For the circuit given below, the value of the g12 and g22 are _______________(a) g12 = –\(\frac{R_2}{R_1+R_2}\), g22 = R3 + \(\frac{R_1 R_2}{R_1+R_2}\)(b) g12 = \(\frac{R_2}{R_1+R_2}\), g22 = -R3 + \(\frac{R_1 R_2}{R_1+R_2}\)(c) g12 = –\(\frac{R_2}{R_1+R_2}\), g22 = R3 – \(\frac{R_1 R_2}{R_1+R_2}\)(d) g12 = \(\frac{R_2}{R_1+R_2}\), g22 = -R3 – \(\frac{R_1 R_2}{R_1+R_2}\)The question was posed to me during an interview.Asked question is from Advanced Problems Involving Parameters in division Two-Port Networks of Network Theory

For the circuit given below, the value of the g12 and g22 are ________

1.	For the circuit given below, the value of the g12 and g22 are _______________(a) g12 = –\(\frac{R_2}{R_1+R_2}\), g22 = R3 + \(\frac{R_1 R_2}{R_1+R_2}\)(b) g12 = \(\frac{R_2}{R_1+R_2}\), g22 = -R3 + \(\frac{R_1 R_2}{R_1+R_2}\)(c) g12 = –\(\frac{R_2}{R_1+R_2}\), g22 = R3 – \(\frac{R_1 R_2}{R_1+R_2}\)(d) g12 = \(\frac{R_2}{R_1+R_2}\), g22 = -R3 – \(\frac{R_1 R_2}{R_1+R_2}\)The question was posed to me during an interview.Asked question is from Advanced Problems Involving Parameters in division Two-Port Networks of Network Theory
Answer» RIGHT ANSWER is (a) g12 = –\(\FRAC{R_2}{R_1+R_2}\), g22 = R3 + \(\frac{R_1 R_2}{R_1+R_2}\) The EXPLANATION is: I1 = –\(\frac{R_2}{R_1+R_2}\)I2 Or, g12 = \(\frac{I_1}{I_2} = -\frac{R_2}{R_1+R_2}\) Also, I2 (R3 + R1 //R2) = I2 \((R_3 + \frac{R_1 R_2}{R_1+R_2})\) ∴ g22 = \(\frac{V_2}{I_2} = R_3 + \frac{R_1 R_2}{R_1+R_2}\).

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