InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
`1`mol of `Cl_(2)` and `3` mol of `PCl_(5)` are placed in a `100 L` vessel heated to `227^(@)C`. The equilibrium pressure is `2.05` atm. Assuming ideal behaviour, calculate the degree of dissociation for `PCl_(5)` and `K_(p)` for the reaction. `PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g)` |
|
Answer» Correct Answer - 0.33 |
|
| 2. |
The change in pressure will not affect the equilibrium constant forA. `N_(2)+3H_(2) hArr 2NH_(3)`B. `PCI_(5) hArr PCI_(3) +CI_(2)`C. `H_(2)+I_(2) hArr 2HI`D. All of these |
| Answer» Correct Answer - D | |
| 3. |
The equation for the reaction in the figure given below is `AB_(5)(g)+Heat hArrAB_(3)(g)+B_(2)(g)` At time three minutes what change was imposed into the equilibrium?A. Pressure was increasedB. Temperature was increasedC. `B_(2)` was added to the systemD. `AB_(3)` was added to the system |
|
Answer» Correct Answer - A |
|
| 4. |
In a 500mL falsk, the degree of dissociation of `PCI_(5)` at equilibrium is `40%` and the initial amount is 5 moles. The value of equilibrium constant in mol `L^(-1)` for the decomposition of `PCI_(5)` isA. `2.33`B. `2.66`C. `5.32`D. `4.66` |
|
Answer» Correct Answer - B `{:(,PCI_(5),hArr,PCI_(3),+,CI_(2)),("Initial moes",5,,0,,0),("Moles at equilibrium",5(1-alpha),,5alpha,,5alpha),("Conc. at equilibrium",(5(1-alpha))/(0.5),,(5alpha)/(0.5),,(5alpha)/(0.5)):}` `alpha = 40% = 0.4` `K_(C) = ([PCI_(3)][CI_(2)])/([PCI_(5)]) =(((5xx 0.4)/(0.5)))/(((5xx0.6)/(0.5))) =2.66 mol//L` |
|
| 5. |
Consider the following reversible system: `A(g)+2B(g)hArrC(g)+2D(g)` At equilibrium there are 1.0 mole of A and 2.0 moles of each B, C and D present. If 2.0 moles of B is added so that moles of A and D do not change? |
|
Answer» Correct Answer - 6 |
|
| 6. |
To determine molar solubility of an unknown metal hydroxide, `M(OH)_(3)` in `0.00101M NaOH,` Jane adds `0.250g` of `M(OH)_(3)` solid to `200mL` of a `0.00101M NaOH` solution and stirred for a long time.A cloudy solution is formed. The undissolved hydroxide is separated from the solution by filtratin `25.00mL` of filtrate is pipetted into a flask `30mL` of water is added adn then the solution is titrated with `0.00444M HCl` solution `13mL` of `HCl` is used for this titration. If Jane carelessly added `20mL` of water tothe flask instead of `30mL` how would this affect the determination of solubility product `(K_(sp))` and molar solubility? (1) The value of `K_(sp)` determined by Jane would be same as true value (2) The value of `K_(sp)` determined by Jane would be higher than the true value. (3) The value of `K_(sp)` determined by Jane would be lower as true value. (4) The molar solubility of `M(OH)_(3)` determined by Jane woud be same as true value. (5) The molar solubility of `M(OH)_(3)` determined by Jane would be higher than true value. (6) The molar solubililty of `M(OH)_(3)` determined by Jane would be lower than the true valueA. 1 and 4B. 2 and 5C. 3 and 6D. 1 and 6 |
|
Answer» Correct Answer - A |
|
| 7. |
An aqueous solution of a metal bromide `MBr_(2)(0.05M)` is saturated with `H_(2)S`. What is the minimum pH at which MS will precipitate ? `K_(SP)` for `M S= 6.0xx10^(-21)` . Concentration of saturqated `H_(2)S=0.1M, K_(1)=10^(-7)and K_(2)=1.3xx10^(-13)` for `H_(2)S` . |
|
Answer» Correct Answer - 1 |
|
| 8. |
`(CH_(3)(OH)_(2)^(1))` is..acidic than `(CH_(3)NH_(3)^(+))`. |
|
Answer» Correct Answer - more |
|
| 9. |
The conjugate acid of amide ion `(NH_(2)^(-))` isA. `NH_(3)`B. `NH_(2)OH`C. `NH_(4)^(+)`D. `N_(2)H_(4)` |
|
Answer» Correct Answer - A |
|
| 10. |
Which of the following relations represent correct relation between standard electrode potential and equilibrium constant ? I. `logK = (nFE^(@))/(2303 RT)` II. `K = e^(-(nFE^(@))/(RT))` III. `log K = (-nFE^(@))/(2303 RT)` IV. `log K = 0.4342 (nFE^(@))/(RT)`A. I,II and IIIB. II and IIIC. I, II and IVD. I and IV |
|
Answer» Correct Answer - C `DeltaG =- 2.303 RT log K, -nFR^(@) =- 2.303 RT log K` `log K = (nFE^(@))/(2.303RT) = 0.4342 (nFE^(@))/(RT)` ..(v) ln `K = (nFE^(@))/(RT)` `K = (-nFE^(@))/(e^(RT))` ...(ii) |
|
| 11. |
The solubility product constant `(K_(sp))` of salts of types `MX, MX_(2)`, and `M_(3)X` at temperature `T` are `4.0 xx 10^(-8), 3.2 xx 10^(-14)`, and `2.7 xx 10^(-15)`, respectively. The solubilities of the salts at temperature `T` are in the orderA. `MX gt MX_(2) gt M_(3)X`B. `M_(3) X gt MX_(2) gt MX`C. `MX_(2) gt M_(3)X gt MX`D. `MX gt M_(3)X gt MX_(2)` |
|
Answer» Correct Answer - D |
|
| 12. |
Which of the following salts undergoes anionic hydrolysis ?A. `CuSO_(4)`B. `NH_(4)CI`C. `FeCI_(3)`D. `Na_(2)CO_(3)` |
|
Answer» Correct Answer - D Anionic hydrolysis means anion reacts with water. `Na_(2)CO_(3) +2H_(2)O hArr 2NaOH H_(2)CO_(3)` or `2Na^(+) +CO_(3)^(2-) +2H_(2)O hArr 2Na^(+) +2OH^(-) +H_(2)CO_(3)` or `CO_(3)^(2-) +2H_(2)O hArr 2OH^(-) +H_(2)CO_(3)` |
|
| 13. |
The `pH` of `0.1M` solution of the following salts decreases in the orderA. `NaCl lt NH_(4) lt NaCN lt HCl`B. `HCl lt NH_(4)Cl lt NaCl lt NaCN`C. `NaCN lt NH_(4)Cl lt NaCl lt HCl`D. `HCl lt NaCl lt NaCN lt NH_(4)Cl` |
|
Answer» Correct Answer - B |
|
| 14. |
Silver chloride is sparingly soluble in water because its lattice energy is greater than_______ |
|
Answer» Correct Answer - hydration |
|
| 15. |
`MX_(2)` dissociates into `M^(2+)` and `X^(-)` ions in an aqeous solution, with a degree dissociation `(alpha)` of 0.5. The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is |
|
Answer» Correct Answer - 2 |
|
| 16. |
The initial rate of hydrolysis of methyl acetate (1M) by a weak acid `(HA,1M)` is `1//100th` of that of a strong acid `(HX, 1M),` at `25^(@)C`. The `K_(a)(HA)` isA. `1xx10^(-4)`B. `1xx10^(-5)`C. `1xx10^(-6)`D. `1xx10^(-3)` |
|
Answer» Correct Answer - A |
|
| 17. |
Aluminium chloride `(AlCl_(3))` is a Lewis acid because it can donate electrons. |
|
Answer» Correct Answer - F |
|
| 18. |
The molar conductivity of a solution of a weak acid `HX(0.01 M)` is 10 times smalller than the molar conductivity of a solution of a weak acid `HY (0.10 M)`. If `lamda_(X^(-))^(@) =lamda_(Y^(-))^(@)`, the difference in their `pK_(a)` values, `pK_(a)(HX) - pK_(a)(HY)`, is (consider degree of ionisation of both acids to be `ltlt 1`): |
|
Answer» Correct Answer - 3 |
|
| 19. |
For the reaction `PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)` the forward reaction at constant temperature is favoured byA. introducing an inert gas at constant volumeB. introducing chlorine gas at constant volumeC. increasing the volume of the containerD. introducing `PCl_(5)` at constant volume |
|
Answer» Correct Answer - C::D |
|
| 20. |
A sample of AgCI was treated with `5.00mL` of `1.5M` `Na_(2)CO_(3)` solubility to give `Ag_(2)CO_(3)` . The remaining solution contained `0.0026g of CI^(-)` per litre. Calculate the solubility product of AgCI. `(K_(SP)for Ag_(2)CO_(3)=8.2xx10^(-12))` |
|
Answer» Correct Answer - `2xx10^(-8))` |
|
| 21. |
The conjugate base of `HSO_(4)^(-)` in aqueous solution is. |
|
Answer» Correct Answer - `SO_(4)^(2-)` |
|
| 22. |
Which of the following statement(s) is (are) correct?A. The `pH` of `1.0xx10^(-8)M` solution of `HCl` is 8B. The conugate base of `H_(2)PO_(4)^(-)` is `HPO_(4)^(2-)`C. Autoprotolysis constant of water increases with temperatureD. When a solution of a weak monoprotic acid is titrated against a strong base, at half-neutralisation point `pH=(1/2)pK_(a)` |
|
Answer» Correct Answer - B::C |
|
| 23. |
The `[Ag^(+)]` ion in a saturated solution of `Ag_(2)CrO_(4)` at `25^(@)C is 1.5xx10^(-4)M`. Determine `K_(SP)` of `Ag_(2)CrO_(4)` at `25^(@)C`.A. `3.3750 xx 10^(-12)`B. `1.6875 xx 10^(-10)`C. `1.6875 xx 10^(-12)`D. `1.6875 xx 10^(11)` |
|
Answer» Correct Answer - C `Ag_(2)CrO_(4) rarr 2Ag^(+) +CrO_(4)^(2-)` `[CrO_(4)^(2-)] = (1)/(2)[Ag^(+)]` `= (1.5 xx 10^(-4))/(2) = 0.75 xx 10^(-4)` `K_(sp) = [Ag^(+)]^(2) [CrO_(4)^(2-)]` `=(1.5 xx 10^(-4))^(2) (0.75 xx 10^(-4))` `= 1.6875 xx 10^(-12)` |
|
| 24. |
If the solubility of `Ag_(2)CrO_(4)` is S mol/L, its solubility product will beA. `S^(2)`B. `S^(3)`C. `4S^(3)`D. `2S^(3)` |
|
Answer» Correct Answer - C `underset(S mol//L)(Ag_(2)CrO_(4)) hArr underset(2s)(2Ag^(+))+underset(S)(CrO_(4)^(2-))` `K_(sp) = [Ag^(+)]^(2)[CrO_(4)^(2-)]` `=(2S)^(2) (S) = 4S^(3)` |
|
| 25. |
The `K_(SP)` of `Ag_(2)C_(2)O_(4)` at `25^(@)C` is `1.29xx10^(-11)mol^(3)L^(-3)`. A solution of `K_(2)C_(2)O_(4)` containing `0.152` mole in 500 mL water is shaken at `25^(@)C` with excess of `Ag_(2)CO_(3)` till the equilbirium is reached. `Ag_(2)CO_(3)+K_(2)C_(2)O_(4)hArrAg_(2)C_(2)O_(4)+K_(2)CO_(3)` Ar equilibrium the solution contains `0.0358` mole of `K_(2)CO_(3)`. Assuming degree of dissociation of `K_(2)C_(2)O_(4)` and `K_(2)CO_(3)` to be same, calculate `K_(SP)` of `Ag_(2)CO_(3)`. |
|
Answer» Correct Answer - `9.67x10^(-11)` |
|
| 26. |
The reaction for which `K_(C)gtK_(P)` at a given temperature is (are)A. `H_(2)(g)+I_(2)(g)to2Hl(g)`B. `2NH_(3)(g)+H_(2)S(g)to(NH_(4))_(2)S(s)`C. `N_(2)(g)+2O_(2)(g)to2NO_(2)(g)`D. `3O_(2)(g)to2O_(3)(g)` |
|
Answer» Correct Answer - B::C::D |
|
| 27. |
Which of the following solution will have `pH` greater than 7 at `25^(@)C`?A. `10mL 0.1M CH_(3)COOH+6mL0.1 M NaOH`B. `5mL 0.1 M CH_(3)COOH+5mL 0.05M Ca(OH)_(2)`C. `10mL0.1M NH_(3)+5mL0.1MHCl`D. `10mL0.1M Na_(2)CO_(3)+5mL 0.1 M HCl` |
|
Answer» Correct Answer - B::C::D |
|
| 28. |
A sulphuric acid solution has `pH = 3`. Its normality isA. `1//1000`B. `1//200`C. `1//2000`D. `1//100` |
|
Answer» Correct Answer - A `pH = 3` `[H^(+)] = 1xx 10^(-3) mol//L` `H_(2)SP_(4) rarr 2H^(+) +SO_(4)^(2-)` `[H_(2)SO_(4)] = (1 xx 10^(-3))/(2) = (1)/(2000)M` `N = 2M` (for `H_(2)SO_(4))` Normality `= (2)/(2000) = (1)/(1000) N` |
|
| 29. |
The pH of `0.01M HCN` solution for which `pK_(a)` is 4 isA. `0.47`B. `1.2`C. `3.0`D. `4.0` |
|
Answer» Correct Answer - C Given, `pK_(a) = 4` `:. K_(A) = 1xx 10^(-4)` `[H^(+)] = sqrt(K_(a) xx C) = sqrt(1xx 10^(-4) xx 0.01)` `=sqrt(10^(-6)) = 10^(-3)M` `pH =- log [H^(+)] =- log 10^(-3) = 3` |
|
| 30. |
The species present in solution when `CO_(2)` is dissolved in waterA. `CO_(2), H_(2)CO_(3), HCO_(3)^(-), CO_(3)^(2-)`B. `H_(2)CO_(3), CO_(30^(2-)`C. `HCO_(3)^(-),CO_(3)^(2-)`D. `CO_(2), H_(2)CO_(3)` |
|
Answer» Correct Answer - A |
|
| 31. |
The expression for the solubility product of `Ag_(2)CrO_(3)` will beA. `K_(sp) = S^(2)`B. `K_(sp) = 4S^(3)`C. `K_(sp) = 27S^(4)`D. `K_(sp) = S` |
|
Answer» Correct Answer - B `Ag_(2)CO_(3)(s) hArr underset(2s)(2Ag^(+)) + underset(s)(CO_(3)^(2-))` `K_(sp) = [Ag^(+)]^(2) [CO_(3)^(2-)]` `= (2S)^(2) S` `K_(sp) = 4S^(3)` |
|
| 32. |
What is the pH of a `0.50M` aqueous NaCN solution ? `(pK_(b)of CN^(-)=4.70)` |
|
Answer» Correct Answer - 11.5 |
|
| 33. |
`pK_(a)` of a weak acid `(HA)` and `pB_(b)` of a weak base `(BOH)` are 3.2 and 3.4 respectively. The `pH` of their salt (AB) solution isA. `7.2`B. `6.9`C. `7.0`D. `1.0` |
|
Answer» Correct Answer - B |
|
| 34. |
The total number of diprotic acids among the following is `H_(3)PO_(4), H_(2)SO_(4), H_(3)PO_(3)` `H_(2)CO_(3), H_(2)S_(2)O_(7), H_(3)BO_(3)` `H_(3)PO_(2), H_(2)CrO_(4), H_(2)SO_(3)` |
|
Answer» Correct Answer - 6 |
|
| 35. |
If dissociation constant of ammonia is `10^(-5)`, its `pK_(b)` and `pK_(4)` value respectively areA. 5 and 9B. 9 and 5C. 7 and 7D. 4 and 10 |
|
Answer» Correct Answer - A `K_(b)` of `NH_(3)` is `10^(-5)` (given) `:. pK_(b) = 5` and `pK_(a) = 14 - 5 = 9` Hence, `pK_(b)` and `pK_(a)` values are 5 and 9 respectively. |
|
| 36. |
`[H^(+)]` of `0.02 NCH_(3) COOH` which is `4%` dissociated, isA. `0.08M`B. `0.12 M`C. `0.008M`D. `0.8M` |
|
Answer» Correct Answer - C `alpha = 4% =(4)/(100) = 0.04`, Normality `=0.2` `:. [H^(+)] = alpha xx N = 0.04 xx 0.2 = 0.008M` |
|
| 37. |
A buffer solution can be prepared from a mixture ofA. sodium acetate and acetic acid in waterB. sodium acetate and `HCl` in waterC. ammonia and ammonium chloride in waterD. ammonia and sodium hydroxide in water |
|
Answer» Correct Answer - A::B::C |
|
| 38. |
The `pH` of `10^(-8)M` solution of `HCl` in water isA. 8B. `-8`C. between 7 and 8D. between 6 and 7 |
|
Answer» Correct Answer - D |
|
| 39. |
At `90^(@)C` pure water has `[H_(3)O^(+)]` as `10^(-6) mol L^(-1)`. What is the value of `K_(w)` at `90^(@)C`?A. `10^(-6)`B. `10^(-12)`C. `10^(-14)`D. `10^(-8)` |
|
Answer» Correct Answer - B |
|
| 40. |
Of the given anions, the strongest base isA. `ClO^(-)`B. `ClO_(2)^(-)`C. `ClO_(3)^(-)`D. `ClO_(4)^(-)` |
|
Answer» Correct Answer - A |
|
| 41. |
Which of the following is the strongest acid?A. `ClO_(3)(OH)`B. `ClO_(2)(OH)`C. `SO(OH)_(2)`D. `SO_(2)(OH)_(2)` |
|
Answer» Correct Answer - A |
|
| 42. |
Amongst the following hydroxides, the one which has the lowest value of `K_(sp)` is:A. `Mg(OH)_(2)`B. `Ca(OH)_(2)`C. `Ba(OH)_(2)`D. `Be(OH)_(2)` |
|
Answer» Correct Answer - D |
|
| 43. |
For the reaction, `SO_(2)(g)+1/2O_(2)(g)hArrSO_(3)(g)` if `K_(p)=K_(C)(RT)^(x)` where, the symbols have usual meaning, then the value of `x` is (assuming ideality)A. `-1`B. `-1/2`C. `1/2`D. `1` |
|
Answer» Correct Answer - B |
|
| 44. |
The concentration of hydrogen ions in a `0.2M` solution of formic acid is `6.4 xx 10^(-3) mol L^(-1)`. To this solution, sodium formate is added so as to adjust the concentration of sodium formate to `1 mol L^(-1)`. What will be the `pH` of this solution? The dissociation constant of formic acid is `2.4 xx 10^(-4)` and the degree of dissociation fo sodium formate is `0.75`. |
|
Answer» Correct Answer - 4.2 |
|
| 45. |
A solution contains a mixture of `Ag^(+)(0.10M)` and `Hg_(2)^(2+)(0.10M)` which are to be separated by selective precipitation. Calculate the miximum concentreation of iodide ion at which one of them gets precipitated almost completely. What % of that metal ion is precipitated ? `(K_(SP)of AgI=8.5xx10^(-17)` and `K_(SP)` of `Hg_(2)I_(2)=2.5xx10^(-26))` |
|
Answer» Correct Answer - 99.83 |
|
| 46. |
`0.1` mole of `CH_(3)NH_(2) (K_(b)=5xx10^(-4))` is mixed with `0.08` mole of `HCl` and diluted to one litre. The `[H^(+)]` in solution isA. `1.6xx10^(-11)`B. `8xx10^(-11)`C. `5xx10^(-5)`D. `8xx10^(-2)` |
|
Answer» Correct Answer - B |
|
| 47. |
For an equilibrium reaction, `N_(2)O_(4)(g) hArr 2NO_(2)(g)`, the concentrations of `N_(2)O_(4)` and `NO_(2)` at equilibrium are `4.8 xx 10^(-2)` and `1.2 xx 10^(-2) mol//L` respectively. The value of `K_(c)` for the reaction isA. `3 xx 10^(-3)mol//L`B. `3.3 xx 10^(-3) xx 10^(-3)mol//L`C. `3 xx 10^(-1) mol//L`D. `3.3 xx 10^(-1)mol//L` |
|
Answer» Correct Answer - A According to law of active mass `K_(C) = ([NO_(2)]^(2))/([N_(2)O_(4)]) = ([1.2 xx 10^(-2)]^(2))/(4.8xx 10^(-2))` `= 0.3xx 10^(-2) = 3xx 10^(-3) mol//L` |
|
| 48. |
The following concentrations were obtained for the formation of `NH_(3)` from `N_(2)` and `H_(2)` at equilibrium at `500 K`. `[N_(2)]=1.5xx10^(-2) M, [H_(2)]=3.0xx10^(-2)M,` and `[NH_(3)]=1.2xx10^(-2)M`. Calculate the equilibrium constant.A. `1.08 xx 10^(4)`B. `3.98 xx 10^(2)`C. `1.06 xx 10^(3)`D. `2.93 xx 10^(4)` |
|
Answer» Correct Answer - B The equilibrium constant for the reaction `N_(2)(g) +3H_(2) hArr 2NH_(3)(g)`can be written as `K_(C) = ([NH_(3)(g)]^(2))/([N_(2)(g)][H_(2)(g)]^(3))` `= ((1.2 xx 10^(-2))^(2))/((1.5 xx 10^(-2))(3.0 xx 10^(-2))^(3))` `= 0.0355 xx 10^(4) = 3.55 xx 10^(2)` `= 3.98 xx 10^(2)` |
|
| 49. |
The equilibrium constant at `298K` for a reaction, `A+BhArrC+D` is 100. If the initial concentrations of all the four species were 1M each, then equilibirum concentration of `D` (in mol`L^(-1)`) will beA. 0.818B. 1.818C. 1.182D. 0.182 |
|
Answer» Correct Answer - B |
|
| 50. |
If the ionisation constant of acetic acid is `1.8 xx 10^(-5)`, at what concentration will it be dissociated to `2%`?A. `1M`B. `0.018M`C. `0.18M`D. `0.045M` |
|
Answer» Correct Answer - D `{:(,CH_(3)COOHhArr,CH_(3)COO^(-),H^(+)),("initially ",C,0,0),("At equilibrium",C(1-a),Calpha,Calpha):}` `K = (Calpha. Calpha)/(C(1-alpha)) = (Calpha^(2))/(1-alpha) = Calpha^(2)` or `C = (K)/(alpha^(2)) = (1.8 xx 10^(-5))/((0.02)^(2)) = 0.045M` |
|