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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 50651. |
A bubble of air is underwater at temperature 15^@ C and the pressure 1.5 bar. If the bubble rises to the surface where the temperature is 25^@ C and the pressure is 1.0 bar, what will happen to the volume of the bubble? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> will <a href="https://interviewquestions.tuteehub.com/tag/become-389953" style="font-weight:bold;" target="_blank" title="Click to know more about BECOME">BECOME</a> <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> by a <a href="https://interviewquestions.tuteehub.com/tag/factor-458892" style="font-weight:bold;" target="_blank" title="Click to know more about FACTOR">FACTOR</a> of 1.6 <br/>volume will become greater by a factor of 1.1 <br/>volume will become <a href="https://interviewquestions.tuteehub.com/tag/smaller-1213327" style="font-weight:bold;" target="_blank" title="Click to know more about SMALLER">SMALLER</a> by a factor of 0.70<br/>volume will become greater by a factor of 2.5</p>Answer :A</body></html> | |
| 50652. |
A bubble of a gas released at the botton of a lake increases to eight times its original volume when it reaches the surface. Assuming that atmospheric pressure is equivalent to the pressure exerted by a column of water 10 m height, the depth of the lake is |
| Answer» <html><body><p>80 m<br/>90 m<br/>40 m<br/>70 m</p>Solution :As <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of the bubble at the surface becomes <a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> times, pressure at the bottom of the lake is 8 times the pressure at the surface. As pressure on the surface =1 atm., pressure at the bottom =8 atm. Thus, pressure due to depth of the lake =7 atm=70 m of <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a>.</body></html> | |
| 50653. |
A brown ring is formed in the ring test for NO_(3)^(-) ion. It is due to the formation of |
| Answer» <html><body><p>`[Fe(H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O)_(5)(NO)]^(2+)`<br/>`FeSO_(4).NO_(2)`<br/>`[Fe(H_(2)O)_(4)(NO)_(2)]^(2+)`<br/>`FeSO_(4),HNIO_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 50654. |
A brominated alkane an analysis gave 12.8% carbon and 2.1%H. If its vapour density is 93.95, what is its molecular formula? |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/percent-1150333" style="font-weight:bold;" target="_blank" title="Click to know more about PERCENT">PERCENT</a> weight of bromium = 100-(%C+%H) = 100-14.9 = 85.<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> <br/> C : H: Br `=(12.8)/(12) : (<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.1)/(1) : (85.1)/(80) = 1 : 2 : 1 ` <br/> Empirical formula is `CH_(2)Br` <br/> Molecular weight `= 2xxV.D. = 2xx93.95 = 187.9` <br/> ` n = (187.9)/(<a href="https://interviewquestions.tuteehub.com/tag/94-342308" style="font-weight:bold;" target="_blank" title="Click to know more about 94">94</a>) = 2` <br/> Molecular formula `=2xxCH_(2)Br = C_(2)H_(4)Br_(2)`</body></html> | |
| 50655. |
A+BrarrC+D, DeltaH=-10.000Jmol^(-1),DeltaS=-33.3mol^(-1)K^(-1) (i) At what temperature the reaction will occur spontaneously from left to right? (ii) At what temperature, the reaction will reverse? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`DeltaG=DeltaH-TDeltaS` At equilibrium, `DeltaG=0` so that <br/> `DeltaH=TDeltaS` (or) <br/> `T=(DeltaH)/(DeltaS)=(-10000Jmol^(-1))/(-33.3Jmol^(-1))=300.3K` <br/> (i) For spontaneity from left to <a href="https://interviewquestions.tuteehub.com/tag/right-1188951" style="font-weight:bold;" target="_blank" title="Click to know more about RIGHT">RIGHT</a>, `DeltaG` should be -ve for the given reaction. This will be so if `Tlt300.3K` <br/> (ii) For reverse reaction <a href="https://interviewquestions.tuteehub.com/tag/ot-584155" style="font-weight:bold;" target="_blank" title="Click to know more about OT">OT</a> <a href="https://interviewquestions.tuteehub.com/tag/occur-583012" style="font-weight:bold;" target="_blank" title="Click to know more about OCCUR">OCCUR</a>. `DeltaG` should be `+ve` for <a href="https://interviewquestions.tuteehub.com/tag/forward-464460" style="font-weight:bold;" target="_blank" title="Click to know more about FORWARD">FORWARD</a> reaction. This will be so if `Tgt300.3K`.</body></html> | |
| 50656. |
A boy after swimming comes out from a poolcovered with a film of waterweighing 80 g .How much heat must be suppliedto evaporate this water ? (Delta_(v) H^(@)=40.79 kJmol^(-1)) |
| Answer» <html><body><p>`1.61 xx10^(2) <a href="https://interviewquestions.tuteehub.com/tag/kj-1063034" style="font-weight:bold;" target="_blank" title="Click to know more about KJ">KJ</a>`<br/>`1.71 xx 10^(2)kJ`<br/>` 1.81xx10^(2) kJ `<br/>` 1.91 xx 10^(2) kJ `</p>Solution :Given `: Delta_("vap") <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>^(@) `for`H_(2)O= 40.79 kJ mol^(-1)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> to be evaporated`= <a href="https://interviewquestions.tuteehub.com/tag/80-337972" style="font-weight:bold;" target="_blank" title="Click to know more about 80">80</a> g( 80)/( 18) <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a>` <br/> `=4.44` mole <br/> Heat required for evaporated of 1 moleof `H_(2)O =40.79kJ` <br/> `:. `Heat required for evaporated of 4.44 moleof`H_(2)O=40.79 xx 4.44 = 1.81 xx 10^(2) kJ`</body></html> | |
| 50657. |
A box contains some identical red coloured balls, labelled as A, each weighing 2g. Another box contains identical blue coloured balls, labelled as B, each weighing 5 g. Consider the combinations AB, AB_(2), A_(2)B and A_(2)B_(3) and show that law of multiple proportions is applicable. |
| Answer» <html><body><p> </p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_CHE_XI_P1_C01_E04_045_S01.png" width="80%"/> <br/> <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> which is combined with fixed mass of A will be 2.5 g, <a href="https://interviewquestions.tuteehub.com/tag/5g-326287" style="font-weight:bold;" target="_blank" title="Click to know more about 5G">5G</a>, 1.25gand 3.75g. They are in the ratio of `2:4 :1:3` which is a simple whole <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> ratio. Hence, the <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of multiple proportions is applicable.</body></html> | |
| 50658. |
A bottle of NH_(3) gas and a bottle of dry HCl gas are connected through a long tube. The tube is opened simultaneously at both the ends. White fume of NH_(4)Cl is formed …………….. |
| Answer» <html><body><p>throughout the length of the <a href="https://interviewquestions.tuteehub.com/tag/tube-1428592" style="font-weight:bold;" target="_blank" title="Click to know more about TUBE">TUBE</a> <br/>near HCl <a href="https://interviewquestions.tuteehub.com/tag/bottle-390839" style="font-weight:bold;" target="_blank" title="Click to know more about BOTTLE">BOTTLE</a> <br/>near `NH_(3)` bottle <br/>at the centre of tube </p>Solution :Atomic pressure in `NH_(3)` gas = 17 gm `mol^(-1)=M_(1)`<br/>Atomic pressure in HCl gas = 36.5 gm `mol^(-1)=M_(2)`<br/>According to Grapham.s gas diffusional Law,Whose atomic pressure is high its diffusion is slow.`(r=(1)/(sqrt(M)))`<br/>The atomic pressure of HCl (36.5 gm `"mole"^(-1)`) is more then the atomic pressure of `NH_(3)` (17.0 gm `"mole"^(-1)`) So, the diffusion of HCl is <a href="https://interviewquestions.tuteehub.com/tag/less-1071906" style="font-weight:bold;" target="_blank" title="Click to know more about LESS">LESS</a>.<br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` The diffusion of HCl is very less.<br/>`therefore` So, the <a href="https://interviewquestions.tuteehub.com/tag/fume-466759" style="font-weight:bold;" target="_blank" title="Click to know more about FUME">FUME</a> of `NH_(4)Cl` is formed `NH_(3)` bottle.</body></html> | |
| 50659. |
A bottle of H_(3)PO_(4) solution contains 70%(w//w) acid. If the density of the H_(3)PO_(4) solution required to prepare 1 L of 1N solution is : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a> mL<br/>45 mL<br/>30 mL<br/>23 mL</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50660. |
A bottle of commercial sulphuric acid (density = 1.787 gm/mL) is labelled 86 percent by weight. What is the molarity of the solution ? What volime of the acid is required to make it 1 litre of 0.2 M H_(2)SO_(4) ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Step I. Molarity of solution <br/> Mass of `H_(2)SO_(4)=86 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>` , Mass of the solution = 100 g <br/> Volume of 100 g of the solution `= ("Mass")/("Density") = (100)/(1.787) = 55.96 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a> = 0.05596 L` <br/> Molarity of solution (M) `= (("Mass of "H_(2)SO_(4))/("Molecular mass of "H_(2)SO_(4)))/("Volume of solution in mL"/(1000))=((86g))/(("<a href="https://interviewquestions.tuteehub.com/tag/98-342802" style="font-weight:bold;" target="_blank" title="Click to know more about 98">98</a> g mol"^(-1))xx("0.05596 L"))` <br/> `=15.68 "mol L"^(-1)=15.68 M`<br/> Step II. Volume of solution required <br/> `overset(("conc."))(M_(1)V_(1))-=overset(("dilute"))(N_(2)V_(2))` <br/> `15.68xxV_(1)=0.2xx1000,V_(1)=(0.2xx1000)/(15.68)=12.75mL`.</body></html> | |
| 50661. |
A bottle of H_2 O_2is labelled as 10 vol H_2O_2 112ml of this H_2O_2 solution is completely titrated with 0.04M acidified KMnO_4solution. The volume of KMnO_4consumed in litres is |
| Answer» <html><body><p><br/></p>Solution : <a href="https://interviewquestions.tuteehub.com/tag/normality-1124423" style="font-weight:bold;" target="_blank" title="Click to know more about NORMALITY">NORMALITY</a> of `H_2O_2 =10/(5.6)` <br/> `10/(5.6)xx112=0.04xx5xxV_2` <br/><a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of `KMnO_4`solution = 1 <a href="https://interviewquestions.tuteehub.com/tag/lit-537267" style="font-weight:bold;" target="_blank" title="Click to know more about LIT">LIT</a></body></html> | |
| 50662. |
A bottle of ammonia and a bottle of HCl connected through a long tube are opened simultaneously at both ends. The white ammonium chloride ring first formed will be |
| Answer» <html><body><p> At the center of the tube<br/><a href="https://interviewquestions.tuteehub.com/tag/near-1112277" style="font-weight:bold;" target="_blank" title="Click to know more about NEAR">NEAR</a> the hydrogen <a href="https://interviewquestions.tuteehub.com/tag/chloride-915854" style="font-weight:bold;" target="_blank" title="Click to know more about CHLORIDE">CHLORIDE</a> <a href="https://interviewquestions.tuteehub.com/tag/bottle-390839" style="font-weight:bold;" target="_blank" title="Click to know more about BOTTLE">BOTTLE</a><br/> Near the ammonia bottle<br/>Throughout the <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> of the tube</p>Solution :Rate of diffusion `alpha 1//sqrt()m` <br/>`m_(NH_3) = 17, m_(<a href="https://interviewquestions.tuteehub.com/tag/hcl-479502" style="font-weight:bold;" target="_blank" title="Click to know more about HCL">HCL</a>)= 36.5` <br/>`gamma_(NH_3) gt gamma_(HCl)` <br/>Hence white fumes first formed near hydrogen chloride.</body></html> | |
| 50663. |
A bottle of ammonia and a bottle of HCl connected through a long tube are opend simultaneously at both ends. The white ammonium chloride ring first formed will be |
| Answer» <html><body><p>At the <a href="https://interviewquestions.tuteehub.com/tag/center-11455" style="font-weight:bold;" target="_blank" title="Click to know more about CENTER">CENTER</a> of the tube <br/><a href="https://interviewquestions.tuteehub.com/tag/near-1112277" style="font-weight:bold;" target="_blank" title="Click to know more about NEAR">NEAR</a> the <a href="https://interviewquestions.tuteehub.com/tag/hydrogen-22331" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGEN">HYDROGEN</a> chloride bottle <br/>Near the ammonia bottle<br/>Throughout the length of the tube </p>Solution :`NH_(3)+HCl+O_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)toNO_(2)+H_(2)`</body></html> | |
| 50664. |
A bottle contains two immiscible liquids. They may be separated by |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/vacuum-1442069" style="font-weight:bold;" target="_blank" title="Click to know more about VACUUM">VACUUM</a> distillation<br/>Fractionating column<br/>Separating funnel<br/>Steam distillation</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50665. |
A bottle contaning ammonia and a bottle containing hydrogen chloride are connected throughalong tube are opened simultaneously at both ends. The white ammoniumchloride first formed will be : |
| Answer» <html><body><p>at the centre of the tube<br/>near the <a href="https://interviewquestions.tuteehub.com/tag/hydrogen-22331" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGEN">HYDROGEN</a> chloride tube<br/>near the ammonia tube<br/>throughout the length of the tube.</p>Solution :`NH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` diffuse at a faster <a href="https://interviewquestions.tuteehub.com/tag/rate-1177476" style="font-weight:bold;" target="_blank" title="Click to know more about RATE">RATE</a> than `<a href="https://interviewquestions.tuteehub.com/tag/hcl-479502" style="font-weight:bold;" target="_blank" title="Click to know more about HCL">HCL</a>` gas because the density of `NH_(3)` is less than that of `HCl` gas.</body></html> | |
| 50666. |
A bottle is heated with mouth open to have a final temperature as five times its original value at 25^(@)C. The fraction of air originally present in the bottle that is expelled, is: |
| Answer» <html><body><p>0.5<br/>0.25<br/>0.33<br/>0.4</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 50667. |
(A) : Both H_(2) and D_(2) have same internuclear distance (R) : Enthalpy of bond dissociation is same for H_(2) and D_(2) |
| Answer» <html><body><p>A is <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> but R is false <br/>A is false but R is true <br/>Both A and R are true, and R is correct <br/>Both A and R are true, and R is not the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of A </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 50668. |
(A): Borax bead test is not suitable for Al(III) (R) : Al_2 O_3 is insoluble in water |
| Answer» <html><body><p> A and R are true, R <a href="https://interviewquestions.tuteehub.com/tag/explains-2627999" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLAINS">EXPLAINS</a> A <br/>A and R are true, R does not explain A<br/>A is true, but R is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>A is false, but R is true</p>Answer :B</body></html> | |
| 50669. |
Abonding molecular orbital is produced by |
| Answer» <html><body><p>Destructive interference of <a href="https://interviewquestions.tuteehub.com/tag/wave-22399" style="font-weight:bold;" target="_blank" title="Click to know more about WAVE">WAVE</a> <a href="https://interviewquestions.tuteehub.com/tag/functions-13351" style="font-weight:bold;" target="_blank" title="Click to know more about FUNCTIONS">FUNCTIONS</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/constructive-2540882" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTRUCTIVE">CONSTRUCTIVE</a> interference of wave functions <br/>Pairing of electrons with <a href="https://interviewquestions.tuteehub.com/tag/opposite-1137237" style="font-weight:bold;" target="_blank" title="Click to know more about OPPOSITE">OPPOSITE</a> spins<br/>Combination of +ve and -ve wave functions</p>Answer :B</body></html> | |
| 50670. |
A bolttle of dry ammonia and a bottle of dry hydrogen chloride connected through a long tube are opened simultaneously at both ends, The white ammonium chloride ring first formed will be |
| Answer» <html><body><p>at the centre of the <a href="https://interviewquestions.tuteehub.com/tag/tube-1428592" style="font-weight:bold;" target="_blank" title="Click to know more about TUBE">TUBE</a> <br/>near the hydrogen chloride bottle <br/>near the ammonia bottle <br/><a href="https://interviewquestions.tuteehub.com/tag/throughout-7258007" style="font-weight:bold;" target="_blank" title="Click to know more about THROUGHOUT">THROUGHOUT</a> the length of the tube. </p>Solution :`r prop 1//sqrt(M)`. Molecular <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of HCl (36.5) is greater than that of `NH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`(17), hence HCl will diffuse slowly, i.e., the ring will be formed near the HCl bottle.</body></html> | |
| 50671. |
(A) : Bohr.s orbits are called stationary orbits (R) : Electrons remain stationary in these orbitss |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/>(A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>(A) is false but (R) is true </p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/electrons-969138" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONS">ELECTRONS</a> are always in motion</body></html> | |
| 50672. |
A bodyof mass x kg ismovingwithvelocityof 100 ms^(-1)itsde - brogliewavelengthis 6.62 xx 10^(-34)m^(-1)Hencex is … (h= 6.62 x 10^(-34) J s) |
| Answer» <html><body><p>`0.25 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>` <br/>`0.15 kg`<br/>`0.2 kg`<br/>`0.1kg`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 50673. |
A body of mass x kg is moving with avelocity of 100 ms^(-1) , its de-Broglie wavelength is 6.62xx10^(-35) m . Hence x is (h=6.62xx10^(-34) Js) |
| Answer» <html><body><p>0.25 kg <br/>0.15 kg <br/>0.2 kg <br/>0.1 kg </p>Solution :According to de-Broglie's <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> , `lambda =<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>/"mv" <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> 6.62xx10^(-35) =(6.62xx10^(-34)) /(x <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>) rArr x =0.1 kg `</body></html> | |
| 50674. |
A body centred unit cell has an atom at the each vertex and at --------- of the unit cell. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a></body></html> | |
| 50675. |
A blue coloured mineral 'lapis lazuli' which is used as a semi-precious stone is a mineral of the following class : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/sodium-1215510" style="font-weight:bold;" target="_blank" title="Click to know more about SODIUM">SODIUM</a> aluminiosilicate<br/>Zinc cobaltate<br/>Basic copper<br/>Prussian blue</p>Answer :A</body></html> | |
| 50676. |
A 500g tooth paste sample 0.3 g fluoride. What is the concentration of fluoride in ppm? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> ppm<br/>100 ppm<br/>150 ppm<br/>200 ppm</p>Answer :D</body></html> | |
| 50677. |
A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate is |
| Answer» <html><body><p>168<br/>192<br/>188<br/>182</p>Solution :Given, equivalent <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of bivalent <a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> `M^(2+)=32` <br/> `:.` Atomic mass of `MM = 32 xx 2 = <a href="https://interviewquestions.tuteehub.com/tag/64-330663" style="font-weight:bold;" target="_blank" title="Click to know more about 64">64</a>` <br/> The metal nitrate formed has the formula `M(NO_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))_(2)` <br/> `:.` Molecular mass of the metal nitrate `= 64+28+96=188`</body></html> | |
| 50678. |
A bivalent metal has 37.2 equivalent weight. The molecular weight of its chloride is |
| Answer» <html><body><p>`216.6`<br/>`148.8`<br/>`145.4`<br/>`172.8`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a> of `MnCl_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=37.2+35.5=72.7impliesM=72.7xx2`</body></html> | |
| 50679. |
Equivalent weights 36. A bivalent metal has 12 equivalent weight. The molecular weight of its oxide is |
| Answer» <html><body><p>16<br/>32<br/>40<br/>52</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50680. |
A binary solid, A^(+) B^(-) ( formula mass= 60) has aCsCl structure. The no. of unit cells present in 6 g ideal crystals of solid are |
| Answer» <html><body><p>`6.02xx10^(<a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a>)`<br/>`6.02xx10^(23)`<br/>`3.01xx10^(23)`<br/>`3.01xx10^(22)`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of formula <a href="https://interviewquestions.tuteehub.com/tag/units-1438468" style="font-weight:bold;" target="_blank" title="Click to know more about UNITS">UNITS</a> in <a href="https://interviewquestions.tuteehub.com/tag/cscl-410997" style="font-weight:bold;" target="_blank" title="Click to know more about CSCL">CSCL</a> structure =1 In 60 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> number of unit cells `=6.2xx10^(23)` In 6 g number of unit cells `=6.02xx10^(22)`</body></html> | |
| 50681. |
A binary salt AB (formula weight = 6.023 Y amu, where Y is an arbitray number) has rock salt structure with 1 : 1 ratio of A to B. The shortes A - B distance in the unit cell is Y^(1//3)nm. (a) Calculate the density of the salt in kg m^(-3) (ii) Given that the measured denstiy of the salt is 20 kg m^(-3), specify the type of point defect present in the crystal |
| Answer» <html><body><p><br/></p>Answer :(a) `<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> kg m^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`, (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) Cancelled (Full marks <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> in part a)</body></html> | |
| 50682. |
A binary compound formed between the elements with atomic numbers 19 and 17 is expected to be |
| Answer» <html><body><p> a <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> soluble compound forming a <a href="https://interviewquestions.tuteehub.com/tag/conducting-928804" style="font-weight:bold;" target="_blank" title="Click to know more about CONDUCTING">CONDUCTING</a> solution in water <br/>a soft, easily deformed solid <br/>a solid with a low <a href="https://interviewquestions.tuteehub.com/tag/melting-1093090" style="font-weight:bold;" target="_blank" title="Click to know more about MELTING">MELTING</a> point <br/>an electrically conducting solid </p>Solution :Element with At. No. 19 will <a href="https://interviewquestions.tuteehub.com/tag/lose-537625" style="font-weight:bold;" target="_blank" title="Click to know more about LOSE">LOSE</a> one electron and element with At.no.17 will gain that electron to <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> an ionic water soluble compound.</body></html> | |
| 50683. |
A+BhArrC+D,K_(c) for this reaction is 10. If 1,2,3,4 mole/litre of A,B,C and D respectively are present in a container at 25^(@)C, the direction of reaction will be |
| Answer» <html><body><p>From <a href="https://interviewquestions.tuteehub.com/tag/left-1070879" style="font-weight:bold;" target="_blank" title="Click to know more about LEFT">LEFT</a> to <a href="https://interviewquestions.tuteehub.com/tag/right-1188951" style="font-weight:bold;" target="_blank" title="Click to know more about RIGHT">RIGHT</a> <br/>From right to left <br/><a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> is at equilibrium<br/>Unpredictable </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 50684. |
A benzene ring deactivated by strong & moderate electron withdrawing groups such a molecule is not electron rich enough to under go friedel-craft's reaction Friedel craft reaction also does not occur with NH_(2) group as it react with AlCl_(3) and produce deactivating group. Q. Which of the following sequence of reaction is correct for the synthesis of product |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_226_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_226_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_226_O03.png" width="30%"/><br/>All are correct </p>Solution :In <a href="https://interviewquestions.tuteehub.com/tag/option-25810" style="font-weight:bold;" target="_blank" title="Click to know more about OPTION">OPTION</a> <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> <a href="https://interviewquestions.tuteehub.com/tag/sequence-1201556" style="font-weight:bold;" target="_blank" title="Click to know more about SEQUENCE">SEQUENCE</a> of <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> is correct.</body></html> | |
| 50685. |
A benzene ring deactivated by strong & moderate electron withdrawing groups such a molecule is not electron rich enough to under go friedel-craft's reaction Friedel craft reaction also does not occur with NH_(2) group as it react with AlCl_(3) and produce deactivating group. Q. Which of the following cannot be starting material for this compound Ph-underset(O)underset(||)(C)-CH_(2)-Ph |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_225_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_225_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_225_O03.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_225_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Acyl group is meta <a href="https://interviewquestions.tuteehub.com/tag/directing-954968" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTING">DIRECTING</a> group which on clenensons reduction <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> <a href="https://interviewquestions.tuteehub.com/tag/alkyl-371497" style="font-weight:bold;" target="_blank" title="Click to know more about ALKYL">ALKYL</a> group.</body></html> | |
| 50686. |
A benzene ring deactivated by strong & moderate electron withdrawing groups such a molecule is not electron rich enough to under go friedel-craft's reaction Friedel craft reaction also does not occur with NH_(2) group as it react with AlCl_(3) and produce deactivating group. Q. Which of the following compound undergoes Friedel-crafts alkylation reaction |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_224_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_224_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_224_O03.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_224_O04.png" width="30%"/></p>Solution :`NH-overset(O)overset(||)(C)-CHO` is moderately activating <a href="https://interviewquestions.tuteehub.com/tag/group-1013370" style="font-weight:bold;" target="_blank" title="Click to know more about GROUP">GROUP</a>. Highly activating and Highly de activating <a href="https://interviewquestions.tuteehub.com/tag/groups-1013609" style="font-weight:bold;" target="_blank" title="Click to know more about GROUPS">GROUPS</a> do not <a href="https://interviewquestions.tuteehub.com/tag/give-468520" style="font-weight:bold;" target="_blank" title="Click to know more about GIVE">GIVE</a> friedal <a href="https://interviewquestions.tuteehub.com/tag/crafts-938246" style="font-weight:bold;" target="_blank" title="Click to know more about CRAFTS">CRAFTS</a> reactions.</body></html> | |
| 50687. |
A benzene ring deactivated by strong and moderate electron withdrawing group that is, any meta directing group, is not electron rich enough to undergo Friedel-Crafts ranctions. Friedel-Crafts reaction also do not occur with HN_(2) group as it react with AICI_(3) and produce deactivating group. Answer the following question : Which of the following cannot be starting for this compound Ph-underset(O)underset(||)(C)-CH_(2)-Ph ? |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_ORG_CHM_P1_C08_E01_188_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_ORG_CHM_P1_C08_E01_188_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_ORG_CHM_P1_C08_E01_188_O03.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/GRB_ORG_CHM_P1_C08_E01_188_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50688. |
(A) : Benzene prefers to participate in substitution reactions than addition reactions (R) : Addition products of benzene do not retain resonance stability |
| Answer» <html><body><p>Both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a>, and R is <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of A <br/>Both A and R are true, and R is not the correct explanation of A <br/>A is true but R is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>A is false but R is true</p>Answer :A</body></html> | |
| 50689. |
(A) Benzene on heating conc. H_(2)SO_(4) gives benzene sulphonic acid which heated with supherheated stem under pressure gives benzene. ( R) suplhonation is a reversible precess. |
| Answer» <html><body><p>If both (A) and ( R) are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and ( R) is <a href="https://interviewquestions.tuteehub.com/tag/corrct-2545530" style="font-weight:bold;" target="_blank" title="Click to know more about CORRCT">CORRCT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A).<br/>If both (A) and ( R) are correct but ( R) is not the corrct explanation of (A). <br/>If (A) is incorrect but ( R) is incorrect.<br/>If(A) is incorrect but ( R) is incorrect. </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :a</body></html> | |
| 50690. |
(A) : Benzene decolourises cold alkaline potassium permanganate solution (R) : Benzene is aromatic hydrocarbon |
| Answer» <html><body><p>Both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a>, and R is <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of A <br/>Both A and R are true, and R is not the correct explanation of A <br/>A is true but R is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>A is false but R is true</p>Answer :D</body></html> | |
| 50691. |
(a) [BeF_(4)]^(2-) exits, but [BeCl_(6)]^(4-) does not. Give reson. (b). Hydrated beryllium ion exists as [Be(H_(2)O)_(4)]^(2+), whereas hydrated magnesium ion exists as [Mg(H_(2)O)_(6)]^(2+). Give reason. |
| Answer» <html><body><p></p>Solution :a. `[BeF_(4)]^(2-)` <a href="https://interviewquestions.tuteehub.com/tag/exists-979838" style="font-weight:bold;" target="_blank" title="Click to know more about EXISTS">EXISTS</a>, but `[BeF_(6)]^(4-)` does not. This can be explained on the basis of valence <a href="https://interviewquestions.tuteehub.com/tag/electronic-968847" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRONIC">ELECTRONIC</a> configuration: <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KSV_INORG_CHM_P1_C05_S01_008_S01.png" width="80%"/> <br/> <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to the absence of low-lying `d`-orbitals in beryllium, it cannot expand its coordination number beyond`4`, hence `[BeF_(4)]^(2-)` exists, but `[BeF_(6)]^(4-)` does not.<br/> b. Hydrated beryllium ion exists as `[Be(H_(2)O)_(4)]^(2+)`. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KSV_INORG_CHM_P1_C05_S01_008_S02.png" width="80%"/> <br/>Due to the presence of only four orbitals of equivalent energy in `Be^(2+)` ion and due to the absence of low-lying `d-`orbitals in `Be^(2+)` ion, it can coordinate with four water molecules only, hence hydrated beryllium ion exists as `[Be(H_(2)O)_(4)]^(2+)`. <br/> Whereas in case of <a href="https://interviewquestions.tuteehub.com/tag/magnesium-1082716" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNESIUM">MAGNESIUM</a>, due to the availability of low-lying d-orbitals of <a href="https://interviewquestions.tuteehub.com/tag/suitable-633281" style="font-weight:bold;" target="_blank" title="Click to know more about SUITABLE">SUITABLE</a> energy, `Mg` can expand its coordination number to 6 <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KSV_INORG_CHM_P1_C05_S01_008_S03.png" width="80%"/><br/> Hence, hydrated magnesium ion exists as `[Mg(H_(2)O_(6))]^(2+)`</body></html> | |
| 50692. |
(A): BeF_2 is predominently a covalent compound. (R) : Electronegativity difference between Be and F is too small |
| Answer» <html><body><p>Both (A) and (R) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A) <br/>Both (A) and (R) are true and (R) is not the correct explanation of (A) <br/>(A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R) is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 50693. |
A beam of specific kind of particles of velocity 2.1 xx 10^7 m/s is scattered by a gold (z = 79) nucleli, Find out specific charge (charge/mass) of this particle if the distance of closet approach is 2.5 xx 10^(-14) m. |
| Answer» <html><body><p>`4.84xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a> ` C/kg<br/>`4.84 xx 10^(-7)` C/kg<br/>`2.42 xx 10^(7)` C/kg<br/>`3xx 10^(-12)` C/kg</p>Solution :`1/2 mv^2 = (K(q_1)q_2)/(r) implies (q_2)/(m) = (r.v^2)/(2k.q_1.Z)` <br/>`implies(q_2)/(m) = (2.5 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>)xx (2.1 xx 10^7)^2)/(2xx 9xx10^9 xx <a href="https://interviewquestions.tuteehub.com/tag/79-335953" style="font-weight:bold;" target="_blank" title="Click to know more about 79">79</a> xx 1.6 xx 10^(-19))` <br/>`implies4.84 xx 10^7` coulomb/kg</body></html> | |
| 50694. |
Assertion: Be and Al have similar properties. Reason : Cations of Be and Al have same polarising power |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/> (A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>(A) is false but (R) is true</p>Answer :A</body></html> | |
| 50695. |
A bcc lattice is made up of hollow spheres of X. Spheres of solid 'Y' are present in hollow spheres of X. The radius of 'Y' is half of the radius of 'X' . Calculate the ratio of the total volume of spheres of 'X' unoccupied by Y in a unit cell and volume of the unit cell ? |
| Answer» <html><body><p></p>Solution :Let the <a href="https://interviewquestions.tuteehub.com/tag/radius-1176229" style="font-weight:bold;" target="_blank" title="Click to know more about RADIUS">RADIUS</a> of <a href="https://interviewquestions.tuteehub.com/tag/hollow-1028416" style="font-weight:bold;" target="_blank" title="Click to know more about HOLLOW">HOLLOW</a> sphere X be r. <br/> As spheres X have <a href="https://interviewquestions.tuteehub.com/tag/bcc-389643" style="font-weight:bold;" target="_blank" title="Click to know more about BCC">BCC</a> structure, edge length (a)=`"4r"/sqrt3 "" (therefore "for bcc", r=sqrt3/4 a)` <br/> `therefore` <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of the unit cell =`a^<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>=("4r"/sqrt3)^3` <br/> Radius of sphere Y=`r/2` (Given ) <br/> `therefore` Volume of sphere `X=4/3pir^3` <br/> Volume of sphere `Y=4/3 pi(r/2)^3` <br/> `therefore` Volume of X unoccupied by Y in unit cell =`2xx[4/3pir^3-4/3pi(r/2)^3]` <br/> ( `because` bcc lattice has 2 spheres per unit cell ) <br/> `=2xx4/3pir^3(1-1/8)=2xx4/3pir^3xx7/8` <br/> `therefore "Volume of X unoccupied by Y in unit cell"/"Volume of unit cell"=(2xx4/3pir^3xx7/8)/((4r)/sqrt3)^3=(7pisqrt3)/64`</body></html> | |
| 50696. |
A bcc lattic is made up of hollow spheres of X. spheres of soldid 'Y,' are present in hollow spheres of X. The radius of 'Y'is half of the radius of 'X' . Calculate the ratio of the total volume of spherees of 'X' unoccupied by Y in a unitcell and volume of the unit cell ? |
| Answer» <html><body><p></p>Solution :Let the radius of hollow <a href="https://interviewquestions.tuteehub.com/tag/sphere-1222094" style="font-weight:bold;" target="_blank" title="Click to know more about SPHERE">SPHERE</a> X be r. <br/>As spheres, X have bccstructure, edge lenth `(a)= (<a href="https://interviewquestions.tuteehub.com/tag/4r-319038" style="font-weight:bold;" target="_blank" title="Click to know more about 4R">4R</a>)/(sqrt3)` <br/>Volume of the unit <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a> = ` a^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) = ( (4r)/(sqrt3))^(3)` <br/>Radius of shphere Y =` r/2 ` (Given )<br/>Volume of Sphere X =` 4/3 <a href="https://interviewquestions.tuteehub.com/tag/pir-591537" style="font-weight:bold;" target="_blank" title="Click to know more about PIR">PIR</a>^(3)`<br/> volume of sphere Y ` 4/3 pi (r/2)^(3)`<br/> Volume of X unoccupied by Y in unit cell = `2 xx [ 4/3 pi r^(3)- 4/3 pi ( r/2)^(3) ]` <br/>( bcc lattice has 2 spheres per unit cell )<br/>` 2xx 4/3 pi r^(3) (1-1/8) = 2xx 4/3 pir^(3) xx 7/8` <br/>`(" Volume of X unoccpied by Y in unit cell")/( " volume of unit cell")= (2xx 4/3 pir^(3) xx7/8)/(((4r)/sqrt3)^(3))= ( (7 pisqrt3))/64`</body></html> | |
| 50697. |
A basic lining is given to a furnace by using |
| Answer» <html><body><p>Calcined dolomite <br/>Lime <a href="https://interviewquestions.tuteehub.com/tag/stone-1228007" style="font-weight:bold;" target="_blank" title="Click to know more about STONE">STONE</a> <br/>Haematite<br/>Silica </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Calcined dolomite is <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a> to give a <a href="https://interviewquestions.tuteehub.com/tag/basic-15343" style="font-weight:bold;" target="_blank" title="Click to know more about BASIC">BASIC</a> lining to a <a href="https://interviewquestions.tuteehub.com/tag/furnace-1002481" style="font-weight:bold;" target="_blank" title="Click to know more about FURNACE">FURNACE</a>.</body></html> | |
| 50698. |
A basic buffer contains equal concentration of base and its salt . The dissociation of base is 10^(-6) . Then the pH of the buffer solution is |
| Answer» <html><body><p>6<br/>8<br/>5<br/>9</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 50699. |
(a) Based on the nature of intermolecular forces, classify the following solids . silicon carbide, Argon (b) ZnO turns yellow on heating , why ? (c ) what is meant by groups 12-16 compounds . Give an example. |
| Answer» <html><body><p><br/></p>Answer :(a) `C_(6) H_(6) ` = Non - polar <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> <a href="https://interviewquestions.tuteehub.com/tag/solid-1216587" style="font-weight:bold;" target="_blank" title="Click to know more about SOLID">SOLID</a> , Ag = <a href="https://interviewquestions.tuteehub.com/tag/metallic-547634" style="font-weight:bold;" target="_blank" title="Click to know more about METALLIC">METALLIC</a> solid<br/>(b) N/A <br/> (C ) N/A</body></html> | |
| 50700. |
(a) Based on the nature of intermolecular forces, classify the following solids. Benzene, Silver (b) AgCl shows Frenkel defect while NaCl does not. Give reason. (c ) What type of semiconductor is formed when Ge is doped with Al ? |
| Answer» <html><body><p><br/></p>Answer :(a) ` Na_(2) SO_(4)` = Ionic Solid , ` H_(2)` = <a href="https://interviewquestions.tuteehub.com/tag/non-580180" style="font-weight:bold;" target="_blank" title="Click to know more about NON">NON</a> - polar molecular solid <br/>(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) Elecrical conductivity increases(c ) N/A</body></html> | |