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11701.

If a function is invertible the graph of its inverse is the mirror image of the function in y=x. If f^(-1)(x) is the inverse function of f(x), then f(f^(-1)(x))=f^(-1)(f(x))=x. If f(x)=ln[((100+x)e^(x^(3)))/((100-x))], then the graph of f^(-1)(x) will be symmetrical about x+y=1

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`x+y=1`
`y=x+1`
`y=-x`
can not say

Answer :C
11702.

Show that the function f defined by f(x)={(x if "x is rational"),(-x if "x is irrational"):} is continuous at x=0 AAxne0inR

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Solution :f(0)=0
L.H.L=`lim_(xto0)f(x)=lim_(hto0)f(-h)`
`=lim_(hto0){(-h if "h is RATIONAL" =0),(h if "h is irrational"):}`
Similarly R.H.L.=0
THUS L.H.L.=R.H.L.=f(0)
Hence f(x) is continuous at x=0
We can easily show that f(x) is discontinuous at all real POINTS `xne0`
11703.

A box contain 6 tickets. Two of the tickets carry a price of Rs 5/- each and the other 4 are the price of Rs 1 each. If one ticket is drawn at random, what is the mean price.

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ANSWER :`7//3`
11704.

A : The value of (Tan^(-1)(4//3))/(Tan^(-1)(1//2)) is equal to 2. R : AAx in[0,1],Tan^(-1)((2x)/(1-x^(2)))=2Tan^(-1)x

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Both A and R are TRUE and R is the CORRECT EXPLANATION of A
Both A and R are true but R is not correct explanation of A
A is true but R is FALSE
A is false but R is true

Answer :A
11705.

A box has 100 pens of which 10 are defective. The probability that out of a sample of 5 pens drawn one by one with replacement and atmost one is defective is

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`a.(9)/(10)`
b. `(1)/(2)((9)/(10))^(4)`
c.`((9)/(10))^(5)+(1)/(2)((9)/(10))^(4)`
d.`(1)/(2)((9)/(10))^(5)`

ANSWER :C
11706.

The radius of the director circle of the hyperbola x^2//25-y^(2)//9=1 is

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3
4
5
8

Answer :B
11707.

Find the roots of the following cubic equations 2x^(3)-3x^(2) cos (A-B)-2 x cos^(2) (A+B)+ sin 2A sin 2 B cos (A-B)=0 .

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ANSWER :`2 COS A cos B, 2 SIN A sin B "and" -(1)/(2) cos (A-B)`.
11708.

If A={a,b,c,d} mention the type of relations on A given below, which of them are equivalence relations?{(b,c),(b,d),(c,d)}

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SOLUTION :Only TRANSITIVE
11709.

The radical axis of two circles whose centres are ( 3,4), (-1,2) and each passing through the centre of the other is

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` 2X+ y +5=0 `
` x-2y +5=0`
` 2x+ y-1=0 `
` 2x+ y-5=0`

ANSWER :D
11710.

Evaluate the following integrals int(logx^(2))dx

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ANSWER :`X((LOGX)^(2)-2logx+2)+C`
11711.

When the coordinate axes ar rotated about the origin in the positive direction through an angle pi/4, IF the equation 25x^2+9y^2=225 is transformed to ax^2+betaxy+ygamma^2=delta, then (alpha+beta+gamma-sqrtdelta)^2=

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3
9
4
16

Answer :B
11712.

Let ABCD is a rectangle with AB=a & BC=b & circle is drawn passing through A & B and touching side CD. Another circle is drawn passing through B & C and touching side AD. Let r_(1) & r_(2) be the radii of these two circle respectively. Minimum value of (r_(1)+r_(2) equals

Answer»

`5/8 (a-b)`
`5/8 (a+b)`
`3/8 (a-b)`
`3/8 (a+b)`

Solution :`r_(1)=b-x_(1)=OP=OA`
`AP_(1)=a//2`
`r_(1)^(2)=x_(1)^(2)+(a/2)^(2)=(b-x_(1))^(2)`
`x_(1)^(2)+(a^(2))/4=b^(2)+x_(1)^(2)-2bx_(1)`
`x_(1)=(4b^(2)-a^(2))/(8b)`
`r_(1)=b-x_(1)=(4b^(2)+a^(2))/(8b)`
SIMILARLY `r_(2)=(4A^(2)+b^(2))/(8a)`

`r_(1)+r_(2)=(a^(3)+b^(3)+4ab(a+b))/(8AB)`
`implies((a+b)(a^(2)+3ab+b^(2)))/(8ab)`
`=((a+b)/8)([(a-b)^(2)+5ab])/(AB)`
But `(a-b)^(2)ge0`
`r_(1)+r_(2)GE((a+b))/8.(5ab)/(ab)`
`impliesr_(1)+r_(2)ge(5(a+b))/8`
11713.

A bag contains 10 white and 15 black balls. The balls are drawn one at a time until only those of the same colour are left. Show that the probability that they are all black is 3/5.

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ANSWER :`(3)/(5)`
11714.

Find mean of following probability distribution.

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ANSWER :2.75
11715.

The solution of (x+y)^(2)(dy)/(dx) = a^(2) is

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`y = TAN^(-1)((X+y)/(a)) + C`
`a y = tan^(-1)(x+y) + c`
`y = a tan^(-1)((x+y)/(a)) + c`
`x = a tan^(-1)((x+y)/(a)) + c`

ANSWER :C
11716.

Let A=[{:(1,-2,1),(-2,3,1),(1,1,5):}] Verify that (A^(-1))^-1=A

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ANSWER :A
11717.

Statement:1 In triangleABC, if a lt b sinA, then the triangle is possible. And Statement:2 In triangleABC a/(sinA)= b/(sinB)

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Statement-1 is TRUE, Statement-2 is true, Statement-2 is a CORRECT EXPLANATION for statement-16
Statement-1 is true, Statement-2 is true, Statement-2 is not a correct expanation for statement-16
Statement-1 is True, Statement-2 is FALSE
Statement-1 is False, Statement-2 is true

ANSWER :D
11718.

The volume of the tetrahedron formed by the coterminous edges veca, vecb, vec c is 3. Then the volume of the parallelopiped formed by the coterminous edges veca+vecb, vecb+vec c, vec c+ veca is

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36
34
32
30

Solution :`(1)/(6)[VECA vecb vec C]=3` (GIVEN)
`[veca vecb vec c]=18`
`"VOL. of parallelopiped"=[veca+vecb""vecb+vec c""vec c + a]`
`=2[veca vecb vec c]=2xx18=36`
11719.

Let A(2sec theta, 3 tan theta ) and B( 2sec phi ,3 tan phi ) where theta + phi =(pi)/(2)be two point on the hyperbola(x^(2))/( 4) -( y^(2))/( 9) =1 . If (alpha , beta )is the point of intersection of normals to the hyperbola at A and B ,then beta =

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`- (13)/(3)`
`(13)/(3)`
`(3)/(13)`
`- (3)/(13)`

ANSWER :a
11720.

Let the smallest positive value of x for which the functionf(x)=sin""(x)/(3)+sin""(x)/(11), ( x in R ) achieves its maximum value bex_(0). Express x_(0) in degree i.e.x_(0)=alpha^(0). Then , the sum of the digits inalphais

Answer»

15
17
16
18

Answer :D
11721.

If1 , omega , omega^(2) are the cube roots of unity , then find the values of the following . (a+ b)^(3) + ( a omega + bomega ^(2))^(3) + ( a omega^(2) + b omega)^(3)

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ANSWER :`3(a^3+b^3)`
11722.

int(x^(2))/(sqrt(1+x^(2))(1+sqrt(1+x^(2))))dx

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ANSWER :`x-sinh^(-1)x+c`
11723.

If the area of the parallelogram whose adjacent sides are (3i + 4j + lambda K) and (2j - 4k) is sqrt(436) square units, and lambda ge 0, then lambda =

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0
4
1
3

Answer :A
11724.

Find the equation of a curve passing through the point (-2,3), given that the slope of the tangent to the curve at any point (x,y) is (2x)/(y^(2)).

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ANSWER :`y = (3X^(2) + 15)^(1/3)`
11725.

A point is taken at random from inside of the circumcircle of an equilateral triangle. The probability that it lies inside the circumcircle but outside the incircle is

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`1//4`
`3//4`
`1//2`
`1//3`

ANSWER :B
11726.

Let A=NxxN Define * on A by (a,b)*(c,d)=(a+c,b+d) Show that (i) A is closed for * (ii) * is commutative (iii) * is associative (iv) identify element does not exist in A

Answer»

Solution :(i) Let (a,b) in A and (c,d) inA Then a,b,c d in N
`(a,b)*(c,d)=(a+c,b+d)in A`[before a+c in N, b +d `in` N]
`therefore` A is CLOSED for*
(a,b)*(c,d)=(a+c,b+d)
`=(c+a,d+b) ["before" a+c=c+a and b+d=d+b]`
=(c,d)*(a,b)
(III)(a,b)*(c,d)*(e,F)=(a+c,b+d)*(e,f)
=[(a+c)+e,(b+d)+f]
=([a+(c+e),b+(d+f)]
=(a,b)*[(c,de,d+f)
`=(a,b)*[(c,d)*(e,f)]`
(IV) (a,b)*(0,0)=(a+0,b+0)=(a,b)
But ,(0,0)`ne` A since one N
So identity element does not BELONG to A
11727.

Let I =int _(0)^(1 ) sqrt((1+sqrtx)/(1-sqrtx))dx and J = int _(0)^(1 ) sqrt((1-sqrtx)/(1+sqrtx))dxthen correct statement (s) is/are:

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`I+J=2`
`I -J =pi`
`I =(2+pi)/(2)`
`J =(4-pi)/(2)`

Answer :B::C
11728.

A body is thrown horizontally with a velocity of v m/s from the top of a tower of height 2h reaches the ground in 't' seconds. If another body double the mass is thrown horizontally with a velocity 5v m/s from the top of another tower of height 8h. In the above problem if the first reaches the ground at a horizontal distance 'x' the second body reaches the ground at a horizontal distance

Answer»

1
2
3
`1.5`

ANSWER :B
11729.

IfDelta = {:[( a_11, a_12, a_13),( a_21,a_22,a_23) ,(a_31,a_32, a_33) ]:} andis Cofactors of a_ijthen value of Deltais given by

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` a_11 A_31+ a_12A_32+a_13A_33`
` a_11A_11+a_12A_21+a_13A_31`
` a_21A_11+a_22A_12+a_23A_13`
`a_11A_11+a_21A_21+a_31A_31`

ANSWER :D
11730.

Let k denote the number of ways in n boys sit in a row such that three particular boys are repeated. Then

Answer»

3! Divides K
`(n-2) !` Divide k
`.^(n-2)C_(3)` divides k
`(n-3)^(2)(n-4)^(2)` divides k

Answer :a,b,C,d
11731.

Evaluate the following integrals : int_(0)^(pi/2)(dx)/(4sin^(2)x+5cos^(2)x)

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ANSWER :`(PI)/(4sqrt5)`
11732.

Show that |{:(a,b,c),(a^(2),b^(2),c^(2)),(a^(2),b^(3),c^(3)):}|=abc(a-b)(b-c)(c-a)

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ANSWER :`(ABC)(a-b)(b-c)(c-a)=R.H.S`
11733.

A straight line through the point (2, 2) intersects the lines sqrt3 x + y = 0 and sqrt3 x - y = 0 at the points A and B. The equation of AB so that the triangle OAB is equilateral, where O is the origin.

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X - 2 = 0
y - 2 = 0
x + y - 4 = 0
x+y+z = 0

Answer :B
11734.

findthe areaboundedby thecurvey=2 cos xandtheX- axisfromx=0tox = 2 pi

Answer»


ANSWER :`=8 ` SEQ . UNIT
11735.

The number of values of x in [0,4pi] satisfying |sqrt(3cosx - sinx )| gt=2 is :

Answer»

2
0
4
8

Answer :C
11736.

Two adjacent sides of a parallelogram are 4x+5y=0,and 7x+2y=0. Area of the parallelogram is

Answer»

3
`3/2`
6
`(2sqrt85)/(3)`

ANSWER :A
11737.

If y=f(x) is the solution of differential equation , e^y((dy)/(dx)-2)=e^(3x) such that f(0)=0 , then f(2) is equal to :

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3
5
6
None of these

Solution :Put `e^y =t rArr e^y DY= dtrArr (dt)/(dx)-2t=e^(3X)`
I.F. =`e^(INT -2dx) =e^(-2x)`
`t.e^(-2x) = int e^(3x). E^(-2x) dx`
`t.e^(-2x) = inte^X dx= e^x +c , e^y e^(-2x) =e^x + c`
Put x=0 ,y=0 we get `e^0 .e^0 =1+c`
`rArr e^y e^(-2x)= e^x`
`e^y =e^(3x) rArr y=3x rArr f(x)=3x`
11738.

If tanA+sinA=p and tanA-sinA=q, then the value of ((p^(2)-q^(2))^(2))/(pq) is :

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16
22
18
42

Answer :A
11739.

A company manufactures the bicycle with gears and without gears in two different factories. The factory A produces 16 bicycles without gears and 20 bicycles with gears in a day. The factory B produces 12 bicycles without gears and 20 bicycles with gears in a day. The expenditure of factory A is Rs. 50,000 daily and the expenditure of factory B is Rs. 40,000 daily. A company has ordered for 96 bicycles without gears and 140 bicycles with gears. To complete these order, how many days the factories will work so that there is minimum expenditure ?

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ANSWER :FACTORY A for 3 DAYS and Factory B for 4 days.
11740.

Which one of the following statements is not equiva- lent to p rarr( q vee r ) ?

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`( p rarr Q ) VEE ( p rarr R ) `
`P ^^ ( ~ q ) rarr r `
`p ^^ ( ~ r) rarr q `
`p ^^ q rarr ( p ^^ r) vee ( q ^^ r)`

Answer :D
11741.

(1^(3))/(1!)+(2^(3))/(2!)+(3^(3))/(3!)+(4^(3))/(4!)+....=

Answer»

e
3e
5e
`e//5`

ANSWER :C
11742.

If joint equation of two lines through the origin, each making an angle theta with the line x+y=0 is x^(2)+2hxy+y^(2)=0 then h=

Answer»

`SEC 2 theta`
`-sec 2 theta`
`TAN 2 theta`
`-TAN2 theta`

Answer :A
11743.

If alpha, beta, gamma in {1,omega,omega^(2)} (where omega and omega^(2) are imaginery cube roots of unity), then number of triplets (alpha,beta,gamma) such that |(a alpha+b beta+c gamma)/(a beta+b gamma+c alpha)|=1 is

Answer»

`3`
`6`
`9`
`12`

Solution :`(C )` As `|(aalpha+bbeta+cgamma)/(a beta+bgamma+calpha)|=1`
`implies` When `ALPHA`, `beta`, `gamma` are different, then number of triplet `(alpha,beta,gamma)=` permutation of `1`, `omega` and `omega^(2)=6` and when `alpha-beta=gamma`, number of TRIPLETS `=3`.
11744.

Evalute the following integrals int tan (x - theta) tan x (x + theta)tan 2x dx

Answer»


Answer :`(1)/(2)` log |sec 2X | - log | sec `(X + theta)` | - log | sec `(x - theta)` | + C
11745.

Consider the system of equations x cos^(3) y+3x cos y sin^(2) y=14 x sin^(3) y+3x cos^(2) y sin y=13 The number of values of y in [0, 6pi] is

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5
3
4
6

Solution :The given equations are
`x cos^(3)y+3x cos y sin^(2) y=14` ...(i)
and `x sin^(2) y+3x cos^(2) y sin y=13` ...(ii)
Adding EQS. (i) and (ii), we have
`x(cos^(3) y+3 cos y sin^(2) y+3 cos^(2) y sin y+ sin^(3) y)=27`
or `x(cos y+ sin y)^(3)=27`
or `x^(1//3) (cos y + sin y) =3` ...(iii)
Subtracting Eq. (ii) from Eq. (i), we have
`x(cos^(3)y+3 cos y sin^(2) y-3 cos^(2) y sin y- sin^(3) y)=1`
or `x(cos y- sin y)^(3)=1`
or `x^(1//3) (cos y- sin y)=1` ...(iv)
Dividing Eq. (iii) by (iv), we get
`cos y+sin y=3 cos y-3 sin y`
or `tan y=1//2`
Case I :
`sin y=1//SQRT(5) and cos y =2//sqrt(5)`
`y=2n pi +alpha`, where `0 lt alpha lt pi//2` and `sin alpha =1//sqrt(5)`
i.e., y lies in the first quadrant
From Eqs. (iii) `x^(1//3) (3//sqrt(5))=3 or x=5 sqrt(5)`
Case II :
`sin y=-1//sqrt(5) and cos y=-2//sqrt(5)`
`y=2npi+(pi+alpha)`, where `0 lt alpha lt pi//2`
and `sin alpha = -1 //sqrt(5)`
i.e., y lies in the third quadrant.
Therefore, from Eq. (iii), `x^(1//3) (-3//sqrt(5))=3 or x=-5sqrt(5)`.
Thus, `sin^(2) y+2 cos^(@) y=1//5+8//5=9//5`.
ALSO there are exactly six VALUES of `y in [0, 6pi]`, there in 1ST quadrant and three in 3rd quadrant.
11746.

Evaluate the following integral int (cos 7x - cos 8x )/(1 + 2 cos 5x) dx

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Answer :`(sin 2X)/(2) - (sin 3x)/(3) + C `
11747.

Solve x^4-5x^3+5x^2+5x-6 =0 given that the product of two of its roots is 3

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ANSWER :`+- 1,2,3`
11748.

(1+3)log_e3+(1+3^2)/(2!) (log_e3)^2+(1+3^3)/(3!) (log_e3)^3+.....oo =

Answer»

27
28
32
57

Answer :B
11749.

Integrate : int (logsqrt(x))^(2)dx

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Answer :`(X)/(4)[(LOGX)^(2)-2logx+2]+C`
11750.

if A_(1) ,B_(1),C_(1) ……. arerespectivelythecofactorsof theelementsa_(1) ,b_(1),c_(1)…… ofthe determinant Delta = |{:(a_(1),,b_(1),,c_(1)),(a_(2),,b_(2),,c_(2)),(a_(3),,b_(3),,c_(3)):}|, Delta ne 0then the value of|{:(B_(2),,C_(2)),(B_(3),,C_(3)):}| is equal to

Answer»

`a_(1)^(2)Delta`
`a_(1)Delta`
`a_(1)Delta^(2)`
`a_(1)^(2)Delta^(2)`

SOLUTION :`B_(2) =a_(1)c_(3) -a_(3)c_(1),C_(2)=-(a_(1)b_(3)-a_(3)b_(1))`
`B_(3) =-(a_(1)C_(2) -a_(2)c_(1)) ,C_(3)=a_(1)b_(2)-a_(2)b_(1)`
` :. |{:(B_(2),,C_(2)),(B_(3),,C_(2)):}|= |{:(a_(1)C_(3)-a_(3)c_(1),,-a_(1)b_(3)+a_(3)b_(1)),(-a_(1)c_(2)+a_(2)c_(1),,a_(1)b_(1)-a_(2)b_(1)):}|`
`=|{:(a_(1)c_(3),,-a_(1)b_(3)),(-a_(1)c_(2),,a_(1)b_(2)):}|+ |{:(a_(1)C_(3),,a_(3)b_(1)),(-a_(1)c_(2),,-a_(2)b_(1)):}|`
`+|{:(-a_(3)C_(1),,-a_(1)b_(3)),(-a_(1)C_(2),,a_(1)b_(2)):}|+ |{:(-a_(3)C_(1),,a_(3)b_(1)),(a_(2)c_(1),,-a_(2)b_(1)):}|`
` =a_(1)^(2) |{:(C_(3),,-b_(3)),(-c_(2),,b_(2)):}|+a_(1)b_(1) |{:(c_(3),,a_(3)),(-c_(2),,-a_(2)):}|`
`+a_(1)c_(1) |{:(-a_(3),,-b_(3)),(a_(2),,b_(2)):}|+b_(1)c_(1) |{:(-a_(3),,a_(3)),(a_(2),,-a_(2)):}|`
`=a_(1){a_(1)(b_(2)c_(3)-b_(3)c_(2))-b_(1)(a_(2)c_(3)-a_(3)c_(2))`
`+c_(1)(a_(2)b_(3)-a_(3)b_(2))}`
` =a_(1)|{:(a_(1),,b_(1),,c_(1)),(a_(2),,b_(2),,c_(2)),(a_(3),,b_(3),,c_(3)):}| =a_(1) Delta`