966 + Interview Questions in CHEMICAL-EQUILIBRIUM IN GENERAL AWARENESS Page 9 InterviewSolution

401.	For an elementary gaseous phase reaction : `2NO+O_2 hArr 2NO_2` at `27^@C` Rate of the forward reaction is given by rate `=2xx10^(3)[NO]^2 [O_2]` and rate of reverse reaction at is given by rate `=20[NO_2]^2` Hence, equilibrium constant for reaction `NO_2 hArr NO+1/2 "at"27^@C`A. 100B. `0.01`C. `0.1`D. 10
Answer» Correct Answer - C

Discussion

402.	One "mole" of `NH_(4)HS(s)` was allowed to decompose in a `1-L` container at `200^(@)C`. It decomposes reversibly to `NH_(3)(g)` and `H_(2)S(g). NH_(3)(g)` further undergoes decomposition to form `N_(2)(g)` and `H_(2)(g)`. Finally, when equilibrium was set up, the ratio between the number of moles of `NH_(3)(g)` and `H_(2)(g)` was found to be `3`. `NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g), K_(c)=8.91xx10^(-2) M^(2)` `2NH_(3)(g) hArr N_(2)(g)+3H_(2)(g), K_(c)=3xx10^(-4) M^(2)` Answer the following: What is the "mole" fraction of hydrogen gas in the equilibrium mixture in the gas phase?A. `1//4`B. `3//4`C. `1//8`D. `4`
Answer» Correct Answer - B `{:(NH_(4)HS(s),hArr,NH_(3)(g),+,H_(2)S(g),),(,,27xx10^(-2),,X):}` `K_(c)=27xx10^(-2)X=8.91xx10^(-2)` `X=(8.91xx10^(-2))/(2.7xx10^(-1))=3.3xx10^(-1)` Number of mol of `NH_(3)=0.27` `H_(2)S=0.33` `N_(2)=0.03` `H_(2)=0.09` `X_(H_(2))=0.09/0.72=1/8` `{:(2NH_(3)(g),hArr,N_(2)(g),+,3H_(2)(g)),(3a,,1/3a,,a):}` `K_(c)=((a//3)a^(3))/((3a)^(2))=a^(4)/3xx1/(9a^(2))` `a^(2)/27=3xx10^(-4)` `:. a^(2)=81xx10^(-4)` `a=9xx10^(-2)`

Discussion

403.	`N_2(g)+3H_2(g) hArr 2 NH_3(g)`.This is a gaseous phase reaction taking place in 1 L flask at `127^@C`.Starting with 1 mole of `N_2` and 3 mole of `H_2`, the equilibrium mixture obtanied is such that if it is titrated requires 500 mL of 1.0 M `H_2SO_4` for neutralisation. Which of the following is the most appropritate `K_C`?A. 0.03B. 0.59C. 0.27D. 0.11
Answer» Correct Answer - B

Discussion

404.	One "mole" of `NH_(4)HS(s)` was allowed to decompose in a `1-L` container at `200^(@)C`. It decomposes reversibly to `NH_(3)(g)` and `H_(2)S(g). NH_(3)(g)` further undergoes decomposition to form `N_(2)(g)` and `H_(2)(g)`. Finally, when equilibrium was set up, the ratio between the number of moles of `NH_(3)(g)` and `H_(2)(g)` was found to be `3`. `NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g), K_(c)=8.91xx10^(-2) M^(2)` `2NH_(3)(g) hArr N_(2)(g)+3H_(2)(g), K_(c)=3xx10^(-4) M^(2)` Answer the following: To attain equilibrium, how much `%` by weight of folid `NH_(4)HS` got dissociated?A. `19%`B. `30%`C. `33%`D. `15%`
Answer» Correct Answer - C Amount of `NH_(4)HS(s)` dissociated amount of `H_(2)S(g)` present at equilibibrium `:.` Amount of `NH_(4)HS(s)` dissociated `=0.33 "mol" %` (by weight) of `NH_(4)HS(s)` dissociated `=0.33/1xx100=33%`

Discussion

405.	n mole each of `H_(2)O(g),H_(2)(g) "and" O_(2)(g)` are mixed at a suitable high temperature to attain the equilibrium `2H_(2)O(g)hArr2H_(2)(g)+O_(2)(g)`. If `y` and mole of `H_(2)O(g)` are the dissociated and the total pressure maintained is `P`, calculate the `K_(P)`.
Answer» Correct Answer - `(P(n+y//2)(n+y)^(2))/((3n+y//2)(n-y)^(2))`

Discussion

406.	The relationship between equilibrium constants `K_(p) "and" K_(c)` for a gaseous reaction is:A. `K_(p)=K_(c).R(T)^(Deltan)`B. `K_(c)=K_(p).(RT)^(Deltan)`C. `K_(p)=K_(c).(RT)^(Deltan)`D. `mol.dm^(-3)`
Answer» Correct Answer - C

Discussion

407.	For the chemical reaction `3X(g)+Y(g) hArr X_(3)Y(g)`, the amount of `X_(3)Y` at equilibrium is affected byA. Temperature and pressureB. Temperature onlyC. Pressure onlyD. Temperature, pressure and catalyst
Answer» Correct Answer - A Factors affecting equilibrium are pressure, temperature and concentration of product or reactant.

Discussion

408.	To the system, `LaCl_(3)(s)+H_(2)O(g) hArr LaClO(s)+2HCL(g)-"Heat"` already at equilibrium, more water vapour is added without altering temperature or volume of the system. When equilibrium is re-established, the pressure of water vapour is doubled. The pressure of `HCl` present in the system increases by a factor of
Answer» Correct Answer - `sqrt(2)`times

Discussion

409.	Which of the following is correct if reaction quotient `(Q)=1`?A. `DeltaG=0`B. `DeltaG^(@)=0`C. `DeltaS^(@)=0`D. `DeltaG=DeltaG^(@)`
Answer» `DeltaG=DeltaG^(@)+RT` In `Q`, if `Q=1`, `DeltaG=DeltaG^(@)`

Discussion

410.	The moisture content of a gas is often expressed in terms of the dew point. The point is the temperature to which the gas must be cooled before the gas becomes saturated with water vapour. At this temperture, water or ice (depending on the temperature) will be deposited on a solid surface. Dew point of `H_(2)O` is `-43^(@)C` at which vapour pressure of ice formed is `0.07 mm`. Assuming that the `CaCl_(2)` owes its desicationg properties to the formation of `CaCl_(2).2H_(2)O`, calculate : (`i`) `K_(p)` at that temperature of the reaction, (`ii`) `DeltaG^(@)` `CaCl_(2(s))+2H_(2)O_((g))hArrCaCl_(2).2H_(2)O_((s))`.
Answer» (`i`) `1.178xx10^(8)atm`, (`ii`) `-35.544 kJ`,

Discussion

411.	`05` moles of `NH_(4)HS(s)` are taken in a container having air at `1` atm. On warming the closed container to `50^(@)C` the pressure attained a constant value of `1.5` atm, with some `NH_(4)HS(s)` remaining unreacted. The `K_(p)` of reaction `NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g) "at" 50^@)C` is:A. `0.25`B. `0.625`C. `0.025`D. `0.0625`
Answer» Correct Answer - D `NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g)` `P P` `2P=1.5-1` `2P=0.5` `P=0.25` `rArrK_(p)=0.25=0.0625`

Discussion

412.	Find out `InK_(eq)` for the formation of `NO_(2)` from `NO` and `O_(2)` at `298 K` `NO_(g)+(1)/(2)O_(2)hArrNO_(2)g` Given: `DeltaG_(f)^(@)(NO_(2))=52.0KJ//mol e` `Delta_(f)^(@)(NO)=87.0KJ//mol e` `Delta_(f)^(@)(O_(2))=0KJ//mol e`A. `(35xx10^(3))/(8.314xx298)`B. `-(35xx10^(3))/(8.314xx298)`C. `(35xx10^(3))/(2.303xx8.314xx298)`D. `(35xx10^(3))/(2xx298)`
Answer» Correct Answer - A `NO+(1)/(2)O_(2)hArrNO_(2)` `DeltaG_(RxH)^(@)=52-87=-35KJ` `DeltaG^(@)=-RTInK_(eq)` `InK_(eq)=(35000)/(8.314xx298).`

Discussion

413.	The dissociation of phosgene, which occurs according to the reaction, `COCI_2(g)+CO(g)+CI_2(g)` is an endothermic process. Which of the following will increase the degree of dissociation of `COCI_2`?A. Adding `CI_2` to the systemB. Adding helium to the system at constant pressureC. Decresing the temperature of the systemD. Reducing the total pressure
Answer» Correct Answer - B::D

Discussion

414.	Choose the correct options:A. Favourable conditions for formation of graphite are high pressure and low temperature from equilibrium diamond `(d=3.5g//ml)hArr` graphite `(d=2.3g//ml),Delta=-1.9kJ//"mole"`B. For reaction `N_2O_4(g)hArr2NO,(g)`, degree of dissociation `(alpha)` is `sqrt(K/(4P+K_P))` where P is equilibrium pressure.C. For reaction `CI_2(g)+3F_2(g)hArr2CIF_3(g),DeltaH=-329kJ` ,dissociation of `CIF_3(g)` will be favoured by additon of inert gas at constant pressure.D. Reaction stops at equilibrium (microscopically).
Answer» Correct Answer - B::C

Discussion

415.	In an empty cylinder piston arrangemnet, `NO_2(g)` at2 atm and `N_(2)O_(4)(g)`at 4 atm is taken and the constant pressure of 6atm and temperature, `27^circC`, is maintained. `N_2O_4(g)hArr2NO_2(g),K_(P)=20` atm at 300K Which of the following property(ies) of system will change correctly (as given ) with time?A. Density of sample will decrease.B. Average molar mass of sample will increase.C. The colour of solution becomes more and more deeper.D. Reaction will not move in any direction.
Answer» Correct Answer - A::C

Discussion

416.	For the reaction, `H_(2)(g)to 2HI(g)` `K_(2)=50.0 at 721 K`. What is the value of `Delta^(circ)` for this reaction (per mole of `H_(2))` at 721K?A. `-32.3kJ`B. `-23.5kJ`C. `-10.2kJ`D. `-0.231kJ`
Answer» Correct Answer - B

Discussion

417.	Equilibrium constant for the following equilibrium is given at `)^(@)C` . `Na_(2)HPO_(4)` . `12H_(2)O(s) hArrNa_(2)HPO_(4)` . `7H_(2)O(s) + 5H_(2)O(g)` `K_(p) = 31.25xx10^(-13)`. At equilibrium what will be partial pressure of water vapour:A. `(1)/(5)xx10^(-3)` atmB. `0.5xx10^(-3)` atmC. `5xx10^(-2)` atmD. `5xx10^(-3)` atm
Answer» Correct Answer - D `Na_(2)HPO_(4)` . `12H_(2)O(s)hArrNa_(2)HPO_(4).7H_(2)O(s)+5H_(2)O(g)` `K_(p) = 31.25xx10^(-13)` `K_(p) = (P_(H_(2)O))^(5)` `(P_(H_(2)O))^(5) =31.25xx10-13` `(P_(H_(2)O)) =(3125)^(1//5)xx(10^(-15))^(1//5)` `(P_(H_(2)O)) =5xx10^(-3)`

Discussion

418.	The theoretically computed equilibrium constant for the polymerisation of formaldehyde to glucose in aqueous solution : `6HCHO hArr C_6H_12O_6` is `1.0xx10^24` If 1 M-solution of glucose was taken, what should be the equilibrium concentration of formaldehyde ?A. `6.0xx10^(-4)M`B. `1.0xx10^(-4)M`C. `1.0xx10^(4)M`D. `(1/6)^(1//6)xx10^(-4)M`
Answer» Correct Answer - B

Discussion

419.	For a reaction, `H_2+I_2hArr 2HI` at 721 K , the value of equilibrium constant is 50. If 0.5 moles each of `H_2` and `I_2` is added to the system the value of equilibrium constant will be :A. `0.02`B. `0.2`C. 50D. 25
Answer» Correct Answer - C

Discussion

420.	At `460^(@)C, K_(C)=81` for the reaction, `SO_(2)(g)+NO_(2)(g)hArrNO(g)+SO_(3)(g)` A mixture of these gases has the following concentrations of the reactants and products: `[SO_(2)]=0.04M [NO_(2)]=0.04m` `[NO]-0.30m [SO]=0.3m` Is the system at equilibrium? If not, in which direction must the reaction proceed to reach equilibrium. What will be the molar concentrations of the four gases at equilibrium?
Answer» Correct Answer - `[SO_(2)]=0.034M;[NO_(2)]=0.034M;[NO]=0.306m;[SO_(3)]=0.306M` `SO_(2)(g)+NO_(2)(g)hArrNO(g)+SO_(3)(g) Q_(c)=((0.3)^(2))/((0.04)^(2))=56.25` `{:(0.04,0.04,0.3,0.3,),(0.04-x,0.04-x,0.3+x,0.3+x,):}` Here, `O_(C)ltK_(C)` hence reaction will proceed in forward direction to reach at state of equilibrium `K_(C)=((0.3+x)^(2))/((0.04-x)^(2))=81` `x=0.006`

Discussion

421.	`{:(Ag^+ +NH_3 hArr[Ag(NH_3)]^+,,K_1=3.5xx10^-3),([Ag(NH_3)]^+ +NH_3 hArr[Ag(NH_3)_2]^+,,K_2=1.8xx10^-3):}` then, the overall formation constant of `[Ag(NH_3)_2]^+` is :A. `6.3xx10^(-6) M`B. `6.3xx10^(6) M`C. `6.3xx10^(-9) M`D. None of these
Answer» Correct Answer - A

Discussion

422.	For reaction `XeF_6+H_2O hArr XeOF_4+2HF, K_1=4` `XeO_4+XeF_6 hArr XeOF_4 + XeO_3F_2 , K_2=100` Find equilibrium constant of `1/2XeO_4+HF hArr 1/2XeO_3F_2+1/2H_2O`
Answer» Correct Answer - 5

Discussion

423.	For the reaction `CO(g)+CI_(2)(g)hArrCOCI_(2)(g)` `K_(p)//K_(c )` is equal toA. `1//RT`B. `Rt`C. `sqrt(RT)`D. `(RT)^(2)`
Answer» Correct Answer - A `K_(p)=K_(c )(RT)^(Deltan)` `Deltan=1-2=-1` `:. K_(p)=K_(c )(RT)^(-1)` or `K_(p)/K_(c )=1/(RT)`

Discussion

424.	For the dissociation of `MgCO_(3)` as `MgCO_(3)(s) hArr MgO(s)+CO_(2)(g)`. Identify the correct option regarding extent of dissociation of `MgCO_(3)`.A. As temperature is increased, extent of dissociation decreases.B. Extent of dissociation at equilibrium will increase if equilibrium is attained at the same temperature in a container of lesser volume.C. Extent of dissociation of `MgCO_(3)` will increase if taken in a larger container.D. Extent of dissociation will remain unchanged on changing volume of the container.
Answer» Correct Answer - C

Discussion

425.	A reaction continues even after the attainment of equilibrium.
Answer» Correct Answer - True

Discussion

426.	Phosphorous pentachloride when heated in a sealed tube at `700 K` it undergoes decomposition as `PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g), K_(p)=38` atm Vapour density of the mixture is `74.25`. If pressure is increased then the equilibrium willA. Be unaffectedB. Shift in backward directionC. Shift in forward directionD. Cannot be predicted
Answer» Correct Answer - B On increasing pressure, the equilibrium shift in such side which have lesser number of molecules i.e., backward direction.

Discussion

427.	Phosphorous pentachloride when heated in a sealed tube at `700 K` it undergoes decomposition as `PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g), K_(p)=38` atm Vapour density of the mixture is `74.25`. Equilibrium constant `K_(c)` for the reaction will beA. `0.66 M`B. `0.56 M`C. `0.46 M`D. `0.36 M`
Answer» Correct Answer - A `K_(p)=K_(c)(RT)^(Deltan), Deltan=3-1=2` `:. K_(p)=K_(c)(RT)^(2)` or `K_(c)=K_(p)/((RT)^(2))=38/((8.314xx700)^(2))`

Discussion

428.	The vapour density of the equilibrium mixture of the reaction: `SO_(2)Cl_(2)(g)hArrSO_(2)(g)+Cl_(2)(g)` is `50`. The percent dissociation of `SO_(2)Cl_(2)` isA. `33.33%`B. `66.67%`C. `30.0%`D. `35.0%`
Answer» Correct Answer - D `50=((64+71))/((1+alpha)) = (135)/((1+alpha))` or `1+alpha =(135)/(2xx50)=1.35` `alpha = 0.35 implies 35.0%`

Discussion

429.	Phosphorous pentachloride when heated in a sealed tube at `700 K` it undergoes decomposition as `PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g), K_(p)=38` atm Vapour density of the mixture is `74.25`. When an inert gas is added to the given reversible process, then the equilibrium will.A. Be unaffectedB. Shift in backward directionC. Shift in forward directionD. Cannot be predicted
Answer» Correct Answer - C Reaction shift in forward direction.

Discussion

430.	Decomposition of ammonium chloride is an endothermic reaction. The equilibrium may be represented as: `NH_(4)Cl(s) hArr NH_(3)(g)+HCl(g)` A `6.250 g` sample of `NH_(4)Cl` os placed in an evaculated `4.0 L` container at `27^(@)C`. After equilibrium the total pressure inside the container is `0.820` bar and some solid remains in the container. Answer the followings The value of `K_(p)` for the reaction at `300 K` isA. `16.2`B. `0.168`C. `1.68`D. `32.4`
Answer» Correct Answer - B `P_(NH_(3))=P_(HCl)=0.820/2` bar `:. K_(p)=P_(NH_(3))xxP_(HCl)=0.41xx0.41=0.168`

Discussion

431.	Decomposition of ammonium chloride is an endothermic reaction. The equilibrium may be represented as: `NH_(4)Cl(s) hArr NH_(3)(g)+HCl(g)` A `6.250 g` sample of `NH_(4)Cl` os placed in an evaculated `4.0 L` container at `27^(@)C`. After equilibrium the total pressure inside the container is `0.820` bar and some solid remains in the container. Answer the followings The value of `K_(p)` for the reaction decreases withA. Increase in volumeB. Decrease in temperatureC. Decrease in pressureD. Increase in temperature
Answer» Correct Answer - B For endothermic reaction, `K_(p)` decreases with decrease in temperature.

Discussion

432.	What is the equilibrium expression for the reaction `P_(4(s)) + 5O_(2(g))hArrP_(4)O_(10(s))` ?A. `K_(C)=[P_(4)O_(10)]//[P_(4)][O_(2)]^(5)`B. `K_(C)=1//[O_(2)]^(5)`C. `K_(C)=[O_(2)]^(5)`D. `K_(C)=[P_(4)O_(10)]//5[P_(4)][O_(2)]`
Answer» Correct Answer - B `P_(4)(g)+5O_(2)(g)hArrP_(4)O_(10)(g) K_(C)=([P_(4)O_(10)(s)])/([P_(4)(s)][O_(2)(g)])^(5)`

Discussion

433.	Assertion: The m.pt. of ice is lowered on increasing the pressure, whereas m.pt. of solids other than ice is raised upon increasing pressure. Reason: Ice shows H-bonding and leads to three dimensional solid of more volume.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explanation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true.
Answer» Correct Answer - A Ice `hArr` Water `V_(s) gt V_(w)` Thus, forward reaction occurs on increasing pressure, i.e., more ice will melt or m.pt.is lowered. Solid `hArr` Liquid `V_(s) lt V_(L)` Thus, more solid will be formed on increasing pressure.

Discussion

434.	Assertion: Water boils at higher temperature in pressure cooker. Reason: Increase in pressure leads to an increase in boiling temperature.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explanation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true.
Answer» Correct Answer - A Boiling of a liquid occurs when its vapour pressure becomes equal to atmospheric pressure.

Discussion

435.	For the reaction , `CO(g)+Cl(g)hArrCOCl_2(g)` then `K_p//K_c` is equal to :A. `1/(RT)`B. `1.0`C. `sqrt(RT)`D. RT
Answer» Correct Answer - A

Discussion

436.	The active mass of `64 g` of `HI` in a `2-L` flask would beA. `2`B. `1`C. `5`D. `0.25`
Answer» Correct Answer - D Active mass = Concentration `= "mol" L^(-1)` `[HI]=64/(128xx2)=0.25 M`

Discussion

437.	Based on the equilibrium constant for the reaction below : `2SO_3(g)hArr2SO_2(g)+O_2(g) " " K=1.8xx10^(-5)` What is the equilibrium constant for the reaction `SO_2(g)+1/2O_2(g)hArr SO_3(g) " " K=?`A. `2.1xx10^(-3)`B. `4.2xx10^(-3)`C. `2.4xx10^(2)`D. `5.6xx10^(4)`
Answer» Correct Answer - D

Discussion

438.	High pressure and low temperature are favourable conditions for the synthesis of ammonia.
Answer» Correct Answer - True

Discussion

439.	The value of K does not depends upon pressure.
Answer» Correct Answer - True

Discussion

440.	`0.5 mol` of `H_(2)` and `0.5` mol of `I_(2)` react in `10 L` flask at `448^(@)C`. The equilibrium constant `(K_(c ))` is `50` for `H_(2)+I_(2) hArr 2HI` a. What is the value of `K_(p)`? b. Calculate the moles of `I_(2)` at equilibrium.
Answer» `{:(,H_(2),+,I_(2),hArr,2HI),("moles at t=0",0.5,,0.5,,0),("moles at equilibrium",(0.5-x),,(0.5-x),,2x):}` `:. K_(p)=K_(c )=(4x^(2))/((0.5-x)^(2))` Note: Volume term is eliminated, if `Deltan=0`. a. `K_(p)=K_(c ) ( :. Deltan=0)` `:. K_(p)=50` b. `50=(4x^(2))/((0.5-x)^(2))` or `(2x)/((0.5-x))=sqrt(50)` `:. x=0.39` `:.` "moles" of `I_(2)` at equilibrium `=0.50-0.39=0.11 "mol"`

Discussion

441.	Calculate the expression for `K_(C) "and" K_(P)` if initially a moles of `N_(2) "and" B "moles of" H_(2)` is taken for the following reaction. `N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) (Deltanlt0)` (P,T,V given)
Answer» Correct Answer - `K_(c)=(4X^(2)V^(2))/((a-x)(b-3x)^(3)):K_(P)=((a+b-2x)^(2).4x^(2))/P^(2(a-x)(b-3x)^(3)` `N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) (Deltanlt0)` (P.T.V given) `{:(At t=0,a,b,0),(t=t_(eq),(a-x)(b-3x),2x,):}` `[N_(2)]=(a-x)/(V), [H_(2)] =(b-3x)/(V), [NH_(3)]=(2x)/(V)` `K_(C)=(((2x)/(V))^(2))/(((1-x)/(V))((b-3x)/(V))^(3))=(4x^(2)V^(2))/((a-x)(b-3x)^(3))` Total no. of moles at equilibrium`=a+b-2x` `[P_(N_(2)]]=(a-x)/(a+b-2x). P, [P_(H_(2)]]=((b-3x))/(a+b-2x).P, [P_(NH_(3)]]=((2x).P)/(a+b-2x)` `K_(P)=[P_(NH_(3)]]^(2)/([P_(N_(2)]][P_(H_(2)]]^(3))=(((2x)/(a+b-2x).P)^(2))/([((a-x)/(a+b-2x)).P][((b-3x)P)/(a+b-2x)]^(3))` `((4x^(2).P^(2))/((a+b-2x)^(2)))/(P^(4)((a-x)(b-3x)^(3))/((a+b-2x)^(4)))=((a+b-2x)^(2).4x^(2))/P^(2(a-x)(b-3x)^(3))`

Discussion

442.	When ethyl alcohol `(C_2H_5OH(l))` and acetic acid `(CH_3COOH(l))` are mixed together in equimolar ratio at `27^@C` , 33% of each is converted into ester.Then the `K_C` for the equilibrium, `C_2H_5OH(l))+CH_3CHOOH(l) hArrCH_3COOC_2H_5(l)+H_2O(l)`A. 4B. `1/4`C. 9D. `1/9`
Answer» Correct Answer - B

Discussion

443.	Each question contains STATEMENT-1 (Assertion) and STATEMENT-2( Reason). Examine the statements carefully and mark the correct answer according to the instruction given below: STATEMENT-1: The melting point of ice decreases with increase of pressure. STATEMENT-2: Ice contracts on melting .A. If both the statements are TRUE and STATEMENT-2 is the correct explanation of STATEMENT-1B. If both the statement are TRUE but STATEMENT-2 is NOT the correct explanation of STATEMENT-1C. If STATEMENT-1 is TRUE and STATEMENT-2 is FALSED. If STATEMENT-1 is FALSE and STATEMENT-2 is TRUE
Answer» Correct Answer - A

Discussion

444.	Each question contains STATEMENT-1 (Assertion) and STATEMENT-2( Reason). Examine the statements carefully and mark the correct answer according to the instruction given below: STATEMENT-1: The equilibrium of `A(g) iffB(g)+c(g)` is not affected by changing the volume. STATEMENT-2: `K_(c)` for the reaction does not depend on volume of the container.A. If both the statements are TRUE and STATEMENT-2 is the correct explanation of STATEMENT-1B. If both the statement are TRUE but STATEMENT-2 is NOT the correct explanation of STATEMENT-1C. If STATEMENT-1 is TRUE and STATEMENT-2 is FALSED. If STATEMENT-1 is FALSE and STATEMENT-2 is TRUE
Answer» Correct Answer - D

Discussion

445.	Each question contains STATEMENT-1 (Assertion) and STATEMENT-2( Reason). Examine the statements carefully and mark the correct answer according to the instruction given below: STATEMENT-1:For a chemical reaction at initial stage rate of forward reaction (`r_(f)`) is greater than rate of reversed reaction(`r_(b)`) STATEMENT-2: When `r_(f)=r_(b)`,chemical reaction is at equilibrium.A. If both the statements are TRUE and STATEMENT-2 is the correct explanation of STATEMENT-1B. If both the statement are TRUE but STATEMENT-2 is NOT the correct explanation of STATEMENT-1C. If STATEMENT-1 is TRUE and STATEMENT-2 is FALSED. If STATEMENT-1 is FALSE and STATEMENT-2 is TRUE
Answer» Correct Answer - B

Discussion

446.	In areversible reaction, study of its mechanism says that both the forward and reverse reaction follows first-order kinetics. If the halflife of forward reaction `(t_(1//2))_(f)` is `400 s` and that of reverse reaction `(t_(1//2))_(b)` is `250 s`, the equilibrium of the reaction isA. `1.6`B. `0.433`C. `0.625`D. `1.109`
Answer» Correct Answer - C `t_(1//2)=0.693/K` (for first-order kinetics) `K_(f)=0.693/400 s^(-1), K_(b)=0.693/250 s^(-1)` `K=K_(f)/K_(b)=250/400=0.625`

Discussion

447.	`K_(p) "is" atm^(2)` for the reaction: `LiCI.3NH_(3)(s)hArrLiCI.NH_(3)(s)+2NH_(3)(g) "at" 40^(@)C`. How many moles of ammonia must be added at this temperature to a `5` litre flask containing `0.1` mole of LiCI. `NH_(3)` in order to completely convert the solid to `LiCI.3NH_(3)`?
Answer» Correct Answer - `0.78` mole

Discussion

448.	In a flask, colourless `N_(2)O_(4)` is in equilibrium with brown-coloured `NO_(2)`. At equilibrium, when the flask is heated to `100^(@)C` the brown colour deepens and on cooling, the brown colour became less coloured. The change in enthalpy `DeltaH` for the ayatem isA. NagativeB. PositiveC. ZeroD. Not defined
Answer» Correct Answer - A The reaction Is endothermic in nature because on decreasing temperature the reaction becomes slow.

Discussion

449.	`A(g)hArr B(g)+C(g),K_C=10^(-8)` `C(g)hArr D(g),K_C=10^(-5)` 1 mole of A(g) is taken in a closed container of volume 1 litre at temperature T. If concentration of D at equilibrium is `10^(-x)`, then , calculate value of x.
Answer» Correct Answer - 9

Discussion

450.	For the reaction, `A+B hArr 2C, 2` mol of `A` and `3` mol of `B` are allowed to react. If the equilibrium constant is `4` at `400^(@)C`, what will be the moles of `C` at equilibrium?
Answer» `{:(,A,+,B,hArr,2C),("Initial moles",2,,3,,0),("moles at equilibrium",(2-x),,(3-x),,2x):}` `:. K_(c )=([C]^(2))/([A][B])=(4x^(2).V.V)/(V^(2)(2-x)(3-x))` `4=(4x^(2))/((2-x)(3-x))` `:. x^(2)=6-5x+x^(2)` `({:([C]=(2x)/V),([A]=(2-x)/V),([B]=(3-x)/V):})` `:. x=1.2` moles of `C` at equilibrium `=2x=2xx1.2=2.4`

Discussion

Explore topic-wise InterviewSolutions in .

n mole each of `H_(2)O(g),H_(2)(g) "and" O_(2)(g)` are mixed at a suitable high temperature to attain the equilibrium `2H_(2)O(g)hArr2H_(2)(g)+O_(2)(g)`. If `y` and mole of `H_(2)O(g)` are the dissociated and the total pressure maintained is `P`, calculate the `K_(P)`.

The relationship between equilibrium constants `K_(p) "and" K_(c)` for a gaseous reaction is:A. `K_(p)=K_(c).R(T)^(Deltan)`B. `K_(c)=K_(p).(RT)^(Deltan)`C. `K_(p)=K_(c).(RT)^(Deltan)`D. `mol.dm^(-3)`

For the chemical reaction `3X(g)+Y(g) hArr X_(3)Y(g)`, the amount of `X_(3)Y` at equilibrium is affected byA. Temperature and pressureB. Temperature onlyC. Pressure onlyD. Temperature, pressure and catalyst

Which of the following is correct if reaction quotient `(Q)=1`?A. `DeltaG=0`B. `DeltaG^(@)=0`C. `DeltaS^(@)=0`D. `DeltaG=DeltaG^(@)`

For the reaction, `H_(2)(g)to 2HI(g)` `K_(2)=50.0 at 721 K`. What is the value of `Delta^(circ)` for this reaction (per mole of `H_(2))` at 721K?A. `-32.3kJ`B. `-23.5kJ`C. `-10.2kJ`D. `-0.231kJ`

For a reaction, `H_2+I_2hArr 2HI` at 721 K , the value of equilibrium constant is 50. If 0.5 moles each of `H_2` and `I_2` is added to the system the value of equilibrium constant will be :A. `0.02`B. `0.2`C. 50D. 25

`{:(Ag^+ +NH_3 hArr[Ag(NH_3)]^+,,K_1=3.5xx10^-3),([Ag(NH_3)]^+ +NH_3 hArr[Ag(NH_3)_2]^+,,K_2=1.8xx10^-3):}` then, the overall formation constant of `[Ag(NH_3)_2]^+` is :A. `6.3xx10^(-6) M`B. `6.3xx10^(6) M`C. `6.3xx10^(-9) M`D. None of these

For reaction `XeF_6+H_2O hArr XeOF_4+2HF, K_1=4` `XeO_4+XeF_6 hArr XeOF_4 + XeO_3F_2 , K_2=100` Find equilibrium constant of `1/2XeO_4+HF hArr 1/2XeO_3F_2+1/2H_2O`

For the reaction `CO(g)+CI_(2)(g)hArrCOCI_(2)(g)` `K_(p)//K_(c )` is equal toA. `1//RT`B. `Rt`C. `sqrt(RT)`D. `(RT)^(2)`

A reaction continues even after the attainment of equilibrium.

Phosphorous pentachloride when heated in a sealed tube at `700 K` it undergoes decomposition as `PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g), K_(p)=38` atm Vapour density of the mixture is `74.25`. Equilibrium constant `K_(c)` for the reaction will beA. `0.66 M`B. `0.56 M`C. `0.46 M`D. `0.36 M`

The vapour density of the equilibrium mixture of the reaction: `SO_(2)Cl_(2)(g)hArrSO_(2)(g)+Cl_(2)(g)` is `50`. The percent dissociation of `SO_(2)Cl_(2)` isA. `33.33%`B. `66.67%`C. `30.0%`D. `35.0%`

What is the equilibrium expression for the reaction `P_(4(s)) + 5O_(2(g))hArrP_(4)O_(10(s))` ?A. `K_(C)=[P_(4)O_(10)]//[P_(4)][O_(2)]^(5)`B. `K_(C)=1//[O_(2)]^(5)`C. `K_(C)=[O_(2)]^(5)`D. `K_(C)=[P_(4)O_(10)]//5[P_(4)][O_(2)]`

For the reaction , `CO(g)+Cl(g)hArrCOCl_2(g)` then `K_p//K_c` is equal to :A. `1/(RT)`B. `1.0`C. `sqrt(RT)`D. RT

The active mass of `64 g` of `HI` in a `2-L` flask would beA. `2`B. `1`C. `5`D. `0.25`

Based on the equilibrium constant for the reaction below : `2SO_3(g)hArr2SO_2(g)+O_2(g) " " K=1.8xx10^(-5)` What is the equilibrium constant for the reaction `SO_2(g)+1/2O_2(g)hArr SO_3(g) " " K=?`A. `2.1xx10^(-3)`B. `4.2xx10^(-3)`C. `2.4xx10^(2)`D. `5.6xx10^(4)`

High pressure and low temperature are favourable conditions for the synthesis of ammonia.

The value of K does not depends upon pressure.

`0.5 mol` of `H_(2)` and `0.5` mol of `I_(2)` react in `10 L` flask at `448^(@)C`. The equilibrium constant `(K_(c ))` is `50` for `H_(2)+I_(2) hArr 2HI` a. What is the value of `K_(p)`? b. Calculate the moles of `I_(2)` at equilibrium.

Calculate the expression for `K_(C) "and" K_(P)` if initially a moles of `N_(2) "and" B "moles of" H_(2)` is taken for the following reaction. `N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) (Deltanlt0)` (P,T,V given)

When ethyl alcohol `(C_2H_5OH(l))` and acetic acid `(CH_3COOH(l))` are mixed together in equimolar ratio at `27^@C` , 33% of each is converted into ester.Then the `K_C` for the equilibrium, `C_2H_5OH(l))+CH_3CHOOH(l) hArrCH_3COOC_2H_5(l)+H_2O(l)`A. 4B. `1/4`C. 9D. `1/9`

`K_(p) "is" atm^(2)` for the reaction: `LiCI.3NH_(3)(s)hArrLiCI.NH_(3)(s)+2NH_(3)(g) "at" 40^(@)C`. How many moles of ammonia must be added at this temperature to a `5` litre flask containing `0.1` mole of LiCI. `NH_(3)` in order to completely convert the solid to `LiCI.3NH_(3)`?

`A(g)hArr B(g)+C(g),K_C=10^(-8)` `C(g)hArr D(g),K_C=10^(-5)` 1 mole of A(g) is taken in a closed container of volume 1 litre at temperature T. If concentration of D at equilibrium is `10^(-x)`, then , calculate value of x.

For the reaction, `A+B hArr 2C, 2` mol of `A` and `3` mol of `B` are allowed to react. If the equilibrium constant is `4` at `400^(@)C`, what will be the moles of `C` at equilibrium?