1.

Determine the phase angle in the circuit shown below.(a) 56⁰(b) 56.5⁰(c) 57.5⁰(d) 57⁰I got this question in an online interview.This key question is from Parallel Circuits topic in portion Complex Impedence of Network Theory

Answer»

Correct CHOICE is (c) 57.5⁰

To elaborate: Phase ANGLE θ=tan^-1(R/Xc). Resistance R = 50Ω and capacitive REACTANCE Xc = 31.83Ω. So the phase angle in the circuit = tan^-1(50/31.83)=57.52⁰.



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