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Determine the phase angle in the circuit shown below.(a) 58(b) 68(c) -58(d) -68This question was addressed to me in unit test.I need to ask this question from Series Circuits topic in chapter Complex Impedence of Network Theory

Answer»

The correct ANSWER is (c) -58

To ELABORATE: The phase ANGLE in the CIRCUIT is phase angle θ = tan^-1⁡(-XC/R) =tan^-1⁡((-3184.7)/2000)=-57.87^o≅-58^o.



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