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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 39151. |
Two capillaries of same diameter are dipped into liquids of specific gravity 0.4 and 0.8 respectively. If their surace tensions are in the ratio 6:5 then the ratio of heights of liquids in them will be |
| Answer» <html><body><p>`12:5`<br/>`5:12`<br/>`4:8`<br/>`8:4`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39152. |
A particle is found to be at rest when seen from a frame S_(1) and moving with a constant velocity when seen from another frame S_(2)(a) Both the frames are inertial(b) Both the frames are non inertial(c ) S_(1) is inertial and S_(2) is non inertial(d) S_(1) is non inertial and S_(2) is inertial |
| Answer» <html><body><p>a, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>, d are true <br/>b, c are true <br/>a, d are true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39153. |
A shell of mass 200 gm is ejected from a gun of mass 4 kg by an explosion that generates 1.05 kJ of energy. Calculate the initial velocity of the shell |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> Data: <br/> m= 200 gm = 0.2 kg , M=<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> kg, <br/> `"Energy <a href="https://interviewquestions.tuteehub.com/tag/generated-2093392" style="font-weight:bold;" target="_blank" title="Click to know more about GENERATED">GENERATED</a>" 1.05 KJ =1.05 xx 10^(3) J` <br/> According to <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of Conservation of linear momentum <br/> `mv=Mv^(.)` <br/> `:. v^(.)=((m)/(M))v` <br/> Total K.E of the <a href="https://interviewquestions.tuteehub.com/tag/gun-1014044" style="font-weight:bold;" target="_blank" title="Click to know more about GUN">GUN</a> and bullet <br/> `=(1)/(2)Mv^(.2)+(1)/(2)mv^(2)` <br/> `=(1)/(2)M((m)/(M)v)^(2)+(1)/(2)mv^(2)` <br/> `=(1)/(2)(m^(2)v^(2))/(M)+(1)/(2)mv^(2)` <br/> `=(1)/(2)mv^(2)[(m)/(M)+1]` <br/> `(1)/(2) xx 0.2 xx v^(2)[1+(0.2)/(4)]=1.05 xx 10^(3)J` <br/> `:. v^(2)=(4 xx 1.05 xx 1000)/(0.1 xx 4.2)=100^(2)` <br/> `v=100 m // s`</body></html> | |
| 39154. |
Give the expression for the fundamental frequency in the case of an open pipe system. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`f_(0) =(v )/( 2L)` where `v -` velocity of <a href="https://interviewquestions.tuteehub.com/tag/sound-648690" style="font-weight:bold;" target="_blank" title="Click to know more about SOUND">SOUND</a> in air and <br/> L-length ofthe pipe <br/> Note `:` with <a href="https://interviewquestions.tuteehub.com/tag/end-971042" style="font-weight:bold;" target="_blank" title="Click to know more about END">END</a> correction `f_(o) = ( v)/(4( L + <a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a> ))`</body></html> | |
| 39155. |
A disc of mass .m. and radius R has a concentric hole of radius .r.. Its M.I. about an axis through centre and normal to its plane is |
| Answer» <html><body><p>`(m)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>-r)^(2)`<br/>`(m)/(2)(R^(2)-r^(2))`<br/>`(m)/(2)(R+r)^(2)`<br/>`(m)/(2)(R^(2)+r^(2))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39156. |
A rope of negligible mass is wound round a hollow cylinder of mass 3 kg and radius 40 cm. What is the angular acceleration of the cylinder if the rope is pulled with a force of 30 N ? What is the linear acceleration of the rope ? Assume that there is no slipping. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a> s^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>),<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> m s^(-2)`</body></html> | |
| 39157. |
Average speed of a particle moving with different speed is average of different speed. |
| Answer» <html><body><p><br/></p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a>. <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> is ratio of total <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> covered and total time.</body></html> | |
| 39158. |
Find the components of vector vecA=2hati+3hatj along the directions of hati+hatj and hati-hatj. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`5/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(hati-hatj);((hatj-hati)/2)`</body></html> | |
| 39159. |
While during a carpet, we give a sudden jerk or beat it with a stick. Why? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Because inertia of rest keeps the <a href="https://interviewquestions.tuteehub.com/tag/dust-960865" style="font-weight:bold;" target="_blank" title="Click to know more about DUST">DUST</a> in its position and the dust gets removed as the carpet <a href="https://interviewquestions.tuteehub.com/tag/moves-1104598" style="font-weight:bold;" target="_blank" title="Click to know more about MOVES">MOVES</a> away.</body></html> | |
| 39160. |
The curve betwee log_(e)L and log_(e)P is (L is the angular momentum and P is the linear momentum): |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C05_E02_033_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C05_E02_033_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C05_E02_033_O03.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C05_E02_033_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39161. |
Energy of a diatomic molecule at high temperature is _________ |
| Answer» <html><body><p>`(7)/(3)RT` <br/>`(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(7)RT` <br/>`(8)/(2)RT` <br/>`(7)/(2)RT` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39162. |
What is compressibility ? Write its formula, unit and dimensional formula. |
| Answer» <html><body><p></p>Solution :The reciprocal of the bulk modulus is called compressibility. It is <a href="https://interviewquestions.tuteehub.com/tag/denoted-7335278" style="font-weight:bold;" target="_blank" title="Click to know more about DENOTED">DENOTED</a> by k. <br/> It is also <a href="https://interviewquestions.tuteehub.com/tag/defined-947013" style="font-weight:bold;" target="_blank" title="Click to know more about DEFINED">DEFINED</a> as the fractional chanage in volume per unit increase in <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a>. <br/> `k = ((1)/(B)) = (-1)/(Delta p) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> ((Delta V)/(V)) =- (Delta V//V)/( Delta p ) ` <br/> Its unit is `N^(-1) m ^(2) or Pa ^(-1)` and dimensional formula `[M^(-1) L ^(1) T ^(2)]`</body></html> | |
| 39163. |
Explain the variation of 'g' with altitude. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Variation of g with altitude: <br/> Consider an object of mass m at a height h from the <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> of the Earth. Acceleration experienced by the object due to Earth is <br/> `g' = (GM)/((R_(E) + h)^(2))` <br/> `R_(E) to` Radius of Earth <br/> `g' = (GM)/(R_(E)^(2)(1 + h/(R_E))^(2)) = (GM)/(R_E^2) (1 + h/(R_E))^(-2)` <br/> If `h < < R_(E)` <br/> We can use Binomial expansion. Taking the terms <a href="https://interviewquestions.tuteehub.com/tag/upto-1440527" style="font-weight:bold;" target="_blank" title="Click to know more about UPTO">UPTO</a> first order <br/> `g' = (GM)/(R_E^2) (1-2h/(R_E)) = g(1-2 h/(R_E))` <br/> We find <a href="https://interviewquestions.tuteehub.com/tag/tat-1239509" style="font-weight:bold;" target="_blank" title="Click to know more about TAT">TAT</a> `g' < g`. This means that as altitude h increases, the acceleration due to gravity g decreases. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_C06_E03_009_S01.png" width="80%"/>.</body></html> | |
| 39164. |
A faulty barometer tube is 90 cm long and it contains some air above mercury. The reading is 74.5 cm when the true atmospheric pressure is 76 cm. What will be the true atmopsheric pressure if the reading on this barometer is 74 cm? (H = 10m of water column) |
| Answer» <html><body><p>73.25 cm<br/>75.45 cm<br/>78.75 cm<br/>80.25 cm</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39165. |
In the question number 62, if the lift starts moving up with a uniform speed of 5 m s^(-1) and the girl again throws the ball up with the same speed, how much does the ball take to return to her hands? |
| Answer» <html><body><p>5 s<br/>10 s<br/>15 s<br/>20 s</p>Solution :When the lift starts moving upwards with uniform <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of `5 m s^(-1)`, there is no <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> of relative velocity of ball w.r.t <a href="https://interviewquestions.tuteehub.com/tag/girl-1005947" style="font-weight:bold;" target="_blank" title="Click to know more about GIRL">GIRL</a>. Hence, even in this case the ball will return to the girl's hands in the same time i.e 10 s.</body></html> | |
| 39166. |
A body of mass 2 kg is allowed to slide down along a quadrant of a circle from the horizontal position. In reaching to the bottom, Its velocity is 6m/sec. The work done in overcoming the friction is 10J. The radius of circle is (g=10 ms^(-2)) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> mgl<br/>4 m<br/>1.5 m<br/>2.3 m </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39167. |
Two ships are 10 km apart on a line running south to north. The one farther north is streaming west at 40 km per hr, the other ship is streaming towards north with the same speed. The time after which the two ships are at closed distance is |
| Answer» <html><body><p>7.5 min<br/>12 min<br/>14 min<br/>20 min</p>Answer :A</body></html> | |
| 39168. |
A foolball at 25^(@)C has 0.5 mole air molecules . calculate the internal energy of air in the ball. |
| Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/internal-517481" style="font-weight:bold;" target="_blank" title="Click to know more about INTERNAL">INTERNAL</a> energy of ideal <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> `=3/2` NkT. The number of air molecules is given in terms of number of moles so, rewrite the <a href="https://interviewquestions.tuteehub.com/tag/expression-980856" style="font-weight:bold;" target="_blank" title="Click to know more about EXPRESSION">EXPRESSION</a> as follows: <br/> `U=3/2muRT` <br/> Since `Nk=muR. "Here"mu` is number of moles. <br/> Gas <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> `R=8.31 J/("<a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>")K` <br/> Temperature`T=273+27^(@)C=300K` <br/> `U3/2xx0.5xx8.31xx300=1869.75J` <br/>This is approximately equivalent to the kinetic energy of a man of 57 kg runinf with a speed of 8 `ms^(-1)`</body></html> | |
| 39169. |
The horizontal acceleration that should be given to a smooth inclined plane of angle sin^(-1)((1)/(l)) to keep an object stationary on the plane, relative to the inclined plane is |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(l^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)-1))`<br/>`gsqrt(l^(2)-1)`<br/>`(sqrt(l^(2)-1))/(g)`<br/>`(g)/(sqrt(l^(2)+1))`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Resolve mg and pseudo <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> into components <br/> At equilibrium `mg sin theta=ma cos theta`</body></html> | |
| 39170. |
Three bodies each of mass.m. are placed at the three corners of a square of side .a.. The gravitational force on unit mass kept at the fourth corner is: |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(3a^(2))`<br/>`(Gm)/(<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)a^(2))`<br/>`(3Gm)/a^(2)`<br/>`(Gm)/a^(2)(sqrt(2) + 1/2)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39171. |
H calories of heat is required to increase thetemperature of one mole of monoatomic gas from 20^(@)C to 30^(@)C at const. volume. The quantity of heat required to increase the temperature of 2 moles of a diatomic gas from 20^(@)C to 25^(@)C is at constant volume is |
| Answer» <html><body><p>`(4H)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` <br/>`(5H)/(3)` <br/><a href="https://interviewquestions.tuteehub.com/tag/2h-300377" style="font-weight:bold;" target="_blank" title="Click to know more about 2H">2H</a> <br/>`(7H)/(3)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 39172. |
Explain why simple harmonic motion is called so ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :No. Because it is not to and <a href="https://interviewquestions.tuteehub.com/tag/fro-1000604" style="font-weight:bold;" target="_blank" title="Click to know more about FRO">FRO</a>.</body></html> | |
| 39173. |
A heavy small sized sphere is suspended by a string of length 2. The sphere is rotated uniformly in a horizontal circle with the string making an angle theta with the vertical. The time period of this conical pendulum is |
| Answer» <html><body><p>`2 pisqrt((<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> tantheta)/( g))`<br/>`2 <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> sqrt((l <a href="https://interviewquestions.tuteehub.com/tag/costheta-2550146" style="font-weight:bold;" target="_blank" title="Click to know more about COSTHETA">COSTHETA</a>)/(g))`<br/>`2 pisqrt((1)/(g))`<br/>`2 pi sqrt((l costheta)/(g))`</p>Solution :`2 pi sqrt((l costheta)/(g))`</body></html> | |
| 39174. |
A uniform flexible chain of mass m and length 2 hangs in equilibrium over a smooth horizontal pin of negligible diameter. One end of the chain is given a small vertical displacement so that the chain slips over the pin. The speed of chain when it leaves pin is- |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2gl)`<br/>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/gl-468610" style="font-weight:bold;" target="_blank" title="Click to know more about GL">GL</a>)`<br/>`sqrt(4gl)`<br/>`sqrt(3gl)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39175. |
A black body of mass 34.38 gm and surface area 19.2" cm"^(2) is at an initial temperature of 400K. It is allowed to cool inside an evacuated enclosure kept at constant temperature 300K. The rate of cooling is 0.04^(0)C per second. The specific heat of the body in J kg^(-1)K^(-1) is approximately |
| Answer» <html><body><p>2800<br/>2100<br/>1400<br/>1200</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39176. |
The blades of a wind mill sweep out a circle of area A. What is the K.E. of the air? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`K.E=(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)mv^(2)=(1)/(2)xx360xx(36xx(5)/(18))^(2)=18000Js^(-1)`</body></html> | |
| 39177. |
A platinum resistance thermometer reads 0^(0)C when its resistance is 80 Omega and 100^(0) C when its resistance is 90 Omega. Find the temperature at the platinum scale at which the resistance is 86 Omega |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>^(0)` <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> <br/>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(0)C `<br/>`<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a>^(0)` C <br/>`10^(0)` C </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39178. |
A rod of length 2m and mass 0.5kg is fixed at one end and allowed to hang vertically from a rigid support. Find the work done in raising the other end of the rod until it makes an angle of 60^(@) with the vertical. (g = 10 ms^(-2)) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`m= 0.5kg, l= <a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a>, theta = <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/word-1458917" style="font-weight:bold;" target="_blank" title="Click to know more about WORD">WORD</a> done `W= mg (l)/(2) (1- cos theta)` <br/> `=0.5 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> xx(2)/(2) (1- cos 60^(@))` <br/> `=5 xx (1 - (1)/(2))= 5 xx (1)/(2) = 2.5J`</body></html> | |
| 39179. |
Two particles which are initially at rest, move towards each other under the action of their internal attraction. if their speeds are v and 2v at any instant , then the speed of the centre of mass of the system will be |
| Answer» <html><body><p>2v<br/>1.5v<br/>zero<br/>v</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39180. |
A sphere of density d is allowed to fall in a liquid of density d/4. The acceleration of the body will be |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>//4`<br/>`3g//4`<br/>`g//2`<br/>`g`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39181. |
Why can't we make any conversaton on the surface of Moon ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Because <a href="https://interviewquestions.tuteehub.com/tag/sond-8331089" style="font-weight:bold;" target="_blank" title="Click to know more about SOND">SOND</a> waves are mechanical which compulasrily <a href="https://interviewquestions.tuteehub.com/tag/need-25476" style="font-weight:bold;" target="_blank" title="Click to know more about NEED">NEED</a> atmosphere. But Moon does not have any atmosphere and so we can not <a href="https://interviewquestions.tuteehub.com/tag/make-546668" style="font-weight:bold;" target="_blank" title="Click to know more about MAKE">MAKE</a> any conversatin on Moon.</body></html> | |
| 39182. |
Identify the increasing order of the angular velocities of the following 1. Earth rotating about its own axis 2. Hour's hand of a clock 3. Second's hand of a clock 4. Flywheel of radius 2 m making 300 rpm |
| Answer» <html><body><p> A, <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>, <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>, D<br/>B.C, D, A<br/>C, D,A,B<br/>D, A, B, C</p>Answer :A</body></html> | |
| 39183. |
A mass of 1 kg is suspended by means of a thread. The system is lifted up with an acceleration of 4.9 m//s^(2) |
| Answer» <html><body><p>`3:<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>`<br/>`1:<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`<br/>`1:3`<br/>`2:1`<br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> while lifting the mass, <br/> `T_(1) = <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> + a = g + (g)/(2) = (3g)/(2) [ because a = (g)/(2)]`</body></html> | |
| 39184. |
A ballistic pendulum is a device that was used to measure the speeds of bullets before the development of electronic tiring, devices. The device consists of a large block of wood of mass M, hanging from two long cords. A bullet of mass m is fired into the block. the bullet comes quickly into rest and the block + bullet rises to a vertical distance h before the pendulum comes momentarily to rest as the ends of the arc. ltbr. In the process. the linear momentum is conserved. In such a collision. some kinetic energy is dissipated as heat: so mechanical energy is not conserved. When there is a loss in mechanical energy, the collision is said to be inelastic. Further when two bodies coalesce, the collision is said to be perfectly inelastic. The energy dissipated as heat in the collision is |
| Answer» <html><body><p>`1/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>"<a href="https://interviewquestions.tuteehub.com/tag/mu-566056" style="font-weight:bold;" target="_blank" title="Click to know more about MU">MU</a>"^(2)-mgh`<br/>`1/2"mu"^(2)-(M+m)gh`<br/>`1/2(M+m)u^(2)-(M+m)gh`<br/>cannot be estimated</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> <a href="https://interviewquestions.tuteehub.com/tag/dissipated-7375209" style="font-weight:bold;" target="_blank" title="Click to know more about DISSIPATED">DISSIPATED</a> in collision <br/> `=` initial energy `-` <a href="https://interviewquestions.tuteehub.com/tag/final-461168" style="font-weight:bold;" target="_blank" title="Click to know more about FINAL">FINAL</a> energy<br/> `=1/2"mu"^(2)-(m+M)gh`</body></html> | |
| 39185. |
A ballistic pendulum is a device that was used to measure the speeds of bullets before the development of electronic tiring, devices. The device consists of a large block of wood of mass M, hanging from two long cords. A bullet of mass m is fired into the block. the bullet comes quickly into rest and the block + bullet rises to a vertical distance h before the pendulum comes momentarily to rest as the ends of the arc. ltbr. In the process. the linear momentum is conserved. In such a collision. some kinetic energy is dissipated as heat: so mechanical energy is not conserved. When there is a loss in mechanical energy, the collision is said to be inelastic. Further when two bodies coalesce, the collision is said to be perfectly inelastic. The collision of block-bullet system is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/perfectly-7309466" style="font-weight:bold;" target="_blank" title="Click to know more about PERFECTLY">PERFECTLY</a> elastic<br/>partially <a href="https://interviewquestions.tuteehub.com/tag/inelastic-7382420" style="font-weight:bold;" target="_blank" title="Click to know more about INELASTIC">INELASTIC</a><br/>partially elastic<br/>perfectly inelastic</p>Solution :As bullet and <a href="https://interviewquestions.tuteehub.com/tag/block-18865" style="font-weight:bold;" target="_blank" title="Click to know more about BLOCK">BLOCK</a> <a href="https://interviewquestions.tuteehub.com/tag/coalesce-421413" style="font-weight:bold;" target="_blank" title="Click to know more about COALESCE">COALESCE</a> after collision <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> collisio is perfectly inelastic.</body></html> | |
| 39186. |
A ballistic pendulum is a device that was used to measure the speeds of bullets before the development of electronic tiring, devices. The device consists of a large block of wood of mass M, hanging from two long cords. A bullet of mass m is fired into the block. the bullet comes quickly into rest and the block + bullet rises to a vertical distance h before the pendulum comes momentarily to rest as the ends of the arc. ltbr. In the process. the linear momentum is conserved. In such a collision. some kinetic energy is dissipated as heat: so mechanical energy is not conserved. When there is a loss in mechanical energy, the collision is said to be inelastic. Further when two bodies coalesce, the collision is said to be perfectly inelastic. What is the initial speed of the bullet in terms of heighth? |
| Answer» <html><body><p>`m/Msqrt(2gh)`<br/>`m/(M+m)sqrt(2gh)`<br/>`(M+m)/msqrt(2gh)`<br/>`sqrt((2m)/(M+m)<a href="https://interviewquestions.tuteehub.com/tag/gh-468237" style="font-weight:bold;" target="_blank" title="Click to know more about GH">GH</a>)`</p>Solution :Using conservation of <a href="https://interviewquestions.tuteehub.com/tag/mechanical-2780" style="font-weight:bold;" target="_blank" title="Click to know more about MECHANICAL">MECHANICAL</a> energy, <br/> `1/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(M+m)V^(2)=(m+M)gh` <br/> `V^(2)=2ghimplies[("mu")/((M+m))]^(2)=2h` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>^(2)=((M+m)/m)^(2)2gh` <br/> `impliesu=([M+m])/m sqrt(2gh)`</body></html> | |
| 39187. |
A ballistic pendulum is a device that was used to measure the speeds of bullets before the development of electronic tiring, devices. The device consists of a large block of wood of mass M, hanging from two long cords. A bullet of mass m is fired into the block. the bullet comes quickly into rest and the block + bullet rises to a vertical distance h before the pendulum comes momentarily to rest as the ends of the arc. ltbr. In the process. the linear momentum is conserved. In such a collision. some kinetic energy is dissipated as heat: so mechanical energy is not conserved. When there is a loss in mechanical energy, the collision is said to be inelastic. Further when two bodies coalesce, the collision is said to be perfectly inelastic. After collision what is the combined velocity of the bullet + block system? |
| Answer» <html><body><p>`m/Mu`<br/>`m/(M+m)u`<br/>`M/(M+m)u`<br/>`(M+m)/Mu`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a> conservation of linear <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> in horizontal direction just before and just after collision <br/> `mu=(m+M)Vimplies V("mu")/((M+m))`</body></html> | |
| 39188. |
A cylindrical drum open at the top contains 30 liters of water. It drains out through a small opening at the bottom. 10 litres of water comes out in first 10%, the next 10 litres in a further time t_(2) and the last 10 litres in a further time t_(3). Then |
| Answer» <html><body><p>`t_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=t_(2)=t_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`t_(1) <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> t_(2) gt t_(3)`<br/>`t_(1) lt t_(2) lt t_(3)`<br/>`t_(2) gt t_(1)= t_(1)`</p>Answer :C</body></html> | |
| 39189. |
Random error can also be called as ............. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/personal-590834" style="font-weight:bold;" target="_blank" title="Click to know more about PERSONAL">PERSONAL</a> error<br/>chance error <br/>gross error <br/><a href="https://interviewquestions.tuteehub.com/tag/unsystematic-7721366" style="font-weight:bold;" target="_blank" title="Click to know more about UNSYSTEMATIC">UNSYSTEMATIC</a> error </p>Solution :chance error</body></html> | |
| 39190. |
A lead shot of 1 mm diameter falls through a long colummn of glycerine. The variation of the velocity v with distance covered (s) is represented by |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C07_E06_031_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C07_E06_031_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C07_E06_031_O03.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C07_E06_031_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/initially-516121" style="font-weight:bold;" target="_blank" title="Click to know more about INITIALLY">INITIALLY</a>, the velocity increases due to the action of gravity. But the graph is not linear due to the upthrust <a href="https://interviewquestions.tuteehub.com/tag/exerted-7272976" style="font-weight:bold;" target="_blank" title="Click to know more about EXERTED">EXERTED</a> by <a href="https://interviewquestions.tuteehub.com/tag/glycerine-474196" style="font-weight:bold;" target="_blank" title="Click to know more about GLYCERINE">GLYCERINE</a>. Then due to <a href="https://interviewquestions.tuteehub.com/tag/viscosity-13767" style="font-weight:bold;" target="_blank" title="Click to know more about VISCOSITY">VISCOSITY</a> of glycerine, the lead shots attains a constant terminal velocity.</body></html> | |
| 39191. |
A hydrogen balloon released on the moon |
| Answer» <html><body><p>climbs up with an <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> of `<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> xx 9.8 ms^(-2)`<br/><a href="https://interviewquestions.tuteehub.com/tag/falls-983294" style="font-weight:bold;" target="_blank" title="Click to know more about FALLS">FALLS</a> down with an acceleration of `9.8 xx 6 ms^(-2)`<br/>falls with acceleration of `9.8 ms^(-2)`<br/>falls with an acceleration of `(9.8)/(6) ms^(-2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39192. |
A ring of radius R made of lead wire of breaking strength rho and density delta, is rotated about a stationary vertical axis passing through its centre and perpendicular to its plane. Calculate the number of rotation per second at which the ring ruptures |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2piR) <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((<a href="https://interviewquestions.tuteehub.com/tag/sigma-1207107" style="font-weight:bold;" target="_blank" title="Click to know more about SIGMA">SIGMA</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a>))`</body></html> | |
| 39193. |
10 gm of ice at - 10^@Cis mixed with 100 gm of water at 50^@Ccontained in a calorimeter weighing 50gm. (Specific heat of water = 1 "cal gm"^(-1).""^(@)C^(-1) Latent heat of ice = 80 cal/gm, specific heat of ice = 0.5 "cal/gm"^(0)Cand specific heat of copper = 0.09 "cal/gm/"^(@)C ). The final temperature reached by the mixtures is |
| Answer» <html><body><p>`25.5^@<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`<br/>`30.0^@C`<br/>`38.2^@C`<br/>`40.0^@C`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 39194. |
Find the moment of inertia of a uniform rod about an axis which is perpendicular to the rod and touches any one end of the rod. |
| Answer» <html><body><p></p>Solution :The concepts to form the integrand to find the moment of inertia are to be followed. Now, the <a href="https://interviewquestions.tuteehub.com/tag/origin-1139399" style="font-weight:bold;" target="_blank" title="Click to know more about ORIGIN">ORIGIN</a> is fixed to the <a href="https://interviewquestions.tuteehub.com/tag/left-1070879" style="font-weight:bold;" target="_blank" title="Click to know more about LEFT">LEFT</a> end of the rod and <a href="https://interviewquestions.tuteehub.com/tag/limits-16465" style="font-weight:bold;" target="_blank" title="Click to know more about LIMITS">LIMITS</a> are to be taken from 0 to `l`. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/SUR_PHY_XI_V02_G_MQP_02_E03_006_S01.png" width="80%"/> <br/> `I=(M)/(l)int_(0)^(l)x^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)dx=(M)/(l)[(x^(3))/(3)]_(0)^(l)=(M)/(l)[(l^(3))/(3)] I=(1)/(3)Ml^(2)`</body></html> | |
| 39195. |
A body falls freely from a height of 125m(g=10m//s^(2)) after 2 sec gravity ceases to act Find the time taken by it to reach the ground? |
| Answer» <html><body><p></p>Solution :Distance covered in 2s under <a href="https://interviewquestions.tuteehub.com/tag/gravity-18707" style="font-weight:bold;" target="_blank" title="Click to know more about GRAVITY">GRAVITY</a> <br/> `s_(1)=(1)/(2)g t^(2)=(1)/(2)(10)2^(2)=<a href="https://interviewquestions.tuteehub.com/tag/20m-293046" style="font-weight:bold;" target="_blank" title="Click to know more about 20M">20M</a>` <br/> velocity at the end of 2s <br/> `V=g t=(10)2=20m//s`. <br/> Now at this instant gravity <a href="https://interviewquestions.tuteehub.com/tag/ceases-911108" style="font-weight:bold;" target="_blank" title="Click to know more about CEASES">CEASES</a> to act <br/> implies velocity by here after <a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> constant. <br/> The remaining distance which is `125-20=105m` is covered by the body with constant velocity of `20m//s`. <br/> Time taken to cover `105m` with constant velocity is given by, <br/> `t_(1)=(S)/(V)impliest_(1)=(<a href="https://interviewquestions.tuteehub.com/tag/105-266496" style="font-weight:bold;" target="_blank" title="Click to know more about 105">105</a>)/(20)=5.25s` <br/> Hence total time taken to reach the ground <br/> `=2+5.25=7.25s`</body></html> | |
| 39196. |
A simple pendulum from earth is shifted to moon (g_(m) = g_(g)//6). Foreign minute on earth, the time on the moon as measured by the pendulum is (For same number of oscillations) |
| Answer» <html><body><p>24.5 <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a><br/>2.45 sec<br/>245 sec<br/>147 sec </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39197. |
During an adiabatic change, specific heat of a gas is |
| Answer» <html><body><p>Zero<br/>Positive<br/>negative<br/>infinity</p>Solution :No <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> , enter or <a href="https://interviewquestions.tuteehub.com/tag/escape-975157" style="font-weight:bold;" target="_blank" title="Click to know more about ESCAPE">ESCAPE</a> from the <a href="https://interviewquestions.tuteehub.com/tag/system-1237255" style="font-weight:bold;" target="_blank" title="Click to know more about SYSTEM">SYSTEM</a> , adiabatic change.</body></html> | |
| 39198. |
A particle of mass m is moving yz-plane with a uniform velocity v with its trajectory running parallel to +ve y-axis and intersecting z-axis at z=a. The change in its angular momentum about the origin as it bounces elastically from a wall at y= constant is |
| Answer» <html><body><p>`mvabari`<br/>`2mvabari`<br/>`-mvabari`<br/>`-2amvbari`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39199. |
In case of superposition of waves (atx=0), y_(1)=4sin(1026pit) and y_(2)=2sin(1014pit) (a) the frequency of resulting wave is 510Hz (b) the amplitude of resulting wave varies at frequency 3Hz (c ) the frequency of beats is 6 per second (d) the ratio of maximum to minimum intensity is 9 The correct statements are |
| Answer» <html><body><p>`a,d`<br/>`b,d`<br/>`a,c,d`<br/>all</p>Solution :Number of beats equal to `n_(1)-n_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` , frequency of <a href="https://interviewquestions.tuteehub.com/tag/resulting-1187445" style="font-weight:bold;" target="_blank" title="Click to know more about RESULTING">RESULTING</a> wave equal to `(n_(1)+n_(2))/(2)`. <a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> of maximum and minimum <a href="https://interviewquestions.tuteehub.com/tag/intensity-1047474" style="font-weight:bold;" target="_blank" title="Click to know more about INTENSITY">INTENSITY</a> is `((a_(1)+a_(2))/(a_(1)-a_(2)))^(2)`</body></html> | |
| 39200. |
For the equation FpropA^(a)v^(b)d^©, where F is the force, A is the area V is the velocity and d is the density, the values of a,b and c are, respectively. |
| Answer» <html><body><p>`1,2,1`<br/>`2,1,1`<br/>`1,1,2`<br/>`0,1,1`<br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(a) `[<a href="https://interviewquestions.tuteehub.com/tag/mlt-2163963" style="font-weight:bold;" target="_blank" title="Click to know more about MLT">MLT</a>^(-2)]=[L^(2a)]xx[L^(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)T^(-b)][M^(c) L^(-3c)]=[M^(c)L^(2a+b-3c)T^(-b)]` <br/> Comparing powers of `M,L` and `T` on both sides, we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> <br/> `c=1, 2a+b-3c=1, -b=-2` or `b=2` <br/> Also `2a+2-3(1)=1implies2a=2` or `a=1` <br/> `:.` This 1,2,1</body></html> | |