1.

Find the impedance in the circuit shown below.(a) 25(b) 26(c) 27(d) 28I got this question in an online interview.I need to ask this question from Parallel Circuits topic in chapter Complex Impedence of Network Theory

Answer»

The CORRECT answer is (c) 27

For explanation: Capacitive reactance XC = 1/2πfC = 1/(6.28×50×100×10^-6)=31.83Ω. Capacitive susceptance BC = 1/XC = 1/31.83 = 0.031S. Conductance G=1/R = 1/50 = 0.02S. TOTAL admittance Y=√(G^2+Bc^2)=√(0.02^2+0.031^2)=0.037S. Total IMPEDANCE Z = 1/Y = 1/0.037 = 27.02Ω.



Discussion

No Comment Found

Related InterviewSolutions