Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Equal volumes of 0.002 M solution of sodium iodate and cupric chlorate are mixed togather. Will it lead to precipitation of copper iodate? `("for cupric iodate" K=7.4xx10^(-8))`.

Answer» Concentration of `[Cu^(2+)]` before mixing `=0.002 M`
Conc. of `[Cu^(2+)]` after mixing `=0.002/2=0.001 M`
(since equal volume, `:.` Volume becomes double after mixing and hence conc. Is half)
Similarly conc. Of `[IO_(3)^(Θ)]=0.001 M`
`Q_(sp)=[Ca^(2+)][IO_(3)^(Θ)]^(2)=0.001xx(0.001)^(2)`
`=10^(-3)xx(10^(-3))^(2)=10^(-9)`
Since `Q_(sp)lt K_(sp)`
`10^(-9) lt 7.4xx10^(-8)`
`:. Cu(IO_(3))_(2)` will not precipitate.
2.

Which of the following is correct order of lewis acidic strength.A. `BeCl_(2) lt SiCl_(4) lt AlCl_(3)`B. `PCl_(5) gt PF_(5) gt C Cl_(4)`C. `Na^(+)gtMg^(+2)gtAl^(3+)`D. `PCl_(3)ltPF_(3)ltPF_(5)`

Answer» Correct Answer - D
`M_(1)V_(1)=M_(2)V_(2)`
`5xxV_(1) = 0.1 xx 250`
`V_(1) = 5 ml`
`V_(H_(2)O)=250-5=245 ml = 0.245 L`
3.

Which of the following is the extensive property of a thermodynamic system ? (a) Pressure (b) Volume (c) Temperature (d) Density

Answer»

Correct option is (b) Volume 

4.

If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with m fraction of octahedral holes occupied by aluminium ions and n fraction of tetrahedral holes occupied by magnesium ions, m and n, respectively, are (A) 1/2 , 1/8(B) 1 , 1/4(C) 1/2 , 1/2(D) 1/4 , 1/8

Answer»

Correct option is (A) 1/2 , 1/8

In ccp lattice: 

Number of O atoms → 4 

Number of Octahedral voids → 4 

Number of tatrahedral voids → 8 

Number of Al3+ = 4 x m

Number of Mg2+ = 8 x n

Due to charge neutrality

4 (-2) + 4m (+3) + 8n (+2) = 0

∴ m = 1/2 and n = 1/8

5.

Positive Tollen’s test is observed for

Answer»

Correct option is (A,B)

Beside aldehyde α-hydroxy ketones can also show Tollen’s test due to rearrangement in aldehyde via ene diol intermediate. (however this needs a terminal α-carbon)

6.

The CORRECT statement(s) for cubic close packed (ccp) three dimensional structure is(are) (A) The number of the nearest neighbours of an atom present in the topmost layer is 12 (B) The efficiency of atom packing is 74% (C) The number of octahedral and tetrahedral voids per atom are 1 and 2, respectively (D) The unit cell edge length is 2 2 times the radius of the atom

Answer»

(B) The efficiency of atom packing is 74% 

(C) The number of octahedral and tetrahedral voids per atom are 1 and 2, respectively 

(D) The unit cell edge length is 2 2 times the radius of the atom

The middle layers will have 12 nearest neighbours. The top-most layer will have 9 nearest neighbours. 4r = a√2 , where ‘a’ is edge length of unit cell and ‘r’ is radius of atom.

7.

Reagent(s) which can be used to bring about the following transformation is(are)(A) LiAlH4 in (C2H5)2O (B) BH3 in THF (C) NaBH4 in C2H5OH (D) Raney Ni/H2 in THF

Answer»

(C) NaBH4 in C2H5OH 

(D) Raney Ni/H2 in THF

NaBH4 and Raney Ni/H2 do not react with acid, ester or epoxide entities of an organic compound.

8.

Describe about lithium-ion battery and its uses.

Answer»

1. Lithium-ion battery

Anode : Porous graphite

Cathode : Transition metal oxide as CoO2 

Electrolyte : Lithium salt in an organic solvent 

2. At the anode oxidation occurs

Li(s) —Li+(aq) + e- 

At the cathode reduction occurs.

Li+ + CoO2(s) + e- → Li CoO2(s)

3. Overall reactions

Li(s) + CoO2 → Li CoO2(s)

4. Both electrodes allow Li+ ions to move in and out of their structures. During discharge the Li+ ions produced at the anode moves towards cathode through the nonaquaeous electrolyte. 

5. When a potential greater than the emf produced by the cell is applied across the electrode, the cell reaction is reversed and now the Li+ ions move from cathode to anode where they become embedded on the porous electrode. This is known as intercalation. 

6. Uses:- This Li-ion battery is used in cellular phones, Laptop computer and digital camera.

9.

Give reasons for the following(1) Rusting of iron is quicker in saline water than in ordinary water. (2) Aluminium metal cannot be produced by the electrolysis of aqueous solution of aluminium salt.

Answer»

1. It is because in saline water, there are more H+ ions. Greater the number of H+ ions, quicker the rusting will take place. 

2. It is because aluminium metal is more reactive than hydrogen aid it will react with H2O.

10.

Rusting of `Fe` is quicker in saline water than in ordinary water. Why ?

Answer» Presence of `Na^(o+)` and `Cl^(c-)` ions in saline water increases the conductance of the solution in contact with the metal surface, which accelerates the formation of `Fe^(2+0` ion and henc that of rust, `Fe_(2)O_(3).Xh_(2)o`.
11.

Rangeela, a dishonest milk seller, when buys milk from his supplier he takes 50 ml extra for every litre but when he sells the same he gives 50 ml less for every litre. If the cost price of milk is Rs. 42/litre and selling price is Rs. 56/litre, then calculate the profit or loss he incurred during a day if he bought 20 litres of milk a day from his supplier.1. Rs. 25.82. Rs. 28.73. Rs. 31.54. Rs. 29.6

Answer» Correct Answer - Option 2 : Rs. 28.7

Given:

CP = Rs. 42/litre

SP = Rs. 56/litre

While buying, Rangeela takes 50 ml extra

While selling, Rangeela gives 50 ml less

Purchase from supplier in a day = 20 litres

Formula used:

Profit = SP - CP

Calculation:

Cost price of 1 litre of milk = Rs. 42

He takes 50 ml extra so by giving the cost of 1 litre of milk he takes 1.05 litres.

He bought 20 litres from his supplier  

He actually bought = 1.05 × 20 = 21 litres

He sells 50 ml less for every litre 

For 21 litre he saves 1.05 litres 

So his total sale is 22.05 litres and he paid for only 20 litres.

Rangeela makes his profit from (22.05 - 20) litres which is 2.05 litres 

Cost price of 2.05 litres = Rs. (42 × 2.05)

⇒ Rs. 86.1

Selling price of 2.05 litres = Rs. (56 × 2.05) = Rs. 114.8

⇒ Rs. 114.8

Profit = SP - CP

⇒ Rs. (114.8 - 86.1)

⇒ Rs. 28.7

∴ Rangeela earned a profit of Rs 28.7.

12.

How many of the following statements are correct ? (a)BeO is amphoteric in nature ltbgt (b)`LiHCO_3` is not found in solid state. ( c)`K_2O_2` is diamagnetic but `KO_2` is paramagnetic (d)Hydrated magnesium chloride on heating in dry air gives anhydrous `MgCl_2` (e)`AlCl_3` is soluble in excess of NaOH and form sodium meta aluminate (f)Anhydrous potassium nitrate on heating with potassium metal gives potassium oxide and nitrogen gas (g)Lithium chloride is highly soluble in water.

Answer» Correct Answer - 5
(a),(b), (e) & (f) are correct.
(b)`LiHCO_3oversetDeltatoLi_2CO_3+H_2O+CO_2`
(d)`MgCl_2 . 6H_2O to MgO+HCl+H_2O`
(e)`AlCl_3+4NaOH("excess")to NaAlO_2+2H_2O+3NaCl`
(f)`KNO_3+K to K_2O+N_2`
13.

Volume of an object is dependent upon its temperature in degree Celsius as V = a + bTC, what is the dependence of volume upon temperature in degree Rankine?(a) V = a + 32b + 9bTR/5(b) V = a + 492b + 9bTR/5(c) V = a + 492b + 5bTR/9(d) None of the mentioned

Answer» Correct answer is (b) V = a + 492b + 9bTR/5

For explanation: TC = 492 + 9TR/5, => V = a + b(492 + 9TR/5), => V = a + 492b + 9bTR/5.
14.

If `y=(sin^4x-cos^4x+sin^2xcos^2x)/(sin^4x+cos^4x+sin^2xcos^2x),x in (0,pi/2)`, then`-3/2lt=ylt=1/2`(b) `1lt=ylt=1/2``-5/3lt=y1`(d) none of theseA. `-(3)/(2)le y le (1)/(2)`B. `(1)/(2)le y le 1`C. `-(5)/(3)le y le 1`D. `-1le y le 1`

Answer» Correct Answer - D
`y = (sin^(4)x-cos^(4)x+sin^(2)x cos^(2)x)/(sin^(4)x +cos^(4)x +sin^(2)x cos^(2)x cos^(2)x)`
`y = (- cos2x+(1)/(4)sin^(2)2x)/(1-(1)/(4)sin^(2)2x)`
`= (1-4cos2x- cos^(2)2x)/(3+cos^(2)2x)`
`(1+y)cos^(2)2x+4cos2x+3y-1=0`
`D ge 0`
`-(5)/(3) le y le 1`
but when `y = 1`
`x = (pi)/(2)` which is not permissible
15.

What is the value of 100^oC in degree Fahrenheit?(a) 212^oF(b) 460^oF(c) 672^oF(d) 884^oF

Answer» Correct option is (a) 212^oF

To explain I would say: TF = (9/5)100 + 32 = 212^oF.
16.

Heat capacity of a substance is given by C = BT^2, where T is in degree Fahrenheit and the value of B is 50, what is the value of B if T is in degree Celsius?(a) 81(b) 25(c) 162(d) 100

Answer» The correct choice is (c) 162

For explanation I would say: TF = 9TF/5 + 32 => coefficient of T^2 in C will be B*(9/5)^2 = 50*81/25 = 162.
17.

Heat capacity of a substance is given by C = 800 – 1600T + 25T^2, where T is temperature in degree Fahrenheit, what is the heat capacity if temperature is in degree Celsius?(a) 81T^2 + 24800(b) 81T^2 – 24800(c) 25T^2 + 24800(d) 25T^2 – 24800

Answer» Right option is (b) 81T^2 – 24800

To elaborate: Temperature in degree Fahrenheit, TF = (9/5)TC + 32, replacing TF in C, => C = 81T^2 – 24800.
18.

The function ..................

Answer» Correct Answer - 2
`x|x|` is differentiable at `x=0`
so `(x-2) (x+2) |x-2| |x-1|+ cos|x|`
`(x-2) |(x-2)|` is differentiable at `x=2` so `f(x)` is not differentiable at `x=1`
19.

The equation ..............

Answer» Correct Answer - 1
`(dy)/(dx)=1-1/x^(2)`
`y=x+1/x+c`
`7/2=2+1/2+c implies c=1`
`y=x+1/x +1`
`implies xy=x^(2) +x+1`
20.

The value of tan-1\(\left(\cfrac{cos(\frac{15π}{4})-1}{sin(\frac{\pi}4)}\right)\) is equal to (A) -π/4 (B) -π/8 (C) -5π/12 (D) -4π/9

Answer»

 Correct option is (B) -π/8

\(tan^{-1}[\cfrac{cos(4π-π/4)-1}{sinπ/4}]\)

⇒ tan-1\((\frac{cos π/4 - 1}{sin π/4})\) 

tan-1(\(\frac{1-√2}1\)) = \(-\frac{\pi}8\)

21.

The two circles x2 + y2 − 2 x + 6 y + 6 = 0 and x2 + y2 − 5 x + 6 y + 15 = 0 touch each other. The equation of their common tangent is :

Answer»

Common tangent (x2 + y2 - 2x + 6y +6) - (x2 + y2 - 5x + 6y + 15) = 0

= - 2x + 5x + 6y - 6y + 6 - 15 = 0

= 3x - 9 = 0

= x = \(\cfrac93\) = 3

= x = 3

Hence, x = 3 is common tangent

22.

Statement-1:  If quadratic equation ax2 + bx − 2 = 0 have non-real roots then a < 0Statement-2:  For the quadratic expression f(x) = ax2 + bx + c if b2 − 4ac < 0 then f(x) = 0 have non real roots.(A) Statement – 1 is True, Statement – 2 is True; Statement – 2 is a correct explanation for Statement – 1. (B) Statement – 1 is True, Statement – 2 is True; Statement – 2 is NOT a correct explanation for Statement – 1.(C) Statement – 1 is True, Statement – 2 is False. (D) Statement – 1 is False, Statement – 2 is True

Answer»

(A) Statement – 1 is True, Statement – 2 is True; Statement – 2 is a correct explanation for Statement – 1. 

23.

If x3 + 12x2 + 10ax + 1999 definitely has a positive zero, if and only if ________. (a) a ≥ 0 (b) a > 0 (c) a < 0 (d) a < 0

Answer»

The correct answer is : (c) a < 0

24.

sin(tan-1 x), |x| &lt; 1 is equal to _______.(a) x/√(1 - x2)(b) 1/√(1 - x2)(c) 1/√(1 + x2)(d) x/√(1 + x2)

Answer»

(d) x/√(1 + x2)

25.

The centre of the circle inscribed in a square formed by the lines x2 – 8x – 12 = 0 and y2 – 14y + 45 = 0 is _____. (a) (4, 7) (b) (7, 4) (c) (9, 4) (d) (4, 9)

Answer»

The correct answer is : (a) (4, 7)

26.

A very large metal plate carries a charge of `Q=-1C`. The work function for the metal is `phi = 3eV` The plate is illuminated by a `60` watt light source with a wavelength `lambda` of `330nm`. How long does it take to completely discharge the plate? (Assume that every efficient photon ejects electron which is instantly removed from the sheet surface. (All photons ejected from light source fall normally on the metal plate) (`h=6.6 xx 10^(-34) m^2 kg//s`)A. 0.005 sB. 0.025 sC. 0.0625 sD. 0.01

Answer» The energy per photon is
`E_(lambda)=(hc)/(lambda)=(6.6xx10^(-34)m^(2)k g //sxx3xx10^(8) m//s)/(3.3xx10^(-7)m) 6xx10^(-19) J`
The time is to discharge the plate is given by total number of electrons divided by the rate of photons
`t=Q//exx(E_(lambda))/P=(6xx10^(-19)J)/(1.6xx10^(-19)xx60J//s) =0.0625 s`
27.

Three indentical uniform blocks of mass m each and length L are placed on a smooth fixed horizontal surface as shown. There is friction between A and B (Friction cofficient `mu`) while there is no friction between A and C. At the instant shown, that is at t=0, the block A has horizontal velocity of magnitude u towards right, whereas speed of B and C is zero. At the instant block A has covered a distance L relative to block B velcity of all blocks are same. The value of `mu` isA. `mu =3/2 (u^(2))/(gL)`B. `mu=1/2 (u^(2))/(gL)`C. `mu=(u^(2))/(gL)`D. `mu =2/3(u^(2))/(gL)`

Answer» From conservation of momentum
`3mv="mu"` or `v=(u)/(3)`
Net workdone by friction `=(1)/(2)3m((u)/(3))^(2)-(1)/(2)"mu"^(2)=-(1)/(3)"mu"^(2)`
net work done by fricktion `=underset(r)overset(0)intmu(xlambdag)(-dx)=-mulambdag(L^(2))/(2)`
Also magnitude of net work done by friction `=mulambdag(L^(2))/(2)=mumg(L)/(2)`
`therefore(1)/(3)"mu"^(2)=mumg(L)/(2)` or `mu=(2)/(3)(u^(2))/(gL)`
`3mg="mu"` or `v=(u)/(3)`
28.

the photon radiated from hydrogen corresponding to the second line of Lyman series is absorbed by a hydrogen like atom X in the second excited state. Then, the hydrogen-like atom X makes a transition of nth orbit.A. `X=He^(+), n=4`B. `X=Li^(++), n=6`C. `X=He^(+),n=6`D. `X=Li^(++) , n=9`

Answer» Correct Answer - D
(D) Energy of `n^(th)` sate in hydrogen is same as energy of `3n^(th)` state in `Li^(++)` `:. 3 to 1` transition in H would give same energy as the `3xx to 1xx3` transition in `Li^(++)`.
29.

The electric field of an electromagnetic wave changes with time as `E=K(1+cosOmega t) cos omega t`, where `Omega= 5xx10^(15) s^(-1), omega= 2xx10^(16) s^(-1)` and K is constant. This radiation is incident on a sample of hydrogen atoms initially in ground state. Assume that atoms absorb light as photons. neglecting recoil of hydrogen nucleus on ionisation, what will be the energy of ejected electrons from hydrogen. [The ionisation energy of hydrogen atom= 13.6 eV and `h=2pi xx 6.6xx 10^(-16) eV-s`]A. 0.7eVB. 0.9 eVC. 1.4 eVD. 2.9 eV

Answer» Correct Answer - D
The expression for electric field can also be written as `E=K cos omega t+1/2 K cos(omega-Omega) t+1/2 K cos (omega+Omega) t`
The three terms correspond to photons of energies `h omega, h(omega-Omega)` and `h(omega-Omega) ` . The latter exceeds the ionisation by 2.9 eV . that difference equals ejected electrons energy.
30.

List down the reasons for the disintegration of Soviet Union.Deviation from the basic principles of socialism.

Answer»
  • Failure in bringing about changes in economic sector. 
  • Regulation on freedom of expression and opinion. 
  • Corruption and inefficiency of the bureaucracy. 
  • Administrative measures of Mikhail Gorbachev.
31.

Calculate the mass of Mg and the volume of Chlorine gas at NTP produced during the electrolysis of molten `MgC1_(2)` by the passage of 2 amperes of current for 1 hour. Molar masses of Mg and `C1_(2)` are 24 g `mol^(-1)` and 71 g `mol^(-1)` resectively

Answer» Mass of Mg produced = 0. 8953 g
Volume of `C1_(2(g)) ` at NTP produced = 835 .6 `cm^(3)`
32.

Calculate equilibrium constant for the reaction `Ni_((s))+ 2A_((aq))^(+) to Ni_((aq))^(+) + 2Ag` at` 25^(@)C` `E_(Ni^(2+) | Ni)^(@) =- 0.25 ` V and `E_(Ag^(+) | Ag)^(@) = 0.799 V`

Answer» `K= 2.754 xx 10^(35)`
33.

Calculate `E_(" cell ")^(@) E_("cell ")` and `Delta G` for the following reaction at `25^(@)C` `Mg_((s)) + Sn^(2+) (0.03 M) to Mg^(2+) (0.04 M) + Sn_((s))` `E_(Mg^(+2)|M) ^(@) =- 2.37 V` and `E_(Sn^(2+) | Sn)^(@) =- 0.14 V` is the reaction spontaneous

Answer» `(i) E_("cell ")^(@) =2 .23 V , (ii) E_("cell ") =2.226 V Delta G =429 .6 kJ`
`(iii) ` Since `E_("cell ") gt 0, Delta G lt 0` the reaction is spontaneous
34.

In chromatography, which of the following statements is incorrect for Rf ? (1) Rf value depends on the type of chromatography. (2) Higher Rf value means higher adsorption. (3) Rf value is dependent on the mobile phase. (4) The value of Rf can not be more than one.  

Answer»

Correct option (2) Higher Rf value means higher adsorption

Explanation:

Low polarity compounds are weekly absorbed and has greater Rf value 

35.

The highest possible oxidation states of uranium and plutonium, respectively are : (1) 4 and 6 (2) 6 and 4 (3) 7 and 6 (4) 6 and 7

Answer»

Correct option (4) 6 and 7

Explanation:

This highest oxidation state of uranium is +6 whereas of plutonium is + 7 

36.

Aluminium is usually found in +3 oxidation state. In contarast, thallium exists in +1 and +3 oxidation states. This is due to : (1)  lanthanoid contraction (2)  lattice effect (3)  diagonal relationship (4)  inert pair effect 

Answer»

Correct option  4) inert pair effect

Explanation :

Due to inert pair effect Tl is stable is +1 oxidation state 

37.

The Union Government of India has decided to declare 2018 as National Year of ______.1. Fruits2. Pulses3. Potatoes4. Millets

Answer» Correct Answer - Option 4 : Millets

The correct answer is Millets.

  • The Union Government of India has decided to declare 2018 as National Year of Millets in order to boost the cultivation of millets on a mission mode to attain nutritional security in the country.
  • The initiative is expected to promote the cultivation of millets like jowar, bajra, ragi.

  • The Union Agriculture Minister Radha Mohan Singh while addressing MPs in a consultative committee meeting in New Delhi in March 2018 stated that millet cultivation has dwindled due to change in dietary habits and unavailability of millets in the country.
  • As a result of this change in dietary habits and unavailability of millets, level of nutrients like proteins, Vitamin-A, iron, and iodine fell in women and children in the country.
  • In order to improve the consumption of nutrients in women and children, a special focus on millets is given under the National Food Security Mission (NFSM) .
  • Millets contain higher amounts of fibre and essential minerals. Barnyard millet, Kodo millet, Little Millet, Proso Millet are considered as the healthiest millet grains available.
  • Millet is a rich source of potassium—a mineral that keeps human organs such as kidney and heart-healthy.
  • It is also an excellent source of Vitamin A, Vitamin B, Phosphorus, Potassium, Antioxidants, Niacin, Calcium, Iron etc.
38.

A disc is free to rotate about an axis passing through its centre and perpendicular to its plane. The moment of inertia of the disc about its rotation axis is I. A light ribbon is tightly wrapped over it in multiple layers. The end of the ribbon is pulled out at a constant speed of u. Let the radius of the ribboned disc be R at any time and thickness of the ribbon be `d (lt lt R)`. Find the force (F) required to pull the ribbon as a function of radius R. A. Angular acceleration of the disc at any insant is proportional to `1/(R^(3))`, where `R` is radius of the ribboned discB. Angular acceleration o the disc at any instant is proportional to `1/(R^(2))` where `R` is the radius of the ribboned disc.C. Force required to pull the ribbon at constant speed `u` is `F=(Iu^(2)d)/(2piR^(4))`D. Force required to pull the ribbon at constant speed `u` is `F=(Iu^(2)d)/(piR^(4))`

Answer» Correct Answer - A::C
`omegaR=u=`constant
`omega(dR)/(dt)+R(domega)/(dt)=0`
`:.(domega)/(dt)=-(omega)/R(dR)/(dt)`
In time `dt` radius decreases by `dR`
`-2pi RdR= uddt`
`:.(dR)/(dt)=-(ud)/(2piR)`
`(domega)/(dt)=alpha=(omega)/R (ud)/(2piR)`
`alpha=(u^(2)d)/(2piR^(3))`
`tau=(Iu^(2)d)/(2piR^(3))`
`:.F=(Iu^(2)d)/(2piR^(4))`
39.

If the angular momentum of a planet of mass m, moving around the Sun in a circular orbit is L, about the center of the Sun, its areal velocity is:(1)   4L/m(2)   L/m(3)   L/2m(4)   2L/m

Answer»

Correct option  (3)  L/2m

Explanation:

dA/dt  =  L/2m

40.

Consider the two complexation equilibria in aqueous solution, between the cobalt (II) ion `Co^(2+)` (aq) and ethylenediamine (en) on the one hand and ammonia `NH_(3)` on the other. `[CO(H_(2)O)_(6)]^(2+)+6NH_(3)hArr[Co(NH_(3))_(6)]^(2+)+6H_(2)O` ...(1) `[Co(H_(2)O_(6))]^(2+)+3enhArr[Co(en)_(3)]^(2+)+6H_(2)O` ..(2) Electronicaly, the ammonia and en ligands are very similar, since both bond through N and since the liwis base strengths of their nitrogen atoms are similar. This means that `DeltaH^(@)` must be very similar for the two reactions, since six Co-N bonds are formed in each case. Interestingly however, the equilibrium constant is 100,000 times larger for the second reaction than it is for the first. This is the so called chelate effect: "the enhanced affinity of chelating ligands for a metal ion compared to similar non-chelating (monodentate) ligands for the same metal". The chelate effect is entropy-driven. Q. Which of the following can be classified as a chelating ligand?A. `edta^(-4)`B. `N_(3)^(-)`C. `PPh_(3)`D. all of these

Answer» Correct Answer - B
41.

A Uniform electric field of `10NC ^(-1)` exists in the vertically downward direction. Find the increase in the electric potential as one goes up through a height of 50cm.

Answer» `E=10NC^(-1),S=50cm=(1)/(2)cm`
`triangleV=ES=10xx(1)/(2)=5V`
42.

de novo synthesis of pyrimidine nucleotides is regulated by which enzyme

Answer»

Recent studies demonstrate that CAD, a rate-limiting enzyme in the de novo synthesis of pyrimidines, is regulated through reversible phosphorylation, Myc-dependent transcriptional changes and caspase-mediated degradation.

43.

Why Li2CO3 decomposes at lower temperature whereas Na2CO3 at higher temperature?

Answer»

Li+ ion is smaller in size. It forms more stable lattice with smaller anion oxide, O2- than with CO32- ion. Therefore, Li2CO3 decomposes into Li2O at lower temperature on the other hand, Na+ ion being larger in size forms more stable lattice with larger anion CO32-than with O2- ion. Therefore, Na2CO3 is quite stable and decomposes into Na2O at very high temperature.

44.

What is aspartate Transcarbamoylase?

Answer»

Aspartate transcarbamoylase (ATCase) catalyzes a key step of pyrimidine biosynthesis, the condensation of carbamoyl phosphate with aspartate to form N-carbamoylaspartate. The Escherichia coli enzyme has been extensively studied.

45.

Sulphur is not present in (A) Thiamine (B) Lipic acid (C) Thymine (D) Biotin

Answer»

Correct option (C) Thymine

46.

Restriction enzymes have been found in (A) Humans (B) Birds (C) Bacteria (D) Bacteriophase

Answer»

(C) Bacteria

47.

What is the difference between plasma and serum

Answer»

A key difference between plasma and serum is that plasma is liquid, and serum is fluid. While most of the components are the same for both plasma and serum, plasma contains fibrinogen which is absent in serum. Both plasma and serum can be extracted from blood with the use of a centrifuge but it’s worth noting that serum is obtained after the clotting of blood, while plasma can be obtained before the coagulation of the blood. Serum is mostly used for blood typing but is also used for diagnostic testing. Plasma on the other hand, is mostly used for blood-clotting related problems.

48.

What transports unconjugated bilirubin to liver

Answer»
  • At the sinusoidal surface of the liver, unconjugated bilirubin detaches from albumin and is transported through the hepatocyte membrane by facilitated diffusion.
  • In order for bilirubin to be excreted into bile and, therefore, eliminated from the body, it must be made more soluble.
  • Hepatocytes have a selective and highly efficient system for removing unconjugated bilirubin from plasma.
  • In the hepatocyte, the transported bilirubin is bound to ligandin, a cytosolic protein, that facilitates transfer to the endoplasmic reticulum, the site of bilirubin conjugation.
49.

What is hysteresis? Define the terms ‘coercivity’ and ‘retentivity’ of a ferro magnetic material.

Answer»

Hysteresis: The phenomenon of lagging behind the magnetic induction (\(\vec B\)) with respect to the magnetizing field (\(\vec h\)) is called hysteresis.

Retentivity: The property of the magnetic material to retain magnetism even in the absence of the magnetizing field is known as retentivity or remanence.

Coercivity: The magnetizing field (H) needed to demagnetize the magnetic material completely is known as coercivity.

50.

In the hot climate areas, houses are often painted with light colours because they do not _____ sunlight.1. Reflect        2. Scatter3. Absorb4. Conduct

Answer» Correct Answer - Option 3 : Absorb
  • Every region has a different house.
  • The type of house depends on the climatic conditions in the region. 
  • Houses are built specially to suit the needs of the people.

  • In places of hot climate, it is advised that the outer walls of the house be painted white because light colour.
  • This does not absorb any heat radiation from the sun which keeps inside cool even if there is a hot climate outside the house.
  • The light colour will reflect the light and therefore absorb less heat.
  • Thereby keeping the house cool.

Thus, in the hot climate areas, houses are often painted with light colours because they do not absorb sunlight.