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1). x < y2). x > y3). x = y4). x ≥ y

Answer»

I. 10x2 + 37X + 7 = 0

⇒ 10x2 + 35X + 2x + 7 = 0

⇒ 5x(2x + 7) + 1(2x + 7) = 0

⇒ (2x + 7)(5x + 1) = 0

Then, x = - 7/2 or x = - 1/5

II. 5Y2 – 14y – 3 = 0

⇒ 5y2 – 15y + y – 3 = 0

⇒ 5y(y – 3) + 1(y – 3) = 0

⇒ (y – 3)(5y + 1) = 0

Then, y = + 3 or y = - 1/5

So, when x = - 7/2, x < y for y = + 3 and x < y for y = - 1/5

And when x = - 1/5, x < y for y = + 3 and x = y for y = - 1/5

∴ So, we can clearly observe that x ≤ y.


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