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Find the current I (mA) in the circuit shown below.(a) 3.03(b) 30.3(c) 303(d) 0.303I got this question during an interview.This is a very interesting question from Series Circuits topic in chapter Complex Impedence of Network Theory |
Answer» RIGHT OPTION is (a) 3.03 For explanation: Total IMPEDANCE Z = (1000+j3140) Ω. Magnitude = 3295.4Ω Current I=Vs/Z = 10/3295.4=3.03mA. |
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