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`cos(2A)/a^2-cos(2B)/b^2 = 1/a^2-1/b^2` |
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Answer» `L.H.S. = (cos2A)/a^2-(cos2B)/b^2` `=(1-2sin^2A)/a^2 - (1-2sin^2b)/b^2` `=1/a^2-1/b^2-2(sin^2A/a^2 - sin^2B/b^2)` From sine law, `sinA/a = sinB/b = sinC /c` `:. sin^2A/a^2 = sin^2B/b^2 ` `:. 1/a^2-1/b^2-2(sin^2A/a^2 - sin^2B/b^2) = 1/a^2-1/b^2-2(0)` `1/a^2-1/b^2 = R.H.S.` |
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