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The base OH-exactly neutralises mole of H+ion, for example 1 mol of OH-will neutralise1 mol of H+ion.

So as per questionnaire 2 moles of H+ion from H2SO4will reacts with 2 moles of OH-for neutralisation.2 moles of NaOH

no. c is the answer I guess

methane is not greenhouse gas

Law of Reciprocal Proportions is illustrated here.

The amount of Sulphur and Oxygen that react with 6 g of carbon are in ratio 32:16= 2:1

Similarly, the other two ratio can be expressed in terms of whole numbers.

Varioustypes ofseparationprocessesare:

Crystallization.

Filtration.

Decantation.

Sublimation.

Evaporation.

Simple distillation.

Fractional distillation.

Chromatography.

Aseparationprocess is a method that converts a mixture or solution ofchemicalsubstances into two or more distinct product mixtures. At least one of results ofthe separationis enriched in one or more ofthesource mixture's constituents.

Adsorption, adhesion of atoms, ions or molecules of gas, liquid, or dissolved solids to a surface

Centrifugationandcyclonic separation, separates based on density differences

Chelation

Methods of Expressing Concentration of Solutions

Percentage by weight (w / w %)

Percentage by volume (V / V%)

Weight by volume (w / v%)

Mole fraction (x)

Parts per million (ppm)

Molarity (M)

Molality (m)

Normality (N)

Formality (F)

Demal (D)

Molecular mass of sugarcane(C6H22O11)=342g1 mole of C6H22O11=342g342g of sugar cane contains 6.023x1023 moleculesthen, 34.2g sugar cane contains 6.023x1022 molecules

19x²=100²-90² then find the value x

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no answer this question

Pc.Vc/RTc = 3/8

=> PcVc = 3RTc/8

option B. because , of all the mentioned , O atom will have least mass that is 8gm.

and moles = m/M , but m is constant = 1gm

so atoms are inversely proportional to M.

no. of atoms in a sample of equal mass. is inversely proportional to the molecular mass.

so, here molecular mass of O is least.

so, Option 1. is correct.

edit.: If its 1 gm of O.

can you explain

Crop only the question that you want a solution for. We will not be able to provide solutions to multiple questions.

since the pic is blurr I am sending this in parts

2g of helium gas = 2/4 = 0.5 mole of He

1 mole of Helium occupies = 22.4 L

therefore, 2g of helium gas occupies =0.5*22.4 =11.2L

11.2L is the correct answer bro

Volume at STP of one more is 22.4 l, and the volume at NTP of one mole is 24 l.

As per the Charles law, the formula is V1 / T1 = V2 / T2.

When 24 l has 1 mole then 1 l will have 1 / 24 moles which is equal to 0.04 moles.

And the molar mass of oxygen comes to 32 g.

You could use the formula pV=nRT

Let the volume of both the solution is 1 L.

Total volume of the mixture after mixing = 2L

Number of moles in 1L of NaCl solution = 0.2

Number of moles in 1L of AgNO3solution = 0.1

In solution

[NO3-]= [AgNO3]= 0.1

After mixing

[NO3-] = 0.1/2

0.05M

option b

the compound having highest number of moles will contain higher number of molecules

so, 2.8gm CO has moles = 2.8/28 = 0.1and 1.7gm NH3 has moles = 1.7/17= 0.13.2 gm of CH4 has moles ,= 3.2/16 = 0.2

so, option 2 is the answer.

(1)2.8/12+16=.1 and (2)3.2/16 =.2 and (3) 1.7/17=.1and(4) 3.2/64=.05 so (2) will be correct

let the molar mass of A be x and B be y

so, ATQ 0.05*(3x+2y) = 9=> 3x+2y = 180.......(1)

and 0.1*(x+2y) = 10=> x+2y = 100......(2)

now subtracting 2 from 1 => 3x -x = 180-100=> 2x = 80. , so x = 80/2 = 40

and hence y = (100-40)/2 = 30..

so , option 3.

let M1 be the molarity of glucose. and M2 be the molarity for Cane -sugar . respectively. Of equal volumes would be mixed then, M1V + M2V = M(2V) M = (M1+M2)/2 would be the new concentration. From first soln. 1.20=M1ST or M1 = 1.20/ST similarly M2 = 2.5/ST Put it in M. then apply for mixed soln. O.P = 1*M*S*T S*T would be canceled out. O.P=3.7/(2*ST) *ST=3.7/2=1.85atm

Z=PV/RT

Z=50×250/8.314×300 Z=5

Z>1 i.e. +ive deviation

E = (-13.6xZ2) / n2eV

where, n = number of orbit = 1

Z = atomic number = 2 (for He)

E = (-13.6x22) / 12

E = (-13.6x4) = -54.4 eV

Amylose instarchis responsible for the formation of a deepbluecolor in the presence ofiodine. In theIodinetest ,Iodinedissolved in aqueous solution of Potassium Iodide (KI) reacts withstarchproducing a bluish colour.

it turns blue black on reacting with starch

starch is the answer for your question

Iodinedissolved in aqueous solution of PotassiumIodide(KI)reactswith starch producing a bluish colour.

The Oxide that forms the salt and the water by reacting with both the acids and the bases are called as the Amphoteric Oxides.

There are three Amphoteric Oxide. They are1. Zinc Oxide (ZnO).2. Lead Oxide (PbO).3. Aluminium Oxide (Al2O3).

Rate at 50°C/(Rate at T1°C)

= (2)^{ΔT/T1}

= (2)^50/10

= 2^5

The correctoption is B

Chemical equilibrium is the required system

Kohlrausch's law statesthat the equivalent conductivity of an electrolyte at infinite dilution is equal to the sum of the conductances of the anions and cations. If a salt is dissolved in water, the conductivity of the solution is the sum of the conductances of the anions and cations.

APPLICATION Determination of the degree of ionisation of a weak electrolyte: TheKohlrausch's lawcan be used for determining the degree of ionisation of a weak electrolyte at any concentration.

X-------YThe conversion follows second order equationrate=k[X]^2If the concentration of X is increased 3 times then the rate of formationR=k(3X)^2=9K[X]^2Thus the final rate =9 times the initian rateis increasedX^2 times that is 9 times.

Order will be 2as when doubled it became four times hence power is 2

OH- = Hydroxyl ion

H+ = Hydrogen ion

When the Hydrogen atom loses an electron all that is left is a proton. It becomes the positively charged hydrogen ion known as H+. This is the form of Hydrogen that produces the ATP enzyme that powers our cells and mitochondria.

The H+ hydrogen ion is the basis of the pH scale.

Give reason -ammonia is a base but does not contain hydroxyl group. Accepted Answer:Ammonia(NH3) is a weakbase, whichdoes nothave hydroxyl groupin its formulabutit gives OH-ions when it reacts with water.

Ammoniainstead ofnothavinghydroxyl groupis abasebecause it forms OH- ions when added to water as it ionises to form ammonium ions and hydroxide ions after forming ammonium hydroxide when mixed in water.Ammonia is a base but doesn't containanyhydroxyl groupbecause it forms OH- ions when it is added to water.

An object that occupies space and have mass is called a matter

The emission spectrum of atomic hydrogen is divided into a number of spectral series, with wavelengths given by the Rydberg formula. These observed spectral lines are due to the electron making transitions between two energy levels in an atom. The classification of the series by the Rydberg formula was important in the development of quantum mechanics. The spectral series are important in astronomical spectroscopy for detecting the presence of hydrogen and calculating.

Lyman series (n′ = 1)The series is named after its discoverer, Theodore Lyman, who discovered the spectral lines from 1906–1914. All the wavelengths in the Lyman series are in the ultraviolet band.

Balmer series (n′ = 2)Named after Johann Balmer, who discovered the Balmer formula, an empirical equation to predict the Balmer series, in 1885. Balmer lines are historically referred to as "H-alpha", "H-beta", "H-gamma" and so on, where H is the element hydrogen.[8] Four of the Balmer lines are in the technically "visible" part of the spectrum, with wavelengths longer than 400 nm and shorter than 700 nm. Parts of the Balmer series can be seen in the solar spectrum. H-alpha is an important line used in astronomy to detect the presence of hydrogen.

Paschen series (Bohr series, n′ = 3)Named after the German physicist Friedrich Paschen who first observed them in 1908. The Paschen lines all lie in the infrared band.[9] This series overlaps with the next (Brackett) series, i.e. the shortest line in the Brackett series has a wavelength that falls among the Paschen series. All subsequent series overlap.

Given that uncertainty in position and momentum i same..so from uncertainty equation

∆x.∆p ≥ h/4π => (∆p)² = h/4π=> ∆p =(1/2)*√h/π

so, m× ∆v = (1/2)*√h/π=> ∆v = (1/2m)*√(h/π)

option C

We have the relation,

(∆x) /(∆v) = h/4πm.........(1)

Here, h= 6.626 x 10^-34 JS = 6.626 x 10^-27 erg sec, ∆x= 1 nm = 1x 10^-7 cm

We know,

m= 9.1x 10^-28 g

∆v = 6.626x 10^-27 erg sec/4 * 3.142 * 9.1 * 10^-28 g * 1× 10^-7 cm

= 6.62 * 10^-27 /114.37*10^-35 cm/sec

= 0.579 * 10^ 7 cm/sec

If the uncertain position of an electron would be zero then:

We would have no idea of where the electron is.

It follows that the momentum will be infinite.

From the given choices, the correct answer is D.

Which is : Infinite

Simply put, the definition ofhuman fertilizationis the union or joining of the egg and the sperm, resulting in a fertilized egg, otherwise known as azygote. But the process of human fertilization is very complicated and comprised of many steps and components necessary to achieve the ultimate result of human life. Read on to learn how such small things work together to make a fertilized egg

Respiration is an oxidation reaction which is exothermic as there is release of heathence option 4

respiration is an oxidation reaction which is exothermic hence option 4

Endothermic reactions are the one in which heat is overall absorbed for carrying out the reaction successfully.

In photosynthesis, as we know plants absorb direct energy from sun in form of sunlight to turn carbon dioxide and water into oxygen and glucose (type of sugar molecule). So from the above definition of endothermic reaction and our knowledge about photosynthesis we can conclude that photosynthesis is an endothermic process.

Photosynthesis is considered as endothermic reaction because it takes place within the plant body.