its deviation due to the magnetic field of earth will be: |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/towards-7269729" style="font-weight:bold;" target="_blank" title="Click to know more about TOWARDS">TOWARDS</a> north<br/>towards south<br/>towards <a href="https://interviewquestions.tuteehub.com/tag/west-1451899" style="font-weight:bold;" target="_blank" title="Click to know more about WEST">WEST</a> <br/>towards <a href="https://interviewquestions.tuteehub.com/tag/east-447972" style="font-weight:bold;" target="_blank" title="Click to know more about EAST">EAST</a></p>Solution :Positive charged <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> are deviated towards east in earth <a href="https://interviewquestions.tuteehub.com/tag/magnetic-551115" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNETIC">MAGNETIC</a> field</body></html> | |
| 35680. |
Find the depression of mensicus in the when a capillary tube of diameter 0.2 mm is dipped in a beaker containg mercury. density of mercury is 13.6xx10^(-3)Kgm^(-3), angle of contact is 130^(@) surface tension of mercury is 0.49Nm^(-1),g=9.8ms^(-2). |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :0.04726 m</body></html> | |
| 35681. |
These questions consists of two statements each printed as Assertion and Reason. While answering these question you are required to choose any one of the following four responses AssertionA body of mass 10 kg is placed on a rough inclined surface (mu=0.7). The surface is inclined to horizontal at angle 30^(@). Acceleration of the body down the plane will be zero. Reason Work done by friction is always negative. |
| Answer» <html><body><p><br/></p>Solution :( c) `mg <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> theta=10xx10xx(1)/(2)=<a href="https://interviewquestions.tuteehub.com/tag/50n-324238" style="font-weight:bold;" target="_blank" title="Click to know more about 50N">50N</a>` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a> mg <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta=0.7xx10xx10xx(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(3))/(2)=60.62N`</body></html> | |
| 35682. |
The magnitude of scalar and vector products of two vector are 48 sqrt(3) and 144 respectively. What is the angle between the two vectors ? |
| Answer» <html><body><p>`30^(@)` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)`<br/>`90^(@)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 35683. |
An eraser weighing 2N is pressed against the black board with a force of 5N. The coefficient of friction is 0.4. How much force parallel to the black board is required to slide the eraser upwards |
| Answer» <html><body><p>2N<br/>2.8N<br/>4N<br/>4.8N</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=f_(s)+<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>, f_(s)=mu_(s)mg`</body></html> | |
| 35684. |
A ray of light is incident on a glass sphere of refractive index 3//2 What should be the angle of incidence so that the ray which enters the sphere does not come out of the sphere? |
| Answer» <html><body><p>`tan^-1(2//3)`<br/>`sin^-1(2//3)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>^@`<br/>`cos^-1(1//3)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35685. |
These questions consists of two statements each printed as Assertion and Reason. While answering these question you are required to choose any one of the following four responses Assertion Block A is resting on one corner of a box as shown in figure. Acceleration of box is (2hati+2 hatj)ms^(-2). Let N_(1) is the normal reaction on block from vertical wall and N_(2) from ground of box. Then (N_(1))/(N_(2))=(1)/(6).(Neglect friction) Reason N_(1)=0, if lift is stationary. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) `N_(1)=ma_(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>)=2m` <br/> `N_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=m(g+a_(y))=12m` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>"" (N_(1))/(N_(2))=(1)/(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)`</body></html> | |
| 35686. |
These questions consists of two statements each printed as Assertion and Reason. While answering these question you are required to choose any one of the following four responses Assertion Two forces are acting on a rope lying on a smooth table as shown in figure. In moving from A to B, tension on string decrease from 2F to F. Reason Situation will becomes in determinant, if we take it a massless string. |
| Answer» <html><body><p><br/></p>Solution :(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) In <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> of <a href="https://interviewquestions.tuteehub.com/tag/massless-1088917" style="font-weight:bold;" target="_blank" title="Click to know more about MASSLESS">MASSLESS</a> string. <br/> `a=(2F-F)/(0)=oo`</body></html> | |
| 35687. |
These questions consists of two statements each printed as Assertion and Reason. While answering these question you are required to choose any one of the following four responses Assertion In the shown figure, tension T connected to the ceiling is 10 N lt T lt 20 N Reason System is not stationary. |
| Answer» <html><body><p><br/></p>Solution :(b) Let `T_(0)` is the <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> in the <a href="https://interviewquestions.tuteehub.com/tag/string-11290" style="font-weight:bold;" target="_blank" title="Click to know more about STRING">STRING</a> connecting the two <a href="https://interviewquestions.tuteehub.com/tag/blocks-21562" style="font-weight:bold;" target="_blank" title="Click to know more about BLOCKS">BLOCKS</a>. Then <br/> `T_(0)-10=1xxa` <br/> `therefore T_(0) gt <a href="https://interviewquestions.tuteehub.com/tag/10n-267183" style="font-weight:bold;" target="_blank" title="Click to know more about 10N">10N</a>, 20-T_(0)=2xxa` <br/> `therefore"" T_(0) lt20N`</body></html> | |
| 35688. |
These questions consists of two statements each printed as Assertion and Reason. While answering these question you are required to choose any one of the following four responses Assertion In the figure shown, block of mass m is stationary with respect to lift. Force of friction acting on the block is greater than mg sin theta. Reason If lift moves with constant velocity, then force of friction is equal to mg sin theta |
| Answer» <html><body><p><br/></p>Solution :(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `f-<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> sin theta=ma sin theta` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NEET_PHY_OBJ_V01_C05_E01_160_S01.png" width="80%"/> <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> "" f=m(g+a)sin theta <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> mg sin theta`</body></html> | |
| 35689. |
The velocity of a rain drop attains constant value because of ………….. . |
| Answer» <html><body><p>(a) surface <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a><br/>(b) upthrust of air<br/>(c) <a href="https://interviewquestions.tuteehub.com/tag/viscous-1447063" style="font-weight:bold;" target="_blank" title="Click to know more about VISCOUS">VISCOUS</a> <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> <a href="https://interviewquestions.tuteehub.com/tag/exerted-7272976" style="font-weight:bold;" target="_blank" title="Click to know more about EXERTED">EXERTED</a> by air<br/>air currents</p>Solution :viscous force exerted by air</body></html> | |
| 35690. |
These questions consists of two statements each printed as Assertion and Reason. While answering these question you are required to choose any one of the following four responses Assertion In the system of two blocks of equla masses as shown, the coefficient of friction between the blocks (mu_(2)) is less than coefficient of friction (mu_(1)) between lower block and ground. For all values of force F applied on upper block, lower block remains at rest. Reason Frictional force on lower block due to upper block is not sufficient to overcome the frictional force on lower block due to ground. |
| Answer» <html><body><p><br/></p>Solution :(a) `(f_(2))_("<a href="https://interviewquestions.tuteehub.com/tag/max-546895" style="font-weight:bold;" target="_blank" title="Click to know more about MAX">MAX</a>")=mu_(2) mg` <br/> `(f_(1))_("max")-mu_(1)(<a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a>)(g)` <br/> Since `(f_(1))_("max")gt (f_(2))_("max")` <br/> Lower <a href="https://interviewquestions.tuteehub.com/tag/block-18865" style="font-weight:bold;" target="_blank" title="Click to know more about BLOCK">BLOCK</a> will not move at all.</body></html> | |
| 35691. |
The length of a rectangular sheet is 1.5cm and breadth 1.203 cm. The area of the sheet is |
| Answer» <html><body><p>1.8045 `cm^2`<br/>`1.804 cm^2`<br/>`1.805 cm^2`<br/>`1.8 cm^2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35692. |
The Doppler effect is applicable for ………… |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/light-1073401" style="font-weight:bold;" target="_blank" title="Click to know more about LIGHT">LIGHT</a> <a href="https://interviewquestions.tuteehub.com/tag/waves-13979" style="font-weight:bold;" target="_blank" title="Click to know more about WAVES">WAVES</a> <br/>sound waves <br/><a href="https://interviewquestions.tuteehub.com/tag/space-649515" style="font-weight:bold;" target="_blank" title="Click to know more about SPACE">SPACE</a> waves <br/>both (a) and (b) </p>Solution :both (a) and (b)</body></html> | |
| 35693. |
Explain method for measurement of dimension of a planet or star. |
| Answer» <html><body><p></p>Solution :Angular diameter: From a point on surface of the earth angle subtended at diameter of the earth is called angular diameter `(alpha)`.<br/>Let diameter of the earth is d. <br/>As shown in figure from point of observation on surface of the earth a can be obtained at diametrically opposite point. <br/> <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> between the earth and planet (Star) is D. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C02_E01_065_S01.png" width="80%"/> <br/> `alpha=(d)/(D)` (radian) <br/> isused to <a href="https://interviewquestions.tuteehub.com/tag/measure-1091857" style="font-weight:bold;" target="_blank" title="Click to know more about MEASURE">MEASURE</a> diameter (d) of the planet. <br/> `I^(@)`(degree) =60. (<a href="https://interviewquestions.tuteehub.com/tag/min-548008" style="font-weight:bold;" target="_blank" title="Click to know more about MIN">MIN</a>) <br/> I. (min)=60.. (<a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>) <br/> `I^(@)=3600..` (sec)</body></html> | |
| 35694. |
Air is streaming past a horizontal aeroplane wing such that the speed of air is 120 m/s over the upper surface and 90 m/s at the lower surface, with respect to the plane. If the density of air is 1.3kg/m^(3) , find the difference in pressure between the top and bottom of the wing. If the wing is 10m long and has an average width of 2m, calculate the gross lift of the wing. |
| Answer» <html><body><p></p>Solution :Neglecting the difference in gravitational potential energy across the <a href="https://interviewquestions.tuteehub.com/tag/thickness-707636" style="font-weight:bold;" target="_blank" title="Click to know more about THICKNESS">THICKNESS</a> of the <a href="https://interviewquestions.tuteehub.com/tag/wing-744059" style="font-weight:bold;" target="_blank" title="Click to know more about WING">WING</a>, accoring to Bernouli.s <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a>, <br/>`P_(1)+(1)/(2)rhoV_(1)^(2)` i.e. `P_(1)-P_(2)=(1)/(2)rho(v_(2)^(2)-v_(1)^(2))` <br/>`=(1)/(2)(1.3 kg//m^(3))(120^(2)-<a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>^(2))(m//s)^(2)=4.1xx10^(3)<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>//m^(2)` <br/>Now, the net uplift due to the difference in pressure is `F_(up)=DeltaPxxA` <br/> `=(4.1xx10^(3)N//m^(3))(10xx2m^(2))=8.2xx10^(4)N` <br/>Note that this is not force of buoyancy (B) as B is a fluid static force.</body></html> | |
| 35695. |
A river isflowing from west to east at a speed of 5 m/s. A man on the south bank of the river capable of swimming it 10 m/s in still water is to swim across the river in shortest path. The direction which he should swim is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/120-270396" style="font-weight:bold;" target="_blank" title="Click to know more about 120">120</a>^(@)` opposite to the direction of <a href="https://interviewquestions.tuteehub.com/tag/flow-993213" style="font-weight:bold;" target="_blank" title="Click to know more about FLOW">FLOW</a> of <a href="https://interviewquestions.tuteehub.com/tag/river-1189947" style="font-weight:bold;" target="_blank" title="Click to know more about RIVER">RIVER</a><br/>`120^(@)` with the direction of flow of river<br/>`60^(@)` with the direction of flow of river<br/>perpendicular to the flow of the river</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 35696. |
Which one of the following fundamental forces in nature binds protons and neutrons in a nucleus? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/gravitational-476409" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITATIONAL">GRAVITATIONAL</a> force<br/>electromagnetic force<br/>strong <a href="https://interviewquestions.tuteehub.com/tag/nuclear-2474" style="font-weight:bold;" target="_blank" title="Click to know more about NUCLEAR">NUCLEAR</a> force<br/>weak nuclear force</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35697. |
(i) Determine the height 'h' to which water rises when capillary tube of radius 0.2 mm is dipped vertically in a beaker containg water (Surface tension of water = 7.0xx10^(-2)Nm^(-1) and angle of contact 0^(@)) (ii) Discuss what will happen if the capillary tube is now pushed down till its height above the surface of water is 4cm. Assume that the density of water is 1000kgm^(-3) and g is 10ms^(-2). |
| Answer» <html><body><p></p>Solution :i) <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> : `h=(2Scostheta)/(rrhog)` <br/> Angle of contact `theta=0^(@) therefore cos0^(@)=1` <br/> Surface tension `S=7xx10^(-2)Nm^(-1)` <br/> Density of water `d=1000kgm^(-3)` <br/> Acceleration due to gravity `g=10ms^(-2)` <br/> Radius of the tube `r=(0.2//1000)m` <br/> `therefore` Height `h=(<a href="https://interviewquestions.tuteehub.com/tag/2xx-1840186" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX">2XX</a>(7xx10^(-2))xx1)/(((0.2)/(1000))xx(1000)xx(10))=7xx10^(-2)mor7cm`. <br/> <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) However, when the capillary tube is pushed down till its height above the surface of water is 4 cm, the water rises up to 4 cm only and it will not over flow. In this <a href="https://interviewquestions.tuteehub.com/tag/special-632090" style="font-weight:bold;" target="_blank" title="Click to know more about SPECIAL">SPECIAL</a> case the angle of contact will change. <br/> `(h_(2))/(h_(1))=(costheta_(2))/(costheta_(1))impliescostheta_(2)=(h_(2))/(h_(1))costheta_(1)` <br/> here `h_(1)=7cm, h_(2)=4cm, theta_(1)=0^(@)` <br/> `costheta_(2)=cos^(-1)(0.5714)=55^(@)`</body></html> | |
| 35698. |
A square lead slab of side 50 cm and thickness 10 cm is subject to a shearing force (on its narrow face) of 9.0xx10^(4)N. The lower edge is riveted to the floor How much will the upper edge be displaced ? |
| Answer» <html><body><p></p>Solution :The leadslab is fixed and the force is appliedparallelto the narrowface as shownin figure. The areaof the face parallelto which this force is appliedis<br/> `A=50cm xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> =0.05 m^(2)` <br/><a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> the stressapplied is <br/>`=(9.4xx10^(4) //0.05)=1.80 xx 10^(6) N.m^(-2)` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_PMH_C10_SLV_036_S01.png" width="80%"/><br/>We know thatshearing strain `=(<a href="https://interviewquestions.tuteehub.com/tag/deltax-2570672" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAX">DELTAX</a>//L)="Stress"//G.` <br/> Therefore the dispalcement `Deltax=("Stress"xxL)//G` <br/> `=(1.8xx10^(6)xx0.5)//(5.6xx10^(9))=0.16mm`</body></html> | |
| 35699. |
Two cars 1 & 2 starting from rest are moving with speeds V_1 and V_2 m//s (V_1 gtV_2). Car 2 is ahead of can '1' by 'S' metres when the driver of car '1' sees car '2'. What minimum retardation should be given to cart avoid collision |
| Answer» <html><body><p>`(V_1 - V_2)/(S)` <br/>`(V_1+V_2)/(S)` <br/>`((V_1+V_2)^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2s-301125" style="font-weight:bold;" target="_blank" title="Click to know more about 2S">2S</a>)` <br/>`((V_1+V_2)^2)/(2S)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35700. |
The position of the particle is represented by y = ut-1/2 "gt"^2 (a) What is the force acting on the particle? (b) What is the momentum of the particle? |
| Answer» <html><body><p></p>Solution :To find the force, we need to find the <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> experienced by the particle.<br/>The acceleration is given by `a= (d^2 y)/(dt^2) " or" a = (dv)/(dt)` <br/>Here v= velocity of the particle in y direction ` v = (dy)/(dt) = u - "gt"` <br/>The momentum of the particle ` = mv = m ( u - "gt" )` <br/>`a = (dv)/(dt) = - g` <br/>The force <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a> on the object is given by <a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> = ma = -mg<br/>The negative <a href="https://interviewquestions.tuteehub.com/tag/sign-1207134" style="font-weight:bold;" target="_blank" title="Click to know more about SIGN">SIGN</a> implies that the force is acting on the negative y direction. This is exactly the force that acts on the object in projectile motion.</body></html> | |