InterviewSolution
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1). x < y2). x > y3). x = y4). x ≥ y |
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Answer» I. 10x2 + 37X + 7 = 0 ⇒ 10x2 + 35X + 2x + 7 = 0 ⇒ 5x(2x + 7) + 1(2x + 7) = 0 ⇒ (2x + 7)(5x + 1) = 0 Then, x = - 7/2 or x = - 1/5 ⇒ 5y2 – 15y + y – 3 = 0 ⇒ 5y(y – 3) + 1(y – 3) = 0 ⇒ (y – 3)(5y + 1) = 0 Then, y = + 3 or y = - 1/5 So, when x = - 7/2, x < y for y = + 3 and x < y for y = - 1/5 And when x = - 1/5, x < y for y = + 3 and x = y for y = - 1/5 ∴ So, we can clearly observe that x ≤ y. |
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