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A 50 Hz current has an amplitude of 25 A. The rate of change of current at t = 0.005 after i = 0 and is increasing is ____________(a) 2221.44 A/s(b) 0(c) -2221.44 A/s(d) -3141.6 A/sThis question was addressed to me during an interview for a job.I would like to ask this question from Series-Parallel Interconnection of Two Port Network topic in section Two-Port Networks of Network Theory

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Correct ANSWER is (b) 0

The EXPLANATION: The CURRENT i (t) is given by,

i = 25 sin 314.16 t and \(\FRAC{di}{dt}\) = 250 X 314.16 cos⁡ωt

Now, at t = 0.005, I = 25 X 314.16 cos (314.16 X 0.005)

= 0.



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