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II. 39b2 - 624b = 01). a < b2). a > b3). a ≤ b4). a ≥ b

Answer»

I. a2 + 18a + 56 = 0

⇒ a2 + 14a + 4a + 56 = 0

⇒ a(a + 14) + 4(a + 14) = 0

⇒ (a + 14) (a + 4) = 0

Then, a = (-4) or a = (-14)

II. 39b2 - 624b = 0

⇒ 39b(b - 16)0

⇒ (b) (b - 16) = 0

Then, b = (0) or b = 16

So, when a = (-4), a < b for b = (16) and a < b for b = 0

And when a = (-14), a < b for b = (16) and a < b for b = 0

∴ we can observe that a < b.


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