Explore topic-wise InterviewSolutions in Class 11.

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.

37701.

Two bodies of different masses are dropped simultaneously from the top of a tower. If air resistance is proportional to the mass of the body,

Answer» <html><body><p>the heavier <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> reaches the ground earlier<br/>the lighter body reaches the ground earlier<br/>bother reach the ground simultaneously <br/>cannot be <a href="https://interviewquestions.tuteehub.com/tag/decided-2566952" style="font-weight:bold;" target="_blank" title="Click to know more about DECIDED">DECIDED</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html>
Discussion
37702.

Two bodies of different masses are dropped simultaneously from the topof a tower. If air resistance is same on both of them,

Answer» <html><body><p>the heavier <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> <a href="https://interviewquestions.tuteehub.com/tag/reaches-1178076" style="font-weight:bold;" target="_blank" title="Click to know more about REACHES">REACHES</a> the <a href="https://interviewquestions.tuteehub.com/tag/ground-1013213" style="font-weight:bold;" target="_blank" title="Click to know more about GROUND">GROUND</a> earlier<br/>the <a href="https://interviewquestions.tuteehub.com/tag/lighter-1073702" style="font-weight:bold;" target="_blank" title="Click to know more about LIGHTER">LIGHTER</a> body reaches the ground earlier<br/>bother <a href="https://interviewquestions.tuteehub.com/tag/reach-1178062" style="font-weight:bold;" target="_blank" title="Click to know more about REACH">REACH</a> the ground simultaneously <br/>cannot be decided </p>Answer :A</body></html>
Discussion
37703.

A satellite moves around the earth in a circular orbit with speed V. If 'm' is the mass of the satellites, its total energy is

Answer» <html><body><p>`-(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(2)`<br/>`(1)/(2)mv^(2)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)/(2)mv^(2)`<br/>`-mv^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
37704.

A brass disc just fits inside the hole of an iron plate. To loosen the disc from the hole easily, which of the following operations would be more convenient? (coefficient of linear expansion of brass is more than that of iron).

Answer» <html><body><p>the junction should be <a href="https://interviewquestions.tuteehub.com/tag/heated-1017243" style="font-weight:bold;" target="_blank" title="Click to know more about HEATED">HEATED</a> <br/>the junction should be cooled<br/>the junction should be <a href="https://interviewquestions.tuteehub.com/tag/hammered-7687615" style="font-weight:bold;" target="_blank" title="Click to know more about HAMMERED">HAMMERED</a> <a href="https://interviewquestions.tuteehub.com/tag/without-3281350" style="font-weight:bold;" target="_blank" title="Click to know more about WITHOUT">WITHOUT</a> heating or <a href="https://interviewquestions.tuteehub.com/tag/cooling-933550" style="font-weight:bold;" target="_blank" title="Click to know more about COOLING">COOLING</a> it<br/>the junction should be heated first and then it should be dipped in water</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
Discussion
37705.

A car accelerates from rest at a constant rate alphafor some time, after which it decelerates at a constant rate betaand comes to rest. If the total time elapsed is t, then the maximum velocity acquired by the car is

Answer» <html><body><p>`((<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>^2 + <a href="https://interviewquestions.tuteehub.com/tag/beta-2557" style="font-weight:bold;" target="_blank" title="Click to know more about BETA">BETA</a>^2)/(alpha beta)) t` <br/>`((alpha^2-beta^2)/(alpha beta))t ` <br/>`(alpha beta t)/(alpha + beta)` <br/>`((alpha + beta)t)/(alpha beta)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
37706.

A bullet loses 25% of its initial kinetic energy after penetrating through a distance of 2cm in a target. The further distance it travels before coming to rest is

Answer» <html><body><p>1cm<br/>2cm<br/>8/3cm<br/>6cm</p>Answer :D</body></html>
Discussion
37707.

Three stars each at mass m, moving in a circular orbit of radius or about a stationary central star of mass M. The three identical stars orbits in the same sense and are symmetrically located with respective each other (The centre of all stars lie in one plane). Considering gravitational force of all remaing bodies on every star, the time period of each of the three stars is

Answer» <html><body><p>`2pisqrt((r^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))/(G[m + (m)/(3)]))`<br/>`2pisqrt((r^(3))/(G[m + (m)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt3-3056952" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT3">SQRT3</a>)]))`<br/>`2pisqrt((r^(3))/(G[m + <a href="https://interviewquestions.tuteehub.com/tag/3m-310999" style="font-weight:bold;" target="_blank" title="Click to know more about 3M">3M</a>]))`<br/>`2pisqrt((r^(3))/(G[m + sqrt3m]))`</p>Answer :B</body></html>
Discussion
37708.

Given reasons for f_(s)=mu_(s)N

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :It isnot avectorequation. <a href="https://interviewquestions.tuteehub.com/tag/therelation-1410479" style="font-weight:bold;" target="_blank" title="Click to know more about THERELATION">THERELATION</a>`f_(s)= mu_(s)N` is <a href="https://interviewquestions.tuteehub.com/tag/nota-571478" style="font-weight:bold;" target="_blank" title="Click to know more about NOTA">NOTA</a> vectorrelation . Thisisbecausethe normalforceN and `f_(s)` are notinthe samedirectioneventhough`f_(s)` is equal to`mu_(s)` timesthe <a href="https://interviewquestions.tuteehub.com/tag/normalforce-2875738" style="font-weight:bold;" target="_blank" title="Click to know more about NORMALFORCE">NORMALFORCE</a>. thisis alsotruein the caseof <a href="https://interviewquestions.tuteehub.com/tag/kineticfriction-2771653" style="font-weight:bold;" target="_blank" title="Click to know more about KINETICFRICTION">KINETICFRICTION</a> .</body></html>
Discussion
37709.

A block of mass m can slide freely in a slot made in a bigger of mass M as shown in fig. There is no friction anywhere in the system. The block m is connected to one end of a string whose other end is fixed at point P. system is released from rest when the string at P makes an angle theta with horizontal. Find the acceleration of m and M after release.

Answer» <html><body><p></p>Solution :Method 1: Just after the release of <a href="https://interviewquestions.tuteehub.com/tag/system-1237255" style="font-weight:bold;" target="_blank" title="Click to know more about SYSTEM">SYSTEM</a>, block M will move towards left (say with acceleration A) and block m will move down with respect ot M (say with acceleration a). As there is no motion of M is vertical direction, hence the acceleration of m in verticle direction will be same as that of M, i.e. A, because horizontal both move together. <br/> Finding constraint Method 1: Let just after release, during a small time dt, the displacement of m(w.r.t. M) is dy downwards and that of M is dx horizontally asshown in fig. <br/> Decreases in the length of segment I`=underset(bar)d xcos theta` <br/> Increases in the length of segment II' `underset(bar)d y` <br/> As the total length of the string is constant , so <br/> `underset(bar)d = underset(bar)d x cos theta` ..(i) <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_V01_C06_S01_054_S01.png" width="80%"/> <br/> Divinding both sides by dt, we get <br/> `(dy)/(dt)=(dx)/(dt) cos theta implies v = V cos theta` ..(ii) <br/> differenting w.r.t. `t=(dv)/(dt)=V(- sin theta)(d theta)/(dt)+(dV)/(dt) cos theta` <br/> But initially `V=<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>`, as `a=A cos theta` ...(iii) <br/> (`:. (dv)/(dt) = a , (dV)/(dt)=A`) <br/> Method 2: we can obtain (i) in the following way. <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_V01_C06_S01_054_S02.png" width="80%"/><br/> The displacment of M towards left is dx, then its component along AP is `dx cos theta`should be decreased in the length of segment I and this should be equal to increases in the length of segment II which is dy. Hence, `dy=dx cos theta`. <br/> `rArr a = A cos theta`<br/> Method 3: <br/>Total length of string : `l=sqrt(h^(2)+y^(2))+x` <br/> differentiating w.r.t. `t=(dl)/(dt) =(d(h^(2)+x^(2))^(1//2))/(dt) +(dx)/(dt)` <br/> `rArr 0=(2y(dy)/(dt))/(2sqrt(h^(2)+y^(2)))+(dx)/(dt)rArr0= cos theta (-V)+r` <br/> (`because(dx)/(dt)=v, (dy)/(dt)=-V`(as y decreases with time)<br/> and `cos theta=(y)/(sqrt(h^(2)+y^(2)))` <br/> `implies v=V cos theta` which is same as (ii) <br/> Now finding acceleration of blocks <br/> We can use any of the following method to find the value of A and a . <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_V01_C06_S01_054_S03.png" width="80%"/> <br/> Method 1: From FBD of M: <br/> `T cos theta-N = MA` ...(<a href="https://interviewquestions.tuteehub.com/tag/iv-501699" style="font-weight:bold;" target="_blank" title="Click to know more about IV">IV</a>) <br/> From FBD of m: `N=mA` ..(v) <br/> `<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>-t=ma` ..(vi) <br/> Combining (iv) and (v) we get <br/> `T cos theta=(m+M)A`...(vii)<br/> Putting `a=A cos theta` in (iv) we get <br/> `mg-T=mA cos theta`..(viii) <br/> Put the value of T form (viii) into (vii) we get <br/> `(mg-mA cos theta)cos theta=(m+M)A` <br/> `implies A=(mg cos theta)/(M+m(1+cos^(2)theta))` <br/> and `a=A cos theta=(mg cos^(2)theta)/(M+m(1+cos^(2) theta))` <br/> The net acceleration of m is <br/> `sqrt(A^(2)+a^(2))=A sqrt(1+cos^(2) theta)=(mg cos thetasqrt(1+cos^(2) theta))/(M+m(1+cos^(2) theta))` <br/> Method 2: Analyzing the block with w.r.t. wedge <br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_V01_C06_S01_054_S04.png" width="80%"/> <br/> W.r.t M, m has only vertcal acceleration which is a downwards. Here we have to apply pseudo force because M is a non inertial frame. <br/> FBD of m w.r.t. M: <br/> `N=mA, mg-T=ma` <br/> These equation are same as (v) and (vi). Now solve to get answer. <br/> Method 3: Analyzing the block and wedge together <br/> Analyzing the system of `(M+m)`, i.e. , block and wedge together in horizontal direction, in horizontal direction both masses have same acceleration which is A. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_V01_C06_S01_054_S05.png" width="80%"/> <br/> `T cos theta=(M+m)A` ...(ix) <br/> Analyzing the motion of blcok in vertical direction <br/> `mg-T=ma` ..(x) <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_V01_C06_S01_054_S06.png" width="80%"/> <br/> <a href="https://interviewquestions.tuteehub.com/tag/solving-1217196" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVING">SOLVING</a> (ix) and (x) , we get <br/> `A=(mg cos theta)/(M+m(1+cos^(2) theta))` <br/> and `a=(mg cos^(2)theta)/(M+m(1+cos^(2) theta))`</body></html>
Discussion
37710.

The Young's modulus of steel is twice that of brass. Two wires of the same length and of the same area of cross section, one of steel and another of brass are suspended from the same roof. If we want the lower ends of the wires to be at the same level, then the weights added to the steel and brass wires must be in the ratio of

Answer» <html><body><p>`1:1`<br/>`1:2` <br/>`2:1` <br/>`4:1` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
37711.

Mass of the earth is 81 times that of the moon. If the distance between their centres is d, then the point on the line joining their centres at which the gravitational field due to them is zero is

Answer» <html><body><p>`(d)/(10)` from the <a href="https://interviewquestions.tuteehub.com/tag/centre-912170" style="font-weight:bold;" target="_blank" title="Click to know more about CENTRE">CENTRE</a> of <a href="https://interviewquestions.tuteehub.com/tag/moon-563673" style="font-weight:bold;" target="_blank" title="Click to know more about MOON">MOON</a><br/>`(d)/(10)` from the centre of earth<br/>`(9d)/(10)` from the centre of moon<br/>`(d)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` from each other </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
37712.

"The rotational vectors are represented by straight lines lying alongaxis of rotation". Why ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Because they are <a href="https://interviewquestions.tuteehub.com/tag/axial-889822" style="font-weight:bold;" target="_blank" title="Click to know more about AXIAL">AXIAL</a> <a href="https://interviewquestions.tuteehub.com/tag/vectors-14090" style="font-weight:bold;" target="_blank" title="Click to know more about VECTORS">VECTORS</a>, They <a href="https://interviewquestions.tuteehub.com/tag/result-1187343" style="font-weight:bold;" target="_blank" title="Click to know more about RESULT">RESULT</a> from the vector product of <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> vectors.</body></html>
Discussion
37713.

The efficiency of Carnot heat engine is 0.5 when the temperature of the source is T_(1) and that of sink is T_(2). The efficiency of another Carnot's heat engine is also 0.5 . The temperature of source and sink of the second engine are respectively

Answer» <html><body><p>`2T_(1),2T_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`2T_(1),T_(2)/2`<br/>`T_(1)+5,T_(2)-5`<br/>`T_(1)+<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>,T_(2)-10`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
37714.

A bullet strikes the wooden block and gets embedded into it. What type of collision is it?

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/perfectly-7309466" style="font-weight:bold;" target="_blank" title="Click to know more about PERFECTLY">PERFECTLY</a> <a href="https://interviewquestions.tuteehub.com/tag/elastic-967540" style="font-weight:bold;" target="_blank" title="Click to know more about ELASTIC">ELASTIC</a> <br/>perfectly <a href="https://interviewquestions.tuteehub.com/tag/inelastic-7382420" style="font-weight:bold;" target="_blank" title="Click to know more about INELASTIC">INELASTIC</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/partially-7321885" style="font-weight:bold;" target="_blank" title="Click to know more about PARTIALLY">PARTIALLY</a> elastic<br/>none of the above</p>Answer :A</body></html>
Discussion
37715.

The mass and diameter of a planet are twice that of the earth. What will be the time period of oscillation of a pendulum on this planet, if it is seconds pendulum on earth.

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a><br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` sec<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/(sqrt(2))`sec<br/>`2sqrt(2)` sec</p>Answer :D</body></html>
Discussion
37716.

The velocity of Boat in still water is 3m/s. Velocity river is 4m/s. Walking velocity of man on Bank is 1 m/s {:("Column-I","Column-II") ,("A) Shortest time taken to cross river ","P) " 40 sqrt(7) "SI units"),("B) Time taken to cross river in shortest path","Q) " (40)/(sqrt(7)) "SI units"),("C) Shortest time taken to reach directly opposite point","R) 40 SI units"),("D) Minimum drift","S) 160 SI units"),(,"T)" (160)/(sqrt(7))"SI units"):}

Answer» <html><body><p> <br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A-R; B-T; C-S; D-P</body></html>
Discussion
37717.

A particle initially at rest starts moving from point A on the surface of a fixed smooth hemisphere of radius r as shwon. The particle looses its contact with hemisphere at point B. C is centre of the hemisphere. The equation relatin alpha and beta is

Answer» <html><body><p>`2sinalpha=2cosbeta`<br/>`2sinalpha=3cosbeta`<br/>`3sinbeta=2cos <a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>`<br/>`2sinbeta=3cosalpha`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
37718.

Figure shown a cylindrical tube of radius r and lengh l fitted with a cork. The friction coefficient between the cork and the tube is mu. The tube contains an ideal gas at temperature T, and atmospheric pressure P_(0) Thetube is slowly heated , the cork pipe out when temperature is boubled. What is normal force per unit length exerted by the periphery of tube? Assume uniform temperature throughout gas any instant.

Answer» <html><body><p>&lt;<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>&gt;</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> volume of the gas is constant, <br/> `(P_(i))/(T_i)=(P_f)/(T_(f)`<br/>`P_(f)=P_(i)((T_(F))/T_(i))=2P_(i)=2P_(0)` <br/> The Forces actihg on the <a href="https://interviewquestions.tuteehub.com/tag/cork-426211" style="font-weight:bold;" target="_blank" title="Click to know more about CORK">CORK</a> are shown in the <a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a> in equilibrium. <br/> `P_(0)xxA+muN=2P_(0)A` <br/> `N=(P_(0)A)/mu` <br/> `N` is the total normal force exerted by the tube on the cork, hence contact force per unil length is<br/> `(dN)/(dl)=(N)/(2pir)`=`(P_(0)A)/(2pimur)`</body></html>
Discussion
37719.

A solid sphere of radius ‘r’ is kept on a concave mirror of radius of curvature R. The arrangement is kept on a horizontal table. If the sphere is displaced from its equilibrium position and left, then it executes SHM. The period of oscillation will be (sphere does't slip)

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a> <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>([(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> - r)(1.4)<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>])`<br/>`2pi sqrt([((R - r))/g])`<br/>`2pi sqrt([((Rr))/g])`<br/>`2pi sqrt([((R))/(gr)])`</p>Answer :A</body></html>
Discussion
37720.

A source of sound moves towards an observer

Answer» <html><body><p>The <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> of the source is increased<br/>The velocity of sound in the <a href="https://interviewquestions.tuteehub.com/tag/medium-1092763" style="font-weight:bold;" target="_blank" title="Click to know more about MEDIUM">MEDIUM</a> is increased<br/>The <a href="https://interviewquestions.tuteehub.com/tag/wavelength-1450414" style="font-weight:bold;" target="_blank" title="Click to know more about WAVELENGTH">WAVELENGTH</a> of sound in the medium <a href="https://interviewquestions.tuteehub.com/tag/towards-7269729" style="font-weight:bold;" target="_blank" title="Click to know more about TOWARDS">TOWARDS</a> the observer is decreased<br/>The amplitude of vibrationof theparticle is increased.</p>Answer :C</body></html>
Discussion
37721.

A saturn year is 29.5 times the earth year. How far is the saturn from the sun if the earth is 1.50 × 10^(8) km away from the sun ?

Answer» <html><body><p></p>Solution :`implies` <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> period of earth = 1 yr<br/> Time period of planet Saturn = 29.5 yr <br/><a href="https://interviewquestions.tuteehub.com/tag/orbital-1138169" style="font-weight:bold;" target="_blank" title="Click to know more about ORBITAL">ORBITAL</a> radius of earth `R_E = 1.5 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(8)`km<br/> Orbital radius of planet Saturn `= R_S` <br/>According to Kepler.s <a href="https://interviewquestions.tuteehub.com/tag/third-1414358" style="font-weight:bold;" target="_blank" title="Click to know more about THIRD">THIRD</a> law, <br/> `T^(2) prop r^3` <br/> `:. ((T_E)/(T_s))^2 = (R_E/R_S)^3` <br/> `:. (1/(29.5))^2 =((1.5xx10^8)/(R_s))^3` <br/> `:. R_s^3 = (29.5)^2 (1.5 xx10^8)^3`<br/> `= 2.947 xx 10^(27) km` <br/> `:. R_s= 1.43 xx10^(<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>) km` <br/> `= 1.43 xx10^(12) m`</body></html>
Discussion
37722.

If look inside a real piano , you'll see that the assumption made in part (b) of Illustration 7.31 is only partially true . The strings are not likely to have the length of the A string is only 64 % of the length of the C string . What is theratio of their tensions ?

Answer» <html><body><p></p>Solution :The ratio of frequencies : <br/> `( f_(1) A)/( f_(1) C) = (L_(C ))/(L_(A)) sqrt (( T_(A))/( T_(C)))` <br/> `(T_(A))/(T_( C)) = ((L_(A))/(L_(C )))^(2) ((f_(1) A)/( f_(1) C))^(2)` <br/> `(T_(A))/( T_( C )) = ( 0.64)^(2) (( <a href="https://interviewquestions.tuteehub.com/tag/440-316801" style="font-weight:bold;" target="_blank" title="Click to know more about 440">440</a>)/( 262))^(2) = 1.16` <br/> <a href="https://interviewquestions.tuteehub.com/tag/notice-25787" style="font-weight:bold;" target="_blank" title="Click to know more about NOTICE">NOTICE</a> that this result <a href="https://interviewquestions.tuteehub.com/tag/represents-1185452" style="font-weight:bold;" target="_blank" title="Click to know more about REPRESENTS">REPRESENTS</a> only a `16 %` increase in tension , compares with the `18.2%` increase in <a href="https://interviewquestions.tuteehub.com/tag/part-596478" style="font-weight:bold;" target="_blank" title="Click to know more about PART">PART</a> (b) of Illustration 7.31.</body></html>
Discussion
37723.

The cylindrical tube of a spray pump has a cross section of 8.0 cm^2 one end of which has 40 fine holes each of diameter 1.0 mm. If the liquid flow inside the tube is 1.5 m min^-1. What is the speed of ejection of the liquid through the holes?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`0.64 ms^-1`</body></html>
Discussion
37724.

As shown in the figure, a planet revolves round the sun in Elliptical orbit with sun at the focus. The shaded areas can be assumed to be equal. If t_(1) and t_(2) represent the time taken for the planet to move from A to B and C to D respectively, then

Answer» <html><body><p>`t_(1) <a href="https://interviewquestions.tuteehub.com/tag/lt-537906" style="font-weight:bold;" target="_blank" title="Click to know more about LT">LT</a> t_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`t_(1) gt t_(2)`<br/>`t_(1) =t_(2)`<br/>none</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
37725.

The maximum number of components a vector can be split are ?

Answer» <html><body><p>2<br/>3<br/>4<br/>Infinite</p>Answer :D</body></html>
Discussion
37726.

At what temperature will the average velocity of oxygen molecules be sufficient so as to escape from the earth ? Escape velocity of earth is 11.0 kms^(-1) and mass of one molecule of oxygen is 5.34xx10^(-26) kg. Boltzmann constant =1.38xx10^(-23) " J molecule"^(-1) K^(-1) .

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :For the <a href="https://interviewquestions.tuteehub.com/tag/molecule-563028" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULE">MOLECULE</a> to just escape from the earth, <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> <a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> energy of the molecule at temperature <br/> T = Escape energy of the molecule. <br/> (or) `3/2k_BT=1/2mv_e^2` <br/> `T = (mv_e^2)/(3k_B)` <br/> `=(5.34xx10^(-26)xx(11.0xx10^3)^2)/(3xx1.38xx10^(-23))` <br/> `= 1.56xx10^5 K`.</body></html>
Discussion
37727.

A sphere of aluminium of 0.047 kg placed for sufficient time in a vessel containing boiling water, so that sphere is at 100" "^(@)C. It is then immediately transferred to 0.14 kg copper calorimeter containing 0.25 kg of water at 20" "^(@)C. The temperature of water rises and attains a steady state at 23" "^(@)C. Calculate the specific heat capacity of aluminium.

Answer» <html><body><p></p>Solution :Mass of sphere `m_(1)=0.047` <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> <br/> Initial temperature of sphere `T_(1)=<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>` <br/> Final temperature of sphere `T_(2)=23^(@)C` <br/> Change in temperature `DeltaT_(1)=T_(1)-T_(2)` <br/> `=(100-23)" "^(@)C` <br/> `=77^(@)C` <br/> Sphere specific heat of sphere `=S_(1)` <br/> Heat lost by aluminum sphere, <br/> `Q_(1)=m_(1)S_(1)DeltaT_(1)` <br/> `=0.047xxS_(1)xx77` <br/> `:.Q_(1)=3.619S_(1)`. . .(1) <br/> Now, mass of water `m_(2)=0.25` kg <br/> Mass of calorimeter `m_(3)=0.14` kg <br/> Specific heat of water, <br/> `S_(2)=4.18xx10^(3)" Jkg"^(-1)K^(-1)` <br/> Specific heat of copper calorimeter, `S_(3)=0.386xx10^(3)" Jkg"^(-1)K^(-1)` <br/> Heat gained by water and calorimeter,<br/> `Q_(2)=m_(2)S_(2)DeltaT_(2)+m_(3)S_(3)DeltaT_(2)` <br/> `=0.25xx4.18xx10^(3)xx3+0.14xx0.386xx10^(3)xx3` <br/> `=3.135xx10^(3)+0.16212xx10^(3)` <br/> `:.Q_(2)=3.29712xx10^(3)`. . .(2) <br/> For <a href="https://interviewquestions.tuteehub.com/tag/steady-1226685" style="font-weight:bold;" target="_blank" title="Click to know more about STEADY">STEADY</a> state, <br/> {Heat lost by sphere} = {Heat gained by water} + {Heat gained by calorimeter} <br/> `Q_(1)=Q_(2)` <br/> `3.619S_(1)=3.29712xx10^(3)` [from equation (1) and (2)] <br/> `:.S_(1)=(3.29712xx10^(3))/(3.619)=0.911xx10^(3)` <br/> `:.S_(1)=0.<a href="https://interviewquestions.tuteehub.com/tag/911-342047" style="font-weight:bold;" target="_blank" title="Click to know more about 911">911</a>" kJ kg"^(-1)=911" Jkg"^(-1)K^(-1)` (specific heat of aluminium)</body></html>
Discussion
37728.

(1)/(12) of the mass of carbon 12 atom is......

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> TMC<br/><a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of neutron<br/>1 amu<br/>mass of <a href="https://interviewquestions.tuteehub.com/tag/hydrogen-22331" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGEN">HYDROGEN</a></p>Solution :mass of hydrogen</body></html>
Discussion
37729.

A simple pendulum excuting S.H.M in a straight line has zero velocity at 'a' and 'b' whose distances from 'o' in the same line OAB are 'a' and 'b'. If the velocity half-way between them is 'v' then its time period is

Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>+a))/(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)`<br/>`pi((b+a)/(v))`<br/>`((b+a)/(<a href="https://interviewquestions.tuteehub.com/tag/2v-300496" style="font-weight:bold;" target="_blank" title="Click to know more about 2V">2V</a>))`<br/>`((b-a)/(2v))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html>
Discussion
37730.

An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900km/h. Compare its centripetal acceleration with the acceleration due to gravity .

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :6.4 <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a></body></html>
Discussion
37731.

A siren of frequency n approaches a stationary observer and then receedes from the observer. If the velocity of source (V) lt ltthe velocity of sound (C ), the apparent change in frequency is

Answer» <html><body><p>`2nV//C`<br/>`2nC//V`<br/>`n//V`<br/>`2VC//n`</p>Solution :`n.=n((V)/(V-V_(S)))=n((C )/(C-V))` <br/> `n..=n((C )/(C+V))` <br/> `Deltan..=n.-n..=<a href="https://interviewquestions.tuteehub.com/tag/nc-576183" style="font-weight:bold;" target="_blank" title="Click to know more about NC">NC</a>[(1)/(C-V)-(1)/(C+V)]` <br/> `=nC[(<a href="https://interviewquestions.tuteehub.com/tag/2v-300496" style="font-weight:bold;" target="_blank" title="Click to know more about 2V">2V</a>)/(C^(2)-V^(2))]` <br/> `V^(2)`can be <a href="https://interviewquestions.tuteehub.com/tag/neglected-7377285" style="font-weight:bold;" target="_blank" title="Click to know more about NEGLECTED">NEGLECTED</a> as `V lt lt C :. Deltan.=(2nV)/(C )`</body></html>
Discussion
37732.

A bullet of mass 10gm hits a fixed target and penetrates through 8cm in it before coming to rest. If the average resistance offered by the target is 100N, the velocity with which the bullet hits the target is,

Answer» <html><body><p>20m/s<br/>25m/s<br/>40m/s<br/>50m/s</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
37733.

A body of mass (4m) is lying in x-y plane at rest. It suddenly explodes into three pieces. Two pieces, each of mass (m) move perpendicular to each other with equal speeds (v). The total kinetic energy generated due to explosion is

Answer» <html><body><p>`mv^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`<br/>`3/2 mv^2`<br/>`2 mv^2`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> mv^2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html>
Discussion
37734.

We can cut vegetables easily with a sharp knife as compared to a blunt knife. Why ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The area of a sharp edge is much Less than the area of blunt edge. For the same total force, defective force <a href="https://interviewquestions.tuteehub.com/tag/per-590802" style="font-weight:bold;" target="_blank" title="Click to know more about PER">PER</a> <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> area is more for the sharp edge than the blunt edge. Has a sharp knife <a href="https://interviewquestions.tuteehub.com/tag/cuts-942304" style="font-weight:bold;" target="_blank" title="Click to know more about CUTS">CUTS</a> <a href="https://interviewquestions.tuteehub.com/tag/easily-964537" style="font-weight:bold;" target="_blank" title="Click to know more about EASILY">EASILY</a> than a blunt knife.</body></html>
Discussion
37735.

Two particles of masses 4 kg and 6 kg are at rest separated by 20 m. If they move towards each other under mutual force of attraction, the position of the point where they meet is

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/12m-271645" style="font-weight:bold;" target="_blank" title="Click to know more about 12M">12M</a>` from `<a href="https://interviewquestions.tuteehub.com/tag/4kg-318964" style="font-weight:bold;" target="_blank" title="Click to know more about 4KG">4KG</a>` body<br/>`12m` from `<a href="https://interviewquestions.tuteehub.com/tag/6kg-332072" style="font-weight:bold;" target="_blank" title="Click to know more about 6KG">6KG</a>` body<br/>`8m` from `4kg` body<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10m-267115" style="font-weight:bold;" target="_blank" title="Click to know more about 10M">10M</a>` from `4kg` body</p>Answer :A</body></html>
Discussion
37736.

Below are four equations expressing relationships between physical qualities. .g. gravitational field strengths, r radius, rho a density, G the universal constant of gravitation, m a mass and T a time period. Which of the are true. equations are true. (a)gT^2=4pir^2 , (b)4/3pirhoGr^2=g , (c)gr^2=Gm , (d)g=4/3 pirhoGr

Answer» <html><body><p>only a&amp;<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are true<br/>only b &amp; <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true<br/>only c&amp;d are true<br/>only a,b &amp; c are true</p>Answer :C</body></html>
Discussion
37737.

The bob of a simple pendulum of mass 200g is oscillating with a time 2sec. If the bob replaced by another bob of mass 450g but of same radius what will be the new time period of oscillation ?

Answer» <html><body><p>1sec<br/>3 sec<br/>4 sec<br/>2 sec</p>Answer :D</body></html>
Discussion
37738.

A boy of mass 30 kg is running with a velocity of 3 ms^(-1) on ground just tangenti - ally to a merry - go - round which is at rest. It has radius R = 2m, a mass of 120 kg and its radius of gyration is 1m. If the boy suddenly jumpes on to the merry - go - round, the angular velocity acquired by the system is

Answer» <html><body><p>`1 <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a> s^(-1)`<br/>`0.5 rad s^(-1)`<br/>`(3)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)rad s^(-1)`<br/>`(4)/(3)rad s^(-1)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
37739.

The first law of thermodynamics is a law of conversion of

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/enegy-2612391" style="font-weight:bold;" target="_blank" title="Click to know more about ENEGY">ENEGY</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> <br/>both <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> and momemtum .<br/><a href="https://interviewquestions.tuteehub.com/tag/neither-1113494" style="font-weight:bold;" target="_blank" title="Click to know more about NEITHER">NEITHER</a> nergy nor momemtum </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html>
Discussion
37740.

Whatis meantby thermalequilibrium ?

Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> <a href="https://interviewquestions.tuteehub.com/tag/systems-1237607" style="font-weight:bold;" target="_blank" title="Click to know more about SYSTEMS">SYSTEMS</a> are said to be in thermal equilibrium with each other if they are at the same <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a>, which will not change with <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a>.</body></html>
Discussion
37741.

What are difficulties arised by using water in a barometer instead of mercury ?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> of water is low , hence if water is used in <a href="https://interviewquestions.tuteehub.com/tag/barometer-394088" style="font-weight:bold;" target="_blank" title="Click to know more about BAROMETER">BAROMETER</a> the <a href="https://interviewquestions.tuteehub.com/tag/length-1071524" style="font-weight:bold;" target="_blank" title="Click to know more about LENGTH">LENGTH</a> of tube used in barometer should keep very long (about 11 meter ) .So it is not convenient .</body></html>
Discussion
37742.

Mercury has an angleof contact equal to 140^(@) with soda lime glass . A narrow tube of radius 1.00 mm made of this glass is dipped in a trough containing mercury .By what amount does the mercury dip down in the tube relative to the liquid surface outside ?Surface tension of mercury at the temperature of the experiment is 0.465Nm^(-1) . Density of mercury =13.6xx10^(3)kgm^(-3)

Answer» <html><body><p></p>Solution :Here , angle of <a href="https://interviewquestions.tuteehub.com/tag/contact-25916" style="font-weight:bold;" target="_blank" title="Click to know more about CONTACT">CONTACT</a> `theta=140^(@)`<br/>Radius of <a href="https://interviewquestions.tuteehub.com/tag/narrow-1110745" style="font-weight:bold;" target="_blank" title="Click to know more about NARROW">NARROW</a> tube `r=1mm=<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-3)m`<br/>Surface <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> `T=0.465Nm^(-1)`<br/> <a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> of mercury `rho=13.6xx10^(3)kgm^(-3)` <br/>Height of liquid in narrow tube of radius r,<br/>`h=(2Tcostheta)/(rrhog)`<br/>`=(2xx0.465xxcos140^(@))/(10^(-3)xx13.6xx10^(3)xx9.8)`<br/>`=0.00534498`<br/>`=-5.34xx10^(-3)m`<br/>Negative sign shows that the mercury level is depressed in the tube.</body></html>
Discussion
37743.

A bus starts from rest with a constant acceleration . At the same time a car travelling witha constantvelocity 50 m/s over-takes and passes the bus. How fast is the bus travelling when they are side by side ?

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> m/s<br/>50 m/s<br/>100 m/s<br/>none</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html>
Discussion
37744.

Assuming the earth to be a sphere of uniform mass density, how much would a body weigh half way down to the centre of the earth if it weighed 250 N on the surface ?

Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a>` Suppose, <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> and `g_d`are the acceleration <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to gravity at the surface and at the depth d of earth respectively and `W and W_d` are the weights of body at the surface and at the depth of earth respectively.<br/> `g(d) = g(1-d/<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)` <br/> `:. g(d) = g (1-(R/2)/R)""[ :. d = R/2]` <br/> `= g (1-1/2)` <br/> `=g/2` <br/> `:.`Weight of body of mass m at depth d <br/> W(d) = mg (d) <br/> `=(mg)/2 ""[ :. g(d) =g/2]` <br/> `W(d) = W/2 ""[ :. mg = W]`<br/> `:. W(d) = (<a href="https://interviewquestions.tuteehub.com/tag/250-297421" style="font-weight:bold;" target="_blank" title="Click to know more about 250">250</a>)/2` <br/> `:. W(d) = 125 N`</body></html>
Discussion
37745.

A copper ball cools from 62^(@)C to 50^(@)C in 10 minutes and to 42^(@)C in the next 10 minutes. Calculate its temperature at the end of another 10 minutes.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`(theta_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)-theta_(2))/t_(1)=<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>[(theta_(1)+theta_(2))/2-theta_(0)]` <br/> `(62-50)/10=k[(62-50)/2-theta_(0)]" "...(1)` <br/> `(theta_(2)-theta_(3))/t_(2)=k[(theta_(2)+theta_(3))/t_(2)-theta_(0)]` <br/> `(50-42)/10=k[(50+42)/(2)-theta_(0)]""...(2)` <br/> `((1))/((2))" gives "theta_(0)=<a href="https://interviewquestions.tuteehub.com/tag/26-298265" style="font-weight:bold;" target="_blank" title="Click to know more about 26">26</a>^(@)C` <br/> `(theta_(3)-theta_(4))/t_(3)=k[(theta_(3)+theta_(4))/2-theta_(0)]` <br/> `(42-theta_(4))/10=k[(42-theta_(4))/2-26]rArrtheta_(4)=36.7^(@)C`</body></html>
Discussion
37746.

When 1 gm of water changes from liquid to vapour phase at constant pressures of 1 atmosphere, the volume increases from 1 cc to 1671 cc. The heat of vaporisation at this pressure is 540 cal/gm. Increase in internal in internal energy of water is (1 atmosphere = 1.01xx10^(6) "dyne/cm"^(2))

Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/4200-1876189" style="font-weight:bold;" target="_blank" title="Click to know more about 4200">4200</a> J<br/>8200 J<br/>1200 J<br/>2100 J</p>Answer :D</body></html>
Discussion
37747.

Calculate the black body temperature of the sun from th e following data :- Stefan's constant = 5.7xx10^(-8) Wm^(-2)K^(-4) . Solarconstant = 1500 W//M^(2). Radius of the sun = 7xx10^(8)m . Distance between sun and earth = 1.5xx10^(11) m.

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`sigma =5.7xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)Wm^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)K^(4), S = W//m^(2) , <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> =7xx10^(8) m, r =1.5xx10^(11) m`<br/> `T = [(r/R)^(2)S_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)/sigma]^(1//4) = [((1.5xx10^(11))/(7xx10^(8)))^(2)xx1500/(5.7xx10^(-8))]^(1/4)`= 5895 K</body></html>
Discussion
37748.

A rain drop of mass m, starts falling from rest and it collects water vapour and grows. If it gains lambda kg/s, find its velocity at any instant.

Answer» <html><body><p></p>Solution :`(d)/(dt) (<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>) = mg , (dm)/(dt) = lambda or m= lambda t + <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>` <br/> where K is a constant when t=0 , `m=m_0 :. m=m_0 + lambda t ` <br/> so , ` (d)/(dt) {(m_0 + lambda t)v} = (m_0 + lambda t ) g` <br/> Integrating , `(m_0 + lambda t) v= int (m_0 + lambda t) g dt = (m_0 t + ( lambda t^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(2) ) g + <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> ` where C is constant <br/> when t =0, v=0 ` :.` C =0 <br/> `:. (m_0 + lambda t) v = ( m_0 t + ( lambda t^2)/(2)) g , v=(g(m_0 t + (lambda t^2)/( 2)))/(m_0 + lambda t ) =(g (t+ (lambdat^(2))/(2m_0)))/( 1 + (lambda t)/( m_0))` <br/> This mean <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> changes w.r.t . time</body></html>
Discussion
37749.

Two wires of same length and radius are joined end to end and loaded. The Young.s modulii of the materials of the two wires are Y_(1) and Y_(2). If the combination behaves as a single wire them its Young.s modulus is

Answer» <html><body><p></p>Solution :`e=e_(1) +e_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)" but " e=(F(<a href="https://interviewquestions.tuteehub.com/tag/2l-300409" style="font-weight:bold;" target="_blank" title="Click to know more about 2L">2L</a>))/(AY_(<a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>)), e_(1)=(<a href="https://interviewquestions.tuteehub.com/tag/fl-462549" style="font-weight:bold;" target="_blank" title="Click to know more about FL">FL</a>)/(AY_(1)), e_(2)=(Fl)/(AY_(2))` <br/> `(F(2l))/(AY_(eq))=(Fl)/(AY_(1))+(Fl)/(AY_(2))`<br/> `(2)/(Y_(eq))=(1)/(Y_(1))+(1)/(Y_(2)) <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> Y_(eq)=(2Y_(1)Y_(2))/(Y_(1)+Y_(2))`</body></html>
Discussion
37750.

Find the component of 3hat(i)+ 4hat(j) along hat(i)+ hat(j)

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Component of `<a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a>(A) "<a href="https://interviewquestions.tuteehub.com/tag/along-1974109" style="font-weight:bold;" target="_blank" title="Click to know more about ALONG">ALONG</a>" vec(B)` is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> by <br/> `(vec(A).vec(B))/(B)= ((3 hat(i) + 4hat(j)).(hat(i) + hat(j)))/(sqrt2)= (7)/(sqrt2)`</body></html>
Discussion