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II. y2 + 22y + 112 = 01). x < y2). x > y3). x = y OR the relationship cannot be determined4). x ≥ y |
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Answer» I. x2 – 18X – 115 = 0 ⇒ x2 – 23x + 5x – 115 = 0 ⇒ x(x – 23) + 5(x – 23) = 0 ⇒ (x – 23)(x + 5) = 0 Then, x = + 23 or x = - 5 II. y2 + 22y + 112 = 0 ⇒ y2 + 14y + 8y + 112 = 0 ⇒ y(y + 14) + 8(y + 14) = 0 ⇒ (y + 14)(y + 8) = 0 Then, y = - 14 or y = - 8 So, when x = + 23, x > y for y = - 14 and x > y for y = - 8 And when x = - 5, x > y for y = - 14 and x > y for y = - 8 ∴ So, we can clearly observe that x > y. |
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