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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 50501. |
A colourless mixture of two salts (A) and (B) excess is soluble in H_(2)O. Separately (A) turns blue litmus red and (B) turns red litmus blue. (A) given white precipitate with (B), which dissolves in excess of (B) forming (C). (A) when placed in moist air gives fumes and can form dimer. (A) gives white precipitate with NH_(4)CI and NH_(4)OH soluble in (B).(A) also gives white precipitate with AgNO_(3) soluble in NH_(4)OH. Colourless mixture contains: |
| Answer» <html><body><p>`ZnCI_(2),NaOH`<br/>`AICI_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>),<a href="https://interviewquestions.tuteehub.com/tag/naci-572479" style="font-weight:bold;" target="_blank" title="Click to know more about NACI">NACI</a>`<br/>`AICI_(3),NaOH`<br/>`CrCI_(3),NaOH`</p>Solution :`(A) rarr AICI`, <br/> (B) `rarr NaOH, AI^(3+) +H_(2)O <a href="https://interviewquestions.tuteehub.com/tag/harr-2692945" style="font-weight:bold;" target="_blank" title="Click to know more about HARR">HARR</a> AI(<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>)^(2+) +H^(+)`</body></html> | |
| 50502. |
A colourless liquid, at room temperature reacts with soda lime to form sodium salt of carboxylic acid and ammonia gas. The liquid is |
| Answer» <html><body><p>Propanamide<br/>Propanoic <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a><br/>Formamide<br/>Methyl Ethanoate</p>Solution :Since in the <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> sodium salt of fatty acid is formed it must be an acid or some acid derivative. Further since `NH_(3)` gas is alos evolved hence it must be an amide. Moreover, at room while all other <a href="https://interviewquestions.tuteehub.com/tag/amides-19989" style="font-weight:bold;" target="_blank" title="Click to know more about AMIDES">AMIDES</a> are <a href="https://interviewquestions.tuteehub.com/tag/colourless-422296" style="font-weight:bold;" target="_blank" title="Click to know more about COLOURLESS">COLOURLESS</a> <a href="https://interviewquestions.tuteehub.com/tag/crystalline-940053" style="font-weight:bold;" target="_blank" title="Click to know more about CRYSTALLINE">CRYSTALLINE</a> solids</body></html> | |
| 50503. |
A colourless liquid A contains H and O elements only. It decomposes slowly on exposusre to light. It is stabilized by mixing urea to store in the presence of light. (i) Suggest possible structrue of A. (ii) Write chemical equatioins of its decomposition reaction in light. |
| Answer» <html><body><p><br/></p>Answer :The liquid A is hydrogen pexoxide `(H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(2))`<br/> `(##SPH_BSR_CHE_QB_XI_MQP_01_E01_023_S01##)` <br/> <br/> `2H_(2)O_(2)<a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>("<a href="https://interviewquestions.tuteehub.com/tag/light-1073401" style="font-weight:bold;" target="_blank" title="Click to know more about LIGHT">LIGHT</a>")(to)2H_(2)O+O_(2)`</body></html> | |
| 50504. |
A colourless liquid 'A' contains H and O elements only. It decomposes slowly on exposure to light. Is stabilised by mixing urea to store in the presence of light. (i) Suggest possible structure of A. (ii) Write chemical equations for its decomposition reaction in light. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> a colourless liquid 'A' contains only H and O and decomposes slowly on <a href="https://interviewquestions.tuteehub.com/tag/exposure-980813" style="font-weight:bold;" target="_blank" title="Click to know more about EXPOSURE">EXPOSURE</a> to <a href="https://interviewquestions.tuteehub.com/tag/light-1073401" style="font-weight:bold;" target="_blank" title="Click to know more about LIGHT">LIGHT</a> but is stabilised by addition of urea, therefore , liquid A may be <a href="https://interviewquestions.tuteehub.com/tag/hydrogen-22331" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGEN">HYDROGEN</a> peroxide. <br/> (i) `2H_(2)O_(2) <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(hv)to 2H_(2)O+ O_(2)`.</body></html> | |
| 50505. |
A colourless liquid .A. contains H and o elements only. It decomposes slowly on exposure to light. It is stabilised by mixing urea to store in the presence of light. (i) Suggest possible structure of A. (ii) Write chemical equations for decomposition reaction in light. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) Since, a colourless liquid .A. contains only hydrogen and oxygen and decomposes slowly on <a href="https://interviewquestions.tuteehub.com/tag/exposure-980813" style="font-weight:bold;" target="_blank" title="Click to know more about EXPOSURE">EXPOSURE</a> to light but is stabilised by addition of urea, therefore, liquid A may be `H_2O_2`.The <a href="https://interviewquestions.tuteehub.com/tag/structure-1230280" style="font-weight:bold;" target="_blank" title="Click to know more about STRUCTURE">STRUCTURE</a> of `H_2O_2`is <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_CHE_XI_P2_C09_E04_074_S01.png" width="80%"/> <br/> (ii)`2H_2O_2 underset"Sunlight"overset"<a href="https://interviewquestions.tuteehub.com/tag/hv-1033771" style="font-weight:bold;" target="_blank" title="Click to know more about HV">HV</a>" to 2H_2O+O_2`</body></html> | |
| 50506. |
A colourless inorganic salt (A) decomposes completely at about 250^(@)C to give only two products, (B) and (C), leaving no residue. The oxide (C) is a liquid at room temperature and neutral to moist litmus paper while the gas (B) is a neutral oxide. White phosphours burns in excess of (B) to produce a strong white dehydrating agent. Write balanced equations for the reactions involved in the above process. |
| Answer» <html><body><p></p>Solution :(i) Since a colourless inorganic salt (A) on <a href="https://interviewquestions.tuteehub.com/tag/heating-1017297" style="font-weight:bold;" target="_blank" title="Click to know more about HEATING">HEATING</a> to `250^(@)C` <a href="https://interviewquestions.tuteehub.com/tag/decomposes-946040" style="font-weight:bold;" target="_blank" title="Click to know more about DECOMPOSES">DECOMPOSES</a> to form twooxides (B) and (C) leaving no residue, therefore, compound (A) must be ammonium nitrate `(NH_(4)NO_(3))`. <br/> `underset((A))(NH_(4)NO_(3))overset(250^(@)C)tounderset((B))(N_(2)O)+underset((C))(2H_(2)O)` <br/> (ii) The fact that inorganic salt (A) is actually ammonium nitrate is confirmed by the observation that oxide (C), i.e., `H_(2)O` is a liquid at room temperature. <br/> (iii) If the oxide (C) is `H_(2)O` then other neutral oxide (B) must be nitrous oxide, `N_(2)O`. <br/> (iv) The fact that the neutral oxide (B) is actually `N_(2)O` is confirmed by the observation that white phosphorus burns in `N_(2)O` to form phosphorus pentoxide which is a strong dehydrating agent. <br/> `underset("Nitrous oxide (B)")(10N_(2)O)+P_(4)tounderset("Phosphorus pentoxide")(P_(4)O_(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>))+10N_(2)` <br/> Thus, inorganic salt (A) is ammonium nitrate `(NH_(4)NO_(3))`, (B) is nitrous oxide `(N_(2)O)` and (C) is water `(H_(2)O)`.</body></html> | |
| 50507. |
A colourless gas which burns with blue flame and reduces CuO to Cu is |
| Answer» <html><body><p>`N_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/co-920124" style="font-weight:bold;" target="_blank" title="Click to know more about CO">CO</a>`<br/>`CO_(2)`<br/>`NO_(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 50508. |
A colourless gas obtain by the electrolysis of NaCl Nelson's cell is made to combine with an element X. The resulting compound has low mellting pt. and boiling pt. It can also act as weak reducing pt. and boiling pt. It can also act as weak reducing agent. The element X forms oxides and hydroxides of the form X_(2)O_(3) and X(OH)_(3). X does not react with HCl. The resulting compound is |
| Answer» <html><body><p>`AlCl_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`B_(2)H_(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)`<br/>`BCl_(3)`<br/>`Ga_(2)Cl_(6)`.</p>Solution :Chlorine from Nelson cell forms `BCl_(3)` with boron.</body></html> | |
| 50509. |
A coloured solution known to contain two metal ions of different groups, was treated with excess cold sodium hydroxide solution. When filtered a whitish solid, slowly changing to brown, was retained on the filter paper and a colourless solution collected as the filtrate. Drop wise adition of hydrochloric acid to the filtrate produced a white precipitate which dissolved in excess acid. Treatment of the residue from the filter paper with a strong oxidiser, PbO_(2) and concentratedHNO_(3) on boiling produced a reddish-violet (purple) solution. Reddish-violet (purple) solution is decolourised by: |
| Answer» <html><body><p>both `SO_(3)^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>-),<a href="https://interviewquestions.tuteehub.com/tag/fe-460008" style="font-weight:bold;" target="_blank" title="Click to know more about FE">FE</a>^(2+)`<br/>both `SO_(4)^(2-),Fe^(3+)`<br/>both `NO_(3)^(-),Fe^(2+)`<br/>both `H_(2)O_(2),HCO_(3)^(2-)`</p>Answer :A</body></html> | |
| 50510. |
A coloured solution known to contain two metal ions of different groups, was treated with excess cold sodium hydroxide solution. When filtered a whitish solid, slowly changing to brown, was retained on the filter paper and a colourless solution collected as the filtrate. Drop wise adition of hydrochloric acid to the filtrate produced a white precipitate which dissolved in excess acid. Treatment of the residue from the filter paper with a strong oxidiser, PbO_(2) and concentratedHNO_(3) on boiling produced a reddish-violet (purple) solution. Reddish-violet solution obtained by oxidation is of: |
| Answer» <html><body><p>`ZnO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)^(2-)`<br/>`MnO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)^(2-)`<br/>`MnO_(4)^(-)`<br/>`MnO_(2)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50511. |
A coloured solution known to contain two metal ions of different groups, was treated with excess cold sodium hydroxide solution. When filtered a whitish solid, slowly changing to brown, was retained on the filter paper and a colourless solution collected as the filtrate. Drop wise adition of hydrochloric acid to the filtrate produced a white precipitate which dissolved in excess acid. Treatment of the residue from the filter paper with a strong oxidiser, PbO_(2) and concentratedHNO_(3) on boiling produced a reddish-violet (purple) solution. White solid changing to brown is due to formation of: |
| Answer» <html><body><p>`Mn(OH)_(2)`<br/>`MgO`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/ai-12496" style="font-weight:bold;" target="_blank" title="Click to know more about AI">AI</a>(OH)_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/mno-548536" style="font-weight:bold;" target="_blank" title="Click to know more about MNO">MNO</a>(OH)_(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 50512. |
A coloured solution known to contain two metal ions of different groups, was treated with excess cold sodium hydroxide solution. When filtered a whitish solid, slowly changing to brown, was retained on the filter paper and a colourless solution collected as the filtrate. Drop wise adition of hydrochloric acid to the filtrate produced a white precipitate which dissolved in excess acid. Treatment of the residue from the filter paper with a strong oxidiser, PbO_(2) and concentratedHNO_(3) on boiling produced a reddish-violet (purple) solution. Filtrate obtained after separation of white solid contains: |
| Answer» <html><body><p>`[AI(OH)_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)]^(-)`<br/>`AI_(2)O_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/mno-548536" style="font-weight:bold;" target="_blank" title="Click to know more about MNO">MNO</a>`<br/>`Na_(2)MnO_(2)`</p>Answer :A</body></html> | |
| 50513. |
A coloured solution known to contain two metal ions of different groups, was treated with excess cold sodium hydroxide solution. When filtered a whitish solid, slowly changing to brown, was retained on the filter paper and a colourless solution collected as the filtrate. Drop wise adition of hydrochloric acid to the filtrate produced a white precipitate which dissolved in excess acid. Treatment of the residue from the filter paper with a strong oxidiser, PbO_(2) and concentratedHNO_(3) on boiling produced a reddish-violet (purple) solution. Indicate any pairs of ions which on testing as above leads to the observed changes. |
| Answer» <html><body><p>`AI^(3+)` and `<a href="https://interviewquestions.tuteehub.com/tag/mn-548487" style="font-weight:bold;" target="_blank" title="Click to know more about MN">MN</a>^(2+)` ions<br/>`<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>^(2+)` and `<a href="https://interviewquestions.tuteehub.com/tag/zn-751409" style="font-weight:bold;" target="_blank" title="Click to know more about ZN">ZN</a>^(2+)` ions<br/>`Mn^(2+)` and `Mg^(2+)` ions<br/>`Zn^(2+)` and `Mn^(2+)` ions</p>Answer :A</body></html> | |
| 50514. |
A coloured salt of cobalt is subjected to borax bead test. The transparent borax bead turns blue. From the given reaction, identify the one which does not take place during the process |
| Answer» <html><body><p>`4NaBO_(2) + CO_(2) rarr Na_(2)B_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)O_(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>) + Na_(2)CO_(3)`<br/>`Na_(2)B_(4)O_(7) rarr 2NaBO_(2) + B_(2)O_(3)`<br/>`Na_(2)[B_(4)O_(5)(OH)_(4)].8H_(2)O rarr Na_(2)B_(4)O_(7) + 10H_(2)O`<br/>`CoO + B_(2)O_(3) rarr Co(BO_(2))_(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 50515. |
A colloidal solution of Na in ether is |
| Answer» <html><body><p>golden <a href="https://interviewquestions.tuteehub.com/tag/yellow-1464953" style="font-weight:bold;" target="_blank" title="Click to know more about YELLOW">YELLOW</a> in <a href="https://interviewquestions.tuteehub.com/tag/colour-422259" style="font-weight:bold;" target="_blank" title="Click to know more about COLOUR">COLOUR</a><br/>blue in colour<br/>colourless <br/>violet in colour. </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :A colloidal solution of <a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a> in <a href="https://interviewquestions.tuteehub.com/tag/ether-975855" style="font-weight:bold;" target="_blank" title="Click to know more about ETHER">ETHER</a> is violet coloured.</body></html> | |
| 50516. |
A colloidal solution of gold in water is |
| Answer» <html><body><p>red in colour<br/>blue in colour<br/>golden spangles<br/>all the three.</p>Solution :Colour of a <a href="https://interviewquestions.tuteehub.com/tag/colloidal-922087" style="font-weight:bold;" target="_blank" title="Click to know more about COLLOIDAL">COLLOIDAL</a> solution depends <a href="https://interviewquestions.tuteehub.com/tag/upon-2315586" style="font-weight:bold;" target="_blank" title="Click to know more about UPON">UPON</a> particle size. As the particle size <a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a>, the colour of gold sol changes from red to blue and finally to golden spangles. At this stage, it turns into a suspension.</body></html> | |
| 50517. |
A colloidal solution is subjected to an electrical field. The particles move towards anode. The coagulation of same sol is studied using NaCl, BaCl_(2) and AlCl_(3)solution. Their coagulating power should be |
| Answer» <html><body><p>`NaCl <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> BaCl_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) gt AlCl_(3)`<br/>`BaCl_(2) gt AlCl_(3) gt NaCl`<br/>`AlCl_(3) gt BaCl_(2) gt NaCl`<br/>`BaCl_(2) gt NaCl gt AlCl_(3)`</p>Answer :C</body></html> | |
| 50518. |
(a) Colloidal sol of Fe(OH)_3 formed by peptization carries positive chrage. (r) During the formation of positively charged colloidal particles of Fe(OH)_3 the electons are lost by the colloidal particles of Fe(OH)_3. |
| Answer» <html><body><p>IF both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and (r) is the correct explanation for (a). <br/>If both (a) and (r) are correct but (r) is not the correct explanation for (a). <br/>IF (a) is correct but (r) is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a>. <br/>If (a) is incorrect but (r) is correct. </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50519. |
(A): COD of water is detennined by oxidising the organic matter with acidified (50% H_2SO_4) potassium dichromate solution (R) Greater the COD value of water greater is its pollution |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of (A) <br/>Both (A) and (R) are true and (R) is not the correct explanation of (A) <br/>(A) is true but (R) is false <br/>(A) is false but (R) is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 50520. |
(A): CO pollution is very high from 9AM to 10 AM in Urban areas (R): Almost 80% CO is released from Automobiles |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation'of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/> (A) is true but (R) is false <br/>(A) is false but (R) is true </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Both (A) and (R) are true and (R) is the correct explanation.of (A)</body></html> | |
| 50521. |
A closed vessel contains equal number of oxygen and hydrogen molecules at a total pressure of 740 mm. If oxygen is removed from the system, the pressure: 1)becomes half of 740 mm2)becomes 1/3 rd of 740 mm3)becomes double of 740 mm4)remains unchanged. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> <a href="https://interviewquestions.tuteehub.com/tag/half-1014510" style="font-weight:bold;" target="_blank" title="Click to know more about HALF">HALF</a> of 740 mm<br/>becomes `1/3` <a href="https://interviewquestions.tuteehub.com/tag/rd-613594" style="font-weight:bold;" target="_blank" title="Click to know more about RD">RD</a> of 740 mm<br/>becomes double of 740 mm<br/>remains unchanged.</p>Solution :becomes half of 740 mm</body></html> | |
| 50522. |
A closed steel Mask contains hot tea. What type of system is this? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The system is a closed system. This is because <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> transfers from the steel walls into the <a href="https://interviewquestions.tuteehub.com/tag/surroundings-1235986" style="font-weight:bold;" target="_blank" title="Click to know more about SURROUNDINGS">SURROUNDINGS</a>,but <a href="https://interviewquestions.tuteehub.com/tag/matter-22749" style="font-weight:bold;" target="_blank" title="Click to know more about MATTER">MATTER</a> is not transfered.</body></html> | |
| 50523. |
A closed bulb cotains 0.01 mole of inert helium gas and a sample of solid white NH_(4)CI The pressure of the he is measured at 27^(@)C and is found to be 114 mm Hg The bulb is then heated to 327^(@)C All the NH_(4)CI decomposes according to the equation NH_(4)CI_((s))rarrNH_(3_(g)) +HCI_((g)) The final total pressure in the bulb after complete decomposition of solid is 908mm Hg Assume all the gases are ideal (a) What is the partial pressure of HCI_((g)) in the bulb at 327^(@)C when reaction is complete (b) How many grams of NH_(4)CI_((s)) were in the bulb at 27^(@)C ? . |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :0.447 <a href="https://interviewquestions.tuteehub.com/tag/atm-364409" style="font-weight:bold;" target="_blank" title="Click to know more about ATM">ATM</a>, 0.797 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a></body></html> | |
| 50524. |
A clear solution which is again converted into colloidal solution, the process is called |
| Answer» <html><body><p>Peptization<br/>Electro addition<br/>Electrophoresis<br/>None of these</p>Answer :D</body></html> | |
| 50525. |
(a) Classify the following as pure substances and mixtures. (b)Separate the pure substances into elements and compounds and divide the mixtures into homogeneous and heterogeneous. (i) air (ii) milk (iii) graphite (iv) diamond (v) gasoline (vi) tap water (vii) distilled water(viii) oxygen (ix) one rupee-coin(x) 22 carat gold (xi) steel (xii) iron (xiii) sodium chloride(xiv) iodised table salt (xv) wood (xvi) cloud |
| Answer» <html><body><p></p>Solution :(i) Air : <a href="https://interviewquestions.tuteehub.com/tag/mixture-1098735" style="font-weight:bold;" target="_blank" title="Click to know more about MIXTURE">MIXTURE</a>, <a href="https://interviewquestions.tuteehub.com/tag/homogeneous-1028736" style="font-weight:bold;" target="_blank" title="Click to know more about HOMOGENEOUS">HOMOGENEOUS</a>. <br/> (ii) Milk : mixture, heterogeneous <br/> (iii) Graphite : pure substance, element carbon <br/> (iv) Diamond : pure substance, element carbon <br/> (v) Gasoline : mixture, homogeneous <br/> (vi) Tap water : mixture, heterogeneous <br/> (vii) Distilled water : pure substance, <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a> <br/> (viii) Oxygen : pure substance, element <br/> (ix) One <a href="https://interviewquestions.tuteehub.com/tag/rupee-1192322" style="font-weight:bold;" target="_blank" title="Click to know more about RUPEE">RUPEE</a> coin : mixture, homogeneous <br/> (x) 22 carat gold : mixture, homogeneous <br/> (xi) Steel : mixture, homogeneous <br/> (xii) Iron : pure substance, element <br/> (xiii) Sodium chloride : pure substance, compound <br/> (xiv) Iodised table salt: mixture, heterogeneous<br/> (xv) Wood : pure substance, compound <br/> (xvi) <a href="https://interviewquestions.tuteehub.com/tag/cloud-11874" style="font-weight:bold;" target="_blank" title="Click to know more about CLOUD">CLOUD</a> : mixture, heterogeneous.</body></html> | |
| 50526. |
(a) Classify followingoxides as neutral, acidic, basic oramphoteric CO, B_(2)O_(3), SiO_(2), CO_(2), Al_(2)O_(3), PbO_(2), Tl_(2)O_(3) (b) Write suitablechemcial equationsto show their nature. |
| Answer» <html><body><p></p>Solution :(a) Neutral oxides : CO : Acidic oxides : `B_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O_(3), SiO_(2), CO_(2)` <br/> Amphoteric oxides : `Al_(2)O_(3), PbO_(2)` Basicoxide : `Tl_(2)O_(3)` <br/> (b) (i) Being acidic `B_(2)O_(3), SiO_(2)` and `CO_(2)` react with <a href="https://interviewquestions.tuteehub.com/tag/alkalis-853350" style="font-weight:bold;" target="_blank" title="Click to know more about ALKALIS">ALKALIS</a> to form salts. <br/> `<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>("<a href="https://interviewquestions.tuteehub.com/tag/anhydride-875713" style="font-weight:bold;" target="_blank" title="Click to know more about ANHYDRIDE">ANHYDRIDE</a>")underset("Boric")(B_(2)O_(3)) + 2NaOH rarr underset("Sod. metaborate")(2NaBO_(2) + H_(2)O) , underset("Silica")(SiO_(2))+2NaOH overset(Delta)rarrunderset(" Sod. silicates ")(Na_(2)SiO_(3))+H_(2)O` <br/> `underset(" Carbon dioxide ")(CO_(2)) + 2NaOH rarr underset(" Sod. carbonate ")(Na_(2)CO) + H_(2)O` <br/> (ii) Being amphoteric, `Al_(2)O_(3)` and `PbO_(2)` reactwith bothacidsand bases. <br/>`underset("Alumina")(Al_(2)O_(3)) + 2NaOHoverset("Fuse")rarr underset(" Sod. meta-aluminate ")(NaAlO_(2)) + H_(2)O, Al_(2)O_(3) + 3H_(2)SO_(4) rarr Al_(2)(SO_(4))_(3) + 3H_(2)O` <br/> `underset(" Lead dioxide ")(PbO_(2)) + 2NaOH rarr underset(" Sod. plumbate ")(Na_(2)PbO_(3)) + H_(2)O , 2PbO_(2) + 2H_(2)SO_(4) rarr 2PbSO_(4) +2H_(2)O + O_(2)` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) Beingbasic, `Tl_(2)O_(3)` dissolvesin acids. <br/> `Tl_(2)O_(3) + 6 HCl rarr 2TlCl_(3) + 3H_(2)O`.</body></html> | |
| 50527. |
A chlorocompound (A) on reduction with Zn-Cu and ethanol gives the hydrocarbon (B) with five carbon atoms. When (A) is dissolved in dry ether and treated with sodium metal it gave 2,2,5,5,-tetramethylhexane. The treatment of A as A overset(alc. KCN)to C The reation of A with aq. KOH will preferably favour |
| Answer» <html><body><p>`S_(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>)<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>` <a href="https://interviewquestions.tuteehub.com/tag/mechanism-15329" style="font-weight:bold;" target="_blank" title="Click to know more about MECHANISM">MECHANISM</a><br/>`S_(N)<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` mechanism<br/>`E_(1)` mechanism<br/>`E_(2)` mechanism</p>Answer :A</body></html> | |
| 50528. |
A chlorocompound (A) on reduction with Zn-Cu and ethanol gives the hydrocarbon (B) with five carbon atoms. When (A) is dissolved in dry ether and treated with sodium metal it gave 2,2,5,5,-tetramethylhexane. The treatment of A as A overset(alc. KCN)to C The reaction of C with Na, C_(2)H_(5)OH is called |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/gilman-473242" style="font-weight:bold;" target="_blank" title="Click to know more about GILMAN">GILMAN</a> reaction<br/>Mendius reaction<br/>Grooves process<br/>Swart's reaction</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 50529. |
A chlorocompound (A) on reduction with Zn-Cu and ethanol gives the hydrocarbon (B) with five carbon atoms. When (A) is dissolved in dry ether and treated with sodium metal it gave 2,2,5,5,-tetramethylhexane. The treatment of A as A overset(alc. KCN)to C The reaction of C with Na, C_(2)H_(5)OH gives |
| Answer» <html><body><p>`(CH_(3))_(3)C CH_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)CONH_(2)`<br/>`(CH_(3))_(3)CNH_(2)`<br/>`(CH_(3))_(3)C CH_(2)NH_(2)`<br/>`(CH_(3))_(2)CHCH_(2)NH_(2)`</p>Answer :C</body></html> | |
| 50530. |
A chlorocompound (A) on reduction with Zn-Cu and ethanol gives the hydrocarbon (B) with five carbon atoms. When (A) is dissolved in dry ether and treated with sodium metal it gave 2,2,5,5,-tetramethylhexane. The treatment of A as A overset(alc. KCN)to C The compound A is |
| Answer» <html><body><p>1-chloro-2, 2-dimethyl propane<br/>1-chloro-2, 2-dimethyl butane<br/>1-chloro-2-methyl butane<br/>2-chloro-2-methyl butane</p>Answer :A</body></html> | |
| 50531. |
A chloro compound with M.F C_3H_3Cl shows the following properties (i) Decolourized bromine in C Cl_4 , (ii)Absorbed hydrogen catalytically, (iii)Gave a precipitate with ammoniacal cuprous chloride solution. Deduce the structure of the chloro compound. |
| Answer» <html><body><p></p>Solution :(i)Since compound (A) absorbs hydrogen catalytically and decolourizes bromine in `C Cl_4`, it <a href="https://interviewquestions.tuteehub.com/tag/must-2185568" style="font-weight:bold;" target="_blank" title="Click to know more about MUST">MUST</a> be an unsaturated compound. <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>)Since Compound (A) gives a precipitate with ammoniacal <a href="https://interviewquestions.tuteehub.com/tag/cuprous-2040167" style="font-weight:bold;" target="_blank" title="Click to know more about CUPROUS">CUPROUS</a> chloride, it must be a terminal alkyne. <br/> The only terminal alkyne with molecular <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> `underset"3-Chloro-1-propyne"(Cl-CH_2-C-=CH)` <br/> Step 1.To explain the reactions <a href="https://interviewquestions.tuteehub.com/tag/involved-7257329" style="font-weight:bold;" target="_blank" title="Click to know more about INVOLVED">INVOLVED</a> in the question <br/> (i)`underset"3-Chloro-1-propyne(A)"(Cl-CH_2-C-=CH)+ 2Br_2 overset(C Cl_4)to underset"1,1,2,2-Tetrabromo-3-chloropropane"(Cl-CH_2-CBr_2-CHBr_2)` <br/> (ii)`Cl-CH_2-C-=CH+2H_2 overset"Catalyst"to underset"1-Chloropropane"(Cl-CH_2-CH_2-CH_3)` <br/> (iii)`ClCH_2C-=CH+CuCl + NH_3 to underset"(Red ppt. )"(Cl-CH_2)-C-=C-Cu+NH_4Cl` <br/> Thus, the compound (A) is 3-chloro-1-propyne.</body></html> | |
| 50532. |
A chloro compound (A) showed the following properties, i. decolourised bromine in CCl_4 (ii). Absorbed hydrogen catalytically. (iii). Gave a red precipitate with ammoniacal cuprous chloride ltbr. (iv). When vaporised 1.49 gm of (A) gave 448 ml of vapours at STP. Identify (A) and write doen the equiation for the reaction is step 3. |
| Answer» <html><body><p></p>Solution :Step 1: To determine the molecular mass of compound (A): <br/> 448 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a> of vapours at STP weigh 1.49 gm <br/> 22400 ml of vapour at STP will weigh <br/> `=(1.49xx22400)/(448)=74.5gm` <br/> Thus, the molecular mass of compound (A) is 74.5 a.m.u. <br/> step 2. To identify the functional groups: <br/> (i). Since (A) decolourises `(Br_2)/(C Cl_4)`, is (A) must be an <a href="https://interviewquestions.tuteehub.com/tag/unsaturated-721485" style="font-weight:bold;" target="_blank" title="Click to know more about UNSATURATED">UNSATURATED</a> compound. This is further supported by the <a href="https://interviewquestions.tuteehub.com/tag/fact-982736" style="font-weight:bold;" target="_blank" title="Click to know more about FACT">FACT</a> that (A) also absorbs hydrogen catalytically. <br/> (ii) Since (A) gave a <a href="https://interviewquestions.tuteehub.com/tag/precipitate-1162804" style="font-weight:bold;" target="_blank" title="Click to know more about PRECIPITATE">PRECIPITATE</a> with ammoniacal `CuLl`, it must be a terminal acetyline, ie.e, it must contain the group `(---C--<a href="https://interviewquestions.tuteehub.com/tag/ch-913588" style="font-weight:bold;" target="_blank" title="Click to know more about CH">CH</a>)` <br/> Step 3. To determine the molecular formula of the compound (A): <br/> Molecular mass of `(---C---CH)` group `=12+12+1=25amu` <br/> Atomic mass of chlorine`=35.5a.m.u` <br/> Molecular mass of the compound `=74.5 amu` <br/> molecular mass of the remaining portion of compound `(A)=74.5-25-35.5=14` <br/> Since the molecualr mass of a `(CH_2)` group is 14 compound (A) contains a chlorine atom, one `(CH_2)` group, and one terminal acetylene group i.e., `(---C--CH)`, therefore the structure of the organic compound is <br/> `underset(3-"chloroprop-1-yne") (ClCH_2)--C-=CH+CuCl+NH_4OHrarrunderset("Copper-3-chlorprop-1-1ynide")(ClCH_2)-=C Cu+NH_4Cl+H_2O`</body></html> | |
| 50533. |
A chloro compound (A) showed the following properties : (i) decolourised bromine in C CI_4, (ii) absorbed hydrogen catalytically , (iii) gave a precipitate with ammoniacal Cu_2CI_2, (iv) when vapourised 1.49g of (A) gave 448mL of vapour at STP. Identify (A) and write down the equation of reaction at step (iii). |
| Answer» <html><body><p></p>Solution :The (i) and (ii) properties show that the chloro compound (A) is an unsaturated compound having double or triple bond. <br/> The compound <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> a precipitate with ammoniacal `Cu_2ci_2`. It is , therefore, an <a href="https://interviewquestions.tuteehub.com/tag/alkyne-853393" style="font-weight:bold;" target="_blank" title="Click to know more about ALKYNE">ALKYNE</a> having acidic hydrogen ,i.e., `-C-=CH`.<br/> Determination of molecular mass: 448mL of the compound <a href="https://interviewquestions.tuteehub.com/tag/weights-1451449" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHTS">WEIGHTS</a> at `STP=1.49 g` <br/> `22400mL` of the compound will weigh at STP `=(1.49)/(448)xx22400` <br/> Mol. mass `=74.5` <br/> Let the formula of the compound be `RCI=-C-=CH` The formula mass `=R+CI+(-C-=CH)=74.5` <br/> `R+35.5+25=74.5` <br/> `R+60.5=74.5` <br/> So, `R=14` <br/> i.e., `CH_2` <br/> The <a href="https://interviewquestions.tuteehub.com/tag/structure-1230280" style="font-weight:bold;" target="_blank" title="Click to know more about STRUCTURE">STRUCTURE</a> of compound (A) is `overset(CI)overset(|)CH_2-C-=CH`. <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> of step (iii). <br/> `overset(CI)overset(|)(2CH)_2-C-=CH+Cu_2CI_2overset(NH_4OH)tooverset(CI)overset(|)(2CH)_2-C-=C-Cu+2HCI`</body></html> | |
| 50534. |
(A) Chlorine has higher electron affinity than fluorine. (R) Chlorine is a poor oxidising agent than fluorine. |
| Answer» <html><body><p>Statement-1 (A) and statement-2 (R) are true and statement-2 (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation for statement-1 (A). <br/>Statement-1 (A) and statement-2 (R) are true and statement-2 (R) is not the correct explanation for statement-1 (A)<br/>Statement-1 (A) is true, statement-2 (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>Statement-1 (A) is false, statement-2 (R) is true </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50535. |
A chlorinated alkane has 10.1%C and 0.84% hydrogen by weight. Calculate its empirical formula. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`CHCl_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`</body></html> | |
| 50536. |
A chloride salt of Rhenium contains 63.6% Re by mass. What is its empirical formula? [Re = 186] |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/recl-3789262" style="font-weight:bold;" target="_blank" title="Click to know more about RECL">RECL</a><br/>`ReCl_(2)`<br/>`ReCl_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`ReCl_(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50537. |
A chloride of a metal contains 47.23% of the metal. Find out the equivalent weight of the metal. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :31.77</body></html> | |
| 50538. |
A chemist was performing an experiment to study the effect of varying voltage on the velocity and de Broglie wavelength of the electrons. In first experiment, the electron was accelerated through a potential difference of 1kV and in second experiment, it was accelerated through a potential difference of 2kV. The wavelength of de Broglie waves associated with electron is given by: lamda=(h)/(sqrt(2qVm)) where, V is the voltage through which an electron is accelerated. Putting the values of h, m and q we get: lamda=(12.3)/(sqrt(V))Ã… Q. The velocity of electron will be: |
| Answer» <html><body><p>same in both<br/>1.4 times in second <a href="https://interviewquestions.tuteehub.com/tag/experiment-980358" style="font-weight:bold;" target="_blank" title="Click to know more about EXPERIMENT">EXPERIMENT</a> than in first experiment<br/>double in second experiment than in first experiment<br/>four <a href="https://interviewquestions.tuteehub.com/tag/tiems-1419779" style="font-weight:bold;" target="_blank" title="Click to know more about TIEMS">TIEMS</a> in the second <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> than in first case.</p>Answer :b</body></html> | |
| 50539. |
A chemist while studying the properties of gaseous C C l_(2)F_(2), a chlorofluorocarbon refrigerant, cooled a 1.25 g sample at constant atmospheric prssure of 1.0 atm from 320 K to 293 K . During cooling the sample volume decreased from 274 to 248 mL. Calculate Delta Hand DeltaU for the chlorofluorocaron for this process. For C Cl_(2)F_(2), C_(p) = 80.7 J // ( mol K ). |
| Answer» <html><body><p></p>Solution :`DeltaH = q_(p) ` and `C_(p)` is heat evolved or absorbed per mole for `1^(@) ` <a href="https://interviewquestions.tuteehub.com/tag/fall-983217" style="font-weight:bold;" target="_blank" title="Click to know more about FALL">FALL</a> or rise in <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> . Here, fall in temperature`= 320- 293 = 27 K` <br/> Molar mass of `<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> C l_(2)F_(2) = <a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a> + 2 xx 35.5 + 2 xx 19 = 121 gmol^(-1)` <br/> `:. `Heat evolved from 1.25 g of the sample on being cooled from 320K to 293 K at constant <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a>`= ( 80.7) /( 121) xx 1.25 xx 27 J = 22.51J`<br/> Further, `Delta H = Delta U + P Delta V = 22.51J` <br/> `P Delta V = 1 atm xx (( 248 0 274))/(100) L = - 0.026 L atm = - 0.026 xx 101.325 J = -2.63 J ` <br/> `:.- 22.51 = Delta U - 2.63 J` <br/> or ` Delta U = - 22.51 + 2.63 J = - 19.88 J `</body></html> | |
| 50540. |
A chemist wishes to prepare 6.022 xx 10^(24) molecules of sulphur dioxide. How many gram-atoms of sulphur does the need ? |
| Answer» <html><body><p><br/></p>Solution :`6.022 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>)` molecules of `SO_(2)=1` gram <a href="https://interviewquestions.tuteehub.com/tag/atom-887280" style="font-weight:bold;" target="_blank" title="Click to know more about ATOM">ATOM</a> of `SO_(2)=1` gram atom of S <br/> `6.022 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a>)` molecules of `SO_(2)=10` gram atom of `SO_(2)=10` gram atoms of S.</body></html> | |
| 50541. |
A chemist was performing an experiment to study the effect of varying voltage on the velocity and de Broglie wavelength of the electrons. In first experiment, the electron was accelerated through a potential difference of 1kV and in second experiment, it was accelerated through a potential difference of 2kV. The wavelength of de Broglie waves associated with electron is given by: lamda=(h)/(sqrt(2qVm)) where, V is the voltage through which an electron is accelerated. Putting the values of h, m and q we get: lamda=(12.3)/(sqrt(V))Ã… Q. In order to get half velocity of electrons in second case, the applied potential will be: |
| Answer» <html><body><p>0.25 kV<br/>2 kV<br/>0.5 kV<br/>0.75 kV</p>Answer :a</body></html> | |
| 50542. |
A chemist was performing an experiment to study the effect of varying voltage on the velocity and de Broglie wavelength of the electrons. In first experiment, the electron was accelerated through a potential difference of 1kV and in second experiment, it was accelerated through a potential difference of 2kV. The wavelength of de Broglie waves associated with electron is given by: lamda=(h)/(sqrt(2qVm)) where, V is the voltage through which an electron is accelerated. Putting the values of h, m and q we get: lamda=(12.3)/(sqrt(V))Ã… Q. The wavelength of electron will be: |
| Answer» <html><body><p>1.4 <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> in <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> than in <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a> case<br/>1.4 times in second case than in first case <br/><a href="https://interviewquestions.tuteehub.com/tag/double-441870" style="font-weight:bold;" target="_blank" title="Click to know more about DOUBLE">DOUBLE</a> in second case than in first case<br/>double in first case than in second case</p>Answer :a</body></html> | |
| 50543. |
A chemist opened a couborad and found four bottles contaning water solutions, each of which had lost its label. Bottles 1,2,3 contained colourless solutions, while bottle 4 contained a blue solution. The lables from the bottles were lying scattered on the floor of the cupboard. They were:Copper (II) sulphate,""Hydrochloric acid Lead nitrate,""Sodium carbonate By mixing samples of the contents of the bottles, in pairs the chemist made the following observations: {:("Bottle +1 Bottle" 2 rarr, "White precipitate is formed"),("Bottle 1+ Bottle"3 rarr,"White precipitate is formed"),("Bottle 1+ Bottle" 4rarr,"White precipitate is formed"),("Bottle2+ Bottle"3rarr,"Colourless and odourless gas is evolved"),("Bottle 2+ Buttel" 4rarr,"No visivle reaction is observed"),("Bottle 3+ Bottle" 4rarr,"Blue precipitate is formed"):} With the help of the above observations answer the following questions. Which of the following bottle will give precipitate with bottle 1? |
| Answer» <html><body><p>Bottle 2<br/>Bottle <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a><br/>Bottle 4<br/>All of these</p>Solution :Bottle `4 <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> CuSO_(4)`, Bottle `2+` Bottle 3 `rarr HCI + Na_(2)CO_(3)` <br/> Bottle `<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> rArr Pb(NO_(3))_(2)`, Bottle `+1` Bottle `4 rArr PbSO_(4) darr` <br/> Bottle `2 rArr HCI`, Bottle `3 rArr Na_(2)CO_(3)` <br/> (Since, HCI doesn't react with `CuSO_(4))`</body></html> | |
| 50544. |
A chemist opened a couborad and found four bottles contaning water solutions, each of which had lost its label. Bottles 1,2,3 contained colourless solutions, while bottle 4 contained a blue solution. The lables from the bottles were lying scattered on the floor of the cupboard. They were:Copper (II) sulphate,""Hydrochloric acid Lead nitrate,""Sodium carbonate By mixing samples of the contents of the bottles, in pairs the chemist made the following observations: {:("Bottle +1 Bottle" 2 rarr, "White precipitate is formed"),("Bottle 1+ Bottle"3 rarr,"White precipitate is formed"),("Bottle 1+ Bottle" 4rarr,"White precipitate is formed"),("Bottle2+ Bottle"3rarr,"Colourless and odourless gas is evolved"),("Bottle 2+ Buttel" 4rarr,"No visivle reaction is observed"),("Bottle 3+ Bottle" 4rarr,"Blue precipitate is formed"):} With the help of the above observations answer the following questions. Which one of the following bottles develops deep blue colour with aqueous ammonia? |
| Answer» <html><body><p>Bottle <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> <br/>Bottle 2<br/>Bottle 3<br/>Bottle <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a></p>Solution :Bottle `4 rArr CuSO_(4)`, Bottle `2+` Bottle 3 `rarr HCI + Na_(2)CO_(3)` <br/> Bottle `1 rArr Pb(NO_(3))_(2)`, Bottle `+1` Bottle `4 rArr PbSO_(4) <a href="https://interviewquestions.tuteehub.com/tag/darr-943899" style="font-weight:bold;" target="_blank" title="Click to know more about DARR">DARR</a>` <br/> Bottle `2 rArr HCI`, Bottle `3 rArr Na_(2)CO_(3)` <br/> (Since, HCI doesn't react with `CuSO_(4))`</body></html> | |
| 50545. |
A chemist opened a couborad and found four bottles contaning water solutions, each of which had lost its label. Bottles 1,2,3 contained colourless solutions, while bottle 4 contained a blue solution. The lables from the bottles were lying scattered on the floor of the cupboard. They were:Copper (II) sulphate,""Hydrochloric acid Lead nitrate,""Sodium carbonate By mixing samples of the contents of the bottles, in pairs the chemist made the following observations: {:("Bottle +1 Bottle" 2 rarr, "White precipitate is formed"),("Bottle 1+ Bottle"3 rarr,"White precipitate is formed"),("Bottle 1+ Bottle" 4rarr,"White precipitate is formed"),("Bottle2+ Bottle"3rarr,"Colourless and odourless gas is evolved"),("Bottle 2+ Buttel" 4rarr,"No visivle reaction is observed"),("Bottle 3+ Bottle" 4rarr,"Blue precipitate is formed"):} With the help of the above observations answer the following questions. Bottle 3 contains: |
| Answer» <html><body><p>copper (II) sulphate<br/>hydrochloric acid<br/>lead nitrate<br/>sodium carbonate</p>Solution :Bottle `4 rArr CuSO_(4)`, Bottle `2+` Bottle 3 `rarr HCI + Na_(2)CO_(3)` <br/> Bottle `<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> rArr <a href="https://interviewquestions.tuteehub.com/tag/pb-597752" style="font-weight:bold;" target="_blank" title="Click to know more about PB">PB</a>(NO_(3))_(2)`, Bottle `+1` Bottle `4 rArr PbSO_(4) darr` <br/> Bottle `2 rArr HCI`, Bottle `3 rArr Na_(2)CO_(3)` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a>, HCI doesn't <a href="https://interviewquestions.tuteehub.com/tag/react-613674" style="font-weight:bold;" target="_blank" title="Click to know more about REACT">REACT</a> with `CuSO_(4))`</body></html> | |
| 50546. |
A chemist opened a couborad and found four bottles contaning water solutions, each of which had lost its label. Bottles 1,2,3 contained colourless solutions, while bottle 4 contained a blue solution. The lables from the bottles were lying scattered on the floor of the cupboard. They were:Copper (II) sulphate,""Hydrochloric acid Lead nitrate,""Sodium carbonate By mixing samples of the contents of the bottles, in pairs the chemist made the following observations: {:("Bottle +1 Bottle" 2 rarr, "White precipitate is formed"),("Bottle 1+ Bottle"3 rarr,"White precipitate is formed"),("Bottle 1+ Bottle" 4rarr,"White precipitate is formed"),("Bottle2+ Bottle"3rarr,"Colourless and odourless gas is evolved"),("Bottle 2+ Buttel" 4rarr,"No visivle reaction is observed"),("Bottle 3+ Bottle" 4rarr,"Blue precipitate is formed"):} With the help of the above observations answer the following questions. Which of the following statements is correct for salts contained in bottle 1 and 4? |
| Answer» <html><body><p>Bottle 4 gives white <a href="https://interviewquestions.tuteehub.com/tag/precipitate-1162804" style="font-weight:bold;" target="_blank" title="Click to know more about PRECIPITATE">PRECIPITATE</a> with excess of <a href="https://interviewquestions.tuteehub.com/tag/ki-533104" style="font-weight:bold;" target="_blank" title="Click to know more about KI">KI</a> solution.<br/>Bottle 4 gives white precipitate with excess of `K_(4)[Fe(CN)_(6)]` solution<br/>Bottle 1 and 4 both gives precipitate with excess of `NaOH` solution.<br/>Bottle 1 gives white precipitate with concentrated HCI solution.</p>Solution :Bottle `4 <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> CuSO_(4)`, Bottle `2+` Bottle 3 `rarr HCI + Na_(2)CO_(3)` <br/> Bottle `1 rArr <a href="https://interviewquestions.tuteehub.com/tag/pb-597752" style="font-weight:bold;" target="_blank" title="Click to know more about PB">PB</a>(NO_(3))_(2)`, Bottle `+1` Bottle `4 rArr PbSO_(4) darr` <br/> Bottle `2 rArr HCI`, Bottle `3 rArr Na_(2)CO_(3)` <br/> (Since, HCI doesn't react with `CuSO_(4))`</body></html> | |
| 50547. |
A chemist dissolves an excess of BaSO_(4) in pure water at 25^(@) C if its K_(sp) = 1 xx 10^(-10) . What is the concentration of barium in the water ? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-4)` M <br/>`10^(-5)` M <br/>`10^(-<a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a>)` M <br/>`10^(-6)` M </p>Solution :`K_(sp) = [<a href="https://interviewquestions.tuteehub.com/tag/ba-389206" style="font-weight:bold;" target="_blank" title="Click to know more about BA">BA</a>^(2+)] [SO_(4)^(2-)]` <br/> `1 xx 10^(-10) = (x) (x)` <br/> `10^(-5) = x`</body></html> | |
| 50548. |
A chemist claims that the following reaction is feasible at 298 K SF_(6)(g) + 8 HI(g) rarr H_(2)S( g + 6 HF (g)4I_(2)(g) ] Verify his claim . Given that DeltaG_(f)^(@) for SF_(6)(g) , HI(g) , H_(2)S(g) and HF (g) are - 991.61, 1.30, -33.01 and -270.73kJ mol^(-1) respectively. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/deltag-2053246" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAG">DELTAG</a>^(@) = - 665.78 <a href="https://interviewquestions.tuteehub.com/tag/kj-1063034" style="font-weight:bold;" target="_blank" title="Click to know more about KJ">KJ</a> <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`</body></html> | |
| 50549. |
A chemist claims that the following reaction is feasibleat 298 K SF_(6)(g) + 8HI(g) rarrH_(2)S(g+ 6HF (g) +4I_(2)(s) ] Verify his claim. Given that Delta_(f)G^(@)for SF_(6)(g), HI(g) , H_(2)S(g) and HF(g) are - 991.61, 1.30, -33.01 and -270.73kJ mol^(-1) respectively. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :Claim is true `(Delta_(f) <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>^(@)= - 665.78 kJ <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))`</body></html> | |
| 50550. |
A chemical reaction is spontaneous at 298 Kbut non-spontaneous at 350 K . Which one of the following following s true for this reaction ? |
| Answer» <html><body><p>`{:(<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> G,DeltaH ,<a href="https://interviewquestions.tuteehub.com/tag/deltas-947743" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAS">DELTAS</a>),(-,-,+):}`<br/>`{:(Delta G,DeltaH ,DeltaS),(+,+,+):}`<br/>`{:(Delta G,DeltaH ,DeltaS),(-,+,-):}`<br/>`{:(Delta G,DeltaH ,DeltaS),(-,-,-):}`</p>Solution :As reaction is spontaneous at <a href="https://interviewquestions.tuteehub.com/tag/low-537644" style="font-weight:bold;" target="_blank" title="Click to know more about LOW">LOW</a> temperature and non-spontaneous at high temperature,i.e., `<a href="https://interviewquestions.tuteehub.com/tag/deltag-2053246" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAG">DELTAG</a>` is-ve at low temperature and `+ve`at high temperature and `DeltaG =DeltaH - T DeltaS`, only ( e) in <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a>.</body></html> | |