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II. 30b2 + 56b + 10 = 01). a < b2). a > b3). a ≤ b4). a ≥ b |
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Answer» I. 16a2 - 52a + 22 = 0 ⇒ 16a2 - 8a - 44a + 22 = 0 ⇒ (8a - 22) (2a - 1) = 0 Then, a = 22/8 or a = 1/2 II. 30b2 + 56b + 10 = 0 ⇒ 30b2 + 6B + 50b + 10 = 0 ⇒ 6b(5b + 1) + 10(5b + 1) = 0 ⇒ (6b + 10) (5b + 1) = 0 Then, b = (-10/6) or b = (-1/5) So, when a = (22/8), a > b for b = (-10/6) and a > b for b = (-1/5) And when a = (1/2), a > b for b = (-10/6) and a > b for b = (-1/5) ∴ we can observe that a > b. |
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