InterviewSolution
Saved Bookmarks
| 1. |
The angles of a triangle `A B C`are in `AdotPdot`and it is being given that `b : c=sqrt(3):sqrt(2)`, find `/_Adot` |
|
Answer» As angles are in A.P., `:. 2/_B = /_A+/_C` Now, `/_A+/_B+/_C = 180` `/_B+2/_B = 180` `/_B = 60^@` Now, from sine law, `b/sinB = c/sinC` `b/c = sinB/sinC` `=>sqrt3/sqrt2 = sin60^@/sinC` `sinC = sqrt3/2*sqrt2/sqrt3 = 1/sqrt2` `:. C = 45^@` `/_A = 180-(60+45) = 75^@` |
|