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For the circuit given below, the value of z22 parameter is ____________(a) z22 = 4 + j6 Ω(b) z22 = j6 Ω(c) z22 = -j4 Ω(d) z22 =-j6 + 4 ΩI have been asked this question in an interview.I would like to ask this question from Advanced Problems on Two Port Network in division Two-Port Networks of Network Theory

Answer»

The correct answer is (c) z22 = -J4

Explanation: z12 = j6 = z21

Z11 – z12 = 4

Or, z11 = z12 + 4 = 4 + j6 Ω

And z22 – z12 = -j10

Or, z22 = z12 + -j10 = -j4 Ω

∴ [Z] = [4+j6:j6; j6:-j4] Ω.



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