InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11701. |
If a function is invertible the graph of its inverse is the mirror image of the function in y=x. If f^(-1)(x) is the inverse function of f(x), then f(f^(-1)(x))=f^(-1)(f(x))=x. If f(x)=ln[((100+x)e^(x^(3)))/((100-x))], then the graph of f^(-1)(x) will be symmetrical about x+y=1 |
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Answer» `x+y=1` |
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| 11702. |
Show that the function f defined by f(x)={(x if "x is rational"),(-x if "x is irrational"):} is continuous at x=0 AAxne0inR |
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Answer» Solution :f(0)=0 L.H.L=`lim_(xto0)f(x)=lim_(hto0)f(-h)` `=lim_(hto0){(-h if "h is RATIONAL" =0),(h if "h is irrational"):}` Similarly R.H.L.=0 THUS L.H.L.=R.H.L.=f(0) Hence f(x) is continuous at x=0 We can easily show that f(x) is discontinuous at all real POINTS `xne0` |
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| 11703. |
A box contain 6 tickets. Two of the tickets carry a price of Rs 5/- each and the other 4 are the price of Rs 1 each. If one ticket is drawn at random, what is the mean price. |
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| 11704. |
A : The value of (Tan^(-1)(4//3))/(Tan^(-1)(1//2)) is equal to 2. R : AAx in[0,1],Tan^(-1)((2x)/(1-x^(2)))=2Tan^(-1)x |
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Answer» Both A and R are TRUE and R is the CORRECT EXPLANATION of A |
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| 11705. |
A box has 100 pens of which 10 are defective. The probability that out of a sample of 5 pens drawn one by one with replacement and atmost one is defective is |
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Answer» `a.(9)/(10)` |
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| 11706. |
The radius of the director circle of the hyperbola x^2//25-y^(2)//9=1 is |
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Answer» 3 |
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| 11707. |
Find the roots of the following cubic equations 2x^(3)-3x^(2) cos (A-B)-2 x cos^(2) (A+B)+ sin 2A sin 2 B cos (A-B)=0 . |
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| 11708. |
If A={a,b,c,d} mention the type of relations on A given below, which of them are equivalence relations?{(b,c),(b,d),(c,d)} |
| Answer» SOLUTION :Only TRANSITIVE | |
| 11709. |
The radical axis of two circles whose centres are ( 3,4), (-1,2) and each passing through the centre of the other is |
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Answer» ` 2X+ y +5=0 ` |
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| 11711. |
When the coordinate axes ar rotated about the origin in the positive direction through an angle pi/4, IF the equation 25x^2+9y^2=225 is transformed to ax^2+betaxy+ygamma^2=delta, then (alpha+beta+gamma-sqrtdelta)^2= |
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Answer» 3 |
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| 11712. |
Let ABCD is a rectangle with AB=a & BC=b & circle is drawn passing through A & B and touching side CD. Another circle is drawn passing through B & C and touching side AD. Let r_(1) & r_(2) be the radii of these two circle respectively. Minimum value of (r_(1)+r_(2) equals |
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Answer» `5/8 (a-b)` `AP_(1)=a//2` `r_(1)^(2)=x_(1)^(2)+(a/2)^(2)=(b-x_(1))^(2)` `x_(1)^(2)+(a^(2))/4=b^(2)+x_(1)^(2)-2bx_(1)` `x_(1)=(4b^(2)-a^(2))/(8b)` `r_(1)=b-x_(1)=(4b^(2)+a^(2))/(8b)` SIMILARLY `r_(2)=(4A^(2)+b^(2))/(8a)` `r_(1)+r_(2)=(a^(3)+b^(3)+4ab(a+b))/(8AB)` `implies((a+b)(a^(2)+3ab+b^(2)))/(8ab)` `=((a+b)/8)([(a-b)^(2)+5ab])/(AB)` But `(a-b)^(2)ge0` `r_(1)+r_(2)GE((a+b))/8.(5ab)/(ab)` `impliesr_(1)+r_(2)ge(5(a+b))/8` |
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| 11713. |
A bag contains 10 white and 15 black balls. The balls are drawn one at a time until only those of the same colour are left. Show that the probability that they are all black is 3/5. |
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| 11714. |
Find mean of following probability distribution. |
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| 11715. |
The solution of (x+y)^(2)(dy)/(dx) = a^(2) is |
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Answer» `y = TAN^(-1)((X+y)/(a)) + C` |
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| 11716. |
Let A=[{:(1,-2,1),(-2,3,1),(1,1,5):}] Verify that (A^(-1))^-1=A |
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| 11717. |
Statement:1 In triangleABC, if a lt b sinA, then the triangle is possible. And Statement:2 In triangleABC a/(sinA)= b/(sinB) |
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Answer» Statement-1 is TRUE, Statement-2 is true, Statement-2 is a CORRECT EXPLANATION for statement-16 |
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| 11718. |
The volume of the tetrahedron formed by the coterminous edges veca, vecb, vec c is 3. Then the volume of the parallelopiped formed by the coterminous edges veca+vecb, vecb+vec c, vec c+ veca is |
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Answer» 36 `[veca vecb vec c]=18` `"VOL. of parallelopiped"=[veca+vecb""vecb+vec c""vec c + a]` `=2[veca vecb vec c]=2xx18=36` |
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| 11719. |
Let A(2sec theta, 3 tan theta ) and B( 2sec phi ,3 tan phi ) where theta + phi =(pi)/(2)be two point on the hyperbola(x^(2))/( 4) -( y^(2))/( 9) =1 . If (alpha , beta )is the point of intersection of normals to the hyperbola at A and B ,then beta = |
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Answer» `- (13)/(3)` |
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| 11720. |
Let the smallest positive value of x for which the functionf(x)=sin""(x)/(3)+sin""(x)/(11), ( x in R ) achieves its maximum value bex_(0). Express x_(0) in degree i.e.x_(0)=alpha^(0). Then , the sum of the digits inalphais |
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Answer» 15 |
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| 11721. |
If1 , omega , omega^(2) are the cube roots of unity , then find the values of the following . (a+ b)^(3) + ( a omega + bomega ^(2))^(3) + ( a omega^(2) + b omega)^(3) |
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| 11723. |
If the area of the parallelogram whose adjacent sides are (3i + 4j + lambda K) and (2j - 4k) is sqrt(436) square units, and lambda ge 0, then lambda = |
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Answer» 0 |
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| 11724. |
Find the equation of a curve passing through the point (-2,3), given that the slope of the tangent to the curve at any point (x,y) is (2x)/(y^(2)). |
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| 11725. |
A point is taken at random from inside of the circumcircle of an equilateral triangle. The probability that it lies inside the circumcircle but outside the incircle is |
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Answer» `1//4` |
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| 11726. |
Let A=NxxN Define * on A by (a,b)*(c,d)=(a+c,b+d) Show that (i) A is closed for * (ii) * is commutative (iii) * is associative (iv) identify element does not exist in A |
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Answer» Solution :(i) Let (a,b) in A and (c,d) inA Then a,b,c d in N `(a,b)*(c,d)=(a+c,b+d)in A`[before a+c in N, b +d `in` N] `therefore` A is CLOSED for* (a,b)*(c,d)=(a+c,b+d) `=(c+a,d+b) ["before" a+c=c+a and b+d=d+b]` =(c,d)*(a,b) (III)(a,b)*(c,d)*(e,F)=(a+c,b+d)*(e,f) =[(a+c)+e,(b+d)+f] =([a+(c+e),b+(d+f)] =(a,b)*[(c,de,d+f) `=(a,b)*[(c,d)*(e,f)]` (IV) (a,b)*(0,0)=(a+0,b+0)=(a,b) But ,(0,0)`ne` A since one N So identity element does not BELONG to A |
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| 11727. |
Let I =int _(0)^(1 ) sqrt((1+sqrtx)/(1-sqrtx))dx and J = int _(0)^(1 ) sqrt((1-sqrtx)/(1+sqrtx))dxthen correct statement (s) is/are: |
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Answer» `I+J=2` |
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| 11728. |
A body is thrown horizontally with a velocity of v m/s from the top of a tower of height 2h reaches the ground in 't' seconds. If another body double the mass is thrown horizontally with a velocity 5v m/s from the top of another tower of height 8h. In the above problem if the first reaches the ground at a horizontal distance 'x' the second body reaches the ground at a horizontal distance |
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Answer» 1 |
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| 11729. |
IfDelta = {:[( a_11, a_12, a_13),( a_21,a_22,a_23) ,(a_31,a_32, a_33) ]:} andis Cofactors of a_ijthen value of Deltais given by |
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Answer» ` a_11 A_31+ a_12A_32+a_13A_33` |
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| 11730. |
Let k denote the number of ways in n boys sit in a row such that three particular boys are repeated. Then |
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Answer» 3! Divides K |
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| 11731. |
Evaluate the following integrals : int_(0)^(pi/2)(dx)/(4sin^(2)x+5cos^(2)x) |
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| 11732. |
Show that |{:(a,b,c),(a^(2),b^(2),c^(2)),(a^(2),b^(3),c^(3)):}|=abc(a-b)(b-c)(c-a) |
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| 11733. |
A straight line through the point (2, 2) intersects the lines sqrt3 x + y = 0 and sqrt3 x - y = 0 at the points A and B. The equation of AB so that the triangle OAB is equilateral, where O is the origin. |
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Answer» X - 2 = 0 |
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| 11734. |
findthe areaboundedby thecurvey=2 cos xandtheX- axisfromx=0tox = 2 pi |
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| 11735. |
The number of values of x in [0,4pi] satisfying |sqrt(3cosx - sinx )| gt=2 is : |
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Answer» 2 |
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| 11736. |
Two adjacent sides of a parallelogram are 4x+5y=0,and 7x+2y=0. Area of the parallelogram is |
| Answer» ANSWER :A | |
| 11737. |
If y=f(x) is the solution of differential equation , e^y((dy)/(dx)-2)=e^(3x) such that f(0)=0 , then f(2) is equal to : |
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Answer» 3 I.F. =`e^(INT -2dx) =e^(-2x)` `t.e^(-2x) = int e^(3x). E^(-2x) dx` `t.e^(-2x) = inte^X dx= e^x +c , e^y e^(-2x) =e^x + c` Put x=0 ,y=0 we get `e^0 .e^0 =1+c` `rArr e^y e^(-2x)= e^x` `e^y =e^(3x) rArr y=3x rArr f(x)=3x` |
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| 11738. |
If tanA+sinA=p and tanA-sinA=q, then the value of ((p^(2)-q^(2))^(2))/(pq) is : |
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Answer» 16 |
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| 11739. |
A company manufactures the bicycle with gears and without gears in two different factories. The factory A produces 16 bicycles without gears and 20 bicycles with gears in a day. The factory B produces 12 bicycles without gears and 20 bicycles with gears in a day. The expenditure of factory A is Rs. 50,000 daily and the expenditure of factory B is Rs. 40,000 daily. A company has ordered for 96 bicycles without gears and 140 bicycles with gears. To complete these order, how many days the factories will work so that there is minimum expenditure ? |
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| 11740. |
Which one of the following statements is not equiva- lent to p rarr( q vee r ) ? |
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Answer» `( p rarr Q ) VEE ( p rarr R ) ` |
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| 11742. |
If joint equation of two lines through the origin, each making an angle theta with the line x+y=0 is x^(2)+2hxy+y^(2)=0 then h= |
| Answer» Answer :A | |
| 11743. |
If alpha, beta, gamma in {1,omega,omega^(2)} (where omega and omega^(2) are imaginery cube roots of unity), then number of triplets (alpha,beta,gamma) such that |(a alpha+b beta+c gamma)/(a beta+b gamma+c alpha)|=1 is |
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Answer» `3` `implies` When `ALPHA`, `beta`, `gamma` are different, then number of triplet `(alpha,beta,gamma)=` permutation of `1`, `omega` and `omega^(2)=6` and when `alpha-beta=gamma`, number of TRIPLETS `=3`. |
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| 11744. |
Evalute the following integrals int tan (x - theta) tan x (x + theta)tan 2x dx |
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| 11745. |
Consider the system of equations x cos^(3) y+3x cos y sin^(2) y=14 x sin^(3) y+3x cos^(2) y sin y=13 The number of values of y in [0, 6pi] is |
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Answer» 5 `x cos^(3)y+3x cos y sin^(2) y=14` ...(i) and `x sin^(2) y+3x cos^(2) y sin y=13` ...(ii) Adding EQS. (i) and (ii), we have `x(cos^(3) y+3 cos y sin^(2) y+3 cos^(2) y sin y+ sin^(3) y)=27` or `x(cos y+ sin y)^(3)=27` or `x^(1//3) (cos y + sin y) =3` ...(iii) Subtracting Eq. (ii) from Eq. (i), we have `x(cos^(3)y+3 cos y sin^(2) y-3 cos^(2) y sin y- sin^(3) y)=1` or `x(cos y- sin y)^(3)=1` or `x^(1//3) (cos y- sin y)=1` ...(iv) Dividing Eq. (iii) by (iv), we get `cos y+sin y=3 cos y-3 sin y` or `tan y=1//2` Case I : `sin y=1//SQRT(5) and cos y =2//sqrt(5)` `y=2n pi +alpha`, where `0 lt alpha lt pi//2` and `sin alpha =1//sqrt(5)` i.e., y lies in the first quadrant From Eqs. (iii) `x^(1//3) (3//sqrt(5))=3 or x=5 sqrt(5)` Case II : `sin y=-1//sqrt(5) and cos y=-2//sqrt(5)` `y=2npi+(pi+alpha)`, where `0 lt alpha lt pi//2` and `sin alpha = -1 //sqrt(5)` i.e., y lies in the third quadrant. Therefore, from Eq. (iii), `x^(1//3) (-3//sqrt(5))=3 or x=-5sqrt(5)`. Thus, `sin^(2) y+2 cos^(@) y=1//5+8//5=9//5`. ALSO there are exactly six VALUES of `y in [0, 6pi]`, there in 1ST quadrant and three in 3rd quadrant. |
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| 11746. |
Evaluate the following integral int (cos 7x - cos 8x )/(1 + 2 cos 5x) dx |
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| 11747. |
Solve x^4-5x^3+5x^2+5x-6 =0 given that the product of two of its roots is 3 |
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| 11748. |
(1+3)log_e3+(1+3^2)/(2!) (log_e3)^2+(1+3^3)/(3!) (log_e3)^3+.....oo = |
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Answer» 27 |
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| 11750. |
if A_(1) ,B_(1),C_(1) ……. arerespectivelythecofactorsof theelementsa_(1) ,b_(1),c_(1)…… ofthe determinant Delta = |{:(a_(1),,b_(1),,c_(1)),(a_(2),,b_(2),,c_(2)),(a_(3),,b_(3),,c_(3)):}|, Delta ne 0then the value of|{:(B_(2),,C_(2)),(B_(3),,C_(3)):}| is equal to |
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Answer» `a_(1)^(2)Delta` `B_(3) =-(a_(1)C_(2) -a_(2)c_(1)) ,C_(3)=a_(1)b_(2)-a_(2)b_(1)` ` :. |{:(B_(2),,C_(2)),(B_(3),,C_(2)):}|= |{:(a_(1)C_(3)-a_(3)c_(1),,-a_(1)b_(3)+a_(3)b_(1)),(-a_(1)c_(2)+a_(2)c_(1),,a_(1)b_(1)-a_(2)b_(1)):}|` `=|{:(a_(1)c_(3),,-a_(1)b_(3)),(-a_(1)c_(2),,a_(1)b_(2)):}|+ |{:(a_(1)C_(3),,a_(3)b_(1)),(-a_(1)c_(2),,-a_(2)b_(1)):}|` `+|{:(-a_(3)C_(1),,-a_(1)b_(3)),(-a_(1)C_(2),,a_(1)b_(2)):}|+ |{:(-a_(3)C_(1),,a_(3)b_(1)),(a_(2)c_(1),,-a_(2)b_(1)):}|` ` =a_(1)^(2) |{:(C_(3),,-b_(3)),(-c_(2),,b_(2)):}|+a_(1)b_(1) |{:(c_(3),,a_(3)),(-c_(2),,-a_(2)):}|` `+a_(1)c_(1) |{:(-a_(3),,-b_(3)),(a_(2),,b_(2)):}|+b_(1)c_(1) |{:(-a_(3),,a_(3)),(a_(2),,-a_(2)):}|` `=a_(1){a_(1)(b_(2)c_(3)-b_(3)c_(2))-b_(1)(a_(2)c_(3)-a_(3)c_(2))` `+c_(1)(a_(2)b_(3)-a_(3)b_(2))}` ` =a_(1)|{:(a_(1),,b_(1),,c_(1)),(a_(2),,b_(2),,c_(2)),(a_(3),,b_(3),,c_(3)):}| =a_(1) Delta` |
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