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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 39201. |
Explain how Newton verified his law of gravitation. |
| Answer» <html><body><p></p>Solution :The gravitational force <a href="https://interviewquestions.tuteehub.com/tag/experienced-13456" style="font-weight:bold;" target="_blank" title="Click to know more about EXPERIENCED">EXPERIENCED</a> by the apple <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to Earth.<br/>`F=-(GM_(E)M_(A))/(R^2)` <br/>`M_(A)` - Mass of the apple, `M_(E)` - Mass of the Earth and R - Radius of the Earth.<br/>Equating the above equation with Newton's <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a> law, we get<br/>`M_(A)a_(A)=-(GM_(E)M_(A))/(R^2)` <br/>Simplifying the above equation we get,<br/>`a_(A)=-(GM_(E))/(R^2)` <br/>`a_(A)` is the acceleration of apple that it equal to 'g'.<br/>Similarly the force experienced by Moon due to Earth is given by<br/>`F=-(GM_(E)Mm)/(R_(m)^(2))` <br/>`R_(m)` - distance of the Moon from the Earth,<br/>`M_(m)` - Mass of the Moon.<br/>The acceleration experienced by the Moon is given by,<br/>`a_(m)=-(GM_(E))/(R_(m)^(2))` <br/>The ratio between the apple's acceleration to Moon's acceleration is given by<br/>`(a_A)/(a_m)=(R_(m)^(2))/(R^2)` <br/>From the Hipparchrus <a href="https://interviewquestions.tuteehub.com/tag/measurement-19276" style="font-weight:bold;" target="_blank" title="Click to know more about MEASUREMENT">MEASUREMENT</a>, the distance to the Moon is 60 times that of Earth radius. `R_(m)=60R` <br/>`(a_(A))/(a_(m))=((60R)^(2))/(R^2)=3600` <br/>The apples's acceleration is 3600 times the acceleration of the Moon.<br/> The same result was obtained by Newton <a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a> his gravitational formula.</body></html> | |
| 39202. |
A bullet of mass 10 g and speed 500m/s is fired into a door and gets embedded exactly at the centre of the door. The door is 1.0 m wide and weighs 12 kg. It is hinged at one end and rotates about a vertical axis practically without friction. Find the angular speed of the door just after the bullet embeds into it. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The moment of inertia of the door about the <a href="https://interviewquestions.tuteehub.com/tag/vertical-726181" style="font-weight:bold;" target="_blank" title="Click to know more about VERTICAL">VERTICAL</a> axis at <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> end is `<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(2)//<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>` <br/>0.625 rad/s</body></html> | |
| 39203. |
A uniform rod of length 2m and mass 5kg is lying on a horizontal surface. The work done in raising one end of the rod with the other end in contact with the surface until the rod makes an angle 30^(@) with the horizontal is, (g= 10 ms^(-2)) |
| Answer» <html><body><p>25J<br/>50J<br/>`<a href="https://interviewquestions.tuteehub.com/tag/25-296426" style="font-weight:bold;" target="_blank" title="Click to know more about 25">25</a> sqrt3J`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> sqrt3J`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39204. |
There is a thin rod of uniform cross-section of mass M and length L. If this rodis is bent at 90^(@) from the mid-point, then the moment of inertia about the axis passing through mid-point and perpendicular to the plane which includes both parts of rod is ......... |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(2))/(<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a>)`<br/>`(ML^(2))/(12)`<br/>`(ML^(2))/(6)`<br/>`(sqrt(2)ML^(2))/(24)` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P1_C07_E05_060_S01.png" width="80%"/> <br/> After the <a href="https://interviewquestions.tuteehub.com/tag/rod-1190628" style="font-weight:bold;" target="_blank" title="Click to know more about ROD">ROD</a> bent at right angle <br/> mass of its energy part = `(M)/(2)` <br/> Length of every part = `(<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)/(2)` <br/> Now total moment of inertia, <br/> I = sum of moment of inertia of both the part <br/> `therefore I=(1)/(3)((M)/(2))((L)/(2))^(2)+(1)/(3)((M)/(2))((L)/(2))^(2)` <br/> `=2((1)/(3)((M)/(2))((L)/(2))^(2))` <br/> `therefore I=(ML^(2))/(12)`</body></html> | |
| 39205. |
Water is flowing through a horizontal tube of length 0.25 m and radius4xx 10 ^(-4) m under a constant pressure head of 0.2 m of water, at the rate of 5 xx 10 ^(-6) m^(3) per minutre . Calculate the coefficient of visosity of water. Density of water = 1000 kg m^(-3) |
| Answer» <html><body><p></p>Solution :` "" l = 0.25 m, r- 4 xx 10 ^(-4) m ` <br/> ` ""P= h rho g =0.2 m " ofwater"= 0.2 xx 10 ^(3)xx 9.<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> Pa` <br/>Volume ` V = 5 xx 10 ^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)m^(3)` <br/> ` "" t= ` one minute = <a href="https://interviewquestions.tuteehub.com/tag/60s-330048" style="font-weight:bold;" target="_blank" title="Click to know more about 60S">60S</a><br/>` eta = ? ` <br/>` <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> = ( V)/(t)= (pi P r^(4))/( 8 eta l) ` <br/>` eta = ( pi h rho g r^(4) t)/( gl V) ` <br/> `= (3.14 xx 0.2 xx 10 ^(-3)xx 9.8 xx ( 4 xx 10 ^(-4) ) ^(4) xx 60 )/( 8 xx 0.25 xx 5 xx 10 ^(-6)) ` <br/> `= 0 .000945 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> s m^(-2)`</body></html> | |
| 39206. |
Water is flowing in streamline motion throw a tube with its axis horizontal consider two point A & B in the tube at the same horizontal levels |
| Answer» <html><body><p>the pressure at A & <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are equal for any shape of the tube<br/>the pressure are <a href="https://interviewquestions.tuteehub.com/tag/never-570518" style="font-weight:bold;" target="_blank" title="Click to know more about NEVER">NEVER</a> equal<br/>the pressure are equal of the tube has a <a href="https://interviewquestions.tuteehub.com/tag/uniform-1437485" style="font-weight:bold;" target="_blank" title="Click to know more about UNIFORM">UNIFORM</a> cross section<br/>the pressure are equal even in the tube has a non-uniform cross section</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 39207. |
In one dimensional motion, instantaneous speed V satisfies 0 le V lt V_(0). |
| Answer» <html><body><p>The displacement in <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> T <a href="https://interviewquestions.tuteehub.com/tag/must-2185568" style="font-weight:bold;" target="_blank" title="Click to know more about MUST">MUST</a> <a href="https://interviewquestions.tuteehub.com/tag/always-373607" style="font-weight:bold;" target="_blank" title="Click to know more about ALWAYS">ALWAYS</a> take nonnegative values.<br/>The displacement x in time T satisfies `-V_(0) T lt x lt V_(0) T.`<br/>The acceleration is always an nonnegative number<br/>The <a href="https://interviewquestions.tuteehub.com/tag/motion-1104108" style="font-weight:bold;" target="_blank" title="Click to know more about MOTION">MOTION</a> has no turning points.</p>Answer :B</body></html> | |
| 39208. |
The magnitude of distance is always |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/positive-1159908" style="font-weight:bold;" target="_blank" title="Click to know more about POSITIVE">POSITIVE</a><br/>negative<br/>either positive ornegative<br/>zero</p></body></html> | |
| 39209. |
In case of a forced vibration, the resonance wave becomes very sharp when the : |
| Answer» <html><body><p>applied periodic force is <a href="https://interviewquestions.tuteehub.com/tag/small-1212368" style="font-weight:bold;" target="_blank" title="Click to know more about SMALL">SMALL</a> quality factor is small <br/>quality factor is small<br/>damping force is small <br/><a href="https://interviewquestions.tuteehub.com/tag/restoring-1187260" style="font-weight:bold;" target="_blank" title="Click to know more about RESTORING">RESTORING</a> force is small </p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/less-1071906" style="font-weight:bold;" target="_blank" title="Click to know more about LESS">LESS</a> damping force gives a taller and narrow resonance peak. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PRE_GRG_PHY_XI_V02_C10_E02_011_S01.png" width="80%"/></body></html> | |
| 39210. |
A bodyof mass 1 kg makes an elastic collision with another body at rest and continues to move in the original direction after collision with a velocity equal to 1/5th of its original velocity. Find the mass of the second body. |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a>`<br/>`(3)/(2) kg`<br/>`(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)/(2) kg`<br/>`(2)/(5) kg`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39211. |
A Ship .A. steams down north at a speed of 8 kmph. And ship B due west at a speed of 6 kmph. The velocity of A w.r.t. B is. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> <a href="https://interviewquestions.tuteehub.com/tag/kmph-533998" style="font-weight:bold;" target="_blank" title="Click to know more about KMPH">KMPH</a>, `Tan^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)((<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)/(3))<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>` of E<br/>10 kmph, `tan^(-1)((4)/(3))E` of N<br/>10 kmph NE<br/>2 kmph, `Tan^(-1)((4)/(3))N` of E</p>Answer :A</body></html> | |
| 39212. |
The path length can be equal to or ........... than the displacement. |
| Answer» <html><body><p>less <br/>`+<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>`<br/>`-1`<br/>greater </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/knowledge-25694" style="font-weight:bold;" target="_blank" title="Click to know more about KNOWLEDGE">KNOWLEDGE</a> based <a href="https://interviewquestions.tuteehub.com/tag/question-25051" style="font-weight:bold;" target="_blank" title="Click to know more about QUESTION">QUESTION</a>.</body></html> | |
| 39213. |
Given noticeable points, about the amplitude of resultant waves of two harmonic progressive waves on stretached string. |
| Answer» <html><body><p></p>Solution :The amplitude of <a href="https://interviewquestions.tuteehub.com/tag/resultant-1187362" style="font-weight:bold;" target="_blank" title="Click to know more about RESULTANT">RESULTANT</a> wave is a function of phase difference `phi` between <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> element waves. <br/> `A (phi) =2 a cos "" (phi)/(2)` <br/> When two waves have same phase, then `phi =0 ` <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>,` y (x,t) =2a sin (<a href="https://interviewquestions.tuteehub.com/tag/kx-1064991" style="font-weight:bold;" target="_blank" title="Click to know more about KX">KX</a> - omega t )` <br/> Relultant amplitude is `A = 2a. `It is maximum amplitude.<br/> If `phi =<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>` the two waves are completely out of phase, the amplitude of the resultant wave reduces to zero. <br/> `therefore (x ,t)= 0 [because A (phi) = 2 cos "" (phi)/(2) = 2 a cos "" (pi)/(2) =0]`</body></html> | |
| 39214. |
A uniform chain of length 'L' and mass 'm' is on a smooth horizontal table, with (1)/(n) th part of its length hanging from the edge of the table. Find the kinetic energy of the chain as it completely slips off the table |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :With respect to the top of the table, the initial potential energy of the chain <br/> `U_(1)`= PF of the chain lying on the table + PE of the hanging part of the chain <br/> `= L (1- (1)/(n)) mg (0)(m)/(n)<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> (-(L)/(2n))= - (<a href="https://interviewquestions.tuteehub.com/tag/mgl-2176708" style="font-weight:bold;" target="_blank" title="Click to know more about MGL">MGL</a>)/(2n^(2))` <br/> P.E of the chain, when it just slips off the table. <br/> `U_(2)= mg ((-L)/(2)) = - (mgL)/(2)` <br/> From <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of conservation of energy <br/> `Delta K= - Delta <a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> K_(r)- K_(i) = - (U_(f)- U_(i))` <br/> `because K_(i)= 0, K_(f)= - [-(mgL)/(2)- (-(mgL)/(2n^(2)))]` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_B_C06_SLV_023_S01.png" width="80%"/> <br/> If .V. is the velocity of the chain, then, `(1)/(2) mv^(2)= (mgL)/(2) [1-(1)/(n^(2))]` <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_NEO_CAO_PHY_XI_V01_B_C06_SLV_023_S02.png" width="80%"/></body></html> | |
| 39215. |
The acceleration of a car is 10 mile per hour per second. The same is (ft)//(s^(2)) is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.467(ft)/(s^(2))`<br/>`14.67(ft)/(s^(2))`<br/>`40ft//s^(2)`<br/>none of these<br/></p>Solution :(a) `n_(1)u_(1)=n_(2)u_(2)` <br/> or `(10"mile")/("hour <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a>")=n_(2)(ft)/(s^(2))` <br/> or `(10xx1760xx3ft)/(60xx60s^(2))=n_(2)(ft)/(s^(2))` <br/>`:. n_(2)=1.467ft//s^(2)`</body></html> | |
| 39216. |
If two objects A and B are moving along a straight line in the opposite direction with the velocities V_(A)andV_(B) respectively, then relative velocity is |
| Answer» <html><body><p>`V_(A)+V_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)`<br/>`V_(A)-V_(B)`<br/>`V_(A)V_(B)`<br/>`V_(A)//V_(B)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A::B</body></html> | |
| 39217. |
A spacecraft is in a circular orbitof radius 3R around the moon as shown in figure-6.109. At point A, the spacraft fires a probe which is supposed to arrive at the surface of the moon at point B. Datermine the necessary velocity v_(r) of the probe relative to the spacecraft just fter ejection. Also calculate the angular displacement theta of the spacecraft when the probe arrives at point B. Assume velocity of spacecraft remains unchanged due to ejection of probe. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`v_(f) = 284 m//s; theta = <a href="https://interviewquestions.tuteehub.com/tag/98-342802" style="font-weight:bold;" target="_blank" title="Click to know more about 98">98</a>^(@)`</body></html> | |
| 39218. |
If excess pressure is balanced by a column of oil (with specific gravity 0.8) 4 mm high, where R = 2.0 cm, Find the surface tension of the soap bubble. |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :The excess of pressure inside the <a href="https://interviewquestions.tuteehub.com/tag/soap-11667" style="font-weight:bold;" target="_blank" title="Click to know more about SOAP">SOAP</a> bubble is <br/> `"" DeltaP = P_(2) - P_(1) = (4T)/R` <br/> But `"" DeltaP = P_1 - P_1 = rho <a href="https://interviewquestions.tuteehub.com/tag/gh-468237" style="font-weight:bold;" target="_blank" title="Click to know more about GH">GH</a> implies rho gh = (4T)/R` <br/> `implies "surface tension" , T = (rho gh R)/4 = ((800)(9.8)(4 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-3))(2 xx 10^(-2)))/(4)` <br/> `T = 15.68 xx 10^(-2) Nm^(-1)`</body></html> | |
| 39219. |
For a given material, the rigidity modulus is ((1)/(3))^(rd) of Young's modulus. Its Poisson's ratio is |
| Answer» <html><body><p>0<br/>0.25<br/>0.<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a><br/>0.5</p>Solution :The relationship of Poission.s ratio, <a href="https://interviewquestions.tuteehub.com/tag/rigidity-623827" style="font-weight:bold;" target="_blank" title="Click to know more about RIGIDITY">RIGIDITY</a> and Young.s modulus is <br/> `eta = Y/(2(1 - sigma))sigma` - Poisson.s ratio <br/> Here, `"" eta1/3 y implies 3 eta = y` <br/> Substituting the value, we <a href="https://interviewquestions.tuteehub.com/tag/get-11812" style="font-weight:bold;" target="_blank" title="Click to know more about GET">GET</a> `sigma = 0.5`</body></html> | |
| 39220. |
The rate of leak from a hole in a tank is ………………. . |
| Answer» <html><body><p>independent of its height from the bottom <br/>more if <a href="https://interviewquestions.tuteehub.com/tag/situated-7263142" style="font-weight:bold;" target="_blank" title="Click to know more about SITUATED">SITUATED</a> <a href="https://interviewquestions.tuteehub.com/tag/near-1112277" style="font-weight:bold;" target="_blank" title="Click to know more about NEAR">NEAR</a> the bottom <br/>more if situated near its <a href="https://interviewquestions.tuteehub.com/tag/top-1422115" style="font-weight:bold;" target="_blank" title="Click to know more about TOP">TOP</a> <br/>more at midway between top and bottom </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39221. |
Calculate the efficiency of an engine whose working substance absorbs 3000 J of heat from the source and rejects 2000 J of heat to the sink. |
| Answer» <html><body><p></p>Solution :Heat <a href="https://interviewquestions.tuteehub.com/tag/absorbed-846166" style="font-weight:bold;" target="_blank" title="Click to know more about ABSORBED">ABSORBED</a> from the <a href="https://interviewquestions.tuteehub.com/tag/soure-3050929" style="font-weight:bold;" target="_blank" title="Click to know more about SOURE">SOURE</a> `= Q_(1) = 3000 J` <br/> Heat rejected to the <a href="https://interviewquestions.tuteehub.com/tag/sink-1210432" style="font-weight:bold;" target="_blank" title="Click to know more about SINK">SINK</a>` = Q_(2) = 2000 J` <br/> Efficiency `= <a href="https://interviewquestions.tuteehub.com/tag/eta-446786" style="font-weight:bold;" target="_blank" title="Click to know more about ETA">ETA</a> ( Q_(1) - Q_(2))/( Q_(2))= ( 3000 - 2000)/( 2000) = 0.5 = <a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a>%`</body></html> | |
| 39222. |
What is the maximum magnitude of change in velocity of a motor cycle moving with uniform speed V_(0) in a circular path of length l= (piR)/(3) and radius R |
| Answer» <html><body><p>`V_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)`<br/>`2V_(0)`<br/>`3V_(0)`<br/>`(V_(0))/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`</p>Answer :A</body></html> | |
| 39223. |
Explain Right hand rule to find the direction of Torque. |
| Answer» <html><body><p></p>Solution :If fingers of right hand are kept along the <a href="https://interviewquestions.tuteehub.com/tag/position-1159826" style="font-weight:bold;" target="_blank" title="Click to know more about POSITION">POSITION</a> <a href="https://interviewquestions.tuteehub.com/tag/vector-20923" style="font-weight:bold;" target="_blank" title="Click to know more about VECTOR">VECTOR</a> with palm facing the direction of the force and when the fingers are <a href="https://interviewquestions.tuteehub.com/tag/curled-7669473" style="font-weight:bold;" target="_blank" title="Click to know more about CURLED">CURLED</a> the thumb <a href="https://interviewquestions.tuteehub.com/tag/points-1157347" style="font-weight:bold;" target="_blank" title="Click to know more about POINTS">POINTS</a> to the direction of the <a href="https://interviewquestions.tuteehub.com/tag/torque-1422441" style="font-weight:bold;" target="_blank" title="Click to know more about TORQUE">TORQUE</a>.</body></html> | |
| 39224. |
Answer with reason: In an elastic collision of two billiard balls, is the total kinetic energy conserved during the short time ofcollision of the balls (i.e., when they are in contact )? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The collision produces a <a href="https://interviewquestions.tuteehub.com/tag/slight-2273584" style="font-weight:bold;" target="_blank" title="Click to know more about SLIGHT">SLIGHT</a> deformation of both the balls. A partof the KE is used for that deformation , so the total KE is not <a href="https://interviewquestions.tuteehub.com/tag/conserved-2539138" style="font-weight:bold;" target="_blank" title="Click to know more about CONSERVED">CONSERVED</a> during the short time of collision. However,due to the elastic stress <a href="https://interviewquestions.tuteehub.com/tag/developed-431631" style="font-weight:bold;" target="_blank" title="Click to know more about DEVELOPED">DEVELOPED</a> in the perfectly elastic balls, the kinetic <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> is regained after the collision.</body></html> | |
| 39225. |
A stone is thrown upward from a moving train. A man can jump on moon six times as high as on earth. Why? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`Hpropto1/g` .The acceleration due to gravity at the <a href="https://interviewquestions.tuteehub.com/tag/surface-1235573" style="font-weight:bold;" target="_blank" title="Click to know more about SURFACE">SURFACE</a> of the <a href="https://interviewquestions.tuteehub.com/tag/moon-563673" style="font-weight:bold;" target="_blank" title="Click to know more about MOON">MOON</a> is nearly `<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>^(th)/6` of that at the earth’s surface</body></html> | |
| 39226. |
A man isswimming against current such that his position with respect to the river bank remains unaltered.Is the man doing any work ? |
| Answer» <html><body><p></p>Solution :The relative <a href="https://interviewquestions.tuteehub.com/tag/displacement-956081" style="font-weight:bold;" target="_blank" title="Click to know more about DISPLACEMENT">DISPLACEMENT</a> of the man with respect to the river <a href="https://interviewquestions.tuteehub.com/tag/bank-13461" style="font-weight:bold;" target="_blank" title="Click to know more about BANK">BANK</a> is zero . So, no <a href="https://interviewquestions.tuteehub.com/tag/work-20377" style="font-weight:bold;" target="_blank" title="Click to know more about WORK">WORK</a> is done by the man. The resistive force of river water just <a href="https://interviewquestions.tuteehub.com/tag/balances-891822" style="font-weight:bold;" target="_blank" title="Click to know more about BALANCES">BALANCES</a> the force applied by the man . So, this case is similar to a force applied against static <a href="https://interviewquestions.tuteehub.com/tag/friction-21545" style="font-weight:bold;" target="_blank" title="Click to know more about FRICTION">FRICTION</a>.</body></html> | |
| 39227. |
The escape velocity of a body from the surface of the earth is nearly |
| Answer» <html><body><p>`7.98 <a href="https://interviewquestions.tuteehub.com/tag/kms-1064571" style="font-weight:bold;" target="_blank" title="Click to know more about KMS">KMS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`8.92 kms^(-1)`<br/>`1048 kms^(-1)`<br/>`11.2 kms^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39228. |
A physical quantity P is related to four observables a,b,c and d as follows: P = a^(3)b^(2)/(sqrtcd) The percentage errors of measurement in a,b, c and d are 1%, 3% , 4% and 2% respectively. What is the percentage error in the quantity P ? If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/13-271882" style="font-weight:bold;" target="_blank" title="Click to know more about 13">13</a>%, 3.8</body></html> | |
| 39229. |
Resultant of two vector of equal magnitude A is |
| Answer» <html><body><p>`sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)Aat 60^(@)`<br/>`sqrt(2)Aat 90^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2aat-1836692" style="font-weight:bold;" target="_blank" title="Click to know more about 2AAT">2AAT</a> <a href="https://interviewquestions.tuteehub.com/tag/120-270396" style="font-weight:bold;" target="_blank" title="Click to know more about 120">120</a>^(@)`<br/>`Aat 180^(@)`</p>Solution :(a,b) <a href="https://interviewquestions.tuteehub.com/tag/resultant-1187362" style="font-weight:bold;" target="_blank" title="Click to know more about RESULTANT">RESULTANT</a> of two vector `A_(R)=2acos(theta)/(2)`</body></html> | |
| 39230. |
A body falls freely from a height 'h' its average velocity when it reaches earth is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(gh)`<br/>`sqrt((gh)/(2))`<br/>`sqrt(2gh)`<br/>`gsqrt(<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39231. |
An ideal refrigerator has a freezer at a temperature of -13∘C. The coefficient of performance of the engine is 5. The temperature ofthe air (to which heat is rejected) will be |
| Answer» <html><body><p>`325^@`<br/>325K<br/>`<a href="https://interviewquestions.tuteehub.com/tag/39-310302" style="font-weight:bold;" target="_blank" title="Click to know more about 39">39</a>^@C`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/320-307501" style="font-weight:bold;" target="_blank" title="Click to know more about 320">320</a>^@C`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 39232. |
A bullet hits and gets embedded in a solid block resting on africtionless table. What Is conserved? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> and K.E<br/>momentum alone<br/>K.E alone<br/>neither momentum nor K.E</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39233. |
Two identical blocks A and B each of mass M are connected to each other through a light string. The system is placed on a smooth horizontal floor. When a constant force F is applied horizontally on the block A, find the tension in the string. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`F//2`</body></html> | |
| 39234. |
In the given (V-T) diagram, what is the relation between pressures P_(1) and P_(2) ? |
| Answer» <html><body><p>`P_(2) gt P_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>Cannot be <a href="https://interviewquestions.tuteehub.com/tag/predicted-7271267" style="font-weight:bold;" target="_blank" title="Click to know more about PREDICTED">PREDICTED</a><br/>`P_(2) = P_(1)`<br/>`P_(2) gt P_(1)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :According to ideal gas equation <br/> PV = nRT or `V = (nRT)/(P)` <br/> For an isobaric process, P = constant and `V prop T` <br/> Therefore, V - T graph is a straight line passing through origin. <a href="https://interviewquestions.tuteehub.com/tag/slope-15649" style="font-weight:bold;" target="_blank" title="Click to know more about SLOPE">SLOPE</a> of this line is inversely proportional to P. In the given figure, <br/> `("Slope")_(2) gt ("Slope")_(1) :. P_(2) lt P_(1)` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/MTG_NEET_GID_PHY_XI_C08_E03_008_S01.png" width="80%"/></body></html> | |
| 39235. |
The period of oscillation of a simple pendulum is T =2pisqrt(L/g). Measuted value of L is 20.0 cm known to 1mm accuracy and time for 100 oscillations of the pendulum is found to be 90s using a wrist watch of 1 s resolution. What is the accuracy in the determination of g ? |
| Answer» <html><body><p></p>Solution :`g= <a href="https://interviewquestions.tuteehub.com/tag/4pi-1882352" style="font-weight:bold;" target="_blank" title="Click to know more about 4PI">4PI</a>^(2) L//T^(2)` Here, `T= (T)/(n) and Delta T = (Delta t)/( n)`. <br/> <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, `(Delta T)/( T) = (Delta t)/( t)`. <br/> The errors in both L and t are the least count errors. <br/> Therefore, `(Deltag //g) = (Delta L//L) + 2(Delta T//T)` <br/> `= (0.1)/( 20.0) +2 ((1)/(90) ) = 0.027` <br/> Thus, the percentage <a href="https://interviewquestions.tuteehub.com/tag/error-25548" style="font-weight:bold;" target="_blank" title="Click to know more about ERROR">ERROR</a> in g is <br/> `<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a> (Delta g//g) = 100(Delta L//L) + 2 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 100 (Delta T //T) = 3`</body></html> | |
| 39236. |
A vector is not changed if |
| Answer» <html><body><p>it is rotated through an arbitrary angle <br/>it is <a href="https://interviewquestions.tuteehub.com/tag/multiplied-7280180" style="font-weight:bold;" target="_blank" title="Click to know more about MULTIPLIED">MULTIPLIED</a> by an arbitrary scalar <br/>it is cross multiplied by a unit vector <br/>it is <a href="https://interviewquestions.tuteehub.com/tag/slid-3811258" style="font-weight:bold;" target="_blank" title="Click to know more about SLID">SLID</a> parallel to itself. </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 39237. |
In experiment to measure density of a subtance mass m=(3+-0.12) kg and volume V=(10+-1)m^(3) recorded. Find relative error in measurement of density (rho=(m)/(V)) |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`rho=(m)/(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)` <br/> Relative <a href="https://interviewquestions.tuteehub.com/tag/error-25548" style="font-weight:bold;" target="_blank" title="Click to know more about ERROR">ERROR</a> in measured density `=(Deltarho)/(rho)` <br/> `=(<a href="https://interviewquestions.tuteehub.com/tag/deltam-2570666" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAM">DELTAM</a>)/(m)+(DeltaV)/(V)=(0.12)/(3)+(1)/(10)=0.04+0.1=0.<a href="https://interviewquestions.tuteehub.com/tag/14-272882" style="font-weight:bold;" target="_blank" title="Click to know more about 14">14</a>` <br/> Percentage error =Relative error `xx100` <br/> `=0.014xx100%=14%`</body></html> | |
| 39238. |
We know that the density of a cube can be measured by measuring its mass and length of its side. If the maximum errors in the measurement of mass and length are 3% and 2% respectively, what is the maximum error in the measurement of the density of the cube? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/9-340408" style="font-weight:bold;" target="_blank" title="Click to know more about 9">9</a>%`</body></html> | |
| 39239. |
Viscous force acting between two layers of liquid having area A and velocity gradient (Deltav)/(Deltaz) is given by F = etaA(Deltav)/(Deltaz) . Find dimension of eta. |
| Answer» <html><body><p>`M^(1)L^(-2)T^(-2)`<br/>`M^(0)L^(0)T^(0)`<br/>`M^(1)L^(-1)T^(-1)`<br/>`M^(1)L^(2)T^(-2)`<br/></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>= <a href="https://interviewquestions.tuteehub.com/tag/etaa-3622529" style="font-weight:bold;" target="_blank" title="Click to know more about ETAA">ETAA</a>(Deltav)/(<a href="https://interviewquestions.tuteehub.com/tag/deltaz-2053564" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAZ">DELTAZ</a>) "" DeltaZ`= distance <br/> `:. <a href="https://interviewquestions.tuteehub.com/tag/eta-446786" style="font-weight:bold;" target="_blank" title="Click to know more about ETA">ETA</a>=(FDeltav)/(ADeltaz) "" DeltaV`= velocity <br/> `:.[eta]=([F][Deltaz])/([A][Deltav])` <br/> `=((M^(1)L^(1)T^(-2))(M^(0)L^(1)T^(0)))/((M^(0)L^(2)T^(0))(M^(0)L^(1)T^(-1)))` <br/> `=M^(1)L^(-1)T^(-1)`</body></html> | |
| 39240. |
An artificial satellite of mass 500 kg revolve around the earth, its angular momentum 4xx10^(7)Js. What will its Ariel velocity? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/2xx10-1840192" style="font-weight:bold;" target="_blank" title="Click to know more about 2XX10">2XX10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)m^(2)s^(-1)`<br/>`2xx10^(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)m^(2)s^(-1)`<br/>`0`<br/>`4xx10^(4)m^(2)s^(-1)`</p>Solution :`(<a href="https://interviewquestions.tuteehub.com/tag/da-943215" style="font-weight:bold;" target="_blank" title="Click to know more about DA">DA</a>)/(dt)=(L)/(2m)=(4xx10^(7))/(2xx500)=4xx10^(4)m^(2)s^(-1)`</body></html> | |
| 39241. |
A force is applied on a body of mass 0.9kg that is at rest. The force is applied for a duration of 5s and as a result the body covers distance of 250m . Find the magnitude of the force. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/18n-1799880" style="font-weight:bold;" target="_blank" title="Click to know more about 18N">18N</a></body></html> | |
| 39242. |
In a circus the diameter of the globe of depth is 20 m calculate the minimum heightmust a cyclist start in order to go round the globesuccessfully |
| Answer» <html><body><p></p>Solution :Whenthe cyclistrollsdownthe inciline <br/>`mgh = (1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a>^(2)` <br/> `:.`velocitygained`v=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2gh)` <br/>forloopingthe loopthe minimumvelocityat <a href="https://interviewquestions.tuteehub.com/tag/thelowest-3199470" style="font-weight:bold;" target="_blank" title="Click to know more about THELOWEST">THELOWEST</a> point`=sqrt(5gr)` <br/> `h= (5r)/(2 )` <br/> `=(5)/(2) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> (10) =25 m` <br/>Heightof thecyclist `=25` m</body></html> | |
| 39243. |
A particle of mass m strikes a smooth floor with speed u at angle of incidence theta with the normal. The coefficient of resultant is e. Find the magnitude and direction of velocity with which the particle rebounds. Also, find the impulse and loss in K.E. |
| Answer» <html><body><p></p>Solution :Before the collision: <br/> After the collision: <br/> Since there is no force <a href="https://interviewquestions.tuteehub.com/tag/along-1974109" style="font-weight:bold;" target="_blank" title="Click to know more about ALONG">ALONG</a> the surface , hence the velocity component remains same. <br/> `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> sin alpha = u sin theta`(i) <br/> Due to the normal force between the particle and the floor , the velocity component becomes `e <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a>` in opposite direction <br/> `v cos alpha = e u cos theta`(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) <br/> `v = sqrt((v sin alpha)^(2) + (v cos alpha)^(2)) = u sqrt(sin^(2) theta + e^(2) cos^(2) theta)` <br/> `tan alpha = ( v sin alpha)/(v cos alpha) = (1)/(e) tan theta` <br/> If the collision is elastic , `e = 1 , v = u , alpha = theta` <br/> `J_(x) = 0` <br/> `J_(y) = m(v cos alpha + u cos theta)` <br/> `= m ( e u cos theta + u cos theta) = mu cos theta ( 1 + e)` <br/> `J = mu cos theta ( 1 + e)` <br/> `Delta <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> = (1)/(2) mu^(2) - (1)/(2) m u^(2)= (1)/(2) mu^(2) cos^(2) theta ( 1 - e^(2))` <br/> `Delta` K: loss in `K.E.` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CPS_V01_C10_S01_069_S01.png" width="80%"/><br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CPS_V01_C10_S01_069_S02.png" width="80%"/></body></html> | |
| 39244. |
A cylindrical block of length 0.4 m and area of cross-section 0.04m^(2) is placed coaxially on a thin metal disc of mass 0.4kg and of the same cross section. The upper face of the cylinder is maintained at constant temperature of 400 K and the initial temperature of the disk is 300K. If the thermal conductivity of the material of the cylinder is 1" wm"^(-1)K^(-1) and the specific heat of the material of the disk is 600 j\kg -K, how long will it take for the temperature of the disc to increase to 350 K. (Assume for purpose of calculation the thermal conductivity of the disc to be very high and the system to be thermally insulated except for the upper face of the cylinder) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/190-280910" style="font-weight:bold;" target="_blank" title="Click to know more about 190">190</a> s<br/>166 s<br/>482 s<br/>300 s</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 39245. |
An ideal gas is trapped between a mercury columnand the closed lower end of a narrow vertical tube of uniform bore. The upper end of the tube is open to the atmosphere. (Atmospheric pressure is 76 cm of mercury). The length of the mercury and the trapped gas columns are 20 cm and 43 cm, respectively. What will be the length of the gas column when the tube is tilted slowly in a vertical plane through an angle of 60^(@). Assume the temperature to be constant. |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :Boyle.s law <a href="https://interviewquestions.tuteehub.com/tag/holds-1028346" style="font-weight:bold;" target="_blank" title="Click to know more about HOLDS">HOLDS</a> <a href="https://interviewquestions.tuteehub.com/tag/good-1009017" style="font-weight:bold;" target="_blank" title="Click to know more about GOOD">GOOD</a> because the <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> is constant. <br/> So, `P_(1)V_(1)=P_(2)V_(2)" or "P_(1)l_(1)=P_(2)l_(2)` , since the bore is uniform <br/> `P_(1)=76+20=96 cm` of Hg , <br/> `l_(1)=43 cm, P_(2)=76+h=76+20cos60^(@)=76+10=86cm` of Hg <br/> `l_(2)=?` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> 96 times 43=86l_(2)` <br/> `therefore l_(2)=48cm` of Hg</body></html> | |
| 39246. |
Read the following two statements below carefully and state, with reasons, if is true or false. (a) The Young's modulus of rubber is greater than of steel , (b) The stretching of a coil is determined by shear modulus. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(a) <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> (<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>) <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a></body></html> | |
| 39247. |
Two smooth spheres A and B, of equal radius but masses m and M, are free to move on a horizontal table. A is projected with speed u towards B which is at rest. On impact, the line joining their centres is inclined at an angle theta to the velocity of A before impact. If e is the coefficient of restitution between the spheres, find the speed with which B begins to move. If A.s path after impact is perpendicular to its path before impact, show that tan ^(2) theta = (eM-m)/(M +m). |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :When B is struck by the impulse J, it <a href="https://interviewquestions.tuteehub.com/tag/begins-894562" style="font-weight:bold;" target="_blank" title="Click to know more about BEGINS">BEGINS</a> to <a href="https://interviewquestions.tuteehub.com/tag/move-548879" style="font-weight:bold;" target="_blank" title="Click to know more about MOVE">MOVE</a> in the direction of J as shown in the . Along the line of centres, we apply <br/> (a) Conservation of linerar momentum , i.e., `m u cos theta MV - mv …(1)` <br/> (b) Law of resistution, i.e., `eu cos theta = V +v ...(2)` <br/> Solving <a href="https://interviewquestions.tuteehub.com/tag/eqs-2072581" style="font-weight:bold;" target="_blank" title="Click to know more about EQS">EQS</a>. (1) and (2) we get <br/> `v = ((eM - m) u cos theta )/( (M +m))and V = ((1 + e ) m u cos theta)/( (M + m ))` <br/> Hence, `tan phi= ( u sin theta)/( v ) = ((M + m ) tan theta)/( (e M - n ))` <br/> Butthe paths of A before and after <a href="https://interviewquestions.tuteehub.com/tag/impact-1037617" style="font-weight:bold;" target="_blank" title="Click to know more about IMPACT">IMPACT</a> are at rigth angles, therefore,` cot phi = tan theta.` <br/> Hence, `((eM - m ))/( (M + m ) tan theta ) = tan theta` <br/> `therefore tan ^(2) theta = (eM - m )/( (M + m ))`</body></html> | |
| 39248. |
A constant force actson a body of mass m_(1) at rest and produces a velocity 'v' over a displacement 's_(1)'. The same force acts on another body of mass m_(2) at rest and produced the same velocity. 'v' over a displacement 's_(2)'. The ratio of the displacements is |
| Answer» <html><body><p>`m_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>):m_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/>`m_(2):m_(1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(m_(1)):sqrt(m_(2))` <br/>`sqrt(m_(2)):sqrt(m_(1))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 39249. |
Two points are taken on a massless wire OC, such that OA = AB = BC. Three bodies of equal mass are tied at the points A, B and C and the system is kept on a horizontal smooth table. Keeping the wire taut, if the system is rotated around the point O, then what will be the ratio of tensions in the three parts of the wire? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> : <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> : <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>`</body></html> | |
| 39250. |
A particle of mass m is executing SHM about the origin on X-axis with frequency sqrt((ka)/(p m)) ,where k is a constant and a is the amplitude. Find its potential energy, if x is the displacement at time t |
| Answer» <html><body><p>`kax^2`<br/>`ka^2x`<br/>`kx^3`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a> kx^3`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |