1.

For the circuit given below, the value of the Inverse hybrid parameter g11 is ___________(a) 0.067 Ω(b) 0.025 Ω(c) 0.3 Ω(d) 0.25 ΩThe question was asked during an online exam.Origin of the question is Inverse Hybrid (g) Parameter in portion Two-Port Networks of Network Theory

Answer»

Right answer is (a) 0.067 Ω

The EXPLANATION is: INVERSE Hybrid parameter g11 is given by, g11 = \(\frac{I_1}{V_1}\), when I2 = 0.

Therefore SHORT circuiting the terminal Y-Y’, we get,

 V1 = I1 ((10||10) + 10)

= I1 \(\left(\left(\frac{10×10}{10+10}\right)+10\right)\)

= 15I1

∴ \(\frac{I_1}{V_1} = \frac{1}{15}\) = 0.067 Ω

Hence g11 = 15 Ω.



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