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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 50401. |
A compound (P) , obtained as an ozonolysis product of (Q) gives brisk effervescence with Na, violet coloration with netutral FeCl_(3) and silver mirrorwith Tollen's reagent . (Q ) may be |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E03_051_O01.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E03_051_O02.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E03_051_O03.png" width="30%"/> <br/>All of these</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E03_051_S01.png" width="80%"/></body></html> | |
| 50402. |
A compound on decomposition in the laboratory produces 24.5 g of nitrogen and 70 g of oxygen. Calculate the empirical formula of the compound. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V01_C01_E04_156_S01.png" width="80%"/></body></html> | |
| 50403. |
A compound on analysis was found to contain 53.33 % C , 15.5 % H , and the rest nitrogen . The formula of the compound is |
| Answer» <html><body><p>`C_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) H_(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>) N`<br/>`C_(2) H_(7) N`<br/>`C_(4) H_(10) N`<br/>`C_(2) H_(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>) N`</p>Answer :B</body></html> | |
| 50404. |
A compound on analysis gave the following percentage composition: C - 54.54%, H = 9.09%, 0 = 36.36% |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`C_2H_4O`</body></html> | |
| 50405. |
A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% 0 = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`C_2H_4O`</body></html> | |
| 50406. |
A compound on analysis gave the following percentage composition: C = 24.47%, H= 4.07 %, Cl = 71.65%. Find out its empirical formula. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V01_C01_E04_181_S01.png" width="80%"/><br/>`:.` The empirical <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> - `CH_(2)Cl`</body></html> | |
| 50407. |
A compound on analysis gave the following percentage composition: Na=14.31% S = 9.97%, H = 6.22%, O = 69.5%, calcualte the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallisation. Molecular mass of the compound is 322 [Na = 23, S = 32, H = 1, 0 = 16]. |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V01_C01_E01_043_S01.png" width="80%"/> <br/>All H combines with 10 oxygen <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> to form as `10H_(2)O` <br/>So the empirical formula is `Na_(2)SO_(4).10H_(2)O` <br/>Empirical formula mass = `(23xx2) + (<a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a> <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) + (16xx4) + (10xx 18)` <br/>= 46 + 32 + <a href="https://interviewquestions.tuteehub.com/tag/64-330663" style="font-weight:bold;" target="_blank" title="Click to know more about 64">64</a> + 180 = 322 <br/>`n=("Molecular mass")/("Emperical formula mass")=322/322=1` <br/>Molecular formula=`Na_(2)SO_(4).10H_(2)O`</body></html> | |
| 50408. |
The compound of vanadium has magnetic moment of 1.73 BM. The vanadium chloride has the formula: |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Magnetic moment `=sqrt(n(n+2))= 1.73 , n=1` <br/>Electron configuration of V(23) = `1s^2 2s^2 2p^6 3s^2 3p^6 3d^3 4s^2` . <br/>As one unpaired electron is <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> in vanadium `V^(n+)` , so the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/oxidation-588780" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDATION">OXIDATION</a> state is +<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>.</body></html> | |
| 50409. |
A compound of the formula C_(4)H_(10)O reacts with sodium and undergoes oxidation to give a carbonyl compound which does not reduce Tollen's reagent, the original compound is |
| Answer» <html><body><p>Diethyl ether<br/>n-Butyl alcohol<br/>Isobutyl alcohol<br/>sec-Butyl alcohol</p>Solution :Because the compound react with Na, it may be alcohol, phenol or a carboxylic acid. As the compound on oxidation gives a carbonyl compounds which does not reduce Tollen's reagent, the compound <a href="https://interviewquestions.tuteehub.com/tag/formed-464209" style="font-weight:bold;" target="_blank" title="Click to know more about FORMED">FORMED</a> on oxidation is a reagent, the compound is a ketone. Because only <a href="https://interviewquestions.tuteehub.com/tag/secondary-638692" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDARY">SECONDARY</a> `(2^(@))` alcohols on oxidation yield <a href="https://interviewquestions.tuteehub.com/tag/ketones-1063498" style="font-weight:bold;" target="_blank" title="Click to know more about KETONES">KETONES</a>, thethe original compound is a secondary alcohol. <br/> `underset(2^(@)-"Butyl alcohol (D)")(CH_(3)-overset(OH)overset(|)(<a href="https://interviewquestions.tuteehub.com/tag/ch-913588" style="font-weight:bold;" target="_blank" title="Click to know more about CH">CH</a>)-CH_(2)-CH_(3))overset([O])rarrunderset("Butane-2-one")(CH_(3)-overset(O)overset(||)(CH)-CH_(2)-CH_(3))`</body></html> | |
| 50410. |
A compound of sodium does not give CO_(2) when heated but it gives CO_(2) when treated with dilute acids. A crystalline compound is found to have 37.1 percent Na and 1.6 percent Ho_(2). Hence the compound is |
| Answer» <html><body><p>`NaHCO_(3), 10H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O`<br/>`NaHCO_(3).5H_(2)O`<br/>`Na_(2)CO_(3).10H_(2)O`<br/>`Na_(2)CO_(3). H_(2)O`</p>Solution :`Na_(2)CO_(3)xxH_(2)O` <br/> `4600=3932.6 +667.8x` <br/> `667.4=667.8x,x=1`</body></html> | |
| 50411. |
A compound of sodium does not give CO_(2) when heated but it gives CO_(2) when treated with dilute acids. A crystalline compound is found to have 37.1% Na and 14.52% H_(2)O. Hence, compound is |
| Answer» <html><body><p>`NaHCO_(3)*10H_(2)O`<br/>`NaHCO_(3)*5H_(2)O`<br/>`Na_(2)CO_(3)*10H_(2)O`<br/>`Na_(2)CO_(3)*H_(2)O`</p>Solution :`CO_(2)` is obatined only when the compound is decomposed by acid thus, it is `Na_(2)CO_(3)`. It cannot be `NaHCO_(3)` since, it given `CO_(2)` on heating. <br/> Probable compound is `Na_(2)CO_(3).xH_(2)O` <br/> `{:(,,"<a href="https://interviewquestions.tuteehub.com/tag/molar-562965" style="font-weight:bold;" target="_blank" title="Click to know more about MOLAR">MOLAR</a> <a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a>","Ratio"),(Na_(2)CO_(3),85.48,0.8064,1),(H_(2)O,14.52,0.8064,1):}` <br/> Thus, compound is `Na_(2)CO_(3)*H_(2)O` <br/> <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> `=124" g "mol^(-1)` <br/> percentage of sodium `=(2xx23)/(124)xx100=37.1%`</body></html> | |
| 50412. |
A compound of formula C_3H_8 does not react with bormine in "CC"I_4 in the dark. The compound could be |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/alkane-853353" style="font-weight:bold;" target="_blank" title="Click to know more about ALKANE">ALKANE</a> <br/>Cycloalkane<br/>Alkene<br/>Cycloalkene</p>Answer :A</body></html> | |
| 50413. |
A compound of C, H and N contains the three element in the ratio of 9 : 1 : 3.5. Calculate the molecular formula given that the molecular mass of the compound is 108 amu Hint : Percentgae of C=(9)/(13.5)xx100=66.7,H=(1)/(13.5)xx100=7.4,N=(3.5)/(13.5)xx100=25.9. |
| Answer» <html><body><p><br/></p>Solution :Step I. Empirical formula of the compound <br/> `{:("Element","<a href="https://interviewquestions.tuteehub.com/tag/percentage-13406" style="font-weight:bold;" target="_blank" title="Click to know more about PERCENTAGE">PERCENTAGE</a>","Atomic mass","Gram <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> (Moles)","Atomic ratio (Molar ratio)","Simplest whole no. ratio"),("C",66.7,12,(66.7)/(12)=5.56,(5.6)/(1.85)=3.0,3),("H",7.4,1,(7.4)/(1)=7.40,(7.40)/(1.85)=4.0,4),("N",25.9,14,(25.9)/(14)=1.85,(1.85)/(1.85)=1.0,1):}` <br/> Empirical formula of compound `= C_(3)H_(4)N` <br/> Step II. Molecular formula of the compound <br/> Empirical formula mass `= 3 xx 12 + 4 xx 1 + 14 = 54 <a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>` <br/> Molecular mass = 108 <a href="https://interviewquestions.tuteehub.com/tag/amu-25369" style="font-weight:bold;" target="_blank" title="Click to know more about AMU">AMU</a> (<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a>) <br/> `nn=("Molecular mass")/("Empirical formula mass")=((108u))/((54u))=2` <br/> `:.` Molecular formula `= 2 xx C_(3)H_(4)N=C_(6)H_(8)N_(2)`.</body></html> | |
| 50414. |
A compound M_(p)X_(q) has cubic close packing (ccp) arrangement of X. Its unit cell structure is shown on the side. The empirical formula of the compound is |
| Answer» <html><body><p>MX<br/>`MX_(2)`<br/>`M_(2)X`<br/>`M_(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)X_(<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>)`</p>Solution :`"No. of M atoms" = underset(("Edge centre"))(4times1/4) + underset(("Body centre"))1=2` <br/> `"No. of atom" = underset("corners")(8times1/8)+underset("face centre")(6times1/2)=4` <br/> `therefore "<a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a>" = M_(2)X_(4)` <br/> `therefore "empirical formula" = MX_(2)`</body></html> | |
| 50415. |
A compound M_p X_q has cubic close packing (ccp) arrangement of X. Its unit cell structure . The empirical formula of the compound is |
| Answer» <html><body><p>MX<br/>`MX_2`<br/>`M_2X`<br/>`M_5X_14`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :No. of M <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> `{:(=4xx1/4,"" 1,=2),("(<a href="https://interviewquestions.tuteehub.com/tag/edge-965664" style="font-weight:bold;" target="_blank" title="Click to know more about EDGE">EDGE</a> centres)","(body-centred)",):}` <br/> No. of X atoms `{:(=8xx1/8,6xx1/2,=4),("(<a href="https://interviewquestions.tuteehub.com/tag/corners-934262" style="font-weight:bold;" target="_blank" title="Click to know more about CORNERS">CORNERS</a>)","(face-centres)",):}` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` Unit formula =`M_2X_4` and empirical formula =`MX_2`</body></html> | |
| 50416. |
A compound made up of elements A and B crystallises in the cubic sttruture. Atoms A are present on the corners as well as face centres wherease atoms B are present on the edge centres as will as body centre. What is the formula of the compound ? Draw the struture of its unit cell. |
| Answer» <html><body><p><br/></p>Solution :`{:("<a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> B/unit cell" , =8xx1/8 , +, 6 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 1/2=<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>),(, ("<a href="https://interviewquestions.tuteehub.com/tag/corners-934262" style="font-weight:bold;" target="_blank" title="Click to know more about CORNERS">CORNERS</a>"), , ("face-centres")),("Atoms B/unit cell" , = 12xx1/4 , +, 1=4),( , ("edge-centres") , , ("body-centre")):}` <br/>A:B = 4 :4 = 1:1 , so the formula is AB.</body></html> | |
| 50417. |
A compound made up of elements A and B crystallises in the cubic structure. Atoms A are present on the corners as well as face centres whereas atoms B are present on the edge centres as well as body centre. What is the formula of the compound ? Draw the structure of its unit cell. |
| Answer» <html><body><p><br/></p>Solution :`{:("<a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> A/unit cell",=8xx1/8"" +,6xx1/2=4),(,"(<a href="https://interviewquestions.tuteehub.com/tag/corners-934262" style="font-weight:bold;" target="_blank" title="Click to know more about CORNERS">CORNERS</a>)","(face-centres)"),("Atoms B/unit cell",=12xx1/4" " +,1=4),(,"(edge-corners)","(body-centres)"):}` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` A:B=4:4=1:1 . So the formula is AB.</body></html> | |
| 50418. |
A compound is soluble is conc. H_(2)SO_(4). It does not decolourise bromine in C Cl_(4) but oxidised by chromic anhydride in aqueous sulphuric acid within two second, turning orange solution to blue green , then opaque. The original solution cotnains |
| Answer» <html><body><p>A <a href="https://interviewquestions.tuteehub.com/tag/secondary-638692" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDARY">SECONDARY</a> alcohol<br/>An alkene<br/>An ether<br/>A primary alcohol</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Since oxidation is <a href="https://interviewquestions.tuteehub.com/tag/easier-447966" style="font-weight:bold;" target="_blank" title="Click to know more about EASIER">EASIER</a> and occuts very <a href="https://interviewquestions.tuteehub.com/tag/quickly-610723" style="font-weight:bold;" target="_blank" title="Click to know more about QUICKLY">QUICKLY</a> (just 2 seconds), hence it must be primary alcohol. The <a href="https://interviewquestions.tuteehub.com/tag/dichromate-951074" style="font-weight:bold;" target="_blank" title="Click to know more about DICHROMATE">DICHROMATE</a> solution changes from organe to blue green.</body></html> | |
| 50419. |
A compound is soluble in water. If ammonia is added to aqueous solution of compound, a reddish brown precipitate appears which is soluble in dill. HCl. The compound is a salt of : |
| Answer» <html><body><p>aluminium<br/>zinc<br/>iron<br/>cadmium</p>Solution :It is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a></body></html> | |
| 50420. |
A compound is soluble in conc. H_(2)SO_(4), it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous solution to blue, green and then opaque. The original compound is |
| Answer» <html><body><p>primary alcohol<br/>tertiary alcohol<br/><a href="https://interviewquestions.tuteehub.com/tag/alkene-853361" style="font-weight:bold;" target="_blank" title="Click to know more about ALKENE">ALKENE</a><br/><a href="https://interviewquestions.tuteehub.com/tag/ether-975855" style="font-weight:bold;" target="_blank" title="Click to know more about ETHER">ETHER</a></p>Solution :As the compound is soluble in conc. `H_(2)SO_(4)`, it may be as alkene, alcohol or ether. <br/> The compound does not decolourise `KMnO_(4)` solution, it cannot be <a href="https://interviewquestions.tuteehub.com/tag/ethene-975852" style="font-weight:bold;" target="_blank" title="Click to know more about ETHENE">ETHENE</a>. <br/> Further, it is oxidised by `CrO_(3)` in `H_(2)SO_(4)` it is not an ether. It is easily oxidised within two seconds it is primary alcohol.</body></html> | |
| 50421. |
A compound is soluble in conc. H_(2)SO_(4). It doesdecolourise bromine in carbon tetrachloride but oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning organge solution to blue, green and then opaque. The original compound is : |
| Answer» <html><body><p>an alkane<br/>a <a href="https://interviewquestions.tuteehub.com/tag/tertiary-665438" style="font-weight:bold;" target="_blank" title="Click to know more about TERTIARY">TERTIARY</a> alcohol<br/>a <a href="https://interviewquestions.tuteehub.com/tag/primary-1165403" style="font-weight:bold;" target="_blank" title="Click to know more about PRIMARY">PRIMARY</a> alcohol<br/>an ether</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50422. |
A compound is known to be hydrated doubel salt of potassium oxalate and oxalic acid of thetuype aK_(2)C_(2)O_(4), bH_(2)C_(2)O_(4), cH_(2)O, where a, b and c are unknown. When 1.613g of this compound is dissolved in water and solution is neutralised by 19.05mL of 0.1Nalkali and reduces25.40mL of this solution. What is the formula of the salt? |
| Answer» <html><body><p><br/></p>Answer :`K_(2)C_()O_(4) 3H_(2)C_(2)O_(4) .4H_(2)O`</body></html> | |
| 50423. |
A compound is heated with zinc dust and ammonium chloride followed by addition of t Tollen's reagent. Formation of silver mirror indicates the presence of following group |
| Answer» <html><body><p>`-CHO`<br/>`-overset(O)overset(||)(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>)-`<br/>`-NO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`-NH_(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 50424. |
A compound is forned by two elemets X and Y , Atoms of the element Y (asanions)make ccp and those of the element X (as cations)occupy all the octahbedral voids. What is the formula of the compound ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/suppose-656311" style="font-weight:bold;" target="_blank" title="Click to know more about SUPPOSE">SUPPOSE</a> number of atoms Y in ccp =n <br/> As number of <a href="https://interviewquestions.tuteehub.com/tag/octahedral-1127994" style="font-weight:bold;" target="_blank" title="Click to know more about OCTAHEDRAL">OCTAHEDRAL</a> voids = No. of atoms in ccp : No of cotahedral voids = n <br/>As alll the octahedral voids <a href="https://interviewquestions.tuteehub.com/tag/ar-380980" style="font-weight:bold;" target="_blank" title="Click to know more about AR">AR</a> occupied by atoms <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> , therefore, number of atoms X = n . <br/> Ratio of X :Y = n: n = 1:1. <br/> Hence the formula of the compound is XY.</body></html> | |
| 50425. |
A compound is formed by two elements X and Y. Atoms of the element Y (as anions) make ccp and those of the element X (as cation) occupy all the octahedral voids. What is the formula of the compound ? |
| Answer» <html><body><p></p>Solution :Suppose number of <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> Y in ccp=<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> <br/> As number of octahedral <a href="https://interviewquestions.tuteehub.com/tag/voids-1447686" style="font-weight:bold;" target="_blank" title="Click to know more about VOIDS">VOIDS</a> = No. of atoms in ccp `therefore` No. of octahedral voids=n <br/> As all the octahedral voids are occupied by atoms <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>, therefore , number of atoms X=n <br/> `therefore` Ratio of X :Y =n:n=1:1 <br/> Hence the formula of the compound is XY</body></html> | |
| 50426. |
A compound is formed by two elements M and N. The element N forms cep and atoms of M occupy 1/3rd of tetrahedral voids. What is the formula of the compound ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/suppose-656311" style="font-weight:bold;" target="_blank" title="Click to know more about SUPPOSE">SUPPOSE</a> the atoms N in the ccp= n `therefore`No. of <a href="https://interviewquestions.tuteehub.com/tag/tetrahedral-2294863" style="font-weight:bold;" target="_blank" title="Click to know more about TETRAHEDRAL">TETRAHEDRAL</a> voids = 2n <br/>As `1/3`rd of the tetrahedral voids are occupied by atoms M, therefore, no. of atoms `M="2n"/3` <br/> `therefore `<a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> of `M:N="2n"/3:n=2:3` . Hence, the formula is `M_2N_3`</body></html> | |
| 50427. |
A compound is formed by the substitution of two chlorine atoms for two hydrogen atoms in propane. What is the number of structural isomers possible ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Four : 1, 1-dichloropropane `(CH_(3)CH_(2)CHCl_(2))`, 1, 2-dichloropropane `(CH_(3)CHClCH_(2)Cl)` , 2,2-dichloropropane `(CH_(3)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> Cl_(2)CH_(3))` and 1, 3-dichloropropane `(ClCH_(2)CH_(2)CH_(2)Cl)`.</body></html> | |
| 50428. |
A compound is formed by elements A and B . This crystallizes in the cubic structure where the A atoms are at the corners of the cube can B atoms are at the body centers. The simplest formula of the compound is |
| Answer» <html><body><p>`A_(8)B_(4)`<br/>`AB_(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)`<br/>AB<br/>`A_(6)<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> of A perunit of the cell =`8times1/8=1` Atoms of B per unit cell=1 <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` The <a href="https://interviewquestions.tuteehub.com/tag/simplest-1208711" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLEST">SIMPLEST</a> formula of the compound is AB</body></html> | |
| 50429. |
A compound having the empirical formula C_(6)H_(6)O has the vapour density 47. find its Molecular formula (ii) The Simple A romatic Hydrocarbon compound (A) reacts with Bromine |
| Answer» <html><body><p></p>Solution :Empirical formula ` = C_(6)H_(6)O` <br/> Empirical formula mass `=(6 xx <a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>)+(6 xx <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)+(16xx1)` <br/> =72 + 6+16 <br/> = 94 <br/> <a href="https://interviewquestions.tuteehub.com/tag/vapour-1442886" style="font-weight:bold;" target="_blank" title="Click to know more about VAPOUR">VAPOUR</a> density =47 <br/> <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> mass `=2 xx ` Vapour density <br/> `= 2 xx 47` <br/> =94 <br/> Molecular formula `=n xx` Empirical formula <br/> `n = ("Molecular mass")/("Empirical formula mass ")` <br/> `n = 94 //94 rArr n = 1 ` <br/> Molecular formula`= 1xx C_(6)H_(6)O` <br/> `=<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> _(6)H_(6)O`<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_SP_MAR_19_E01_042_S01.png" width="80%"/></body></html> | |
| 50430. |
A Compound having the empirical formula C_(6) H_(6) O has the vapour density 47 . Find its Molecular formula. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/empirical-445984" style="font-weight:bold;" target="_blank" title="Click to know more about EMPIRICAL">EMPIRICAL</a> Formula ` = C_(6) H_(6) O`<br/>`n = ("<a href="https://interviewquestions.tuteehub.com/tag/molar-562965" style="font-weight:bold;" target="_blank" title="Click to know more about MOLAR">MOLAR</a> <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a>")/("Calculated empirical formula mass")`<br/>`= (2 xx "vapour <a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a>")/(<a href="https://interviewquestions.tuteehub.com/tag/94-342308" style="font-weight:bold;" target="_blank" title="Click to know more about 94">94</a>) = (2 xx 47)/(94) = 1 `<br/>molecular formula `(C_(6)H_(6)O) xx 1 = C_(6) H_(6) O`</body></html> | |
| 50431. |
A compound having bcc geometry has atomic mass 50. Calculate the density of the unit cell, if the edge length is 290pm. |
| Answer» <html><body><p>`6.81gcm^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`3.40gcm^(-3)`<br/>`13.62gcm^(-3)`<br/><a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> of these<br/></p>Solution :(a) density of unit <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a>, `d=(ZxxM)/(N_(A)xxa^(3))` <br/> `d=(2xx50)/((290xx10^(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>))^(3)xx6.023xx10^(23))=6.81g//cm^(3)`</body></html> | |
| 50432. |
A compound has molar of 98.98g. The analysis gave 24.27%C, 4.07%H and 71.6% CI. Determine the molecular formula of alkane from which the chlorinated compound is obtained. |
| Answer» <html><body><p></p>Solution :`C : <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a> : CI = (24.27)/(12) : (4.07)/(1) : (71.<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)/(35.5) = 1 : 2 : 1 `<br/> Empirical <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> is ` CH_(2)CI` <br/> <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of repeating empirical units in the <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> formula `= ("Molecular formula mass" )/("Empirical formula mass")=(98.98)/(49.5) = 2` <br/> Molecular formula is `C_(2)H_(4)CI_(2)` <br/> The formula of alkane from which the halogenated compound is obtained `= C_(2)H_(6)`.</body></html> | |
| 50433. |
A compound has the following composition Mg = 9.76%,S = 13.01%, 0 = 26.01, H_2O = 51.22, what is its empirical formula?[Mg = 24, S = 32, O = 16, H = 1] |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_TEL_CHE_XI_P1_C01_SLV_006_S01.png" width="80%"/> <br/><a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> the empirical formula is Mg `SO_4 .<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a> H_2O`.</body></html> | |
| 50434. |
A compound has C, H,N&S. The weight percentages of C&H are 41.37 and 5.75 respectively. On Kjeldahlising, the ammonia obtained from 1.01 g of the substance was neutralised by 11.6 ml of 1N HCI. In Carius method 0.2066 g of the substance gave 0.5544 g of BaSO_4.The molecular formula of the compound is |
| Answer» <html><body><p>`C_3H_4N` <br/>`C_3H_5NS`<br/>`C_2H_4NS`<br/>`C_6H_5NS`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 50435. |
A compound gives 'X' gas on addition of dilute HCI. The gas 'X', when passed through lime water or baryta water, gives white turbidity. Identify the compound. |
| Answer» <html><body><p>`Na_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)CO_(3)`<br/>`Na_(2)SO_(3)`<br/>`Na_(2)S_(2)O_(3)`<br/>`BaCO_(3)`</p>Answer :A::B::C::D</body></html> | |
| 50436. |
A compound forms hexagonl close-packed structure. What is the total number of voids in 0.5 mol of its? How many of these are tetrahedral voids ? |
| Answer» <html><body><p></p>Solution :No. of <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> in the olose packing = 0.5 mol = ` 0.5 xx 6.022 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(23) = 3.011 xx 10^(23)`<br/> No. of <a href="https://interviewquestions.tuteehub.com/tag/octahedral-1127994" style="font-weight:bold;" target="_blank" title="Click to know more about OCTAHEDRAL">OCTAHEDRAL</a> <a href="https://interviewquestions.tuteehub.com/tag/voids-1447686" style="font-weight:bold;" target="_blank" title="Click to know more about VOIDS">VOIDS</a> =No, of atoms in the packing = ` 3.011 xx 10^(23)` <br/>No. of <a href="https://interviewquestions.tuteehub.com/tag/tetrahedral-2294863" style="font-weight:bold;" target="_blank" title="Click to know more about TETRAHEDRAL">TETRAHEDRAL</a> voids = ` 2xx` No, of atoms in the packing = ` 2xx 3.011 xx 10^(23)= 6.022 xx 10^(23)`<br/>Total no. of voidsl `= 3.011 xx 10 + 6.022 xx 10^(23) = 9.033 xx 10^(23)`</body></html> | |
| 50437. |
A compound forms hexagonal close-packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids ? |
| Answer» <html><body><p></p>Solution :No. of <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> in the <a href="https://interviewquestions.tuteehub.com/tag/close-408965" style="font-weight:bold;" target="_blank" title="Click to know more about CLOSE">CLOSE</a> packing =0.5 mol =`0.5 xx 6.022xx10^23 =3.011xx10^23` <br/> No. of octahedral <a href="https://interviewquestions.tuteehub.com/tag/voids-1447686" style="font-weight:bold;" target="_blank" title="Click to know more about VOIDS">VOIDS</a>= No. of atoms in the packing =`3.011xx10^23` <br/> No. of tetrahedral voids= 2 x No. of atoms in the packing =`2xx3.011xx10^23 =6.022xx10^23` <br/> Total no. of voids =`3.011xx10+6.022xx10^23=9.033xx10^23`</body></html> | |
| 50438. |
A compound formed by elements X and Y has a cubic structure in which X atoms are at the corner of the cube and also at alternate face centers. Y atoms are present at the body center and also at the alternate edge center of the cube. If all the atoms are removed from one of the axis passing through the middle of the cube not containing face center atoms, formula of the compounds 64. If all the |
| Answer» <html><body><p>XY<br/>`X_(2)Y`<br/>`XY_(2)`<br/>`XY_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XII_V02_C02_E01_328_S01.png" width="80%"/> <br/> Formula `Z_(<a href="https://interviewquestions.tuteehub.com/tag/eff-966053" style="font-weight:bold;" target="_blank" title="Click to know more about EFF">EFF</a>(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>))=2,Z_(eff(Y))=1` <br/> `therefore` Formula `=X_(2)Y`</body></html> | |
| 50439. |
A compound formed by elements X and Y has a cubic structure in which X atoms are at the corner of the cube and also at alternate face centers. Y atoms are present at the body center and also at the alternate edge center of the cube. If all the atoms are removed from one of the plane passing through the middle of the cube which contains atoms both on the edge center as well as on the face center, calculate |
| Answer» <html><body><p>1<br/><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a><br/>3<br/>4<br/></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XII_V02_C02_E01_326_S01.png" width="80%"/> <br/> `XrArr =2X` atoms from face center are removed <br/> `YrArr=4Y` atoms from edge center are removed `YrArr=1Y` atom from <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> center is removed <br/> `Z_(<a href="https://interviewquestions.tuteehub.com/tag/eff-966053" style="font-weight:bold;" target="_blank" title="Click to know more about EFF">EFF</a>(X))=(n_(c))/(8)+("Alternate"n_(f))/(2)=(8)/(8)+((2-2))/(2)=1+0=1` <br/> `Z_(eff(Y))=(r_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>))/(1)+("Altranate"n_(c))/(4)=((1-1))/(1)+((4-4))/(4)=0+0=`zero<br/> `Z_(eff(X+Y))=1+0=1`</body></html> | |
| 50440. |
A compound formed by elements X and Y has a cubic structure in which X atoms are at the corner of the cube and also at alternate face centers. Y atoms are present at the body center and also at the alternate edge center of the cube. If all the atoms are removed from one of the plane passing through the middle of the cube which neither contains atoms on the edge center nor on the face center, total number of atoms in a cube. |
| Answer» <html><body><p>8<br/>12<br/><a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a><br/>18<br/></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XII_V02_C02_E01_327_S01.png" width="80%"/> <br/> `YrArr=1Y` atom from body center is removed Total number of atoms in a <a href="https://interviewquestions.tuteehub.com/tag/cube-940156" style="font-weight:bold;" target="_blank" title="Click to know more about CUBE">CUBE</a> =8(corner)+2 (<a href="https://interviewquestions.tuteehub.com/tag/alternate-373425" style="font-weight:bold;" target="_blank" title="Click to know more about ALTERNATE">ALTERNATE</a> <a href="https://interviewquestions.tuteehub.com/tag/face-982590" style="font-weight:bold;" target="_blank" title="Click to know more about FACE">FACE</a> center)+4 (alternate edge center) +<a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> (body center)=14 atoms/unit cube.</body></html> | |
| 50441. |
A compound formed by elements X and Y has a cubic structure in whch X atoms are at the corner of the cube and also at the face centers. Y atoms are present at the body center and at the edge center of the cube. If all the atoms are removed from one of the axis passing through one of the face centers of the cube, then formula of the compound is |
| Answer» <html><body><p>XY<br/>`XY_(2)`<br/>`X_(2)Y`<br/>`XY_(3)`<br/></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XII_V02_C02_E01_331_S01.png" width="80%"/> <br/> `YrArr1` body <a href="https://interviewquestions.tuteehub.com/tag/center-11455" style="font-weight:bold;" target="_blank" title="Click to know more about CENTER">CENTER</a> atom is removed <br/> `XrArr2` <a href="https://interviewquestions.tuteehub.com/tag/face-982590" style="font-weight:bold;" target="_blank" title="Click to know more about FACE">FACE</a> center atoms are removed <br/> Formula : `Z_(eff(X))=3,Z_(eff(Y))=3` <br/> Formula is `X_(3)Y_(3)` or 3XY.</body></html> | |
| 50442. |
A compound formed by elements X and Y has a cubic structure in whch X atoms are at the corner of the cube and also at the face centers. Y atoms are present at the body center and at the edge center of the cube. If all the atoms from the diagonals of one of the face of the cube are removed, then Z_(eff) is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a><br/>4<br/>7<br/><a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a><br/></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XII_V02_C02_E01_329_S01.png" width="80%"/> <br/> `XrArr4` corner atoms are removed <br/> `XrArr1` <a href="https://interviewquestions.tuteehub.com/tag/face-982590" style="font-weight:bold;" target="_blank" title="Click to know more about FACE">FACE</a> center atom is removed <br/> `Z_(eff(X))=(n_(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>))/(8)+(n_(f))/(2)=((8-4))/(8)+((6-1))/(2)=(1)/(2)+(5)/(2)=3`<br/> `Z_(eff(Y))=(n_(b))/(1)+(n_(f))/(4)=(1)/(1)+(12)/(4)=1+3=4` <br/> `Z_(eff(X))=3+4=7`</body></html> | |
| 50443. |
A compound formed by elements X and Y has a cubic structure in whch X atoms are at the corner of the cube and also at the face centers. Y atoms are present at the body center and at the edge center of the cube. If all the atoms are removed from one of the plane passing through the middle of the cube, calculate total number of atoms in the cube, |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a><br/>9<br/>12<br/>18<br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/plane-1155510" style="font-weight:bold;" target="_blank" title="Click to know more about PLANE">PLANE</a> <a href="https://interviewquestions.tuteehub.com/tag/passing-1148520" style="font-weight:bold;" target="_blank" title="Click to know more about PASSING">PASSING</a> through the middle of cube (other atoms are not <a href="https://interviewquestions.tuteehub.com/tag/shown-1206565" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWN">SHOWN</a>) <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XII_V02_C02_E01_330_S01.png" width="80%"/> <br/> `YrArr1` body center atom is removed <br/> `YrArr4` edge center atoms are removed <br/> `XrArr4` <a href="https://interviewquestions.tuteehub.com/tag/face-982590" style="font-weight:bold;" target="_blank" title="Click to know more about FACE">FACE</a> center atoms are removed <br/> Total number of atom in the cube =8 (corner)+2 (face centeres) +zero (body center)+8 (edge centers).</body></html> | |
| 50444. |
A compound formed by elements X and Y crystallizes in the cubic structure where Y atoms are at the corners of the cube and X atoms are at the alternate faces. What is the formula of the compound ? |
| Answer» <html><body><p><br/></p>Solution :As there are 8 Y <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> at the corners and <a href="https://interviewquestions.tuteehub.com/tag/contribution-932552" style="font-weight:bold;" target="_blank" title="Click to know more about CONTRIBUTION">CONTRIBUTION</a> of each =`1/8`, therefore , no. of Y atoms/unit <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a> `=8xx1/8=1` . There can be only two X atoms on <a href="https://interviewquestions.tuteehub.com/tag/alternate-373425" style="font-weight:bold;" target="_blank" title="Click to know more about ALTERNATE">ALTERNATE</a> faces. As contribution of each of them =`1/2`, therefore, no. of X-atoms/unit cell =`2xx1/2=1`. Hence, formula is <a href="https://interviewquestions.tuteehub.com/tag/xy-747762" style="font-weight:bold;" target="_blank" title="Click to know more about XY">XY</a></body></html> | |
| 50445. |
A compound formed by elements X and Y crystallises in a cubic structure in which the X atoms are at the corners of a cube and the Y atoms are at the face-centres. The formula of the compound is |
| Answer» <html><body><p>`XY_(2)`<br/>`XY_(3)`<br/>`X_(3)Y`<br/><a href="https://interviewquestions.tuteehub.com/tag/xy-747762" style="font-weight:bold;" target="_blank" title="Click to know more about XY">XY</a></p>Solution :No. of A <a href="https://interviewquestions.tuteehub.com/tag/stoms-3077995" style="font-weight:bold;" target="_blank" title="Click to know more about STOMS">STOMS</a> present per <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> cell =`8times1/8=1` <br/> No. of B atoms present per unit cell =`6times1/2=3` ltbegt `therefore` Correct composition of `A_(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>)B_(y)"is"AB_(3)`</body></html> | |
| 50446. |
A compound formed by elements A and B has a cubic structure in which A atoms are at the corners of the cube and B atoms are at the face centres. Derive the formula of the compound. |
| Answer» <html><body><p></p>Solution :As A atoms are <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> at the <a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> <a href="https://interviewquestions.tuteehub.com/tag/corners-934262" style="font-weight:bold;" target="_blank" title="Click to know more about CORNERS">CORNERS</a> of the cube, therefore , number of atoms of A in the unit <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a> `=1/8xx8=1` <br/> As B atoms are present in the face centres of the 6 <a href="https://interviewquestions.tuteehub.com/tag/faces-982657" style="font-weight:bold;" target="_blank" title="Click to know more about FACES">FACES</a> of the cube, therefore, number of atoms of B in the unit cell`=1/2xx6=3` <br/> `therefore` Ratio of atoms A:B =1:3 <br/> Hence, the formula of the compound is `AB_3`</body></html> | |
| 50447. |
A compound exists in the gaseous phase both as monomer (A) and dimer (A_(2)) The mo1 wt of A is 48 In an experiment 96g of compound was confined in a container of volume 33.6 litre and heated to 273^(@)C Calulate the pressure developed if the compound exists as dimer to the extent of 50% by weight under these conditions . |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/2atm-300626" style="font-weight:bold;" target="_blank" title="Click to know more about 2ATM">2ATM</a>`</body></html> | |
| 50448. |
A compound decolourises Baeyer's reagent and gives a mixture of propanoic acid and ethanoic acid when treated with a hot and conc. solution of KMnO_4 . The compound is |
| Answer» <html><body><p>pent-1-ene<br/>pent-2-ene<br/>2-methylbut-1-ene<br/>2-methylbut-2-ene</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 50449. |
A compound contains two types of atoms X and Y. It crystallizes in a cubic lattice with atom X at the corners of the unit cell and atom Y at the body centres. The simplest possible formula of this compound is |
| Answer» <html><body><p>`X_()<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)Y`<br/>`X_(2)Y`<br/>XY<br/>`XY_(6)`</p>Solution :X atoms <a href="https://interviewquestions.tuteehub.com/tag/per-590802" style="font-weight:bold;" target="_blank" title="Click to know more about PER">PER</a> unit <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a> =`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>//8times8=1` <br/> Y atoms per unit cell =1 <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` formula of compound :XY</body></html> | |
| 50450. |
A compound contains two dissimilar asymmetric carbon atoms. The number of optical isomers is |
| Answer» <html><body><p>2<br/>3<br/><a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a><br/>5</p>Solution :4</body></html> | |