This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Out put characteristics of n - p - n transistor in CE configuration is shown. From the characteristics curve determine the current gainatV_("CE") = 1 V. |
| Answer» ANSWER :A | |
| 2. |
(a) A 900 pF capacitor is charged by 100 V battery [Fig. 2.31(a)]. How much electrostatic energy is stored by the capacitor? (b) The capacitor is disconnected from the battery and connected to another 900 pF capacitor [Fig. 2.31(b)]. What is the electrostatic energy stored by the system? |
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Answer» Solution :(a) The charge on the capacitor is Q = CV = `900 xx 10^(-12) F xx 100 V = 9 xx 10^(-8) C` The energy STORED by the capacitance is `=(1//2)CV^(2) = (1//2) QV = (1//2) xx 9 xx 10^(-8) C xx 100 V = 4.5 xx 10^(-6)` J (b) In the steady situation, the two capacitors have their positive plates at the same potential, and their negative plates at the same potential. Let the common potential difference be V′. The charge on each capacitance is then `Q. = CV.`. By charge conservation, `Q. = Q//2`. This implies `V. = V//2`. The total energy of the system is `=2 xx 1/2 Q.V. = 1/4 QV = 2.25 xx 10^(-6)` J Thus in going from (a) to (b), though no charge is lost, the final energy is only half the initial energy. Where has the remaining energy gone? There is a transient period before the system settles to the situation (b). During this period, a transient current flows from the first capacitor to the second. Energy is lost during this time in the form of HEAT and electromagnetic RADIATION. |
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| 3. |
Waves of same amplitude and same frequency from two coherent source overlap at a point. The ratio of the resultant intensity when they arrive in phase to that when they arrive with 90^(@) phase difference is |
| Answer» Answer :C | |
| 4. |
A coil of radius r=25cm is made of a thin copper wire of length l=500m and resistance R rotates with an angular velocity omega=500m and resistance R rotates with an angular velocity omega=300 rad//sec about its axis. Calculate the quantities of charges in the coil that will flow duie to the sudden stoppage of the coil "["Hint: Loss in KE= Heat produced"]" |
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| 5. |
वह स्थान जहाँ बीजाण्ड , बीजाण्डवृन्त से जुड़ता है कहलाता है : |
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Answer» निभाग |
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| 6. |
In the circuit shown in the fig the equivalent resistance between a and b is R_(ab) and the equivalent between a and c is R_(ac). find the ratio R_(ab) : R_(ac). |
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| 7. |
If M,m_n and m_p are masses (in kg) of nucleus X_z^A, neutron and proton respectively, then mass defect(Deltam) is equal to |
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Answer» `DELTAM=[(A-Z)m_n+Am_p-M]` |
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| 8. |
A particle of massmis dropped from a heighth above the ground. At the same time another particle of mass 2m is thrown vertically upwards from the ground with a speed ofsqrt(gh) . If they collide head-on completely inelastically, the time taken for the combined mass to reach the ground, in units of sqrt(h/g) is : |
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Answer» `(sqrt40-2)/6` Particles will collide after time `t_0 = (h)/(sqrt(gh)) ` at collision ,`v_A = "GT"_0 ""v_B = u_B - "gt"_0` `implies v_A = - gsqrt(h//g), v_B = 0 ` Time TAKEN by combined mass to REACH the ground Time `= ((sqrt(40)-2)/(6)) sqrt(h//g)`
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| 9. |
Nehru often known as |
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Answer» CHACHA |
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| 10. |
Let there be a spherically symmetric charge distribution with charge density varying as rho (r) = rho_0((5)/(4) - (r)/(R) ) upto r = R, and rho (r) = 0 for r >R, where r is the distance from the origin. The electric field at a distance r (r |
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Answer» `(4 PI rho_0r)/(3 epsi_0) ((5)/(3) -(R )/(R ))` |
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| 11. |
A block of mass 10 kg is released from top of rough inclined plane as shown in the figure if coefficient of friction between the block and inclined plane is then total work done on the block by all the forces acting on it till it reaches the bottom s = 10 ms |
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Answer» 200 j |
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| 12. |
In Young's double slit experiment (d)/(D) = 10^(-4) (d = distance between slits, D =distance of screen from the slits) At a point P on the screen the resulting intensity is equal to the intensity due to individual slit I_(0).Then the distance of point P from the central maximum is (lambda = 6000 Å) : |
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Answer» 2 mm As `I = I_(0)` `THEREFORE I_(0) = 4I_(0) cos^(2)((phi)/(2))` `therefore cos((phi)/(2)) = 1/2 Rightarrow (phi)/(2) = (pi)/(3)` `phi = (2pi)/(3) = (2 pi)/(lambda).Deltax` `therefore 1/3 = 1/(lambda).Deltax` But `Deltax = (yd)/(D)` `therefore 1/3 = 1/(lambda).(yd)/(D)` `therefore y = (lambda)/(3((d)/(D)) = 2 xx 10^(-3)` m `y = 2mm`. |
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| 13. |
Match the corresponding entries of column 1 with column 2. [Where m is the magnification produced by the mirror. {:("Column 1","Column 2"),((A)m=-2,"(a) Convex mirror"),((B)m=-(1)/(2),"(b) Concave"),((C)m=+2,"(c) Real image"),((D)m=+(1)/(2),"(d) Virtual image"):} |
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Answer» `Ararra and C, Brarr a and d, C rarr a and b, Drarrc and d` |
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| 14. |
An artificial satellite is moving in a circular orbit around the earth, with a speed which is equal to half the magnitude of the escape velocity from the earth. What is the height of the satellite above the- surface of earth |
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Answer» a)6311 sec |
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| 15. |
What does the poet mean by body of "clay"? |
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Answer» Ignorance |
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| 16. |
A coil with an inductance of 2.0 Hand a resistance of 10 Omega is suddenly connected to an ideal battery with E = 100 V. At 0.10 s after the connection is made, what is the rate at which (a) energy is being stored in the magnetic field, (b) thermal energy is appearing in the resistance, and ( c) energy is being delivered by the battery? |
| Answer» Solution :(a) `2.4 xx 10^(2)` W, (b) `1.5 xx 10^(2) W, (C) 3.9 cx 10^(2) W` | |
| 17. |
कौन से राज्य के पास गांव में लोगों ने 1200 हेक्टेयर वन भूमिभैरोंदेव डाकव अभ्यारण्य को घोषित कर दी हैं? |
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Answer» मध्य प्रदेश |
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| 18. |
Define normal shift. Obtain an expression for normal shift when an object in a denser medium is viewed from a rarer medium. |
Answer» Solution :The apparent shift in the position of the object kept in one medium and viewed normally through another medium. OP = INCIDENT ray PQ = refracted ray produced backwards meet ON at I. NN. = normal OI = normal shift `/_RPO = i = ` angle of incidence = NPO `/_ QPS =r=` angle of REFRACTION= NIP t = thickness of the optical medium. ` sin i = ( NP )/( OP )`[ From the `Delta NPO`] `sin r = ( NP )/( IP )`[ From the `Delta NP]` `n_(1) sin i = n _(2) sin r ` Here, `n_(1)= n , n_(2) = 1 ` `n= ( NP )/( OP) = 1( NP )/( IP )` `n = ( NP )/( IP ) xx ( OP )/( NP) = ( OP )/( IP ) = ( ON )/(IN ) ` `:.`P is the point which is very close to N `n = ( "real DEPTH ")/( "apparent depth")` Normal shift `= OI = ON -IN` `= ON - ( ON )/( n )` `NS = ON [ 1- (1)/( n )] =t [ 1- ( 1)/ (n ) ]` Normal shift `= t [ 1- ( 1)/( n ) ]` |
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| 19. |
Long sightedness or ______can be cured by use of convex lens. |
| Answer» SOLUTION :HYPERMETROPIA | |
| 20. |
A device which can operate in the reverse breakdown voltage region continuously without being damaged is called_____. |
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| 21. |
Is the expression n=(sin((A+D)/(2)))/(sin(A//2)) true for all the positions of the prism? |
| Answer» SOLUTION :No. This EXPRESSION is TRUE for SYMMETRIC REFRACTION only. | |
| 22. |
A nuclear transformation is denoted by X(n,alpha), ""_(3)^(7)Li. Which of the following is X nucleus ? |
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Answer» `""_(5)^(9)B` |
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| 23. |
A bar with a crack at its centre buckles as a result of temperature rise of 32^(@)C. If the fixed distacne L_(0) is 3.77 m and the coefficient of linear expansion of the bar is 25xx10^(6)//""^(@)C find the rise (in metre) of the centre. |
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Answer» Solution :CONSIDER one half of THEBAR, its initial LENGTH `l_(0)=(L_(0))/2` Its length after increase in temperature `Deltat`, `l=l_(0)(1+ALPHA DeltaT)` By Pythogoras theorem `l_(0)^(2)(1+alpha DeltaT)^(2)-l_(0)^(2)` `=l_(0)^(2) 2 alpha DeltaT` or `x=l_(0)sqrt(2 alpha DeltaT)` `=3.77/2sqrt(2(25xx10^(-6)xx32))` `=7.5xx10^(-2)m` |
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| 24. |
The figure shows a diagonal symetric arrangement of capacitors and a battery.The value of charge q_(1),q_(2) and q_(3)as shown in the figure are |
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Answer» `q_(1) = 32 muC,q_(2) = 24 muC, q_(3) =-8 muC` |
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| 25. |
Two short bar mangets of length 1 cm each have magnetic moments 1.20and 1.00 am^(2)respectivelythey have a commonmagnetic value of the resultant horizontal magnetic induction at the mid point O of the line joining their centreis closeto |
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Answer» `2.56 xx10^(-4) wb//m^(2)`
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| 26. |
Two are given many resistance, capacitors and inductors . These are connected to a variable DC voltage source (the first two circuits) or an AC voltage source of 50Hz frequency(the next three circuits) in different ways as shown in Column B. When a current I (steady state for DC or rms for AC ) flows through the circuit, the correspondingvoltage V_(1) and V_(2) (indicated in circuits) are related as shown in Column A . Match the two |
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| 27. |
A wire carrying a current i is first bent in the form of a square of side a and placed at right angle to a uniform magnetic field of induction B. The work done in changing its shape into a circle is |
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Answer» `ia^2 B ( PI+2)` |
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| 28. |
No net force acts on a rectangular loop carrying a steady current when suspended freely in a uniform magnetic field. Is the statement correct or wrong? Justify your an swer. |
| Answer» Solution : CORRECT. The FORCES on pair of opposite sides are EQUAL and opposite HENCE no NET force | |
| 29. |
How does Dalton's hypothesis explain the Gay-Lussac's law? |
| Answer» Solution :When Avogadro's HYPOTHESIS is COMBINED with Dalton's ATOMIC THEORY this explain Gay-Lussac's LAW. | |
| 30. |
For writer it was hard to believe that his grandmother was young and pretty? |
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Answer» YES |
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| 31. |
An alpha- particle and a proton of the same kinetic energy are in turn allowed to pass through a magnetic field vecB, acting normal to the direction of motion of the particles. Calculate the ratio of radii of the circular paths described by them. |
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Answer» SOLUTION :We know that radius of circular PATH `R = (mv)/(qB) = (sqrt(2mk))/(qB)` Here `K_(alpha) = K_(p)` but `m_(alpha) = 4m and q_(alpha) = 2q_p` `:. (r_(alpha))/(r_p) = sqrt((m_(alpha))/(m_p)) xx ((q_P)/(q_(alpha))) = sqrt((4m_p)/(q_(alpha))) xx ((q_p)/(2q_p)) = 1` `implies r_(alpha) = r_(p)` |
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| 32. |
The young's double slit experiment is done in a medium of refractive index 4/3. A light of 600 nm wavelength is falling on the slits having 0.45 mm separation. The lower slit S_(2) is covered by a thin glass sheet of thickness 10.4 mu m and refractive index 1.5. The interference pattern is observed on a screen placed. 1.5 m from the slit as shown in figure. Find the light intensity at point O relative to the maximum fringe intensity |
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| 33. |
A polarized light of intensity I_(0) is passed through another polarizer whose pass axis makes an angle of 60^(@) with the pass axis of the former.What is the intensity of emergent polarized light from second polarizer ? |
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Answer» `I = I_(0)` (I = Intensity of emergent polarized light) where `theta = 60^(@), I = ?` (`I_(0)` = Intensity passed through polariser) ` = I_(0) xx ((1)/(2))^(2) = (I_(0))/(4)` |
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| 34. |
A plane with a wing span of 18 m flies horizontally at a speed of 800 km/h. The vertical component of the Earth's magnetic field strength is about 40 A/m. Find the voltage across the tips of the wings. Will a light bulb connected to the wing tips glow? |
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| 35. |
Calculate the volume at 273K, 1 atm occupied by 1.5 moles of carbon dioxide |
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Answer» 22.4 L |
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| 36. |
Across a metallic conductor of non-uniform cross section a constant potential difference is applied. The quantity which remains constant along the conductor is : |
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Answer» ELECTRIC CURRENT density Given CONDUCTOR is said to be made by connecting DIFFERENT conductors in series as shown and in series connection current always· remains same.
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| 37. |
A car is moving with at a constant speed of 60 km h^(-1) on a straight road. Looking at the rear view mirror, the driver finds that the car following him is at a distance of 100 m and is approaching with a speed of 5 km h^(-1). In order to keep track of the car in the rear, the driver begins to glance alternatively at the rear and side mirror of his car after every 2 s till the other car overtakes. If the two cars were maintaining their speeds, which of the following statement (s) is//are correct? |
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Answer» The speed of the car in the REAR is 65 km `h^(-1)`. |
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| 38. |
A. The wavelength of microwaves is greater than that of UV-rays. B. The wavelength of IR rays is lesser than that of UV- rays. C. The wavelength of microwaves is lesser than that of IR rays. D. Gamma rays has shortest wavelength in the electromagnetic spectrum. |
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Answer» A and B are true |
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| 39. |
A concave mirror and a concave lens are held in water. The focal length of both mirror as well as lens gets changed. |
| Answer» Solution :On immersion into water focal length of CONCAVE MIRROR remains unchanged but focal length of concave LENS INCREASES. | |
| 41. |
A flat search coil of 100 turns and each of area 3xx10^(-4)m^(2) is connected to a galvanometer, so that the total resistance of the circuit is 90Omega. The plane of the coil is normal to a magnetic field, B = 0.4T. Calculate the change in flux when the coil is moved to a region of negligible magnetic field and the charge passes through the galvanometer. |
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Answer» Solution :`A=3xx10^(-4)m^(2),N=100,R=90Omega,B=0.4T` Magnetic FLUX `(phi_(B))=NAB=100xx3xx10^(-4)xx0.4=1.2xx10^(-2)` weber `phi_(B)=1.2xx10^(-2),phi_(B)=0` `THEREFORE` Charge `Q=(phi_(B)-phi_(B).)/(R)=(1.2xx10^(-2))/(90)=1.33xx10^(-4)C` |
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| 42. |
Explain transducer. |
| Answer» Solution :It is a DEVICE which converts one FORM of energy into another. Transducer is used in electronoic communication system. For example, a microphone is a transducer which converts SOUND energy into ELECTRIC energy and hence acts as a transducer. | |
| 43. |
For what angle between the two vectors, their resultant is maximum? |
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Answer» `180^(@)` R shall be MAXIMUM if cos `theta =+1` `:. theta` zero |
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| 44. |
Where electromagnetic waves are used ? |
| Answer» SOLUTION :RADIO, TELEVISION and other COMMUNICATION SYSTEMS. | |
| 45. |
Two cells of emfs E_(1) and E_(2) are connected together in two ways shown here. The 'balance points' in a given potentiometer experiment for these two combinations of cells are found to be at 351.0 cm and 70.2 cm respectively. Calculate the ratio of the emfs of the two cells. |
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| 46. |
Light from two coherent sources of same amplitude and same wavelength illuminates the screen. The intensity of the central maximum is I. If the sources were noncoherent, the intensity at the same point will be |
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Answer» `I"/"2` |
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| 47. |
Name the reaction responsible for energy production in the Sun. |
| Answer» SOLUTION :NUCLEAR FUSION REACTION. | |
| 48. |
The amount of heat radiated pr unit time, per unit area by perfectly black body at 27^@C is (sigma = 5.6 xx 10^(-8) J/m^2 sk^(4)) |
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Answer» 453.6 `watt/m^3` |
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| 49. |
A long round conductor of cross-sectional area S is made of material whose resistivity depends only on a distance r from the axis of the conductor as rho=alpha//r^(2), where alpha is a constant. Find the total resistance per unit length of the rod when potential difference is applied across its length. |
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Answer» `(PI alpha)/(S^(2))` |
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| 50. |
Draw the energy band diagram of a n-type semiconductor. Deduce an expression for conductivity of a n-type semiconductor. |
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Answer» SOLUTION :Energy band DIAGRAM of a n-type semiconductor Conductivity of n-type semiconductor `sigma=e[n_(e)mu_(e)+n_(h)mu_(h)]`...........`(i)` For n-type semiconductor `n_(e) gt gt n_(h)`. If `N_(d)` is the number DENSITY of DONOR ATOMS then `n_(e)=N_(d)` So Eq. `(i)` for n-type semiconductor becomes `sigma=eN_(d)mu_(e)` |
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