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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 35601. |
A solid material is supplied with heat at a constant rate. The temperature of the material is changing with the heat input as shown in figure. Study the graph carefully and answer the following questions : (i) What do the horizontal regions AB and CD represent? (ii) if CD = 2AB, what do you infer ? (iii) The slope of OA gt the slope of BC. What does this indicate ? (iv) What does the slope DE represent ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) In the regions AB and CD the <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> of the material remains constant. So AB represents fusion and CD represents vapourisation. <br/>(ii) CD= 2AB or `Q_(4) = 2Q_(2)`, it shows that latent <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> of vapourisation is twice that of latent of fusion. <br/>(iii) Let `S_(1) and S_(2)` be the specific heats of <a href="https://interviewquestions.tuteehub.com/tag/solid-1216587" style="font-weight:bold;" target="_blank" title="Click to know more about SOLID">SOLID</a> and liquid states respectively, then <br/> `Q_(1) = mS_(1) Delta T_(1) " or " S_(1) = (1)/(m((Delta T_(1))/(Q_(1)) ) ) = (1)/( m xx "slope of OA")` <br/> Similarly `S_(2) = (1)/(m xx "slope of BC")` <br/> Since slope of OA `gt` slope of BC, `therefore S_(1) lt S_(2)`. <br/> (iv) If `S_(3)` is the specifice heat of vapour state (region DE),<br/> then `S_(2) = (1)/(m xx "slope of BC")` <br/> or Slope of DE= `(1)/(mS_(3)) = (1)/("heat capacity")`</body></html> | |
| 35602. |
An iron ball of diameter 6cm and is 0.01 mm too large to pass through a hole in a brass plate when the ball and plate are at a temperature of 20^(@) C. The temperature at which (both for ball and plate)the ball just pass through the hole is(alpha_("iron")= 12 xx 10^(-6)//1^(@)C, alpha_("brass") = 18 xx 10^(-6) //1^(@) C) |
| Answer» <html><body><p>`68^(@) C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/48-318016" style="font-weight:bold;" target="_blank" title="Click to know more about 48">48</a>^(@) C`<br/>`28^(@) C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>^(@) C`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 35603. |
The moon has no atmosphere. Why? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The escape velocity on the <a href="https://interviewquestions.tuteehub.com/tag/moon-563673" style="font-weight:bold;" target="_blank" title="Click to know more about MOON">MOON</a> is <a href="https://interviewquestions.tuteehub.com/tag/small-1212368" style="font-weight:bold;" target="_blank" title="Click to know more about SMALL">SMALL</a> `(2.38 kms^-1)`. The air molecules have thermal velocities greater than the escape velocity. Therefore, the air molecules escape away and cannot form atmosphere on the moon.</body></html> | |
| 35604. |
A straight rope of length 'L' is kept on a frictionless horizontal surface and a force 'F' is applied to one end of the rope in the direction of its length and away from that end. The tension in the rope at a distance 'l' from that end is |
| Answer» <html><body><p>`(F)/(l)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/lf-537024" style="font-weight:bold;" target="_blank" title="Click to know more about LF">LF</a>)/(l)`<br/>`(1-(l)/(L))F`<br/>`(1+(l)/(L))F`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`F-T=m_(1)a, T=m_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)a`</body></html> | |
| 35605. |
If A = 6.00i - 8.00j units, B= 8.00i + 3.00j units and C = 26.0i + 19.0 j units, determine a and b when a A + b B + C = 0 |
| Answer» <html><body><p>a = 0.9, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> `= -<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>.93`<br/>a= 0.9, b= 3.93<br/>a= 0.6, b `= -3`<br/>a= 0.4, b= 0.8</p>Answer :A</body></html> | |
| 35606. |
Acceleration of a particle changes when |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> of <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> changes<br/>magnitude of velocity changes<br/>either of above <br/><a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> is constant</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35607. |
The distance travelled by a body during last second of its total flight is d when the body is projected vertically up with certain velocity. If the velocity of projection is doubled, the distance travelled by the body during last second of its total flight is |
| Answer» <html><body><p>2 d<br/>d<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2d-300662" style="font-weight:bold;" target="_blank" title="Click to know more about 2D">2D</a>+(g)/(2)`<br/>`2d-(g)/(2)`</p>Answer :C</body></html> | |
| 35608. |
Is it possible for a constant to have dimensions? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/yes-749457" style="font-weight:bold;" target="_blank" title="Click to know more about YES">YES</a> , gravitationalconstanthas <a href="https://interviewquestions.tuteehub.com/tag/dimensions-439808" style="font-weight:bold;" target="_blank" title="Click to know more about DIMENSIONS">DIMENSIONS</a>.</body></html> | |
| 35609. |
A diatomic ideal gas is contained in a rigid container of volume V with walls of total inner surface area A, thickness d and thermal conductivity k. The gas initially is at temperature T_0 and pressure P_0. Find the pressure of the gas after a time t seconds if the surrounding temperature is T_s. All temperatures are in Kelvin scale. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`P_t (P_0)/(T_0) [(T_s -T_0) <a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>^(- <a href="https://interviewquestions.tuteehub.com/tag/alphat-2412786" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHAT">ALPHAT</a>)] " where " <a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> = (<a href="https://interviewquestions.tuteehub.com/tag/2ka-1837555" style="font-weight:bold;" target="_blank" title="Click to know more about 2KA">2KA</a>)/(2dR)`</body></html> | |
| 35610. |
Doppler's effect is exhibited by |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/sound-648690" style="font-weight:bold;" target="_blank" title="Click to know more about SOUND">SOUND</a> <a href="https://interviewquestions.tuteehub.com/tag/waves-13979" style="font-weight:bold;" target="_blank" title="Click to know more about WAVES">WAVES</a> only<br/><a href="https://interviewquestions.tuteehub.com/tag/light-1073401" style="font-weight:bold;" target="_blank" title="Click to know more about LIGHT">LIGHT</a> waves only<br/>both light and sound waves<br/>ultrasonics</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35611. |
To simulate car accidents, auto manufactures study the collisions of moving cars with mounted springs of different spring constants. Consider a typical simulation with a car of mass 1000 kg moving with a speed 18.0 km/h on a smooth road and coliding 6.25 xx 10^(3) N m^(-1). What is the maximum compression of the spring ? |
| Answer» <html><body><p></p>Solution :At <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> <a href="https://interviewquestions.tuteehub.com/tag/compression-20610" style="font-weight:bold;" target="_blank" title="Click to know more about COMPRESSION">COMPRESSION</a> `x_(m)`, the potentia energy V of the spring is equal to the kinetic K of the <a href="https://interviewquestions.tuteehub.com/tag/moving-548882" style="font-weight:bold;" target="_blank" title="Click to know more about MOVING">MOVING</a> car from the principle of conservation of <a href="https://interviewquestions.tuteehub.com/tag/mechanical-2780" style="font-weight:bold;" target="_blank" title="Click to know more about MECHANICAL">MECHANICAL</a> energy. <br/> `K=UrArr(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)mu^(2)=(1)/(2)kx_(m)^(2)rArrx_(m)=usqrt((m)/(k))rArrx_(m)=usqrt((m)/(k))` <br/> We obtain `x_(m)` = 2.00m</body></html> | |
| 35612. |
Two identical vessels A and B with frictionless pistons contain the same ideal gas at the same temperature and the same volume V. The masses of gas in A and B are m_(A) and m_(B) respectively. The gases are allowed to expand isothermally to the same final volume 3 V. The change in pressures of the gas in A and B are found to be Delta P and 1.5 Delta P respectively Then |
| Answer» <html><body><p>`9m_(A) = 4m_(B)`<br/>`3m_(A) = 2m_(B)`<br/>`2m_(A) = 3m_(B)`<br/>`4m_(A) = 8m_(B)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 35613. |
A bomb travelling in a parabolic path under the effect of gravity explodes in mid air. The centre of mass of fragments will |
| Answer» <html><body><p>Move <a href="https://interviewquestions.tuteehub.com/tag/vertically-3260386" style="font-weight:bold;" target="_blank" title="Click to know more about VERTICALLY">VERTICALLY</a> <a href="https://interviewquestions.tuteehub.com/tag/upwards-2318352" style="font-weight:bold;" target="_blank" title="Click to know more about UPWARDS">UPWARDS</a> and then vertically downwards<br/>Move vertically upwards<br/>Move in an irregular path<br/>Move in the parabolic path the unexploded bomb <a href="https://interviewquestions.tuteehub.com/tag/would-3285927" style="font-weight:bold;" target="_blank" title="Click to know more about WOULD">WOULD</a> have travelled.</p>Answer :D</body></html> | |
| 35614. |
A block of weight W rests on horizontal floor with coefficient of static friction mu. It is desired to make the block move by applying minimum amount of force. The angle thetafrom the horizontal at which the force should be applied and the magnitude F of the force is |
| Answer» <html><body><p>`theta = 0,<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> = <a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a> W` <br/>`theta = tan^(-1) , F = (mu W)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(1+mu^2))` <br/>`theta = tan^(-1) (1/mu) , F = (<a href="https://interviewquestions.tuteehub.com/tag/muw-2850330" style="font-weight:bold;" target="_blank" title="Click to know more about MUW">MUW</a>)/(sqrt(1+mu^2))` <br/>`theta = tan^(-1) ((mu)/(1+mu)),F= (muW)/(1+mu^2)`</p>Answer :B</body></html> | |
| 35615. |
In the Fig 7.89 shown , m_(2) = 2.5 kg, h = 1.5 m , the system is released fromrest at t = 0 and the mass m_(2) strikes ground at t = 0.82s . The system is placed in its initial position and a 1.2 kgmass is placed on top of the block of mass m_(1) . Released from rest , the mass m_(2) now strikes the ground 1.3 s later .Determine the mass m_(1)and the coefficient of kinetic friction between m_(1) and the shelf . |
| Answer» <html><body><p><br/></p>Solution :Initial acceleration of system when `1.<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` kg mass is not placedover `m_(1)` kg block <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_AM_PHY_C07_E01_010_S01.png" width="80%"/> <br/> `a_(0) = sqrt((2h)/(t^(2))) =sqrt((2 xx 1.5)/(0.82 xx 0.82))` <br/>As , `"" m_(2) <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> - T = m_(2)a_(0) ""…… (i) ` <br/> `T - mu m_(1) g = m_(1) a_(0) "" ...... (ii)` <br/> Adding Eqns. (i) and (ii) <br/> `g (m_(2) - mum_(1)) = a_(0) (m_(1) + m_(2)) "" ..... (iii)` <br/> Now when `1.2` kg mass is placed , then <br/> `a= sqrt((2h)/(t'^(2))) = sqrt((2 xx 1.5)/(1.3xx 1.3))` <br/> as `m_(2)g - T = m_(2)a "" ...... (iv)` <br/> `T - mu(m_(1) + 1.2)g = a [m_(2) + m_(1) + 1.2] "".....(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)` <br/> Adding Eqns. (iv) and (v) <br/>`m_(2)g - mu_(g) (m_(1) + 1.2) = a[m_(2) + m_(1) + 1.2] "" .... (vi)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/solving-1217196" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVING">SOLVING</a> Eqns. (iii) and (vi) , <br/> we get <a href="https://interviewquestions.tuteehub.com/tag/values-25920" style="font-weight:bold;" target="_blank" title="Click to know more about VALUES">VALUES</a> of `mu` and`m_(1)`.</body></html> | |
| 35616. |
A solid rubber ball of desity d and radius R falls through air. Assume that the air resistance acting on the ball is KRV, where V is velocity of the ball and K is a constant.The terminal velocity attained by the ball is (neglect buoyance) |
| Answer» <html><body><p>`4piR^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)dg//3K`<br/>`4piRdg//3K`<br/>`4piRd^(2)g//3K`<br/>None</p>Answer :A</body></html> | |
| 35617. |
A neutron moving with a certain kinetic energy collides head on with an atom of mass number A. The fractional kinetic energy retained by it is |
| Answer» <html><body><p>`(A-1)/(A+1)`<br/>`((A+1)/(A-1))^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/>`(A+1)/(A-1)`<br/>`((A-1)/(A+1))^(2)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35618. |
A capilllary glass tube of uniform bore contains a thread of mercury 1 m long at 0^(@)C. When temperature is raised to 100^(@)C, the thread is found to be 16.5 mm longer. If the coefficient of real expansion of mercury is =18.2 times 10^(-5@)C^(-1), then what will be the coefficient of linear expansion of glass? |
| Answer» <html><body><p><br/></p>Answer :`8.36 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> 10^(-6@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>^(-1)`</body></html> | |
| 35619. |
Which of the following phenomenon is used by the musicians to tune their musical instruments? |
| Answer» <html><body><p>Interferance<br/>Diffraction<br/>Beats<br/>Polarisation</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35620. |
Two wheels of M.I. 3kgm^(2) and 5kgm^(2) are rotating at a rate of 600 rpm and 800 rpm respectively in opposite directions. If they are coupled so as to rotated with the same axis of rotation , the resultant speed of rotation (in rpm) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/725-1918448" style="font-weight:bold;" target="_blank" title="Click to know more about 725">725</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/850-339521" style="font-weight:bold;" target="_blank" title="Click to know more about 850">850</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/420-316321" style="font-weight:bold;" target="_blank" title="Click to know more about 420">420</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/630-330562" style="font-weight:bold;" target="_blank" title="Click to know more about 630">630</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35621. |
A particle is given an initial velocity of 20m/s. acceleration of the particle changes with time and its variation is shown in the following figure. |
| Answer» <html><body><p><br/></p>Solution :Area under <a href="https://interviewquestions.tuteehub.com/tag/theacceleration-706313" style="font-weight:bold;" target="_blank" title="Click to know more about THEACCELERATION">THEACCELERATION</a> - time graph representsthe change in <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a>. Area above the time axis is takenas positive andbelow the timeaxis , it is taken as negative . To acquireinitial velocityagain ,changein velocitymust be zero . Ifwe canextend the graph for 6s then we can see that <a href="https://interviewquestions.tuteehub.com/tag/totalarea-3225740" style="font-weight:bold;" target="_blank" title="Click to know more about TOTALAREA">TOTALAREA</a> becoms zero <a href="https://interviewquestions.tuteehub.com/tag/dueto-960654" style="font-weight:bold;" target="_blank" title="Click to know more about DUETO">DUETO</a> equal amounts of positive and negative areas. Henceparticle acquires <a href="https://interviewquestions.tuteehub.com/tag/back-389278" style="font-weight:bold;" target="_blank" title="Click to know more about BACK">BACK</a> its initialvelocity att = 6s. <br/> Answer is 6 .</body></html> | |
| 35622. |
Which of the following examples represent periodic motion? An arrow released from a bow. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :It is not a <a href="https://interviewquestions.tuteehub.com/tag/periodic-598580" style="font-weight:bold;" target="_blank" title="Click to know more about PERIODIC">PERIODIC</a> <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a>.</body></html> | |
| 35623. |
If the length of a cylinder is L = (4.00 +-0.01)cm radius r = (0.250 +- 0.001)cm and mass m = (6.25+- 0.01)g . Calculate the percentage error in determination of density. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Density of cylinder, `rho=(("<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a>")/("volume")V)=(m)/(pir^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>) ( :. V=pi r^(2)l)` <br/> `:.` Relative <a href="https://interviewquestions.tuteehub.com/tag/error-25548" style="font-weight:bold;" target="_blank" title="Click to know more about ERROR">ERROR</a> in `rho=(Delta rho)/(rho)=(Deltam)/(M)+2(Deltar)/(r)+(Deltal)/(l)` <br/> `=(0.01)/(6.25)+2xx(0.001)/(0.250)+(0.01)/(4.00)` <br/> `=0.0016+0.008+0.0025` <br/> `=:.(Delta rho)/(rho)=0.0121` <br/> `:.` The percentage error in `rho=0.0121xx100=1.2%`</body></html> | |
| 35624. |
Three copper blocks of masses M_1, M_2 and M_3 kg respectively are brought into thermal contact till they reach equilibrium. Before contact they were at T_1, T_2, T_3 (T_1 gt T_2 gt T_3). Assuming there is no heat loss to the surroundings, the equilibrium temperature T is (s is specific heat of copper) |
| Answer» <html><body><p>`T=(T_1+T_2+T_3)/<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`<br/>`T=(M_1T_1+M_2T_2+M_3T_3)/(M_1+M_2+M_3)`<br/>`T=(M_1T_1+M_2T_2+M_3T_3)/(3(M_1+M_2+M_3))` <br/>`T=(M_1T_1s+M_2T_2s+M_3T_3s)/(M_1+M_2+M_3)` </p>Solution :Suppose temperature of <a href="https://interviewquestions.tuteehub.com/tag/system-1237255" style="font-weight:bold;" target="_blank" title="Click to know more about SYSTEM">SYSTEM</a> in <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a> is T and `T_1 gt T_2 gt T_3`and suppose, `T_1 <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> T, T_2 lt T`and `T_3 gt T`. Block does not lost heat in sink hence heat lost by `M_3`= Heat gained by `M_1` + heat gained by `M_2` <br/> `M_3 s(T_3-T)=M_1s(T-T_1)+M_2s(T-T_2)` <br/> `therefore M_3sT_3-M_3sT=M_1sT-M_1sT_1 + M_2sT-M_2sT_2` <br/> `therefore M_3sT_3+M_1sT_1 + M_2sT_2 = M_1sT+ M_2sT+M_3sT` <br/> `therefore M_1T_1+M_2T_2+M_3T_3 =[M_1+M_2+M_3]T` <br/> `T=(M_1T_1+M_2T_2+M_3T_3)/(M_1+M_2+M_3)`</body></html> | |
| 35625. |
Two point size bodies of same mass are knotted to a horizontal string one at the end, and the other at the mid point of it. The string is rotated in horizontal plane with the other end as centre. If T is tension in the string between centre of circles and first body then the tension in the string between the two bodies is |
| Answer» <html><body><p>`T//2`<br/><a href="https://interviewquestions.tuteehub.com/tag/2t-301164" style="font-weight:bold;" target="_blank" title="Click to know more about 2T">2T</a><br/>`2T//3`<br/>`3T//2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35626. |
What is rolling motion? |
| Answer» <html><body><p></p>Solution :(i) It is the combination of pure translational and pure rotational motion. <br/> (I) The rolling motion is the most commonly observed motion in daily life. The motion of wheel is an example of rolling motion. (II) Round objects like ring, disc, sphere etc. are most suitable for rolling. Let us study the rolling of a disc on a horizontal surface. Consider a point P on the edge ofthe disc. (III) While rolling, the point, undergoes translational motion along with its center of mass and rotational motion with respect to its center of mass. <br/> (ii) (I) If the radius of the rolling object is <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>, in one full rotation, the center of mass is displaced by `2 pi R` (its circumference). <br/> (II) Not only the center of mass, but all the points on the disc are displaced by the same `2 pi R` after one full rotation. The only difference is that the center of mass takes a straight path, but, all the other points. <br/> (III) Undergo a path which has a combination of the translational and rotational motion. Especially the point on the edge undergoes a path of a cycloid. <br/> (IV) As the center of mass takes only a straight line path, its velocity `v_(CM)` is only translational velocity `v_("<a href="https://interviewquestions.tuteehub.com/tag/trans-1425477" style="font-weight:bold;" target="_blank" title="Click to know more about TRANS">TRANS</a>") (v_(CM) = v_("TRANS"))`. All the other points have two <a href="https://interviewquestions.tuteehub.com/tag/velocities-1444510" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITIES">VELOCITIES</a>. One is the translational velocity `v_("TRANS")`, (which is <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> the velocity of center of mass) and the other is the rotational velocity `v_("ROT") (v_("ROT") = r omega)`. <br/> (v) Here, r is the distance of the point from the center of mass and `omega` is the angular velocity. The rotational velocity `v_("ROT")` is perpendicular to the instantaneous position vector from the center of mass. <br/> (vi) The resultant of these two velocities is v. This resultant velocity v is perpendicular to the position vector from the point of contact of the rolling ojbect with the surface on which it is rolling as <a href="https://interviewquestions.tuteehub.com/tag/shown-1206565" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWN">SHOWN</a> in Figure. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V01_C05_E16_007_S01.png" width="80%"/></body></html> | |
| 35627. |
The velocity of a particle of mass 10^(-2)kg is given as vecv=(2xhatu+3yhatj+4zhatk) m/sec (where x, y and z are in meter). The amount of work done by applied force in displacing a particle from (1m, 2m, 0) to (-1m, 3m, 1m) is ….. |
| Answer» <html><body><p>0.31 joule<br/>0.24 joule<br/>0.48 joul<br/>0.72 joule</p>Answer :A</body></html> | |
| 35628. |
Sound waves of wavelength greater than that of audible sound are called ………. |
| Answer» <html><body><p>infrasonic <a href="https://interviewquestions.tuteehub.com/tag/waves-13979" style="font-weight:bold;" target="_blank" title="Click to know more about WAVES">WAVES</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/ultrasonic-719610" style="font-weight:bold;" target="_blank" title="Click to know more about ULTRASONIC">ULTRASONIC</a> waves <br/><a href="https://interviewquestions.tuteehub.com/tag/sonic-3814279" style="font-weight:bold;" target="_blank" title="Click to know more about SONIC">SONIC</a> waves <br/><a href="https://interviewquestions.tuteehub.com/tag/seismic-2265344" style="font-weight:bold;" target="_blank" title="Click to know more about SEISMIC">SEISMIC</a> waves </p>Solution :infrasonic waves</body></html> | |
| 35629. |
A ball is fallen freely from top of tower of height 100 m and another ball is thrown upwards with 50 m/s at the same time when they will cross each other ? (g = 10 m//s^(2)) |
| Answer» <html><body><p>1 s <br/>2 s <br/><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> s <br/><a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> s </p>Solution :For the ball falling freely `v _(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>) = 0, d = 100 m` <br/> `therefore` <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> covered in .t. time <br/> `d _(1) = v _(0)t + 1/2 g t^(2)` <br/> `d _(1) = 0 + 1/2 (10) t ^(2) = 5t ^(2) ""…(1)` <br/> Initial velocity of the ball thrown upwards is `v _(0).=50m//s` and it meets the first ball at `(100 -d _(1)`)m distance <br/> `therefore 100 -d _(1) = v _(0) .t = 1/2 g t ^(2)` <br/> `therefore 100 - d _(1) = 50 t - 1/2 (10) t ^(2) `<br/> `therefore 100 -d _(1) = 50 t -5t ^(2)` <br/> From equation (1), <br/> `therefore 100-5t ^(2) = 59 t - 5t ^(2)` <br/> `therefore 50 t = 100` <br/> `therefore t = (100)/(50)` <br/> `therefore t =2s`</body></html> | |
| 35630. |
Give the quantities for which the following are the dimensions: M^(1)T^(-2) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a></body></html> | |
| 35631. |
A particle performing uniform circular motion has angular momentum Lwrt centre. If its angular frequency is doubled and its kinetic energy is haved, then the new angular momentum is |
| Answer» <html><body><p>`L//4`<br/><a href="https://interviewquestions.tuteehub.com/tag/2l-300409" style="font-weight:bold;" target="_blank" title="Click to know more about 2L">2L</a> for `v_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)gesqrt(5gl)` <br/><a href="https://interviewquestions.tuteehub.com/tag/4l-318786" style="font-weight:bold;" target="_blank" title="Click to know more about 4L">4L</a><br/>`L//2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35632. |
The bobof mass50 gm of a pendulumis released from a horizontal position A as shownin the figure ..If the lengthof the pendulumis1.5 m , what is itskinetic energyat the lowermostpointB ? (g = 10 m/(s^(2))) |
| Answer» <html><body><p>`2.5 xx10^(-11)` J <br/>`15 xx10^(-1) J ` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/5xx10-1901302" style="font-weight:bold;" target="_blank" title="Click to know more about 5XX10">5XX10</a>^(-1) J ` <br/>`7.5 xx10^(-1) J ` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Potential energy of a bob of pendulum at pointA = K.E of bob at <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> B <br/>` :. ` K.E of bob at `B(1/2 <a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(2)) = <a href="https://interviewquestions.tuteehub.com/tag/mgh-1095458" style="font-weight:bold;" target="_blank" title="Click to know more about MGH">MGH</a> ` <br/> ` = 50 xx10^(-3) xx10 xx1/5` <br/> `= 7.5 xx10^(-1) J `</body></html> | |
| 35633. |
The sample of gas expands from v_1to v_2The amount of workdone by the gas is greatest,when the expansion is, |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/adiabatic-849856" style="font-weight:bold;" target="_blank" title="Click to know more about ADIABATIC">ADIABATIC</a> <br/>isobaric <br/>isothermal <br/> <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> in all <a href="https://interviewquestions.tuteehub.com/tag/cases-910165" style="font-weight:bold;" target="_blank" title="Click to know more about CASES">CASES</a> </p>Solution :isothermal</body></html> | |
| 35634. |
A body of mass 1 kg makes an elastic collision with another body at rest and continues to move in the original direction after collision with a velocity equal to 1/5th of its original velocity. Find the mass of the second body. |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)<a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>`<br/>`(3)/(2)kg`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)/(2)kg`<br/>`(2)/(5)kg` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 35635. |
When a rod of length 2.5 m and radius 10 mm is subjected to a force the elongation is 3mm and decrease of radius is 0.0025 mm. Find poisson.s ratio of the material of the rod. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`0.2`</body></html> | |
| 35636. |
A satellite moves around the earth in a circular orbit with speed V. If 'm' is the mass of the satellite, its potential energy is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`mv^(2)`<br/>`mv^(2)`<br/>`-mv^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 35637. |
If the zero of potential energy is at infinity, the total energy of an orbiting satellite is negative of its kinetic/potential energy. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a>,</body></html> | |
| 35638. |
The motor of an engine is rotating about its axis with angular velocity of 120 r.p.m. it comes to rest in 10s, after being switched off. Assuming constant deceleration, calculate the number of revolutions made by it before coming to rest. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Here, `omega_(0)=120` r.p.m `=<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` r.p.s `=4pirads^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` <br/> `omega=0` and `t=10s` `omega=omega_(0)+at` <br/> `0=4pi+axx10` or `a=-0.4pirads^(-2)` <br/> Also, the angle covered by the motor, <br/> `theta=omega_(0)t+(1)/(2)at^(2)` <br/> `:. theta=4pixx10+(1)/(2)xx(-0.4pi)xx10^(2)=40pi-<a href="https://interviewquestions.tuteehub.com/tag/20pi-1822115" style="font-weight:bold;" target="_blank" title="Click to know more about 20PI">20PI</a>` <br/> `=20pi`rad <br/> Hence, the number of revoluations <a href="https://interviewquestions.tuteehub.com/tag/completed-409685" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLETED">COMPLETED</a> <br/> `n=(theta)/(2pi)=(20pi)/(2pi)=10`</body></html> | |
| 35639. |
A particle is moving along a circular path. The angular velocity, linear velocity, angular acceleration and centripetal acceleration of the particle at any instant are vec(omega), vecv, veca, veca_(c) respectively. Which of the following relation is not correct ? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a> omega <a href="https://interviewquestions.tuteehub.com/tag/bot-25566" style="font-weight:bold;" target="_blank" title="Click to know more about BOT">BOT</a> vec v`<br/>`vec omega bot vec a`<br/>`vec omega bot vec a_(c)`<br/>`vec v bot vec a_(c)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 35640. |
block of silver of mass 4 kg hanging from a string is immersed in a liquid of relative density 0.72 If yolative density of silver is 10, then tension in the string will be a |
| Answer» <html><body><p>`37.12N`<br/>42N<br/>73N<br/>21N</p>Answer :A</body></html> | |
| 35641. |
A geostationary satellite is orbiting the earth at a height of 6R above the surface of the earth. The time period of another satellite at a height of 2.5 R from the surface of the earth is |
| Answer» <html><body><p>6hr<br/>8hr<br/>12 <a href="https://interviewquestions.tuteehub.com/tag/hr-25457" style="font-weight:bold;" target="_blank" title="Click to know more about HR">HR</a><br/>`6sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` hr</p>Answer :D</body></html> | |
| 35642. |
The phase of simple harmonic motion at t = 0 is called |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/phase-22748" style="font-weight:bold;" target="_blank" title="Click to know more about PHASE">PHASE</a> <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> phase <br/><a href="https://interviewquestions.tuteehub.com/tag/epoch-973439" style="font-weight:bold;" target="_blank" title="Click to know more about EPOCH">EPOCH</a> <br/>All the above</p>Answer :D</body></html> | |
| 35643. |
A train is moving with a uniform velocity of (2 hat(i)- hat(j)+ hat(k)) ms^(-1). If the force required to overcome friction is (hat(i)- 3hat(j) + 2hat(k))N, the power of the engine is |
| Answer» <html><body><p>7W<br/>10W<br/>13W<br/>15W</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35644. |
Out of the following graphs the graph that represents the variaion of the value of gravitational potential V, with distance r from the centre, due to a hollow spherical shell is |
| Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C09_E01_089_O01.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C09_E01_089_O02.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C09_E01_089_O03.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_B_C09_E01_089_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 35645. |
Two moles of air, when heated through10 K expand by an amount of 1.66 xx 10^(-3) m^(3)under a constant pressure of 10^(5) N//m^(2). If C_(v)=20.81 J/mole K, then C_(p)is, |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/29-299821" style="font-weight:bold;" target="_blank" title="Click to know more about 29">29</a>. 11J/mole K<br/>19.11 J/mole K<br/>32.11 J/mole k<br/>19.11J/mole k</p>Answer :A</body></html> | |
| 35646. |
State the expressions for the moment of inertia of a circular ring and a circular dise about an axis passing through its centre and perpendicular to its plane. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :MO.I. of circular ring about an <a href="https://interviewquestions.tuteehub.com/tag/axis-889931" style="font-weight:bold;" target="_blank" title="Click to know more about AXIS">AXIS</a> passing through its <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a> and perpendicular to its plane is `I=<a href="https://interviewquestions.tuteehub.com/tag/mr-549185" style="font-weight:bold;" target="_blank" title="Click to know more about MR">MR</a>^(2)` <br/>M.O.I. of a circular disc about an axis passing through its centre centre and perpendicular to its <a href="https://interviewquestions.tuteehub.com/tag/plan-25498" style="font-weight:bold;" target="_blank" title="Click to know more about PLAN">PLAN</a> is `I=(MR^(2))/(2)`</body></html> | |
| 35647. |
cylinder of capacity 20 litres is filled with H_2 gas. The total average kinetic energy of translatory motion of its molecules is 1.5 xx 10^(5) J. The pressure of hydrogen in the cylinder is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2xx10-1840192" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX10">2XX10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)N//m^(2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/3xx10-1865443" style="font-weight:bold;" target="_blank" title="Click to know more about 3XX10">3XX10</a>^(6)N//m^(2)`<br/>`4xx10^(6)N//m^(2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/5xx10-1901302" style="font-weight:bold;" target="_blank" title="Click to know more about 5XX10">5XX10</a>^(6)N//m^(2)`</p>Answer :D</body></html> | |
| 35648. |
The wettability of a suface by a liquid depends primarily on: |
| Answer» <html><body><p>viscosity<br/><a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> tension<br/>density<br/>angle of <a href="https://interviewquestions.tuteehub.com/tag/contact-25916" style="font-weight:bold;" target="_blank" title="Click to know more about CONTACT">CONTACT</a> between the surface and the liquid</p>Answer :D</body></html> | |
| 35649. |
State Pascal's lae in fluids. |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C07_E01_049_S01.png" width="80%"/> <br/><a href="https://interviewquestions.tuteehub.com/tag/pascal-596772" style="font-weight:bold;" target="_blank" title="Click to know more about PASCAL">PASCAL</a>'s law states that if the effect of gravity can be generated then the pressure in a fluid in equilibrium is the same everywhere.<br/> <a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> us consider any two points A and B inside the fluid imagined. A cylinder is such that points A and B lie at the centre of the circular surface at the <a href="https://interviewquestions.tuteehub.com/tag/top-1422115" style="font-weight:bold;" target="_blank" title="Click to know more about TOP">TOP</a> and bottom of the cylinder. Let the fluid inside this cylinder be in equilibrium under the action of forces from <a href="https://interviewquestions.tuteehub.com/tag/outside-1143075" style="font-weight:bold;" target="_blank" title="Click to know more about OUTSIDE">OUTSIDE</a> the fluid. The forces <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a> on the circular, top and bottom surfaces are perpendicular to the forces acting on the cylindrical surface. Therefore the forces acting on the faces at A and B are equal and opposite and hence add to zero.<br/>As the areas of these two faces are equal, pressure at A = pressure at B.<br/>This is the proof of Pasccal's law when the effect of gravity is not taken into account.</body></html> | |
| 35650. |
At what temperature will be r.m.s velocity of hydrogen be double of its value at NTP? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`819^0` <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |