Determine Z in the figure shown below.(a) 26∠-20.5⁰(b) 26∠20.5⁰(c) 25∠-20.5⁰(d) 25∠20.5⁰I had been asked this question during an online interview.This intriguing question comes from Parallel Circuits in chapter Complex Impedence of Network Theory

Determine Z in the figure shown below.(a) 26∠-20.5⁰(b) 26∠20.5�

1.	Determine Z in the figure shown below.(a) 26∠-20.5⁰(b) 26∠20.5⁰(c) 25∠-20.5⁰(d) 25∠20.5⁰I had been asked this question during an online interview.This intriguing question comes from Parallel Circuits in chapter Complex Impedence of Network Theory
Answer» The correct option is (b) 26∠20.5⁰ To explain: FIRST the inductive reactance is calculated. XL=6.28 X 50 x 0.1 = 31.42Ω. In figure the 10Ω resistance is in series with the PARALLEL combination of 20Ω and j31.42Ω. ZT = 10 + (20)(j31.42)/(20+j31.42)=24.23+j9.06=25.87∠20.5⁰.

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