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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 48851. |
Acetone (CH_(3)COCH_(3)) and propanal (CH_(3)CH_(2)CHO) are |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/functional-466801" style="font-weight:bold;" target="_blank" title="Click to know more about FUNCTIONAL">FUNCTIONAL</a> <a href="https://interviewquestions.tuteehub.com/tag/isomers-1052476" style="font-weight:bold;" target="_blank" title="Click to know more about ISOMERS">ISOMERS</a><br/>position isomers<br/>geometrical isomers<br/>optical isomers</p>Solution :Acetone `(CH_(3)COCH_(3))` and <a href="https://interviewquestions.tuteehub.com/tag/propanal-1169788" style="font-weight:bold;" target="_blank" title="Click to know more about PROPANAL">PROPANAL</a> `(CH_(3)CH_(2)CHO)` are functional isomers.</body></html> | |
| 48852. |
Acetone and water is purified by ______ methods. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/crystallization-940088" style="font-weight:bold;" target="_blank" title="Click to know more about CRYSTALLIZATION">CRYSTALLIZATION</a> <br/>Simple <a href="https://interviewquestions.tuteehub.com/tag/distillation-15402" style="font-weight:bold;" target="_blank" title="Click to know more about DISTILLATION">DISTILLATION</a> <br/>Chromatography <br/>distillation </p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/difference-951394" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFERENCE">DIFFERENCE</a> in their boiling point is large.</body></html> | |
| 48853. |
Acetone and propen-2-ol are |
| Answer» <html><body><p>enantiomers<br/>keto-enol tautomers<br/>diastereoisomers<br/>meso compounds</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 48854. |
Acetone and prop-1-in-2-ol are example of which type of isomerism? |
| Answer» <html><body><p>Position isomerism<br/>tautomerism<br/>Functional group<br/>metamerism</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>("<a href="https://interviewquestions.tuteehub.com/tag/acetone-847404" style="font-weight:bold;" target="_blank" title="Click to know more about ACETONE">ACETONE</a>")(CH_(3)-underset(underset(O)(||))(C )-CH_(3)) <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> underset("prop-1-en-2-ol")(CH_(3)-underset(underset(OH)(|))(C )=CH_(2))`</body></html> | |
| 48855. |
Acetoacetic ester behaves as |
| Answer» <html><body><p>An unsaturated hydroxy compound<br/>A keto compound<br/>Both of these ways<br/>None of these</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>("Acetoacetic ester (keto form)")(H_(3) C - overset(O)overset(||)(C) - CH_(2) - overset(O)overset(||)(C) - OC_(2)H_(5) ) <a href="https://interviewquestions.tuteehub.com/tag/harr-2692945" style="font-weight:bold;" target="_blank" title="Click to know more about HARR">HARR</a> underset(("<a href="https://interviewquestions.tuteehub.com/tag/enolic-2072033" style="font-weight:bold;" target="_blank" title="Click to know more about ENOLIC">ENOLIC</a> form"))(H_(3) C - overset(OH)overset(|)(C) = <a href="https://interviewquestions.tuteehub.com/tag/ch-913588" style="font-weight:bold;" target="_blank" title="Click to know more about CH">CH</a> - overset(O)overset(||)(C) - OC_(2)H_(5))`</body></html> | |
| 48856. |
Acetic anhydride is used for the detection and estimation of |
| Answer» <html><body><p>`-OH` group<br/>`-<a href="https://interviewquestions.tuteehub.com/tag/cooh-409857" style="font-weight:bold;" target="_blank" title="Click to know more about COOH">COOH</a>` group<br/>`-<a href="https://interviewquestions.tuteehub.com/tag/cho-408392" style="font-weight:bold;" target="_blank" title="Click to know more about CHO">CHO</a>` group<br/>`-CONH_(2)` group</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/acetic-1967065" style="font-weight:bold;" target="_blank" title="Click to know more about ACETIC">ACETIC</a> <a href="https://interviewquestions.tuteehub.com/tag/anhydride-875713" style="font-weight:bold;" target="_blank" title="Click to know more about ANHYDRIDE">ANHYDRIDE</a> is used for the <a href="https://interviewquestions.tuteehub.com/tag/detection-949838" style="font-weight:bold;" target="_blank" title="Click to know more about DETECTION">DETECTION</a> and estimation of `-OH` group</body></html> | |
| 48857. |
Acetic anhydride is prepared in the laboratory by heating sodium acetate with |
| Answer» <html><body><p>ethyl chloride<br/>acetyl chloride<br/>conc. `H_(2)SO_(4)`<br/>Zinc dust.</p>Solution :`CH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)COONa + CH_(3)COCl overset(<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a>)rarr underset("Acetic anhydride")(CH_(3)COOCOCH_(3)) + NaCl`</body></html> | |
| 48858. |
Acetic anhydride is obtained by the reaction of |
| Answer» <html><body><p>sodium and <a href="https://interviewquestions.tuteehub.com/tag/acetic-1967065" style="font-weight:bold;" target="_blank" title="Click to know more about ACETIC">ACETIC</a> acid<br/>water and acetic acid<br/>ethyl <a href="https://interviewquestions.tuteehub.com/tag/alcohol-853024" style="font-weight:bold;" target="_blank" title="Click to know more about ALCOHOL">ALCOHOL</a> and acetic acid<br/>`P_(2)O_(5)` and acetic acid</p>Solution :`2CH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)<a href="https://interviewquestions.tuteehub.com/tag/cooh-409857" style="font-weight:bold;" target="_blank" title="Click to know more about COOH">COOH</a> overset(P_(2)O_(5) //Delta)rarr (CH_(3)CO)_(2)O + H_(2)O`</body></html> | |
| 48859. |
Acetic acid when treated with NH_(3) forms ammonium acetate which on heating gives |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/methyl-1095247" style="font-weight:bold;" target="_blank" title="Click to know more about METHYL">METHYL</a> cyanide<br/>acetic anhydride<br/>acetaldehyde<br/>acetamide</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/see-630247" style="font-weight:bold;" target="_blank" title="Click to know more about SEE">SEE</a> <a href="https://interviewquestions.tuteehub.com/tag/properties-11511" style="font-weight:bold;" target="_blank" title="Click to know more about PROPERTIES">PROPERTIES</a> of <a href="https://interviewquestions.tuteehub.com/tag/acids-366963" style="font-weight:bold;" target="_blank" title="Click to know more about ACIDS">ACIDS</a></body></html> | |
| 48860. |
Acetic acid reacts with PCl_(5) to form |
| Answer» <html><body><p>`CH_(2)ClCOOH`<br/>`CHCl_(2)COOH`<br/>`CH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)COCl`<br/>`CH_(3)COOCl`</p>Solution :`CH_(3) - overset(O)overset(||)(C) - <a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a> + PCl_(5) rarr CH_(3) - overset(O)overset(||)(C) - Cl + <a href="https://interviewquestions.tuteehub.com/tag/hcl-479502" style="font-weight:bold;" target="_blank" title="Click to know more about HCL">HCL</a> + POCl_(3)`</body></html> | |
| 48861. |
Acetic acid is weaker acid than formic acid. This is explained by |
| Answer» <html><body><p>Mesomeric effect<br/>Inductive effect<br/>Hyper conjugation<br/>electromeric effect</p>Solution :Due to Inductive effect of `-CH_3` <a href="https://interviewquestions.tuteehub.com/tag/group-1013370" style="font-weight:bold;" target="_blank" title="Click to know more about GROUP">GROUP</a> acitic <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a> is <a href="https://interviewquestions.tuteehub.com/tag/weaker-3271297" style="font-weight:bold;" target="_blank" title="Click to know more about WEAKER">WEAKER</a>.</body></html> | |
| 48862. |
Acetic acid is found to have molar mass as 120 g mol ^(-1). Prove it. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(i) In certain <a href="https://interviewquestions.tuteehub.com/tag/solvent-1217160" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVENT">SOLVENT</a>, solute molecules associate to from a dimer. This reduces the total number of molecules formed in solution and as a <a href="https://interviewquestions.tuteehub.com/tag/result-1187343" style="font-weight:bold;" target="_blank" title="Click to know more about RESULT">RESULT</a> the calculated molar mass will be higher than the actual molar mass. <br/> (ii) <a href="https://interviewquestions.tuteehub.com/tag/acetic-1967065" style="font-weight:bold;" target="_blank" title="Click to know more about ACETIC">ACETIC</a> <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a> in benzene exist as a dimer <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V02_C09_E03_152_S01.png" width="80%"/><br/> (iii) The molar mass of acetic acid calculate using colligative properties is found to be around 120 g `mol^(-1)` is two times of the actual molar mass `60 g mol ^(-1)`</body></html> | |
| 48863. |
Acetic acid is added to the solution of sodium carbonate the gas evolved does not turn purple colour of KMnO_(4) but turns lime water milky forming a compound (M) which becomes soluble by passing the same gas in excess forming another compound (N). But same obserbation is not obtained with boric acid. The correct order of increasing acidity is: |
| Answer» <html><body><p>Boric acid `lt` <a href="https://interviewquestions.tuteehub.com/tag/acetic-1967065" style="font-weight:bold;" target="_blank" title="Click to know more about ACETIC">ACETIC</a> acid `lt` Carbonic acid<br/>Acetic acid `lt` Boric acid `lt` Carbonic acid<br/>Carbonic acid `lt` Acetic acid `lt` Boric acid<br/>Boric acid `lt` carbonic acid `lt` Acetic acid </p>Solution :`Na_(2)CO_(3) <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(AcOH)rarr CO_(2) overset(<a href="https://interviewquestions.tuteehub.com/tag/ca-375" style="font-weight:bold;" target="_blank" title="Click to know more about CA">CA</a>(OH)_(2))rarr underset((M))(CaCO_(3)darr) overset(CO_(2))underset(H_(2)O)rarr underset((<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>))(Ca(HCO_(3))_(2))`</body></html> | |
| 48864. |
Acetic acid is added to the solution of sodium carbonate the gas evolved does not turn purple colour of KMnO_(4) but turns lime water milky forming a compound (M) which becomes soluble by passing the same gas in excess forming another compound (N). But same obserbation is not obtained with boric acid. The compound formed in the above sequence (M) and (N) are respectively. |
| Answer» <html><body><p>water <a href="https://interviewquestions.tuteehub.com/tag/soluble-3046305" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUBLE">SOLUBLE</a> `CaCO_(3)` and water soluble `Ca(HCO_(3))_(2)`<br/>water insoluble `CaCO_(3)` and water insoluble `Ca(HCO_(3))_(2)`<br/>water insoluble `CaCO_(3)` and water soluble `Ca(HCO_(3))_(2)`<br/>water soluble `CaCO_(3)` and water insoluble `Ca(HCO_(3))_(2)`</p>Solution :`Na_(2)CO_(3) overset(<a href="https://interviewquestions.tuteehub.com/tag/acoh-1966500" style="font-weight:bold;" target="_blank" title="Click to know more about ACOH">ACOH</a>)rarr CO_(2) overset(Ca(OH)_(2))rarr underset((M))(CaCO_(3)<a href="https://interviewquestions.tuteehub.com/tag/darr-943899" style="font-weight:bold;" target="_blank" title="Click to know more about DARR">DARR</a>) overset(CO_(2))underset(H_(2)O)rarr underset((N))(Ca(HCO_(3))_(2))`</body></html> | |
| 48865. |
Acetic acid is added to the solution of sodium carbonate the gas evolved does not turn purple colour of KMnO_(4) but turns lime water milky forming a compound (M) which becomes soluble by passing the same gas in excess forming another compound (N). But same obserbation is not obtained with boric acid. Purple colour of KMnO_(4) has not changed because: |
| Answer» <html><body><p>the gas has no oxidising property since central atom is in minimum oxidation state<br/>the gas has no reducingproperty since the central atom is in <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> oxidation state<br/>the gas has no precipitattion characteristics<br/>the gas <a href="https://interviewquestions.tuteehub.com/tag/precipitates-1162809" style="font-weight:bold;" target="_blank" title="Click to know more about PRECIPITATES">PRECIPITATES</a> `CaCO_(3)` from line water</p>Solution :`Na_(2)CO_(3) <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(<a href="https://interviewquestions.tuteehub.com/tag/acoh-1966500" style="font-weight:bold;" target="_blank" title="Click to know more about ACOH">ACOH</a>)rarr CO_(2) overset(Ca(OH)_(2))rarr underset((M))(CaCO_(3)darr) overset(CO_(2))underset(H_(2)O)rarr underset((<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>))(Ca(HCO_(3))_(2))`</body></html> | |
| 48866. |
Acetic acid has a dissociation constant of 1.8xx10^(-5), Calculate the pH values of the decinormal solution of Acetic acid. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`[H^(+)]=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(K_(a).<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>)""C=0.1M` <br/> `sqrt(1.8xx10^(-1)xx10^(-1))=1.34xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/> `pH=-log[H^(+)]=-log01.34xx10^(-1)=2.872`</body></html> | |
| 48867. |
Acetic acid has a dissociationconstant of 1.8xx10^(-5). Calculate the pH value of the decinormal solution of acetic acid. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :2.87</body></html> | |
| 48868. |
Acetic acid exist as a dimer in benzene due to |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/condensation-19217" style="font-weight:bold;" target="_blank" title="Click to know more about CONDENSATION">CONDENSATION</a> reaction<br/>Hydrogen bonding<br/>Presence of phenyl group<br/>Presence of hydrogen <a href="https://interviewquestions.tuteehub.com/tag/atom-887280" style="font-weight:bold;" target="_blank" title="Click to know more about ATOM">ATOM</a> at & -carbon</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 48869. |
Acetic acid exist as a __________ |
| Answer» <html><body><p>monomer<br/>dimer<br/>trimer<br/>octamer</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 48870. |
Acetic acid dissociates as CH_(3) "COOH" hArr CH_(3) "COO"^(-) + H^(+).If a little amount of sodium acetate is added to its aqueous solution |
| Answer» <html><body><p>The acid <a href="https://interviewquestions.tuteehub.com/tag/dissociates-2586693" style="font-weight:bold;" target="_blank" title="Click to know more about DISSOCIATES">DISSOCIATES</a> further<br/>The `H^(+)` <a href="https://interviewquestions.tuteehub.com/tag/ion-1051153" style="font-weight:bold;" target="_blank" title="Click to know more about ION">ION</a> concentration increases<br/>The acid dissocitaion is suppressed<br/>The <a href="https://interviewquestions.tuteehub.com/tag/equilibrium-974342" style="font-weight:bold;" target="_blank" title="Click to know more about EQUILIBRIUM">EQUILIBRIUM</a> is unaffected</p>Solution :`CH_(3)COONa` increases `[CH_(3)COO^(-)]` <br/> `:.` <a href="https://interviewquestions.tuteehub.com/tag/backward-391901" style="font-weight:bold;" target="_blank" title="Click to know more about BACKWARD">BACKWARD</a> reaction <a href="https://interviewquestions.tuteehub.com/tag/favoured-7681397" style="font-weight:bold;" target="_blank" title="Click to know more about FAVOURED">FAVOURED</a></body></html> | |
| 48871. |
Acetic acid and glucose have same |
| Answer» <html><body><p>emperical formula<br/>weight <a href="https://interviewquestions.tuteehub.com/tag/composition-22493" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOSITION">COMPOSITION</a> of elements <br/><a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> of masses of <a href="https://interviewquestions.tuteehub.com/tag/individual-1041871" style="font-weight:bold;" target="_blank" title="Click to know more about INDIVIDUAL">INDIVIDUAL</a> elements <br/>number of gramatoms of each element <a href="https://interviewquestions.tuteehub.com/tag/per-590802" style="font-weight:bold;" target="_blank" title="Click to know more about PER">PER</a> mole</p>Solution :Same E.F. implies Same % i.e., same ratio of masses.</body></html> | |
| 48872. |
Acetamide is amhoteric in nature. Hence it can react with limited amount of |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/hcl-479502" style="font-weight:bold;" target="_blank" title="Click to know more about HCL">HCL</a><br/> HgO<br/>HCl as <a href="https://interviewquestions.tuteehub.com/tag/well-734398" style="font-weight:bold;" target="_blank" title="Click to know more about WELL">WELL</a> as HgO<br/>NaOH</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/factual-982918" style="font-weight:bold;" target="_blank" title="Click to know more about FACTUAL">FACTUAL</a> <a href="https://interviewquestions.tuteehub.com/tag/question-25051" style="font-weight:bold;" target="_blank" title="Click to know more about QUESTION">QUESTION</a></body></html> | |
| 48873. |
Acetamide is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/highly-2102664" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHLY">HIGHLY</a> acidic<br/>highly basic<br/>neutral<br/>amphoteric</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>(("Acid"))(CH_(3) - <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(O)overset(||)(C) - NH_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)) + Na rarr CH_(3) - overset(O)overset(||)(C) - overset(-)(NH) overset(+)(Na) + (1)/(2) H_(2) <a href="https://interviewquestions.tuteehub.com/tag/uarr-3241817" style="font-weight:bold;" target="_blank" title="Click to know more about UARR">UARR</a>`<br/> `underset(("Base"))(CH_(3) - overset(O)overset(||)(C)) - NH_(2) + HCl rarr CH_(3) - overset(O)overset(||)(C) - overset(+)(N)H_(3) overset(-)(Cl`</body></html> | |
| 48874. |
Acetamide and NaOBr//OH^(-) produce |
| Answer» <html><body><p>Ethanamine<<a href="https://interviewquestions.tuteehub.com/tag/br-390993" style="font-weight:bold;" target="_blank" title="Click to know more about BR">BR</a>>Methanamine<br/>`CH_(3)<a href="https://interviewquestions.tuteehub.com/tag/cn-907325" style="font-weight:bold;" target="_blank" title="Click to know more about CN">CN</a>`<br/>`NH_(3)`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/hoffman-7754708" style="font-weight:bold;" target="_blank" title="Click to know more about HOFFMAN">HOFFMAN</a> Bromamide reaction <br/> `CH_(3) - <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(O)overset(||)(C) - NH_(2) + Br_(2) + 4 <a href="https://interviewquestions.tuteehub.com/tag/naoh-572531" style="font-weight:bold;" target="_blank" title="Click to know more about NAOH">NAOH</a> rarr CH_(3) NH_(2) + Na_(2)CO_(3) + 2NaBr + H_(2)O`</body></html> | |
| 48875. |
Acetaldehyde is polar and benzene is non-polar. But benzene boils at higher temperature. Why? |
| Answer» <html><body><p></p>Solution :Acetaldehyde is polar and has dipole-dipole <a href="https://interviewquestions.tuteehub.com/tag/attractions-385215" style="font-weight:bold;" target="_blank" title="Click to know more about ATTRACTIONS">ATTRACTIONS</a> between its molecules. However, benzene molecules has dispersion of <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> electron cloud. <br/> <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> molecules of benzene are more associated. Because of the dispersed picloud, <a href="https://interviewquestions.tuteehub.com/tag/benzee-2000390" style="font-weight:bold;" target="_blank" title="Click to know more about BENZEE">BENZEE</a> is less volatile and has higher <a href="https://interviewquestions.tuteehub.com/tag/boiling-17187" style="font-weight:bold;" target="_blank" title="Click to know more about BOILING">BOILING</a> point compared to acetaldehyde</body></html> | |
| 48876. |
Acetaldehyde and propyne can be distinguish by (i) Tollen's reagent(ii) I_(2)//NaOH(iii) Lucas reagent(iv) neutral FeCl_(3) |
| Answer» <html><body><p>(i) ,(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>)& (iii) <br/>(ii) & (iii) <br/>(i) & (ii) <br/>(iii) & (iv) </p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/acetaldehyde-366764" style="font-weight:bold;" target="_blank" title="Click to know more about ACETALDEHYDE">ACETALDEHYDE</a> and propyne can be <a href="https://interviewquestions.tuteehub.com/tag/distinguished-440820" style="font-weight:bold;" target="_blank" title="Click to know more about DISTINGUISHED">DISTINGUISHED</a> by tollen's <a href="https://interviewquestions.tuteehub.com/tag/reagent-1178480" style="font-weight:bold;" target="_blank" title="Click to know more about REAGENT">REAGENT</a> and iodoform test.</body></html> | |
| 48877. |
Accroding to Bohr's theory angular momentum of an electron in 6^(th) orbit is |
| Answer» <html><body><p>`2.5 <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>/pi`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> h/pi`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> h/pi`<br/>`(2.5 h)/(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)`</p>Answer :C</body></html> | |
| 48878. |
Account for the foolowing: (a) Aluminium is not prepared by carrying out the electrolysis of moltent alumina (Al_(2)O_(3)). (b) Aluminium is preferred in electrical cables though it is relatively less conducting than copper. (iii) Aluminium dissolves in both acidic and basic solutions. |
| Answer» <html><body><p></p>Solution :(a) Alumina `(Al_(2)O_(3))` is a poor <a href="https://interviewquestions.tuteehub.com/tag/conductor-928880" style="font-weight:bold;" target="_blank" title="Click to know more about CONDUCTOR">CONDUCTOR</a> of <a href="https://interviewquestions.tuteehub.com/tag/electricity-968393" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRICITY">ELECTRICITY</a> and, therefore, the process of electrolysis is not very successful. <a href="https://interviewquestions.tuteehub.com/tag/moreover-563893" style="font-weight:bold;" target="_blank" title="Click to know more about MOREOVER">MOREOVER</a>, the melting point of alumina is also very high (2323K) and it is very difficult to attain and maintain this temperature. Alumina is genrally mixed with cryolite `(Na_(3)AIF_(6))` which lowers the melting point to maintain this temperature. Alumina is generally mixed with cryolite `(Na_(3)AIF_(6))` which lowers the meltingpoint to about 1173k and also converts aluminium oxide to aluminium <a href="https://interviewquestions.tuteehub.com/tag/fluoride-993703" style="font-weight:bold;" target="_blank" title="Click to know more about FLUORIDE">FLUORIDE</a> `(AIF_(3))` which is quite conducting. <br/> (b) Although aluminium is less conducting than copper it is <a href="https://interviewquestions.tuteehub.com/tag/still-653256" style="font-weight:bold;" target="_blank" title="Click to know more about STILL">STILL</a> preferred in the electric cables because it is cheaper than copper. <br/> (c) Aluminium is weakly electrospostive in nature. it, therefore, reacts with both acids and bases <br/> `2Al+6HCLrar2AlCl_(3)+3H_(2)` <br/> `2Al+2NaOH+2H_(2)Orarr2NaAlO_(2)+3H_(2)` <br/>Sod. metaaluminate</body></html> | |
| 48879. |
Account for the following:The experimentally determined N_F bond length inNF_(3)is greater than the sum of the sigle covalent radii of N andF. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :This is because both <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> and F aresmall and hence have high <a href="https://interviewquestions.tuteehub.com/tag/electron-968715" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRON">ELECTRON</a> density . So they repal the bond <a href="https://interviewquestions.tuteehub.com/tag/pairs-1145786" style="font-weight:bold;" target="_blank" title="Click to know more about PAIRS">PAIRS</a><br/> thereby making the N-F bond length <a href="https://interviewquestions.tuteehub.com/tag/larger-1067345" style="font-weight:bold;" target="_blank" title="Click to know more about LARGER">LARGER</a>.</body></html> | |
| 48880. |
Account for the following: t-butyl chloride reacts with aqueous KOH by S_(N)1 mechanism while n-butyl chloride reacts with S_(N^(2)) mechanism. |
| Answer» <html><body><p></p>Solution :This is because rate of `S_(N(2))` <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> is directly proportional to delta <a href="https://interviewquestions.tuteehub.com/tag/inversely-7688775" style="font-weight:bold;" target="_blank" title="Click to know more about INVERSELY">INVERSELY</a> proportional to steric crowding. Ter-buty & chloride has vast steric crowding. Ter-buty & chloride has vast steric crowding and <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a> it is more stable. For `S_(N^(1))` reaction rather then `S_(N^(2))` reaction.</body></html> | |
| 48881. |
Account for the following : PCl_(5) is more covalent than PCl_(3). |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/oxidation-588780" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDATION">OXIDATION</a> state of P in `PCl_(5)` is +5 and that in `PCl_(3)` is +3. Since <a href="https://interviewquestions.tuteehub.com/tag/elements-969381" style="font-weight:bold;" target="_blank" title="Click to know more about ELEMENTS">ELEMENTS</a> in the +5 oxidation state have less <a href="https://interviewquestions.tuteehub.com/tag/tendency-1241592" style="font-weight:bold;" target="_blank" title="Click to know more about TENDENCY">TENDENCY</a> to <a href="https://interviewquestions.tuteehub.com/tag/lose-537625" style="font-weight:bold;" target="_blank" title="Click to know more about LOSE">LOSE</a> electrons than in the +3 oxidation state, therefore, P in the +5 oxidation state has more tendency to share its electrons with Cl than in the +3 oxidation state. <a href="https://interviewquestions.tuteehub.com/tag/thus-2307358" style="font-weight:bold;" target="_blank" title="Click to know more about THUS">THUS</a>, `PCl_(5)` is more covalent than `PCl_(3)`.</body></html> | |
| 48882. |
Account for the following: p-dichloro benzene has higer melting point than those of o-and m-dichloro benzene. |
| Answer» <html><body><p></p>Solution :p-dichloro benzene is more symmetrical than O and m isomers and so <a href="https://interviewquestions.tuteehub.com/tag/fits-991213" style="font-weight:bold;" target="_blank" title="Click to know more about FITS">FITS</a> perfectly in crystal lattice. <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> more <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> is required to <a href="https://interviewquestions.tuteehub.com/tag/break-903849" style="font-weight:bold;" target="_blank" title="Click to know more about BREAK">BREAK</a> the crystal lattice of p-dichlorobenzens and so has higher <a href="https://interviewquestions.tuteehub.com/tag/melting-1093090" style="font-weight:bold;" target="_blank" title="Click to know more about MELTING">MELTING</a> point.</body></html> | |
| 48883. |
Account for the following observations : Though fluorine is more electronegative than chlorine yet BF_3 is a weaker Lewis acid than Cl_3. |
| Answer» <html><body><p></p>Solution :In `BF_3`, boron has a <a href="https://interviewquestions.tuteehub.com/tag/vacant-3253649" style="font-weight:bold;" target="_blank" title="Click to know more about VACANT">VACANT</a> <a href="https://interviewquestions.tuteehub.com/tag/2p-300467" style="font-weight:bold;" target="_blank" title="Click to know more about 2P">2P</a> orbital and fluorine has one of the 2p orbital completely <a href="https://interviewquestions.tuteehub.com/tag/filled-2641169" style="font-weight:bold;" target="_blank" title="Click to know more about FILLED">FILLED</a> and unutilized. Both have same energy and can <a href="https://interviewquestions.tuteehub.com/tag/overlap-1144089" style="font-weight:bold;" target="_blank" title="Click to know more about OVERLAP">OVERLAP</a> effectively to give `ppi-ppi` bond. <br/>While such type of bonding is not possible in `BCl_3` as there is no effective overlapping between the 2p-orbital of boron and 3p-orbital of chlorine. <br/>Therefore electron deficiency of B is higher than that of `BF_3`. Therefore `BF_3` is weaker Lewis <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a>. <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_CHE_XI_P2_C11_E04_065_S01.png" width="80%"/></body></html> | |
| 48884. |
Account for the following observations : The +1 oxidation state of thallium is more stable than its +3 state. |
| Answer» <html><body><p></p>Solution :`Tl^+`is more table than `Tl^(+<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to <a href="https://interviewquestions.tuteehub.com/tag/inert-1043160" style="font-weight:bold;" target="_blank" title="Click to know more about INERT">INERT</a> <a href="https://interviewquestions.tuteehub.com/tag/pair-1145723" style="font-weight:bold;" target="_blank" title="Click to know more about PAIR">PAIR</a> <a href="https://interviewquestions.tuteehub.com/tag/effect-966056" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECT">EFFECT</a>.</body></html> | |
| 48885. |
Account for the following observations : PbO_2is a stronger oxidizing agent than SnO_2. |
| Answer» <html><body><p></p>Solution :In `PbO_2` and `SnO_2` both lead and the tin are present in +4 oxidation <a href="https://interviewquestions.tuteehub.com/tag/state-21805" style="font-weight:bold;" target="_blank" title="Click to know more about STATE">STATE</a> but due to stronger inert pair effect, `Pb^(+2)` ion is more stable than `<a href="https://interviewquestions.tuteehub.com/tag/sn-646415" style="font-weight:bold;" target="_blank" title="Click to know more about SN">SN</a>^(+2)` ion. So `PbO_4` is stronger <a href="https://interviewquestions.tuteehub.com/tag/oxidising-2209005" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDISING">OXIDISING</a> <a href="https://interviewquestions.tuteehub.com/tag/agent-369049" style="font-weight:bold;" target="_blank" title="Click to know more about AGENT">AGENT</a>.</body></html> | |
| 48886. |
Account for the following observations : (i) AlCl_(3) is a lewis acid. (ii) Though fluorine is more electronegative than chlorine yet BF_(3) is a weaker Lewis acid than BCl_(3). (iii) PbO_(2)is stronger oxidising agent than SnO_(2).(iv) The +1 oxidation state of thallium is more stable than its +3 state. |
| Answer» <html><body><p></p>Solution :(i) The `Al` atoms in `AlCl_(3)`, has only six electron in tis valence shell and hence can accept apair of its octet. Therefore, it actsas a Lewis acid. <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) The B atom in `BF_(3)` or has only six electronsin the valene shell and hence can accept a pair of electrons to <a href="https://interviewquestions.tuteehub.com/tag/complete-423576" style="font-weight:bold;" target="_blank" title="Click to know more about COMPLETE">COMPLETE</a> its octet. Therefore,both `BF_(3)` and`BCl_(3)` act asLewis acids.But in `BF_(3)`,the <a href="https://interviewquestions.tuteehub.com/tag/size-1211196" style="font-weight:bold;" target="_blank" title="Click to know more about SIZE">SIZE</a> of empty 2p-orbital on Band 2p-orbital on F containingthe lone pair of electronsof F is donated to the empty 2p-orbital to a considerable <a href="https://interviewquestions.tuteehub.com/tag/extent-981159" style="font-weight:bold;" target="_blank" title="Click to know more about EXTENT">EXTENT</a> and hence electrondeficiency of B decreases. In contrast,in `BCl_(3)`, the size of `3p`-orbital of Cl containing the lone pair . <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C11A_E12_002_S01.png" width="80%"/> <br/> of electron is muchbigger than the empty 2p-orbital of B and hence donation of lone pairof electron of Cl to B does notoccur to any significantextent. Thereforeelectron deficiency of B is much higherin `BCl_(3)` than thatis `BF_(3)`and hence `BCl_(3)` is a stronger <a href="https://interviewquestions.tuteehub.com/tag/lewisacid-2156750" style="font-weight:bold;" target="_blank" title="Click to know more about LEWISACID">LEWISACID</a> than `BF_(3)`. <br/> (iii) N/A, (iv) N/A</body></html> | |
| 48887. |
Account for the following observation: (i) AlCl_(3) is Lewis acid (ii) Though fluorine is more electronegative than chlorine yet BF_(3) is a weaker Lewis acid than BCl_(3) (iii) PbO_(2) is a stronger oxidising agent thatn SnO_(2) (iv) The +1 oxidation state of thallium is more stable than its +3state. |
| Answer» <html><body><p></p>Solution :(i) `AlCl_(3)` is a Lewis acid because the central Al <a href="https://interviewquestions.tuteehub.com/tag/atom-887280" style="font-weight:bold;" target="_blank" title="Click to know more about ATOM">ATOM</a> has a sextel of electrons after <a href="https://interviewquestions.tuteehub.com/tag/sharing-25803" style="font-weight:bold;" target="_blank" title="Click to know more about SHARING">SHARING</a>. It is electron deficient and `AlCl_(3)` <a href="https://interviewquestions.tuteehub.com/tag/behaves-894569" style="font-weight:bold;" target="_blank" title="Click to know more about BEHAVES">BEHAVES</a> as a Lewis acid. <br/> (ii) For answer, consult <a href="https://interviewquestions.tuteehub.com/tag/section-25668" style="font-weight:bold;" target="_blank" title="Click to know more about SECTION">SECTION</a> 11.12. <br/> (iii) +2 oxidation state of Pb in `PbO_(2)` is more stable than +2 oxidatin state of Sn in `SnO_(2)` due to greater <a href="https://interviewquestions.tuteehub.com/tag/inert-1043160" style="font-weight:bold;" target="_blank" title="Click to know more about INERT">INERT</a> pair effect. This means that `PbO_(2)` is a stronger oxidising agent than `SnO_(2)` and changes to +2oxidisionstate more easily. <br/> (iv) For answer, consult section 11.2.</body></html> | |
| 48888. |
Account for the following observations : AlCl_3 is a Lewis acid. |
| Answer» <html><body><p></p>Solution :In `AlCl_3`, the <a href="https://interviewquestions.tuteehub.com/tag/octet-1128040" style="font-weight:bold;" target="_blank" title="Click to know more about OCTET">OCTET</a> of Al is incomplete as it has <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> electrons and accepts pair of electrons. <a href="https://interviewquestions.tuteehub.com/tag/electron-968715" style="font-weight:bold;" target="_blank" title="Click to know more about ELECTRON">ELECTRON</a> accepters are Lewis <a href="https://interviewquestions.tuteehub.com/tag/acids-366963" style="font-weight:bold;" target="_blank" title="Click to know more about ACIDS">ACIDS</a>.</body></html> | |
| 48889. |
Account for the following observations (a) AlCl_(3) is a Lewis acid (b) Though fluorine is more electronegative than chlorine yet BF_(3) is a weaker Lewis acid than CI_(3) (c) PbO_(2) is a stronger oxidising agent than SnO_(2) (d) The +1 oxidation state of thallium is more stable than its +3 state. |
| Answer» <html><body><p></p>Solution :(a) In `AlCl_(3),Al` has only six electron in its valence shell. It is an electron deficient <a href="https://interviewquestions.tuteehub.com/tag/species-650011" style="font-weight:bold;" target="_blank" title="Click to know more about SPECIES">SPECIES</a>. Therefore, it acts as a Lewis acid (electron <a href="https://interviewquestions.tuteehub.com/tag/acceptor-846761" style="font-weight:bold;" target="_blank" title="Click to know more about ACCEPTOR">ACCEPTOR</a>) <br/> (b) In `BF_(3)` boron has a vacant 2p-orbital and fluorine has one 2p-completely filled unutilised orbital. Both of these <a href="https://interviewquestions.tuteehub.com/tag/orbitals-1138192" style="font-weight:bold;" target="_blank" title="Click to know more about ORBITALS">ORBITALS</a> belong to same energy level therefore, they can overlap efficitively and form `p pi - p pi` bond. This type of bond formation is known as back bonding. <br/> While back bonding is not possible in `BCl_(3)`, because there is no <a href="https://interviewquestions.tuteehub.com/tag/effective-966090" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECTIVE">EFFECTIVE</a> overlapping between 2p-orbital of boron and 3p-orbital of chlorine. Therefore, electron deficiency of B is higher in `BCl_(3)` than that of `BF_(3)`. That's why `BF_(3)` is a weaker Lewis acid than `BCl_(3)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NCERT_EXE_CHM_XI_C11_S01_042_S01.png" width="80%"/> <br/> (c) In `PbO_(2) and SnO_(2)`, both lead and tin are present in +4 oxidation state. But due to stronger inert pair effect, `Pb^(2+)` ion is more stable than `Sn^(2+)` ion. In other words, `Pb^(4+)` ions i.e., `PbO_(4)` is more easily reduced to `Pb^(2+)` ions than `Sn^(4+)` ions reduced to `Sn^(2+)` ions. Thus, `PbO_(2)` acts as a stronger <a href="https://interviewquestions.tuteehub.com/tag/oxidising-2209005" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDISING">OXIDISING</a> agent than `SnO_(2)` <br/> (d) `Tl^(+)` is more stable than `Tl^(3+)` because of inert pair effect.</body></html> | |
| 48890. |
Account for the following (i) t-butyl chloride reacts with aqueous KOH by S_(N^1) mechanism while n-butyl chloride reacts with S_(N^2)mechanism. (ii) p-dichlorobenzene has higher melting point than those of o-and m - dichlorobenzene. |
| Answer» <html><body><p></p>Solution :(i) In t-butyl chloride, there is more <a href="https://interviewquestions.tuteehub.com/tag/steric-2282020" style="font-weight:bold;" target="_blank" title="Click to know more about STERIC">STERIC</a> hindr ance and it involves formation of a stable tertiary <a href="https://interviewquestions.tuteehub.com/tag/carbocation-909158" style="font-weight:bold;" target="_blank" title="Click to know more about CARBOCATION">CARBOCATION</a>. Therefore it reacts with KOH by`S_(N^1)`- mechanism rather than `S_(N^2)`-mechanism because `S_(N^1)`-mechanism is favourable in case of steric crowding and is directly proportional to partial positive charge on carbon atom. <br/> In n-butyl chloride, there is least steric hindrance and involves formation of less stable primary carbocation. Thus it takes place in one step and is favoured by `S_(N^2)`-mechanism.<br/> (ii) Melting point ofp- dichlorobenzene is <a href="https://interviewquestions.tuteehub.com/tag/higher-1022060" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHER">HIGHER</a> than that of ortho and meta-dichlorobenzene. <br/> This is due to the <a href="https://interviewquestions.tuteehub.com/tag/fact-982736" style="font-weight:bold;" target="_blank" title="Click to know more about FACT">FACT</a> that is has a symmetrical structure and therefore, its molecules can easily pack closely in the crystal lattice. p-dichlorobenzene being more symmetrical fits closely in the crystal lattice and has stronger intermolecular <a href="https://interviewquestions.tuteehub.com/tag/attraction-887653" style="font-weight:bold;" target="_blank" title="Click to know more about ATTRACTION">ATTRACTION</a> than o & m isomers. So p-isomer has high melting point than the corresponding o & m-isomers.</body></html> | |
| 48891. |
Account for the following: (i) PbX_(2) is more stable than PbX_(4) (X = Cl, Br) (ii) PbCl_(4) is more stable than SnCl_(4) but PbCl_(2) is more stable than SnCl_(2), (iii) PbCl_(4) is less stablethan SnCl_(4) ? |
| Answer» <html><body><p></p>Solution :(i) <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to inert pair effect, the +2 <a href="https://interviewquestions.tuteehub.com/tag/oxidationstate-2906371" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDATIONSTATE">OXIDATIONSTATE</a> of Pb is more stablethan `+4`. Hence, `PbX_(2)` is more stable than `PbX_(4)`. (ii) <a href="https://interviewquestions.tuteehub.com/tag/stability-651358" style="font-weight:bold;" target="_blank" title="Click to know more about STABILITY">STABILITY</a> of `+4` oxidationstate decreases down the groupwhile that of `+2`oxidationstate increases due to inert pair effect. (iii) Same as (ii).</body></html> | |
| 48892. |
Account for the following : (i) Be(OH)_(2) is insoluble but Ba(OH)_(2) is fairly soluble in water . (ii) Be(OH)_(2) is amphoteric while Mg(OH)_(2) is basic . |
| Answer» <html><body><p></p>Solution :(i) Be has small size , <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> ionization enthalpy and comparatively high electronegativity . Therefore , `Be(OH)_(2)` is essentially covalent and hence is insoluble in water . However , as we <a href="https://interviewquestions.tuteehub.com/tag/move-548879" style="font-weight:bold;" target="_blank" title="Click to know more about MOVE">MOVE</a> down the group from Be to Ba , the atomic size increases , ionization enthalpy and electronegativity decrease . therefore , ionic characters of their hydroxides increases down the group . Further , it has been found that with increase in size the lattice down the group from Be to Ba . In other words , `Be(OH)_(2)` is insoluble but `Ba(OH)_(2)` is <a href="https://interviewquestions.tuteehub.com/tag/fairly-2078571" style="font-weight:bold;" target="_blank" title="Click to know more about FAIRLY">FAIRLY</a> soluble in water . <br/> (ii) Because of <a href="https://interviewquestions.tuteehub.com/tag/higher-1022060" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHER">HIGHER</a> sum of `Delta_(i)H_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) + Delta_(i) H_(2)` of Be than that of Mg , the M-OH bond can break less easily in `Be(OH)_(2)` than in `Mg(OH)_(2)` . In other words , `Be(OH)_(2)` acts as a weak base even weaker than `Mg(OH)_(2)` . <br/> Further because of smaller size and higher electronegativity than that of Mg , `Be(OH)_(2)` can accept `OH^(-)` ions from alkalies to form beryllate ion but Mg`(OH)_(2)` does not . <br/> `Be(OH)_(2) + 2OH^(-) to Be(OH)_(4)^(2-) to underset("Beryllate ion")(BeO_(2)^(2-) ) + 2H_(2)O` <br/> `Mg(OH)_(2) + 2OH^(-) cancelto Mg(OH)_(4)^(2-)` <br/> Thus , `Be(OH)_(2)` acts as a weak acid but `Mg(OH)_(2)` does not . Combining both the facts , we conclude that the `Be(OH)_(2)` is amphoteric but `Mg(OH)_(2)` is basic .</body></html> | |
| 48893. |
Account for the following: (i) water is a liquid while H_(2)S is a gas (ii) NH_(3) has higher boiling point than PH_(3). |
| Answer» <html><body><p></p>Solution :(i) In case of <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a>, hydrogen bonding causes association of the `H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)O` molecules. There is no such hydrogen bonding in `H_(2)S,`that is why it is a <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a>. <br/> (ii) There is hydrogen bonding in `NH_(3)` but not in `PH_(3).`</body></html> | |
| 48894. |
Account for the following : BiH_(3) is the strongest reducing agent in Group 15 element hydrides. |
| Answer» <html><body><p></p>Solution :As we move down the <a href="https://interviewquestions.tuteehub.com/tag/group-1013370" style="font-weight:bold;" target="_blank" title="Click to know more about GROUP">GROUP</a> from N to Bi, the size of the element increases. As a result, bond <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> increases and bond strength decrease from N to Bi. In other words, Bi-<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a> bond is the weakest and hence decomposes, on heating, to liberate `H_(2)` most readily. Thus, `BiH_(3)` is the strongest reducing agent in group <a href="https://interviewquestions.tuteehub.com/tag/15-274069" style="font-weight:bold;" target="_blank" title="Click to know more about 15">15</a> element hydrides.</body></html> | |
| 48895. |
Account for the decrease in first ionization energy between phosphorous and sulphur. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/phosphorous-599815" style="font-weight:bold;" target="_blank" title="Click to know more about PHOSPHOROUS">PHOSPHOROUS</a> has a stable <a href="https://interviewquestions.tuteehub.com/tag/half-1014510" style="font-weight:bold;" target="_blank" title="Click to know more about HALF">HALF</a> filled <a href="https://interviewquestions.tuteehub.com/tag/configuration-11827" style="font-weight:bold;" target="_blank" title="Click to know more about CONFIGURATION">CONFIGURATION</a>, so its first ionization energy is <a href="https://interviewquestions.tuteehub.com/tag/higher-1022060" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHER">HIGHER</a> than sulphur. This <a href="https://interviewquestions.tuteehub.com/tag/sort-648643" style="font-weight:bold;" target="_blank" title="Click to know more about SORT">SORT</a> of trend is also observed between nitrogen and oxygen where the former has higher first ionization energy.</body></html> | |
| 48896. |
Account for following: (a) Use of DDT was banned in United States in 1973. (b) Benzylic halides show high reactivity towards S_(N)1 reaction. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) Because of chemical stability of DDT and its fat stability, it is not metabolised very <a href="https://interviewquestions.tuteehub.com/tag/rapidly-2972968" style="font-weight:bold;" target="_blank" title="Click to know more about RAPIDLY">RAPIDLY</a> by animals. Rather it gets deposited and stored in fatty tissues. This raised alarming danger due to its toxic effects. Therefore, its use has been banned in U.S.A. <br/> (b) <a href="https://interviewquestions.tuteehub.com/tag/benzylic-895241" style="font-weight:bold;" target="_blank" title="Click to know more about BENZYLIC">BENZYLIC</a> halides show high reactivity towards `S_(N)1` reactions because benzyl carbocation formed is <a href="https://interviewquestions.tuteehub.com/tag/highly-2102664" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHLY">HIGHLY</a> stable through resonance.</body></html> | |
| 48897. |
Accound for the following with ittle or no PhCH_(2)(Br)CH_(3))_(2) formed. |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C04_E01_261_S01.png" width="80%"/> <br/> This <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> proceeds <a href="https://interviewquestions.tuteehub.com/tag/via-723599" style="font-weight:bold;" target="_blank" title="Click to know more about VIA">VIA</a> free radical mechanism forming <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> free <a href="https://interviewquestions.tuteehub.com/tag/radicals-1175948" style="font-weight:bold;" target="_blank" title="Click to know more about RADICALS">RADICALS</a>, of which `2^(@)` benzylic free radical is stabilized more by resonance of phenyl ring and with <a href="https://interviewquestions.tuteehub.com/tag/hyperconjugation-13962" style="font-weight:bold;" target="_blank" title="Click to know more about HYPERCONJUGATION">HYPERCONJUGATION</a> of `-CH_(3)` group, thus resulting in the formation of `PhCH(Br)CH(CH_(3))_(2)` as the major product.</body></html> | |
| 48898. |
According to whom chemistry is the science of 100 elements ? |
| Answer» <html><body><p>Lavoisier<br/>Dalton<br/>Roald <a href="https://interviewquestions.tuteehub.com/tag/hoffman-7754708" style="font-weight:bold;" target="_blank" title="Click to know more about HOFFMAN">HOFFMAN</a><br/> Avogadro</p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>::D</body></html> | |
| 48899. |
According to which theory, NH_3 is not a base ? |
| Answer» <html><body><p>Lewis<br/>Arrhenius<br/>Bronsted-Lowry<br/>Ionization</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 48900. |
According to which law different proportion of oxygen exist in oxides of Nitrogen ? |
| Answer» <html><body><p> Law of <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> composition<br/> Law of combining weight<br/>Law of multiple proportion<br/> None of these</p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |