1.

`cos(2A)/a^2-cos(2B)/b^2 = 1/a^2-1/b^2`

Answer» `L.H.S. = (cos2A)/a^2-(cos2B)/b^2`
`=(1-2sin^2A)/a^2 - (1-2sin^2b)/b^2`
`=1/a^2-1/b^2-2(sin^2A/a^2 - sin^2B/b^2)`
From sine law,
`sinA/a = sinB/b = sinC /c`
`:. sin^2A/a^2 = sin^2B/b^2 `
`:. 1/a^2-1/b^2-2(sin^2A/a^2 - sin^2B/b^2) = 1/a^2-1/b^2-2(0)`
`1/a^2-1/b^2 = R.H.S.`


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