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Determine total impedance in the circuit shown below.(a) 25∠-58.8⁰(b) 25∠-58.8⁰.(c) 26∠-58.8⁰.(d) 26∠58.8⁰.The question was posed to me by my school principal while I was bunking the class.Question is from Parallel Circuits topic in division Complex Impedence of Network Theory |
Answer» RIGHT ANSWER is (c) 26∠-58.8⁰. Easy explanation: The CURRENT lags BEHIND the voltage by 58.8⁰. Total impedance Z = VS/IT = 20∠0⁰ / 0.77∠-58.8⁰ = 25.97∠-58.8⁰Ω. So the total impedance in the circuit shown is 25.97∠-58.8⁰Ω. |
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