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Design a rectangular sedimentation tank to treat 2.4 million litres of raw water per day. The detention period may be assumed to be 3 hours. Find overflow rate?(a) 28,000 l/d/m^2(b) 12,000 l/d/m^2(c) 24,000 l/d/m^2(d) 4,670 l/d/m^2I had been asked this question during an interview for a job.Question is taken from Principle for the Preparation of Water Supply topic in section Valuation, Reports Technical and Design Data of Civil Engineering Drawing

Answer»

Correct answer is (C) 24,000 l/d/m^2

Easy explanation: Raw water flow per day is 2.4 x 106 l. Detention period is 3h.

Volume of TANK = Flow x Detention period = 2.4 x 103 x 3/24 = 300 m^3

Assume depth of tank = 3.0 m.

SURFACE area = 300/3 = 100 m^2

L/B = 3 (assumed). L = 3B.

3B2 = 100 m^2 i.e. B = 5.8 m

L = 3B = 5.8 X 3 = 17.4 m

Hence surface loading (Overflow rate) = 2.4 x 106 = 24,000 l/d/m^2 < 40,000 l/d/m^2.



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