Explore topic-wise InterviewSolutions in Class 11.

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.

35701.

A spring gun of spring constant 90 N cm^(-1) is compressed 12 cm by a ball of mass 16 g. If the trigger is pulled, the velocity of the ball is

Answer» <html><body><p>`50 m s^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`40 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)`<br/>`60 m s^(-1)`<br/>`90 ms^(-1)`</p>Solution :Here , `m = 16 g = 16 xx 10^(-3) kg` <br/>`k = 90 N cm^(-1) = 90 xx 10 Nm^(-1)` <br/>`x = 12 cm = 12 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) m` <br/> According to the law of <a href="https://interviewquestions.tuteehub.com/tag/conservation-929810" style="font-weight:bold;" target="_blank" title="Click to know more about CONSERVATION">CONSERVATION</a> of energy, <br/> `1/2 mv^2 = 1/2 kx^2 " or " <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>^2 = (kx^2)/(m)` <br/> or `v = xsqrt(k/m) (12 xx 10^(-2)m) sqrt((90 xx 100 Nm^(-1))/(16 xx 10^(-3) kg)) = 90 ms^(-1)`. <br/> Thus the velocity of the ball `90 ms^(-1)`.</body></html>
Discussion
35702.

The distance travelled by a body moving along a line in time t is proportional to t^3 . The acceleration - time (a, t) graph for the motion of the body will be

Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_APP_E02_048_O01.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_APP_E02_048_O02.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_APP_E02_048_O03.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP1_APP_E02_048_O04.png" width="30%"/> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
35703.

Three forces bar(F_(1)), bar(F_(2)) and bar(F_(3)) are simultaneously acting on a particle of mass 'm' and keep it in equilibrium. If bar(F_(1)) force is reversed in direction only, the acceleration of the particle will be.

Answer» <html><body><p>`bar(F_(1))//m`<br/>`2bar(F_(1))//m`<br/>`-bar(F_(1))//m`<br/>`-2bar(F_(1))//m`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Under equilibrium condition `<a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a>(F_(1))+vec(F_(2))+vec(F_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))=<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>` <br/> `vec(F_(1))=-(F_(1)+F_(2)), a=(-F_(1)+F_(2)+F_(3))/(m)`</body></html>
Discussion
35704.

A sphere of radius 10 cm is hung inside an oven whose walls are at a temperature of 1000 K. Calculate total heat energy incident per second (in joules//sec) on the sphere, sigma=5.67xx10^(-8) mks units.

Answer» <html><body><p><br/></p>Solution :Here, `r=10 cm =10^(1) m, T=1000 K`, <br/> `<a href="https://interviewquestions.tuteehub.com/tag/sigma-1207107" style="font-weight:bold;" target="_blank" title="Click to know more about SIGMA">SIGMA</a>= 5.67xx10^(-8)` mks units <br/> Heat energy incident/sec area`=sigma T^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)` <br/> Total heat energy incident/sec <br/> `E=sigma T^(4)` x area of sphere `=sigma T^(4)xx4 pi r^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/> `=5.67xx10^(-8)xx(10^(3))^(4)xx4xx(22)/(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)(10^(-1))^(2)` <br/> `E= 7128 j s^(-1)`</body></html>
Discussion
35705.

Starting from rest a wheel rotates with uniform angular acceleration 2pi rad s^(-2). After 4s, if the angular acceleration ceases to act, its angular displacement in the next 4s is

Answer» <html><body><p>`8pi <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a>`<br/>`16pi rad`<br/>`24pi rad`<br/>`32pi rad`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>
Discussion
35706.

For a satellite moving in an orbit around the earth, the ratio of kinetic energy of potential

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a><br/>`sqrt2` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/2`<br/>`(1)/(sqrt2)` </p>Solution :`(GMm)/(R^2) = m omega^2 R` <br/> `KE = 1/2 I omega^2= 1/2 mR^2 omega^2 = (GMm)/(<a href="https://interviewquestions.tuteehub.com/tag/2r-300472" style="font-weight:bold;" target="_blank" title="Click to know more about 2R">2R</a>)` <br/> `PE= - (GMm)/(R )` <br/> `(KE)/(|P.E|) = (GMm)/(2R) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> (R )/(GMm) = 1/2 `</body></html>
Discussion
35707.

In a measurement, a choice of change of different units

Answer» <html><body><p>does not <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> the number of <a href="https://interviewquestions.tuteehub.com/tag/significant-1207363" style="font-weight:bold;" target="_blank" title="Click to know more about SIGNIFICANT">SIGNIFICANT</a> <a href="https://interviewquestions.tuteehub.com/tag/figures-987769" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURES">FIGURES</a> <br/>increase the number of significant figures<br/>decrease the number of significant figures<br/><a href="https://interviewquestions.tuteehub.com/tag/may-557248" style="font-weight:bold;" target="_blank" title="Click to know more about MAY">MAY</a> increase or may decrease the number of significant figures</p>Answer :A</body></html>
Discussion
35708.

A force F =(6hati +2hatj -3hatk)acts on a particle and produces a displacement of vecs = (2hati-3hatj+xhatk). If work done is zero, the value of x is

Answer» <html><body><p>`-2`<br/> `1/2`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>`<br/>`2` </p>Solution :`W = vecF. Vecs = (6 hati + 2 hatj - 3hatk).(2 hati - <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> hati + <a href="https://interviewquestions.tuteehub.com/tag/xhatk-3292300" style="font-weight:bold;" target="_blank" title="Click to know more about XHATK">XHATK</a>)` <br/> `= <a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a> - 6 - <a href="https://interviewquestions.tuteehub.com/tag/3x-310805" style="font-weight:bold;" target="_blank" title="Click to know more about 3X">3X</a>` <br/> As W = 0 (Given) <br/> `:.` 12 - 6 - 3x= 0 or x = 2`.</body></html>
Discussion
35709.

Explain the characteristics of elastic and inelastic collision. (OR) What is the condition for perfect inelastic collision ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V01_C04_E01_019_S01.png" width="80%"/></body></html>
Discussion
35710.

Which of the following velocity-time graphs represent uniform motion

Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_048_O01.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_048_O02.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_048_O03.png" width="30%"/><br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_A_C03_E01_048_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
35711.

When a projectile is projected in oblique motion expressions for time of flight andrange of the projectile are given . Which of the following pairis correct ?

Answer» <html><body><p>`t_(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>) = (u sin <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2g-300351" style="font-weight:bold;" target="_blank" title="Click to know more about 2G">2G</a>):R = (u^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) sin 2 theta)/(2g)`<br/>`t_(f) = (2u sin theta)/(g):R = (u^(2) sin 2 theta)/(g)`<br/>`t_(f) = (2u costheta)/(g):R = (u^(2) <a href="https://interviewquestions.tuteehub.com/tag/cos2-935923" style="font-weight:bold;" target="_blank" title="Click to know more about COS2">COS2</a> theta)/(g)`<br/>`t_(f) = (2u sin theta)/(g):R = (u^(2) sin2 theta)/(2g)`</p>Answer :B</body></html>
Discussion
35712.

A simple pendulum is suspended from the roof of a trolley that moves freely down a plane of inclination theta. What is the time period of oscillation ? What is the angle made by the string with the inclined plane in the mean position ?

Answer» <html><body><p></p>Solution :The effective <a href="https://interviewquestions.tuteehub.com/tag/acceleation-2395037" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELEATION">ACCELEATION</a> g. is the <a href="https://interviewquestions.tuteehub.com/tag/resultant-1187362" style="font-weight:bold;" target="_blank" title="Click to know more about RESULTANT">RESULTANT</a> of g acting <a href="https://interviewquestions.tuteehub.com/tag/vertically-3260386" style="font-weight:bold;" target="_blank" title="Click to know more about VERTICALLY">VERTICALLY</a> downwards and the inertial acceleration g `sin theta` acting up the <a href="https://interviewquestions.tuteehub.com/tag/plane-1155510" style="font-weight:bold;" target="_blank" title="Click to know more about PLANE">PLANE</a>. <br/>`g. = sqrt(g^2 + g^2 sin^2 theta + 2(g)(g sin theta) cos (90^@ +theta))`<br/>`=gsqrt(1+sin^2theta - 2 sin^2 theta) = g cos theta` <br/>Time <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> T=` 2pi sqrt((1)/(g cos theta))` <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_PHY_XI_V01_C_C05_SLV_055_S01.png" width="80%"/></body></html>
Discussion
35713.

Water drops fall from the roof of a building 20m high at regular time intervals. If the first drop strikes the floor when the sixth drop begins to fall, the heights of the second and fourth drops from the ground atthat instant are (g=10ms^(-2))

Answer» <html><body><p>12.8 m and 3.2 m<br/>12.8 m and 7.2 m<br/>19.2 m and 0.8 m<br/>7.2 m and 16.8 m</p>Answer :D</body></html>
Discussion
35714.

An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram. If Q_(1), Q_(2), Q_(3) indicate the heat absorbed by the gas along the three processes and Delta U_(1) , Delta U_(2), Delta U_(3) indicate the change in internal energy along the three processes respectively, then

Answer» <html><body><p>`Q_(1) <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> Q_(2) gt Q_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` and `Delta U_(1) = Delta U_(2) = Delta U_(3)`<br/>`Q_(1) gt Q_(2) gt Q_(3)` and `Delta U_(1) = Delta U_(2) = Delta U_(3)`<br/>`Q_(1) = Q_(2) = Q_(3)` and `Delta U_(1) gt Delta U_(2) gt Delta U_(3)`<br/>`Q_(3) gt Q_(2) gt Q_(1)` and `Delta U_(1) gt Delta U_(2) gt Delta U_(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
35715.

An ideal gas system undergoes an isothermal process, then the work done during the process is

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/nrt-1109890" style="font-weight:bold;" target="_blank" title="Click to know more about NRT">NRT</a> ln ((V_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(V_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)))`<br/>`nRT ln ((V_(1))/(V_(2)))`<br/>`2nRT ln ((V_(2))/(V_(1)))`<br/>`2nRT ln ((V_(1))/(V_(2)))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
35716.

If unit of mass is taken as 1kg, of time as 1 minute and that acceleration due to gravity is taken as 9.81ms^(-2), what is the unit of energy?

Answer» <html><body><p></p>Solution :New uunit of energy `= E_(1)` <br/> New <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> of <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> `M_(2)= 1kg` <br/> New unit of time `T_(1)=1` minute = 60 sec <br/> New unit of length `=L_(1)` <br/> `E_(1)= [M_(1)L_(1) T_(1)^(-2)]` <br/> New unit of acceleration <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> gravity, `g_(1)= 9.81 ms^(-2)` <br/> `g_(1)= L_(1) T_(1)^(-2), L_(1)= g_(1)T_(1)^(-2)= 9.81 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> (60)^(2)` meter <br/> `E_(1)= [1kg xx (9.81 xx 60^(2))^(2) m^(2) (60)^(-2) S^(-2)]` <br/> `E_(1)= (1 xx 9.81 xx 60 xx 60 xx 9.81 xx 60 xx 60)/(60 xx 60) kg m^(2) s^(-2)` <br/> `E_(1)= 3.464 xx 10^(5) kg m^(2) sec^(-2)` <br/> `therefore` The new unit of energy `E_(1)= 3.464 xx 10^(5)` joule.</body></html>
Discussion
35717.

A train of length 200m travelling at a speed of 30ms^(-1) overtakes another train of length 300m travelling ata speed of 20ms^(-1) in the same direction. The time taken by the first train to pass the second train is

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> s<br/>10 s<br/>20 s<br/>40s</p>Answer :A</body></html>
Discussion
35718.

A ball is projected vertically upwards. Air resistance and variation in g may be neglected. The ball rises to its maximum height H in a time T, the height being h after a time t : (1) The graph of kinetic energy E_(k) of the ball against height h is shown in figure 1 (2) The graph of height h against time t is shown in figure 2 (3) The graph of gravitational energy E_(k)of the ball against height h is shown in figure 3 (1) (2)In the above situation the block wili have maximum velocity when:

Answer» <html><body><p>the <a href="https://interviewquestions.tuteehub.com/tag/spring-11487" style="font-weight:bold;" target="_blank" title="Click to know more about SPRING">SPRING</a> force <a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> <br/>the <a href="https://interviewquestions.tuteehub.com/tag/frictional-465947" style="font-weight:bold;" target="_blank" title="Click to know more about FRICTIONAL">FRICTIONAL</a> force becomes zero <br/>the net force becomes zero<br/>the acceleration of block becomes zero</p>Answer :C::D</body></html>
Discussion
35719.

A ball is projected vertically upwards. Air resistance and variation in g may be neglected. The ball rises to its maximum height H in a time T, the height being h after a time t : (1) The graph of kinetic energy E_(k) of the ball against height h is shown in figure 1 (2) The graph of height h against time t is shown in figure 2 (3) The graph of gravitational energy E_(k)of the ball against height h is shown in figure 3 (1) -Which the figure shows the correct answers ?

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> only<br/>1, 2<br/>2, 3<br/>1 only</p>Answer :A</body></html>
Discussion
35720.

The component of position vector vecr along x - axis will maximum value if

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/vecr-3257533" style="font-weight:bold;" target="_blank" title="Click to know more about VECR">VECR</a>` is <a href="https://interviewquestions.tuteehub.com/tag/along-1974109" style="font-weight:bold;" target="_blank" title="Click to know more about ALONG">ALONG</a> x-axis<br/>`vecr` <a href="https://interviewquestions.tuteehub.com/tag/makes-2811811" style="font-weight:bold;" target="_blank" title="Click to know more about MAKES">MAKES</a> an <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> of `<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^(@)` with y-axis<br/>`vecr` is along y-axis<br/>`vecr` is -ve along u-axis</p>Solution :`vecr` is along x-axis</body></html>
Discussion
35721.

Proveis therateof changeofangularmomentumofthe earthaboutthe sun ?

Answer» <html><body><p></p>Solution :Thearealvelocityof theearthaboutthe sum`=(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)<a href="https://interviewquestions.tuteehub.com/tag/vr-724066" style="font-weight:bold;" target="_blank" title="Click to know more about VR">VR</a> =`constant(Kepler.ssecondlaw )<br/> `therefore ` angularmomentum=mvr =constant . <br/><a href="https://interviewquestions.tuteehub.com/tag/hencethe-2698358" style="font-weight:bold;" target="_blank" title="Click to know more about HENCETHE">HENCETHE</a> rateofchange ofangularmomentum oftheearthaboutthe <a href="https://interviewquestions.tuteehub.com/tag/sun-1234558" style="font-weight:bold;" target="_blank" title="Click to know more about SUN">SUN</a> <a href="https://interviewquestions.tuteehub.com/tag/iszero-2750609" style="font-weight:bold;" target="_blank" title="Click to know more about ISZERO">ISZERO</a> .</body></html>
Discussion
35722.

Match the statements, situations in Column I with that in Column II. One or more matching is possible.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>::D</body></html>
Discussion
35723.

Passage - I : A massless inextensible string is wound arounf two indeentical discs A and B. Disc A is fixed at the centre but is free to rotate about its axis and B is free to fall down. If the string does not slip on either of the disc answer the following (Given mass of each disc is m and radius of each disc is R) The angular acceleration of disc A and tention in the string is

Answer» <html><body><p>`(g)/(3R),(<a href="https://interviewquestions.tuteehub.com/tag/2mg-1835961" style="font-weight:bold;" target="_blank" title="Click to know more about 2MG">2MG</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/2g-300351" style="font-weight:bold;" target="_blank" title="Click to know more about 2G">2G</a>)/(3R),(mg)/(3)`<br/>`(2g)/(5R),(mg)/(5)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/4g-318729" style="font-weight:bold;" target="_blank" title="Click to know more about 4G">4G</a>)/(5R),(mg)/(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html>
Discussion
35724.

Passage - I : A massless inextensible string is wound arounf two indeentical discs A and B. Disc A is fixed at the centre but is free to rotate about its axis and B is free to fall down. If the string does not slip on either of the disc answer the following (Given mass of each disc is m and radius of each disc is R) The acceleration of disc B is

Answer» <html><body><p>`g/<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/2g-300351" style="font-weight:bold;" target="_blank" title="Click to know more about 2G">2G</a>)/(3)`<br/>`(2g)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/4g-318729" style="font-weight:bold;" target="_blank" title="Click to know more about 4G">4G</a>)/(5)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>
Discussion
35725.

At a given temperature the root mean square velocities of oxygen and hydrogen molecules are in the ratio

Answer» <html><body><p>`16:1`<br/>`1:16`<br/>`4:1`<br/>`1:4`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>
Discussion
35726.

The normal length of a steel spring is 8cm. Keeping one end of the spring fixed at a point, if a weight is attached to the other end, its length becomes 14 cm. The weight is pulled down slightly and then released. Find the time period of oscillation of the spring?

Answer» <html><body><p></p>Solution :Increase in <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> of the spring for the mass m is, <br/> l = 14 - 8 = 6 cm. <br/> So, <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> constant k (force required for a unit increase in length) = `(mg)/6"<a href="https://interviewquestions.tuteehub.com/tag/dyn-2596635" style="font-weight:bold;" target="_blank" title="Click to know more about DYN">DYN</a>"*cm^(-1)`. <br/> Time <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a>, `T=2pisqrt(m/k)=2pisqrt(m/((mg)/6))` <br/> = `2pisqrt(6/g)=2xx3.14xxsqrt(6/980)=0.49s`.</body></html>
Discussion
35727.

In hot summerafter aboththe body's

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/internal-517481" style="font-weight:bold;" target="_blank" title="Click to know more about INTERNAL">INTERNAL</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a><br/>internal energy increases<br/>heat decreases<br/>no <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in internal energy and heat</p>Solution :internal energy decreases</body></html>
Discussion
35728.

Mass m_(1) hits & sticks with m_(2) while sliding horizontally with velocity v along the common line of centres of the three equal masses (m_(1)=m_(2)=m_(3)=m). Initially masses m_(2) and m_(3) are stationary and the spring is unstretched. Find (a) the velocities of m_(1),m_(2) and m_(3) immediately after impact. (b) the maximum kinetic energy of m_(3). (c) the minimum kinetic energy of m_(2). (d) the maximum compression of the spring.

Answer» <html><body><p><br/></p>Solution :Just before collision <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BSL_PHY_CMMC_E01_099_S01.png" width="80%"/> <br/><br/> (a) We can use conservation of momentum as spring force is not an impulsive force. <br/> `rArrmv+0=(2m)<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>'rArr=(v)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/> `rArrv_(m_(1))=(v)/(2),v_(m_(2))=(v)/(2),v_(m_(3))=0` <br/> (b) Looking from <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> <a href="https://interviewquestions.tuteehub.com/tag/frome-2088630" style="font-weight:bold;" target="_blank" title="Click to know more about FROME">FROME</a> of refernce <br/> `v_(CM)=((2m)v'+m(0))/(2m+m)=(2)/(3)v'=(v)/(3)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BSL_PHY_CMMC_E01_099_S02.png" width="80%"/> <br/> (Both the blocks will execute SHM of same time period in CM frome of reference) <br/> `rArr(v_(m_(3)))_(max)=(v)/(3)+v_(CM)=(v)/(3)+(v)/(3)=(2v)/(3)` <br/> `rArr(KE_(m_(3)))_(max)=(1)/(2)m(v_(3))_(max)^(2)=(1)/(2)m((2v)/(3))^(2)=(2mv^(2))/(9)` <br/> (c) `(v_(m_(2)))_(min)=(v)/(3)-(v)/(6)=(v)/(6)` <br/> `rArr(KE_(m_(2)))_(min)=(1)/(2)m(v_(2))_(min)^(2)=(1)/(2)m((v)/(6))^(2)=(<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(2))/(72)` <br/> (d) At the time of maximum compression, both blacks will be at rest in CM frame of reference <br/> `rArr(1)/(2)kx_(max)^(2)=(1)/(2)(2m)((v)/(6))^(2)+(1)/(2)m((v)/(3))^(2)` <br/> `rArr(1)/(2)Kx_(max)^(2)=(1)/(12)mv^(2)` <br/> `rArrx_(max)=vsqrt((m)/(6k))`</body></html>
Discussion
35729.

Mention the MKS and GGS unit of work and define them and also write the dimensional formula of work .

Answer» <html><body><p></p>Solution :MKS unit of work `("kg m"^(2))/(s^(2))` .It is also known as <a href="https://interviewquestions.tuteehub.com/tag/joule-526299" style="font-weight:bold;" target="_blank" title="Click to know more about JOULE">JOULE</a> . <br/> Joule : Work done is said to be one joule, " When a force of one Newton actually moves a body through a distance of one metre in the direction of applied force . " <br/> ` :.1 "Joule " = 1 Nm = (1 " kg m"^(2))/(s^(2))`<br/> <a href="https://interviewquestions.tuteehub.com/tag/cgs-415525" style="font-weight:bold;" target="_blank" title="Click to know more about CGS">CGS</a> unit of work is `(" g cm"^(2))/(s^(2))` .It alsoknown as <a href="https://interviewquestions.tuteehub.com/tag/erg-446447" style="font-weight:bold;" target="_blank" title="Click to know more about ERG">ERG</a> .<br/> Erg: Work daone is saidto beone erg . " When a force of one day <a href="https://interviewquestions.tuteehub.com/tag/dyne-961313" style="font-weight:bold;" target="_blank" title="Click to know more about DYNE">DYNE</a> actuallymoves a body through a distanceof one cm inthe direction of <a href="https://interviewquestions.tuteehub.com/tag/appliedforce-2438302" style="font-weight:bold;" target="_blank" title="Click to know more about APPLIEDFORCE">APPLIEDFORCE</a> ". <br/> ` :. 1 "er = 1 dyne cm = 1 " ("g cm"^(2))/(s^(2))`<br/> SI unit of work is Joule (J) : J = Ns<br/> Dimensional formulaof work is`[M^(1)L^(2)T^(-2)]` [ Joule = `10^(7)`erg]<br/> Some practical units of work /energy shown in table (in Joule ) <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C06_E01_016_S01.png" width="80%"/></body></html>
Discussion
35730.

A steel wire has a length of 12.0m and a mass of 2.10kg. What should be the tension in the wire so that speed of a transverse wave on the wire equals the speed of sound in dry air at 20^(@)C= 343ms^(-1)

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`2.06 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>`</body></html>
Discussion
35731.

Two moles of a monoatomic gas in state ‘A’ having critical pressure P_0 and temperature 3T_0is takento a state B having pressure 3P, and temperature T_0//3by the process of equation P^2T= constant. Then, state B is taken to state C keeping volume constant and comes back to initial state ‘A’ keeping temperature constant. Heat supplied to the gas during complete cycle is cycle is RT_0 [(18 logx) – 8] .Determine the value of .x..

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a></body></html>
Discussion
35732.

If 484 J of energy is spent in increasing the speed of a wheel from 60 rpm to 360 rpm, the M.I. of the wheel is

Answer» <html><body><p>`1.6 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> m^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`0.3 kg m^(2)`<br/>`0.7 kg m^(2)`<br/>`1.2 kg m^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
35733.

Calculate the quantity of heat required to convert 10^(-2)kg of ice at 0^(@)C to steam at 100^(@)C. (Given L_("ice")=0.335xx10^(6)Jkg^(-1),L_("steam")=2.26xx10^(6)Jkg^(-1), Specific heat of water = 4186Jkg^(-1)K^(-1)).

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Quantity of <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> required to <a href="https://interviewquestions.tuteehub.com/tag/convert-425734" style="font-weight:bold;" target="_blank" title="Click to know more about CONVERT">CONVERT</a> ice into water at `0^(@)C(Q_(1))=mL_("ice")=10^(-2)xx0.335xx10^(6)=3350J` <br/> Quantity of heat required to raise the temperature of water from `0^(@)C" to "100^(@)C`. <br/> `(Q_(2))=mS_(<a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a>)(t_(2)-t_(1))=10^(-2)xx4186xx100=4186J` <br/> Quantity of heat required to convert water into steam at `100^(@)C` <br/> `(Q_(3))=mL_("steam")=10^(-2)xx2.26xx10^(6)=22600J` <br/> Total amont of heat required `(<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>)=Q_(1)+Q_(2)+Q_(3)` <br/> = 3350 + 4186 + 22600 = 30136 J.</body></html>
Discussion
35734.

A stream of water flowing horizontally with a speed of 15 m s^(-1) gushes out of a tube of cross-sectional area 10^(-2) m^2, and hits a vertical wall nearby. What is the force exerted on the wall by the impact of water, assuming it does not rebound?

Answer» <html><body><p>`1.25xx 10^3N`<br/>`2.25 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^3 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>`<br/>`3.25 <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> 10^3 N`<br/>`4.25 xx 10^3 N`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`2.25 xx 10^3 N`</body></html>
Discussion
35735.

16 cc. of water per second through a capillary tube of radius r and length / when connected to a pressure head of hom of water. If a tube of the same length and radius r/2 is connected to the same pressure head, the quantity of water flowing through this tube per second in c.c will be ......

Answer» <html><body><p>16cc<br/>4cc<br/>1cc<br/>8cc</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
35736.

Give an equation state for an isochoric process.

Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> of state for an isochoric process is given by <br/> `P((muR)/(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>))T` <br/> `"where"((muR)/(V))="Constant"` <br/> We can infer that the pressure is directly proportional to temperature. This implies that the `P-T` graph for an isochoric process is a straight <a href="https://interviewquestions.tuteehub.com/tag/line-1074199" style="font-weight:bold;" target="_blank" title="Click to know more about LINE">LINE</a> passing through origin.</body></html>
Discussion
35737.

In figure shown, left arm of a U-tube is immersed in a hot water bath at temperature T, and right arm is immersed in a bath of melting ice, the height of monomeric liquid in respective columns is h_(t) and h_(0). Determine the coefficient of expansion of the liquid

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/gamma-470142" style="font-weight:bold;" target="_blank" title="Click to know more about GAMMA">GAMMA</a> = [ ( h_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) -h_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)) //h_(0) t]`</body></html>
Discussion
35738.

A body is projected at an angle thetaso that its range is maximum. If T is the time of flight then the value of maximum range is (acceleration due to gravity=g)

Answer» <html><body><p>`(g^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> T)/(2)` <br/>`(<a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a>)/(2)` <br/>`(gT^2)/(2)` <br/>`(g^2 T^2)/(2)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
35739.

A body is moving in a circular path with accelerationaifits velocity gets doubledfind the ratio accelerationafter and before the change

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>:<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>`<br/>`1/4:1`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>:1`<br/>`4:1`</p>Solution :Centripetalacceleration`a=(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>^(2))/(r )` <br/> Accelerationbeforechange `=a_(1)` <br/> Accelerationafter change `=a_(2)` <br/> `v_(1) =- v` <br/> `v_(2)=2 v` <br/> `(a_(2))/(a_(1))= ((<a href="https://interviewquestions.tuteehub.com/tag/2v-300496" style="font-weight:bold;" target="_blank" title="Click to know more about 2V">2V</a>)^(2))/(v^(2))= (4)/(1)` <br/> `a_(2) : a_(1)4:1`</body></html>
Discussion
35740.

Two particles of same mass are projected simultaneously with same speed 20ms^(-1) from the top of a tower of height 20m. One is projected vertically upwards and other projected horizontally. The maximum height attained by centre of mass from the ground will be (g=10ms^(-2))

Answer» <html><body><p>`10sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)m`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/25m-298112" style="font-weight:bold;" target="_blank" title="Click to know more about 25M">25M</a>`<br/>`25sqrt(2)m`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/5m-326516" style="font-weight:bold;" target="_blank" title="Click to know more about 5M">5M</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
Discussion
35741.

Is viscosity a vector or a scalar ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :It is the <a href="https://interviewquestions.tuteehub.com/tag/property-1170155" style="font-weight:bold;" target="_blank" title="Click to know more about PROPERTY">PROPERTY</a> of <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> . So it has no <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> it is a <a href="https://interviewquestions.tuteehub.com/tag/scalar-629745" style="font-weight:bold;" target="_blank" title="Click to know more about SCALAR">SCALAR</a>.</body></html>
Discussion
35742.

The additional force required to lift a flat circular disc of radius 5 cm from the surface of water with surface tension 75 "dyne"cm^(-1). Will be

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/750-335306" style="font-weight:bold;" target="_blank" title="Click to know more about 750">750</a> <a href="https://interviewquestions.tuteehub.com/tag/dyne-961313" style="font-weight:bold;" target="_blank" title="Click to know more about DYNE">DYNE</a><br/>`750 <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>` dyne<br/>30 dyne<br/>60 dyne</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
Discussion
35743.

If a shell is fired from a cannon explodes in mid-air, then:

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> <br/>total momentum decreases<br/>total <a href="https://interviewquestions.tuteehub.com/tag/ke-527890" style="font-weight:bold;" target="_blank" title="Click to know more about KE">KE</a> increases <br/>momentum and KE doesn't change</p>Solution :`K.Epropv`</body></html>
Discussion
35744.

An object falling freely covers half of its total distance in last second, then find total height and total times g = 9.8 ms^(-2).

Answer» <html><body><p></p>Solution :Suppose, total time is T and total height is h, <br/> In `h = ut + <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/2 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> g ^(2) , u = 0` <br/> `h = 1/2g t ^(2) ""…(1)` <br/> Now `t = (T-1) and h = h/2` <br/> `h /2 = 1/2 g (T -1) ^(2)` <br/> `therefore h = g (T - 1) ^(2) ""…(2)` <br/> By comparing equation (1) and (2). <br/> `therefore 1/2 g t ^(2) = g (T ^(2) - 2T +1)` <br/> `therefore T ^(2) = 2 T ^(2) - 4 T + 2` <br/> `therefore T ^(2) -4T + 2=0` <br/> `a = 1, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> =- 4, c =2` <br/> `Delta = b ^(2) - 4ac` <br/> `=<a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a>-4 xx 1 xx 2 ` <br/>`=16 -8 =8` <br/> `therefore sqrtDelta = 2 <a href="https://interviewquestions.tuteehub.com/tag/sqrt2-3056932" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT2">SQRT2</a>` <br/> `therefore` Solution `T = (-b pm sqrtDelta )/( 2a) = (4 pm 2 sqrt2)/(2)` <br/> `T = 2 pm sqrt2` <br/> `therefore T = 2 + 1.4.4 = 3.414s or 2-1414 = 0.586 s` <br/> But `T=0.586` s is not possible <br/> `therefore T = 3.414 s ` <br/> Now from equation `h = 1/2 g t ^(2) ` <br/> `h = 1/2 xx 9.8 xx (3.414) ^(2)` <br/> `therefore h = 57.11 m`</body></html>
Discussion
35745.

How does the use of ball bearing reduces friction

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Ballbearingprovidesanothereffectiveway to reducethe kineticfirictionin <a href="https://interviewquestions.tuteehub.com/tag/machines-550361" style="font-weight:bold;" target="_blank" title="Click to know more about MACHINES">MACHINES</a> . Ifballbearingare fixedbetweentwosurfaceduringthe relativemotiononly therollingfrictioncometo effectand notkineticfriction. Sincethe rollingfrictionis <a href="https://interviewquestions.tuteehub.com/tag/much-2164829" style="font-weight:bold;" target="_blank" title="Click to know more about MUCH">MUCH</a> smallerthankineticfricitionthe machinesare protectedfromwearandtearover <a href="https://interviewquestions.tuteehub.com/tag/theyears-1412968" style="font-weight:bold;" target="_blank" title="Click to know more about THEYEARS">THEYEARS</a>.</body></html>
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35746.

The difference in the value of .g.at pole and at a lattitude is 3/4Romega^(2) then latitude angle is

Answer» <html><body><p>`60^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(@)`<br/>`45^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/95-342378" style="font-weight:bold;" target="_blank" title="Click to know more about 95">95</a>^(@)` </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
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35747.

Find the change in internal energy in joule, when 10g of air is heated from 30^(@)C" to " 40^(@)C (C_(V)=0.172"kcal/kg K", J=4200" J/kcal")

Answer» <html><body><p>62.24 J<br/>72.24 J<br/>52.24 J<br/>82.24 J</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
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35748.

A body of mass m is thrown up at a velocity u along a plane of inclination theta. If coefficient of friction between the body and the plane is mu, what would be the work done by friction when the body rises up to the highestpoint of itsmotion?

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(u^2mum)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(mu+tan <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>))`</body></html>
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35749.

the value of energy for the O_(2) molecule (rigidrotator) is

Answer» <html><body><p>`3/2 K_BT`<br/>`5/2K_BT`<br/>`3/2 K_BT`<br/>`1/2 K_BT`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
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35750.

Two persons are pulling a heavy block with the help of horizontal inextensible strings. At the instant shown, the velocities of the two persons are v_(1) and v_(2) directed along the respective strings with the strings making an angle of 60^(@) between them. (a) Find the speed of the block at the instant shown. (b) For what ratio of v_(1) and v_(2) the instantaneous velocity of the block will be along the direction of v_(1).

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a) `(2)/(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)) sqrt(v_(1)^(2) +v_(2)^(2) - v_(1)v_(2))` (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `(v_(1))/(v_(2)) = 2`</body></html>
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