Explore topic-wise InterviewSolutions in Class 11.

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48751.

Additionof water to 3-methylbut-1-ene in the presence of dil. H_(2)SO_(4) gives mainly

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>-Methylbutan-1-ol<br/>3-Methylbutan-2-ol<br/>2-Methylbutan-1-ol<br/>2-Methylbutan-2-ol</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>("3-Methylbut-1-ene")(CH_(3)-underset(CH_(3))underset(|)(<a href="https://interviewquestions.tuteehub.com/tag/ch-913588" style="font-weight:bold;" target="_blank" title="Click to know more about CH">CH</a>)-CH=CH_(2))overset(H^(+))<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a>` <br/> `CH_(3)-underset((2^(@)))(underset(CH_(3))underset(|)(CH))-overset(+)(CH)=CH_(3)overset("Hydride <a href="https://interviewquestions.tuteehub.com/tag/shift-1205367" style="font-weight:bold;" target="_blank" title="Click to know more about SHIFT">SHIFT</a>")rarr` <br/> `CH_(3)-underset(3^(@))underset(CH_(3))underset(|)overset(+)(C)-CH_(2)-CH_(3)overset(OH^(-))rarrunderset("2-Methylbutan-2-ol")(CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)(C)-CH_(2)-CH_(3))`</body></html>
48752.

Addition of surface to water leads .

Answer» <html><body><p>An increase in <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> of contact<br/>An increase in surface tension<br/>A decrease in angle of contact and increase in surface tension .<br/>A decrease in angle of contact and increase in surface tension .<br/></p>Solution :Addition of <a href="https://interviewquestions.tuteehub.com/tag/soap-11667" style="font-weight:bold;" target="_blank" title="Click to know more about SOAP">SOAP</a> redues surface tension of system.</body></html>
48753.

Addition of sulphuric acid in alkene and addition of sulphuric acid in alkene with addition reaction.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Dissociation of sulphuric acid `(H_(2)SO_(4) hArr <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>^(<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a>+)O^(delta-)SO_(3)H)` fragement are `H^(delta+)` and `HSO_(4)^(-)` or `""^(-)OSO_(3)H` positive and negative radicals on `pi`-bond as per Markovnikov rule electrophilic <a href="https://interviewquestions.tuteehub.com/tag/addition-367641" style="font-weight:bold;" target="_blank" title="Click to know more about ADDITION">ADDITION</a> reaction. <br/> (i) `H_(2)SO_(4) rarr overset(+)(H)+bar(O)SO_(2)OH` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_CHE_XI_P2_C13_E01_113_S01.png" width="80%"/> <br/> (ii) Propene is reacted with`H_(2)SO_(4)` where `overset(+)(H)` is electrophilic species. More stable carbocation `CH_(3)overset(+)(C)HCH_(3)` is formed first, negative part hydrogen sulfate, is added as addition product and formed <a href="https://interviewquestions.tuteehub.com/tag/isopropyl-1052512" style="font-weight:bold;" target="_blank" title="Click to know more about ISOPROPYL">ISOPROPYL</a> hydrogen sulphare. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_CHE_XI_P2_C13_E01_113_S02.png" width="80%"/> <br/> This reaction occurs at normal temperature and ractants are added in ratio 1:1 and formation of alkyl hydrogen sulpare.</body></html>
48754.

Addition of sodium hydroxide solution to a weak acid (HA) results in a buffer of pH 6 . If ionisation constant of HA is 10^(-5) , the ratio of salt to acid concentration in the buffer solution will be

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> : <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> : <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>`<br/>`1 : 10`<br/>`5 : 4`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
48755.

Addition of phposphate and nitrate/feticlizers in to water leads to

Answer» <html><body><p>Increased <a href="https://interviewquestions.tuteehub.com/tag/growth-1013761" style="font-weight:bold;" target="_blank" title="Click to know more about GROWTH">GROWTH</a> of decomposers <br/><a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a> algal growth <br/>Increased algal growth <br/>Niutrient enrichment (eutrophication)</p>Solution :addition of phosphate and nitratefertilizers into water <a href="https://interviewquestions.tuteehub.com/tag/leads-540453" style="font-weight:bold;" target="_blank" title="Click to know more about LEADS">LEADS</a> to <a href="https://interviewquestions.tuteehub.com/tag/nutrient-1126817" style="font-weight:bold;" target="_blank" title="Click to know more about NUTRIENT">NUTRIENT</a> enrichment or eutrophication</body></html>
48756.

Addition of ozone to acetylene gives a product which is

Answer» <html><body><p>monocyclic <br/>bicyclic <br/><a href="https://interviewquestions.tuteehub.com/tag/tricyclic-2311312" style="font-weight:bold;" target="_blank" title="Click to know more about TRICYCLIC">TRICYCLIC</a> <br/>tetracyclic</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
48757.

Addition of phosphate fertilizers into water leads to

Answer» <html><body><p>Increased growth of <a href="https://interviewquestions.tuteehub.com/tag/decomposers-15861" style="font-weight:bold;" target="_blank" title="Click to know more about DECOMPOSERS">DECOMPOSERS</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a> <a href="https://interviewquestions.tuteehub.com/tag/algal-1972753" style="font-weight:bold;" target="_blank" title="Click to know more about ALGAL">ALGAL</a> growth <br/>Increased algal growth <br/>Nutrient <a href="https://interviewquestions.tuteehub.com/tag/enrichment-451938" style="font-weight:bold;" target="_blank" title="Click to know more about ENRICHMENT">ENRICHMENT</a> (eutrophication) </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>
48758.

Addition of mineral acid to an aqueous solution of borax, the following compound is formed :

Answer» <html><body><p>boron hydride<br/>pyroboric acid<br/>metaboric acid<br/>orthoboric acid</p>Solution :Orthoboric acid is formed. <br/> `Na_(2)B_(4)O_(7) +H_(2)SO_(4) rarr underset(" Orthoboric acid ") (4H_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)BO_(3)) + Na_(2)SO_(4)`</body></html>
48759.

Addition of HX on alkene proceed through formation of carbocation . This reaction is follows Markovnikov's rule. According to markovnikov's rule addition of electrophile occurs on that carbon of alkene which have more number of -H atom Ph-CH = CH_2 underset(HX)to underset("(major)")(Ph-overset(x)overset(|)CH-CH_3) + underset("(minor)")(Ph-CH_2-CH_2-X) Which of the following alkenes will give markovnikov's reaction ?

Answer» <html><body><p>`F_3 C - CH =CH_2 <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(<a href="https://interviewquestions.tuteehub.com/tag/hcl-479502" style="font-weight:bold;" target="_blank" title="Click to know more about HCL">HCL</a>)to`<br/>`H_3N^(+)-CH = CH_2 overset(HCl)to `<br/>`O_2N - CH = CH_2 overset(HBr)to`<br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E03_195_O04.png" width="30%"/> </p>Solution :A) Because `F_3C- overset(<a href="https://interviewquestions.tuteehub.com/tag/oplus-2895718" style="font-weight:bold;" target="_blank" title="Click to know more about OPLUS">OPLUS</a>)(C)H-CH_3` is unstable due to powerful - I effect of `CF_3` <a href="https://interviewquestions.tuteehub.com/tag/group-1013370" style="font-weight:bold;" target="_blank" title="Click to know more about GROUP">GROUP</a> <br/>B) `H_3^(oplus)N - CH - CH_2 overset(HCl)to H_3overset(oplus)N -CH_2 - Cl`. <br/> Because `NH_3 -CH-CH_3` unstable due to powerful - I effect of `NH_3` group <br/> C) `NO_2 - CH - CH_2 NO_2 - CH_2 - Br ` <br/> Because `NO_2 - overset(oplus)CH_2 - CH_3` is unstabledue to -I effect to `NO_2` group <br/> D) <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E03_195_S01.png" width="80%"/> <br/> is more <a href="https://interviewquestions.tuteehub.com/tag/stable-1223548" style="font-weight:bold;" target="_blank" title="Click to know more about STABLE">STABLE</a> I effect `-CH_3` groups and .9. hypen conjugative structures</body></html>
48760.

Addition of HX on alkene proceed through formation of carbocation . This reaction is follows Markovnikov's rule. According to markovnikov's rule addition of electrophile occurs on that carbon of alkene which have more number of -H atom Ph-CH = CH_2 underset(HX)to underset("(major)")(Ph-overset(x)overset(|)CH-CH_3) + underset("(minor)")(Ph-CH_2-CH_2-X) Which of the following alkenes can produce diastereomers

Answer» <html><body><p>`CH_3-CH=CH-CH_3`<br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E03_194_O02.png" width="30%"/> <br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E03_195_O03.png" width="30%"/> <br/>`CH_3-CH=CH_2` </p>Solution :Optically inactive <a href="https://interviewquestions.tuteehub.com/tag/alkene-853361" style="font-weight:bold;" target="_blank" title="Click to know more about ALKENE">ALKENE</a> does not <a href="https://interviewquestions.tuteehub.com/tag/produces-1167808" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCES">PRODUCES</a> <a href="https://interviewquestions.tuteehub.com/tag/diastereomers-16563" style="font-weight:bold;" target="_blank" title="Click to know more about DIASTEREOMERS">DIASTEREOMERS</a> on addition of HX Optically active <a href="https://interviewquestions.tuteehub.com/tag/alkenes-14874" style="font-weight:bold;" target="_blank" title="Click to know more about ALKENES">ALKENES</a> produce diastereomers if a chiral carbon in generated uring addition <br/>A) Is not optically active <br/> <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) is not optically active<br/> C) Is optically active D) Is not optically active <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E03_194_S01.png" width="80%"/></body></html>
48761.

Addition of HOCl to allyl alcohol gives

Answer» <html><body><p>2-Chloropropane-1, 3-diol<br/>3-Chloropropane-1, 2-diol<br/>2, 3-Dichloropropanol<br/>1, 2,3-Trichloropropane</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/DIN_OBJ_CHM_V02_C6_1_E01_232_S01.png" width="80%"/></body></html>
48762.

Addition of HBr to propene yields 2-bromopropane, while inpresence of benzoyl peroxide, the same reaction yields 1-bromopropane. Explain and give mechanism.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Addition of HBr to propene is an ionic electrophilic addition <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> in which the electrophile, i.e., `H^+` first <a href="https://interviewquestions.tuteehub.com/tag/adds-849677" style="font-weight:bold;" target="_blank" title="Click to know more about ADDS">ADDS</a> to give a more stable `2^@` carbocation. In the 2nd second, the carbocation is rapidly attacked by the nucleophile `Br^-` <a href="https://interviewquestions.tuteehub.com/tag/ion-1051153" style="font-weight:bold;" target="_blank" title="Click to know more about ION">ION</a> to give 2-bromopropane <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C13_E08_016_S01.png" width="80%"/> <br/> In presence of benzoyl peroxide , the reaction is still electrophilic but the electrophile here is a `oversetdot(Br)` free radical which is obtained by the action of benzoyl peroxide on HBr <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C13_E08_016_S02.png" width="80%"/> <br/> In the first step, `oversetdot(Br)` radical adds to propene in such a way as to generate a more stable `2^@` radical . In the second step, the free radical thus obtained rapidly abstracts a hydrogen atom from HBr to give 1-bromopropane.<br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C13_E08_016_S03.png" width="80%"/> <br/> it is evident that although both reactions (i.e., in presence or absence of benzoyl peroxide ) are electrophilic addition but it is due to different order or sequence of addition of H and Br atoms which gives different <a href="https://interviewquestions.tuteehub.com/tag/products-18828" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCTS">PRODUCTS</a>.</body></html>
48763.

Addition of HBr to propene yields 2-bromopropane, while in the presence of benzoyl peroxide, the same reaction yields 1-bromopropane. Explain and give mechanism.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/addition-367641" style="font-weight:bold;" target="_blank" title="Click to know more about ADDITION">ADDITION</a> to <a href="https://interviewquestions.tuteehub.com/tag/unsymmetrical-7721365" style="font-weight:bold;" target="_blank" title="Click to know more about UNSYMMETRICAL">UNSYMMETRICAL</a> <a href="https://interviewquestions.tuteehub.com/tag/alkenes-14874" style="font-weight:bold;" target="_blank" title="Click to know more about ALKENES">ALKENES</a>.</body></html>
48764.

Addition of HBr to propene yields 2-bromo-propene, while in the presence of benzoyl peroxide, the same reaction yields 1-bromo-propane. Explain and give mechanism.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) Addition to <a href="https://interviewquestions.tuteehub.com/tag/hbr-479388" style="font-weight:bold;" target="_blank" title="Click to know more about HBR">HBR</a> to propene, yields 2-bromo-propane and it is electrophilic addition reaction. <br/> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) Addition to Hbr to propene in <a href="https://interviewquestions.tuteehub.com/tag/presence-25557" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENCE">PRESENCE</a> of peroxide, forms 1-bromopropane, it is free-radical addition reaction.</body></html>
48765.

Addition of HBr to propene gives 2 - bromo propane, this reaction is intiated by

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>^(o+)`&lt;<a href="https://interviewquestions.tuteehub.com/tag/br-390993" style="font-weight:bold;" target="_blank" title="Click to know more about BR">BR</a>&gt;`Br^(-)`<br/>`Br`<br/>`Br^(o+)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
48766.

Addition of HBr to 2-butene gives two products while that of HBr to 1-buane gives three products . Explain why ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Addition of HBr to 2-butene gives 2-bromobutane which being a chiral molecule <a href="https://interviewquestions.tuteehub.com/tag/exists-979838" style="font-weight:bold;" target="_blank" title="Click to know more about EXISTS">EXISTS</a> as two <a href="https://interviewquestions.tuteehub.com/tag/stereoisomers-13555" style="font-weight:bold;" target="_blank" title="Click to know more about STEREOISOMERS">STEREOISOMERS</a> ( I and II) .&lt;<a href="https://interviewquestions.tuteehub.com/tag/br-390993" style="font-weight:bold;" target="_blank" title="Click to know more about BR">BR</a>&gt; <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C13_E18_008_S01.png" width="80%"/> <br/> In contrast, 1-butene is an unsymmetrical molecule, therefore , it gives two products, i.e., 2-bromobutane (major product ) and 1-bromobutane (minor product). Since 2-bromobutane is a chiral molecule, it exists as two stereoisomers (I+II) as shown below above . While 1-bromobutane being a achiral molecule exists as such (III). <br/> `underset"1-Butene"(CH_3-CH_2-CH=CH_2) overset"HBr"to underset"I+II"(CH_3-CH_2-undersetunderset(Br)|overset**CH-CH_3)+underset"III"(CH_3CH_2CH_2CH_2-Br)` <br/> Thus, in all three products (I, II and III ) are <a href="https://interviewquestions.tuteehub.com/tag/formed-464209" style="font-weight:bold;" target="_blank" title="Click to know more about FORMED">FORMED</a>.</body></html>
48767.

Addition of HBr to 2-pentene gives

Answer» <html><body><p>2-bromopentane only <br/>3-bromopentane only <br/>2-bromopentane and 3-bromopentane<br/>1-bromopentane and 3-bromopentane</p>Solution :Addition of a proton to 2-pentene can give two <a href="https://interviewquestions.tuteehub.com/tag/carbocations-19004" style="font-weight:bold;" target="_blank" title="Click to know more about CARBOCATIONS">CARBOCATIONS</a> (I and II) <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_CHE_02_XI_C13_E20_060_S01.png" width="80%"/> <br/>which are almost equally stable since <a href="https://interviewquestions.tuteehub.com/tag/carbocation-909158" style="font-weight:bold;" target="_blank" title="Click to know more about CARBOCATION">CARBOCATION</a> (I) is stabilized by five (3+2) <a href="https://interviewquestions.tuteehub.com/tag/hyperconjugation-13962" style="font-weight:bold;" target="_blank" title="Click to know more about HYPERCONJUGATION">HYPERCONJUGATION</a> structures and carbocation (II) is stabilized by <a href="https://interviewquestions.tuteehub.com/tag/four-464592" style="font-weight:bold;" target="_blank" title="Click to know more about FOUR">FOUR</a> (2+2) hyperconjugation structures . Therefore , nucleophilic <a href="https://interviewquestions.tuteehub.com/tag/attack-887517" style="font-weight:bold;" target="_blank" title="Click to know more about ATTACK">ATTACK</a> on these gives the coresponding bromoalkanes in almost equal amounts . Of course , the yield of 2-bromopentane will be slightly more than that of 3-bromopentane.</body></html>
48768.

Addition of H_(2)O into alkene.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`H_(2)O` means `overset(+delta)(H) overset(-delta)(OH)`. Alkene reacts with `H_(2)SO_(4)`, an addition of `H_(2)O, -OH` (alcohol) is formed. <br/> This reaction is addition of `H_(2)O` or dydrolysis of alkene or <a href="https://interviewquestions.tuteehub.com/tag/formation-996531" style="font-weight:bold;" target="_blank" title="Click to know more about FORMATION">FORMATION</a> of alocohol from alkene. This reaction is electrophilic addition reaction. markonikov rule is applied. <br/>`underset("Ethene")(CH_(2)=CH_(2))+H_(2)O underset((H_(2)SO_(4)))overset(100^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> H^(+), Delta)rarr underset("<a href="https://interviewquestions.tuteehub.com/tag/ethanol-975823" style="font-weight:bold;" target="_blank" title="Click to know more about ETHANOL">ETHANOL</a>")(CH_(3)-CH_(2)OH)` <br/> `underset("<a href="https://interviewquestions.tuteehub.com/tag/propene-1169814" style="font-weight:bold;" target="_blank" title="Click to know more about PROPENE">PROPENE</a>")(CH_(3)CH=CH_(2))+H_(2)O underset(H_(2)SO_(4))overset(373 K H^(+))rarr underset("Propane-2-ol")(CH_(3)-underset(OH)underset(|)(CH)-CH_(3))` <br/> `underset("2-Methyl prepene")(CH_(3)-underset(CH_(3))underset(|)(C)=CH_(2)+H_(2)O)underset(H_(2)SO_(4))overset(H^(+))rarr underset("2-Methyl prepane-2-ol")(CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)(C)-CH_(3))`</body></html>
48769.

Addition of H_2 to 2-butyne in presence of Lindlar's catalyst . Gives cis-2-butene while with Na/in liq. NH_3 gives trans-2-butene.Why so ? Explain.

Answer» <html><body><p></p>Solution :In presence of Lindlar's catalyst (Pd deposited over `BaSO_4` and partially <a href="https://interviewquestions.tuteehub.com/tag/poisoned-7328856" style="font-weight:bold;" target="_blank" title="Click to know more about POISONED">POISONED</a> by addition of S or quinoline), `H_2` gets first absorbed over the catalyst as H atoms and then transferred to the same face of 2-butyne giving cis-2-butene. <br/> <a href="https://interviewquestions.tuteehub.com/tag/however-1032379" style="font-weight:bold;" target="_blank" title="Click to know more about HOWEVER">HOWEVER</a>, in <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> of Na in liquid `NH_3`, (Birch <a href="https://interviewquestions.tuteehub.com/tag/reduction-621019" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCTION">REDUCTION</a>), the reduction <a href="https://interviewquestions.tuteehub.com/tag/occurs-1127848" style="font-weight:bold;" target="_blank" title="Click to know more about OCCURS">OCCURS</a> through two electron transfers and two proton transfer giving trans-2-butene .</body></html>
48770.

Addition of catalyst in a system

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> equilibrium <a href="https://interviewquestions.tuteehub.com/tag/concentrations-928106" style="font-weight:bold;" target="_blank" title="Click to know more about CONCENTRATIONS">CONCENTRATIONS</a><br/>No <a href="https://interviewquestions.tuteehub.com/tag/effect-966056" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECT">EFFECT</a> on equilibrium concentrations<br/>Decreases equilibrium concentrations<br/>Increases rate of forward <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> and decreases rate of <a href="https://interviewquestions.tuteehub.com/tag/backward-391901" style="font-weight:bold;" target="_blank" title="Click to know more about BACKWARD">BACKWARD</a> reaction.</p>Solution :Catalyst does not effect on equilibrium concentrations.</body></html>
48771.

Addition of bromine to cis-3 hexene gives

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/racemic-2969368" style="font-weight:bold;" target="_blank" title="Click to know more about RACEMIC">RACEMIC</a> dibromide<br/>a <a href="https://interviewquestions.tuteehub.com/tag/mixture-1098735" style="font-weight:bold;" target="_blank" title="Click to know more about MIXTURE">MIXTURE</a> of <a href="https://interviewquestions.tuteehub.com/tag/diastereomeric-2576949" style="font-weight:bold;" target="_blank" title="Click to know more about DIASTEREOMERIC">DIASTEREOMERIC</a> dibromides<br/>optically <a href="https://interviewquestions.tuteehub.com/tag/active-367234" style="font-weight:bold;" target="_blank" title="Click to know more about ACTIVE">ACTIVE</a> dibromide<br/>meso dibromide</p>Answer :A</body></html>
48772.

Addition of bromine to buta-1,3- diene gives

Answer» <html><body><p>1,2- <a href="https://interviewquestions.tuteehub.com/tag/addition-367641" style="font-weight:bold;" target="_blank" title="Click to know more about ADDITION">ADDITION</a> product only<br/> <a href="https://interviewquestions.tuteehub.com/tag/three-708969" style="font-weight:bold;" target="_blank" title="Click to know more about THREE">THREE</a> carbon atoms <br/>1,4-addition product only<br/> <a href="https://interviewquestions.tuteehub.com/tag/six-631160" style="font-weight:bold;" target="_blank" title="Click to know more about SIX">SIX</a> carbon atoms </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_TRG_AO_CHE_XI_V01_D_C04_E02_183_S01.png" width="80%"/></body></html>
48773.

Addition of BrC CI_(3) to propene in the presence of peroxides gives 3-bromo-1, 1, 1-trichloro-2-methylpropane.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :False: `CH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)<a href="https://interviewquestions.tuteehub.com/tag/ch-913588" style="font-weight:bold;" target="_blank" title="Click to know more about CH">CH</a>=CH_(2) underset(ROOR)overset(BrC Cl_(3)) underset("2-Bromo-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>, 1, 1-trichlorobutane")(CH_(3)underset(<a href="https://interviewquestions.tuteehub.com/tag/br-390993" style="font-weight:bold;" target="_blank" title="Click to know more about BR">BR</a>)underset(|)CH-CH_(2)C Cl_(3))`</body></html>
48774.

Addition of Br, takes place redily with

Answer» <html><body><p>`CH_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=CH_(2)` <br/>`CH_(3)-<a href="https://interviewquestions.tuteehub.com/tag/ch-913588" style="font-weight:bold;" target="_blank" title="Click to know more about CH">CH</a>=CH_2`<br/>`CH_(3)-CH=CH-CH_(3)` <br/>`CH_(3)-underset(CH_3)underset(|)(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) = CH -CH_3` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>
48775.

Addition of I mole of N_(2) is made to an equilibrium mixture of PCl_(5) in a piston fittcd cylinder. Which of the following is correct.

Answer» <html><body><p>No effect on equilibrium constant `K_c` or `K_p`<br/>The degree of dissociation of `PCI_5` decreases<br/>The <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of <a href="https://interviewquestions.tuteehub.com/tag/container-20566" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAINER">CONTAINER</a> does not change<br/>No effect on equilibrium concentration</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/inert-1043160" style="font-weight:bold;" target="_blank" title="Click to know more about INERT">INERT</a> gas does not <a href="https://interviewquestions.tuteehub.com/tag/affect-851195" style="font-weight:bold;" target="_blank" title="Click to know more about AFFECT">AFFECT</a> `K_(p)` or `K_(C)` volume changes equilibrium shifts</body></html>
48776.

Addition of 1 equivalent of HCL to CH_(2)=C=CH_(2) gives

Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C03_E01_195_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C03_E01_195_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C03_E01_195_O03.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XI_V06_C03_E01_195_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
48777.

Add : (i) 93.4 + 4.03 (ii) 77.86, 14.12 and 5.7

Answer» <html><body><p><br/></p>Solution :(i) Add : `{:(93.4),(4.03),(bar(97.43)):}` <br/> The <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> is 97.4 <br/> (Digit 3 is to be <a href="https://interviewquestions.tuteehub.com/tag/deleted-7261501" style="font-weight:bold;" target="_blank" title="Click to know more about DELETED">DELETED</a>) <br/> (ii) Add : `{:(77.86),(14.12),(" 5.7"),(bar(97.68)):}` <br/> The correct answer is 97.7<br/> (Digit <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> has been <a href="https://interviewquestions.tuteehub.com/tag/rounded-2999253" style="font-weight:bold;" target="_blank" title="Click to know more about ROUNDED">ROUNDED</a> off to 7)</body></html>
48778.

Add 6.65xx10^(4) and 8.95xx10^(3).

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Exponent is <a href="https://interviewquestions.tuteehub.com/tag/made-3718337" style="font-weight:bold;" target="_blank" title="Click to know more about MADE">MADE</a> same for the both <a href="https://interviewquestions.tuteehub.com/tag/numbers-22758" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBERS">NUMBERS</a> <br/> `6.65 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(4) +0.895 xx 10^(4)=7.545 xx 10^(4)`</body></html>
48779.

Add 18.11, 12.0 and 2.021 and report the result in significant figures.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :18.11+12.0+2.021 = 32.131 <br/> Here, 12.0 has <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> digit after the decimal <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> and the result should be <a href="https://interviewquestions.tuteehub.com/tag/reported-2248280" style="font-weight:bold;" target="_blank" title="Click to know more about REPORTED">REPORTED</a> only up to one digit after decimal point. Hence round off the result to 32.1 <br/> <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of significant figures is 3</body></html>
48780.

Adam's catalyst is

Answer» <html><body><p>Platinum<br/>Iron<br/>Molybdenum<br/>Nickel</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/generally-471963" style="font-weight:bold;" target="_blank" title="Click to know more about GENERALLY">GENERALLY</a> <a href="https://interviewquestions.tuteehub.com/tag/transition-712134" style="font-weight:bold;" target="_blank" title="Click to know more about TRANSITION">TRANSITION</a> elements acts as <a href="https://interviewquestions.tuteehub.com/tag/catalysts-910647" style="font-weight:bold;" target="_blank" title="Click to know more about CATALYSTS">CATALYSTS</a>. Adam's catalyst is <a href="https://interviewquestions.tuteehub.com/tag/another-876628" style="font-weight:bold;" target="_blank" title="Click to know more about ANOTHER">ANOTHER</a> name of platinum.</body></html>
48781.

Adamantive is the crystalline form of

Answer» <html><body><p>Aluminium<br/><a href="https://interviewquestions.tuteehub.com/tag/boron-400820" style="font-weight:bold;" target="_blank" title="Click to know more about BORON">BORON</a><br/>Thallium<br/>Beryllium</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/adamantive-1968172" style="font-weight:bold;" target="_blank" title="Click to know more about ADAMANTIVE">ADAMANTIVE</a> is the <a href="https://interviewquestions.tuteehub.com/tag/crystalline-940053" style="font-weight:bold;" target="_blank" title="Click to know more about CRYSTALLINE">CRYSTALLINE</a> <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> of boron.</body></html>
48782.

Acyl halide is formed by reacting PCl_(5) with

Answer» <html><body><p>Alcohol<br/>Ester<br/>Amide<br/>Both carboxylic <a href="https://interviewquestions.tuteehub.com/tag/acids-366963" style="font-weight:bold;" target="_blank" title="Click to know more about ACIDS">ACIDS</a> as well as esters</p>Solution :The answer are based upon the <a href="https://interviewquestions.tuteehub.com/tag/reactions-20919" style="font-weight:bold;" target="_blank" title="Click to know more about REACTIONS">REACTIONS</a> <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> in Comprehensve <a href="https://interviewquestions.tuteehub.com/tag/review-1188334" style="font-weight:bold;" target="_blank" title="Click to know more about REVIEW">REVIEW</a>.</body></html>
48783.

Active species involved in the process C_6H_6 rarr C_6 H_5SO_3H is

Answer» <html><body><p>`SO_3`<br/>`HSO_4^(-)` <br/>`SO_3^(+)`<br/>`SO_2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
48784.

Active mass of 5.6 lit N_2 at STP

Answer» <html><body><p>22.4M<br/> 0.25M<br/>`1/(22.4)M`<br/> 4M</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/active-367234" style="font-weight:bold;" target="_blank" title="Click to know more about ACTIVE">ACTIVE</a> mass = `(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>//"(<a href="https://interviewquestions.tuteehub.com/tag/lit-537267" style="font-weight:bold;" target="_blank" title="Click to know more about LIT">LIT</a>)")=((5.6)/(22.4))/(5.6)=(1)/(22.4)M`</body></html>
48785.

Active mass of 0.64g SO_(2) in 10 lit vessel is

Answer» <html><body><p>`10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` M<br/>`10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` M<br/>`10^(-1)` M<br/>0.64g</p>Solution :Active mass = `(n)/(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>//"(<a href="https://interviewquestions.tuteehub.com/tag/lit-537267" style="font-weight:bold;" target="_blank" title="Click to know more about LIT">LIT</a>)")`</body></html>
48786.

Action of water or dilute mineral acids on metals can give.....

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mono-11612" style="font-weight:bold;" target="_blank" title="Click to know more about MONO">MONO</a> hydrogen<br/>Tritium<br/>Di hydrogen<br/>Trihydrogen</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
48787.

Action of nitrous acid on ethylamine gives

Answer» <html><body><p>`C_(2)H_(6)`<br/>`C_(2)H_(5)OH`<br/>`C_(2)H_(5)OH` and `C_(2)H_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`<br/>`C_(2)H_(5)OH` and `NH_(3)`</p>Solution :`C_(2)H_(5)-NH_(2)<a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(HNO_(2))rarrC_(2)H_(5)OH+N_(2)+H_(2)O`</body></html>
48788.

Action of caustic acid soda on aluminium hydroxide gives a compound having formula

Answer» <html><body><p>`Al_(2)(OH)_(4)`<br/>`Na_(2)Al(OH)_(4)`<br/>`NaAlO_(2)`<br/>`Na_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)AlO_(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`underset("<a href="https://interviewquestions.tuteehub.com/tag/caustic-7374706" style="font-weight:bold;" target="_blank" title="Click to know more about CAUSTIC">CAUSTIC</a> soda")(<a href="https://interviewquestions.tuteehub.com/tag/naoh-572531" style="font-weight:bold;" target="_blank" title="Click to know more about NAOH">NAOH</a>) + Al(OH)_(3) rarr underset("Sod. Metaaluminate")(NaAlO_(2)+2H_(2)O)`</body></html>
48789.

Action of acetylene on dilute H_(2)SO_(4)gives

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/acetic-1967065" style="font-weight:bold;" target="_blank" title="Click to know more about ACETIC">ACETIC</a> acid<br/>Acetone <br/><a href="https://interviewquestions.tuteehub.com/tag/acetaldehyde-366764" style="font-weight:bold;" target="_blank" title="Click to know more about ACETALDEHYDE">ACETALDEHYDE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/ethyl-976035" style="font-weight:bold;" target="_blank" title="Click to know more about ETHYL">ETHYL</a> alcohol</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
48790.

Action of a heterogeneous catalyst depends upon

Answer» <html><body><p>mass<br/>solubility<br/><a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> <a href="https://interviewquestions.tuteehub.com/tag/size-1211196" style="font-weight:bold;" target="_blank" title="Click to know more about SIZE">SIZE</a><br/>none.</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/action-2544" style="font-weight:bold;" target="_blank" title="Click to know more about ACTION">ACTION</a> of heterogeneous <a href="https://interviewquestions.tuteehub.com/tag/catalyst-21033" style="font-weight:bold;" target="_blank" title="Click to know more about CATALYST">CATALYST</a> <a href="https://interviewquestions.tuteehub.com/tag/depends-948548" style="font-weight:bold;" target="_blank" title="Click to know more about DEPENDS">DEPENDS</a> upon particle size.</body></html>
48791.

Across theperiod , Ionisation energy _________

Answer» <html><body><p>increases<br/>decreases<br/>does not very<br/>First decreases and then increases</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/across-367070" style="font-weight:bold;" target="_blank" title="Click to know more about ACROSS">ACROSS</a> the <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> , <a href="https://interviewquestions.tuteehub.com/tag/ionisation-1051250" style="font-weight:bold;" target="_blank" title="Click to know more about IONISATION">IONISATION</a> <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> is increases and down the group , Ionisation energy is and down the group ,Ionisation energy is decreases.</body></html>
48792.

Acidity or alkalinity of a solution depend upon the concentration of hydrogen ion relative to that of hydroxyl ions. The product of hydrogen ion & hydroxyl ion concentration is given by K_(w) = [H^(+)][OH^(-)] the valueof which depends only on the temperature & not on the individual ionic concentration. If the concentratoin of hydrogen ions exceeds that of the hydroxyl ions, the solution is said to be acidic, whereas, if concentrations of hydroxyl ion exceeds that of the hydrogen ions, the solution is said to be alkaline. The pH corresponding to the acidic and alkaline solutions at 25^(@)C will be less than and greter than seven, respectively. To confirm the above facts 0.5 M CH_(3)COOH is taken fro the experiments. [Given : K_(a) of acetic acid = 1.8 xx 10^(-5)] To what volume at 25^(@)C must 1 dm^(3) of this solution be diluted in order to double the pH

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>.37 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>) <a href="https://interviewquestions.tuteehub.com/tag/dm-432223" style="font-weight:bold;" target="_blank" title="Click to know more about DM">DM</a>^(3)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> xx 10^(3) dm^(3)`<br/>`1.68 xx 10^(4) dm^(3)`<br/>`3.18 xx 10^(3) dm^(3)`</p>Solution :`M_(1)V_(1) = M_(2)V_(2)` <br/> Amount of water to be added `= V_(2) - V_(1)`</body></html>
48793.

Acidity or alkalinity of a solution depend upon the concentration of hydrogen ion relative to that of hydroxyl ions. The product of hydrogen ion & hydroxyl ion concentration is given by K_(w) = [H^(+)][OH^(-)] the valueof which depends only on the temperature & not on the individual ionic concentration. If the concentratoin of hydrogen ions exceeds that of the hydroxyl ions, the solution is said to be acidic, whereas, if concentrations of hydroxyl ion exceeds that of the hydrogen ions, the solution is said to be alkaline. The pH corresponding to the acidic and alkaline solutions at 25^(@)C will be less than and greter than seven, respectively. To confirm the above facts 0.5 M CH_(3)COOH is taken fro the experiments. [Given : K_(a) of acetic acid = 1.8 xx 10^(-5)] pH of the solution will be:-

Answer» <html><body><p>`2.52`<br/>`2.22`<br/>`5`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>.92`</p>Solution :`[H^(+)] = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((k_(a)c))` <br/> `k_(a) = 1.8 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-5)` <br/> `c = 5 xx 10^(-1) M` <br/> `:. [H^(+)] = sqrt(1.8 xx 10^(-5) xx 5 xx 10^(-2)) = sqrt(9 xx 10^(-6)) = 3 xx 10^(-3)`</body></html>
48794.

Acidity of phenol was explained by .....

Answer» <html><body><p> I <a href="https://interviewquestions.tuteehub.com/tag/effect-966056" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECT">EFFECT</a> <br/> E-effect<br/>R-effect <br/><a href="https://interviewquestions.tuteehub.com/tag/hyper-493279" style="font-weight:bold;" target="_blank" title="Click to know more about HYPER">HYPER</a> <a href="https://interviewquestions.tuteehub.com/tag/conjugating-7673120" style="font-weight:bold;" target="_blank" title="Click to know more about CONJUGATING">CONJUGATING</a> effect </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :R-effect</body></html>
48795.

Acidity of phenol was explained by .............

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> -<a href="https://interviewquestions.tuteehub.com/tag/effect-966056" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECT">EFFECT</a></body></html>
48796.

Acidity of BF_3 can be explained on the basis of which of the following concepts ?

Answer» <html><body><p>Arrhenius concept<br/>Bronsted Lowry concept<br/>Lewis concept<br/>Bronsted Lowry as well as Lewis concept.</p>Solution :Lewis in 1923 <a href="https://interviewquestions.tuteehub.com/tag/defined-947013" style="font-weight:bold;" target="_blank" title="Click to know more about DEFINED">DEFINED</a> an acid as is the substance which accepts an electron <a href="https://interviewquestions.tuteehub.com/tag/pair-1145723" style="font-weight:bold;" target="_blank" title="Click to know more about PAIR">PAIR</a> and <a href="https://interviewquestions.tuteehub.com/tag/base-892693" style="font-weight:bold;" target="_blank" title="Click to know more about BASE">BASE</a> which donates an electron pair. As `BF_3` is an electron <a href="https://interviewquestions.tuteehub.com/tag/deficient-7361123" style="font-weight:bold;" target="_blank" title="Click to know more about DEFICIENT">DEFICIENT</a> <a href="https://interviewquestions.tuteehub.com/tag/compound-926863" style="font-weight:bold;" target="_blank" title="Click to know more about COMPOUND">COMPOUND</a>, hence, it is a Lewis acid.</body></html>
48797.

Acidity of BF_(3) can be explained on the basis of which of the following concepts?

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/arrhenius-382100" style="font-weight:bold;" target="_blank" title="Click to know more about ARRHENIUS">ARRHENIUS</a> concept<br/>Bronsted Lowry concept<br/>Lewis concept<br/>Bronsted Lowry as <a href="https://interviewquestions.tuteehub.com/tag/well-734398" style="font-weight:bold;" target="_blank" title="Click to know more about WELL">WELL</a> as Lewis concept.</p>Solution :`BF_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` is electron deficient compound and <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> is a Lawis <a href="https://interviewquestions.tuteehub.com/tag/acid-847491" style="font-weight:bold;" target="_blank" title="Click to know more about ACID">ACID</a>.</body></html>
48798.

Acidity of acetylene, water and ammonia decreases in the order _______

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> , <a href="https://interviewquestions.tuteehub.com/tag/acetylene-847427" style="font-weight:bold;" target="_blank" title="Click to know more about ACETYLENE">ACETYLENE</a> , <a href="https://interviewquestions.tuteehub.com/tag/ammonia-859284" style="font-weight:bold;" target="_blank" title="Click to know more about AMMONIA">AMMONIA</a></body></html>
48799.

Acidified solution of chromic acid on treatment with H_2O_2 yields.

Answer» <html><body><p>`CrO_3+H_2O+O_2`<br/>`Cr_2O_3+H_2O+O_2`<br/>`CrO_5+H_2O`<br/>`H_2O_7+H_2O+O_2` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
48800.

Acidified KMnO_(4) oxidizes acid to CO_(2). What is the volume ( in litre) of 10^(-4) M KMnO_(4) required to completely oxidize 0.5 litre of 10^(-2) M oxalic acid in acid medium ?

Answer» <html><body><p>125<br/>1250<br/>200<br/>20</p>Solution :`2KMnO_(4)+3H_(2)SO_(4)+5{:(COOH,),(|"",),(COOH,):}toK_(2)SO_(4)+2MnSO_(4)+10CO_(2)+8H_(2)O` <br/> `(M_(1)V_(1))/(n_(1))(KMnO_(4))=(M_(2)V_(2))/(n_(2)){:((COOH,),(|"",),(COOH,)):}` <br/> `(10^(-4)xxV_(1))/(2)=(10^(-2)xx0.5)/(5)` <br/> `V_(1)=20 <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>`</body></html>