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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 50551. |
A chemical reaction cannot occur at all if its |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a> is (+) ve and Delta S is (-)ve `<br/>`Delta H is (-) ve and Delta S is (+) ve `<br/>`Delta H and Delta S are (+ ) ve` but ` Delta H <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> T Delta S` <br/>`Delta H and Delta S"are" (-) ve butDelta H <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> T Delta S` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 50552. |
A chemical equilibrium is : |
| Answer» <html><body><p>a static <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a> where <a href="https://interviewquestions.tuteehub.com/tag/reactants-1178112" style="font-weight:bold;" target="_blank" title="Click to know more about REACTANTS">REACTANTS</a> & products stop combining to give products & reactants respectively<br/>adynamicequilibriumwherethereactantsandproductscontinuetogiveproductsandreactants respectively.<br/>Rates of forward and backward reactions are equal<br/>Gibb’s <a href="https://interviewquestions.tuteehub.com/tag/free-465311" style="font-weight:bold;" target="_blank" title="Click to know more about FREE">FREE</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> is zero</p>Solution :Properties of equilibrium</body></html> | |
| 50553. |
A chemical equation tells the actual number of moles of reactants and products. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a></body></html> | |
| 50554. |
Chemical equation is balanced according to the law of |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/multiple-1105557" style="font-weight:bold;" target="_blank" title="Click to know more about MULTIPLE">MULTIPLE</a> proportions<br/>constant proportions<br/>reciprocal proportions<br/>Conservation of mass</p>Answer :D</body></html> | |
| 50555. |
A chemical equation is always balanced with respect which one of the following (i)Number of atoms (ii) Number of molecules (iii) Number of moles (iv) Mass |
| Answer» <html><body><p>Only i is <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <br/>Only <a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a> correct <br/>Only <a href="https://interviewquestions.tuteehub.com/tag/iv-501699" style="font-weight:bold;" target="_blank" title="Click to know more about IV">IV</a> Correct <br/>Both i & iv correct </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 50556. |
A chemical commonly called "dioxin" has been very much in the news in the past few years. (It is the by product of herbicide manufacture and is thought to be quite toxic.) Its formula is C_(12)H_(4)Cl_(4)O_(2). If you have a sample of dirt (28.3 g) that contains 1.0xx10^(-4)% dioxin, how many moles of dioxin are in the dirt sample? |
| Answer» <html><body><p><br/></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>=((28.3xx1xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))/(<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>))/([12xx12+4+35.5xx4+16xx2])=<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>.8xx10^(-8)` mole</body></html> | |
| 50557. |
A chemical A is used for the preparation of washing soda to recover ammonia . When CO_(2) is bubbled through an aqueous solution of A , the solution turns milky . It is used in white washing due to its disinfectant nature . What is the chemical formula of A ? |
| Answer» <html><body><p>`Ca(HCO_(3))_(2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/cao-411869" style="font-weight:bold;" target="_blank" title="Click to know more about CAO">CAO</a>`<br/>`Ca(OH)_(2)`<br/>`CaCO_(3)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50558. |
A chemical A is used for the preparation of washing soda. When CO_2 is bubbled through an aqueous solution of A, the solution turns milky. It is used in white washing due to disinfectant nature. What is the chemical formula of A? |
| Answer» <html><body><p>`Ca(HCO_3)_2`<br/>CaO<br/>`Ca(<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>)_2`<br/>`CaCO_3`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50559. |
A chemical A is used for the preparation of washing soda to recover ammonia. When CO_(2)is bubbled through an aqueous solution of A, the solution turns milky. It is used in white washing due to disinfectant nature. What is the chemical formula of A? |
| Answer» <html><body><p>`Ca(HCO_(3))_(2)` <br/>CaO <br/>`Ca(OH)_(2)` <br/>`CaCO_(3)` </p>Solution :To recover `NH_(3)` is solvay ammonia soda process, `Ca(OH)_(2)`is <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a>. It is treated with `NH_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)Cl`. <br/> `2NH_(4)Cl+Ca(OH)_(2) to 2NH_(3)+CaCl_(2)+2H_(2)O` <br/> On passing `CO_(2)` through `Ca(OH)_(2)`, lime water, which is colourless, turns milky due to the <a href="https://interviewquestions.tuteehub.com/tag/formation-996531" style="font-weight:bold;" target="_blank" title="Click to know more about FORMATION">FORMATION</a> of `CaCO_(3)`. <br/> `Ca(OH)_(2)CO_(2) to CaCO_(3) darr+H_(2)O` <br/> `Ca(OH)_(2)` is used for white washing also.</body></html> | |
| 50560. |
A chamber contains 77g of CO_2. The chamber was divided into three compartments X, Y and Z as shown below. Suggest the relation between the internal energies of the gas in the three compartments X, Y and Z. X11 g CO_2 "" y 22g CO_2 "" Z 44g CO_2 |
| Answer» <html><body><p></p>Solution :Under <a href="https://interviewquestions.tuteehub.com/tag/similar-1207900" style="font-weight:bold;" target="_blank" title="Click to know more about SIMILAR">SIMILAR</a> conditions the <a href="https://interviewquestions.tuteehub.com/tag/internal-517481" style="font-weight:bold;" target="_blank" title="Click to know more about INTERNAL">INTERNAL</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> of a given substance depends on its quantity because it is an <a href="https://interviewquestions.tuteehub.com/tag/extensive-981051" style="font-weight:bold;" target="_blank" title="Click to know more about EXTENSIVE">EXTENSIVE</a> property. The internal energies of `CO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`in the compartments X, Y and Z are in the ratio 1:2:4.</body></html> | |
| 50561. |
(A): CH_(3)CH(OH)COOH is optically active (R) : CH_(3)CH(OH)COOH do not possess any element of symmetry. The correct answer is |
| Answer» <html><body><p>Both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and R <a href="https://interviewquestions.tuteehub.com/tag/explains-2627999" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLAINS">EXPLAINS</a> A <br/>Both A and R are true and R does not explains A <br/>A is true, R is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>A is false, R is true </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Both A and R are true and R explains A</body></html> | |
| 50562. |
A certain weight of sodium Iodine and sodium chloride mixture when treated with sulphuric acid was found to give the same weight (as that of mixture) of sodium sulphate. The percentage composition of NaCl is |
| Answer» <html><body><p>`18.86`<br/>`52.23`<br/>`35.57`<br/>`71.14`</p>Solution :`2NaCl+H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)SO_(4)rarrNa_(2)SO_(4)+2HCl` <br/> `2NaI+H_(2)SO_(4)rarrNa_(2)SO_(4)+2HI` <br/> Let the wt of the mixture = 1 g <br/> `{:(2xx58.5g NaCl" gives",<a href="https://interviewquestions.tuteehub.com/tag/142g-1788148" style="font-weight:bold;" target="_blank" title="Click to know more about 142G">142G</a> Na_(2)SO_(4)),(<a href="https://interviewquestions.tuteehub.com/tag/xg-747279" style="font-weight:bold;" target="_blank" title="Click to know more about XG">XG</a> NaCl" gives",142 xg Na_(2)SO_(4)),(,117):}` <br/> <a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a> g of NaI gives 142g `Na_(2)SO_(4)` <br/> (1-x)g of NaI gives `((1-x)xx142)/(300)gNa_(2)SO_(4)` <br/> `(142x)/(117)+((1-x)xx142)/(300)=1impliesx=0.7114g` <br/> % of `NaCl=(0.7114)/(1)xx100=71.14`</body></html> | |
| 50563. |
A certain weak acid has K_(a)=1.0xx10^(-4). Calculate the equilibrium constant for its reaction with a strong base. |
| Answer» <html><body><p></p>Solution :`{:(HA,+,BOH,hArr,<a href="https://interviewquestions.tuteehub.com/tag/ba-389206" style="font-weight:bold;" target="_blank" title="Click to know more about BA">BA</a>,+,H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O),("weak",,"strong",,,,,):}`:}` <br/> or HA+<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>^(+)+OH^(-) hArr B^(+)+A^(-)+H_(2)O or HA + OH^(-) hArr A^(-)+ H_(2)O` <br/> `K=([A^(-)])/([HA][OH^(-)])` ...(i) <br/> Further, for the weak acid, `HA hArr H^(+)+A^(-), K_(a) = ([H^(+)][A^(-)])/([HA])` ...(ii) <br/> Also `K_(w)=[H^(+)][OH^(-)]`...(iii) <br/> From eqns. (i), (ii) and (iii), `K=(K_(a))/(K_(w))=(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-4))/(10^(-<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>))=10^(10)`</body></html> | |
| 50564. |
A certain weak acid has K_(a), = 10^(-5). If the equilibrium constant for is its reaction with a strong base is repesented as yxx 10^(y) then find the value of y. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :` HA+ <a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>^(-)hArr A^(-)+H_2O ,K` <br/> ` K= (1)/(K_b)= (K_a) /(K_w)=(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> ^(-5))/( 10^(-<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>))=10 ^(9) `</body></html> | |
| 50565. |
A certain volume of Methane diffuses in 10 Sec through a porous partition. The time taken by an equal volume of oxygen to diffuse under the same condition is |
| Answer» <html><body><p>14.14 Sec. <br/>7.07 Sec. <br/><a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> sec. <br/>5 Sec <br/></p>Solution :`((<a href="https://interviewquestions.tuteehub.com/tag/deltav-2053504" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAV">DELTAV</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>))/((DeltaV)/(t_2)) = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(32/16) = sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`. <br/> `(t_2)/(10) = 1.414 implies t_2 = 14.14 "sec"`.</body></html> | |
| 50566. |
A certain third period element has the following successive values of ionization energies in K . J . mol^(-1){:(IE_(1),IE_(2),IE_(3),IE_(4),IE_(5)),(786,580,3230,4360,16100):}the element is |
| Answer» <html><body><p>Carbon<br/>Nitrogen <br/>Aluminium<br/>Silicon </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 50567. |
A certain transition in H spectrum from an excited state to ground state in one or more steps gives rise to total 10 lines. How many of these belong to uv spectrum? |
| Answer» <html><body><p>3<br/>4<br/>5<br/>6</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 50568. |
A certain substances contains only carbon and hydrogen and has a molecular weight of 70. Photochemical chlorination gave only one monochloride. Write the structure and IUPAC name of the hydrocarbon and its monochloride. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(##ALN_CHM_C02_(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>)_E01_054_A01##)`</body></html> | |
| 50569. |
A certain substance contains only carbon and hydrogen and its molecular mass is 70. Photochlorination gave only one monochloride. Write the structure and the IUAC name of the substance and its monochloride. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The available <a href="https://interviewquestions.tuteehub.com/tag/information-1043838" style="font-weight:bold;" target="_blank" title="Click to know more about INFORMATION">INFORMATION</a> suggests that the hydrocarbon with molecular <a href="https://interviewquestions.tuteehub.com/tag/mas-1088358" style="font-weight:bold;" target="_blank" title="Click to know more about MAS">MAS</a> <a href="https://interviewquestions.tuteehub.com/tag/70-333629" style="font-weight:bold;" target="_blank" title="Click to know more about 70">70</a> is cyclic in <a href="https://interviewquestions.tuteehub.com/tag/nature-1112013" style="font-weight:bold;" target="_blank" title="Click to know more about NATURE">NATURE</a>. It is cyclopentane. The chemical reaction is as follows : <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SKM_COMP_CHM_V02_XI_C12_S01_133_S01.png" width="80%"/></body></html> | |
| 50570. |
A certain sample of cuprous sulphide is found to have the composition Cu_(1.92)S_(1.00) because of incorporation of Cu^(2+) and Cu^(+) ions in the crystal then ratio of Cu^(2+) and Cu^(+) ions is : |
| Answer» <html><body><p>`0.08: 1.00`<br/>`1:23`<br/>`1:24`<br/>`1:1`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 50571. |
A certain sample of coal contain 1%of sulphur by weight. What is the weight of sulphur dioxide produced when 2'10^(6)kg of this coal isburnt? |
| Answer» <html><body><p>`2xx10^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)<a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>`<br/>`4xx10^(4)kg`<br/>`4xx10^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)kg`<br/>`2xx10^(5)kg`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of sulphur present in coal <br/> `(2xx10^(6)xx1)/(100)=2xx10^(4)kg""S+O_(2)rarr SO_(2)` <br/> `32xx10^(-2)kg rarr 64xx10^(-3)kg. 2xx10^(4)kg rarr?`<br/> weight of sulphur dioxide <br/> `=(2xx10^(4)xx64xx10^(-3))/(32xx10^(-3))=4xx10^(4)kg`</body></html> | |
| 50572. |
A certain salt X, givesthe followingresults.(i) Its aqueous solution isalkaline tolitmus. (ii) It swell up to a glassy materialY onstrongheating. (iii) When conc. H_(2)SO_(4)is added to a hot solution of X,white crystal of anacid Z separate out Writeequations for all the above reaction and identify X,Y and Z. |
| Answer» <html><body><p></p>Solution :(i) Since the aqueoussolution of salt (X) is alkaline to litmus, it must be the saltof a strong base and a weak acid. <br/> (ii) Since the salt (X) swellsup to a glassy material (Y) on strong heating,therefore (X) must be borax and (Y)must be a <a href="https://interviewquestions.tuteehub.com/tag/mixtureof-2837249" style="font-weight:bold;" target="_blank" title="Click to know more about MIXTUREOF">MIXTUREOF</a> sodium metaborate and boric anhydride. <br/> (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>)When <a href="https://interviewquestions.tuteehub.com/tag/conc-927968" style="font-weight:bold;" target="_blank" title="Click to know more about CONC">CONC</a>. `H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)SO_(4)`is added to a hot solution of X, i.e, borax,white crystalsof an acid (Z)separateout, therefore(Z)must beorthobasicacid. The equations for thereactionsinvolvedin the question are : <br/> (i) `underset("Borax (X)")(Na_(2)B_(4)O_(7). 10 H_(2)O) overset("Water")rarr underset(("Strong alkali"))(2NaOH)+ underset(("Weask acid"))(H_(2)B_(4)O_(7) + 8H_(2)O` <br/> (ii) `underset((X))(Na_(2)B_(4)O_(7).10H_(2)O)overset("Heat")rarrNa_(2)B_(4)O_(7)+10H_(2)O, Na_(2)B_(4)O_(7) overset("Heat")rarrubrace(2NaBO_(2) + B_(2)O_(3))_("Glassy material")` <br/> (iii) `Na_(2)B_(4)O_(7).10H_(2)O+H_(2)SO_(4)rarrunderset(" Boric acid (Z) ")(4H_(3)BO_(3))+Na_(2)SO_(4)+5H_(2)O`</body></html> | |
| 50573. |
A certain salt X gives the following results (i) Its aqueous solution shows alkaline to litmus paper (ii) It swells up to a hot glassy material Y on strong heating(iii) When conc. H_(2)SO_(4) is added to a solution of X white crystal of an acid Z separates out. Write equation for all the above reactions and identify X,Y and Z. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) `Na_(2)B_(4)O_(7)+ 7H_(2)O rarr 2NaOH+4H_(2)BO_(3)+2H_(2)`<br/> (ii) `underset(("Borax"(x))) (Na_(2) B_(4)O_(7)) overset("heat") (rarr) 2NaBO_(2)+B_(2)O_(3)` <br/> (iii) `underset((x))(Na_(2)B_(4)O_(7))+underset(("<a href="https://interviewquestions.tuteehub.com/tag/cone-928925" style="font-weight:bold;" target="_blank" title="Click to know more about CONE">CONE</a>"))(H_(2)SO_(4))+5H_(2)O overset("heat") (rarr) Na_(2)SO_(4)+underset((z))(4H_(3)BO_(3))`</body></html> | |
| 50574. |
A certain salt (X) gives the following tests : (a) Its aqueous solution is alkaline to litmus. (b) On strong heating, it swells up to give a glassy material (Y). (c) When conc. H_(2) SO_(4) is added to a hot concentrated solution of (X), white crystal ofa weak acid (Z) separates out. Identify (X), (Y) and (Z) and write down the chemical equations for reaction at steps a, b and c. |
| Answer» <html><body><p></p>Solution :(i) <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a>, the alkaline solution of the given salt [X] is alkaline to litmus, it <a href="https://interviewquestions.tuteehub.com/tag/must-2185568" style="font-weight:bold;" target="_blank" title="Click to know more about MUST">MUST</a> be a salt of strong base and weak acid. <br/> (ii) The salt [X] on heating <a href="https://interviewquestions.tuteehub.com/tag/swells-1236482" style="font-weight:bold;" target="_blank" title="Click to know more about SWELLS">SWELLS</a> up to a <a href="https://interviewquestions.tuteehub.com/tag/glassy-2674980" style="font-weight:bold;" target="_blank" title="Click to know more about GLASSY">GLASSY</a> material (Y). Therefore, [X] should be borax and [Y] a mixture of sodium metaborate and boric anhydride. <br/> (iii) When conc. H2SO4 is added to a hot solution of borax [A], white crystals of orthoboric acid [Z] <a href="https://interviewquestions.tuteehub.com/tag/separate-1201161" style="font-weight:bold;" target="_blank" title="Click to know more about SEPARATE">SEPARATE</a> out. Hence, [X] = `Na_2 B_4 O_7 . 10 H_2 O , [Y] = NaBO_2 + B_2 O_3 and [Z] = H_3 BO_3`. <br/>The reaction can be expressed as follows : <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/NTN_HCS_ISC_CHE_XI_P2_C11_E09_050_S01.png" width="80%"/></body></html> | |
| 50575. |
A certain salt X, gives the following results. (i) Its aqueous solution is alkaline to litmus. (ii) It swells up to a glassy material Y on strong heating (iii) When conc. H_2SO_4 is added to a hot solution of X, white crystal of an acid Z separates out. Write equations for all the above reactions and identify X, Y and Z. |
| Answer» <html><body><p></p>Solution : (i) The given salt is alkaline to litmus. Therefore, X is a salt of a <a href="https://interviewquestions.tuteehub.com/tag/strong-653928" style="font-weight:bold;" target="_blank" title="Click to know more about STRONG">STRONG</a> base and a weak acid. Also, when X is strongly heated, it swells to <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> substance Y. Therefore, X <a href="https://interviewquestions.tuteehub.com/tag/must-2185568" style="font-weight:bold;" target="_blank" title="Click to know more about MUST">MUST</a> be borax. <br/> `underset"(X)"(Na_2B_4O_7). 10H_2O overset(H_2O) tounderset"(Strong base)"(2NaOH) + underset"(Weak acid)"(H_2B_4O_7)` <br/> (ii) When borax is heated, it loses <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> and swells to form sodium metaborate. When heating is continued, it solidifies to form a glassy material Y. Hence, Y must be a mixture of sodium metaborate and boric anhydride. <br/>`Na_2B_4O_7 . 10H_2O overset(Delta)to Na_2B_4O_7 + 10 H_2O` <br/> `Na_2B_4O_7 <a href="https://interviewquestions.tuteehub.com/tag/oversetdeltato-2905750" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSETDELTATO">OVERSETDELTATO</a> ubrace(2NaBO_2+B_2O_3)_((Y))` <br/> (iii)When concentrated acid is added to borax, white crystals of orthoboric acid (Z) are formed.<br/> `Na_2B_4O_7. 10H_2O + H_2SO_4 to underset"(Z)"(4H_3BO_3) + 5H_2O + Na_2SO_4`</body></html> | |
| 50576. |
A certain salt X gives the following reactions (ii) It swells up to a glassy matter Y on heating |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`Na_2B_4O_7.10h_2Ounderset(-H_2O)<a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(<a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a>)rarrNa_2B_4O_overset(heat)rarr2NaBO_2+B_2O_3`</body></html> | |
| 50577. |
A certain salt X gives the reaction,When Con.H_2SO_4 is added to a hot solution of X, white crystals of an acid Z separates out. Identify X,and Z. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`Na2B_4O_7.10H_2O+H_2SO_4rarr4H_3BO_3+Na_2SO_4+5H_2O`</body></html> | |
| 50578. |
A certain salt X gives the following reactions (i) Its aqueous solution is alkaline to litmus |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> = <a href="https://interviewquestions.tuteehub.com/tag/borax-400720" style="font-weight:bold;" target="_blank" title="Click to know more about BORAX">BORAX</a>, Y = `NaBO_2+B_2O_3, <a href="https://interviewquestions.tuteehub.com/tag/z-750254" style="font-weight:bold;" target="_blank" title="Click to know more about Z">Z</a> = `H_3BO_3` <br/> `Na2B_4O_7+H_2Ooverset(<a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a>)rarr2NaOH+4H_3BO_3`</body></html> | |
| 50579. |
Acertain rection has equilibrium constant 10 and 100 at 300K and 400K respectively. The ratio of Delta G^(@) at 300K and 400K respectively |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(10)`<br/>`(3)/(8)`<br/>`(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(3)/(4)`</p>Solution :`(Delta G_(1)^(@))/(Delta G_(2)^(@))=(-2.303 RT_(1) log K_(P_(1)))/(-2.303 RT_(2) log K_(P_(2)))=(T_(1))/(T_(2)) xx (log K_(P_(1)))/(log K_(P_(2)))=(300)/(400) xx (log^(10))/(log^(<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>))=(3)/(8)`</body></html> | |
| 50580. |
A certain quantity of a gas occupies 300 mL when collected over water at 25^@C and 745 mm pressure. It occupied 182.6 mL in dry state at S.T.P. Find the vapour pressure of water at 25^@C. |
| Answer» <html><body><p><br/></p>Solution :Let us calculate the <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> <a href="https://interviewquestions.tuteehub.com/tag/exerted-7272976" style="font-weight:bold;" target="_blank" title="Click to know more about EXERTED">EXERTED</a> by 182.6 mL (at S.T.P.) of the <a href="https://interviewquestions.tuteehub.com/tag/dry-960094" style="font-weight:bold;" target="_blank" title="Click to know more about DRY">DRY</a> <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> when its volume is 300 mL and temperature is `25^@C, i.e.`, <br/> `P_1 = 760 " mm Hg. " V_1 = 182.6 mL`, <br/> `T_1 = 273 K` (at S.T.P.) <br/> `P_2 = ?, "" V_2 = 300 ml, "" T_2 = 25 + 273 = 298 K` <br/> According to the gas equation, `(P_1V_1)/T_1 = (P_2V_2)/T_2`<br/>Substituting the values, we have <br/> `(760 xx 182.6)/273 =(P_2 xx 300)/298 or P_2 = 504.9` mm Hg <br/>Under <a href="https://interviewquestions.tuteehub.com/tag/similar-1207900" style="font-weight:bold;" target="_blank" title="Click to know more about SIMILAR">SIMILAR</a> conditions, the wet gas exerts a pressure of 745 mm. <br/> `:." Vapour pressure of water at " 25^@C` <br/> `= 745 - 504.9 = 240.1 mm`</body></html> | |
| 50581. |
A certain quantity of a gas occupies 100ml when collected over water at 15°C and 750mm pressure. If it occupies 91.9ml in dry state at STP, the vapour pressure of water at 15°C is |
| Answer» <html><body><p>12.8mm<br/>14.8mm <br/>13.2mm<br/>13.7mm</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50582. |
A certain quantity of a gas measured 500 mL at a temperature of 15^@C and 750 mm Hg What pressure is required to compress this quantity of gas into a 400 mL vessel at a temperature of 50^@C ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In the present case, <br/> `P_1 = 750 mm Hg`, <br/> `V_1 = <a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a> mL`, <br/> `T_1 = 273 + 15 = <a href="https://interviewquestions.tuteehub.com/tag/288-1834218" style="font-weight:bold;" target="_blank" title="Click to know more about 288">288</a> K " and"P_2` = ? <br/> `V_2 = 400 ml`, <br/>`T_2 = 273 + 50 = 323 K` <br/> Therefore, <a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to the gas equation, we have <br/> `(P_1 V_1)/(T_1) = (P_2 V_2)/(t_2) " or "(750 xx 500)/288=(P_2 xx 400)/323" or "P_2 = 1051 mm` <br/>Hence, the given gas should be compressed to 1051 mm pressure.</body></html> | |
| 50583. |
A certain public water supply contained 0.10 parts per billion of chloroform CHCl_(3) How many molecules of CHCl_(3)would be contained in a 0.05 ml drop of this water ? |
| Answer» <html><body><p></p>Solution :Volume = 0.05 mL <br/> Amount of `CHCl_(3)` in th drop `=(0.05 xx 0.1)/<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) = 5.0 xx 10^(-12)`g <br/> Molecule <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of `CHCl_(3) = 12+1 + 3 xx 35.5` <br/> `=119.5 g mol^(-1)` <br/> Moles of `CHCl_(3)` <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> `=(5.0 xx 10^(-12))/119.5` <br/> <a href="https://interviewquestions.tuteehub.com/tag/molecules-563030" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULES">MOLECULES</a> of `CHCl_(3)` present in the drop <br/> `=(5.0 xx 10^(-12))/119.5 xx 6.022 xx 10^(23) = 2.5 xx 10^(19)`.</body></html> | |
| 50584. |
A certain particle carries 2.5 xx 10^(-16) C of static electric charge. Calculate the number of electrons present in it. |
| Answer» <html><body><p></p>Solution :Charge <a href="https://interviewquestions.tuteehub.com/tag/carried-7257188" style="font-weight:bold;" target="_blank" title="Click to know more about CARRIED">CARRIED</a> by one electron `= 1.6022 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-19) <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>` <br/> `:.` Electrons present in particle <a href="https://interviewquestions.tuteehub.com/tag/carrying-909956" style="font-weight:bold;" target="_blank" title="Click to know more about CARRYING">CARRYING</a> `2.5 xx 10^(-16) C " charge" = (2.5 xx 10^(-16))/(1.6022 xx 10^(-19)) = 1560`</body></html> | |
| 50585. |
A certain positive ion A^(+2)has 22 mass number of most abundant isotope of A? |
| Answer» <html><body><p>42<br/>38<br/>40<br/>None of these</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50586. |
Acertainparticlecarreis2.5 xx 10^(16)C ofstaticelectriccharge.Caculatethe numberofelectronspresenctin it. |
| Answer» <html><body><p></p>Solution :Staticelectriccharge of <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> <br/> (q ) = 2.5 `<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(16) <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>` <br/>Chargeofoneelectron =1,6022`xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/19-280618" style="font-weight:bold;" target="_blank" title="Click to know more about 19">19</a>) C` <br/>`=(2.5 xx 10^(16) C)/(1.6022xx 10^(19))<br/> `=1560 ` electrons</body></html> | |
| 50587. |
A certain oxide of iron contains 2.5 grams of oxide for every 7.0grams of iron. If it is regarded as a mixture of FeO and Fe_(2)O_(3) in the weight ratio a:b, what is a:b ? (atomic weight of iron = 56) |
| Answer» <html><body><p>`9:10`<br/>`9:20`<br/>`14:5`<br/>`1:1`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 50588. |
A certain particle carries -2.5 xx 10^(-16)C of static charge. Calculate the number of electrons present in it. |
| Answer» <html><body><p></p>Solution :`"No.of <a href="https://interviewquestions.tuteehub.com/tag/electrons-969138" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONS">ELECTRONS</a> "= ("<a href="https://interviewquestions.tuteehub.com/tag/static-1226026" style="font-weight:bold;" target="_blank" title="Click to know more about STATIC">STATIC</a> charge <a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>")/("coulomb charge of each "e^(-))=(2.5xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a>)"coulomb ")/(1.602xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/19-280618" style="font-weight:bold;" target="_blank" title="Click to know more about 19">19</a>)"coulomb")` <br/> `=1.56xx10^(3)" electrons "= "1,560 electrons"`.</body></html> | |
| 50589. |
A certain non-volatile substance (non-electrolyte) contains 40%C, 6.7%H, 53.3 % O. An aqueous solution containing 5% by mass of the solute boils at 100.15^(@)C. Molecular formula of the compound is : |
| Answer» <html><body><p>`CH_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O`<br/>`C_(2)H_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)O_(2)`<br/>`C_(6)H_(12)O_(6)`<br/>`C_(12)H_(22)O_(<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>)`</p>Answer :C</body></html> | |
| 50590. |
A certain metal sulphide MS_(2) is used extensively as a high temperature lubricant. If MS_(2) is 40.00% by mass sulphur, atomic mass of M is |
| Answer» <html><body><p>60<br/>96<br/>100<br/>80</p>Solution :`%S=40=(2xx32)/(M+32)<a href="https://interviewquestions.tuteehub.com/tag/xx100-3292680" style="font-weight:bold;" target="_blank" title="Click to know more about XX100">XX100</a>` <br/> `%M=60=(M)/(M+32)xx100` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> M=(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)xx2xx32=96`</body></html> | |
| 50591. |
A certain line of the Lyman series of hydrogen and a certain line of the Balmer series of He^(+) ion have nearly the same wavelength to what transition do they belong? Small differences between their Rydberg constant may be neglected. Differences between their Rydberg constant may be neglected. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`{:("<a href="https://interviewquestions.tuteehub.com/tag/hydrongen-2118658" style="font-weight:bold;" target="_blank" title="Click to know more about HYDRONGEN">HYDRONGEN</a>","<a href="https://interviewquestions.tuteehub.com/tag/helium-484142" style="font-weight:bold;" target="_blank" title="Click to know more about HELIUM">HELIUM</a>"),(2to1,4to2),(3to1,6to2),(4to1,8to2):}`</body></html> | |
| 50592. |
A certain gas was found to occupy a volume of 1000 cm^(3)at 27^(@)C.Calculate the temperature at which the gas occupies a volume of 600 cm^(3) at a constant pressure. |
| Answer» <html><body><p></p>Solution :`v_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=<a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a> cm^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>), v_(2)=600 cm^(3), T_(1)=(27+273)=<a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a> <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>,T_(2)= ?` <br/> `(V_(1))/(T_(1))=(V_(2))/(T_(2)) or T_(2), =(T_(1)V_(2))/(V_(1))=(300xx600)/(1000)=180K` <br/> `:. T_(2)=180K`</body></html> | |
| 50593. |
A certain gas occupies 0.418 litres at 27^@C and 740 mm of Hg. If we increase the weight of the gas to 7.5 g in the same vessel and the temperature is changed to 280 K, what would be its pressure ? |
| Answer» <html><body><p><br/></p>Solution :According to the gas equation <br/> `PV = <a href="https://interviewquestions.tuteehub.com/tag/nrt-1109890" style="font-weight:bold;" target="_blank" title="Click to know more about NRT">NRT</a>` <br/> Now, `n= (7.5)/(181.5),R = 0.0821L " atm " K^(-1)<a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>^(-1)` <br/>`T = <a href="https://interviewquestions.tuteehub.com/tag/280-299547" style="font-weight:bold;" target="_blank" title="Click to know more about 280">280</a> K and V = 0.418L` <br/> `:. "" P =(7.5/181.5xx0.0821xx280)/0.418=2.27` atm<br/> <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, the pressure of the gas <a href="https://interviewquestions.tuteehub.com/tag/would-3285927" style="font-weight:bold;" target="_blank" title="Click to know more about WOULD">WOULD</a> be 2.27 atm.</body></html> | |
| 50594. |
A certain gas takes three times as long to effuse out as helium. Its molecular mass will be |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/27-298706" style="font-weight:bold;" target="_blank" title="Click to know more about 27">27</a> u`<br/>`36 u`<br/>`64 u`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a> u`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 50595. |
A certain gas occupies 0.418 litres at 27^@C and 740 mm Hg. What is the volume at S.T.P. ? |
| Answer» <html><body><p><br/></p>Solution :According to the gas equation <br/> `(Р_1 V_1)/T_1 =(P_2 V_2)/T_2` <br/>In the present case, <br/> `P_1 = <a href="https://interviewquestions.tuteehub.com/tag/740-334871" style="font-weight:bold;" target="_blank" title="Click to know more about 740">740</a> " mm Hg,"V_1 = 0.418 <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>` <br/> `T_1 = 27 + 273 = <a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a> <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>` <br/>`P_2 = <a href="https://interviewquestions.tuteehub.com/tag/760-335611" style="font-weight:bold;" target="_blank" title="Click to know more about 760">760</a> " mm Hg, " V_2 = ? "" T_2 = 273 K` (at S.T.P.) <br/> Substituting the values, we have <br/> `(740 xx 0.418)/300 =(760 xx V_2)/300`<br/> `:. "" V_2 = 0.37 L`</body></html> | |
| 50596. |
A certain gas is expanded from (1L, 10atm) to (4L, 5atm) against a constant external pressure of 1 atm. If the initial temperature of gas is 300K and heat capacity for the process is 50J ""^(@)C^(-1) (use 1L atm = 100J), then |
| Answer» <html><body><p>`|W| = 0.3kJ`<br/>`|<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>| = 15 <a href="https://interviewquestions.tuteehub.com/tag/kj-1063034" style="font-weight:bold;" target="_blank" title="Click to know more about KJ">KJ</a>`<br/>`Delta U = 14.7 kJ`<br/>`Delta H = 15.7 kJ`</p>Solution :Constant, P, `W = - P_("ext") Delta V` <br/> `= -1 xx (<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>-1) = - 3` latern, `|W| = 0.3 KJ` <br/> `(P_(1)V_(1))/(T_(1)) =(P_(2)V_(2))/(T_(2)), (1 xx 10)/(<a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a>)= (4 xx 5)/(T_(2)) , T_(2) = 600K` <br/> `|q| = C Delta T = (50 xx 300)/(1000) = 15KJ` <br/> `Delta U = q + W = + 15 - 0.3 = 14.7` <br/> `Delta H = Delta U + Delta (PV)` <br/> `=14.7 + (5 xx 4 - 10 xx 1) xx 0.1 KJ = 15.7 KJ`</body></html> | |
| 50597. |
A certain gas occupies 0.418 litres at 27^@C and 740 mm Hg. If the same gas weighs 3.00 g, what is its molecular weight? |
| Answer» <html><body><p><br/></p>Solution :Number of <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> in 3.00 g of gas = `(3.00)/M`, where M is the <br/>molecular <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a> of the gas. According to the gas equation <br/>`PV = nRT` <br/> <a href="https://interviewquestions.tuteehub.com/tag/substituting-1231652" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTITUTING">SUBSTITUTING</a> the values, we have `740/760 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 0.418 = 3.00/M xx 0.0821 xx 300` <br/>(P = 760/760 atm ) <br/>`:. ""M = 181.5`</body></html> | |
| 50598. |
A certain element is a metalloid that forms an acidic oxide with the formula R_(2)O_(5). Identify the elements |
| Answer» <html><body><p></p>Solution :Since the elements forms as axide with formula, `R_(2)O_(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)`, it must be an element of <a href="https://interviewquestions.tuteehub.com/tag/group-1013370" style="font-weight:bold;" target="_blank" title="Click to know more about GROUP">GROUP</a> 15. Now group 1 has <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> metalloids, As and Sb. Since the acidic character of pentoxides of group 15 elements decrease while the basic character increases down the group, therefore, `As_(2)O_(5)` is acidic while `Sb_(2)O_(5)` is amphoteric. <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, the metalloid of group 15 elements which forms an acidic pentoxide `(As_(2)O_(5))` is As.</body></html> | |
| 50599. |
A certain crystal has (i) density = 0.456 cm^(-3) , (ii) a fourfold axis of symmetry and (iii) 4 molecules per unit cell. Side lengths of the unit cell are a = b = 658 pm and c = 593 pm. Calculate the molar mass in g mol^(-1). |
| Answer» <html><body><p>`16.20`<br/>`17.62`<br/>`19.25`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 50600. |
A certain compound X impats golden yellow flame. Whenzinc powder is heated with concenrated solution of X, H_(2) gas is evolved. X combines with CO_(2) to give a salt Y. Y is a hydrated salt which on reaction with HCl or ecess of CO_(2) gives another salt Z which is an important part of baking powder. identify X, Y and Z. |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>-NaOH,Y-Na_(2)CO_(3),Z-NaHCO_(3)`<br/>`X-HCl, Y-NaOH,Z-NaHCO_(3)`<br/>`X-KOH,Y-K_(2)CO_(3),Z-KHCO_(3)`<br/>`X-<a href="https://interviewquestions.tuteehub.com/tag/nacl-572483" style="font-weight:bold;" target="_blank" title="Click to know more about NACL">NACL</a>,Y-Na_(2)CO_(3),Z-NaOH`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`Zn+<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>((X))(<a href="https://interviewquestions.tuteehub.com/tag/2naoh-1838094" style="font-weight:bold;" target="_blank" title="Click to know more about 2NAOH">2NAOH</a>) to Na_(2)ZnO_(2)+H_(2)` <br/> `underset((X))(2NaOH)+CO_(2)tounderset((Y))(Na_(2)CO_(3))+H_(2)O` <br/> `underset((Y))(Na_(2)CO_(3))+HCl to underset((Z))(NaHCO_(3))+NaCl` ltBrgt `underset((Y))(Na_(2)CO_(3))+CO_(2)+H_(2)O to underset((Z))(2NaHCO_(3))`</body></html> | |