1.

If a two port network is passive, then we have, with the usual notation, the relationship as _________(a) h21 = h12(b) h12 = -h21(c) h11 = h22(d) h11 h22 – h12 h22 = 1This question was posed to me in an interview for job.The question is from Advanced Problems on Two Port Network in portion Two-Port Networks of Network Theory

Answer»

Correct OPTION is (d) h11 h22 – h12 h22 = 1

The EXPLANATION: We know that, I1 = y11 V1 + y12 V2 ……… (1)

I2 = y21 V1 + y22 V2 ………. (2)

And, V1 = h11 I1 + h12 V2 ………. (3)

I2 = h21 I1 + h22 V2 ……….. (4)

Now, (3) and (4) can be rewritten as,

I1 = \(\frac{V_1}{h_{11}}– \frac{h_{12} V_2}{h_{11}}\)………. (5)

And I2 = \(\frac{h_21 V_1}{h_11}+ \left(- \frac{h_{21} h_{12}}{h_{11}} + h_{22}\right) V_2\) ………. (6)

Therefore using the above 6 equations in representing the hybrid parameters in terms of the Y parameters and applying ∆Y = 0, we get,

h11 h22 – h12 h22 = 1 [hence proved].


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