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Find the Y – parameter Y12 in the circuit shown below.(a) 1/2(b) -1/2(c) -1/4(d) 1/4The question was posed to me in a national level competition.Question is from Short Circuit Admittance(Y) Parameters in portion Two-Port Networks of Network Theory

Answer»

The CORRECT answer is (c) -1/4

Easy explanation: Short circuiting a-a’, -I1 = 2/5 I2 and I2 = 5 V2/8. On solving -I1 = 2/5×5/8 V2 = V2/4. We know Y12 = I1/V2. We GOT I1/V2 = -1/4. So the value of Y12 will be -1/4 mho.



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