Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Three particles of identical masses 'm' are kept at the vertices of an equilateral triangle of each side length 'a'. Find the gravitational force of attraction on any one of the particles.

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Solution :Let `F_(A)` and `F_(B)` be the forces due to the masses at A and B on the mass at C.
Here `F_(A) = F_(B)`
Hence the resultant force on the mass at C `""F = 2F_(A) COS""(theta)/(2)`
`= 2.(GM^(2))/(a^(2)) cos 30^(@) = 2 xx (Gm^(2))/(a^(2)) xx (sqrt(3))/(2) -sqrt(3)(Gm^(2))/(a^(2))`
2.

Statement I: A reference frame attached to the earth is an inertial frame of reference. Statement II: The reference frame which has zero acceleration is called a inertial frame of reference.

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STATEMENT I is TRUE, statement II is true, statement II is a correct explanation for statement I.
Statement I is true, statement II is true, statement II is not a correct explanation for statement I.
Statement I is true, statement II is false.
Statement I is false, statement II is true.

Answer :D
3.

A body of mass 10 kg and radius 0.5 m is moving in a circular path. The rotational kinetic energy of the body is 32.8 J. Radius of gyration of the body is

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0.25 m
0.2 m
0.5 m
0.4 m

ANSWER :D
4.

A thin metal disc of radius 'r' floats on water surface bends the surface downwards along the perimeter making an angle theta with vertical edge of the disc. If the disc displaces a weight of water W and surface tension of water is T, then the weight of metal disc is

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`2 pi R T + W`
`2 pi r T cos theta - W`
`2 pi r T cos theta + W`
`W - 2PI r T cos theta`

ANSWER :C
5.

Who made these remarks : 'time is what a clock rads'.

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NEWTON
Einstein
CV Raman
none of these

Answer :(B)
6.

The position of a particle is given byr=3.0thati+2.0t^(2)hatj+5,0hatkwhere t is in seconds and the coefficients have the proper units for r to be in matres. (a) Find v (t) and a(t) of the particle . (b) Findthe magnitude and direction of v (t) at t=1.0 s.

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Solution :`V(t)=(DR)/(dt)=(d)/(dt)(3.0thati+2.0t^(2)hatj+5.0hatk)`
`=3.0hati+4.0thatj`
a `(t)=(dv)/(dt)=+4.0hatj`
`a=4.0 "m s"^(-2)` along y- direction
At t=1.0s, `v=3.0hati+4.0hatj`
It .s magnitude is `v=sqrt(3^(2)+4^(2))=5.0 " m s"^(-1)`and direction is
`theta=tan^(-1)((v_(y))/(v_(X)))=tan^(-1)((4)/(3))~=53^(@)`with x - axis.
7.

The period of a satellite in circular orbit of radius R is T. The period of an other satellite in a circular orbit of radius 4R is

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4T
`T//4`
8T
`T//8`

ANSWER :C
8.

A uniform rod of mass m, length L, area of cross-section A and Young.s modulus Y hangs from the ceiling. Its elongation under its own weight will be (MCQ)

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ZERO
`(MGL)/(2AY)`
`(mgL)/(AY)`
`(2mgL)/(AY)`

ANSWER :2
9.

A satellite in its orbit around the earth is weight less on account of its ……………………

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momentum
acceleration
speed
none

Answer :B
10.

What physical change occurs when source of sound waves is at rest and the listener moves?

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SOLUTION :The number of SOUND WAVES RECEIVED by the listener changes.
11.

A tuning fork is used to produce resonance in a glass tube. The length of the air column in this tube can be adjusted by a variable piston. At room temperature of 27 ^(@)C two successive resonance are produced at 20 cm and 73 cm of column length. If the frequency of the tuning fork is 320 Hz, the velocity of sound in air at 27^(@) C is

Answer»

`300 m//s`
`330 m//s`
`350 m//s`
`339 m//s`

Solution :We have `f _(1) = (v)/(2L)`
TAKING `L = L _(2) ` we get, `f _(1) = (v)/(2 (L _(2) - L _(1)))`
`THEREFORE v = 2F _(1) (L_(2) -L_(1))`
`= 2 xx 320 xx (0.73 -0.20)`
`= 339.2 m//s`
`~~ 339 m//s`
12.

The density of a planet is rhoThe orbital period of a satellite revolving around it with remaining close to its surface is ..........

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`((3pi)/(Grho))^(3/2)`
`((3pi)/(Grho))^(1/2)`
`((3pi)/(2Grho))^(3/2)`
`((3pi)/(2Grho))^(1/2)`

Solution :`implies` For planetary motion
centripetal force = Gravitational force between planet and satellite
`(mv^2)/R = (GMm)/(R^2)`
`:.v = ((GM)/R)^(1/2)`
`"Rw" = ((GM)/R)^(1/2)"" [ :. v = "rw"]`
but , M = VOLUME `v xx` density `rho`
`=4/3 piR^3 rho`
`:. Rw=((G xx4/3piR^3rho)/R)1/2`
`:. w = (4/3 PI Grho)^(1/2)`
`:. T = (2pi)/w=(2pi)/((4/3piGrho)^(1/2))`
`:. T = ((3pi)/(Grho))^(1/2)`
13.

What is the pressure inside the drop of mercury of radius 3.00 mm at room temperature (20"^(@)C)is 4.65xx10^(-1)Nm^(-1).The atmospheric pressure is 1.01xx10^(5) Pa. Also give excess pressure inside the drop.

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Solution :Drop of MERCURY has one FREE surface,
`thereforeP_(i)-P_(o)=(2S)/(r)`
`P=(2S)/(r)`
`=(2xx4.65xx10^(-1))/(3xx10^(-3))`
`=310Pa`
`thereforeP_(i)-P_(o)=P`
`thereforeP_(i)=P_(o)+P`
`=1.01xx10^(5)+310`
`=1.01xx10^(5)+0.00310xx10^(5)`
`=1.01310xx10^(5)`
Correct UPTO three significant figures,
`P_(i)=1.01xx10^(5)Pa`
14.

A vector barQ which has a magnitude of 8 is added to the vector barp which lies along the X-axis. The resultant of these two vectors is a third barR which lies along the Y-axis and has a magnitude twice that of barP. The magnitude of barP is

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ANSWER :`8/(SQRT(5))`
15.

A horizontal disc is freely rotating about a vertical axis passing through its centre at the rate of 100 rpm. A bob of wax of mass 20 g falls on the disc and sticks to it a distance of 5 cm from the axis. If the moment of inertia of the disc about the given axis is 2xx10^(-4)kg m^(2) find new frequency of rotation of the disc.

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Solution :`I_(1)=` Moment of inertia of the disc `= 2xx10^(-4)kgm^(2)`
`I_(2)=` Moment of inertia of the disc + Moment of inertia of the BOB of WAX on the disc.
`=2xx10^(-4)+mr^(2)=2xx10^(-4)+20xx10^(-3)(0.05)^(2)`
`= 2xx10^(-4)=2.5xx10^(-4)kgm^(2)`
`(n//t)_(1)=100` rpm , `(n//t)_(2)= ?`
By the PRINCIPLE of CONSERVATION of angular momentum,
`I_(1)omega_(1)=I_(2)omega_(2) "" I_(1)2pi((n)/(r))_(1)=I_(2)2pi((n)/(t))_(2)`
`2xx10^(-4)xx100=2.5xx10^(-4)((n)/(t))_(2)`
`((n)/(t))_(2)=(100xx2)/(2.5)=80` rpm.
16.

One of the combination from the fundamental physical constants is hc//G. The unit of this expression is

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`KG^(2)`
`m^(3)`
`s^(-1)`
none of these

Solution :`(HC)/(G)= ((Js)(MS^(-1)))/(NM^(2)kg^(-2))= ((Nm s)(ms^(-1)))/(Nm^(2)kg^(-2))= kg^(-2)`
17.

A block is placed on rough floor and a horizontal force F is applied on it. The force of friction f by the floor on the block is measured for diffeent values of F and a graph is plotted between them(a) The graph is straight line of slope 45^(@)(b) The graph is straight line parallel to the F - axis.(c ) The graph is straight line of slope 45^(@) for small F and a straight line parallel to the F - axis for large F.There is a small kink on the graph.

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a and C are TRUE
a, B and d are true
c and d are true
all are true

ANSWER :C
18.

An ideal gas or a perfect gas is that which strictly obeys the gas laws (such as Boyle's Law, Charle's Law etc.) Two essential characteristics of an ideal gas are : (i) size of molecule of an ideal gas is zero. (ii) There is no force of attraction or reputation amongst the moleculess of an ideal gas. In view of this, no real gas is perfect. Read the above passage and answer the following questions : (i) Under what conditions do same real gases behave as nearly perfect gases ? What does this concept imply in day to day life ?

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Solution :(i) At extremely LOW pressure and high temperature, some REAL gases like helium, hydrogen, OXYGEN, etc. Behave as nearly perfect gases.
(ii) in day to day life, this concept impliesthat none of us is perfect. Only rarest of the rate who has PRACTISED totalrenunciation can be taken as nearly perfect. such a person has REDUCED his size to zero, as he has merged himself with God Almighty . He has no individual identity and there is no question of force of attractions (raga) and repulsion(dwesha) with respect to him.
19.

The radius of gyration of a solid sphere of radius about a certain axis is r. The distance of that axis from the centre of the sphere is

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`(2)/(5)r`
`sqrt((2)/(5))r`
`sqrt(0.6)r`
`sqrt((5)/(3))r`

Solution :From parallel AXIS theorem `I=I_(C)+Md^(2)`
`:. mr^(2)=(2)/(5)mr^(2)+Md^(2)`
`d= sqrt((3)/(5))r= sqrt(0.6)r`
20.

A simple harmonic oscillator has a time period of 2 sec. The change in phase 0.5 sec after leaving the mean position is in radian

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`PI`
`(pi)/(2)`
`(pi)/(3)`
`(pi)/(4)`

ANSWER :B
21.

(A): In rolling, all points of a rigid body have the same linear speed. (R) : The rotational motion donot change the linear velocity of rigid body.

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Both .A. and .R. are TRUE and .R. is the CORRECT EXPLANATION of .A.
Both .A. and .R. are true and .R. is not the correct explanation of .A.
A. is true and .R. is FALSE
.A. is false and .R. are true

Answer :D
22.

A ray of light passes through an equilateral prism in such a manner that the angle of incidance is equal to the angle of emergence of each of these angles equal to 3//4of angle of the prism. The angle of deviation is

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`45^@`
`39^@`
`60^@`
`30^@`

ANSWER :D
23.

A body moves along a circular path of radius 1m & mu = 0.4. The maximum angular velocity in rad/sec of the body so that it does not slide is (g=10 ms^(-2))

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2
30
15
4

Answer :A
24.

Mention any two arbitrary initial conditions in order to determine the linear simple harmonic motion .

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Solution :Initial position and VELOCITY or amplitudeand PHASE or energy and phase are two ARBITRARY initial CONDITIONS to determine SHM SUFFICIENTLY.
25.

How doesthe change of acceleration due to gravity affect the path of a projectile ?

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Solution :The locus of a PROJECTILE is denoted by
`y=xtan alpha-(G)/(2u^2 cos^2alpha)x^2` ….(1)
Let U and `alpha` be constants.

Now from equation (1) we can say that both the maximum height and the HORIZONTAL range of a projectile decrease with increasing g. In this case, the locus of the projectile is shown by line a [Fig.2.76]
On the other hand , both the quantities INCREASE with decreasingg. In this case, the locus of the projectile is shown by line b [Fig.2.76].
26.

Albert Einstein, the greastest scientist of all times once remarked : 'The most incomprehensible thing about the world is that it is comprehensible.' Another famous philosopher Bertrand Russel once commented 'We know very little and yet it is astonsihing that we know so much, and still more astonishing that so little knowledge (of science) can giveus so much power.' Read the above paragraph and answer the following questions : (i) Are the two remarks identical ? What is the underlying basis of the two remarks ? (ii) How do these remarks apply in day to day life ?

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Solution :(i) Yes, the TWO remarks are identical. Both the remarks are based on a simple fact that the BEHAVIOUR of everything in this vast universe is governed by a few laws, which are well defined and well understood.
(ii) God created all inert thing in the universe and also the human beings. Just as behaviour of inert THINGS is governed by a few laws only , all human beings are also governed by a few simple principles. For example : As you harvest, so you reap. Do good. Those who live in glass HOUSES should not throw stones on others, and so on. These simple principles APPLY equally to all human beings.
27.

The waves produced by a motor boat sailing in water are

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TRANSVERSE
LONGITUDINAL
longitudinal and transverse
STATIONARY

ANSWER :C
28.

A small coin is placed on a flat horizontal turn table. The turn table is observed to make three revolutions in 3.14 sec. What is the coefficient of static friction between the coin and turn table if the coin is observed to slide off the turn table when it is greater than 10cm from the centre of turn table

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0.4
0.36
4
0.004

Solution :`f=mromega^(2), f=mumg`
29.

Two bodies move towards each other and collide inelastically. The velocity of the first body before impact is 2m/s and of the second is 4m/sec. The common velocity after collision is 1m/s in the direction of the first body. By how many times did the K.E. of the first body exceed that of the second body before collision?

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ANSWER :`1.25`
30.

From a given sample of uniform wire, two circular loops moment of inertia of O about its axis is 4 times that of P about its axis (assuming wire diameter much smaller, than either radius), the value of n is

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`(4)^(2//3)`
`(4)^(1//3)`
`(4)^(1//2)`
`(4)^(1//4)`

Solution :Given `I_(Q) = 4 I_(P)`
Here I = mass `XX "(radius)"^(2)`
If `MU` be the linear mass density (mass/length) of the wire , then `mu xx 2pi (n r) xx n^(2) r^(2) = 4 (mu xx 2pi r xx r^(2))`
On SOLVING , we get `n^(3) = 4` or `n = (4)^(1//3)`
31.

Which of the following pairs does not have similar dimensions?

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Stress and PRESSURE
Tension and surface tension
Angle and strain
Planck's constant and ANGULAR momentum

Solution :Tension is force and surface tension is `"force"//"LENGTH"`.So they do not have the same DIMENSIONS.
32.

Water is allowed to flow through a capillary tube of length 10cm and diameter 2 mm under a constant pressure difference of 6.5 cm of water level. If 0.16 litres of water flows in 1 minute, its coefficient of viscosity is,

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`0.00937` POISE
`0.0937` poise
`0.000937` poise
`0.937` poise

ANSWER :C
33.

What will be percentage decrease in weight of body when taken to the depth of 64 km below the surface of earth ?

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SOLUTION :`g. = g(1-(d)/(R ))`
`g. - g = (-GD)/(R )`
`g - g. = (gd)/(R )`
PERCENTAGE DECREASE in weight `= ((mg - mg.)/(mg))XX 100`
`= ((g-g.)/(g)) xx 100`
`= (gd)/(Rg) xx 100`
`= (d)/(R ) xx 100`
`= (64)/(6,400) xx 100`
= 1%
34.

Regarding elasticity which of the following statements are correct? a) the point where the elasticity ends and plasticity starts is called yield point b) breaking stress depends on the area of cross section c) the value of poisons ratio can not be greater than 0.5 d) air is more elastic than water

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a, B are correct
a, C are correct
b, d are correct
a and d are correct

Answer :2
35.

Ten moles of an ideal gas at constant temperature 600 K is compressed from 100l to 10L. The work done in the process is ……………. .

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`4.11xx10^(4)J`
`-4.11xx10^(4)J`
`11.4xx10^(4)J`
`-11.4xx10^(4)J`

SOLUTION :The process is isothermal. The work DONE is
`W=nRT ln ((V_(2))/(V_(1)))=2.3026xx10xx8.3xx600xxlog_(10)((10)/(100))rArr W=-11.4xx10^(4)J`
36.

Two bodies of masses m, and m, have equal momentum. Their K.E. are in the ratio

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`SQRT(m_(2)):sqrt(m_(1))`
`m_(1):m_(2)`
`m_(2):m_(1)`
`m_(1)^(2):m_(2)^(2)`

ANSWER :C
37.

A boy performs an experiment in which he uses a simple pendulum to find the value of 'g' using the formula g=(4pi^(2)l)/(T^(2))= Where l = 1m. Error in measurements of length is Delta l, human error in time measurement is 0.15 sec and least count of stop watch Delta T, for what value of amplitude (A). Delta l and Delta T error in calculation of 'g' is maximum.

Answer»

`A=1.4, DELTA L = 0.5m, Delta T = 0.1 SEC`
`A=0.4, Delta l = 0.1 m, Delta T = 0.5 sec`
`A=0.5, Delta l =0.5m, Delta T = 0.2 sec`
`A=0.05, Delta l = 0.1 m, Delta T = 0.5 sec`

ANSWER :D
38.

Turpentine oil is flowing through a capillary tube of length l and radius r. The pressure difference between the two ends of the tube is P. The viscosity of oil is given by: eta = (p(r^2 - x^2))/(4vl) Here v is velocity of oil at a distance x from the axis of the tube. From this relation, the dimensional formula of etais 1

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`[ML^(-1) T^(-1)]`
`[MLT^(-1)]`
`[ML^2T^(-2)]`
`[M^0L^0T^0]`

ANSWER :A
39.

An elevator can carry a maximum load of 1800 kg (elevator + passengers) is moving up with a constant speed of 2 ms^(-1). The frictional force opposing the motion is 4000 N. Determine the minimum horse power delivered by motor to the elevator.

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Solution :The downward force on the elevator is
`F = mg + F_f = (1800 xx 10) + 4000 = 22000 N`.
The motor MUST supply enough power to BALANCE this force.
Hence, `P= vecF . vecv = 22000 xx 2 = 44000 W. `
40.

Which fo the following mass measurements is most accurate and why? (i) 5.00 kg (ii) 5.004 kg (iii) 5.01 kg.

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SOLUTION :The OBSERVATION (II) has least FRACTIONAL ERROR and hence, more accurate.
41.

Choose the correct statement. a) Any motion that repeats itself in equal intervals of time along the same path is called periodic motion. b) The displacement of a particle in periodic motion can always be expressed in terms of sine and cosine functions of time. c) A body in periodic motion moves back and forth over the same path is called oscillatory or vibrating motion d) Simple harmonic motion is a particular case of periodic motion.

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Only a, B, d are TRUE
Only b, C, d are true
Only a, c, d are true
All are true

Answer :D
42.

What is magnus effect ?

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Solution :DUE to pressure difference TRAJECTORY of spinning ball becomes curve .It becomes CONVEX for region of high pressure .This is CALLED magnus effect.
43.

In the above given problem if the lower thread is pulled with a jerk, what happens ?

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Solution :When the lower thread `CD` is PULLED with a jerk the thread `CD` itself May break . This is because PULL on `CD` may not be tranmitted to `AB` INSTANTLY .
44.

The two ends of uniform rod of thermal conductivity K are maintained at different but constant temperatre. The temperature gradient at any point on the rod is d theta // dx. The heat flow per unit time per unit cross-section of the rod is I. (i) (d theta)/(dx) is the same for all point on the rod (ii) I = K (d theta)/(dx)

Answer»

(i) only
(II) only
(i), (ii)
none

Answer :C
45.

A 100 watt bulb operates at 3000K. Assuming it loses energy only by radiation, the total surface area of the filament will be

Answer»

`0.218" cm"^(2)`
`100" cm"^(2)`
`3000" cm"^(2)`
`300" cm"^(2)`

ANSWER :A
46.

Define Scalar product of two vector. Give any four properties of scalar product.

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Solution :(i) The scalar PRODUCT (or dot product) of two VECTORS is defined as the product of the magnitudes of both the vectors and the cosine of the angle between them.
(ii) Thus if there are two vectors `vec(A) " and " vec(B)` having an angle `theta` between them, then their scalar product is defined as `vec(A)*vec(B)=ABcostheta`. Here, A and B are magnitudes of `vec(A) " and " vec(B)`.
Properties of Scalar Products:
(i) The product QUANTITY `vec(A).vec(B)` is always a scalar. It is positive if the angle between the vectors is acute (i.e. `theta lt 90^(@)`) and negative if the angle between them is obtuse
(i.e. `90^(@) lt theta lt 180^(@)`).
(ii) The scalar product is commutative,
i.e. `vec(A)*vec(B)=vec(B)*vec(A)`
(iii) The vectors OBEY distributive law i.e.
`vec(A)*(vec(B)+vec(C))=vec(A).vec(B)+vec(A).vec(C)`
(iv) The angle between the vectors
`theta=cos^(-1)[(vec(A).vec(B))/(AB)]`
47.

Why a tall chimney is perfered for kitchen?

Answer»

Solution :Ventillator is a small window arrangedat the top of room just below the ceiling of a room. The WARM AIR which is LIGHTER RISES up and escapethrough the ventillator. Then fresh and dense air ENTERS into room through the doors and windows which are open.
48.

Heat capacity of a substance is infinite. It means ……………….. .

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infinite heat is GIVEN out
infinite heat is taken in
no changein TEMPERATURE whether heat is taken in or given out
all of these

Solution :`"HEATH"MC Delta theta, c=(H)/(mDelta theta)`
If`Deltatheta=0` tehn `c =OO`
49.

A uniform rope of mass m hangs freely from a ceiling. A bird of mass M climbs up the rope with an acceleration a. The force exerted by the rope on the ceiling is

Answer»

Ma + mg
M(a + g) + mg
M(a + g)
DEPENDENT on the position of BIRD on the rope

Answer :B
50.

In resonance column experiment we can hear maximum sound at certain height this is due to the phenamenon of resonance open pipes are preferred to close pipes in musical instruments. why?

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Solution :In OPEN PIPES, all HARMONICS are present. But in closed pipes only ODD harmonics are present.