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Quadrangular

(i)Cricket’s most important tools are all made of natural, pre-industrial materials. The bat is made of wood, as are the stumps and the bails. 

(ii)The ball is made with leather, twine and cork. Even today both bat and ball are handmade, not industrially manufactured. 

(iii)The material of the bat changed slightly over time. Once it was cut out of a single piece of wood. Now it consists of two pieces, the blade, which is made out of the wood of the willow tree, and the handle, which is made out of cane that became available as European colonialists, and trading companies established themselves in Asia. 

(iv)Unlike golf and tennis, cricket has refused to remake its tools with industrial or man-made materials: plastic, fibre glass and metal have been firmly rejected. 

(v)But in the matter of protective equipment, cricket has been influenced by technological change. The invention of vulcanized rubber led to the introduction of pads in 1848 and protective gloves soon after wards, and the modern game would be unimaginable without helmets made out of metal and synthetic lightweight materials. 

Australian television tycoon

1. A scheduled tour of MCC in 1930 was cancelled due to Gandhi’s Dandi March and the Civil Disobedience.

2. The first Indian team toured England in 1932. Due to World War II in 1939, various tournaments were affected. By now Congress and Muslim League had taken opposite stands. Communal feelings had crept into sports.

3. In 1940, a Pentangular was played in Brabourne stadium, Bombay. Seats were allotted on communal basis, 2000 to Hindus, 1250 each to Muslim and Parsis.

Since India had the largest viewership for the game amongst the cricket-playing nations and the largest market in the cricketing world, the game’s centre of gravity shifted to South Asia. This shift was symbolized by the shifting of the ICC headquarters from London to tax-free Dubai. 

A more important sign that the centre of gravity in cricket has shifted away from the old, Anglo-Australian axis is that innovations in cricket technique in recent years have mainly come from the practice of sub continental teams in countries like India, Pakistan and Sri Lanka. 

Pakistan has pioneered two great advances in bowling: the doosra and the ‘reverse swing’. Both skills were developed in response to sub continental conditions: the doosra to counter aggressive batsmen with heavy modern bats who were threatening to make finger-spin obsolete and ‘reverse swing’ to move the ball in on dusty, unresponsive wickets under clear skies.

In time, it came to be accepted that the laws of cricket could not continue to be framed for British or Australian conditions of play, and they became part of the technique of all bowlers, everywhere in the world. 

By selling television rights to television companies

Eight times has India won the Olympic gold medals in hockey.

The ICC headquarters shifted from London to Dubai.

Earlier there was only a very slight difference between a cricket bat and a hockey stick. Now, a hockey stick is made of single piece of wood and curved at the bottom while a cricket bat is flat and straight and made up of two pieces, the blade and the handle.

The first World Cup successfully staged in 1975.

The first hockey club in India was started in Calcutta.

Colonial officials in India

Blackbuck is a herbivore animal and eyes on either side of the head gives them wide angle vision which helps to protect themselves from predators.

Tiger is a carnivorous animal. So the sharp and pointed canine teeth help the tiger to tear the prey and eat.

Frogs have webbed toes, slippery, smooth skin and triangular head. This helps the frog to swim easily through water.

Diameter of a circle = d = side of a square = 28 cm.

∴ d = 28 cm

⇒ r = d/2 = 28/2 = 14 cm

∴ Area of a circle = 22/7 × 14 × 14

= 22 × 28

= 616 sq.cm.

Correct option is  B) 1/2h (a + b)

Correct option is  D) 154

Correct option is  B) 22/7

Correct option is  C) 132

(i) Area of the outer rectangle – Area of the inner rectangle.

(ii) Area of the outer square – Area of the – inner square.

(iii) Area of the outer circle – Area of the inner circle. π(R + r)(R – r)

Correct option is  A) 2πr

Correct option is  A) 2

Correct option is  B) 20

The dimensions of a rectangular acrylic sheet = 36 cm × 25 cm.

∴ Its area = l × b

= 36 × 25 = 900 sq.cm

The diameter of a circular button = 3.5 cm

radius = r = d/2 = 3.5/2 = 1.75 cm.

∴ Area of each button = πr²

= 22/7 × (1.75)²

= 22/7 × 1.75 × 1.75

= 9.625 sq.cm.

The area of 56 such buttons = 56 × 9.625 = 539 sq.cm.

∴ The area of remaining sheet

= Area of a rectangular sheet – Area of 56 buttons

= 900 – 539

= 361 sq.cm

Correct option is  D) 120°

Correct option is  D) 32

Correct option is  A) 16

Correct option is  B) 4ab

Correct option is  B) 40

Correct option is  A) \(\frac{\sqrt3}{4}\)a² 

Correct option is   A) \(\sqrt{l^2+b^2}\)

Correct option is  B) \(\frac{\sqrt3}{2}\)a 

Correct option is  A) 7

Correct option is  C) 252

Correct option is  D) 81

A rigid body is said to be in equilibrium if the net external force actin on the body does not change its translationl and rotational states.

After the children became friendly with Mitra, they realized that Reshma must have felt bad because they did not play with her.

The given equations are 

a² x + b² y = c² ………(i) 

b² x + a² y = d² ………(ii) 

Multiplying (i) by a² and (ii) by b² and subtracting, we get 

a⁴ x – b⁴ x = a² c² - b² d²

⇒ x = \(\frac{a^2c^2-b^2d^2}{a^4-b^4}\)

Now, multiplying (i) by b² and (ii) by a² and subtracting, we get

b⁴ y – a⁴ y = b² c² - a² d²

⇒ y =\(\frac{b^2c^2-a^2d^2}{a^4-b^4}\)

Hence, x = \(\frac{a^2c^2-b^2d^2}{a^4-b^4}\) and y = \(\frac{b^2c^2-a^2d^2}{a^4-b^4}\)

The given equations are: 

x/a + y/b = 2 

⇒ bx+ay/ab = 2 [Taking LCM] 

⇒bx + ay = 2ab …….(i) 

Again, ax – by = (a² – b²) …..(ii) 

On multiplying (i) by b and (ii) by a, we get:

b²x + bay = 2ab² ……..(iii) 

a²x – bay = a(a² – b²) …….(iv) 

On adding (iii) from (iv), we get: 

(b² + a²)x = 2a²b + a(a² – b²) 

⇒(b² + a²)x = 2ab² + a³ – ab² 

⇒(b² + a²)x = ab² + a³ 

⇒(b² + a²)x = a(b² + a²) 

⇒x = a(b²+ a²) (b²+ b²) = a 

On substituting x = a in (i), we get: 

ba + ay = 2ab 

⇒ ay = ab 

⇒ y = b 

Hence, the solution is x = a and y = b.

The given equations are 

x + y = a + b ………(i) 

ax - by = a² - b² ………(ii) 

From (i) 

y = a + b - x 

Substituting y = a + b - x in (ii), we get 

ax – b(a + b - x) = a² - b² 

⇒ ax – ab - b² + bx = a² - b² 

⇒x = a²+ab/a+b = a 

Now, substitute x = a in (i) to get 

a + y = a + b 

⇒ y = b 

Hence, x = a and y = b

The given equations are 

px + qy = p – q ………(i) 

qx – py = p + q ………(ii) 

Multiplying (i) by p and (ii) by q and adding them , we get 

p²x + q²x = p² – pq + pq + q² 

x = p²+ q²/p²+ q² = 1 

Substituting x = 1 in (i), we have 

p + qy = p – q 

⇒ qy = - p

⇒ y = -1 

Hence, x = 1 and y = -1.

The given equations are 

px + qy = p – q ………(i) 

qx – py = p + q ………(ii) 

Multiplying (i) by p and (ii) by q and adding them , we get 

p² x + q² x = p² – pq + pq + q² 

x = p² + q² / p² + q² = 1

Substituting x = 1 in (i), we have 

p + qy = p – q 

⇒qy = -p

⇒y = -1 

Hence, x = 1 and y = -1.

a. Asset A/c Dr 

    To Revaluation A/c

b. Liability A/c Dr 

     To Revaluaton A/c 

c. Asset A/c Dr 

      To Revaluaton A/c 

d. Old Partner’s Capital A/c Dr 

           To Revaluaton A/c

Revaluation a/c

a) Change in the profit sharing ratio of the existing partners 

b) Admission of a new partner 

c) Retirement of an existing partner 

d) Death of a partner. 

e) Amalgamation of two partnership rms.

• Revaluation a/c Dr. 
• To Machinery A/c

d) Dissolution of the firm

D) Weighted Capitalisation Method

Value of goodwill = Total value of business – Net assets 

Total value of business Net Assets = Assets – Liabilities 

= 1,50,000 – 50,000 

= 1,00,000 

Goodwill = 1,20,000 -1,00,000 = 20,000