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A signal generator supplies a sine wave of 20V, 5 kHz to the circuit as shown. Determine total current IT.(a) 0.21∠33⁰(b) 0.22∠33⁰(c) 0.23∠33⁰(d) 0.24∠33⁰This question was addressed to me by my college professor while I was bunking the class.The doubt is from Parallel Circuits topic in portion Complex Impedence of Network Theory

Answer»

Correct OPTION is (d) 0.24∠33⁰

Explanation: Capacitive reactance = 1/(6.28×5×10^3×0.2×10^-6)=159.2Ω.CURRENT in the resistance BRANCH IR=VS/R=20/100 = 0.2A.Current in capacitive branch IC=VS/XC = 20/159.2 = 0.126A.Total current IT = (IR+j IC) A = (0.2+j0.13) A. In polar FORM, IT = 0.24∠33⁰ A.



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