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4851.

Three charged particles ( their sign sare shown ) move along the path in a uniform electric fiel as shown . In each of three cases state whether the potential energy increases of decreases ?

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SOLUTION :(A ) Potential ENERGY decreases .
(B) Potential energy increases .
(C ) Potential energy decreases.
4852.

A solid disk rotates in the horizontal plane at an angular velocity of 0.067 "rad"//s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.10 kg.m^(2). From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.40 m from the axis. The sand in the ring has a mass of 0.50 kg. After all the sand is in place, what is the angular velocity of the disk?

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`0.067 "RAD"//s`
`0.046 "rad"//s`
`0.059 "rad"//s`
`0.037 "rad"//s`

ANSWER :D
4853.

During total solar eclipse, the spectrum of the sunlight observed is

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LINE EMISSION spectrum
CONTINUOUS spectrum
Line ABSORPTION spectrum
Band spectrum

Answer :A
4854.

A metal surace objects electrons when hit by green light but none when hit by yellow light .The electrons will be ejected when the surface is hit by…….

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BLUE light
heat rays
infrared rays
red light

Solution :`lambda_("blue")lt "yellow"`
`(1)/(2)m_(MAX)^(2)=hf-phi=hf-hf_(0)`
4855.

From two sources, sound waves of frequency 270 Hz are emitted in phase in the positive direction of an x axis. At a detector that is on the axis and 5.00 m from one source and 4.00 m from the other source, what is the phase difference between the waves (a) in radians and (b) as a multiple of the wavelength?

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SOLUTION :(a) 4.95 RAD, (B) 0.787
4856.

A point P moves in counter-clockwise direction on a circular path as shown in the figure. The movement of 'P ' is such that it sweeps out a lengths=t ^ 3+5where s isinmetersandtisinseconds.Theradiusofthepathis20m.The acceleration of ' P ' when t = 2 s is nearly:

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` 13 m//s ^ 2`
`12 m//s ^ 2`
` 7.2 m//s^ 2`
` 14m//s ^ 2`

Solution :DISTANCE time relation of the particle, `s=t^(3)+5`
speed of the particle `V=(ds)/(dt)=(d)/(dt) (t^(3)+5)=3t^(2)`
Tangential acceleration, `a_(t)=(DV)/(dt)=(d)/(dt) (3t^(2))=6t`
At time t=2s, Speed of the particle `v=3(2)^(2)=12m//s`
Tangential acceleration, `a_(x)=6(2)=12m//s^(2)`
Centripetal acceleration, `a_(c)=v^(2)/R=((12)^(2))/(20)=(144)/(20)=7.2 m//s^(2)`
Net acceleration `a=sqrt((a_(c))^(2)+(a_(t))^(2))=sqrt((7.2)^(2)+(12)^(2))=14m//s^(2)`
4857.

In Sun, the important source of energy is

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Proton-Proton CYCLE
Carbon-nitrogen cycle
Carbon-carbon cycle
Nitrogen-nitrogen cycle

ANSWER :A
4858.

Hydrogen atoms are in an excited state with n = 5. In terms of the Bohr's model, (a) how many spectral lines can be radiated as these atoms return to be ground state? (b) Find the energies of the line with the longest and shortest wavelengths.

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SOLUTION :(a) 10, (B) 4000 NM, 95 nm
4859.

Aseries resonance LCR A.C. , circuit is called:

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a rejector CIRCUIT
an inductive circuit
an ACCEPTOR circuit
a harmonic circuit

Answer :C
4860.

Draw a ray diagram to show image formation for a (Cassegrain) reflecting telescope. What is its magnifying power ?

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Solution :The RAY diagram is being shown in Fig. 9.52.

MAGNIFYING power of a reflecting telescope in normal adjustment `=-f_(0)/f_(e)`, where `f_(0)` = focal length of OBJECTIVE MIRROR and `f_(e)`= focal length of EYEPIECE.
4861.

About how many times more intense will the normal ear perceive a sound of 10^(-6)W//m^2? than one of 10^(-9) W//m^2 ?

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SOLUTION :TWO TIMES
4862.

A dipole of dipole moment vec(P) = P_(o) hat(j) is placed at point (l,0). There exists an electric field vec(E)=2ax^(2)hat(i)+(2by^(2)+2cy)hat(j). Then

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<P>force on dipole is `2rho_(c )hat(J)`
force on dipole is `p(2c + 4bl)hat(j)`
Torque on dipole about its centroidal axis is `2rho_(0)ahat(k)`
Torque on dipole about its centroidal axis is ZERO

Answer :A
4863.

A small sphere of mass m and having charge q is suspended by a light thread.

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Tension in the THREAD may reduce to zero if another charged SPHERE is placed vertically below it.
tension in the thread is greater than mg if another charged sphere is held in the horizontal line in which first sphere stays inequlibrium.
tension in the thread may increases to twice of its ORIGINAL VALUE if another charged sphere is placed vertically below it
tension in the thread is ALWAYS equal to mg.

Answer :A::B::C
4864.

The adjoining figure shows a long straight wire of a circular cross section (radius a) carrying steady current I. The current I is uniformly distributed across its cross section. Calculate the magnetic field at a distance from its axis for (i) r lt a , (ii) r gt a .

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SOLUTION :N/A
4865.

Ultraviolet radiation of 6.2 e V falls on an aluminium surface (work function 4.2 e V). The kinetic energy in Joule of the fastest electron emitted is approximately :

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`3 XX 10^(-21)`
` 3.2 xx 10 ^(-19)`
`3 xx 10 ^(-17)`
`3 xx 10^(-15)`

Answer :B
4866.

A diminished image of an object is to be obtained on a screen 1.0 m from it. This can be achieved by appropriately placing

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a convex mirror of suitable focal length.
a CONCAVE mirror of suitable focal length.
a concave lens of suitable focal length.
a convex lens of suitable focal length less than 0.25 m.

Solution :To form a real and diminished image at a DISTANCE of 1.0 m from the object, we can use a convex lens WHOSE focal length `f LE (d)/(4)` i.e., `f le 0.25m.`
4867.

If the hydrogen atom is initially at n = 2 state, how much work have to do to move the electron and proton far into the hydrogen atom?

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`13.6xx1.6xx10^(-19)J`
`3.4xx1.6xx10^(-19)J`
`1.51xx1.6xx10^(-19)J`
0

Solution :If there is a LARGE distance between the electrons and protons, then the energy between them is zero. The work done for carrying electrons and protons too FAR.
`W=E_(f)=E_(i)`
`=[-(13.6)/(oo^(2))-(-(13.6)/(n^(2)))]eV`
`=(13.6)/(2^(2))eV=(13.6)/(4)xx1.6xx10^(-19)J`
`:.W=3.4xx1.6xx10^(-19)J`
4868.

Two blocks of masses 10 kg and 4 kg are connected by a negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m/s to the heavier block in the direction of the lighter block. The velocity of the centre of mass is :

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30 m/s
20 m/s
10 m/s
5 m/s

Solution :The VELOCITY of C.M. is given by

`v_(C.M.)=(m_(1)v_(1)+m_(2)v_(2))/(m_(1)+m_(2))=(10xx14+4xx0)/(10+4)=10MS^(-1)`
4869.

(A): However long a fuse wire may be, the safe current that can be allowed is the same through it. (R): The safe current that can be allowed to pass through a fuse wire depends on the radius of wire.

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Both 'A' and 'R' are TRUE and 'R' is the CORRECT EXPLANATION of 'A'
Both 'A' and 'R' are true and 'R' is not the correct explanation of 'A'
'A' is true and 'R' is FALSE 
'A' is false and 'R' is false 

Answer :B
4870.

A ball is dropped from height of Im. If coefficient of restituion between surface and ball is 0.6. The ball rebounds to a height of:

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0.4 m
1 m
0.6 m
0.36 m

Answer :d
4871.

What is the number of electrons which constitutes a current of one ampere ?

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SOLUTION :`6.25xx10^15s^(-1)`
4872.

Att the magnetic materials lose their magnetic properties , when :

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DIPPED in water
Dipped in oil
Brought NEAR a PIECE of iron
Strongly heated

Answer :B
4873.

If capacitor of 60muF has charge of 3xx10^4C on each plate in coulomb. Then the energy, stored is :

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`1.4xx10^-4J`
`2.5xx10^-4J`
`5.0xx10^-6J`
`7.5xx10^-4J`

ANSWER :D
4874.

Mention the principle behind the working of a transformer. Can a transformer used to step up a d.c. voltage ?

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SOLUTION :MUTUAL INDUCTION.
No.
4875.

A proton, a deuteron and an a-particle have same kinetic energies. Their velocities are in the ratio of:

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`1:sqrt2:1`
`1:1:sqrt2`
`sqrt2:1:1`
`1:(1)/(sqrt(2)):1`

Solution :Here `R=(mv)/(Be)= sqrt((mxx mv^(2)))/(Be)=sqrt(2mE_(k))/(Be)`
Here K.E. and B are the same `:. r PROP (sqrt(m))/(e)`
`:.r_(p):r_(d):r_(alpha): :sqrt(m_(p))/(e): sqrt(m_(d))/(e):sqrt(m_(alpha))/(2e)=1: sqrt(2):1`
`:.m_(d)=2m_(p) and m_(alpha)=4m_(p)`
4876.

A conductor is moved at right angles to a magnetic field, will an emf be induced between the ends of the conductor ?

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Solution :Yes, It is because in the CASE Lorentz FORCE ACTS on the free ELECTRONS in the CONDUCTOR.
4877.

If W_(1), W_(2) and W_(3) represent the work done in moving a particle from A to B along three different paths 1, 2 and 3 respectively(as shown) in a gravitational field of point mass m, then

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`W_(1)=W_(2)=W_(3)`
`W_(1) gt W_(2) gt W_(3)`
`W_(11) LT W_(2) lt W_(3)`
`W_(1) lt W_(3) lt W_(2)`

Solution :ENERGY required = Increase in Gravitational POTENTIAL energy
`= -(GMM)/(3R)+(GMm)/(2R)=(GMm)/(6R)`
CORRECT choice is (d).
4878.

A charge Q_(0) is placed at the center of spherical cavity of a conductor and another charge Q is placed outside the conductor as shown in the figure. The correct statement is :

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Force on `Q_(0)` and Q are EQUAL and OPPOSITE
Force on `Q_(0)` is ZERO and force on Q is nonzero
Force on Q and `Q_(0)` is zero
Force on `Q_(0)` is nonzero and force on Q is zero

Answer :B
4879.

Assertion (A): The alloys manganin and constant on are used to make standard resistors.Reason (R) : Resistivity of nichrome is maximum amongst all alloys.

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If both assertion and REASON are true and the reason is the CORRECT explanation of the assertion.
If both assertion and reason are true but reason is not the correct explanation of the assertion.
If assertion is true but reason is false.
If the assertion is false but reason is true.

Solution : Manganin and CONSTANTON are USED to make standard resistors because their thermal coefficientof resistivity is extremely small.
4880.

A star emitting light of 5000 Å is receding away from earth with a velocity of 300 km/s. the apparent wavelength of light is :

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5000Å
5005 Å
5050 Å
4096 Å

Solution :`Delta LAMBDA = (u lambda)/(C ) = (5000 xx 3XX 10^(5))/(3 xx 10^(8)) `
`Delta lambda = 5 `Å
`therefore lambda. - lambda rArr lambda = 5000 + 5 `Å.
Hence the correct choice is (B) .
4881.

A telescope has a magnification equal to 5 and the length of its tube is 60 cm. The focal length of its eye piece is

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10 cm
20 cm
30 cm
40 cm

Solution :Magnification of TELESCOPE
`m=(f_0)/(f_e)`
`THEREFORE 5=(f_0)/(f_e)`
`therefore f_0=5f_e`
Now tube length
`f_0+f_e`
`60=5f_e+f_e`
`therefore 60 =6f_e`
`thereforef_e=10` cm
4882.

At a certain voltage applied to an X-rays tuve with aluminium anticathode the short-wave cut-off wavelength of the continuous X-rays spectum is equal to 0.50nm. Will the K series of the characteristic specturm whose excitation potential is equal to 1.56kV be also observed in this case?

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SOLUTION :Since the short wavelength cut off of the continuous specturm is
`lambda_(0)=0.50nm`
the voltage applied must be `V=(2 pi ħ )/(2 lambda_(0))=2.48kV`
since this is greater than the EXCITATION potential of the `K` SERIES of the characteristic specturm (which is only `1.56kV`) the latter will be observed.
4883.

A tuning fork vibrates and produces concentric circular transverse wave on the surface of water. If distance between 10 crests is 9.0m and velocity of the wave on the surface of water is 450m/s, what is frequency of the tuning fork ?

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SOLUTION :DISTANCE between 10 crest = 9m.
`lamda = 0.9m v =nlamda n = v/lamda` = 450/0.9 = 500 HZ
4884.

Arigid circular loop of radius r nnd mass m lies in the x - y plane on a flat table and has a current i flowing in it. At this is particular place , the earth's magnetic field is B = Bxhati + Bzhatk. The value of i so that one edge of the loop lifts from the table is

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`(MG)/(pirsqrt(B_(X)^(2)+B_(z)^(2)))`
`(mg)/(pirB_(z))`
`(mg)/(pirB_(x))`
`(mg)/(pirsqrt(B_(x)B_(z)))`

Answer :C
4885.

As the quantum number increases, the difference of energy between consecutive energy leveles

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DECREASES
increases
first decreases and then increases
remains the same

Answer :A
4886.

A double-slit experiment is immersed in a liquid of refractive index 1.33. The separation between the slits is 1mm and the distance between the slits and screen is 1.33 m. If slits are illuminated by a parallel beam of light whose wavelength is 6300 Å, then fringe width will be

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6.3mm
63 mm
0.63 mm
None of these

ANSWER :C
4887.

The half-life period of a radioactive element X is same as mean life of another radioactive element Y. Initially they have same no. of atoms, then:

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Y decays faster than X
X and Y DECAY EQUALLY initially
X and Y decay at same rate always
X will decay faster than Y.

Solution :`T_(X)=(0.693)/(lambda X)`
`T_(Y)=1/(lambda_(Y))=(0.693)/(lambda_(Y)) xx (1)/(0.693) =(T_(Y))/(0.693)`
`T_(X)=(T_(Y))/(0.693) RARR T_(X) gt T_(Y)`
Y decays faster than X.
4888.

For increasing the sharpness of resonance in a LCR series a.c. circuit, the presence in the circuit should be minimum.

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SOLUTION :RESISTANCE R
4889.

In the double-slit experiment, the electric fields of the waves arriving at point P are given by E_(1)=(2.00 mu V // m)sin[(1.26 xx 10^(15))t] E_(2)=(2.00 mu V // m)sin[(1.26=10^(15))t+38.6 "rad"]  where timer is in seconds. (a) What is the amplitude of the resultant electric field at point P? (b) What is the ratio of the intensity I_(P) at point P to the intensity I_("cen") at the center of the interference pattern? (C) Describe where point P is in the interference pattern by giving the maximum or minimum on which it lies, or the maximum and minimum between which it lies. In a phasor diagram of the electric fields, (d) at what rate would the phasors rotate around the origin and (e) what is the angle between the phasors?

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<P>

Solution :(a) 2.33 `mu V // m`, (b) 0.338, (c) POINT P is between the sixth side MAXIMUM (at which `PHI= 6` wavelengths) and the seventh minimum (at which `phi= 6(1)/(2)` wavelengths), (d) `1.26 xx 10^(15) rad // s`, (e) `2270^(@)`
4890.

Describe Young's slit experiment to produce interference pattern due to a monochromatic source of light. Deduce the expression for the fringe width.

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Solution :A SIMPLE schematic diagram of Young.s double-slit experiment to produce interference pattern due to a monochromatic source of light is shown in figure. Let `S_(1) and S_(2)` be two narrow slits, a small distance .d. apart, illuminated by a monochromatic light source S of wavelength `lamda`, kept
equidistant from the slits `S_(1) and S_(2)`. Consider a point P on the screen MN, situated at a normal distance .D. from the slits, at a distance .x. from the symmetrical central point O of screen. Path difference between light waves reaching point P from two slit sources is `S_(2) P-S_(1)P`, where
`(S_(2)P)^(2)=D^(2)+(x+(d)/(2))^(2) and (S_(1)P)^(2)=D^(2)+(x-(d)/(2))^(2)`
`therefore (S_(2)P)^(2)-(S_(1)P)^(2)=[D^(2)+(x+(d)/(2))^(2)]-[D^(2)+(x-(d)/(2))^(2)]=2xd`
`implies(S_(2)P-S_(1)P)(S_(2)P+S_(1)P)=2xd`
WIDTH="80%">
or `(S_(2)P-S_(1)P)=(2xd)/((S_(2)P+S_(1)P))`
If x and d are very very small as compared to D, then `(S_(2)P+S_(1)P)` may be considered as 2D. hence,
`[S_(2)P-S_(1)P]=(2xd)/(2D)=(xd)/(D)`
For constructive interference, path difference MUST be an integer multiple of `lamda` i.e., `(xd)/(D)=nlamda`,
where `n=0,1,2,3,`. etc.
`impliesx=(nDlamda)/(d)` i.e., positions of various maxima (bright bands) will be given by :
For destructive interference, path difference must be an odd multiple of `(lamda)/(2)` i.e., `(xd)/(D)=(2n-1)(lamda)/(2)`,
where n=1,2,3, . . etc.
`impliesx=((2n-1)Dlamda)/(2d)` i.e., positions of various minima (dark bands) will be given by:
`x_(1).=(Dlamda)/(2d),x_(2).=(3Dlamda)/(2d),x_(3).=(5Dlamda)/(2d)` . . .
Fringe width of the fringe pattern is defined as the distance between two SUCCESSIVE maxima or successive minima. therefore, considering two successive maxima, we have
Fringe width `beta=x_(n+1)-x_(n)=((n+1)Dlamda)/(d)-(nDlamda)/(d)=(Dlamda)/(d)`
4891.

A uniform electric field is prevailing in X- direction in certain region. The Co-ordinates of points P, Q and R are (0, 0), (2, 0), (0, 2) respectively which of the following alternatives is true for the potentials at these points ?

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`V_(P) GT V_(Q), V_(P) = V_(R) `
`V_(P) = V_(Q), V_(P) gt V_(R) `
`V_(P) LT V_(R), V_(Q) = V_(R) `
`V_(P) = V_(Q), V_(P) lt V_(Q) `

Solution :
`:. V_(p) gt V_(Q) , V_(P) = V_(R)`
4892.

Two coherent sources S_1" and "S_2 produce interference fringes. If a thin mica plate is introduced in the path of light from S_(1) then the central maximum

Answer»

SHIFT TOWARDS `S_2`
shift towards `S_1`
do not shift to any side
disappear

Answer :B
4893.

Monochromatic light of wavelength 589 nm is incident from air on water surface. If the R.l. of water is 1.33, the frequency of refracted light is:

Answer»

`5xx10^14Hz`
`4.5xx10^14Hz`
`6.775xx10^14Hz`
`6xx10^14Hz`

ANSWER :A
4894.

The resistance R of a conductor depends on its length l,area of crossection A and resistivity p of the meterial.Write an expression connecting R,I, A and rho.

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SOLUTION :`R= rhol/A`
4895.

Two conducting large plates P_(1) & P_(2) are placed parallel to each other at very small seperation 'd'. The plate area of either face of plate is A. A charge +2Q is given to plate P_(1) & -Q to the plate P_(2) (neglect ends effects). If plate P_(1) & P_(2) are now connected by conducting wire, then total amount of heat produced is

Answer»

`(4Q^(2)d)/(3in_(0) A)`
`(9Q^(2)d)/(8in_(0) A)`
`(3Q^(2) d)/(8 in_(0) A)`
None of these

Solution :`C=(varepsilon_(0)A)/d U_(i)=(1.5Q)^(2)/(2c)=(2.25Q^(2)d)/(2C)`
`Rightarrow U_(i) = (9Q^(2)d)/(8varepsilon_(0)A)`
After CONNECTING
Heat `=U_(i)-U_(f)=(9Q^(2))/(dvarepsilon_(0)A)`
4896.

Two circular coils of radii 20 cm and 30cm having number of turns 50 and 100 made of same material are connected in series. The ratio of the magnetic field of induction at their centres is

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`3:2`
`9:4`
`3:4`
`1:3`

ANSWER :C
4897.

A galvanometer has a current sensitivity of 1 mA per division. A variable slhunt is connected across the galvanometer and the combination is put in series with a resistance of 500Omega and cell of internal resistance 1Omega. It gives a deflection of 5 division for shunt of 5 ohm and 20 division for shunt of 25 ohm. The emf of cell is

Answer»

`47.1` V
`57.1` V
` 67.1 `V
`77.1` V

Solution :
`"Here", I=(E)/(R+r+(GS)/(G+S))and I_(R)=(IS)/(G+S)`
`I_(R)=(E)/((R+r)+(GS)/((G+S)))XX(S)/((G+S))`
`therefore I_(R)=(ES)/(((R+r)(G+S)+GS))`
For S=5ohm, `I_(R)=5xx10^(-3)A` and for S=25ohm,
`I_(R)=20xx10^(-3)A`
`"Hence", 5xx10^(-3)=(Exx5)/(501(G+5)+5G)......(I)`
`and 20xx10^(-3)=(Exx25)/(501(G+5)+25G)......(II)`
Dividing and solving
`G=88.2Omega`
From, (i) we get
`E=10^(-3) [501 (88.2+5)+5xx88.2]`
=47.1 volt
4898.

An electric dipole consists of charges pm 2.0 xx 10^(-8) C separated by a distance of 2.0 xx 10^(-3)m. It is placed near a long line charger of linear charger density 4.0 xx 10^(4) C//m. As shown in figure, such that the negative charge is a distance of 2.0 cm from the line charge. Find the force acting on the dipole

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0.6 N TOWARDS the LINE charge
0.1 N AWAY from the line charge
0.9 N towards the line charge
1.5 N away away from the line charge

Answer :A
4899.

Column -I a. Radius of orbit is related with atomic number(Z) b. Current associated due to orbital motion of electron with atomic number(Z). c. Magnetic field at the center due to orbital motion of electron related with Z d. Velocity of an electron related with atomic number(Z) Column- II p. is proportional to Z q. is inversely proportion to Z r. is proportional to Z^(2) s. is proportional to Z^(3).

Answer»

a-q b-r c-r d-p
a-q b-s c-r d-p
a-p b-r c-s d-p
a-p b-s c-s d-q

ANSWER :A
4900.

If a ray of light is incident from rarer medium at an angle 45° on the surface which separates two medium having refractive indices 1 and sqrt(2) for rarer and denser medium, then angle of deviation of refractive ray with incident ray is

Answer»

45°
15°
30°
75°

Answer :B