For the 2 port network as shown below, the Z-matrix is ___________(a) [Z1; Z1 + Z2; Z1 + Z2; Z3](b) [Z1; Z1; Z1 + Z2; Z2](c) [Z1; Z2; Z2; Z1 + Z2](d) [Z1; Z1; Z1; Z1 + Z2]I got this question at a job interview.My doubt stems from Inverse Hybrid (g) Parameter topic in section Two-Port Networks of Network Theory

For the 2 port network as shown below, the Z-matrix is ___________(a)

1.	For the 2 port network as shown below, the Z-matrix is ___________(a) [Z1; Z1 + Z2; Z1 + Z2; Z3](b) [Z1; Z1; Z1 + Z2; Z2](c) [Z1; Z2; Z2; Z1 + Z2](d) [Z1; Z1; Z1; Z1 + Z2]I got this question at a job interview.My doubt stems from Inverse Hybrid (g) Parameter topic in section Two-Port Networks of Network Theory
Answer» The correct OPTION is (d) [Z1; Z1; Z1; Z1 + Z2] To explain I WOULD say: z11 = \(\FRAC{V_1}{I_1}\), when I2 = 0 z22 = \(\frac{V_2}{I_2}\), when I1 = 0 z12 = \(\frac{V_1}{I_2}\), when I1 = 0 z21 = \(\frac{V_2}{I_1}\), when I2 = 0 Now, in the given CIRCUIT putting I1 = 0, we get, z12 = Z1 and z22 = Z1 + Z2 And putting I2 = 0, we get, z21 = Z1 and z11 = Z1.

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