A parallel RLC circuit with R1 = 20, L1 = \(\frac{1}{100}\) and C1 = \(\frac{1}{200}\) is scaled giving R2 = 10^4, L2 = 10^-4 and C2, the value of C2 is ___________(a) 0.10 nF(b) 0.3 nF(c) 0.2 nF(d) 0.4 nFThis question was addressed to me in an interview for internship.My question comes from Series-Parallel Interconnection of Two Port Network in section Two-Port Networks of Network Theory

A parallel RLC circuit with R1 = 20, L1 = \(\frac{1}{100}\) and C1 = \

1.	A parallel RLC circuit with R1 = 20, L1 = \(\frac{1}{100}\) and C1 = \(\frac{1}{200}\) is scaled giving R2 = 10^4, L2 = 10^-4 and C2, the value of C2 is ___________(a) 0.10 nF(b) 0.3 nF(c) 0.2 nF(d) 0.4 nFThis question was addressed to me in an interview for internship.My question comes from Series-Parallel Interconnection of Two Port Network in section Two-Port Networks of Network Theory
Answer» The correct answer is (c) 0.2 nF For explanation I WOULD SAY: K1 = \(\frac{R_2}{R_1}\) = \(\frac{10^4}{20}\) = 5 X 10^2 = 500 Ω And \(\frac{L_1}{L_2}= \frac{kω}{k_1}\) Or, \(\frac{kω}{k_1} =\frac{L_1}{L_2}X k_1\) Or, \(\frac{10^{-2}}{10^{-4} X 5 X 10^2}\) = 5 X 10^4 Or, C2 = \(\frac{C_1}{kω.k_1} = \frac{0.5 X 10^{-2}}{5 X 10^4 X 500}\) = 0.02 X 10^-8 = 0.2 nF.

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