InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 50351. |
A cubic solid is made up of two elements X and Y. Atoms Y are present at the corners of the cube and atoms X at the body centre. What is the formula of the compound ? What are the coordination numbers of X and Y ? |
| Answer» <html><body><p></p>Solution :As <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> Y are present at the 8 <a href="https://interviewquestions.tuteehub.com/tag/corners-934262" style="font-weight:bold;" target="_blank" title="Click to know more about CORNERS">CORNERS</a> of the cube, <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> , number of atoms of Y in the <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> cell `=1/8xx8=1` <br/> As atoms X are present at the body centre, therefore, number of atoms of X in the unit cell=1<br/> `therefore` Ratio of atoms X :Y =1:1 <br/> Hence, the formula of the <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a> is XY <br/> Coordination number of each of X and Y =8</body></html> | |
| 50352. |
A cubic solid is made up of two elements P and Q. Atoms Q are present at the corners of the cube and atoms P at the body centre. What is the formula of the compound ?What are the coordination numbers of P and Q ? |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :( Usesymbols P and <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> in <a href="https://interviewquestions.tuteehub.com/tag/place-1155224" style="font-weight:bold;" target="_blank" title="Click to know more about PLACE">PLACE</a> of <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> and Y)</body></html> | |
| 50353. |
A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8 g cm^(-3), then the number of atoms present in 256 g of the crystal is Nxx10^24 . The value ofN is |
| Answer» <html><body><p><br/></p>Solution :`rho=(ZxxM)/(a^3xxN_0xx10^(-30))`where a is in pm and M in g `<a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>^(-1)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>=(4xxM)/((400)^3xx6xx10^23xx10^(-30))` or M=76.8<br/> <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> in 256 g =`256/76.8`=3.33<br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` No. of atoms =`3.33xx6xx10^23=2xx10^24`</body></html> | |
| 50354. |
A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8g cm^(-3) , then the number of atoms present in 256 g of the crystal isN xx 10^(24). The value of N is |
| Answer» <html><body><p><br/></p>Solution :`p ( Z <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> M)/( a^(3) xx N_(0) xx 10^(-30)` <br/>Where a is in pm and M in g ` Mol^(-1)`<br/>` 8 = ( 4 xx M)/((400)^(3) xx 6 xx 10^(23) xx 10^(-30))) <a href="https://interviewquestions.tuteehub.com/tag/orm-11673" style="font-weight:bold;" target="_blank" title="Click to know more about ORM">ORM</a> = 76.8` <br/>Moles in <a href="https://interviewquestions.tuteehub.com/tag/256-297976" style="font-weight:bold;" target="_blank" title="Click to know more about 256">256</a> g = ` 256/76.8 = 3.33` <br/> No, of <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a>= ` 3.33 xx 6 xx 10^(23)`<br/>`= <a href="https://interviewquestions.tuteehub.com/tag/2xx-1840186" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX">2XX</a> 10^(24)`</body></html> | |
| 50355. |
A crystalline solid has a cubic structure in which tungsten (W) atoms are located at the cube corners of the unit cell,oxygen atoms atthe cube edgesand sodium atom at the cubecentre. The molecular formula of the compund is |
| Answer» <html><body><p>`Na_(2)WO_(3)`<br/>`NaWO_(4)`<br/>`NaWO_(3)`<br/>`Na_(2)WO_(4)`</p>Solution :No. of W <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a>=`8times1/8=1`<br/> No. of O atoms=`12times1/4=3`<br/> No. of <a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a> atoms=`1times1=1` ltbnrgt <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> of <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a>: `NaWO_(3)`.</body></html> | |
| 50356. |
A crystalline solid have |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/disordered-7375297" style="font-weight:bold;" target="_blank" title="Click to know more about DISORDERED">DISORDERED</a> arrangement <br/>Long range order <br/>Short range order <br/>None of these </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :A <a href="https://interviewquestions.tuteehub.com/tag/crystalline-940053" style="font-weight:bold;" target="_blank" title="Click to know more about CRYSTALLINE">CRYSTALLINE</a> solid have long range order.</body></html> | |
| 50357. |
A crystalline salt on being rendered anhydrous loses 45.6 % of its weight. The percentage composition of anhydrous salt is : Al = 10.5 % , K = 15.1 % , S = 24.96 %, O = 49.92 % Find the simplest formula of the anhydrous and crystalline salt. |
| Answer» <html><body><p><br/></p>Solution :Step I. Formula of anhydrous <a href="https://interviewquestions.tuteehub.com/tag/salt-1193804" style="font-weight:bold;" target="_blank" title="Click to know more about SALT">SALT</a> <br/> `{:("Element","Percentage","Atomic mass","Gram atoms (Moles)","Atomic ratio (Molar ratio)","Simplest whole no. ratio"),("Al",10.5,27,(10.50)/(27)=0.39,(0.39)/(0.38)=1.03,1),("K",15.1,39,(15.1)/(39)=0.38,(0.38)/(0.38)=1.00,1),("S",24.96,32,(24.96)/(32)=0.78,(0.78)/(0.38)=2.05,2),("O",49.92,16,(49.92)/(16)=3.12,(3.12)/(0.380)=<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>.21,8):}` <br/> Formula of anhydrous salt `= AlKS_(2)O_(8)` <br/> Empirical formula mass `= 27 + 39 + 2 xx 32 + 8 xx 16 = 258 u` <br/> Step II. Formula of crystalline salt <br/> <a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> the <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of hydrated salt = 100 u , Weight of water lost = 45.6 u <br/> Weight of anhydrous salt `= 100 - 45.6 u = 54.4 u` <br/> If the weight the anhydrous salt is 54.4 u, that of water = 45.6 u <br/> If the weight of anhydrous salt is 258 u, that of water `= ((45.6u))/((54.4u))xx(258u)=216.3u` <br/> No. of `H_(2)O` molecules `= ("Weight of water")/("Molecular mass of water")=((216.3u))/((18u))=12` (approx) <br/> `:.` The formula of crystalline salt `= KAlS_(2)O_(8).12H_(2)O`.</body></html> | |
| 50358. |
A crystalline compound when heated become anhydrous by losing 51.2 % of the mass. On analysis, the anhydrous compound gave the following percentage composition : Mg = 20.0 % , S = 26.66 % and O = 53.33 %. Calculate the molecular formula of the anhydrous compound and crystalline compound. The molecular mass of anhydride compound is 120 u. |
| Answer» <html><body><p></p>Solution :Step I. <a href="https://interviewquestions.tuteehub.com/tag/determination-949893" style="font-weight:bold;" target="_blank" title="Click to know more about DETERMINATION">DETERMINATION</a> of empirical formula of the anhydrous compound <br/> `{:("Element","Percentage","Atomic mass","Gram atoms (Moles)","Atomic ratio (Molar ratio)","Simplest whole no. ratio"),("<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>",20.0,24,(24.0)/(24)=0.83,(0.83)/(0.83)=1,1),("S",26.66,32,(26.66)/(32)=0.83,(0.83)/(0.83)=1,1),("O",53.33,16,(53.33)/(16)=3.33,(3.33)/(0.83)=4.01,4):}` <br/> `:.` The empirical formula of anhydrous compound is `MgSO_(4)` <br/> Step II. Determination of the molecular formula of the anhydrous compound <br/> Empirical formula mass `= 24+32 +4 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 16 = 24 + 32 + 64 = <a href="https://interviewquestions.tuteehub.com/tag/120-270396" style="font-weight:bold;" target="_blank" title="Click to know more about 120">120</a>` u <br/> Molecular mass = 120 u (Given) , `n=("Molecular mass")/("Empirical formula mass")=(120)/(120)=1` <br/> `:.` Molecular formula `=nxx` Empirical formula `=1 xx MgSO_(4)=MgSO_(4)` <br/> `:.` Molecular formula of anhydrous compound `= MgSO_(4)` <br/> Step III. Determination of molecular formula of the crystalline compound <br/> Let us first calculate the number of molecules of water of crystallisation in the compound. For that, <br/> Let the weight of hydrated compound = 100 u <br/> Weight of water lost = 51.2 u <br/> `:.` Weight of anhydrous compound `= 100-51.2 = 48.9` u <br/> Now, if the weight of anhydrous compound is 48.8 u, then that of water 51.2 u <br/> If the weight of anhydrous compound is 120 u, then that of water `= (51.2)/(48.8)xx120 = 125.9` u <br/> Molecular mass of water `(H_(2)O)=2xx1+16 = 18` u <br/> `:.` No. of `H_(2)O` molecules `= ("Weight of water")/("Molecular mass of water")=(125.9)/(18)=7` (approx) <br/> Thus, the formula of crystalline compound `= MgSO_(4).7H_(2)O`.</body></html> | |
| 50359. |
A crystal of Lead (II) suphide has NaCl structure. In this crystal the shortest distance between thePb^(2+) ion ands^(2-) ion is 297 pm. What is the length of the edge of the unit cell in lead sulphide ?Also calculate the unit cell volume. |
| Answer» <html><body><p><br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/edge-965664" style="font-weight:bold;" target="_blank" title="Click to know more about EDGE">EDGE</a> 'a' of unit cell = <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> ` xx` <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> between` Pb^(2+) and S^(2-)` <a href="https://interviewquestions.tuteehub.com/tag/ions-1051295" style="font-weight:bold;" target="_blank" title="Click to know more about IONS">IONS</a> .</body></html> | |
| 50360. |
A crystal of Lead (II) sulphide has NaCl structure. In this crystal the shortest distance between the Pb^(2+) ion and S^(2-) ion is 297 pm. What is the length of the edge of the unit cell in lead sulphide ? Also calculate the unit cell volume. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Edge 'a' of <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a> = 2 x Distance between `Pb^(2+)` and `S^(2-)`ions .</body></html> | |
| 50361. |
A crystal of KCl containing a small amount of CaCl_(2) will have |
| Answer» <html><body><p>vacant `<a href="https://interviewquestions.tuteehub.com/tag/cl-408888" style="font-weight:bold;" target="_blank" title="Click to know more about CL">CL</a>^(-)` sites<br/>vacant `<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>^(+)` sites and a higher <a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> as compared to pure KCl<br/>vacant `K^(+)` sites and a <a href="https://interviewquestions.tuteehub.com/tag/lower-1080637" style="font-weight:bold;" target="_blank" title="Click to know more about LOWER">LOWER</a> density as compared to pure KCl<br/>`K^(+)` ions in the interstitial sites</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50362. |
A crystal may have a number of planes or axes of symmetry but it possesses only one ----- of symmetry. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a></body></html> | |
| 50363. |
A crucially important species formed by oxygen in stratosphere is ______. |
| Answer» | |
| 50364. |
A cricket ball of mass 0.5 kg is moving with a velocity of 100 ms^(-1), the wavelength associated with its motion is |
| Answer» <html><body><p>`13.25xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/26-298265" style="font-weight:bold;" target="_blank" title="Click to know more about 26">26</a>) m`<br/>`13.25 xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/34-308171" style="font-weight:bold;" target="_blank" title="Click to know more about 34">34</a>)` m <br/>`13.25xx10^(-36) m`<br/>`6.6xx10^(-34) m`</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/lambda-539003" style="font-weight:bold;" target="_blank" title="Click to know more about LAMBDA">LAMBDA</a> = (<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>)/(mv) = (6.6xx10^(-34))/(0.5xx100) = 13.25 xx 10^(-36) m `</body></html> | |
| 50365. |
A covalent molecule AB_(3) has trigonal pyramidal structure. The number of lone pair and bonding pair of electrons in the molecule are ...... . |
| Answer» <html><body><p>2 and 2 <br/><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> and 1<br/>1 and 3 <br/>0 and 4</p>Solution :1 and 3 <br/>`AB_(3) and AB_(3)` E are the same type <a href="https://interviewquestions.tuteehub.com/tag/atom-887280" style="font-weight:bold;" target="_blank" title="Click to know more about ATOM">ATOM</a>. There are `sigma` type three A - B <a href="https://interviewquestions.tuteehub.com/tag/bond-900583" style="font-weight:bold;" target="_blank" title="Click to know more about BOND">BOND</a> in it and one nonbonding electron pair on A. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_CHE_XI_P1_C04_E03_095_S01.png" width="80%"/> <br/> Due to this non bonding electron pair and as per the principal of VSEPR three A - B bonds come closer and <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> the pyramidal triangle structure.</body></html> | |
| 50366. |
A covalent bond is likely to be fonny between two elements which |
| Answer» <html><body><p>have <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> electronegativities<br/>have low ionization energies <br/>have low <a href="https://interviewquestions.tuteehub.com/tag/melting-1093090" style="font-weight:bold;" target="_blank" title="Click to know more about MELTING">MELTING</a> <a href="https://interviewquestions.tuteehub.com/tag/points-1157347" style="font-weight:bold;" target="_blank" title="Click to know more about POINTS">POINTS</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> <a href="https://interviewquestions.tuteehub.com/tag/ions-1051295" style="font-weight:bold;" target="_blank" title="Click to know more about IONS">IONS</a> with a small charge </p>Answer :A</body></html> | |
| 50367. |
A correct IUPAC name for the following compound is: |
| Answer» <html><body><p>3,6,7-trimethyl-4-bromo-1-octene <br/>4-bromo-3-methyl-6-isopropyl-1-heptene<br/>4-bromo-3,6,7-triethyl-1-octene<br/>4-bromo-6-isopropyl-3-methyl-1-heptene</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50368. |
A correct IUPAC name for the following compound is: |
| Answer» <html><body><p> 2,5-Dimethyl-3-propyl <a href="https://interviewquestions.tuteehub.com/tag/heptane-1018318" style="font-weight:bold;" target="_blank" title="Click to know more about HEPTANE">HEPTANE</a> <br/> 3,6-Dimethyl-5-propyl heptane<br/>6-Methyl-4-(1-methylethyl)<a href="https://interviewquestions.tuteehub.com/tag/octane-1128027" style="font-weight:bold;" target="_blank" title="Click to know more about OCTANE">OCTANE</a> <br/>3-Methyl-5-(1-methylethyl)octane </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 50369. |
A correct IUPAC name for the following compound is : |
| Answer» <html><body><p>4-propyl-5-chloro-3-heptanol<br/>4-(1-chloropropyl)-3-heptanol <br/> 4-propyl-3-chloro-5-heptanol <br/>5-chloro-4-propyl-3-heptanol </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 50370. |
A copper wire is dipped in silver nitrate solution in beaker A and a silver wire is dipped in a solution of copper sulphate kept in beaker B. If the standard electrode potential for Cu^(2+) +2e^(-) rarr Cu " is " +0.34 and for Ag^(+) +e^(-) rarr Agis 0.80 V . Given E^@(Ni^(2+)|Ni)=-0.25V and E^@(Cu^(2+) |Cu) = 0.34 V Predict in which beacker the ions present will get reduced ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :In <a href="https://interviewquestions.tuteehub.com/tag/beaker-894039" style="font-weight:bold;" target="_blank" title="Click to know more about BEAKER">BEAKER</a> A , `<a href="https://interviewquestions.tuteehub.com/tag/ag-362275" style="font-weight:bold;" target="_blank" title="Click to know more about AG">AG</a>^(+)` will be <a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a>.</body></html> | |
| 50371. |
A copper plate of 20 cm x 10 cm is to be plated with silver of 1 mm thickness on both the sides. Number of moles of silver required for plating is (density of silver =10.8 g m /cc)____________ |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> = `20xx10xx0.1=<a href="https://interviewquestions.tuteehub.com/tag/20c-292943" style="font-weight:bold;" target="_blank" title="Click to know more about 20C">20C</a> C` <br/> `1C C-10.8g` <br/> `20C C-20xx10.8=2169` <br/> On both sides `=2xx216=432g` <br/> `therefore` No. of moles of `Ag=(432)/(<a href="https://interviewquestions.tuteehub.com/tag/108-266746" style="font-weight:bold;" target="_blank" title="Click to know more about 108">108</a>)=4`</body></html> | |
| 50372. |
A container of just 10cc has 2.69 xx 10^20 gas molecules at 0^@C. What is the pressure exerted? |
| Answer» <html><body><p></p>Solution :Number of <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> of the gas = `(2.69 xx 10^20)/(6.022 xx 10^(23)) = <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>.47 xx 10^(-4)` <br/> Pressure (P) exerted by gas <a href="https://interviewquestions.tuteehub.com/tag/molecules-563030" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULES">MOLECULES</a> : <br/> `P = (nRT)/V = (4.47 xx 10^(-4) xx 82.1 xx273)/10 = 1 atm`.</body></html> | |
| 50373. |
A container is separated into two 1 litre compartments by a piston of negligible mass as shown below. In lower compartment 0.1 bar pressure and the other compartment is empty. Now the stoppers are removed so that the gas expands to 2 litre. Heat is supplied to the gas so that finally pressure of gas equals to 0.1 bar. Calculate DeltaHof the process in joule. [1 "bar" liter = 100 J] |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a></body></html> | |
| 50374. |
A container holds 3 liter of N_(2(g)) and H_(2)O_((l)) at 29^(@)C The prssure is found to be 1 atm The water in container is instantaneously electrolysed to give H_(2) and O_(2) following the reaction H_(2)O_(l) rarrH_(2(g)) +(1)/(2)O_(2_(g)) At the end of electrolysis the pressure was found to be 1.86atm calculate the amount of water present in the container If the aqueous tension of water at 29^(@)C is 0.04 atm. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`1.24 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>`</body></html> | |
| 50375. |
A conjugated alkediene having molecular formula C_13H_22 on ozonolysis yielded ethyl methyl ketone and cyclohexanecarbaldehyde. Identify the diene, write its structural formula and give its IUPAC name. |
| Answer» <html><body><p></p>Solution :The structures of the products of ozonolysis are : <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C13_E02_002_S01.png" width="80%"/> <br/> Since, the total number of carbon atoms of the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> products is 11 (4+7) while the MF of the <a href="https://interviewquestions.tuteehub.com/tag/conjugated-7673119" style="font-weight:bold;" target="_blank" title="Click to know more about CONJUGATED">CONJUGATED</a> diene is `C_13H_22`, therefore , the ozonolysis must have also produced another two carbon product. Further since the <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a> `(C_13H_22)` is an alkadiene, therefore , this two carbon product. Further since the given compound `(C_13H_22)` is an alkadiene, therefore , this two carbon product must be glyoxal, O=CH-CH=O. Replace the oxygen atoms from these three products by double bonds, the structure of the alkadiene is <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C13_E02_002_S02.png" width="80%"/></body></html> | |
| 50376. |
A conjugated alkadiene having molecular formula C_(13)H_(22), on ozonolysis, yielded ethyl methylketone and cyclohexanecarbaldehyde. The IUPAC name of the diene is |
| Answer» <html><body><p> 1-cyclohexyl-2-methylhexa-1,3-diene<br/>1-cyclohexyl-4-methylhexa-1,3-diene <br/>1-cyclohexyl-1-methylhexa-1,4-diene<br/>1-cyclohexyl-3-methylhexa-1,4-diene </p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/structures-17929" style="font-weight:bold;" target="_blank" title="Click to know more about STRUCTURES">STRUCTURES</a> of the products of ozonolysis are <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E02_170_S01.png" width="80%"/><br/> Since the number of carbon atoms of the two products is 11(4+7), therefore, the ozonolysis must have <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> produced another two carbon <a href="https://interviewquestions.tuteehub.com/tag/atom-887280" style="font-weight:bold;" target="_blank" title="Click to know more about ATOM">ATOM</a> product. Further, since the given compound `(C_(13) H_(22))` cis an alkadiene, this two carbon compound must be glyoxal. OHCCHO. Replace the oxygen atoms from these <a href="https://interviewquestions.tuteehub.com/tag/three-708969" style="font-weight:bold;" target="_blank" title="Click to know more about THREE">THREE</a> products by double bonds, the structure of alkadiene is <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E02_170_S02.png" width="80%"/></body></html> | |
| 50377. |
(A): Concentration of soluble F^(-) ions in drinking water about 1 ppm is essential. (R) Enamel on teeth is made much harder by converting hydroxyapatile 3Ca_(3)(PO_4)_2Ca(OH)_2 into 3Ca_(3)(PO_4)_2 CaF_2 |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a>'of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/> (A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R) is true </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Both (A) and (R) are true and (R) is not the correct explanation of (A)</body></html> | |
| 50378. |
The compound 'A' on heating gives a colourless gas and a residue. The residue dissolves in water to obtain (B). When excess of CO_(2) is bubbled through aqueous solution of B gentle heating gives back A. Compound 'C' is |
| Answer» <html><body><p>`CaCO_(3)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/ca-375" style="font-weight:bold;" target="_blank" title="Click to know more about CA">CA</a>(HCO_(3))_(2)`<br/>`NaCO_(3)`<br/>`NaHCO_(3)`</p>Solution :`CaCO_(3)(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>)overset(Delta)rarrCaO+CO_(2)uarroverset(H_(2)O)rarrCa(<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>)_(2)(Y)overset(CO_(2))rarrCa(HCO_(3))_(2)(Z)`</body></html> | |
| 50379. |
A compound X of boron, reacts with NH_(3)on heatingto giveanother compound Y which is called inorganicbenzene. The compound X canbe prepared by treatingBF_(3) withLithium aluminiumhydride. The compounds X and Y are representedby the formules. |
| Answer» <html><body><p>`B_(2)H_(6), B_(3)N_(3)H_(6)`<br/>`B_(2)O_(3), B_(3)N_(3)H_(6)`<br/>`BF_(3),B_(3)N_(3)H_(6)`<br/>`B_(3)N_(3)H_(6), B_(2)H_(6)`</p>Solution :`underset("Diborane (<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>)")(B_(2)H_(6)) + 6NH_(3) overset(473 K)<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> underset("Inorganic benzene (Y)")(2B_(3)N_(3)H_(6)) + 12H_(2)` <br/> `4BF_(3)+3LiAlH_(4)rarr 2B_(2)H_(6) + 3LiF+3AlF_(3)`</body></html> | |
| 50380. |
A compound X, of boron reacts with NH_3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF_3 with lithium aluminum hydride. The compounds X and Y are represented by the formulas… |
| Answer» <html><body><p>`B_2H_6, B_3N_3H_6`<br/>`B_2O_3 , B_3N_3H_6`<br/>`BF_3, B_3N_3H_6`<br/>`B_3N_3H_6, B_2H_6`</p>Solution :(i)`B_2H_6` reacts with ammonia and gives `B_2H_6 . 2NH_3`which is formulated as `[BH_2(NH_3)_2]^(+) [BH_4]^(-)`and on <a href="https://interviewquestions.tuteehub.com/tag/heating-1017297" style="font-weight:bold;" target="_blank" title="Click to know more about HEATING">HEATING</a> gives `B_3H_3H_6`borazine <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> called borazole. <br/> `underset"(X)"(3B_2H_6+6NH_3) to <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>[BH_2(NH_3)_2]^(+) [BH_4]^(-) oversetDeltato underset"(Y)"(2B_3N_3H_6) + 12H_2` <br/> (ii)`B_2H_6` can be prepared by reduction of `BF_3` with `LiAlH_4 . 4BF_3 + 3LiAlH_4 to underset"(Y)"(2B_2H_6) + 3LiF + 3AlF_3`</body></html> | |
| 50381. |
A compound X is heated with C_(2)H_(5) OH and H_(2)SO_(4) the fumes produced burn with green flame. The compound X is |
| Answer» <html><body><p>`H_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)BO_(3)`<br/>`Na_(2)B_(4)O_(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>). 10 H_(2) O`<br/>`K_(3)BO_(3)`<br/><a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> of these</p>Answer :B</body></html> | |
| 50382. |
A compound "X" has molecular formula C_5H_(9) Cl. It does not react with bromine in C Cl_4. On treatment with strong base it produces single compound "Y" (C_5H_8) and reacts with Br_(2)(aq). Ozonolysis of "Y" produces a compound C_5H_(8)O_2. The structure of X is |
| Answer» <html><body><p><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E01_042_O01.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E01_042_O02.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E01_042_O03.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E01_042_O04.png" width="30%"/> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E01_042_S01.png" width="80%"/></body></html> | |
| 50383. |
A compound ''X" has boiling point of 475 K but it starts decomposing at 400 K. Which type of distillation process is suitable for its purification ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/distillation-15402" style="font-weight:bold;" target="_blank" title="Click to know more about DISTILLATION">DISTILLATION</a> under <a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a> <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a></body></html> | |
| 50384. |
A compound X has a molecular formula C_(2)Cl_(3)OH. It reduces Fehling solution and on oxidation produces a monocarboxylic acid Y. X can also be obtained by the action of Cl_(2) on Ethanol. X is |
| Answer» <html><body><p>Chloral<br/>`CHCl_(3)`<br/>`CH_(3)<a href="https://interviewquestions.tuteehub.com/tag/cl-408888" style="font-weight:bold;" target="_blank" title="Click to know more about CL">CL</a>` <br/>Chloroacetic acid</p>Solution :As it reduces Fehling solution, so it <a href="https://interviewquestions.tuteehub.com/tag/contains-11473" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAINS">CONTAINS</a> aldehyde group. It is chloral `Cl_(3)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> - CHO` since it is obtained by the action of `Cl_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` on ethanol</body></html> | |
| 50385. |
A compound (X ) gives fruity smell. [X] on hydrolysis gives an acid and alcohol . Acid give violet colour with neutral FeCl_(3) while alcohol give yellow precipitate on boiling with I_(2) and NaOH. (X) can be : |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E02_025_O01.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E02_025_O02.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E02_025_O03.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E02_025_O04.png" width="30%"/> </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`[R-underset(O)underset(||)(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>)-OR' <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>("Hydrolysis")to R-CO OH +R'-OH]`</body></html> | |
| 50386. |
A compound X declourises Br_(2) water and reacts slowly with conc H_(2)SO_(4) to give an addition product. X reacts with HBr to form Y. Y reacts with NaOH to form Z. on oxidation Z gives hexan-3-one. X, Y and Z in the reactions are underset("Addition product") underset(darr "conc. "H_(2)SO_(4))(X) overset(Br_(2)" water")to"Decolourisation" X overset(HBr) to Y overset(NaOH) to Z overset([O])to CH_(3)CH_(2)underset("Hexan-3-one")(CH_(2)-underset(O)underset(||)(C)-CH_(2)CH_(3)) |
| Answer» <html><body><p>`X=CH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)CH_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)CH=CHCH_(3),Y=CH_(3)CH_(2)CH(Br)CH(Br)CH_(2)CH_(3),Z=CH_(3)CH_(2)CH_(3)`<br/>`X=CH_(3)CH=CHCH_(3),Y=CH_(3)CH(Br)CH(Br)CH_(3),Z=CH_(3)CH_(2)CH_(2)OH`<br/>`X=CH_(3)CH_(2)CH=CHCH_(2)CH_(3),Y=CH_(3)CH_(2)-<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>(Br)underset(|)(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>)H-CH_(2)CH_(2)CH_(3),Z=CH_(3)CH_(2)CH_(2)-underset(OH)underset(|)(C)H-CH_(2)CH_(3)`<br/>`X=CH_(3)CH_(2)CH_(2)CH=CHCH_(3),Y=CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)CH_(2)Br, Z=CH_(3)CH_(2)CH_(2)CH_(2)OH`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_OBJ_FING_CHE_XI_C13_E01_053_S01.png" width="80%"/></body></html> | |
| 50387. |
A compound X (C_5H_8) reacts with ammoniacal AgNO_3 to give a white precipitate, and on oxidation with hot alkaline KMnO_4 gives the acid, (CH_3)_2CHCOOH. Therefore , X is |
| Answer» <html><body><p>`CH_2=CHCH=CHCH_3`<br/>`CH_3(CH_2)_2C-=CH`<br/>`(CH_3)_2CH-C-=CH`<br/>`(CH_3)_2C=C=CH`</p>Solution :Terminal <a href="https://interviewquestions.tuteehub.com/tag/alkyne-853393" style="font-weight:bold;" target="_blank" title="Click to know more about ALKYNE">ALKYNE</a> containing `(CH_3)_2CH` <a href="https://interviewquestions.tuteehub.com/tag/group-1013370" style="font-weight:bold;" target="_blank" title="Click to know more about GROUP">GROUP</a> on oxidation <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> `(CH_3)_2CHCOOH`.</body></html> | |
| 50388. |
A compound X (C_(5)H_(10)O) react with 2,4-DNP but does not give silver mirror test and idoform reaction. The possible structure for X is |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`CH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)-CH_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)-overset(O)overset(||)(C)-CH_(2)-CH_(3)`</body></html> | |
| 50389. |
A compound with molecular formula C_(8)H_(14), contains 12 secondary and two tertiary H atoms. The compound is : |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ALN_CHM_C02_(II)_E01_081_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ALN_CHM_C02_(II)_E01_081_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ALN_CHM_C02_(II)_E01_081_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ALN_CHM_C02_(II)_E01_081_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>::D</body></html> | |
| 50390. |
A compound with molecular formula, C_7 H_(16)shows optical isomerism, the compound will be |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>, 3-dimethylpentane<br/>2,2-dimethylpentane<br/>2-methylhexane<br/>2,3-dimethylhexane</p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AO_CHE_XI_V01_D_C02_E03_036_S01.png" width="80%"/> <br/> 2,3 <a href="https://interviewquestions.tuteehub.com/tag/dimethyl-439813" style="font-weight:bold;" target="_blank" title="Click to know more about DIMETHYL">DIMETHYL</a> pentane is optically active due to the <a href="https://interviewquestions.tuteehub.com/tag/presence-25557" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENCE">PRESENCE</a> of <a href="https://interviewquestions.tuteehub.com/tag/chiral-2514284" style="font-weight:bold;" target="_blank" title="Click to know more about CHIRAL">CHIRAL</a> centre</body></html> | |
| 50391. |
A compound with molecular formula C_(4)H_(10)O_(4) on acylation with acetic anhydride gives a compound with molecular formula C_(12)H_(18)O_(8). How many hydroxyl groups are present in the compound? |
| Answer» <html><body><p>1<br/>2<br/>3<br/>4</p>Solution :Mol. Mass of `C_(4)H_(10)O_(4)` <br/> `= 12 xx 4 + 10 xx 1 + 4 xx 16 = 122` <br/> Mol. Mass of acylated product `(C_(12)H_(18)O_(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>))` <br/> `= 12 xx 12 + 18 xx 1 + 4 xx 16 = <a href="https://interviewquestions.tuteehub.com/tag/290-1834725" style="font-weight:bold;" target="_blank" title="Click to know more about 290">290</a>` <br/> Increase in mol. Mass `= 290 - 122 = 168` <br/> The reaction involved is `-OH + CH_(3)COCl rarr - O.CO. CH_(3) + <a href="https://interviewquestions.tuteehub.com/tag/hcl-479502" style="font-weight:bold;" target="_blank" title="Click to know more about HCL">HCL</a>` <br/> Increase in mol mass due to one `-OH` group = (Mol. mass of `COCH_(3)`) - At. mass of H `= 2 xx 12 + 16 + 3 - 1 = 42` <br/> `:.` No. of `-OH` groups `= (168)/(42) = 4`</body></html> | |
| 50392. |
A compound with molecular formula C_(4)H_(10)O_(3) is converted by the action of acetyl chloride to a compound with molecular weight 190. The original compound has : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> OH group<br/>Two OH group<br/>Three OH group<br/>No OH group</p>Solution :M. Mass of compound `= <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> xx 12 + 1 xx 10 + 3 xx <a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a> = 106` and the <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> mass of its acetate derivative is 190. Hence No. of OH groups `= (190-160)/(<a href="https://interviewquestions.tuteehub.com/tag/42-316129" style="font-weight:bold;" target="_blank" title="Click to know more about 42">42</a>)=2`.</body></html> | |
| 50393. |
A compound with empirical formula C_2H_5O has a vapour density of 45. The molecular formula of the compound will be |
| Answer» <html><body><p>`C_(2)H_(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)O`<br/>`C_(2)H_(2)O_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`<br/>`C_(5)H_(<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>)O_(4)`<br/>`C_(4)H_(10)O_(2)` </p>Solution : empiricalformulamass=45,<a href="https://interviewquestions.tuteehub.com/tag/molecularmass-2840135" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULARMASS">MOLECULARMASS</a> `=2 xx 45=90, therefore n=2`</body></html> | |
| 50394. |
The compound which is not isomeric with diethyl ether is |
| Answer» <html><body><p>n-Propyl <a href="https://interviewquestions.tuteehub.com/tag/methyl-1095247" style="font-weight:bold;" target="_blank" title="Click to know more about METHYL">METHYL</a> either<br/>1-Butanol<br/>2-Methyl-2-propanol<br/>Butanone</p>Answer :D</body></html> | |
| 50395. |
A compound which does not give a positive test in Lassaigne.s test for nitrogen is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/urea-1440871" style="font-weight:bold;" target="_blank" title="Click to know more about UREA">UREA</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/hydrazine-493075" style="font-weight:bold;" target="_blank" title="Click to know more about HYDRAZINE">HYDRAZINE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/azobenzene-1989655" style="font-weight:bold;" target="_blank" title="Click to know more about AZOBENZENE">AZOBENZENE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/phenyl-1153039" style="font-weight:bold;" target="_blank" title="Click to know more about PHENYL">PHENYL</a> hydrazine </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Hydrazine.</body></html> | |
| 50396. |
A compound which contains one atom of X and two atoms of Y for each three atoms of Z is made by mixing 5.00 g of X, 1.15 xx 10^(23) atoms of Y and 0.03 mole of Z atoms. Given that only 4.40 g of the compound is formed. Calculate the atomic weight of Y if the atomic weights of X and Z are 60 and 80 amu respectively. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Moles of <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> =`(5)/(60)= 0.08` mole <br/> Moles of Y = `(1.15xx10^(23))/(6.022xx10^(23))=0.19` mole <br/> Moles of Z = 0.03 mole . <br/> Since the formula of the compound is `XY_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)Z_(3)` <br/>moles of X : moles of Y : moles of Z =1 : 2:3 = 0.01 : 0.02: 0.03 . Comparing these values with the moles of X, Y and Z calculated above, we find that moles of X and Y are in excess and therefore, moles of X and Y associated with 0.03 mole of Z are 0.01 and 0.02 mole respectively. Now, <br/> <a href="https://interviewquestions.tuteehub.com/tag/wt-1462289" style="font-weight:bold;" target="_blank" title="Click to know more about WT">WT</a> of Z + wt . of Y + wt. of Z = wt. of `XY_(2)Z_(3)` <br/> or `0.01xx60 +0.02 xx ` at. wt. of Y + `0.03xx80 = 4.4 ` <br/> `:. ` at .wt. of Y = 70 <a href="https://interviewquestions.tuteehub.com/tag/amu-25369" style="font-weight:bold;" target="_blank" title="Click to know more about AMU">AMU</a> .</body></html> | |
| 50397. |
A commercial sample of common salt has 45.5% chlorine. What is the weight percentage of pure sodium chloride in the sample? |
| Answer» <html><body><p></p>Solution :Formula weight of <a href="https://interviewquestions.tuteehub.com/tag/sodium-1215510" style="font-weight:bold;" target="_blank" title="Click to know more about SODIUM">SODIUM</a> chloride =23+35.5=58.5 <br/> Weight percentage of <a href="https://interviewquestions.tuteehub.com/tag/chlorine-915874" style="font-weight:bold;" target="_blank" title="Click to know more about CHLORINE">CHLORINE</a> in pure sodium chloride <br/> `=(35.5)/(58.5)xx <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>=60.6` <br/> 60.6 <a href="https://interviewquestions.tuteehub.com/tag/parts-1148278" style="font-weight:bold;" target="_blank" title="Click to know more about PARTS">PARTS</a> of Cl (100% pure) has 45.5 parts of Cl <br/> Percentage <a href="https://interviewquestions.tuteehub.com/tag/purity-609119" style="font-weight:bold;" target="_blank" title="Click to know more about PURITY">PURITY</a> of sodium chloride `=(45.5)/(60.6) xx 100=75`</body></html> | |
| 50398. |
A compound (P) on reaction with "Q" in basic medium (KOH) gives a bad smelling compound (CH_(3)CH_(2)NC). Compound Q can be prepare by reaction with calcium hypochlorite [Ca(O Cl)_(2)] P and Qcan : |
| Answer» <html><body><p>`CH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)-CH_(2)-NH_(2) & CHCl_(3)`<br/>`CH_(3)-CH_(2)-NO_(2) & CH_(3)Cl`<br/>`CH_(3)-CH_(2)-NH-CH_(3) & COCl_(2)`<br/>`(CH_(3)-CH_(2))_(3)N & Cl_(2)`</p>Solution :`CH_(3)-CH_(2)-NH_(2)+CHCl_(3)+<a href="https://interviewquestions.tuteehub.com/tag/koh-528424" style="font-weight:bold;" target="_blank" title="Click to know more about KOH">KOH</a> to CH_(3)CH_(2)NC` <br/> `CH_(3)-CO-CH_(3)+<a href="https://interviewquestions.tuteehub.com/tag/ca-375" style="font-weight:bold;" target="_blank" title="Click to know more about CA">CA</a>(<a href="https://interviewquestions.tuteehub.com/tag/ocl-583082" style="font-weight:bold;" target="_blank" title="Click to know more about OCL">OCL</a>)_(2) to CHCl_(3) +(CH_(3)CO O)_(2)Ca`</body></html> | |
| 50399. |
A compound P(C_(5)H_(6)) gives positive Bayer test and on hydrogenation form a hydrocarbon B(C_(5)H_(10)) which gives only one monochloro product. The compound "P" is |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E03_075_O01.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E03_075_O02.png" width="30%"/> <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E03_075_O03.png" width="30%"/> <br/>`CH-=C-CH_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)-CH=CH_(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/RES_CHM_SIPOC_E03_075_S01.png" width="80%"/></body></html> | |
| 50400. |
A compound P(C_(5)H_(10)O) reacts with dilute sulfuric acid to give Q and R as the final products. This reactions is about 10^(15) times faster than of ethylene. Both Q and R give positive iodoform test. Identify the structure of P, Q and R (b) Rationalize the extraordinary reactivity of P. |
| Answer» <html><body><p><br/></p>Answer :`(##RES_CHM_ROHR_E03_008_A01##)` <br/> (b) The <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> <a href="https://interviewquestions.tuteehub.com/tag/stability-651358" style="font-weight:bold;" target="_blank" title="Click to know more about STABILITY">STABILITY</a> of the <a href="https://interviewquestions.tuteehub.com/tag/oxonium-7624931" style="font-weight:bold;" target="_blank" title="Click to know more about OXONIUM">OXONIUM</a> intermediate is <a href="https://interviewquestions.tuteehub.com/tag/responsible-613932" style="font-weight:bold;" target="_blank" title="Click to know more about RESPONSIBLE">RESPONSIBLE</a> for the extraordinary reactivity. This is demonstrated for the teo <a href="https://interviewquestions.tuteehub.com/tag/sets-14209" style="font-weight:bold;" target="_blank" title="Click to know more about SETS">SETS</a> of P, Q, R (case I and ii above) as follows. <br/> `(##RES_CHM_ROHR_E03_008_A02##)`</body></html> | |