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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C? |
| Answer» C's 1 day's work = 1 - 1 + 1 = 1 - 7 = 1 . 3 6 8 3 24 24 A's wages : B's wages : C's wages = 1 : 1 : 1 = 4 : 3 : 1. 6 8 24 C's share (for 3 days) = Rs. 3 x 1 x 3200 = Rs. 400. 24 | |
| 2. |
10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work? |
| Answer» 1 woman's 1 day's work = 1 70 1 child's 1 day's work = 1 140 (5 women + 10 children)'s day's work = 5 + 10 = 1 + 1 = 1 70 140 14 14 7 5 women and 10 children will complete the work in 7 days. | |
| 3. |
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last? |
| Answer» Work done by X in 4 days = 1 x 4 = 1 . 20 5 Remaining work = 1 - 1 = 4 . 5 5 (X + Y)'s 1 day's work = 1 + 1 = 8 = 2 . 20 12 60 15 Now, 2 work is done by X and Y in 1 day. 15 So, 4 work will be done by X and Y in 15 x 4 = 6 days. 5 2 5 Hence, total time taken = (6 + 4) days = 10 days. | |
| 4. |
A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days? |
| Answer» Ratio of times taken by A and B = 100 : 130 = 10 : 13. Suppose B takes x days to do the work. Then, 10 : 13 :: 23 : x x = 23 x 13 x = 299 . 10 10 A's 1 day's work = 1 ; 23 B's 1 day's work = 10 . 299 (A + B)'s 1 day's work = 1 + 10 = 23 = 1 . 23 299 299 13 Therefore, A and B together can complete the work in 13 days. | |
| 5. |
Ravi and Kumar are working on an assignment. Ravi takes 6 hours to type 32 pages on a computer, while Kumar takes 5 hours to type 40 pages. How much time will they take, working together on two different computers to type an assignment of 110 pages? |
| Answer» Number of pages typed by Ravi in 1 hour = 32 = 16 . 6 3 Number of pages typed by Kumar in 1 hour = 40 = 8. 5 Number of pages typed by both in 1 hour = 16 + 8 = 40 . 3 3 Time taken by both to type 110 pages = 110 x 3 hours 40 = 8 1 hours (or) 8 hours 15 minutes. 4 | |
| 6. |
A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Working together, they will complete the same work in: |
| Answer» Formula: If A can do a piece of work in n days, then A's 1 day's work = 1 . n (A + B + C)'s 1 day's work = 1 + 1 + 1 = 7 . 24 6 12 24 Formula: If A's 1 day's work = 1 , then A can finish the work in n days. n So, all the three together will complete the job in 24 days = 3 3 days. 7 7 | |
| 7. |
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work? |
| Answer» B's 10 day's work = 1 x 10 = 2 . 15 3 Remaining work = 1 - 2 = 1 . 3 3 Now, 1 work is done by A in 1 day. 18 1 work is done by A in 18 x 1 = 6 days. 3 3 | |
| 8. |
4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it? |
| Answer» Let 1 man's 1 day's work = x and 1 woman's 1 day's work = y. Then, 4x + 6y = 1 and 3x + 7y = 1 . 8 10 Solving the two equations, we get: x = 11 , y = 1 400 400 1 woman's 1 day's work = 1 . 400 10 women's 1 day's work = 1 x 10 = 1 . 400 40 Hence, 10 women will complete the work in 40 days. | |
| 9. |
A and B can together finish a work 30 days. They worked together for 20 days and then B left. After another 20 days, A finished the remaining work. In how many days A alone can finish the work? |
| Answer» (A + B)'s 20 day's work = 1 x 20 = 2 . 30 3 Remaining work = 1 - 2 = 1 . 3 3 Now, 1 work is done by A in 20 days. 3 Therefore, the whole work will be done by A in (20 x 3) = 60 days. | |
| 10. |
A and B can do a work in 8 days, B and C can do the same work in 12 days. A, B and C together can finish it in 6 days. A and C together will do it in : |
| Answer» (A + B + C)'s 1 day's work = 1 ; 6 (A + B)'s 1 day's work = 1 ; 8 (B + C)'s 1 day's work = 1 . 12 (A + C)'s 1 day's work = 2 x 1 - 1 + 1 6 8 12 = 1 - 5 3 24 = 3 24 = 1 . 8 So, A and C together will do the work in 8 days. | |
| 11. |
A can finish a work in 24 days, B in 9 days and C in 12 days. B and C start the work but are forced to leave after 3 days. The remaining work was done by A in: |
| Answer» (B + C)'s 1 day's work = 1 + 1 = 7 . 9 12 36 Work done by B and C in 3 days = 7 x 3 = 7 . 36 12 Remaining work = 1 - 7 = 5 . 12 12 Now, 1 work is done by A in 1 day. 24 So, 5 work is done by A in 24 x 5 = 10 days. 12 12 | |
| 12. |
X can do a piece of work in 40 days. He works at it for 8 days and then Y finished it in 16 days. How long will they together take to complete the work? |
| Answer» Work done by X in 8 days = 1 x 8 = 1 . 40 5 Remaining work = 1 - 1 = 4 . 5 5 Now, 4 work is done by Y in 16 days. 5 Whole work will be done by Y in 16 x 5 = 20 days. 4 X's 1 day's work = 1 , Y's 1 day's work = 1 . 40 20 (X + Y)'s 1 day's work = 1 + 1 = 3 . 40 20 40 Hence, X and Y will together complete the work in 40 = 13 1 days. 3 3 | |
| 13. |
A and B can do a job together in 7 days. A is 1 times as efficient as B. The same job can be done by A alone in : |
| Answer» (A's 1 day's work) : (B's 1 day's work) = 7 : 1 = 7 : 4. 4 Let A's and B's 1 day's work be 7x and 4x respectively. Then, 7x + 4x = 1 11x = 1 x = 1 . 7 7 77 A's 1 day's work = 1 x 7 = 1 . 77 11 | |
| 14. |
A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work alone in 44 days. In how many days shall B finish the whole work alone? |
| Answer» Let A's 1 day's work = x and B's 1 day's work = y. Then, x + y = 1 and 16x + 44y = 1. 30 Solving these two equations, we get: x = 1 and y = 1 60 60 B's 1 day's work = 1 . 60 Hence, B alone shall finish the whole work in 60 days. | |
| 15. |
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be: |
| Answer» Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y. Then, 6x + 8y = 1 and 26x + 48y = 1 . 10 2 Solving these two equations, we get : x = 1 and y = 1 . 100 200 (15 men + 20 boy)'s 1 day's work = 15 + 20 = 1 . 100 200 4 15 men and 20 boys can do the work in 4 days. | |
| 16. |
A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it? |
| Answer» A's 1 hour's work = 1 ; 4 (B + C)'s 1 hour's work = 1 ; 3 (A + C)'s 1 hour's work = 1 . 2 (A + B + C)'s 1 hour's work = 1 + 1 = 7 . 4 3 12 B's 1 hour's work = 7 - 1 = 1 . 12 2 12 B alone will take 12 hours to do the work. | |
| 17. |
A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in: |
| Answer» Suppose A, B and C take x, x and x days respectively to finish the work. 2 3 Then, 1 + 2 + 3 = 1 x x x 2 6 = 1 x 2 x = 12. So, B takes (12/2) = 6 days to finish the work. | |
| 18. |
A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in : |
| Answer» (A + B)'s 1 day's work = 1 + 1 = 1 . 15 10 6 Work done by A and B in 2 days = 1 x 2 = 1 . 6 3 Remaining work = 1 - 1 = 2 . 3 3 Now, 1 work is done by A in 1 day. 15 2 work will be done by a in 15 x 2 = 10 days. 3 3 Hence, the total time taken = (10 + 2) = 12 days. | |
| 19. |
A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work? |
| Answer» 2(A + B + C)'s 1 day's work = 1 + 1 + 1 = 15 = 1 . 30 24 20 120 8 Therefore, (A + B + C)'s 1 day's work = 1 = 1 . 2 x 8 16 Work done by A, B, C in 10 days = 10 = 5 . 16 8 Remaining work = 1 - 5 = 3 . 8 8 A's 1 day's work = 1 - 1 = 1 . 16 24 48 Now, 1 work is done by A in 1 day. 48 So, 3 work will be done by A in 48 x 3 = 18 days. 8 8 | |
| 20. |
A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work in : |
| Answer» Ratio of rates of working of A and B = 2 : 1. So, ratio of times taken = 1 : 2. B's 1 day's work = 1 . 12 A's 1 day's work = 1 ; (2 times of B's work) 6 (A + B)'s 1 day's work = 1 + 1 = 3 = 1 . 6 12 12 4 So, A and B together can finish the work in 4 days. | |
| 21. |
Twenty women can do a work in sixteen days. Sixteen men can complete the same work in fifteen days. What is the ratio between the capacity of a man and a woman? |
| Answer» (20 x 16) women can complete the work in 1 day. 1 woman's 1 day's work = 1 . 320 (16 x 15) men can complete the work in 1 day. 1 man's 1 day's work = 1 240 So, required ratio = 1 : 1 240 320 = 1 : 1 3 4 = 4 : 3 (cross multiplied) | |
| 22. |
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in: |
| Answer» (A + B)'s 1 day's work = 1 10 C's 1 day's work = 1 50 (A + B + C)'s 1 day's work = 1 + 1 = 6 = 3 . .... (i) 10 50 50 25 A's 1 day's work = (B + C)'s 1 day's work .... (ii) From (i) and (ii), we get: 2 x (A's 1 day's work) = 3 25 A's 1 day's work = 3 . 50 B's 1 day's work 1 - 3 = 2 = 1 . 10 50 50 25 So, B alone could do the work in 25 days. | |
| 23. |
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work? |
| Answer» Whole work is done by A in 20 x 5 = 25 days. 4 Now, 1 - 4 i.e., 1 work is done by A and B in 3 days. 5 5 Whole work will be done by A and B in (3 x 5) = 15 days. A's 1 day's work = 1 , (A + B)'s 1 day's work = 1 . 25 15 B's 1 day's work = 1 - 1 = 4 = 2 . 15 25 150 75 So, B alone would do the work in 75 = 37 1 days. 2 2 | |
| 24. |
A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. All the machines are started at 9 A.M. while machine P is closed at 11 A.M. and the remaining two machines complete work. Approximately at what time will the work (to print one lakh books) be finished ? |
| Answer» (P + Q + R)'s 1 hour's work = 1 + 1 + 1 = 37 . 8 10 12 120 Work done by P, Q and R in 2 hours = 37 x 2 = 37 . 120 60 Remaining work = 1 - 37 = 23 . 60 60 (Q + R)'s 1 hour's work = 1 + 1 = 11 . 10 12 60 Now, 11 work is done by Q and R in 1 hour. 60 So, 23 work will be done by Q and R in 60 x 23 = 23 hours 2 hours. 60 11 60 11 So, the work will be finished approximately 2 hours after 11 A.M., i.e., around 1 P.M. | |
| 25. |
A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is : |
| Answer» A's 1 day's work = 1 ; 15 B's 1 day's work = 1 ; 20 (A + B)'s 1 day's work = 1 + 1 = 7 . 15 20 60 (A + B)'s 4 day's work = 7 x 4 = 7 . 60 15 Therefore, Remaining work = 1 - 7 = 8 . 15 15 | |
| 26. |
A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in: |
| Answer» (A + B + C)'s 1 day's work = 1 , 4 A's 1 day's work = 1 , 16 B's 1 day's work = 1 . 12 C's 1 day's work = 1 - 1 + 1 = 1 - 7 = 5 . 4 16 12 4 48 48 So, C alone can do the work in 48 = 9 3 days. 5 5 | |
| 27. |
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in: |
| Answer» Ratio of times taken by A and B = 1 : 3. The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day. If difference of time is 2 days, B takes 3 days. If difference of time is 60 days, B takes 3 x 60 = 90 days. 2 So, A takes 30 days to do the work. A's 1 day's work = 1 30 B's 1 day's work = 1 90 (A + B)'s 1 day's work = 1 + 1 = 4 = 2 30 90 90 45 A and B together can do the work in 45 = 22 1 days. 2 2 | |
| 28. |
P can complete a work in 12 days working 8 hours a day. Q can complete the same work in 8 days working 10 hours a day. If both P and Q work together, working 8 hours a day, in how many days can they complete the work? |
| Answer» P can complete the work in (12 x 8) hrs. = 96 hrs. Q can complete the work in (8 x 10) hrs. = 80 hrs. P's1 hour's work = 1 and Q's 1 hour's work = 1 . 96 80 (P + Q)'s 1 hour's work = 1 + 1 = 11 . 96 80 480 So, both P and Q will finish the work in 480 hrs. 11 Number of days of 8 hours each = 480 x 1 = 60 days = 5 5 days. 11 8 11 11 | |
| 29. |
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is: |
| Answer» Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4. Suppose Tanya takes x days to do the work. 5 : 4 :: 20 : x x = 4 x 20 5 x = 16 days. Hence, Tanya takes 16 days to complete the work. | |
| 30. |
A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day? |
| Answer» A's 2 day's work = 1 x 2 = 1 . 20 10 (A + B + C)'s 1 day's work = 1 + 1 +1 = 6 = 1 . 20 30 60 60 10 Work done in 3 days = 1 + 1 = 1 . 10 10 5 Now, 1 work is done in 3 days. 5 Whole work will be done in (3 x 5) = 15 days. | |