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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 37551. |
A particle of mass 1 kg moves from test along a straight line by the action of a force F which varies with the distance x as shown in the F-x graph. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> kinetic energy of the <a href="https://interviewquestions.tuteehub.com/tag/particle-1147478" style="font-weight:bold;" target="_blank" title="Click to know more about PARTICLE">PARTICLE</a> is 25 J<br/>Maximum rate of <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in kinetic energy is `10sqrt(40)`W<br/>Total work <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> by the particle is 5J.<br/>There will be no power delivered by the particle at x=3 and 6m</p>Answer :A::<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>::D</body></html> | |
| 37552. |
An artificial satellite of mass 'm' is revolving around the earth, in a circular orbit of radius 'r'. If the mass of the earth is 'm' angular momentum of the satellite with respect to the centre of earth is (G-universal gravitational constant) |
| Answer» <html><body><p>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/gmm-2090431" style="font-weight:bold;" target="_blank" title="Click to know more about GMM">GMM</a>^(2)<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>)`<br/>`2msqrt(<a href="https://interviewquestions.tuteehub.com/tag/gmr-468745" style="font-weight:bold;" target="_blank" title="Click to know more about GMR">GMR</a>)`<br/>`2msqrt(Gmr)`<br/>`sqrt((<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(r))`</p>Answer :A</body></html> | |
| 37553. |
A stone is allowed to fall from the top of a tower 300m height and at the same time another stone is projected vertically up from the ground with a velocity 100ms^(-1). Find when and where the two stones meet? |
| Answer» <html><body><p></p>Solution :Suppose the two stones meet at a <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> x from ground after t <a href="https://interviewquestions.tuteehub.com/tag/seconds-1198593" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDS">SECONDS</a>. <br/> `x=100t-(1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)g t^(2)…..(1)` <br/> `300-x=0+(1)/(2)g t^(2)…..(2)` <br/> Solve 1, 2 <br/> `t=3` <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>, `x=255.9m`</body></html> | |
| 37554. |
Resonance is an example of : |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/tuning-1428825" style="font-weight:bold;" target="_blank" title="Click to know more about TUNING">TUNING</a> of <br/><a href="https://interviewquestions.tuteehub.com/tag/damped-943597" style="font-weight:bold;" target="_blank" title="Click to know more about DAMPED">DAMPED</a> variation<br/>forced <a href="https://interviewquestions.tuteehub.com/tag/vibration-1446079" style="font-weight:bold;" target="_blank" title="Click to know more about VIBRATION">VIBRATION</a><br/>free vibration </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37555. |
Calculate the excess of pressure inside an air bubble of radius 1 mm formed just below the free surface of water. Given surface tension of water 72xx10^-3Nm^-1. |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/excess-978535" style="font-weight:bold;" target="_blank" title="Click to know more about EXCESS">EXCESS</a> <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> P = 2s/R <br/> = `(2xx72xx10^-3)/(1xx10^-3)=144Nm^-2`</body></html> | |
| 37556. |
If the ratio of the orbital distance of two planets (d_1)/(d_2)=2, what is the ratio of gravitational field experienced by these two planets? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Given:`(d_1)/(d_2)=<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` <br/><a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a>:Gravitational <a href="https://interviewquestions.tuteehub.com/tag/field-987291" style="font-weight:bold;" target="_blank" title="Click to know more about FIELD">FIELD</a>,<br/>`E=(GM)/(d^2)` <br/>`(E_2)/(E_1)=(((GM)/(d_(2)^(2))))/(((GM)/(d_(1)^(2))))=((d_1)/(d_2))^(2)=(2)^(2)` <br/>`(E_2)/(E_1)=4` <br/>`E_(2)=4E_(1)`</body></html> | |
| 37557. |
A bomb, while falling vertically downward explodes, just when it attains the velocity u, into two fragments of mass ratio 2 : 1. If the heavier of the two masses starts moving vertically downwards with a velocity 2u, find the direction and magnitude of velocity of the lighter mass at that moment. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>, <a href="https://interviewquestions.tuteehub.com/tag/upwards-2318352" style="font-weight:bold;" target="_blank" title="Click to know more about UPWARDS">UPWARDS</a></body></html> | |
| 37558. |
According to Newton's law of cooling, the rate of cooling of a body is proportional to (Delta theta)^(n) , where Delta thetais difference of temperature of body and surroundings, and n is equal to |
| Answer» <html><body><p>1<br/>2<br/>3<br/>4</p>Answer :A</body></html> | |
| 37559. |
When is the work done on the body said to be zero ? |
| Answer» <html><body><p></p>Solution :The work done on the body be zero under following situationusingformula `W = fd <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a> theta `<br/> (1) Work done is zerowhenthe force.Asfor example, a blockmovingon a smoothhorizontaltableis notactedupon by a horizontalforcebutmayundergoa largedisplacement . <br/> (2) There is no displacement of bodyeven the force is exerted on it . As for example, when one push hard againsta rigidbrick wall , the force exert on the wall does not work .<br/> (<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) When force and displacement are mutually perpendicular . <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C06_E01_015_S01.png" width="80%"/><br/> For example, during uniform circularmotion , the displacementof the body is always along tangent of the circle andthe force actingon the bodyis alwaystowardsthe centreof circleso forceand displacement is perpendicularto eachother . In this situation work doneby centripetal force is zero . <br/> (4) (a) When more than one force acts on body and the net force of all these forces is zero then work done is zero . <br/> For example: A <a href="https://interviewquestions.tuteehub.com/tag/cylinder-942617" style="font-weight:bold;" target="_blank" title="Click to know more about CYLINDER">CYLINDER</a> is vertically tugwith string as shown in figure . Gravitational force of earth acting on the cylinder and hence tension in teh stringacting in upward directionbut here displacement of cylinder is zero so work done is also zero .<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C06_E01_015_S02.png" width="80%"/><br/> (b) A sphere is placed in a V - shaped ditch as shown in figure (<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> ). There are three forcesacting on it . Even though it doesn.t <a href="https://interviewquestions.tuteehub.com/tag/move-548879" style="font-weight:bold;" target="_blank" title="Click to know more about MOVE">MOVE</a> . So the displacement by every force is zero and hence total work is also zero .</body></html> | |
| 37560. |
Statement 1 represents Assertion, statement 2represent Reasons .Statement I :In a non uniform circular motion, a body has one acceleration along the tangent to the circle and the other acceleration acts towards the centre of the circular motion . Setement 2: The magnitude and direction of the velocity of the bodychange with time in the non-uniform circular motion. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/statement-16478" style="font-weight:bold;" target="_blank" title="Click to know more about STATEMENT">STATEMENT</a> <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> is true and statement 2 is ture and explains statement 1 correctly.<br/>Statement 1 is true and statement 2 is true but it is not the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation for statement 1 <br/>Statement 1 is true and statement 2 is false.<br/>Statement 1 is false and statement 2 is true.</p>Answer :A</body></html> | |
| 37561. |
A disc of radius R=10 cm oscillates as a physical pendulum about an axis perpendicular to the plane of the disc at a distance r from its centre. If r=(R)/(4), the approximate period of oscillation is (Take g=10ms^(-2)) |
| Answer» <html><body><p>0.84 s<br/>0.94 s<br/>1.26 s<br/>1.42 s</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_OBJ_FING_PHY_XI_C14_E01_082_S01.png" width="80%"/> <br/> `T=2pisqrt((I)/(mgh))` <br/> Where I is the moment of inerrtia of the <a href="https://interviewquestions.tuteehub.com/tag/pendulum-1149901" style="font-weight:bold;" target="_blank" title="Click to know more about PENDULUM">PENDULUM</a> about an axiis through the pivot, <br/> m is the mass of the pendulum and h is the distance from the pivot to the centre of mass. <br/> In this case, a <a href="https://interviewquestions.tuteehub.com/tag/solid-1216587" style="font-weight:bold;" target="_blank" title="Click to know more about SOLID">SOLID</a> disc of R oscillates as a physical pendulum about an axiis perpendicular to the plane of the disc at a distance r from its centre. <br/> `thereforeI=(mR^(2))/(2)+mr^(2)=(mR^(2))/(2)+m((R)/(4))^(2)=(mR^(2))/(2)+(mR^(2))/(16)` <br/> `=(9mR^(2))/(16)""(becauser=(R)/(4))` <br/> Here, `R=10cm=0.1m,h=(R)/(4)` <br/> `thereforeT=2pisqrt(((9mR^(2))/(16))/((mgR)/(4)))=2pisqrt((9R)/(4g)` <br/> `=2pisqrt((9xx0.1)/(4xx10))=2pixx(3)/(2)xx(1)/(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)=0.94s`</body></html> | |
| 37562. |
A particle is subjected to two S H Ms x_(1) = A_(1) sin wt and x_(2) = A_(2) sin (w t + pi//4). The resultant S H M will have an amplitude of |
| Answer» <html><body><p>`(A_1 +A_2)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(A_1^2 + A_2^2)`<br/>`sqrt(A_1^2+ A_2^2 + sqrt(2) A_1A_2) `<br/>`A_1A_2`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37563. |
A wheel is rotating at the rate of 33 "rev min"^(-1). If it comes to stop in 20 s. Then, the angular retardation will be |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> <a href="https://interviewquestions.tuteehub.com/tag/rad-1175618" style="font-weight:bold;" target="_blank" title="Click to know more about RAD">RAD</a> s^(-2)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a> pi rads^(-2)`<br/>`(pi)/(200) rads^(-2)`<br/>`(11 pi)/(200) rads^(-2)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Angular <a href="https://interviewquestions.tuteehub.com/tag/retardation-1187717" style="font-weight:bold;" target="_blank" title="Click to know more about RETARDATION">RETARDATION</a>, `alpha=(omega_(0))/(t)""(because 0=omega_(0)-alphat)` <br/> `=(2pixx33//60)/(20)=(11pi)/(200) "rad s"^(-2)`.</body></html> | |
| 37564. |
Let the source propagate a sound waves whose intensity ata point (initially) be l. suppose we consider a case when the amplitude of the sound wave is doubled and the frequency is reduced to one-fourth. Calculate now the new intensity of sound at the same point? |
| Answer» <html><body><p></p>Solution :Intensity of sound <a href="https://interviewquestions.tuteehub.com/tag/wave-22399" style="font-weight:bold;" target="_blank" title="Click to know more about WAVE">WAVE</a> (old) = `I_(1)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/amplitudeof-2415378" style="font-weight:bold;" target="_blank" title="Click to know more about AMPLITUDEOF">AMPLITUDEOF</a> sound wave `(A_(2)) = 2 A_(1)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> of the sound wave `f_(2) = (1)/(4) f_(1)` <br/> Intensity of sound wave `I_(2) = ?` <br/> `I_(1) <a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> f_(1)^(2) A_(1)^(2) , I_(2) prop f_(2)^(2) A_(2)^(2)` <br/> `(I_(1))/(I_(2)) = (f_(1)^(2) * A_(1)^(2))/(f_(2)^(2) * A_(2)^(2)) = (f_(1)^(2) A_(1)^(2))/((1)/(16) f_(1)^(2) * 4 A_(1)^(2)) = (16)/(4) = 4` <br/> `I_(2) = (1)/(4) I_(1)`</body></html> | |
| 37565. |
Find the derivative with respect to t, of the function x=A_(0)+A_(1)t+A_(2)t^(2) where A_(0),A_(1)andA_(2) are constants. |
| Answer» <html><body><p></p>Solution :Note that here the independent variable is . and the dependent variable is .<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>.. <br/> The <a href="https://interviewquestions.tuteehub.com/tag/required-1185621" style="font-weight:bold;" target="_blank" title="Click to know more about REQUIRED">REQUIRED</a> <a href="https://interviewquestions.tuteehub.com/tag/derivative-948877" style="font-weight:bold;" target="_blank" title="Click to know more about DERIVATIVE">DERIVATIVE</a> is `(dy)/(dx)=+A_(1)+2A_(2)t`. <br/> he second derivative is `(d^(2)<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>)/(dt^(2))=2A_(2)`.</body></html> | |
| 37566. |
A synchronous satellite should be at a proper height moving |
| Answer» <html><body><p>from <a href="https://interviewquestions.tuteehub.com/tag/west-1451899" style="font-weight:bold;" target="_blank" title="Click to know more about WEST">WEST</a> to <a href="https://interviewquestions.tuteehub.com/tag/east-447972" style="font-weight:bold;" target="_blank" title="Click to know more about EAST">EAST</a> in equatorial <a href="https://interviewquestions.tuteehub.com/tag/plane-1155510" style="font-weight:bold;" target="_blank" title="Click to know more about PLANE">PLANE</a> <br/>from south to <a href="https://interviewquestions.tuteehub.com/tag/north-1124498" style="font-weight:bold;" target="_blank" title="Click to know more about NORTH">NORTH</a> in equatorial plane<br/>from east to west in equatorial plane<br/>from north to south in equatorial plane</p>Answer :A</body></html> | |
| 37567. |
The amount of work done by a moving body depends on the |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of body<br/>velocity<br/>time<br/>all of the above</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37568. |
In order to double the frequnecy of the fundamental note emitted by a stratched string the length is reduced to 3/4 th of the original length andthe tension is changed. The factor by which the tension is to be changed is |
| Answer» <html><body><p>`3/8`<br/>`2/3`<br/>`8/9`<br/>`9/4`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37569. |
An electronand a proton are moving under the influence of mutual forces . In calculating the change in the kineticenergy of the system during motion , one ignores the magnetic force of one on another . This is , because |
| Answer» <html><body><p>the <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> <a href="https://interviewquestions.tuteehub.com/tag/magnetic-551115" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNETIC">MAGNETIC</a> <a href="https://interviewquestions.tuteehub.com/tag/forces-16875" style="font-weight:bold;" target="_blank" title="Click to know more about FORCES">FORCES</a> are equal and opposite ,so they produce no net effect<br/>the magnetic forces do not <a href="https://interviewquestions.tuteehub.com/tag/work-20377" style="font-weight:bold;" target="_blank" title="Click to know more about WORK">WORK</a> on each particle <br/>the magnetic forces do equal and opposite (but non -zero) work on each particle .<br/>the magnetic forces are necessarily negligible .</p>Solution :When electron and proton are moving under influence of their mutual forces , the magnetic forces are perpendicular to tem hence work done by these forces is zero .</body></html> | |
| 37570. |
The earth is an approximate sphere. If the interior contained matter which is not of the same density everywhere, then on the surface of the earth, the acceleration due to gravity. |
| Answer» <html><body><p>will be directed towards the centre but not the same everywhere<br/>will have the same value everywhere but not directed towards the centre<br/>will be same everywhere in <a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a> directed towards the same<br/>cannot be <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> at any point</p>Solution :If we assume the earth as a sphere of uniform density, then it can bee treated as point <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> placed at its centre. In it is is not so, if the earth is <a href="https://interviewquestions.tuteehub.com/tag/considered-7257760" style="font-weight:bold;" target="_blank" title="Click to know more about CONSIDERED">CONSIDERED</a> as a sphere of non-uniform density, in that case value of g will be <a href="https://interviewquestions.tuteehub.com/tag/different-951434" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFERENT">DIFFERENT</a> at different points and cannot be zero at any point.</body></html> | |
| 37571. |
Action and reaction are forces acting simultaneously and acting on same object. |
| Answer» <html><body><p><br/></p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a>. Action and <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> are force <a href="https://interviewquestions.tuteehub.com/tag/acting-269" style="font-weight:bold;" target="_blank" title="Click to know more about ACTING">ACTING</a> on different <a href="https://interviewquestions.tuteehub.com/tag/object-11416" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECT">OBJECT</a>.</body></html> | |
| 37572. |
A satellite orbits the earth at a distance equal to the radius of the earth above its surface. Find (i) its speed and (ii) its period |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`5592ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>), <a href="https://interviewquestions.tuteehub.com/tag/4hrs-318949" style="font-weight:bold;" target="_blank" title="Click to know more about 4HRS">4HRS</a>`</body></html> | |
| 37573. |
A ball is thrown upwardsat a certain angle with the horizontal and it returns to the ground describing a parabolic path . Which of the following remains constant ? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> of the ball<br/>Kinetic <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> of the ball<br/>vertical <a href="https://interviewquestions.tuteehub.com/tag/component-926634" style="font-weight:bold;" target="_blank" title="Click to know more about COMPONENT">COMPONENT</a> of the <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a><br/>Horizontal component of the velocity </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37574. |
A body of mass 100 gm moving with an initial velocity of 4ms^(-1) collides with another body of mass 150 gm moving in opposite direction with velocity 6 ms^(-1). If the collision is perfectly inelastic, then after the collision, |
| Answer» <html><body><p>the two bodies inter change their velocities <br/>the two bodies combine and move with a <a href="https://interviewquestions.tuteehub.com/tag/common-923599" style="font-weight:bold;" target="_blank" title="Click to know more about COMMON">COMMON</a> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of `<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> ms^(-1)` in the <a href="https://interviewquestions.tuteehub.com/tag/initial-499269" style="font-weight:bold;" target="_blank" title="Click to know more about INITIAL">INITIAL</a> direction of lighter body <br/>the two bodies combine and move with a common velocity of `5.2 ms^(-1)` in the initial direction of heavier body<br/>the wo bodies combine and move with a common velocity of `2ms^(-1)` in the initial direction of heavier body</p>Answer :D</body></html> | |
| 37575. |
Four identical balls A,B,C and D are placed in a line on a frictionless horizontal surface. A and D are moved with same speed .u. towards the middle as shown. Assuming elastic collisions, find the final velocities. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`V _(A) = <a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> (to) ,V _(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) = 0, V _(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> ) = 0 and V _(D) = u (to)`</body></html> | |
| 37576. |
A transverse harmonic wave on a string is described by y(x,t)=3.0 sin (36t+0.018x +pi//4), where x and y are in cm and t is in s. The positive direction of x is from left to right. |
| Answer» <html><body><p>The wave is travelling from right to left. <br/>The speed of the wave is `20m//s`<br/>Frequency of the wave is 5.7 Hz<br/>The least distance betweent two successive crests in the wave is 2.5cm</p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> equation is`y(x,t)=3.0sin [36t+0.018x+(pi)/(4)]` <br/> (a As positive <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> is from left to right and x positive, therefore, wave is travelling from right to left. <br/> (b) <a href="https://interviewquestions.tuteehub.com/tag/compare-11929" style="font-weight:bold;" target="_blank" title="Click to know more about COMPARE">COMPARE</a> the given equation with the standard form <br/> `y=rsin[(2pit)/(T)+(2pix)/(lambda0+phi)]` <br/> `(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>)/(T)=36, (2pi)/(<a href="https://interviewquestions.tuteehub.com/tag/lambda-539003" style="font-weight:bold;" target="_blank" title="Click to know more about LAMBDA">LAMBDA</a>)=0.018` <br/> speed of wave, `upsilon=(lambda)/(T)=(36)/(0.018)=2000cm//s=20m//s` <br/> (c) Again, `T=(2pi)/(36)=(pi)/(18)` <br/> Frequency, `v=(1)/(V)=(18)/(pi)Hz=5.7Hz`</body></html> | |
| 37577. |
A barometer kept in an elevator moving upwards with an acceleration 2ms^-2 reads 63.1 cm of mercury. What will be the possible air pressure inside the elevator? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Pressure inside the elevator, <br/> = `(<a href="https://interviewquestions.tuteehub.com/tag/hrho-3664288" style="font-weight:bold;" target="_blank" title="Click to know more about HRHO">HRHO</a>(g+a))/(rhog)=(63.1xx13.6xx10^2(9.8+2))/(13.6xx10^3xx9.8)` = 76 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> of Hg</body></html> | |
| 37578. |
A person measures the time period of a simple pendulum inside a stationary lift and finds it to be 'T'. If the lift starts acceleration down wards with an acceleration g"/"3, the time period of the pendulum will be |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)T`<br/>`sqrt((3)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))T`<br/>`(T)/(sqrt(3))`<br/>`T"/"3`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37579. |
The mean length of an object is 5 cm. Which of the following measurements is most accurate ? |
| Answer» <html><body><p>`4.9 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>`<br/>`4.805 cm`<br/>`5.25 cm`<br/>`5.4 cm`<br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Among the <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> options, 4.9 cm is the closest to the exact <a href="https://interviewquestions.tuteehub.com/tag/value-1442530" style="font-weight:bold;" target="_blank" title="Click to know more about VALUE">VALUE</a>.</body></html> | |
| 37580. |
If a simple pendulum is arranged in an artificial satellite its a) Time period becomes infinity b) Frequency becomes infinity c) Both time period and frequency become infinity d) It does not oscillate |
| Answer» <html><body><p>a and d are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a><br/> a and b are correct<br/>b, <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> correct<br/>c, d are correct</p>Answer :A</body></html> | |
| 37581. |
Explain why high & low tide are formed on seas. |
| Answer» <html><body><p></p>Solution :The gravitational <a href="https://interviewquestions.tuteehub.com/tag/attraction-887653" style="font-weight:bold;" target="_blank" title="Click to know more about ATTRACTION">ATTRACTION</a> of moon on sea water cause high tides. Tides at one <a href="https://interviewquestions.tuteehub.com/tag/place-1155224" style="font-weight:bold;" target="_blank" title="Click to know more about PLACE">PLACE</a> cause low tides at another. Attraction by <a href="https://interviewquestions.tuteehub.com/tag/sun-1234558" style="font-weight:bold;" target="_blank" title="Click to know more about SUN">SUN</a> also causes tides but only half of the <a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a>. <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> on new moon and fall moon days. When both effects add, tides are very high.</body></html> | |
| 37582. |
A baloon of mass M is stationary in air. It has a ladder on which a man of mass m is standing. If the man starts climbing up the ladder with a velocity v relative to ladder, the velocity of balloon is |
| Answer» <html><body><p>`(m)/(M)` v <a href="https://interviewquestions.tuteehub.com/tag/upwards-2318352" style="font-weight:bold;" target="_blank" title="Click to know more about UPWARDS">UPWARDS</a> <br/>`(<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>)/((M+m))` <a href="https://interviewquestions.tuteehub.com/tag/downwards-959173" style="font-weight:bold;" target="_blank" title="Click to know more about DOWNWARDS">DOWNWARDS</a> <br/>`(mv)/((M+m))` upwards <br/>`(Mv)/((M+m))` downwards </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 37583. |
Find the time period of another pendulum of length equal to half of it at the same place. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> of <a href="https://interviewquestions.tuteehub.com/tag/simple-1208262" style="font-weight:bold;" target="_blank" title="Click to know more about SIMPLE">SIMPLE</a> <a href="https://interviewquestions.tuteehub.com/tag/pendulum-1149901" style="font-weight:bold;" target="_blank" title="Click to know more about PENDULUM">PENDULUM</a> is given by <br/> `T= 2pisqrt((l)/(g)) ….(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) :. G= 4pi^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)(l)/(T^(2))` i.e., `(l)/(T_(1)^(2))= (l_(2))/(T_(2)^(2)) implies (1.0)/(2^(2))= (0.50)/(T_(2)^(2))` or `T_(2)^(2)= (0.50)/(1.01) xx 4= 2 ` <br/> `:. T_(2)= sqrt(2)= 1.414s`</body></html> | |
| 37584. |
Due to Doppler effect , the shift in wavelenght observed is0.1 Åfor A star producing a wavelength of 6000Å What is the velocity of recession of the star ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :N/A</body></html> | |
| 37585. |
The displacement of a periodically vibrating particle isy = 4 cos ^(2)((1)/(2)t)sin (1000t) .Calculate the number of harmonic waves that are superposed . |
| Answer» <html><body><p></p>Solution :`y = 4 <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) ((1)/(2)t) ` sin (1000t)<br/>`2 * 2 cos^(2) ((1)/(2)t)* ` sin (1000 t)<br/>= 2 (1 + cos t ) sin (1000 t )<br/>= 2 sin (1000 t) + 2 sin (1000 t ) cos t<br/>= 2 sin (1000 t ) + sin (1000 t + t ) + sin ( 1000 t - t)<br/>= 2 sin (1000 t) + 1 sin (101 t ) + 1 sin (999 t )<br/>` = y_(1) + y_(2) + y_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>Here each of `y_(1),y_(2) and y_(3)`in the form of `a sin omegat` .Thus,each of them represents a harmonic wave .<br/>Hence, the number of <a href="https://interviewquestions.tuteehub.com/tag/superposed-7715918" style="font-weight:bold;" target="_blank" title="Click to know more about SUPERPOSED">SUPERPOSED</a> harmonic <a href="https://interviewquestions.tuteehub.com/tag/waves-13979" style="font-weight:bold;" target="_blank" title="Click to know more about WAVES">WAVES</a> = 3 .</body></html> | |
| 37586. |
Consider the following statements and identify the correct statements(A) Frictional force always opposes motion(B) Static frictional force is always greater than kinetic frictional force for a given pair of surfaces.(C ) Frictional force is a non conservative force |
| Answer» <html><body><p>All <a href="https://interviewquestions.tuteehub.com/tag/statements-17642" style="font-weight:bold;" target="_blank" title="Click to know more about STATEMENTS">STATEMENTS</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> <br/>Only <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true <br/>Only C is true <br/>Only B is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 37587. |
One end of a long metallic wire of length L is tied to the ceiling. The other end is tied to a spring of spring constant K. A mass m hangs from the free end of the spring. The area of cross-section and Young.s modulus of the wire are A and Y respectivley. Find the time period with which the mass m will oscillate if it is slightly pulled down and released? |
| Answer» <html><body><p></p>Solution :`Y=(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>)/(A),(L)/(x_(1)) rArr x_(1)=(FL)/(AY), F=Kx_(2) rArr x_(2)=(F)/(<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>=x_(1)+x_(2)=(F(LK+AY))/(KAY) rArr x= ma((LK+AY))/(KAY), (x)/(a) m=((LK+AY))/(KAY) rArr T=2pi <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((x)/(a))` <br/> `T=2pi sqrt((m(LK+AY))/(KAY))`</body></html> | |
| 37588. |
According to kinetic theory of gases, the rms velocity of the gas molecules is directly proportional to ....... |
| Answer» <html><body><p>`sqrtT` <br/>`T^3` <br/>`T` <br/>`T^4` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> velocity , ` V_(<a href="https://interviewquestions.tuteehub.com/tag/rms-1190227" style="font-weight:bold;" target="_blank" title="Click to know more about RMS">RMS</a>) = <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>( (3KT)/(m) ) <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> V_(rms) prop sqrtT`</body></html> | |
| 37589. |
What is the condition for the vectors 2i+3j-4k and 3i-aj+bk to be parallel ? |
| Answer» <html><body><p>`a=-9//<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>, b=-6`<br/>`a=-6, b=-9//2`<br/>a = <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>, b =5 <br/>a = <a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>, b = 2 </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37590. |
(A) When a body slides on rough surface, its momentum is not conserved.(B) When a ball falls from a height, momentum of earth ball system is conserved(C ) In case of explosion of flying bomb, momentum is conserved. |
| Answer» <html><body><p>A, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> <br/>A, B, <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are true <br/>A, C are <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>A is false </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 37591. |
Which fall faster-big rain drops or small rain drops? |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/terminal-11506" style="font-weight:bold;" target="_blank" title="Click to know more about TERMINAL">TERMINAL</a> velocity of rain drops is directly proportional to the sequence of radius of the drop.<br/>`V_(t)propr^(2)` <br/><a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> big drops <a href="https://interviewquestions.tuteehub.com/tag/fall-983217" style="font-weight:bold;" target="_blank" title="Click to know more about FALL">FALL</a> faster.</body></html> | |
| 37592. |
A refrigerator whose coefficient of performance is 5 extracts heat from the cooling compartment at the rate of 250 J per cycle. How mush electric energy is spend per cycle ? How much heat per cycle is discharged to the room ? |
| Answer» <html><body><p></p>Solution :`beta = (Q_(2))/(W)` <br/> `:. W = (Q_(2))/(beta) = (250)/(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) = <a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> J` <br/> `:.` Electric energy <a href="https://interviewquestions.tuteehub.com/tag/spent-1222060" style="font-weight:bold;" target="_blank" title="Click to know more about SPENT">SPENT</a> per cycle = 50 J <br/> Again, `Q_(1) = Q_(2) + W` <br/> or `Q_(1) = 250 + 50` or `Q_(1) = 300 J` <br/> `:.` <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> energy discharged per cycle to room = 300 J</body></html> | |
| 37593. |
Name and state the principle used .in solving the above problem. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/principle-1166255" style="font-weight:bold;" target="_blank" title="Click to know more about PRINCIPLE">PRINCIPLE</a> of <a href="https://interviewquestions.tuteehub.com/tag/homogeneity-1028735" style="font-weight:bold;" target="_blank" title="Click to know more about HOMOGENEITY">HOMOGENEITY</a>- of <a href="https://interviewquestions.tuteehub.com/tag/dimensions-439808" style="font-weight:bold;" target="_blank" title="Click to know more about DIMENSIONS">DIMENSIONS</a>.</body></html> | |
| 37594. |
Coefficient of restitution during the collision is changed to 1/2 keepting all other parameters unchanged. What is the velocity of the ball B after the collision ? |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)(3sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)hat(i) + 9hat(<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>)) m//s`<br/>`(1)/(4)(9hat(i) - 3sqrt(3)hat(j)) m//s`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/6hat-1912285" style="font-weight:bold;" target="_blank" title="Click to know more about 6HAT">6HAT</a>(i) + 3sqrt(3)hat(j))m//s`<br/>`(6hat(i) - 3sqrt(3)hat(j))m//s`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 37595. |
In the quastion number 71, what is the difference in the masses of the pieces? |
| Answer» <html><body><p>0.02 g <br/>0.021 g <br/>0.022 g<br/>0.024 g</p>Solution :Difference in masses <br/> `=m_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)-m_(1)=20.17g-20.15g` <br/> `=0.02`g (<a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> upto two places of <a href="https://interviewquestions.tuteehub.com/tag/decimal-435752" style="font-weight:bold;" target="_blank" title="Click to know more about DECIMAL">DECIMAL</a>)</body></html> | |
| 37596. |
The correct statement from the following is |
| Answer» <html><body><p>A body having Zero velocity will not <a href="https://interviewquestions.tuteehub.com/tag/necessarily-7276297" style="font-weight:bold;" target="_blank" title="Click to know more about NECESSARILY">NECESSARILY</a> have zero acceleration.<br/>A body having zero velocity will necessarily have zero acceleration.<br/>A body having uniform <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> can have only uniform acceleration.<br/>A body having monunilarm velocity will have zero itcgeleration</p>Answer :A</body></html> | |
| 37597. |
A ray of light refracts from medium 1 into a thin layer of medium 2, crosses the layer and is incident at the critical angle on the interface between the medium 2 and 3 as shown in the figure. IF the angle of incidence of ray is theta the value of of theta is: |
| Answer» <html><body><p>`sin^-1 (8/9)`<br/>`sin^-1 (13/18)`<br/>`sin^-1(13/16)`<br/>`sin^-1(8/13)</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 37598. |
A cylindrical container has cross sectional area of 0.20m^(2) and is open at the top. At the bottom, it has a small hole (A) kept closed by a cork. There is an air balloon tied to the bottom surface of the container. Volume of balloon is 2.2 litre. Now water is filled in the container and the balloon gets fully submerged. Volume of the balloon reduces to 2.0 litre.The cork is taken out to open the hole and at the same moment the whole container is dropped from a large height so as to fall under gravity. Assume that the container remains vertical. find the change in level of water inside the falling container 2 second after it starts falling. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> <a href="https://interviewquestions.tuteehub.com/tag/level-1072714" style="font-weight:bold;" target="_blank" title="Click to know more about LEVEL">LEVEL</a> will <a href="https://interviewquestions.tuteehub.com/tag/rise-1189674" style="font-weight:bold;" target="_blank" title="Click to know more about RISE">RISE</a> by <a href="https://interviewquestions.tuteehub.com/tag/1mm-283034" style="font-weight:bold;" target="_blank" title="Click to know more about 1MM">1MM</a>.</body></html> | |
| 37599. |
A 0.4 kg body is rotated with a constant angular speed of 2 rps in a verticle circle of radius 1.2 m with the help of a string. The tension in the string when it is at the highest point is (g = 10 ms^(-2) and pi^(2) = 10) |
| Answer» <html><body><p>79.8 N<br/>97.8 N<br/>72.8 N<br/>85.7 N</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 37600. |
A block of mass 1kg lies on a horizontal surface in the truck, the coefficient of friction between the block and the surface is 0.6. If the acceleration of the truck is 5ms^(-2) the frictional force acting on the block is |
| Answer» <html><body><p>2N<br/>5N<br/>3N<br/>6N</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |