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II. 39b2 - 624b = 01). a < b2). a > b3). a ≤ b4). a ≥ b |
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Answer» I. a2 + 18a + 56 = 0 ⇒ a2 + 14a + 4a + 56 = 0 ⇒ a(a + 14) + 4(a + 14) = 0 ⇒ (a + 14) (a + 4) = 0 Then, a = (-4) or a = (-14) II. 39b2 - 624b = 0 ⇒ 39b(b - 16)0 ⇒ (b) (b - 16) = 0 Then, b = (0) or b = 16 So, when a = (-4), a < b for b = (16) and a < b for b = 0 And when a = (-14), a < b for b = (16) and a < b for b = 0 ∴ we can observe that a < b. |
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