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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 37651. |
A bimetallic strip made of brass and steel strips shown in the figure given below is heated. What shape does it acquire? (alpha of brass =19xx10^(-6)//""^(0)C and alpha of steel =11xx10^(-6)//""^(0)C.) ("Brass")/("Steel") |
| Answer» <html><body><p></p>Solution :It bends with brass on convex side as `<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a>` of brass is <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> than `alpha` of <a href="https://interviewquestions.tuteehub.com/tag/steel-1227006" style="font-weight:bold;" target="_blank" title="Click to know more about STEEL">STEEL</a>.</body></html> | |
| 37652. |
State stokes'law .By using it deduce the expression for : (i) Initial acceleration of smooth sphere and (ii)Equation of terminal velocity of sphere falling freely through the viscousmedium. (iii) Explain : Upward motion of bubbles produced in fluid. |
| Answer» <html><body><p></p>Solution :Scientist Stokes. said that , viscous force `F_(V)` on small spherical solid body of radius r and moving with velocity v through a viscous medium of large dimensions having coefficient of viscosity `eta` is `6pietarv`.<br/><img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C10_E01_052_S01.png" width="80%"/><br/>As shown in <a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a> a small spherical body of radius r, density `rho` falling in viscous medium of density `sigma`. <br/> Following forces acted on it .<br/> (i) Weight `F_(1)=mg=("volume"<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>"density")g`<br/>`=((4)/(3)pir^(3)rho))g`...(1) (In downward)<br/>Where m = mass of spehre <br/> (ii) Buoyant force `F_(2)=m_(o)g`<br/>`=((4)/(3)pir^(3)sigma)g=`(2) (in upward)<br/> where `m_(0)` = mass of liquid having volume of sphere <br/> (iii) According to stokes.law<br/>`F_(v)=6pietarv` ...(3)<br/><a href="https://interviewquestions.tuteehub.com/tag/resultant-1187362" style="font-weight:bold;" target="_blank" title="Click to know more about RESULTANT">RESULTANT</a> force acting on the sphere,<br/>`F_(R)=F_(1)-F_(2)-F_((v))`<br/>`F_(R)=((4)/(3)pir^(3)rho)g-((4)/(3)pir^(3)sigma))g-6pietarv`<br/>`F_(R)=(4)/(3)pir^(3)g(rho-sigma)-6pietarv` ...(4)<br/> (i)Equation of initial acceleration<br/>If mass of sphere is m and initial acceleration `a_(0)` then<br/> `F_(R)=ma_(0)=(4)/(3)pi^(3)rhoa_(0)`<br/>From equation (4),<br/>`((4)/(3)pir^(3)rho)a_(0)=(4)/(3)pir^(3)g(rho-sigma)-6pietarv`<br/>Taking initial velocity of freely falling sphere v=0<br/>`((4)/(3)pir^(3)rho)a_(0)=(4)/(3)pir^(3)g(rho-sigma)`<br/>`thereforerho(a_(0))=g(rho-sigma)`<br/>`thereforea_(0)=((rho-sigma)g)/(rho)` ...(5)<br/> (ii)Terminal velocity :<br/>As the time passes velocity of sphere will increase hence in equation (3), the force `6pietarv` wil increase and resultant force `F_(R)` decreases. <br/>For any one velocity of spehere `F_(R)`becomes zero and hence according to <a href="https://interviewquestions.tuteehub.com/tag/newton-11212" style="font-weight:bold;" target="_blank" title="Click to know more about NEWTON">NEWTON</a> first law , spehre moves with constant velocity . This constant velocity is known as final or terminal velocity `v_(t)` of sphere.<br/>In equation (4) `v=v_(t)andF_(R)=0`,<br/> `therefore(6pietar)v_(t)=(4)/(3)pir^(3)g(rho-sigma)`<br/>`thereforev_(t)=(2)/(9)(r^(2)g(rho-sigma))/(eta)` ...(6)<br/>Hence terminal velocity of small sphere in viscous medium `v_(t)`<br/> (i) Proportional to the square radius of sphere `v_(t)<a href="https://interviewquestions.tuteehub.com/tag/propr-3782068" style="font-weight:bold;" target="_blank" title="Click to know more about PROPR">PROPR</a>^(2)`<br/>(ii) Proportional to the difference of densities of sphere and fluid.<br/> `v_(t)prop(rho-sigma)`<br/>(iii)Inversely proportional to the coefficients of viscosity of fluid `v_(t)prop(1)/(eta)`.<br/> (iv)Upward motion of bubbles produced in fluid :<br/>The denisty `(rho)` of air bubble produced in the fluid is less then the density of fluid `(sigma)` .Hence `(rholtsigma)`, so terminal velocity is negative and hence bubble would travel in upward direction.</body></html> | |
| 37653. |
A perfect gas goes from state A to state B by absorbing 8xx10^(5)J of heat and doing 6.5xx10^(5)J of external work. It is now transferred between the same two states in another process in which it absorbs 10^(5)J of heat. In second process. Find the work done in the second process. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :According to the <a href="https://interviewquestions.tuteehub.com/tag/first-461760" style="font-weight:bold;" target="_blank" title="Click to know more about FIRST">FIRST</a> <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of thermodynamics <br/> `DeltaU=DeltaQ-DeltaW` <br/> In the first process `DeltaU=8xx10^(5)-6.5xx10^(5)=1.5xx10^(5)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>` <br/> Now `DeltaU`, being a state function, remains the same in the second process, <br/> `DeltaW=DeltaQ-DeltaU=1 xx10^(5)-1.5xx10^(5)` <br/> `DeltaW=-0.5xx10^(5)J` <br/> The negative sign shows that work is doen on the <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a>.</body></html> | |
| 37654. |
A particle is moving along a circular path. The angular velocity, linear velocity,. Angular acceleration, and centripetal acceleration of the particle at any instant. Respectively are vec omega, vec v, vec prop, and vec a_c. Which of the following relations is not correct ? |
| Answer» <html><body><p>`vec omega _|_ vec v`<br/>`vec omega _|_ vec prop`<br/>`vec omega _|_ vec prop_c`<br/>`vec v _|_ vec prop_c`.</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(b) Angular acceleration and angular <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> are <a href="https://interviewquestions.tuteehub.com/tag/along-1974109" style="font-weight:bold;" target="_blank" title="Click to know more about ALONG">ALONG</a> the axis of circular <a href="https://interviewquestions.tuteehub.com/tag/path-11833" style="font-weight:bold;" target="_blank" title="Click to know more about PATH">PATH</a>. So they cannot be perpendicular to each other.</body></html> | |
| 37655. |
Consider two cylinders with same radius and same mass. Let one of the cylinders be solid and another one be hollow. When subjected to some torque, which one among them gets more angular acceleration than the other? |
| Answer» <html><body><p></p>Solution :Moment of inertia of a solid cylinder about its axis `I_(s)=(1)/(2)<a href="https://interviewquestions.tuteehub.com/tag/mr-549185" style="font-weight:bold;" target="_blank" title="Click to know more about MR">MR</a>^(2)` <br/> Moment of inertia of a hollow cylinder about its axis `I_(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)=MR^(2)` <br/> `I_(s)=(1)/(2)I_(h) or I_(h)=2I_(s)` <br/> torque `<a href="https://interviewquestions.tuteehub.com/tag/tau-663951" style="font-weight:bold;" target="_blank" title="Click to know more about TAU">TAU</a> =I alpha=(tau)/(1)` <br/> `alpha_(s)=(tau)/(I_(s)) and a_(h)=(tau)/(I_(b))` <br/> <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> `I_(h) gt I_(s) rArr (I_(h))/(I_(s)) gt I` <br/> `:. alpha_(s) gt alpha_(h)` <br/> For the same torque, a solid cylinder gets more <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> than a hollow cylinder.</body></html> | |
| 37656. |
The pressure P for a gas is plotted against its absolute temperature T for two different volumes V_1 and V_2 where V_1 gt V_2. If P is plotted on y-axis and T on x-axis, then: |
| Answer» <html><body><p>The curve for `V_1` has greater slope than that for `V_2`<br/>The curve for `V_2` has greater slope than that for `V_1`<br/>Both <a href="https://interviewquestions.tuteehub.com/tag/curves-941810" style="font-weight:bold;" target="_blank" title="Click to know more about CURVES">CURVES</a> have same slope <br/>The curves <a href="https://interviewquestions.tuteehub.com/tag/intersect-1049831" style="font-weight:bold;" target="_blank" title="Click to know more about INTERSECT">INTERSECT</a> at some <a href="https://interviewquestions.tuteehub.com/tag/point-1157106" style="font-weight:bold;" target="_blank" title="Click to know more about POINT">POINT</a> other than `T=0`.</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37657. |
Statements :(a) Motion of centre of mass depends on external forces applied on it. (b) The motion of the centre of mass of the body is called the translational motion of the body. |
| Answer» <html><body><p>both a and <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> <br/>both a and b are <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>a is true, b is false <br/>a is false, b is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37658. |
When the road is dry and coefficient of friction is mu. the maximum speed of a cur in a circular path is 10m//sec, If the road becomes wet and mu^(1) = mu//2. What is the maximum speed permitted |
| Answer» <html><body><p>`5m//<a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> m// sec`<br/>`10 <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) m//sec`<br/>`5sqrt(2) m//sec`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37659. |
A carnot.engine whose sink is at 300 K has an efficiency of 40 %. By how much should the temperature of source be increased so as to increase its efficiency by 50% of original efficiency ? |
| Answer» <html><body><p><br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/efficiency-20674" style="font-weight:bold;" target="_blank" title="Click to know more about EFFICIENCY">EFFICIENCY</a> of a carnot engine, <br/> `eta=(T_1-T_2)/T_1` , where `T_1`=<a href="https://interviewquestions.tuteehub.com/tag/temperatureof-2293939" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATUREOF">TEMPERATUREOF</a> the <a href="https://interviewquestions.tuteehub.com/tag/source-1219297" style="font-weight:bold;" target="_blank" title="Click to know more about SOURCE">SOURCE</a> <br/> `T_2`=temperature of the sink <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> 0.40=(T_1-300)/T_1` <br/> `therefore T_1-300=0.40T_1` <br/> `therefore 0.6T_1=300 rArr T_1=300/0.6=3000/6`=500 K <br/> Now, 50% efficiency increases , <br/> `therefore 0.60=(T_1-300)/T_1 rArr T_1-300=0.6T_1` <br/> `therefore 0.4T_1=300 rArr T_1 =300/0.4=(300xx10)/4` =750 <br/> Increase in temperature of source =750-500=250 K</body></html> | |
| 37660. |
Two clocks are being tested against a standard clock located in a national laboratory . At 12:00:00 noon by the standard clock, the regarding of the two clocks are : If you are doing an experiment that requires precision time interval measurements, which of the two clocks will you prefer ? |
| Answer» <html><body><p></p>Solution :The range of variation over the seven <a href="https://interviewquestions.tuteehub.com/tag/days-944904" style="font-weight:bold;" target="_blank" title="Click to know more about DAYS">DAYS</a> of observations is 162 s for clock 1, and 31s for clock 2. The average reading of clock 1 is much closer to the standard time than the average reading of clock 2. The <a href="https://interviewquestions.tuteehub.com/tag/important-1038039" style="font-weight:bold;" target="_blank" title="Click to know more about IMPORTANT">IMPORTANT</a> point is that a clock.s zero error is not as <a href="https://interviewquestions.tuteehub.com/tag/significant-1207363" style="font-weight:bold;" target="_blank" title="Click to know more about SIGNIFICANT">SIGNIFICANT</a> for precision work as its variation, because a .zero-error. can always be easily corrected . <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> clock 2 is to be preferred to clock 1.</body></html> | |
| 37661. |
As we move from poles to equator of earth, the magnitude of acceleration due to gravity increases/decreases correct the sentence. |
| Answer» <html><body><p></p>Solution :The magnitude of <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to gravity <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a>.</body></html> | |
| 37662. |
(A) : In the given Fig . 7 . 184 , a force20 N pulls a block of mass 10 kg on a rough floor . If coefficient of friction is mu = 0.4 , force of friction acting on the block will be 20 N. (R) : Force of kinetic friction is slightly less than the limiting value of force of friction . |
| Answer» <html><body><p>If both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are true and R is the correct explanation of A . <br/>If both A and R are true but R is not correct explanation of A . <br/>If A is false but R is false . <br/>If A is false but R is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37663. |
The temperature of a solid object is observed to be constant during a period. In this period. |
| Answer» <html><body><p>heat may have <a href="https://interviewquestions.tuteehub.com/tag/supplied-3090548" style="font-weight:bold;" target="_blank" title="Click to know more about SUPPLIED">SUPPLIED</a> to the body <br/>heat may have been extracted from the body <br/>no heat is supplied to the body <br/>no heat is extracted from the body. </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A::<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37664. |
Consider a P-V diagram in which the path followed by one mole of perfect gas in a cylindrical container as shown in Fig a) Find the work done when the gas is taken from state 1 to state 2. b) What is the ratio of temperature T_(1)//T_(2), if V_(2)=2V_(1) ? c) Given the internal energy for one mole of gas at temperature T is (3//2) RT, find the heat supplied to the gas when it is taken from state 1 to 2, with V_(2)=2V_(1) . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :a) Work done by the <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> (Let` PV^(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>//2)=A`) <br/> `DeltaW=int_(V_(1))^(V_(2))pdv=A int_(V_(1))^(V_(2))(dV)/sqrtV=A[(sqrtV)/(1//2)]_(V_(1))^(V_(2))=2A(sqrtV_(2)-sqrtV_(1))=2P_(1)V_(1)^(1//2)[V_(2)^(1//2)-V_(1)^(1//2)]` <br/> b) <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> `T =pV//nR=A/(nR).sqrtV` <br/> Thus `T_(2)/T_(1)=sqrt(V_(2)/V_(1))=sqrt2` <br/> c) Then, the change in internal energy <br/> `DeltaU=U_(2)-U_(1)=3/2R(T_(2)_T_(1))=3/2RT_(1)(sqrt2-1)` <br/> `DeltaW=2AsqrtV_(1)(sqrt2-1)=2RT_(1)(sqrt2-1)` <br/> `DeltaQ=(7//2)RT_(1)(sqrt2-1)`</body></html> | |
| 37665. |
In the figure. The time taken by the projectile to reach from A to B is t. Then the distance AB is equal to |
| Answer» <html><body><p>`( <a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> t)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(3))`<br/>`(sqrt(3) u t)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`sqrt(3) ut`<br/>`2 ut `</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37666. |
A relay satellite transmits the television programme from one part of the world to another part continuously because its period |
| Answer» <html><body><p>is <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> than the period of the earth about its axis <br/>is <a href="https://interviewquestions.tuteehub.com/tag/less-1071906" style="font-weight:bold;" target="_blank" title="Click to know more about LESS">LESS</a> than period of <a href="https://interviewquestions.tuteehub.com/tag/ration-619513" style="font-weight:bold;" target="_blank" title="Click to know more about RATION">RATION</a> of the earth about its axis<br/>has no relation with the period of ration of the earth about its axis.<br/>is equal to the period of <a href="https://interviewquestions.tuteehub.com/tag/rotation-11281" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATION">ROTATION</a> of the earth about its axis.</p>Answer :D</body></html> | |
| 37667. |
An ideal gas has molecules with 5 degrees of freedom. The ratio of specific heats at constant pressure (C_P) and at constant volume (C_v) is : |
| Answer» <html><body><p>`7/2`<br/>`7/5`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>`<br/>`5/2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37668. |
A rocket is moving at a speed of 200 m s^(-1) towards a stationary target. While moving, it emits a wave of frequency 1000 Hz. Some of the sound reaching the target gets reflected back to the rocket as an echo. Calculate (1) the frequency of the sound as detected by the target and (2) the frequency of the echo as detected by the rocket. |
| Answer» <html><body><p></p>Solution :(1) The observer is at rest and the source is moving with a speed of `200 m s^(-1)`. <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> this is <a href="https://interviewquestions.tuteehub.com/tag/comparable-7359202" style="font-weight:bold;" target="_blank" title="Click to know more about COMPARABLE">COMPARABLE</a> with the <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of sound, `300 m s^(-1)`, we must use Eq. (15.50) and not the approximate Eq. (15.51). Since the source is approaching a stationary target, `v_(o) = 0`, and `v_(s)` must be replaced by `- v_(s)`. thus , we have <br/> `v = v_(o) (1 - (v_(s))/(v))^(-1)` <br/> `v = 1000 Hz xx [1 - 200 m s^(-1)//330 m s^(-1)]^(-1)` <br/> `~= 2540 Hz` <br/> (2) The target is now the source (because it is the source of echo) and the rocket.s <a href="https://interviewquestions.tuteehub.com/tag/detector-949853" style="font-weight:bold;" target="_blank" title="Click to know more about DETECTOR">DETECTOR</a> id now the detector or observer (because it detects echo). thus , `v_(s) = 0` and `v_(o)` has a positive value. The drequency of the sound emitted by the source (the target) is v. Therefore , the frequency as registered by the rocket is <br/> `v. = v ((v + v_(o))/(v))` <br/> `= 2540 Hz xx ((200 m s^(-1) + 330 m s^(-1))/(330 m s^(-1)))` <br/> `~= 4080 Hz`</body></html> | |
| 37669. |
A point mass is orbiting a significant mass M lying at the focus of the elleptical orbit having major and minor axes given by 2a and 2b respectively. Let r be the distance between the mass M and the point of major axis. The velocity of the particle can be given as |
| Answer» <html><body><p>`(ab)/(2r) sqrt((<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(a^(3)))`<br/>`(ab)/rsqrt((GM)/(b^(3)))`<br/>`(ab)/rsqrt((GM)/(a^(3)))`<br/>`(2ab)/rsqrt((GM)/(((a+b)/2)^(2)))`</p>Solution :on stopping, the satellite will fall along the radius `<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>` of the orbit which can be regarded as a limiting case of an <a href="https://interviewquestions.tuteehub.com/tag/ellipse-450431" style="font-weight:bold;" target="_blank" title="Click to know more about ELLIPSE">ELLIPSE</a> with semi-major axis `r/2` Using kepler's <a href="https://interviewquestions.tuteehub.com/tag/third-1414358" style="font-weight:bold;" target="_blank" title="Click to know more about THIRD">THIRD</a> <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> `T^(2)propr^(3)` <br/> time of fall `(T')/2=T/(2sqrt(8))=(sqrt(2)T)/8`</body></html> | |
| 37670. |
In the following question statement 1 represent Assertion and statement 2 represents Reason .Statement 1 :The velocity of a particle at a point on its trajectory is equal to the slope at that point .Statement 2 : The velocity of the particle acts along the tangent to the trajectory atthe point .Select the correct statement from the following statements . |
| Answer» <html><body><p>Statement 1 is true, statement 2 is true and it explains statement 1 <a href="https://interviewquestions.tuteehub.com/tag/correctly-409968" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECTLY">CORRECTLY</a>.<br/>Statement 1 is true, statement 2 is true and does not explain statement 1 correctly .<br/>Statement 1 is true, statement 2 is false.<br/>Statement 1 is false , statement 2 is true .</p>Solution :The slop of the trajectory is zero at the <a href="https://interviewquestions.tuteehub.com/tag/highest-1022683" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHEST">HIGHEST</a> point . But the velocity of the <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> is <a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> cos`<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>` .</body></html> | |
| 37671. |
Two particles initially at rest are approaching each other due to their mutual force of attraction. What is the velocity of the centre of mass of the system when the particles have a relative velocity v ? |
| Answer» <html><body><p></p>Solution :For a two-particle system, the <a href="https://interviewquestions.tuteehub.com/tag/mutual-2850190" style="font-weight:bold;" target="_blank" title="Click to know more about MUTUAL">MUTUAL</a> attraction is an <a href="https://interviewquestions.tuteehub.com/tag/internal-517481" style="font-weight:bold;" target="_blank" title="Click to know more about INTERNAL">INTERNAL</a> <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> and has no <a href="https://interviewquestions.tuteehub.com/tag/effect-966056" style="font-weight:bold;" target="_blank" title="Click to know more about EFFECT">EFFECT</a> on the motion of the centre of mass. Hence the velocity of the centre of mass is zero.</body></html> | |
| 37672. |
(i) In the arrangement shown in the figure the coefficient of friction between the 2 kg block and the vertical wall is mu= 0.5. A constant horizontal force of 40 N keeps the block pressed against the wall. The spring has a natural length of 1.0 m and its force constant is k = 400 Nm^(–1). What should be the height h of the block above the horizontal floor for it to be in equilibrium. The spring is not tied to the block. (ii) A block of mass M is pressed against a rough vertical wall by applying a force F making anangle of theta with horizontal (as shown in figure). Coefficient of friction between the wall and the block is mu = 0.75. (a) If F = 2 Mg, find the range of values of theta so that the block does not slide [Take "tan" 37^(@) = 0.75, "sin" 24^(@) = 0.4] (b) Find the maximum value of theta above which equilibrium is not possible for any magnitude of force F. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a> <a href="https://interviewquestions.tuteehub.com/tag/le-540308" style="font-weight:bold;" target="_blank" title="Click to know more about LE">LE</a> <a href="https://interviewquestions.tuteehub.com/tag/13-271882" style="font-weight:bold;" target="_blank" title="Click to know more about 13">13</a>^(@)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/37-309797" style="font-weight:bold;" target="_blank" title="Click to know more about 37">37</a>^(@)`</body></html> | |
| 37673. |
These questions have statement I and statement II. Of the four choices given below, choose the one that best describes the two statements. Statement I: The centre of mass of the system will not alter in any direction if the external force is not exerted on it. Statement II: If net external force is zero then the linear momentum of the system remains constant. |
| Answer» <html><body><p>Statement I is true, statement <a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a> is true, statement II is a <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> for statement I.<br/>Statement I is true, statement II true, statement II is not a correct explanation for statement I.<br/>Statement I is true, statement II is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a>. <br/>Statement I is false, statement II is true.</p>Answer :D</body></html> | |
| 37674. |
Two rotating bodies A and B of masses mand 2m with moments of inertia I_(A)and I_(B)(I_(B)>I_(A)) have equal kinetic energy of rotation. If L_(A) and L_(B) be their angular momenta respectively, then |
| Answer» <html><body><p>`L_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> L_(A)`<br/>`L_(A) gt L_(B)`<br/>`L_(A)=(L_(B))/(2)`<br/>`L_(A)=2L_(B)`</p>Answer :A</body></html> | |
| 37675. |
A ring is cut from a platinum tube of 8.5cm internal and 8.7cm external diameter. It is supported horizontally from a pan of a balance so that it comes in contact with the water in a glass vessel. If an extra 3.97g weight is required to pull it away from water, then surface tension of water is nearly (18.03) X dyne / cm. Find x (g=980cm/s^2) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a></body></html> | |
| 37676. |
The pressure p of a gas is plotted against itsabsolute temperature T for two different constant volumes V_(1) and V_(2),where V_(1) gt V_(2).pis plotted on the y-axis and T on the x-axis |
| Answer» <html><body><p>The curve for `V_(1)`has <a href="https://interviewquestions.tuteehub.com/tag/greater-476627" style="font-weight:bold;" target="_blank" title="Click to know more about GREATER">GREATER</a> slope than <a href="https://interviewquestions.tuteehub.com/tag/thecurve-3193388" style="font-weight:bold;" target="_blank" title="Click to know more about THECURVE">THECURVE</a> for `V_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`.<br/> The curve for `V_(2)`has greater slope than thecurve for `V_(1)` <br/>The curves must intersect at some pointother than T = 0<br/>The curves have the same slope and do notintersect</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37677. |
The ring R in the arrangement shown can slide along a smooth, fixed, horizontal rod XY. It is attached to the block B by a light string. The block is released from rest, with the string horizontal |
| Answer» <html><body><p>One point in the <a href="https://interviewquestions.tuteehub.com/tag/string-11290" style="font-weight:bold;" target="_blank" title="Click to know more about STRING">STRING</a> will have only vertical <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> <br/>R and <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> will have momenta of the same magnitude.<br/>When the string becomes vetical , the speed of R and B Will be directly propertionaly to their masses <br/>R will <a href="https://interviewquestions.tuteehub.com/tag/lose-537625" style="font-weight:bold;" target="_blank" title="Click to know more about LOSE">LOSE</a> <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> with the rod at some point</p>Answer :A</body></html> | |
| 37678. |
A calorimeter of heat capacity 83.72JK^(-1) contains 0.48 kg of water at 35^(@)C. How much mass of ice at 0^(@)C should be added to decrease the temperature of the calorimeter to 20^(@)C. |
| Answer» <html><body><p></p>Solution :Let .m. be the mass of <a href="https://interviewquestions.tuteehub.com/tag/ice-1035302" style="font-weight:bold;" target="_blank" title="Click to know more about ICE">ICE</a> added, <br/> Heat gained by ice during melting = <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a> <br/> = `mxx0.335xx10^(6)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>` <br/> Heat gainerd by molten ice (water) during rise in temperature = `mxx4186xx(20-0)=mxx83720J` <br/> `therefore` Heat gained by the ice = Heat <a href="https://interviewquestions.tuteehub.com/tag/lost-537630" style="font-weight:bold;" target="_blank" title="Click to know more about LOST">LOST</a> by the <a href="https://interviewquestions.tuteehub.com/tag/calorimeter-908024" style="font-weight:bold;" target="_blank" title="Click to know more about CALORIMETER">CALORIMETER</a> and water <br/> `mxx[0.335xx10^(6)+83720]=1255.8+30139.2=31395J` <br/> `m[335000+83720]=31395` <br/> `m=31395/418720=0.07498kg`.</body></html> | |
| 37679. |
A cylinder wooden float whose base area S=4000cm^(2) & the altitude H=50cm drifts on the water surface specific weight of wood d=0.8gf//cm^(3) (i). What work must be performed to take the float out of the water? (ii). Compoute the work to be performed to submerged completely the float into the water. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(i). `(d^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>^(2)S)/(2rhog)=32kgf-m` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>). `(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)SH^(2)(1-d^(2))=2Kgf-m`</body></html> | |
| 37680. |
On what factors the value of "g" at any place on the Earth depends? |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/factors-458933" style="font-weight:bold;" target="_blank" title="Click to know more about FACTORS">FACTORS</a> on which the value of "g" on the <a href="https://interviewquestions.tuteehub.com/tag/earth-13129" style="font-weight:bold;" target="_blank" title="Click to know more about EARTH">EARTH</a> <a href="https://interviewquestions.tuteehub.com/tag/depends-948548" style="font-weight:bold;" target="_blank" title="Click to know more about DEPENDS">DEPENDS</a> are<br/>(i) <a href="https://interviewquestions.tuteehub.com/tag/altitude-858777" style="font-weight:bold;" target="_blank" title="Click to know more about ALTITUDE">ALTITUDE</a><br/>(ii) Rotation<br/>(iii) <a href="https://interviewquestions.tuteehub.com/tag/depth-948801" style="font-weight:bold;" target="_blank" title="Click to know more about DEPTH">DEPTH</a><br/>(iv) Shape</body></html> | |
| 37681. |
Two capillary tubes of same radiusr but of lengths, l_(1) and l_(2) are fitted in parallel to the bottom of a vessel. The pressure head is P. What should be the length of a single tube that can replace the two tubes so that the rate of flow is same as before |
| Answer» <html><body><p>`l_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)+l_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(1)/(l_(1))+(1)/(l_(2))`<br/>`(l_(1)l_(2))/(l_(1)+l_(2))`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)/(l_(1)+l_(2))`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37682. |
If a simple pendulum of length 'l’ is about to start to make SHM, when it is brought a position so that its length has maximum angular displacement 'q'. If the mass of the bob is 'm", then the maximum K.E at its mean position is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)m((<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)/(g))`<br/>`(1)/(2)mglsinq`<br/>2 <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> l<br/>`mgl(1-cosq)`</p>Answer :D</body></html> | |
| 37683. |
(A) : The size and shape of the rigid body remains unaffected under the effect of external forces.(R ) : The distance between two particles remains constant in a rigid body. |
| Answer» <html><body><p>Both (A) and (R ) are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of (A)<br/>Both (A) and (R ) are true and (R ) is not the correct explanation of (A) <br/>(A) is true but (R ) is false <br/>Both (A) and (R ) are false </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37684. |
An ideal gas undergoes a quasi static, reversible process in which its molar heat capacity C remains constant. If during this process the relation of pressure P and volume Vis given by PV^(n)= constant, then n is given by (Here C_(P) and C_(V) are molar specific heat at constant pressure and constant volume, respectively): |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> -(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>-C_V)/( C-C_P)`<br/>`n= (C_P)/( C_V)`<br/>`n= (C-C_P)/( C- C_V)`<br/>`n= (C_P - C)/( C- C_V)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 37685. |
The internal radius of one arm of a glass capillary U tube is r_(1) and for the second arm it is r_(2)(gt r_(1)). The tube is filled with some mercury having surface tension T and contact angle with glass equal to 90^(@) + theta. (a) It is proposed to connect one arm of the U tube to a vacuum pump- so that the mercury level in both arms can be equalized. To which arm the pump shall be connected?(b) When mercury level in both arms is same, how much below the atmospheric pressure is the pressure of air in the arm connected to the pump? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a) To capillary of smaller radius (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `(2Tsin <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>(r_(2)-r_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))/(r_(1)r_(2)`</body></html> | |
| 37686. |
The menual of a car instructs the owner to inflate the tyres to pressure of 200 kPa. (a) What is the recommended gauge pressure ? (b) What is the recommended absolute pressure ? (c ) If after the required inflation of the tyres, the car is driven to a mountain peak. where the atmospheric pressrre is 10 % below that at sea level, what will be the tyre gauge read ? Atmospehric pressure=1.01 xx 10^5Pa. |
| Answer» <html><body><p></p>Solution :(a) Pressure Instructed by manual = `P_(g) = <a href="https://interviewquestions.tuteehub.com/tag/200-288914" style="font-weight:bold;" target="_blank" title="Click to know more about 200">200</a> K P_(a)` <br/> (b) Absolute Pressure = `101 k P_(a) + 200 k P_(a) = 301 k P_(a)` <br/> At <a href="https://interviewquestions.tuteehub.com/tag/mountain-565001" style="font-weight:bold;" target="_blank" title="Click to know more about MOUNTAIN">MOUNTAIN</a> <a href="https://interviewquestions.tuteehub.com/tag/peak-1149480" style="font-weight:bold;" target="_blank" title="Click to know more about PEAK">PEAK</a> Pa′ is 10% less <br/> `P_(a)=<a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a> kP_(a)`<br/> If we <a href="https://interviewquestions.tuteehub.com/tag/assume-384429" style="font-weight:bold;" target="_blank" title="Click to know more about ASSUME">ASSUME</a> absolute pressure in tyre does not change during driving then <br/> `P_(g) = P – P_(a)′ = 301 – 30 = 211 k P_(a)` <br/> So the tyre will read 211 k `P_(a)`, pressure.</body></html> | |
| 37687. |
Which of the following statements is /are true |
| Answer» <html><body><p>The direction of the excess pressure in the meniscus of a liquid of angle of <a href="https://interviewquestions.tuteehub.com/tag/contact-25916" style="font-weight:bold;" target="_blank" title="Click to know more about CONTACT">CONTACT</a> 2`<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>`/3 is <a href="https://interviewquestions.tuteehub.com/tag/upward-721781" style="font-weight:bold;" target="_blank" title="Click to know more about UPWARD">UPWARD</a> <br/>If the excess pressure in a soap bubble is P, the excess pressure in an air bubble is P/2<br/>In a meniscus of radius <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>. with excess pressureand atmospheric pressure , the force experienced is <br/>If the excess pressure in a soap bubble is, the excess pressure in an air bubble is </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A::B::C</body></html> | |
| 37688. |
Four particles, each of mass M and equidistant "from each other, move along a circle of radius R under the action of the mutual gravitational attraction. The speed of each particle is ......... (G = universal gravitational constant) |
| Answer» <html><body><p>`sqrt((<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/R (1+2sqrt2))` <br/>`1/2sqrt((GM)/R (1+2sqrt2))` <br/>`sqrt((GM)/R)` <br/>`sqrt(2sqrt2 (GM)/R)`</p>Solution :`implies` The force of attraction due to to <a href="https://interviewquestions.tuteehub.com/tag/particles-1147533" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLES">PARTICLES</a> B and D on <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> A is <br/> `F_1 = F_2 = (GM^2)/(2R^2)` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C08_E05_058_S01.png" width="80%"/> <br/>and force attraction exerted by particle at C on particle at A <br/> `F_3 = (GM^2)/(4R^2)` <br/> `:.` The <a href="https://interviewquestions.tuteehub.com/tag/total-711110" style="font-weight:bold;" target="_blank" title="Click to know more about TOTAL">TOTAL</a> force on particle A <br/> `F= F_1 + F_2 + F_3` <br/> but resultant force of `F_1 +F_2` <br/> `F.=sqrt(F_1^2 +F_2^2+2F_1^2 cos 90^@) `<br/> `F. = sqrt(F_1^2 +F_1^2) = sqrt(2F_1^2)` <br/> `:. F. = sqrt2F_1` <br/> `:. F. = sqrt2 F_1 +F_3` <br/> `=sqrt2 (GM^2)/(2R^2) + (GM^2)/(4R^2)`<br/> `:. (Mv^2)/R = (GM^2)/(2R^2) [sqrt2 +1/2]` <br/>`v^2 =(GM)/(2R) [(2sqrt2 +1)/2]` <br/> `:. v = 1/2 sqrt((GM)/R (1+ 2sqrt2)`</body></html> | |
| 37689. |
A satellite moves around the earth in a circular orbit with speed V. If 'm' is the mass of the satellites, its potential energy is |
| Answer» <html><body><p>`mv^2`<br/>`mv^2`<br/>`mv^2`<br/>`-mv^2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37690. |
Which of the following examples represent periodic motion? |
| Answer» <html><body><p>A swimmer completing <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> (return) <a href="https://interviewquestions.tuteehub.com/tag/trip-1427711" style="font-weight:bold;" target="_blank" title="Click to know more about TRIP">TRIP</a> from one bank of a river to the other and back.<br/>A freely suspended bar <a href="https://interviewquestions.tuteehub.com/tag/magnet-1082747" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNET">MAGNET</a> <a href="https://interviewquestions.tuteehub.com/tag/displaced-440680" style="font-weight:bold;" target="_blank" title="Click to know more about DISPLACED">DISPLACED</a> from its N-S direction and released.<br/>A hydrogen molecule <a href="https://interviewquestions.tuteehub.com/tag/rotating-1191156" style="font-weight:bold;" target="_blank" title="Click to know more about ROTATING">ROTATING</a> about its centre of mass.<br/>An arrow released from a bow.<br/></p>Solution :(b), (c)</body></html> | |
| 37691. |
What is the need for banking of tracks? Draw free body diagram of a car negotiating a banked track [ Take friction into account]. Write the expression for maximum velocity to negotiate the curve safely. |
| Answer» <html><body><p></p>Solution :A vehicle moving along a curved path needs some centripetal force. If the path is banked. i.e., inclined with the horizontal , then the horizontal components of friction and normal <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> help to provide this centripetal force. The vehicle may <a href="https://interviewquestions.tuteehub.com/tag/attain-364547" style="font-weight:bold;" target="_blank" title="Click to know more about ATTAIN">ATTAIN</a> a velocity greater than that if the path <a href="https://interviewquestions.tuteehub.com/tag/would-3285927" style="font-weight:bold;" target="_blank" title="Click to know more about WOULD">WOULD</a> have been horizontal along the <a href="https://interviewquestions.tuteehub.com/tag/curve-941741" style="font-weight:bold;" target="_blank" title="Click to know more about CURVE">CURVE</a>.</body></html> | |
| 37692. |
A force F is given by F = at + bt^(2), where t is time. The dimensions of a and b are |
| Answer» <html><body><p>`[MLT^(-3)]` and `[MLT^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)]`<br/>`[MLT^(-4)]` and `[MLT^(-3)]`<br/>`[MLT^(-1)]` and `[MLT^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)]`<br/>`[MLT^(-2)]` and `[MLT^(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)]`</p>Solution :From `<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>= at+bt^(2)` <br/> `[a]= ([F])/([t])= ([MLT^(-2)])/([T])= [MLT^(-3)]` <br/> `[b]=([F])/([t^(2)])= ([MLT^(-2)])/([T^(2)])= [MLT^(-4)]`</body></html> | |
| 37693. |
A rod of length 'l' and mass m, pivoted at one end, is held by a spring at its mid point and a spring at far end, both pulling in opposite directions. The springs have spring constant K, and equilibrium their pull is perpendicular to the rod. Find the frequency of small oscillations about the equilibrium position |
| Answer» <html><body><p><br/></p>Solution :Let `theta` be the <a href="https://interviewquestions.tuteehub.com/tag/small-1212368" style="font-weight:bold;" target="_blank" title="Click to know more about SMALL">SMALL</a> <a href="https://interviewquestions.tuteehub.com/tag/angular-11524" style="font-weight:bold;" target="_blank" title="Click to know more about ANGULAR">ANGULAR</a> displacement of the rod <br/>Let `x_1 and x_2` be the changes in the lengths of the springs . Coresponding restoring forces will <a href="https://interviewquestions.tuteehub.com/tag/act-1106" style="font-weight:bold;" target="_blank" title="Click to know more about ACT">ACT</a> as shown. <br/>Here `x_2 = L theta and x_1 =(L theta)/(2)` <br/>Net restoning torque on the rod will be<br/>`tau =(K x_2)L + (Kx_1) L/2 =-(KL^2 + K (L^2)/(4))theta` <br/>So, `(ML^2)/(3) <a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> = K ((5L^2)/(4)) theta` <br/>`alpha = - ((15L^2)/(4mL^2)K)theta , alpha =- ((15K)/(4m)) theta` <br/>frequency `=1/(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>) sqrt((alpha)/(theta)) = 1/(2pi) sqrt((15K)/(4m))` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_PHY_XI_V01_C_C05_E04_067_S01.png" width="80%"/></body></html> | |
| 37694. |
If angle between vec(a) and vec(b) is (pi)/(3), then angle between 2bar(a) and -3vec(b) is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`(2pi)/(3)`<br/>`(pi)/(6)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/5pi-1900435" style="font-weight:bold;" target="_blank" title="Click to know more about 5PI">5PI</a>)/(3)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 37695. |
Explain characteristics of streamlines. |
| Answer» <html><body><p></p>Solution :Characteristics of streamlines :<br/> (i) In a steady flow streamline can never intersect each other . <br/> (ii)The tangent drawn at point on the streamline <a href="https://interviewquestions.tuteehub.com/tag/indicates-1041501" style="font-weight:bold;" target="_blank" title="Click to know more about INDICATES">INDICATES</a> the direction of velocity of fluid particle at that point.<br/> (iii) The velocity of each fluid particles passing at a point on streamline is same but it is different at different point.<br/> (iv)Widely <a href="https://interviewquestions.tuteehub.com/tag/spaced-3051656" style="font-weight:bold;" target="_blank" title="Click to know more about SPACED">SPACED</a> streamlinesindicates <a href="https://interviewquestions.tuteehub.com/tag/region-1182095" style="font-weight:bold;" target="_blank" title="Click to know more about REGION">REGION</a> of low speed and <a href="https://interviewquestions.tuteehub.com/tag/closely-7288047" style="font-weight:bold;" target="_blank" title="Click to know more about CLOSELY">CLOSELY</a> streamlines indicates region of high speed .</body></html> | |
| 37696. |
When 1 g of water 100^(@) C is converted into steam at100^(@)C,. It occupies a volumn of 1671 cc at normal atmospheric pressure . Find the increase in internal energy of the molecules of steam. |
| Answer» <html><body><p></p>Solution :`1" atmosphere" = 1.013xx10^(5) Nm^(-2)` , <br/>volume of 1 gm of water, `V_(1) = 1cc = 10^(-6)m^(3)`, <br/> volume of steams = `1671 cc =1671xx10^(-6) m^(3)` <br/> External <a href="https://interviewquestions.tuteehub.com/tag/work-20377" style="font-weight:bold;" target="_blank" title="Click to know more about WORK">WORK</a> done dW = `P(V_(2)-V_(1)) = 1.013xx10^(5)(1671xx10^(-6) -1xx10^(-6))=1.013xx167=169.2 J`. <br/> Specific latent heat of vaporisation of steam=540cal/g. So, heat supplied to <a href="https://interviewquestions.tuteehub.com/tag/convert-425734" style="font-weight:bold;" target="_blank" title="Click to know more about CONVERT">CONVERT</a> 1g of water into steam. <br/> `Delta Q = 540xx4.2J=2268J` <br/> By first <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of <a href="https://interviewquestions.tuteehub.com/tag/thermodynamics-12722" style="font-weight:bold;" target="_blank" title="Click to know more about THERMODYNAMICS">THERMODYNAMICS</a> <br/> `Delta <a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> = Delta Q-Delta W = 2268-169.2=2098.8J`</body></html> | |
| 37697. |
A ball strikes against the floor and returns with double the velocity. What type of collision is it? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/perfectly-7309466" style="font-weight:bold;" target="_blank" title="Click to know more about PERFECTLY">PERFECTLY</a> <a href="https://interviewquestions.tuteehub.com/tag/elastic-967540" style="font-weight:bold;" target="_blank" title="Click to know more about ELASTIC">ELASTIC</a> <br/>perfectly <a href="https://interviewquestions.tuteehub.com/tag/inelastic-7382420" style="font-weight:bold;" target="_blank" title="Click to know more about INELASTIC">INELASTIC</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/partially-7321885" style="font-weight:bold;" target="_blank" title="Click to know more about PARTIALLY">PARTIALLY</a> elastic<br/>none of the above</p>Answer :A</body></html> | |
| 37698. |
A solid sphere of mass 1.5 kg rolls on a frictionless horizontal surface, its centre of mass moving at a speed of 5 ms^(-1). Then it rolls up an incline of 30° to horizontal. The height attained by the sphere before it stops is (g = 10 sm^(-2)) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> m<br/>1.5 m<br/>1.75 m<br/>3.65 m </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37699. |
A ship'A' steams down to North at 16 kmph, and ship 'B' due west at 12 kmph. Relative velocity of B of w.r.t. A is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> kmph<br/>25 kmph<br/>6 kmph<br/>20 kmph</p>Answer :D</body></html> | |
| 37700. |
Two particle are projected at the same instant from the same point at inclinations alpha and beta to the horizontal. If they simultaneously hit the top and bottom of a vertical pole subtending angle theta at the pointof projection, find (tan alpha-tan beta). |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a> <a href="https://interviewquestions.tuteehub.com/tag/theta-1412757" style="font-weight:bold;" target="_blank" title="Click to know more about THETA">THETA</a>`</body></html> | |