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Now, putting the value of x = 200 m, y = 150 m in equation of area of plot, we get

The area of the rectangular plot is xy = 200 × 150 = 30,000 m² .

Hence, the area of the rectangular plot is 30,000 m²

The chronological order is as follows 

1. Problem Identification 

2. Coding of a program 

3. Translation 

4. Documentation

(d) Copy right, others are phases in programming

Let the radius of the circle is r and side length of a square is a. 

∴ the circumference and the area of the circle are 2πr and πr² respectively. 

And the perimeter and the area of the square are 4a and a² respectively. 

Given that the circumference of the circle and the perimeter of the square are equal. 

∴ 2πr = 4a ⇒ = \(\frac{2a}π\).

Now, the ratio of the areas of the circle and area of the square is

\(\frac{π r^2}{a^2}\) = \(\frac{(\frac{2a}π)^2}{a^2}\) = \(\frac{\frac{4a^2π}{π^2}}{a^2}\) = \(\frac{4 a^2}{a^2π}\) = \(\frac{4}π\) > 1. (∵ π = 3.14 < 4. ∴ 4/π > 1)

Hence, \(\frac{Area\,of\,circle}{Area\,of\,square}\) > 1.

∴ Area of circle > Area of square.

Hence, area of circle is greater.

Electronic configuration of Ca is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 

Filling of 3d orbital starts after the filling of 4s orbitals. If the aufbau principle had not been followed, the filling of 3d orbital would have been prior to filling of 4s orbital and the electronic configuration of Ca would have been  1s² 2s² 2p⁶ 3s² 3p⁶ 3d² and it belongs to d block.

(C) T₁ = (mgcosβ)/sin(α + β), T₂ = (mgcosα)/sin(α + β)

Young’s modulus is defined as ratio of longitudinal stress acting on the body to the longitudinal strain produced in it.  

Current (I) is lags behind the voltage by 90°.

I = V/XL amps. 

XL = 2πfL ohms. 

P = I * V * cosϕ watts. (Where cosϕ is 90 because current lags behind voltage by 90°. So cosϕ 90° = 0) 

∴ P = I * V * 0 = 0 watts. 

Inductance;

A coil carrying alternating current produces an alternating flux, which causes to link with same coil and produces an emf in the coil, which opposes the applied emf. This property is known as inductance. The unit for measurement is henry.

Inductive reactance:

The opposition or the reactance offered by the property of inductance in the circuit is known as inductive reactance and denoted by the letter XL. The unit for measurement is ohm.  

Current (I) is leading the voltage by 90°. 

I = V/XC amps. 

X_C = 1/2πfC ohms.

P = I * V * cosϕ watts. (Where cosϕ is 90 because current is leading the voltage by 90°. So cosϕ 90° = 0) 

∴ P = I * V * 0 = 0 watts. 

Current (I) is in-phase with the voltage.

I = V/R amps. 

P = I * V * cosϕ or I² R watts. (Where cosϕ is zero because the voltage and current are in-phase. So cosϕ 0° (zero) = 1) 

Work is said to be done, when the point of application of the force moves. Work done is equal to force * distance. The unit of work is Newton (M.K.S system) and joule (1 Newton Meter). 

C = Q/E farad. 

The types of capacitor,

a. Paper capacitor. 

b. Rolled plastic cover or polyester type capacitor. 

c. Mica capacitor. 

d. Silver mica capacitor. 

e. Ceramic capacitor. 

f. Electrolytic capacitor. 

The Basket-Ball match is decided in the way either team gets more points will be considered winner.

The duration of the Basket-ball game is 10-2-10-10-10-2-10. At the time when match ended in draw extra 5-2-5 minutes are given, in case again it remains draw, extra 5-5 minutes are given without rest, after five minutes sides of basket-ball court are changed. This duration will be given till the match is decided.

In Basket-Ball game two time-outs are there before interval for each team and two after the interval each team can take. The duration of time outs is one minute.

When a player has committed five fouls, he is not allowed to play further.

Given:

A tank can be filled by tap A in 5 hours, by B in 4 hours, C can empty it in 8 hours

Calculation:

Efficiency of A = 1/5, of B = 1/4, C =  -1/8

Time Taken by A, B, C ∝ 1/Efficiency  = (1/5 + 1/4 – 1/8) = (8 + 10 – 5)/40 = 13/40

∴ Time Taken by A, B, C = 40/13 hours

Formula used:

If we have a group of 'n' objects out of which we make a selection taking 'r' object at a time, then the number of such selections is given by the combination formula

ⁿC_r = n!/(r!(n – r!))

Calculation:

Number of groups can be formed by 5 men and 2 women out of 7 men and 3 women

⇒ ⁷C₅ × ³C₂

⇒ 7!/(5! × (7 – 5)!) × 3!/(2! × (3 – 2)!)

⇒ 7!/(5! × 2!) × 3!/(2! × 1!)

⇒ (7 × 6 × 5!)/(5! × 2) × (3 × 2!)/(2!)

⇒ (7 × 3) × (3)

⇒ 63

∴ The number of ways to arrange men and women is 63

η = P₀/P₁

η = 0.21 

P₀ = P_i = 47.5 MW

η = 1 - T₁/T₂

T₁/T₂ = 0.79

Example of network solid is diamond . It is the network solid of carbon atoms. 

Correct answer is (a)

We know that propagation wave vector

∵ \(\vec{E} = \hat{k}\)

\(\vec{B} = 2\hat{i} - 2\hat{j}\)

\(\vec{C} = \vec{E} \times \vec{B}\)

\(\vec{C} = \begin{vmatrix}\hat{i} & \hat{j} & \hat{k} \\0 & 0 & 1 \\2 & -2 & 0\end{vmatrix}\)

\(\vec{C} = \hat{i}(0 + 2) - \hat{j}(0 - 2) + 0\,\hat{k}\)

\(\vec{C} = 2\hat{i} + 2\hat{j}\)

unit vector of propagation wave = \(\frac{\vec{C}}{|\vec{C}|}\)

\(=\frac{2\hat{i} + 2\hat{j}}{\sqrt{4 + 4}}\)

\(=\frac{2\hat{i} + 2\hat{j}}{\sqrt{8}}\)

\(\Rightarrow \frac{1}{\sqrt{2}}(\hat{i} + \hat{j})\)

I = \(\frac{1}{2}\)\(\epsilon_0 \epsilon^2_0\)

I =  \(\frac{P}{AC}\)

\(\frac{P}{C\times4\pi R^2}\) = \(\frac{1}{2}\)\(\epsilon_0 \epsilon^2_0\)

\(\epsilon^2_0\) = \(\frac{P}{2\pi \epsilon_0R^2C}\)

\(\epsilon_0 \) = \(\sqrt\frac{P}{2\pi \epsilon_0 R^2 C}\)

Azeotropes are binary mixtures having the same composition in liquid and vapour phase and boil at a constant temperature. In such cases, it is not possible to separate the components by fractional distillation. 

Magnetic flux = Φ₀ = 5 Wb
The page is turned around through an angle = 30° 
Thus, magnetic through the edge of the paper is 
Φ_B = Φ₀ cosθ = 5 cos 30° = 5 x 0.866 = 4.33 Wb 

Electric field in wire,

\(E=\frac{V}{L}=\frac{IR}{L}\) (V=IR, ohm's Law)

and,

\(H=\frac{I}{2\pi a}\) (current distributed along surface of wire)

\(S=EH=\frac{I^2R}{2\pi aL}\)

Threshold energy – 

The minimum amount of energy which must be associated with the molecules, so that their mutual collisions result in product formation.

The magnetic flux formula is given by,

\(\phi_B=B.A\)

\(\phi_B=BACos\theta\)

Where,

B = Magnetic field,

A =  Surface area and

\(\theta\) =  Angle between the magnetic field and normal to the surface.