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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 37601. |
Area enclosed by x rarr t graph gives distance covered. |
| Answer» <html><body><p><br/></p>Answer :False. Area <a href="https://interviewquestions.tuteehub.com/tag/enclosed-970935" style="font-weight:bold;" target="_blank" title="Click to know more about ENCLOSED">ENCLOSED</a> by `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> t` <a href="https://interviewquestions.tuteehub.com/tag/graph-17327" style="font-weight:bold;" target="_blank" title="Click to know more about GRAPH">GRAPH</a> gives distance <a href="https://interviewquestions.tuteehub.com/tag/covered-2552266" style="font-weight:bold;" target="_blank" title="Click to know more about COVERED">COVERED</a>.</body></html> | |
| 37602. |
At what temperature, hydrogen molecules will escape from the earth's surface? (Take mass of hydrogen molecule =0.34 xx 10^(-6) kg, Boltzman constant =1.38 xx 10^(-23) KJ^(-1). Radius of earth =6.4 xx 10^(6)m" and acceleration due to gravity "=9.8 ms^(-2)) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/10k-267087" style="font-weight:bold;" target="_blank" title="Click to know more about 10K">10K</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)K`<br/>`10K`<br/>`10^(4)K`</p>Answer :D</body></html> | |
| 37603. |
A small source of sound vibrating at frequency 500 Hz is rotated in a circle of radius 100/2pi cm at a constant angular speed of 5-0 revolutions per second. A listener situates himself in the plane of the circle. Find the minimum and the maximum frequency of the sound observed. Speed of sound in air = 332 m s^-1. |
| Answer» <html><body><p><br/></p>Solution :Acording to given data <br/> `Radius of the circle `=100/picm` <br/> `=100/pixx10^-2m` <br/> `=(1/pi)<a href="https://interviewquestions.tuteehub.com/tag/metres-1095332" style="font-weight:bold;" target="_blank" title="Click to know more about METRES">METRES</a>` <br/> `omega=5rev/sec` <br/> So the linear speed <br/> `v=omegar=5/pi=(1.59)` <br/> so, velocity of the <a href="https://interviewquestions.tuteehub.com/tag/source-1219297" style="font-weight:bold;" target="_blank" title="Click to know more about SOURCE">SOURCE</a> <br/> `V_s=1.59m/s` <br/> so the at the position A the observer will listen maximum and at the position <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> it will listen <a href="https://interviewquestions.tuteehub.com/tag/minimum-561095" style="font-weight:bold;" target="_blank" title="Click to know more about MINIMUM">MINIMUM</a> frequency. <br/> So apparent frequency at A <br/> `=(<a href="https://interviewquestions.tuteehub.com/tag/332-1856202" style="font-weight:bold;" target="_blank" title="Click to know more about 332">332</a>/(332+159))xx500~~515Hz` <br/> So apparent frequency at B <br/> `=(332/((332+159))xx500~~485GHz`</body></html> | |
| 37604. |
If the time period (t) of vibration of a liquid drop depends on density (rho) of the liquid, radius (r) of the drop and surface tension (S), then the expression of t is where k is a dimensionless constant. |
| Answer» <html><body><p>`t= ksqrt((rhor^(3))/(S))`<br/>surface tension<br/>`t= ksqrt((rhor^(3))/(S^(1//2)))`<br/>`t= ksqrt((rhor)/(S))`</p>Solution :Let `t= krho^(x)r^(y)S^(z)` <br/> where k is a dimensionless constant <br/> Equating dimensions on both sides, we get <br/> `[T]= [<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(-3)]^(x)[<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>]^(y)[ML^(0)T^(-2)]^(z)` or `[M^(0)L^(0)T]= [M^(x+z)L^(-3x+z)T^(-<a href="https://interviewquestions.tuteehub.com/tag/2z-301338" style="font-weight:bold;" target="_blank" title="Click to know more about 2Z">2Z</a>)]` <br/> According to <a href="https://interviewquestions.tuteehub.com/tag/principle-1166255" style="font-weight:bold;" target="_blank" title="Click to know more about PRINCIPLE">PRINCIPLE</a> of homogeneity of dimensions we get <br/> x+z= 0...(i) <br/> -3x+y=0 ..(ii) <br/> -2z = 1 ...(iii) <br/><a href="https://interviewquestions.tuteehub.com/tag/solving-1217196" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVING">SOLVING</a> equations (i), (ii), and (iii), we get <br/> `x= (1)/(2), y= (3)/(2), z= (-1)/(2) :. t= krho^(1//2)r^(3//2)S^(-1//2)` or `t= ksqrt((rhor^(3))/(S))`</body></html> | |
| 37605. |
Two holes, each of area A = 0.2 cm^(2) are drilled in the wall of a vessel filled with water. The distances of the holes from the level of water are h and h + H. Find the point where the streams flowing out of the holes intersect. The level of water is maintained in the vessel by regulated supply. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`[<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> = 2sqrt(<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>(h+H)), y = H + <a href="https://interviewquestions.tuteehub.com/tag/2h-300377" style="font-weight:bold;" target="_blank" title="Click to know more about 2H">2H</a>]`</body></html> | |
| 37606. |
Find the angle .theta. with the lower vertical at which the resultant acceleration of the bob is along the horizontal, when the perpendicular is released from horizontal position. |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Since the resultant acceleration is along the horizontal, the <a href="https://interviewquestions.tuteehub.com/tag/vertical-726181" style="font-weight:bold;" target="_blank" title="Click to know more about VERTICAL">VERTICAL</a> acceeleration at .P. should be zero. <br/> ie., `a_(c) sin(90 - theta) = a_(t) sin theta` <br/> `(a_(c))/(a_(1)) = tan theta ..... (1)`<br/> But `a_(c) = (v^(2))/(l)(2glcostheta)/(l)=2gcostheta` <br/> and `a_(1) = g sin theta` <br/> Then `(a_(c))/(a_(t)) = 2 cot theta` <br/> <a href="https://interviewquestions.tuteehub.com/tag/substituting-1231652" style="font-weight:bold;" target="_blank" title="Click to know more about SUBSTITUTING">SUBSTITUTING</a> in <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> (1) <br/> `2 cot theta = Tan theta` <br/> Hence `theta = tan^(-1) (sqrt(2))` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP2_C06_SLV_030_S01.png" width="80%"/></body></html> | |
| 37607. |
A bullet is fired normally on an immovable wooden plank of thickness 2 m. It loses 20% of its kinetic energy in penetrating a thickness 0.2 m of the plank. The distance penetrated by the bullet inside the wooden plank is |
| Answer» <html><body><p>0.2m<br/>0.8m<br/>1m<br/><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.5m</p>Solution :The wood offers a constant retardation. If the <a href="https://interviewquestions.tuteehub.com/tag/bullet-403823" style="font-weight:bold;" target="_blank" title="Click to know more about BULLET">BULLET</a> loses 20% of its kinetic energy by <a href="https://interviewquestions.tuteehub.com/tag/penetrating-2919730" style="font-weight:bold;" target="_blank" title="Click to know more about PENETRATING">PENETRATING</a> 02 m. It can <a href="https://interviewquestions.tuteehub.com/tag/penetrate-590781" style="font-weight:bold;" target="_blank" title="Click to know more about PENETRATE">PENETRATE</a> further into `4xx 0.2 = 0.8 m` with the remaining kinetic energy So the total <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> penetrated by the bullet is `0.2 + 0.8 = 1 m`</body></html> | |
| 37608. |
The volume of a liquid (v) flowing per second through a cylindrical tube depends upon the pressure gradient (p/l) radius of the tube (r ) coefficient of viscosity (eta) of the liquid by dimensional method the correct formula is |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>>`V <a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> (<a href="https://interviewquestions.tuteehub.com/tag/pr-592713" style="font-weight:bold;" target="_blank" title="Click to know more about PR">PR</a>^(4))/(<a href="https://interviewquestions.tuteehub.com/tag/eta-446786" style="font-weight:bold;" target="_blank" title="Click to know more about ETA">ETA</a> l)`<br/>`V oo (P r)/(eta l^(4))`<br/>`V prop (Pl^(4))/(eta r)`<br/>none</p>Answer :A</body></html> | |
| 37609. |
Explain in detail the idea of weightlessness using lift as an example. |
| Answer» <html><body><p></p>Solution :When a man is standing in the elevator, there are two forces acting on him. <br/>1. Gravitational force which acts downward. If we take the vertical direction as <a href="https://interviewquestions.tuteehub.com/tag/positive-1159908" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVE">POSITIVE</a> y direction, the gravitational force acting on the man is `vecF_G =- <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a> hatj` <br/>The normal force exerted by floor.on the man which acts vertically upward, `vecN = Nhatj`Weightlessness of freely falling bodies: Freely falling objects <a href="https://interviewquestions.tuteehub.com/tag/experience-25558" style="font-weight:bold;" target="_blank" title="Click to know more about EXPERIENCE">EXPERIENCE</a> only gravitational force. As they fall freely, they are not in <a href="https://interviewquestions.tuteehub.com/tag/contact-25916" style="font-weight:bold;" target="_blank" title="Click to know more about CONTACT">CONTACT</a> with any surface (by neglecting air friction). The normal force acting on the object is zero. The downward acceleration is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to the acceleration due to the gravity of the i.e., (a = g) . Newton.s 2nd law acting on the man `N= mg (g - a) [ because a = g ] N= 0`</body></html> | |
| 37610. |
A spring of force constant 'k' is stretched by a small length 'x'. The work done is stretching it further by a small length 'y' is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)k(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>^(2)+y^(2))`<br/>`(1)/(2)k(x+y)^(2)`<br/>`(1)/(2)k(y^(2)-x^(2))`<br/>`(1)/(2)<a href="https://interviewquestions.tuteehub.com/tag/ky-1065003" style="font-weight:bold;" target="_blank" title="Click to know more about KY">KY</a>(2x+y)`</p>Answer :D</body></html> | |
| 37611. |
A simple pendulum with a metal bob has a time period 'T'. Now the bob is immersed in a liquid which is non viscous. Thus time period is '3T'. Then the ratio of densities of metal bob and that of liquid is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> : <a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>`<br/>`9 : 8`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> : 9`<br/>`9 : 1`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37612. |
In above problemabout an axisperpendicularto the palneof frameand passing through a cornerof framethe moment of inertiaof threebodies is |
| Answer» <html><body><p>`ML^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`2ML^(2)`<br/>`sqrt(3)ML^(2)`<br/>`(3ML^(2))/2 ` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`I = 2 [ ML^(2)] `</body></html> | |
| 37613. |
In the following question statement 1 represent Assertion and statement 2 represents Reason .Statement 1 : In a uniform circularmotion the momentum of a particle does not change with time .Statement 2 : The kinetic energy of the particle remains constnat .Choose the correct statement of the following statements |
| Answer» <html><body><p>Statement <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> is true and statement 2 is true and it <a href="https://interviewquestions.tuteehub.com/tag/explains-2627999" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLAINS">EXPLAINS</a> statement 1.<br/>Statement 1 is true and statement 2 is true and it does not explain statement 1.<br/>Statement 1 is true and statement 2 is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a>.<br/>Statement 1 is false and statement 2 is true.</p>Solution :The momentum changes with time sincethe <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> ofvelocity vector <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> with time .<br/>But its velocity remains constant . So kinetic energy remainsconstant .</body></html> | |
| 37614. |
A body cools from 70^(@)C to 50^(@)C in 5 minutes. Temperature of surroundings is 20^(@)C. Its temperature after next 10 minutes is |
| Answer» <html><body><p>`25^(0)C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/35-308504" style="font-weight:bold;" target="_blank" title="Click to know more about 35">35</a>^(0)C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(0)C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^(0)C`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 37615. |
{:("List -I","List -II"),((a)"fraction of total energy that is utilised to increase internal energy of a monoatomic gas ",(e)0.25),((b)"fraction of total energy that is involved in expansion for a triatomic gas ",(f) "infinity"),((c)"specific heat during isothermal process ",(g) zero),((d)"specific heat during adiabatic process",(h)0.6):} |
| Answer» <html><body><p>a-h, b-e,<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>-g,d-h<br/>a-g, b-h, c-f, d-e<br/>a-h, b-e, c-f, d-g <br/>a-e, b-h, c-f, d-g</p>Answer :C</body></html> | |
| 37616. |
A horizontal disc is freely rotating about a vertical axis passing through its centre at the rate of 100 rpm. A bob of wax of mass 20 g falls on the disc and sticks to it a distance of 5 cm from the axis. If the moment of inertia of the disc about the given axis is 2xx10^(-4)kgm^(2), find new frequency of rotation of the disc. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`I_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` Momnet of inertia of the disc `=2xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)kgm^(2)` <br/> `I_(2)` = <a href="https://interviewquestions.tuteehub.com/tag/moment-25786" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENT">MOMENT</a> of inertia of the disc+Moment of inertia of the bob of wax on the dise <br/> `=2xx10^(-4)+mr^(2)=2xx10^(-4)+20xx10^(-3)(0.05)^(2)` <br/> `=2xx10^(-4)+0.5xx10^(-4)=2.5xx10^(-4)kgm^(2)` <br/> `(n//t)_(1)=100" rpm" ,(n//t_(2))=?` <br/> By the principle of conservation of angular momentum, <br/> `I_(1)omega_(1)=I_(2)omega_(2)""I_(1)2pi((n)/(t))_(1)=I_(2)2pi((n)/(t))_(2)` <br/> `2xx10^(-4)xx100=2.5xx10^(-4)((n)/(t))_(2)` <br/> `((n)/(t))_(2)=(100xx2)/(2.5)=80" rpm"`</body></html> | |
| 37617. |
A particle moves along a straight line retardation a = ksqrt(v) [ k is a positive constant ]. The velocity of the particle at time t = 0 is u. How far would the particle move before coming to rest ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(2)/(<a href="https://interviewquestions.tuteehub.com/tag/3k-310983" style="font-weight:bold;" target="_blank" title="Click to know more about 3K">3K</a>)usqrt(<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>);(2)/(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)sqrt(u)`</body></html> | |
| 37618. |
(A): A wire may be stiffer than another wire B. But B may stronger than A (R): A high Young's modulus does not necessarily imply a high value for the breaking stress |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A) <br/> Both (A) and (R) are true and (R) is not the correct explanation of (A)<br/>(A) is true but (R) is false<br/>Both (A) and (R) are false</p>Answer :A</body></html> | |
| 37619. |
The coefficient of linear expansion alpha of a rod length 2m varies with distance x from one end as alpha=a+bx where a=1.5xx10^(-5)//""^(0)C and b=2.5xx10^(-6)//m-""^(0)C. Find the increase in the length of the rod when heated through 350^(0)C. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :12.25 <a href="https://interviewquestions.tuteehub.com/tag/mm-1098795" style="font-weight:bold;" target="_blank" title="Click to know more about MM">MM</a></body></html> | |
| 37620. |
A small hole is made at the bottom of a hollow sphere. The water enters into it when it is taken to a depth of 40 cm under water. If the surface tension of water is 0.07 Nm^(-1), diameter of the hole is |
| Answer» <html><body><p>`10//7mm`<br/>`10//14mm`<br/>`2//15mm`<br/>`1//14mm`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37621. |
The displacement r of a particle varies with time as x=4t^(2)-15t+25Find the position, velocity and acceleration of the particle at t = 0 |
| Answer» <html><body><p></p>Solution :Position, x=25 <br/> Velocity `=(dx)/(dt)=8t-15` <br/> `t=0,v=0-15=-15m//s` <br/> <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> `a=(<a href="https://interviewquestions.tuteehub.com/tag/dv-433533" style="font-weight:bold;" target="_blank" title="Click to know more about DV">DV</a>)/(dt)=8ms^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`.</body></html> | |
| 37622. |
Consider the system of weights P_(1)=1 kg,P_(2) = 2 kg,P_(3) = 5kg and P_(4) = 0.5 kg as shown in Figure 7.14. alpha = 30^(@), g = 9.8 ms^(-2) and the coefficient of friction between the weights and the planes is 0.2 Find (a) the acceleration of the system (b) tensions in the strings between P_(1) and P_(2) and that between P_(2) and P_(2) respectively and (c) the force with which P_(4) presses down on P_(3) [Hint : Make free-body diagrams and apply Newton's law of motion after resolving the forces acting on a body along and perpendicular to the plane on which it lies] |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`6.87 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) `8.83 N,16.12 N` (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>) 1.465 N</body></html> | |
| 37623. |
A boat moves relative to water with a velcity which is .n. times the river flow (a) If n lt t boat can not cross the river (b) If n = 1 boat can not cross the river without drifting (c) Ifgt 1 boat ca cross the river along shortest path (d) Boat can cross the river what ever is the value of n excluding zero value |
| Answer» <html><body><p>only a is correct<br/>a, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are correct<br/>c, d are correct<br/>b, c & d are correct</p>Answer :D</body></html> | |
| 37624. |
A large tank of water at a constant temperature of 90^(0)C is connected to a small vessel containing 10kg water at 10^(0)C, through a metal rod of length 2m, area of cross-section 0.5m^(2) and thermal conductivity of 20 units. If the time taken for the temperature of the water in small vessel at 30^(0)C is t=Nxx4200log(4//3), then find the value of N. (Given, specific heat of water =4200" J kg"^(-1)""^(0)C^(-1)) |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 37625. |
Examine table.s and express a) The energy required to break one bond in DNA in eV, b) the kinetic energy of an air molecule (10^(-2) J in eV, c) The daily intake of a human adult in kilocalories. |
| Answer» <html><body><p></p>Solution :a) Energy required to break one bond of DNA is: <br/> `(10^(-20)/(1.6 xx 10^(-19) J//eV) =~ 0.06 eV` <br/> Note, 0.1eV = 100meV (100 millielectron <a href="https://interviewquestions.tuteehub.com/tag/volt-1447797" style="font-weight:bold;" target="_blank" title="Click to know more about VOLT">VOLT</a>). B) the kinetic energy of an air molecule is <br/> `(10^(-21))/(1.6 xx 10^(-19)J//.eV=~ 0.0062eV` <br/> this is the same as 6.2 meV. <br/> c) The average human consumption in a <a href="https://interviewquestions.tuteehub.com/tag/day-944776" style="font-weight:bold;" target="_blank" title="Click to know more about DAY">DAY</a> is <br/> `10^(7)/(4.2xx 10^(3)J/kcal) -~2400 kcal` We point out a common misconception created by newspapers and magzines. They mention food <a href="https://interviewquestions.tuteehub.com/tag/values-25920" style="font-weight:bold;" target="_blank" title="Click to know more about VALUES">VALUES</a> in calories and urge us to restrict diet <a href="https://interviewquestions.tuteehub.com/tag/intake-1046890" style="font-weight:bold;" target="_blank" title="Click to know more about INTAKE">INTAKE</a> to below 2400 claories. What they should be saying in kilocalories (kcal) and not calories. A person <a href="https://interviewquestions.tuteehub.com/tag/consuming-931375" style="font-weight:bold;" target="_blank" title="Click to know more about CONSUMING">CONSUMING</a> 2400 calories a day will soon starve to death 1 food calorie is 1 kcal.</body></html> | |
| 37626. |
Two bodies of masses m_1 and m_2are separated by certain distance. If vecF_(12)is the force on m_1due to m_2and vecF_(21)is the force on m_2due to m_1then |
| Answer» <html><body><p>`F_(<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>) = F_(<a href="https://interviewquestions.tuteehub.com/tag/21-293276" style="font-weight:bold;" target="_blank" title="Click to know more about 21">21</a>)`<br/>`vecF_(12) = F_(21)`<br/>`vecF_(12) = -F_(21)`<br/>both 1 & 3 </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37627. |
A cyclist is riding with a speed of 27kmh^(-1). As he approaches a circular turn on the road of radius 80m, he applies brakes and reduces his speed at the constant rate of 0.50ms^(-1) every second. The net acceleration of the cyclist on the circular turn is |
| Answer» <html><body><p>`0.68 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`0.86 ms^(-2)`<br/>`0.56 ms^(-2)`<br/>`0.76 ms^(-2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37628. |
Why does a child feel more pain when she falls down on a hard cement floor, than when she falls on the soft muddy ground in the garden ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/whena-3274932" style="font-weight:bold;" target="_blank" title="Click to know more about WHENA">WHENA</a> childfallsona cementfloorthemomentumis reducedto zeroin comparativelylesserttime .<a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to thisrateof changeofmometumis largeso greaterforceact on himandchildfeels morepain.<br/> When childfalls on softmuddygroundmomentumis <a href="https://interviewquestions.tuteehub.com/tag/reduced-1181337" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCED">REDUCED</a> incomparativelylargertimehenceforcedecreaseandchildfeel lesspain.</body></html> | |
| 37629. |
The equation of motion of a particle is x=acos(alphat)^(2). The motion is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/periodic-598580" style="font-weight:bold;" target="_blank" title="Click to know more about PERIODIC">PERIODIC</a> but not oscillatory<br/>periodic and oscillatory<br/>oscillatory but not periodic<br/>Neither periodic nor oscillatory.</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> `x=acos(alphat)^(2)=acosalpha^(2)t^(2)` <br/> as the equation of motionn <a href="https://interviewquestions.tuteehub.com/tag/involves-519086" style="font-weight:bold;" target="_blank" title="Click to know more about INVOLVES">INVOLVES</a> <a href="https://interviewquestions.tuteehub.com/tag/cosine-936114" style="font-weight:bold;" target="_blank" title="Click to know more about COSINE">COSINE</a> function and `t^(2)` <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> it is oscillatory but not periodic.</body></html> | |
| 37630. |
A body is released from the top of a smooth inclined plane of inclination theta. It reaches the bottom with velocity v. If the angle of inclination is doubled for the same length of the plane, what will be the velocity of the body on reaching the ground |
| Answer» <html><body><p>v<br/>2v<br/>`(2cos theta)^((1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))v`<br/>`(2 <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> theta)^((1)/(2))v`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`v=sqrt(2gl sin theta), v^(1)=sqrt(2gl sin 2 theta)`</body></html> | |
| 37631. |
Two identical metal rods A and B are joined end to end. The free end of A is kept at 27°C and the free end of B at 37°C. Calculate the temperature of the interface. Thermal conductivity of A = 385 "Wm"^(-1) "K"^(-1), that of B 110 "Wm"^(-1) "K"^(-1). |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/385-1860872" style="font-weight:bold;" target="_blank" title="Click to know more about 385">385</a> A (T - 300) // <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> = 110 A (310 A - T) // l, T = 302.2 "K"`</body></html> | |
| 37632. |
According to parallelogram law of vector addition, the resultant is given by : |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(P^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) +<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a>^(2) +2PQcos theta)`<br/>`sqrt(P^(2) +Q^(2) - 2PQ <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta)`<br/>`sqrt((P^(2))/(Q^(2)))`<br/>`sqrt(P^(2) cos^(2) theta +Q^(2) sin ^(2) theta)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37633. |
A liquid is kept in a cylindrical vessel which is being rotated about a vertical axis through the centre of the circular base .If the redius of the vessel is r and angular velocity of rotation is omega, then the difference in the heights of the liquid at the centre of the vessel and the edge is ..... |
| Answer» <html><body><p>`(romega)/(2g)`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(2)omega^(2))/(2g)`<br/>`sqrt(2gromega)`<br/>`(omega^(2))/(2gr^(2))`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/according-366619" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDING">ACCORDING</a> to Bernoulli.s equation,<br/>`P_(A)+(1)/(2)rhov_(A)^(2)+rhogh_(A)`<br/>`=P_(B)+(1)/(2)rhov_(B)^(2)+rhogh_(B)`<br/>Here , `h_(A)=h_(B)`<br/>`thereforeP_(A)+(1)/(2)rhov_(A)^(2)`<br/>`=P_(B)+(1)/(2)rhov_(B)^(2)`<br/>`thereforeP_(A)-P_(B)=(1)/(2)rho[v_(B)^(2)-v_(A)^(2)]`<br/>Now ,`v_(A)=0,v_(B)-romegaandP_(A)-P_(B)=rhog`<br/>`thereforehrhog=(1)/(2)<a href="https://interviewquestions.tuteehub.com/tag/rhor-2993346" style="font-weight:bold;" target="_blank" title="Click to know more about RHOR">RHOR</a>^(2)omega^(2)orh=(r^(2)omega^(2))/(2g)`</body></html> | |
| 37634. |
Two bodies of masses m_(1) and m_(2) are moving at uniform speed along circular paths of radii r_(1) and r_(2) respectively. If they take equal time to describe the cricles completely, the ratio of their angular velocities will be |
| Answer» <html><body><p>`(r_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))/(r_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`(m_(1))/(m_(2))`<br/>`(m_(1) r_(1))/(m_(2) r_(2))`<br/>1</p>Answer :D</body></html> | |
| 37635. |
A cylinderical vessel filled with water is released on a fixed inclined surface of angle theta as shown in figure. The friction coefficient of surface with vessel in mu(lt tan theta). Then the constant with the incline will be (Neglect the viscosity of liquid) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/tan-1238781" style="font-weight:bold;" target="_blank" title="Click to know more about TAN">TAN</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) <a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a>`<br/>`theta-tan^(-1) mu`<br/>`theta+tan^(-1)mu`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/cot-936468" style="font-weight:bold;" target="_blank" title="Click to know more about COT">COT</a>^(-1)mu`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37636. |
Fill in the blanks using the words from the list appended with each statement Viscosity of glass…….with temperature,whereas viscosity of liquids…..with temperature (increases/decreases) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`eta` of <a href="https://interviewquestions.tuteehub.com/tag/gases-13668" style="font-weight:bold;" target="_blank" title="Click to know more about GASES">GASES</a> increases, `eta` of <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> <a href="https://interviewquestions.tuteehub.com/tag/decreases-946143" style="font-weight:bold;" target="_blank" title="Click to know more about DECREASES">DECREASES</a> with temperature</body></html> | |
| 37637. |
The area of the surface of water in a vessel is 40cm^2. It is transferred into a cylindrical vessel of area of cross section 220cm^2. If the surface tension of water is 0.07 Nm^(-1), the workdone in the transfer of water is neglect gravity. |
| Answer» <html><body><p>12.6 erg<br/>1.26 erg<br/>`12.6 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)` <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a><br/>`1.26 xx10^(-4)` J</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37638. |
Consider a cycle tyre bering filled with air by a pump. Let V be the volume of the tyre (fixed) and at each stroke of the pump DeltaV(=V) of air is transferred to the tube adiabatically. What is the work done when the pressure in the tube is increased from P_(1)" to "P_(2) ? |
| Answer» <html><body><p></p>Solution :`P(V+Deltaupsilon)^(<a href="https://interviewquestions.tuteehub.com/tag/gamma-470142" style="font-weight:bold;" target="_blank" title="Click to know more about GAMMA">GAMMA</a>)=(P+<a href="https://interviewquestions.tuteehub.com/tag/deltap-2053537" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAP">DELTAP</a>)V^(gamma)`<br/> `P[1+gamma(Deltaupsilon)/V]=P[1+(Deltap)/P]` <br/> `gamma(Deltaupsilon)/V=(Deltap)/P,(dupsilon)/(<a href="https://interviewquestions.tuteehub.com/tag/dp-959208" style="font-weight:bold;" target="_blank" title="Click to know more about DP">DP</a>)=V/(gammaP)` <br/> W.D =`int_(P_(1))^(P_(2))Pdupsilon= int_(P_(1))^(P_(2))PV/(gammaP)dp=((P_(2)-P_(1)))/gammaV`</body></html> | |
| 37639. |
The work done in moving a body of mass 5kg from the bottom of a smooth inclined plane to the top is 50 j. If the angle of inclination of the inclined plane is 30^(@), its length is (g = 10 ms^(-2)) |
| Answer» <html><body><p>1/2m<br/>1m<br/>2m<br/>4m</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37640. |
(I) Net Torque produces linear motion in rigid object. (II) Rolling motion is the combination of translational and rotational motions. Which statement is Incorrect ? |
| Answer» <html><body><p>I only <br/><a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a> only <br/>both are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/none-580659" style="font-weight:bold;" target="_blank" title="Click to know more about NONE">NONE</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :a</body></html> | |
| 37641. |
What is rolling friction ? Write laws of rolling friction. Define coefficient of rolling friction. |
| Answer» <html><body><p></p>Solution :Whenbody isrollingwithoutslidingfrictionforceis calledrollingfrictionit is denoted by`f_(r )`<br/> Duringrollingthe surfacein contactgetmomentarilydeformeda littleand smallpart ofbodyremainin contactwith surface<br/>Asa resultthere is componentof the contactforceparallelto surfacewhichopposesmotion<br/> `mu_(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a> ) ltmu_(k)<a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> mu_(s)`</body></html> | |
| 37642. |
Which of the following quantity is dimensionless ? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/strain-17653" style="font-weight:bold;" target="_blank" title="Click to know more about STRAIN">STRAIN</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/specific-1220917" style="font-weight:bold;" target="_blank" title="Click to know more about SPECIFIC">SPECIFIC</a> <a href="https://interviewquestions.tuteehub.com/tag/gravity-18707" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITY">GRAVITY</a> <br/>all of these </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37643. |
A system consists of three particles located at the corners of a right triangle as shown in the figure. Find the position vector of centre of mass of the system. |
| Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_MP2_C07_SLV_012_S01.png" width="80%"/> <br/> Using the <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> <br/> `X_(c)=(summ_(i)x_(i))/(M)=(2md+m(b+d)+3m(d+b))/(<a href="https://interviewquestions.tuteehub.com/tag/6m-332078" style="font-weight:bold;" target="_blank" title="Click to know more about 6M">6M</a>)=d+(2//<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)b` <br/> `Y_(c)=(summ_(i)y_(i))/(M)=(2m(o)+m(o)+<a href="https://interviewquestions.tuteehub.com/tag/3mh-1863494" style="font-weight:bold;" target="_blank" title="Click to know more about 3MH">3MH</a>)/(6m)=<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>//2` <br/> `Z_(c)=0`, because the particles are in X - Y plane we can express the position of centre of mass from the origin using a position vector as <br/> `vecr_(c)=X_(c)hati+Y_(c)hatj+Z_(c)hatk,vecr_(c)=(d+(2)/(3)b)hati+(h)/(2)hatj`</body></html> | |
| 37644. |
In a jar having a mixture of H_(2), and He |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/hydrogen-22331" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROGEN">HYDROGEN</a> has more <a href="https://interviewquestions.tuteehub.com/tag/mean-1091459" style="font-weight:bold;" target="_blank" title="Click to know more about MEAN">MEAN</a> KE<br/>Helium has more mean KE<br/>Both have same mean KE<br/>Both have same <a href="https://interviewquestions.tuteehub.com/tag/internal-517481" style="font-weight:bold;" target="_blank" title="Click to know more about INTERNAL">INTERNAL</a> energy</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37645. |
What is the excess pressure inside a bubble of soap solution of radius 5.00 mm. given that the surface tension of soap solution at the temperature (20^@C) is 2.50 times 10^-2 N m^-1? If an air bubble of the same dimension were formed at depth of 40.0 cm inside a container the soap solution (of relative density 1.20] what would be the pressure inside the bubble?[1 atmospheric pressure is 1.01 times 10^5 Pa). |
| Answer» <html><body><p></p>Solution :Excess pressure inside the soap <a href="https://interviewquestions.tuteehub.com/tag/bubble-904920" style="font-weight:bold;" target="_blank" title="Click to know more about BUBBLE">BUBBLE</a> =20.0 Pa excess pressure inside the <a href="https://interviewquestions.tuteehub.com/tag/air-852233" style="font-weight:bold;" target="_blank" title="Click to know more about AIR">AIR</a> bubble in soap solution =10.0Pa <a href="https://interviewquestions.tuteehub.com/tag/outside-1143075" style="font-weight:bold;" target="_blank" title="Click to know more about OUTSIDE">OUTSIDE</a> pressure for air bubble =`1.01 times 10^5+0.4 times 10^3 times 9.8 times 1.2=1.06 times 10^5 Pa`. The excess pressure is so small that up to <a href="https://interviewquestions.tuteehub.com/tag/three-708969" style="font-weight:bold;" target="_blank" title="Click to know more about THREE">THREE</a> significant <a href="https://interviewquestions.tuteehub.com/tag/figures-987769" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURES">FIGURES</a>, total pressures inside the air bubble is `1.06 times 10^5 Pa`</body></html> | |
| 37646. |
A Carnot engine of efficiency 40% , takes heat from a source maintained at a temperature of 500 K . If is desired to have an engine of efficiency 60%. Then , the source temperature for the same sink temperature must be |
| Answer» <html><body><p></p>Solution :`eta=<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>-(T_(2))/(T_(1)),0.4=1-(T_(2))/(500)<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> T_(2)=<a href="https://interviewquestions.tuteehub.com/tag/300k-306432" style="font-weight:bold;" target="_blank" title="Click to know more about 300K">300K</a>` <br/> `0.6=1-(T_(2))/(T_(1)^(1))=1-(<a href="https://interviewquestions.tuteehub.com/tag/300-305868" style="font-weight:bold;" target="_blank" title="Click to know more about 300">300</a>)/(T_(1)^(1))rArr T_(1)^(1)=(300)/(0.4)=<a href="https://interviewquestions.tuteehub.com/tag/750k-1919963" style="font-weight:bold;" target="_blank" title="Click to know more about 750K">750K</a>`</body></html> | |
| 37647. |
A body is rotating uniformly about vertical axis fixed in an inertial frame. The resultant force on a particle of the body not on the axis is |
| Answer» <html><body><p>vertical<br/>horizontal and <a href="https://interviewquestions.tuteehub.com/tag/skew-1211319" style="font-weight:bold;" target="_blank" title="Click to know more about SKEW">SKEW</a> with the axis<br/>horizontal and <a href="https://interviewquestions.tuteehub.com/tag/intersecting-2745467" style="font-weight:bold;" target="_blank" title="Click to know more about INTERSECTING">INTERSECTING</a> the axis<br/>none of these </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37648. |
The torque acting on a planet due to gravitational force of attraction is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a>`<br/>0<br/>moderate<br/>very high</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37649. |
The density of a non-uniform rod of length 1m is given by rho (x)=a (1+bx^(2)) where, a and b are constant and 0 le x le 1. The centre of mass of the rod will be at |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>(2+<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>))/(4(3b+b))`<br/>`(4(2+b))/(3(3+b))`<br/>`(3(3+b))/(4(2+b))`<br/>`(4(3+b))/(3(2b+b))`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Density is given as `rho (x) = a (1+bx^(2))` <br/> where a and b are constants and `0 le x le 1` <br/> <a href="https://interviewquestions.tuteehub.com/tag/let-11597" style="font-weight:bold;" target="_blank" title="Click to know more about LET">LET</a> `b rarr 0`, in this case <br/> `rho (x) = a=` constant <br/> Hence, centre of mass will be at `x=0.5` m (<a href="https://interviewquestions.tuteehub.com/tag/middle-1096062" style="font-weight:bold;" target="_blank" title="Click to know more about MIDDLE">MIDDLE</a> of the rod) Putting, `b=0` in all the options, only (a) given 0.5. <br/> Note : We should not check options by putting `a=0`, because `rho = 0` for a = 0.</body></html> | |
| 37650. |
A motorist drives north for 35.0 minutes at 85.0 km/h and then stops for 15.0 minutes. He next continues north, travelling 130 km in 2.00 hours. What is his total displacement |
| Answer» <html><body><p>85km<br/>179.6km<br/>20km<br/>140km</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |